How many grams of H3PO4 could be produced from 94 g of H2O and 186 g of PCL5 according to the equation below?

How Many Grams Of H3PO4 Could Be Produced From 94 G Of H2O And 186 G Of PCL5 According To The Equation

Answers

Answer 1

Answer:

[tex]89.4\text{ g of H}_3PO_4[/tex]

Explanation:

Here, we want to get the mass of H3PO4 produced

We start by getting the balanced equation of reaction:

[tex]PCl_5\text{ + 4H}_2O\text{ }\rightarrow\text{ 5HCl + H}_3PO_4[/tex]

The mass of H3PO4 produced would be based on the limiting reactant

The limiting reactant here is the one that would produce less amount of the product H3PO4

Firstly, let us get the number of moles of H3PO4 produced by each of the reactants

To get this, we start by getting the number of moles of each that reacted

We get this by dividing the masses by the molar masses

For water, we have it that the molar mass is 18 g/mol

Thus, the number of moles would be:

[tex]\frac{94}{18}\text{ = 5.2 moles}[/tex]

From the balanced equation of reaction:

4 moles of water produced 1 mole of H3PO4

5.2 moles of water will produce x moles of H3PO4

Thus:

[tex]\begin{gathered} x\text{ }\times4\text{ = 5.2}\times1 \\ x\text{ = }\frac{5.2}{4}\text{ = 1.3 mole} \end{gathered}[/tex]

For PCl5

The molar mass is 208 g/mol

Thus,we have the number of moles as:

[tex]\frac{186}{208}\text{ = 0.894 mol}[/tex]

From the equation of reaction:

1 mol of PCl5 produced 1 mol of H3PO4

That means 0.894 mol of PCl5 produced 0.894 mol of H3PO4

Since PCl5 produced a lesser amount of moles of water, that means, it is the limiting reactant

To get the mass of H3PO4 produced, we multiply this number of moles by

the molar mass of H3PO4

The molar mass of H3PO4 is 100 g/mol

Thus, we have the mass of H3PO4 produced as:

[tex]0.894\text{ }\times\text{ 100 = 89.4 g}[/tex]


Related Questions

convert 123 joules to k cal

Answers

Answer:

0.029397 kCal

Explanations:

According to the question, we are to convert Joules to kCal

Using the conversion factor:

1 Joule = 0.000239 Kcal

Next is to convert 123 Joules to kCal

To do that, we will multiply 123 Joules with the factor as 0.000239

123 Joules = (0.000239 * 123) kcal

123 Joules = 0.029397 kCal

Hence the value of 123 joules is equal to 0.029397 kCal

Which element has 6-p electrons?

halogens


noble gases


alkali metals


alkaline earth metals

Answers

alkali metals has 6-p electrons

what are the properties of alkali metals ?

The alkali metals are elements of group 1 elements which are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).,

These elements are s-block elements because they have their outermost electron in an s-orbital.

The alkali metals are soft, shiny and highly reactive and  lose their outermost electron to create cations with charge +1, it can tarnish rapidly in the air due to oxidation by atmospheric moisture and oxygen.

Alkali metals are good conductors of heat and electricity, these elements are  specific, They are soft and can be cut by knife.

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9. Calculate the molarity of a 400.0 mL solution that contains 41.5 g of NaCl.

Answers

Answer

1.775 M

Explanation

Given:

Volume of solution, V = 400.0 mL

Mass of NaCl = 45.5 g

What to find:

The molarity of the solution.

Step-by-step solution:

Step 1: Convert the volume from mL to L.

This can be done by dividing the volume in mL by 1000.

V = 400.0 mL = (400.0/1000) = 0.4L

Step 2: Convert the mass of NaCl to moles.

The mass can be converted to moles using the mole formula below:

[tex]\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \end{gathered}[/tex]

From the periodic table, the molar mass is determined to be = 58.44 g/mol

Putting mass = 41.5 g and molar mass = 58.44 g/mol into the formula, we have:

[tex]Moles=\frac{41.5g}{58.44g\text{/}mol}=0.7101\text{ }mol[/tex]

Step 3: Calculate the molarity of the solution using the molarity formula.

Molarity formula is given by:

[tex]Molarity=\frac{Moles}{Volume\text{ }in\text{ }L}[/tex]

Moles= 0.7101 mol and V = 0.4 L

Therefore,

[tex]Molarity=\frac{0.7101mol}{0.4L}=1.775\text{ }M[/tex]

The molarity of a 400.0 mL solution that contains 41.5 g of NaCl = 1.775 M.

2. Complete and correctly balance each of the following reactions: 5 pts(a) Double replacement: Ba Cl2 (aq) + AgNO3 (aq)-(b) Decomposition: HgO (s)(c) Combustion: C4H10 (9) + O2 (9)-(d) Single replacement: Ca (s) + AlCl3 (s)(e) Combination: Mg(s) + N2 (9)-

Answers

2. (a) We are told that it is a double displacement reaction, so there will be two substitutions and Cl will exchange places with NO3.

Now, that will be the full reaction but we need to balance it. Count the atoms of each element on each side of the reaction. In the figure we can see that Chlorine, Nitrogen and Oxygen are not balanced.

We place the coefficient 2 in front of the AgCl molecule to balance the chlorides. You can see the picture.

Now we will balance the nitrogens. There are two nitrogens in the products. We place the coefficient two in the AgNO3 molecule. In the figure I will make the update.

Now the equation is balanced, so the balanced reaction will be:

[tex]BaCl_{2(aq)}+2AgNO_{3\left(aq\right)}+\rightarrow Ba\left(NO_3\right)_{2\left(aq\right)}+2AgCl(s)[/tex]

Finish balancing:__al + 3zn(no3)2 -> __al(no3)3 +__znWhat coefficient does al(no3)3 have in the balanced equation?

Answers

In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient. In the reaction from the question we can properly balance by adding the following stoichiometric coefficients

For our question, we have:

2 Al + 3 Zn(NO3)3 -> 2 Al(NO3)3 + 3 Zn

Now this reaction is properly balanced

Al(NO3)3 has the coefficient 2

% w/v relates which two units?A.grams and molesB.grams and millilitersC.moles and litersD.temperature and volumeE.milliliters and moles

Answers

Explanation:

The % w/v s the number of grams of solute in 100 mL of solution

So it relates grams of solute with mL of solution.

Answer: B. grams and milliliters

Balance the following chemical equation using algebraic method ( A value is 2 ) ( please include procedure ) Sn (NO2)4 + Pt3N4 = Sn3N4 + Pt(NO2)4

Answers

Answer: 3Sn (NO2)4 + Pt3N4 → Sn3N4 + 3Pt(NO2)4

Given the equation:

• Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4

(1) The first thing we noticed is that this is a double replacement equation

• ,Sn combines with N4 to form Sn3N4, (,take note that Sn→ Sn3,)

• Pt3 combines with (NO2) to form Pt(NO2)4 ( ,take note that Pt3 → Pt)

(2) Balancing the equation

• Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4 ....(,place 3 infront of Sn in the reactant side .)

• 3,Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4...( ,then place 3 infront of Pt in the product side,)

,

• 3,Sn (NO2)4 + Pt3N4 → Sn3N4 + ,3,Pt(NO2)4

Check :

3Sn reactant : Sn3 Product

(NO2)4 reactant : (NO2)4 product

Pt3 reactant : 3Pt product

N4 reactant : N4 product

RHS = LHS ,this means that our equation has now balance.

Which of the following is a conclusion that the student can draw based on these observations? The two clear liquids-

Answers

In the process that they describe to us, a mixture initially occurs between these two liquids, when they are mixed, a chemical reaction occurs and one of the products obtained is not soluble in the liquids, therefore a precipitate will form. This type of reaction is called a precipitation reaction.

Therefore, the answer will be:

C) Have gone through a chemical reaction in which a new substance called a precipitate was produced

what would be the effect on the melting point of a sample if it were not dried completely after filtering the recrystallized sample?

Answers

It can lower and expand the melting point if the sample is not dried completely.

Impurities may be present in a sample if the drying process is not complete. The melting point is decreased and widened when contaminants are still present in a sample. For instance, if a substance's usual melting point range is 104C to 106C, improper drying could result in the presence of impurities, which would lower and widen the melting point range to something like 85C to 97C.

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What is a molecular equation and how do I do that

Answers

option A is  is a true molecular equation depicted.

Na2S+2HCl→2NaCl+H2S↑

A molecular equation is a balanced chemical equation in which the constituent ions of the ionic compounds are represented as molecules. Each of a compound's constituent components and the amount of atoms they each possess are listed in the molecular formula. Similar rules apply to the most basic formula: all the constituents are mentioned, but the numbers represent their relative proportions.

There are three different types of equations that may be developed for a reaction involving ionic compounds: molecular equations, full ionic equations, and net ionic equations. In chemistry, each of these equations has a specific function. Because it details exactly which compounds were employed in a process, a molecular equation is useful.

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Which types of electron orbitals will have higher energy than a 4d orbital?A. 4pB. 3sC. 4fD. 5s

Answers

Answer:

5s. Option D is correct

Explanations:What are electron orbitals?

Electron orbitals are area around the nucleus where electron resides. The closer the orbital to the nucleus, the higher the energy level.

Based on the explanation above, 5s will be higher in energy than the 4d orbital.

Do neutrons have postive,negative, or neutral charge ?

Answers

Answer:

Balls uhhh neutron but if theres a better answer take it cuz im prolly wrong

Explanation:

50/50 im right up to you to take the chance or jus search it on tha goog

neutrons have a neutral charge, protons have a positive charge and electrons have a negative charge

How many grams are in 4.02 x 10^21 atoms of calcium?

Answers

Answer:

0.268grams

Explanations:

According to the Avogadro's constant

1 mole of an atom = 6.02 * 10^23 molecules

Given the following

atoms of calcium = 4.02 x 10^21 atoms

Determine the moles of calcium

[tex]\begin{gathered} moles\text{ of Ca}=\frac{4.02\times10^{21}}{6.02\times10^{23}} \\ moles\text{ of Ca}=0.668\times10^{21-23} \\ moles\text{ }of\text{ Ca}=0.668\times10^{-2} \\ moles\text{ of Ca}=0.00688moles \end{gathered}[/tex]

Determine the mass of Calcium

[tex]\begin{gathered} Mass=mole\times molar\text{ mass} \\ Mass=0.00688\times40.078 \\ Mass\text{ of Ca}=0.268gram \end{gathered}[/tex]

Hence the required grams in 4.02 x 10^21 atoms of calcium is 0.268grams

What is the pH of a Strong Acid solution whose concentration is 10-7M?

Answers

Answer

pH = 6

Explanation

Given that:

The concentration of the acid [H⁺] = 10⁻⁷ M

What to find:

The pH of the strong acid solution.

Step-by-step solution:

The pH of the strong acid solution whose concentration is 10⁻⁷ M can be calculated using the pH formula.

The pH formula is given by: pH = -log[H⁺]

Substitute [H⁺] as 10⁻⁷ M, we have:

pH = - log(10⁻⁷)

pH = -(-6)

pH = 6

The pH of the strong acid solution whose concentration is 10⁻⁷ M is 6.

If compound has molecular weight of 114.22g/mole and its empirical formula is C4H9 FIND its molecular formulaa. C12 H27b) C16 H36c) C8 H18d) C4 H9

Answers

Answer

c) CH₁

Explanation

Given that:

A compound has a molecular weight of 114.22 g/mol

The empirical formula for the compound is C₄H₉

What to find:

To determine the molecular formula for the compound.

Step-by-step solution:

(Empirica formula)n = (Molecular weight)

(C₄H₉)n = 114.22

(4 x 12.01 + 9 x 1.01)n = 114.22

(48.04 + 9.09)n = 114.22

57.13n = 114.22

Divide both sides by 57.13

n = 114.22/57.13

n = 2

Therefore, the molecular formula for the compound is (C₄H₉)₂ = CH₁

The correct answer is option c) CH₁

A sample of helium gas initially at 0.90 atm is cooled from 18 degreeC to -48 degreeC at constant volume. What is the final pressure?

Answers

Answer: By using Ideal gas law  PV=nRT  ,the final pressure is calculated

Explanation:

In thermodynamics a constant volume process is known as isochoric process and in this volume remains constant and pressure varies along with the temperature .

FORMULA USED - PV=nRT

If Volume is constant ,then  initial Temperature  = 18+273 = 291K

final temperature =225K

initial pressure = 0.90 atm

final pressure = ?

The final pressure comes out to be 0.6958 atm.

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pls help meHow many liters of NH3 are needed to react completely with 30.0 L of NO (at STP)?4NH3 (g)+ 6NO(g) 5N2(g)+ 6H2o(g)a.5.0 Lc.7.5 Lb.20.0 Ld.120.0 L

Answers

Answer:

[tex]20.0\text{ L}[/tex]

Explanation:

Here, we want to get the volume of NH3 that will react with 30L of NO at STP

From the question, we have it that 4 moles of ammonia reacted 6 moles of NO

Thus, we have the mole ratio as 6 to 4

Thus, the volume of ammonia reacted would be:

[tex]\frac{4}{6}\times30\text{ = 20.0 L}[/tex]

could you calculate the percent composition for 15 and the empirical formal for 16

Answers

To solve this question, we need to know the molar mass of Ca. It is 40 g/mol

There are 3 atoms of Ca in Ca3(PO4)2

So the mass of Ca in Ca3(PO4)2 is 3x40 = 120 g

So:

375 grams ---- 100%

120 g --- x

x = 32%

Answer: 32% of calcium.

what is the % concentration by mass of 3.5 g of NaCl dissolved in 100.0 grams of water

Answers

Step 1 - Understanding % concentration in mass

% concentration in mass expresses the concentration of a solute by its percentage, in mass, in relation to the total mass of the solution.

Mathematically, we can find this percentage by the following relation:

[tex]\text{ \%concentration = }\frac{m_{solute}}{m_{solution}}\times100[/tex]

Step 2 - Caculating the % concentration for the given solution

According to the exercise:

[tex]\begin{gathered} m_{solute}=3.5g\text{ \lparen NaCl is the solute\rparen} \\ \\ m_{solution}=100+3.5=103.5 \end{gathered}[/tex]

Setting these values in the equation:

[tex]\text{ \%concentration = }\frac{3.5}{103.5}\times100=3.38\text{ \%}[/tex]

Answer: the % concentration of NaCl in this solution is 3.38%.

1. A 26.6g sample of mercury is heated to 110.0℃ and then placed in 125g of water in a coffee-cupcalorimeter. The initial temperature of the water is 23.00℃. (c Hg = 0.139 J/g℃). What is the finaltemperature of the water and the mercury? 2. Draw the Lewis bonding structure for PCl3. what would be the hybrid orbitals

Answers

The Lewis structure tells us how atoms are bonded and shows the valence electrons of each element as dots. These valence electrons can be found in the periodic table of the elements, and they coincide with the group number to which the element belongs.

So phosphorus (P) belongs to group 5 and has 5 valence electrons. Chlorine (Cl) is in group 7 and has 7 valence electrons.

The Lewis scheme will be:

The blue dots correspond to the valence electrons of phosphorus, and the purple dots are the electrons of chlorine. The electrons they share can be written with a line.

We have that the geometry of the molecule will be:

Four sp3 type hybrid orbitals are formed, three of which overlap with each of the Cl atoms and the other houses the lone electrons. Sigma type bonds.

Answer: 4 sp3 hybrid orbitals

Calculate ∆G° for each reaction using ∆Gf° values: (a) 2Mg(s) + O2(g) → 2MgO(s)

Answers

The free energy of formation of the MgO is −597 kJ/mol.

What is the standard free energy of formation?

We know that the free energy of formation is defined as the energy that is evolved or absorbed when a substance is formed from its components under standard conditions. In this case, we have that the magnesium and the oxygen are all pure substances.

It is important that we recall that the free energy of formation of a pure substance is zero. We have the free energy  of formation of the magnesium oxide as−597 kJ/mol.

Hence;

Sum of free energy of formation of products - Sum of free energy  of formation of reactants

We have;

(−597 kJ/mol) - (0  kJ/mol)

free energy of formation = −597 kJ/mol

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Calculate the pOH for an aqueous solution containing 0.01 moles of HCl in a 2.5 L solution.

Answers

The question requires us to calculate the pOH value for a solution containing 0.01 moles of HCl in 2.5 L of solution.

To solve this problem, we'll need to go through the following steps:

I) calculate the molar concentration of the HCl solution to obtaine the concentration of H+ ions;

II) using the concentration of H+ ions, calculate the pH of the solution;

III) with the value obtained for pH, calculate the value of pOH for this solution.

Next, we'll go through the steps to solve the question:

I) Since the question provided the number of moles of HCl and the volume of the solution, we can calculate the molar concentration using the following equation:

[tex]\text{molar concentration = }\frac{\text{number of moles (mol)}}{\text{volume (L)}}_{}[/tex]

Thus, applying the values provided:

[tex]\text{molar concentration of HCl= }\frac{0.01\text{ mol}}{2.5\text{ L}}=0.004\text{ mol/L}[/tex]

Therefore, the concentration of the HCl solution is 0.004 mol/L.

Since HCl is a strong acid, we can expect it to completely dissociate in H+ and Cl-: the concentration of H+ ions for this solution would also be 0.004 mol/L ( [H+] = 0.004 mol/L).

III) The next step is calculate the pH of this solution. We'll use the following equation and apply the concentration of H+ ions obtained in the previous step ( [) using H+] = 0.004 mol/L):

[tex]pH=-\log _{10}\lbrack H^+\rbrack\to pH=-\log _{10}(0.004)=2.39[/tex]

Now, we know that the pH of the solution is 2.39.

III) The last step is use the pH value calculated (pH = 2.39) to calculate the pOH of the solution, using the following equation:

[tex]pH+\text{pOH =14}\to pOH\text{ = 14 - pH}[/tex][tex]\text{pOH = 14-2.39 = 11.6}[/tex]

Therefore, the pOH of the HCl solution given is 11.6.

during the decomposition of 34 gr ammonia into nitrogen and hydrogen 92 KJ are absorbed. How many grams of ammonia are decomposed when 184 KJ are absorbed? write the decomposition reaction

Answers

Explanation:

Ammonia will decompose into nitrogen gas and hydrogen gas according to the following reaction. In that reaction 92 kJ will be absorbed.

2 NH₃ ----> N₂ + 3 H₂ ΔH = 92 kJ

Since the heat is absorbed, the sign is positive and we can add it to the reactants side.

2 NH₃ + 92 kJ ----> N₂ + 3 H₂

When 92 kJ are absorbed 34 g of ammonia are reacted. We can use that relationship to find the mass of ammonia that reacted when 184 kJ where absorbed.

34 g of NH₃ : 92 kJ

mass of NH₃ = 184 kJ * 34 g of NH₃/(92 kJ)

mass of NH₃ = 68 g

Answer: 68 g of ammonia were decomposed.

2 NH₃ ----> N₂ + 3 H₂ ΔH = 92 kJ

3. Do the changes that you observed in the relative solubilities of NaCl agree with their Solubility Curves ? Explain your answer .

Answers

6. As we can see from the graph, if we have only 100 grams of water, at 30°C, we will have 10 grams of KClO3 being dissolved in water, therefore if we have 300 grams of H2O, we will have 30 grams of KClO3 being dissolved at 30°C

7. The least soluble substance will be the one that shows up first in the temperature "line", if you follow the temperature up, the first solute that is listed will be considered to least soluble, therefore the least one will be KClO3

Please help with 2nd and 3rd questions In question b) Aluminum reacts with hydrocloric acid

Answers

In order to solve the question b):

We have the following reaction occuring:

[tex]2Al+6HCl\rightarrow2AlCl_3+3H_2[/tex]

We need to calculate the number of moles of aluminum needed to produce 30ml of H2 (hydrogen gas) at a temperature of 22°C and a pressure of 763mmHg.

To calculate the number of moles of hydrogen produced we use the ideal gas equation:

[tex]P.V=n.R.T[/tex]

Where:

P is the pressure

V is the volume

n is the number of moles

R is the gas constant

T is the temperature

R is a constant and it's value is:

[tex]R=8.314\text{ }\frac{m^3.Pa}{K.mol}[/tex]

So we need to convert each variable to the units of this constant.

[tex]\begin{gathered} T:\text{ }22^{\circ}C=295.15^{\circ}K \\ P:\text{ }763mmHg=101725\text{ }Pa \\ V:\text{ 30ml}:0.00003m^3 \end{gathered}[/tex]

So now we calculate:

[tex]n=\frac{P.V}{R.T}=\frac{101725Pa.0.00003m^3}{8.314\frac{m^3.Pa}{K.mol}.295.15^{\circ}C}=0.00124mol[/tex]

So we know that 0.00124 moles of H2 are formed.

Now we know that for every 2 moles of aluminum 3 moles of H2 are formed.

So we calculate the moles of Al needed:

[tex]n_{Al}=0.00124mol_{H2}.\frac{2mol_{Al}}{3mol_{H2}}=0.000826mol_{Al}[/tex]

So the answer is 0.000826 moles of Al°

How do you figure this question out in CHEM 101?What is the mass in grams are in 5.32x10^22 molecules of CO2?

Answers

To answer this question, the first step is to convert the given number of molecules to moles using Avogadro's number:

[tex]5.32\times10^{22}molecules\cdot\frac{1molCO_2}{6.022\times10^{23}molecules}=0.088molCO_2[/tex]

Now, use the molecular weight of CO2 to find the mass of this amount of moles:

[tex]0.088molCO_2\cdot\frac{44g}{molCO_2}=3.872g[/tex]

The mass of 5.32x10^22 molecules of CO2 is 3.872g.

How many grams of glucose are required to heat 175 mL of water from 20.0 °C to 25.0°C?

Answers

We must first determine the heat needed to heat 175mL of water. In the working temperature range we can assume that the density of water is 1g/mL, so the mass of water that we must heat will be 175g of water.

Now, the heat we need to heat that mass of water is calculated with the following equation:

[tex]Q=mCp\Delta T[/tex]

Where Q is the heat required to heat the water

Cp is the specific heat of water equal to 4186 J/g°C

delta T is the change of temperature = 25°C-20°C=5°C

We replace the know values:

[tex]Q=175g\times4186\frac{J}{g\degree C}\times\frac{1kJ}{1000J}\times5\degree C=3662.75kJ[/tex]

Now, to heat the water they tell us that the glucose combustion will take place. We must assume that all the heat generated in the reaction will go to heating the water and that there is no heat loss to the environment.

The combustion reaction of glucose generates 2538.7 kJ/mol. So the moles of glucose needed will be:

[tex]\begin{gathered} molGlucose=givenHeatrequired\times\frac{1molGlucose}{2538.7kJ} \\ molGlucose=3662.75kJ\times\frac{1molGlucose}{2,538.7kJ}=1.44molGlucose \end{gathered}[/tex]

We calculate the grams of glucose by multiplying the moles by the molar mass of glucose equal to 180.2g/mol

grams of glucose= 1.44 mol x 180.2 g/mol=260g

Answer: To heat 175 mL of water from 20.0 °C to 25.0°C are required 260g of glucose

Why is DNA describes as a blueprint for a cell?

Answers

DNA describes as a blueprint for a cell because it contain the instruction needed for an organism to grow develop and survive

DNA is called a blueprint of life because it contain the instruction needed for an organism to grow develop and survive and reproduce and DNA does this by controlling protein synthesis and protein do must of the work cell and are basic unit of structure and function in the cell of organism

DNA is read by the enzyme RNA polymerase and this enzyme attaches itself to the DNA strand slightly in front of a gene and it then slides along the DNA strand making a copy of the gene only using RNA building blocks instead of DNA building block

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Radioactive iodine (I-131) is an isotope of iodine that emits radiation and is used for various medical applications, such as in the treatment of thyroid cancer. The half-life for I-131 is 8 days. Based on the half-life of I-131, how many half-lives have to pass for a 200 mg sample of I-131 to decay down to 25 mg?

Answers

Half life is the time period in which half of the initial amount of an element will decay into a new element due to instability. For I-131, the half life is 8 days.

From 200 to 25 grams, let's see how many half lives are there:

200g -> 100g

100g -> 50g

50g -> 25g

Therefore for 200g of I-131 reach 25 grams, 3 half lives are necesseray, 3 half lives or 24 days

Neon (Z=10) has the minimum electron affinity in the 2nd period in the periodic tableIs it true or false? And why?

Answers

ANSWER

False

EXPLANATION

Electron affinity is defined as the energy released by adding an electron to an isolated gaseous atom

Neon has the electronic configuration of 2, 8, This implies that it belongs to period 2 and group 8

Recall, that Neon is a noble gas. Noble gases do not accept or release electrons.

Hence, neon does not have the tendency to accept or release electrons.

Neon as a noble gas has a large positive value for electron affinity

Therefore, the statement is not TRUE

Other Questions
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