How would you prepare 250 mL of 0.125 M HCl from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mLnote: find moles in 250 mL of 0.125 HCl

Answers

Answer 1

Answer

250 mL of 0.125 M HCl can be prepared from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mL by adding 2.49 mL of HCL(38%) into a small quantity of water, mix to disperse; then dilute with solvent water up to but not to exceed the total needed volume of solution (in this case 250 mL).

Explanation

The problem can be solve in four steps:

Step 1: Calculate the number of moles in 38.0% by mass of HCl.

[tex]\begin{gathered} \text{HCl (38.0}\%)\text{ }=(\frac{38g\text{ HCl}}{100\text{ g solution}})=(\frac{x\text{ moles HCl}}{1.0\text{ Liter Solution}}) \\ \\ \Rightarrow Moles\text{ of HCl in 38 grams }=\frac{38g\text{ HCl}}{36\text{ g/mol}}=1.06\text{ mole HCl} \end{gathered}[/tex]

Step 2: The volume of the 38.0% by mass HCl solution.

Volume of solution in Liters containing 1.06 mole of HCl =

[tex]\frac{Mass}{D\text{ensity}}=\frac{100g}{1.19gmL^{-1}^{}}=84.03\text{ mL HCl(38.0}\%)\text{ }=0.084\text{ L HCl(38.0}\%)[/tex]

Step 3: Calculate the molarity of HCl (38.0%)

[tex]\text{Molarity of HCl (38.0}\%)=\frac{Number\text{ of mole}}{Volume\text{ in liters}}=\frac{1.06\text{ mole HCl}}{0.084\text{ L HCl}}=12.62\text{ M}[/tex]

Step 4: To calculate the volume of HCl (38.0%) required to prepare 250 mL of 0.125 M HCl.

Note: Formula weight of HCl = 36 g/mol

[tex]\begin{gathered} \text{Volume of HCl(38.0}\%)\text{ required }=\frac{(Molarity)(Volume)(Formula\text{ Weight)}}{(\text{Purity)(Specific Gravity)}} \\ \\ \text{Volume of HCl(38.0}\%)\text{ required }=\frac{(0.125\text{ M)})(250\text{ }mL)(36\text{ g/mol)}}{(0.38\text{)}(1.19\text{ g/mL)}} \\ \\ \text{Volume of HCl(38.0}\%)\text{ required }=\frac{(0.125\text{ M)})(0.250\text{ }L)(36\text{ g/mol)}}{(0.38\text{)}1.19\text{ g/mL)}} \\ \\ \text{Volume of HCl(38.0}\%)\text{ required }=\frac{1.125}{0.4522}=2.49\text{ mL} \end{gathered}[/tex]

Therefore, 250 mL of 0.125 M HCl can be prepared from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mL by adding 2.49 mL of HCL(38%) into a small quantity of water, mix to disperse; then dilute with solvent water up to but not to exceed the total needed volume of solution (in this case 250 mL).


Related Questions

Radioactive iodine (I-131) is an isotope of iodine that emits radiation and is used for various medical applications, such as in the treatment of thyroid cancer. The half-life for I-131 is 8 days. Based on the half-life of I-131, how many half-lives have to pass for a 200 mg sample of I-131 to decay down to 25 mg?

Answers

Half life is the time period in which half of the initial amount of an element will decay into a new element due to instability. For I-131, the half life is 8 days.

From 200 to 25 grams, let's see how many half lives are there:

200g -> 100g

100g -> 50g

50g -> 25g

Therefore for 200g of I-131 reach 25 grams, 3 half lives are necesseray, 3 half lives or 24 days

2. Complete and correctly balance each of the following reactions: 5 pts(a) Double replacement: Ba Cl2 (aq) + AgNO3 (aq)-(b) Decomposition: HgO (s)(c) Combustion: C4H10 (9) + O2 (9)-(d) Single replacement: Ca (s) + AlCl3 (s)(e) Combination: Mg(s) + N2 (9)-

Answers

2. (a) We are told that it is a double displacement reaction, so there will be two substitutions and Cl will exchange places with NO3.

Now, that will be the full reaction but we need to balance it. Count the atoms of each element on each side of the reaction. In the figure we can see that Chlorine, Nitrogen and Oxygen are not balanced.

We place the coefficient 2 in front of the AgCl molecule to balance the chlorides. You can see the picture.

Now we will balance the nitrogens. There are two nitrogens in the products. We place the coefficient two in the AgNO3 molecule. In the figure I will make the update.

Now the equation is balanced, so the balanced reaction will be:

[tex]BaCl_{2(aq)}+2AgNO_{3\left(aq\right)}+\rightarrow Ba\left(NO_3\right)_{2\left(aq\right)}+2AgCl(s)[/tex]

Calculate the pOH for an aqueous solution containing 0.01 moles of HCl in a 2.5 L solution.

Answers

The question requires us to calculate the pOH value for a solution containing 0.01 moles of HCl in 2.5 L of solution.

To solve this problem, we'll need to go through the following steps:

I) calculate the molar concentration of the HCl solution to obtaine the concentration of H+ ions;

II) using the concentration of H+ ions, calculate the pH of the solution;

III) with the value obtained for pH, calculate the value of pOH for this solution.

Next, we'll go through the steps to solve the question:

I) Since the question provided the number of moles of HCl and the volume of the solution, we can calculate the molar concentration using the following equation:

[tex]\text{molar concentration = }\frac{\text{number of moles (mol)}}{\text{volume (L)}}_{}[/tex]

Thus, applying the values provided:

[tex]\text{molar concentration of HCl= }\frac{0.01\text{ mol}}{2.5\text{ L}}=0.004\text{ mol/L}[/tex]

Therefore, the concentration of the HCl solution is 0.004 mol/L.

Since HCl is a strong acid, we can expect it to completely dissociate in H+ and Cl-: the concentration of H+ ions for this solution would also be 0.004 mol/L ( [H+] = 0.004 mol/L).

III) The next step is calculate the pH of this solution. We'll use the following equation and apply the concentration of H+ ions obtained in the previous step ( [) using H+] = 0.004 mol/L):

[tex]pH=-\log _{10}\lbrack H^+\rbrack\to pH=-\log _{10}(0.004)=2.39[/tex]

Now, we know that the pH of the solution is 2.39.

III) The last step is use the pH value calculated (pH = 2.39) to calculate the pOH of the solution, using the following equation:

[tex]pH+\text{pOH =14}\to pOH\text{ = 14 - pH}[/tex][tex]\text{pOH = 14-2.39 = 11.6}[/tex]

Therefore, the pOH of the HCl solution given is 11.6.

Calculate the pH and pOH of aqueous solutions with the following concentrations.[OH﹘] = 1.0 x 10-7M

Answers

Answer;

pH = 7

pOH = 7

Explanations:

The formula for calculating the pOH of a solution is given as:

[tex]pOH=-log[OH^-][/tex]

Given the following parameter

[tex][OH^-]=1.0\times10^{-7}M[/tex]

Substitute

[tex]\begin{gathered} pOH=-log(1.0\times10^{-7}) \\ pOH=-log(10^{-7}) \\ pOH=-(-7) \\ pOH=7 \end{gathered}[/tex]

Determine the pH of the solution

Recall that pH + pOH = 14, hence;

[tex]\begin{gathered} pH=14-pOH \\ pH=14-7 \\ pH=7 \end{gathered}[/tex]

Hence the required pH and pOH of aqueous solution are 7 and 7 respectively

An tank contains oxygen (O2) at a pressure of 2.29 atm . What is the pressure in the tank in terms of torr

Answers

Explanation:

One atm of pressure is equal to 760 torr. We can use this relationship to find the answer to our problem.

1 atm = 760 torr

P = 2.29 atm = 2.29 atm * 760 torr/(1 atm)

P = 1740 torr

Answer: The pressure of the tank in torr is 1740 torr.

Lists the groups of the periodic table in order from left to right.

Answers

1 Alkali metals
2 Alkaline earth metals
3 Transition metals
4 Halogen
5 Nobel gases

The groups of the periodic table from left to right are alkali metals, alkaline earth metals,transition metals,halogens and noble gases.

What is periodic table?

Periodic table is a tabular arrangement of elements in the form of a table. In the periodic table, elements are arranged according to the modern periodic law which states that the properties of elements are a periodic function of their atomic numbers.

It is called as periodic because properties repeat after regular intervals of atomic numbers . It is a tabular arrangement consisting of seven horizontal rows called periods and eighteen vertical columns called groups.

Elements present in the same group have same number of valence electrons and hence have similar properties while elements present in the same period show gradual variation in properties due to addition of one electron for each successive element in a period.

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How many grams are in 4.02 x 10^21 atoms of calcium?

Answers

Answer:

0.268grams

Explanations:

According to the Avogadro's constant

1 mole of an atom = 6.02 * 10^23 molecules

Given the following

atoms of calcium = 4.02 x 10^21 atoms

Determine the moles of calcium

[tex]\begin{gathered} moles\text{ of Ca}=\frac{4.02\times10^{21}}{6.02\times10^{23}} \\ moles\text{ of Ca}=0.668\times10^{21-23} \\ moles\text{ }of\text{ Ca}=0.668\times10^{-2} \\ moles\text{ of Ca}=0.00688moles \end{gathered}[/tex]

Determine the mass of Calcium

[tex]\begin{gathered} Mass=mole\times molar\text{ mass} \\ Mass=0.00688\times40.078 \\ Mass\text{ of Ca}=0.268gram \end{gathered}[/tex]

Hence the required grams in 4.02 x 10^21 atoms of calcium is 0.268grams

Why is DNA describes as a blueprint for a cell?

Answers

DNA describes as a blueprint for a cell because it contain the instruction needed for an organism to grow develop and survive

DNA is called a blueprint of life because it contain the instruction needed for an organism to grow develop and survive and reproduce and DNA does this by controlling protein synthesis and protein do must of the work cell and are basic unit of structure and function in the cell of organism

DNA is read by the enzyme RNA polymerase and this enzyme attaches itself to the DNA strand slightly in front of a gene and it then slides along the DNA strand making a copy of the gene only using RNA building blocks instead of DNA building block

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Please help with 2nd and 3rd questions In question b) Aluminum reacts with hydrocloric acid

Answers

In order to solve the question b):

We have the following reaction occuring:

[tex]2Al+6HCl\rightarrow2AlCl_3+3H_2[/tex]

We need to calculate the number of moles of aluminum needed to produce 30ml of H2 (hydrogen gas) at a temperature of 22°C and a pressure of 763mmHg.

To calculate the number of moles of hydrogen produced we use the ideal gas equation:

[tex]P.V=n.R.T[/tex]

Where:

P is the pressure

V is the volume

n is the number of moles

R is the gas constant

T is the temperature

R is a constant and it's value is:

[tex]R=8.314\text{ }\frac{m^3.Pa}{K.mol}[/tex]

So we need to convert each variable to the units of this constant.

[tex]\begin{gathered} T:\text{ }22^{\circ}C=295.15^{\circ}K \\ P:\text{ }763mmHg=101725\text{ }Pa \\ V:\text{ 30ml}:0.00003m^3 \end{gathered}[/tex]

So now we calculate:

[tex]n=\frac{P.V}{R.T}=\frac{101725Pa.0.00003m^3}{8.314\frac{m^3.Pa}{K.mol}.295.15^{\circ}C}=0.00124mol[/tex]

So we know that 0.00124 moles of H2 are formed.

Now we know that for every 2 moles of aluminum 3 moles of H2 are formed.

So we calculate the moles of Al needed:

[tex]n_{Al}=0.00124mol_{H2}.\frac{2mol_{Al}}{3mol_{H2}}=0.000826mol_{Al}[/tex]

So the answer is 0.000826 moles of Al°

What is a molecular equation and how do I do that

Answers

option A is  is a true molecular equation depicted.

Na2S+2HCl→2NaCl+H2S↑

A molecular equation is a balanced chemical equation in which the constituent ions of the ionic compounds are represented as molecules. Each of a compound's constituent components and the amount of atoms they each possess are listed in the molecular formula. Similar rules apply to the most basic formula: all the constituents are mentioned, but the numbers represent their relative proportions.

There are three different types of equations that may be developed for a reaction involving ionic compounds: molecular equations, full ionic equations, and net ionic equations. In chemistry, each of these equations has a specific function. Because it details exactly which compounds were employed in a process, a molecular equation is useful.

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Balance the following chemical equation using algebraic method ( A value is 2 ) ( please include procedure ) Sn (NO2)4 + Pt3N4 = Sn3N4 + Pt(NO2)4

Answers

Answer: 3Sn (NO2)4 + Pt3N4 → Sn3N4 + 3Pt(NO2)4

Given the equation:

• Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4

(1) The first thing we noticed is that this is a double replacement equation

• ,Sn combines with N4 to form Sn3N4, (,take note that Sn→ Sn3,)

• Pt3 combines with (NO2) to form Pt(NO2)4 ( ,take note that Pt3 → Pt)

(2) Balancing the equation

• Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4 ....(,place 3 infront of Sn in the reactant side .)

• 3,Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4...( ,then place 3 infront of Pt in the product side,)

,

• 3,Sn (NO2)4 + Pt3N4 → Sn3N4 + ,3,Pt(NO2)4

Check :

3Sn reactant : Sn3 Product

(NO2)4 reactant : (NO2)4 product

Pt3 reactant : 3Pt product

N4 reactant : N4 product

RHS = LHS ,this means that our equation has now balance.

during the decomposition of 34 gr ammonia into nitrogen and hydrogen 92 KJ are absorbed. How many grams of ammonia are decomposed when 184 KJ are absorbed? write the decomposition reaction

Answers

Explanation:

Ammonia will decompose into nitrogen gas and hydrogen gas according to the following reaction. In that reaction 92 kJ will be absorbed.

2 NH₃ ----> N₂ + 3 H₂ ΔH = 92 kJ

Since the heat is absorbed, the sign is positive and we can add it to the reactants side.

2 NH₃ + 92 kJ ----> N₂ + 3 H₂

When 92 kJ are absorbed 34 g of ammonia are reacted. We can use that relationship to find the mass of ammonia that reacted when 184 kJ where absorbed.

34 g of NH₃ : 92 kJ

mass of NH₃ = 184 kJ * 34 g of NH₃/(92 kJ)

mass of NH₃ = 68 g

Answer: 68 g of ammonia were decomposed.

2 NH₃ ----> N₂ + 3 H₂ ΔH = 92 kJ

what is the % concentration by mass of 3.5 g of NaCl dissolved in 100.0 grams of water

Answers

Step 1 - Understanding % concentration in mass

% concentration in mass expresses the concentration of a solute by its percentage, in mass, in relation to the total mass of the solution.

Mathematically, we can find this percentage by the following relation:

[tex]\text{ \%concentration = }\frac{m_{solute}}{m_{solution}}\times100[/tex]

Step 2 - Caculating the % concentration for the given solution

According to the exercise:

[tex]\begin{gathered} m_{solute}=3.5g\text{ \lparen NaCl is the solute\rparen} \\ \\ m_{solution}=100+3.5=103.5 \end{gathered}[/tex]

Setting these values in the equation:

[tex]\text{ \%concentration = }\frac{3.5}{103.5}\times100=3.38\text{ \%}[/tex]

Answer: the % concentration of NaCl in this solution is 3.38%.

How do you figure this question out in CHEM 101?What is the mass in grams are in 5.32x10^22 molecules of CO2?

Answers

To answer this question, the first step is to convert the given number of molecules to moles using Avogadro's number:

[tex]5.32\times10^{22}molecules\cdot\frac{1molCO_2}{6.022\times10^{23}molecules}=0.088molCO_2[/tex]

Now, use the molecular weight of CO2 to find the mass of this amount of moles:

[tex]0.088molCO_2\cdot\frac{44g}{molCO_2}=3.872g[/tex]

The mass of 5.32x10^22 molecules of CO2 is 3.872g.

The police found 488.43 grams of chlorate of
potassium (KCIO) in the room. To kill someone with the
mixture, 420.45g of potassium chloride would be required.
Is there enough potassium chloride to
that Melanie killed the butler?
KCIO3 > KCI + O2?

Answers

The formed amount of KCl from the reaction is 297.12 g which is not enough to kill someone.

What is the limiting reagent?

A limiting reagent can be defined as a reactant that is exhausted completely from the mixture at the completion of a chemical reaction.

When quantities of reactant are not taken in stoichiometry, the limiting reactants in the chemical reaction will decide the maximum amount of product.

Given, a balanced equation of the decomposition of KClO₃ is:

[tex]KClO_3\longrightarrow KCl +O_2[/tex]

One mole of KClO₃ will produce one mole of KCl.

122.55 g of the KClO₃ will produce KCl = 74.55 g

Given, the amount of KClO₃ = 488.43 g

Then 488.43 g of KClO₃ will produce KCl  = (74.55/122.55) × 488.43

                                                                      = 297.12 grams

As given 420.45g of potassium chloride would be required to kill someone. Therefore,  there is not enough potassium chloride that Melanie killed the butler.

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In the equation:2H2 + O2 → 2H2O100 molecules of hydrogen react with ........... molecules of oxygen.

Answers

Answer:

[tex]50\text{ molecules}[/tex]

Explanation:

Here, we want to know the number of molecules of oxygen that was reacted with

From the question, we can see that the mole ratio is 2 to 1

Thus, the number of molecules of oxygen reacted will be half that of hydrogen

Hence, the number of molecules of oxygen will be:

[tex]\rightarrow\frac{100}{2}\text{ = 50 molecules}[/tex]

Which element has 6-p electrons?

halogens


noble gases


alkali metals


alkaline earth metals

Answers

alkali metals has 6-p electrons

what are the properties of alkali metals ?

The alkali metals are elements of group 1 elements which are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).,

These elements are s-block elements because they have their outermost electron in an s-orbital.

The alkali metals are soft, shiny and highly reactive and  lose their outermost electron to create cations with charge +1, it can tarnish rapidly in the air due to oxidation by atmospheric moisture and oxygen.

Alkali metals are good conductors of heat and electricity, these elements are  specific, They are soft and can be cut by knife.

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Do neutrons have postive,negative, or neutral charge ?

Answers

Answer:

Balls uhhh neutron but if theres a better answer take it cuz im prolly wrong

Explanation:

50/50 im right up to you to take the chance or jus search it on tha goog

neutrons have a neutral charge, protons have a positive charge and electrons have a negative charge

most of the elements that make good insulators are located at the _____ of the periodic table?A. Top B. right C. left D. bottom

Answers

So,

The elements that belong to group 18 of the modern periodic table can be considered as some of the best electric insulators since they all contain completely filled valence shells and are, therefore, stable.

In general, elements that make good insulators are nonmetals, and these are located at the right of the periodic table. Thus the correct answer is B.

What is the pH of a Strong Acid solution whose concentration is 10-7M?

Answers

Answer

pH = 6

Explanation

Given that:

The concentration of the acid [H⁺] = 10⁻⁷ M

What to find:

The pH of the strong acid solution.

Step-by-step solution:

The pH of the strong acid solution whose concentration is 10⁻⁷ M can be calculated using the pH formula.

The pH formula is given by: pH = -log[H⁺]

Substitute [H⁺] as 10⁻⁷ M, we have:

pH = - log(10⁻⁷)

pH = -(-6)

pH = 6

The pH of the strong acid solution whose concentration is 10⁻⁷ M is 6.

3. Do the changes that you observed in the relative solubilities of NaCl agree with their Solubility Curves ? Explain your answer .

Answers

6. As we can see from the graph, if we have only 100 grams of water, at 30°C, we will have 10 grams of KClO3 being dissolved in water, therefore if we have 300 grams of H2O, we will have 30 grams of KClO3 being dissolved at 30°C

7. The least soluble substance will be the one that shows up first in the temperature "line", if you follow the temperature up, the first solute that is listed will be considered to least soluble, therefore the least one will be KClO3

How many grams of glucose are required to heat 175 mL of water from 20.0 °C to 25.0°C?

Answers

We must first determine the heat needed to heat 175mL of water. In the working temperature range we can assume that the density of water is 1g/mL, so the mass of water that we must heat will be 175g of water.

Now, the heat we need to heat that mass of water is calculated with the following equation:

[tex]Q=mCp\Delta T[/tex]

Where Q is the heat required to heat the water

Cp is the specific heat of water equal to 4186 J/g°C

delta T is the change of temperature = 25°C-20°C=5°C

We replace the know values:

[tex]Q=175g\times4186\frac{J}{g\degree C}\times\frac{1kJ}{1000J}\times5\degree C=3662.75kJ[/tex]

Now, to heat the water they tell us that the glucose combustion will take place. We must assume that all the heat generated in the reaction will go to heating the water and that there is no heat loss to the environment.

The combustion reaction of glucose generates 2538.7 kJ/mol. So the moles of glucose needed will be:

[tex]\begin{gathered} molGlucose=givenHeatrequired\times\frac{1molGlucose}{2538.7kJ} \\ molGlucose=3662.75kJ\times\frac{1molGlucose}{2,538.7kJ}=1.44molGlucose \end{gathered}[/tex]

We calculate the grams of glucose by multiplying the moles by the molar mass of glucose equal to 180.2g/mol

grams of glucose= 1.44 mol x 180.2 g/mol=260g

Answer: To heat 175 mL of water from 20.0 °C to 25.0°C are required 260g of glucose

Which types of electron orbitals will have higher energy than a 4d orbital?A. 4pB. 3sC. 4fD. 5s

Answers

Answer:

5s. Option D is correct

Explanations:What are electron orbitals?

Electron orbitals are area around the nucleus where electron resides. The closer the orbital to the nucleus, the higher the energy level.

Based on the explanation above, 5s will be higher in energy than the 4d orbital.

A sample of helium gas initially at 0.90 atm is cooled from 18 degreeC to -48 degreeC at constant volume. What is the final pressure?

Answers

Answer: By using Ideal gas law  PV=nRT  ,the final pressure is calculated

Explanation:

In thermodynamics a constant volume process is known as isochoric process and in this volume remains constant and pressure varies along with the temperature .

FORMULA USED - PV=nRT

If Volume is constant ,then  initial Temperature  = 18+273 = 291K

final temperature =225K

initial pressure = 0.90 atm

final pressure = ?

The final pressure comes out to be 0.6958 atm.

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convert 123 joules to k cal

Answers

Answer:

0.029397 kCal

Explanations:

According to the question, we are to convert Joules to kCal

Using the conversion factor:

1 Joule = 0.000239 Kcal

Next is to convert 123 Joules to kCal

To do that, we will multiply 123 Joules with the factor as 0.000239

123 Joules = (0.000239 * 123) kcal

123 Joules = 0.029397 kCal

Hence the value of 123 joules is equal to 0.029397 kCal

pls help meHow many liters of NH3 are needed to react completely with 30.0 L of NO (at STP)?4NH3 (g)+ 6NO(g) 5N2(g)+ 6H2o(g)a.5.0 Lc.7.5 Lb.20.0 Ld.120.0 L

Answers

Answer:

[tex]20.0\text{ L}[/tex]

Explanation:

Here, we want to get the volume of NH3 that will react with 30L of NO at STP

From the question, we have it that 4 moles of ammonia reacted 6 moles of NO

Thus, we have the mole ratio as 6 to 4

Thus, the volume of ammonia reacted would be:

[tex]\frac{4}{6}\times30\text{ = 20.0 L}[/tex]

% w/v relates which two units?A.grams and molesB.grams and millilitersC.moles and litersD.temperature and volumeE.milliliters and moles

Answers

Explanation:

The % w/v s the number of grams of solute in 100 mL of solution

So it relates grams of solute with mL of solution.

Answer: B. grams and milliliters

Calculate ∆G° for each reaction using ∆Gf° values: (a) 2Mg(s) + O2(g) → 2MgO(s)

Answers

The free energy of formation of the MgO is −597 kJ/mol.

What is the standard free energy of formation?

We know that the free energy of formation is defined as the energy that is evolved or absorbed when a substance is formed from its components under standard conditions. In this case, we have that the magnesium and the oxygen are all pure substances.

It is important that we recall that the free energy of formation of a pure substance is zero. We have the free energy  of formation of the magnesium oxide as−597 kJ/mol.

Hence;

Sum of free energy of formation of products - Sum of free energy  of formation of reactants

We have;

(−597 kJ/mol) - (0  kJ/mol)

free energy of formation = −597 kJ/mol

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Finish balancing:__al + 3zn(no3)2 -> __al(no3)3 +__znWhat coefficient does al(no3)3 have in the balanced equation?

Answers

In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient. In the reaction from the question we can properly balance by adding the following stoichiometric coefficients

For our question, we have:

2 Al + 3 Zn(NO3)3 -> 2 Al(NO3)3 + 3 Zn

Now this reaction is properly balanced

Al(NO3)3 has the coefficient 2

could you calculate the percent composition for 15 and the empirical formal for 16

Answers

To solve this question, we need to know the molar mass of Ca. It is 40 g/mol

There are 3 atoms of Ca in Ca3(PO4)2

So the mass of Ca in Ca3(PO4)2 is 3x40 = 120 g

So:

375 grams ---- 100%

120 g --- x

x = 32%

Answer: 32% of calcium.

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Can you please help me out with a question how much iodine (I2) in moles, should be added to water to produce 2.5L of solution with a molarity of 0.6M? ginny is raising pumpkins to enter a contest to see who can grow the heaviest pumpkin. her best pumpkin weighs 22 pounds and is growing at the rate of 2.5 pounds per week. martha planted her pumpkins late. her best pumpkin weighs 10 pounds but she expects it grow 4 pounds per week. define the "let" statements for x and y. then write equations that represent the weight of ginny and martha's pumpkins.Let x=Let y=ginny's equations=Martha's equation: (a) By how many percent is the torque of a motor decreased if its permanent magnets lose 3.9% of their strength? %(b) How many percent would the current need to be increased to return the torque to original values? % Represent the given condition using a single variable , x Please help us in figuring out this math problem so that we can move onto the next one thank you very much 2.3= p + 0.6What does p equal? Choose the right interjections and write in the blank spaces.a............ ! The poor man has died. (Alas, Pooh) !b............. I have passed (Oh, Hurrah) c...............! He is so cruel. (Alas, Pooh) d. ............ ! Well played. (Oh, Bravo)e............ ! Don't make a noise. (Oh, Hush) ! f.................How are you? (Hello, Oh)g. ..............! You live in a lovely place. (Aha, Alas) the Firgure shows two triangles on a coordinate grid: Which set of transformations have been performed on triangle ABC to form triangle A'B'C'? A) Dilation by a scale factor of 1/3 followed by reflection about the x-axisB) Dilation by a scale factor of 3 followed by reflection about the x-axis C) Dilation by a scale factor of 1/3 followed by reflection about the y-axis D) Dilation by a scale factor of 3 followed by reflection about the y-axis The information below shows the different genotypes that were observed during the meiosis simulation and the number of copies of each genotype that were present at the end of all rounds of meiosis. Use this info to answer the below question: EAD- 6EaD- 19Ead- 25eAD-25eAd- 19ead-6 Which genotype that were observed in one or more daughter cells was also present in the parental cell? Which were ONLY in the daughter cell? Which were ONLY in the parental cell? the drop down menu is the same on both sides What is a helicapterHi I keep getting a step wrong because Im getting a radio that isnt on here.. 30 points helps What are the coordinates of each vertex if the figure is rotated 180 clockwise about the origin?[G.CO.2, G.CO.4, G.C0.5] The following is a sample of 20 measurements.Answer b part Devonte creates a scatter plot of the relationship between his hourly pay in dollars, y, and the number of customers he serves at a coffee shop, X. He calculates the equation of the trend line to be y = 2.52 +7. Part A What does the y-intercept represent? Enter the correct answers in the boxes. per hour when he serves customers. The y-intercept represents that Devonte earns $ Which of the following is an Autotroph?A. TigerB. Primary consumerC. OaktreeD. Decomposer Will a truck that is 14 feet wide carrying a load that reaches 12 feet above the ground clear the semielliptical arch on the one-way road that passes under the bridge shown in the figure on the right? Error Analysis Denzel identified (3, 2) as a point on the line y - 2 = 2/3 (x + 3). What is the error that Denzel made? The vivandire sold viands and sandwiches. If she sold 300 total and 50 more viands than sandwiches, how many of each did she sell?