Explain the melting of a solid in terms of molecules and energy
Heat generates energy when you melt a solid; as you heat up molecules, they move faster and begin to break apart into a liquid form.
What is the melting point?The melting point is the point at which a substance transforms from a solid to a liquid.
The melting point of a liquid is the temperature at which it transforms from a solid to a liquid at atmospheric pressure. This is the point where the liquid and solid phases are in balance.
Heat generates energy when you melt a solid; as you heat up molecules, they move faster and begin to break apart into a liquid form.
The kinetic energy of the molecule is due to the movement of the molecule as the temperature of the system increases the melting point comes closer.
As the temperature increases the kinetic energy of the molecule increases.
Hence the energy, melting point, and temperature relatively affect each other.
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Which of the following is a compound? A)oxygen B)water C)nitrogen D)hydrogen
Answer:
water
Explanation:
water is a compound
Why do some organisms never turn into fossils?
A. They are far too large to be buried in the ground.
B. They are made mostly of soft tissues.
C. They contain too much protein to be preserved.
D. They contain chemicals that prevent the hardening of their bodies.
Answer:
The answer is B.
Explanation:
Since they are made up of soft tissues, they decompose become they become fossils.
Sound travels Faster through _____________ mediums.
A) Denser
B) Less Dense
C) Colder
D) Sound always travels at the same period
Answer:
I know for sure that it's either A or B have a great day sorry I don't know which one completely
Use the scenario below for questions 4-7.
A rocket launched at a 60-degree angle has a launch velocity of
31.00 m/s.
4. What is the magnitude of the rocket's initial vertical velocity?
a. 10 m/s
b. 15.5 m/s
c. 26.85 m/s
d. 31 m/s
i need help in (a) and (c)
please at least try
I don't know please mark as brilliant
which of the following is an example of potential energy:
(choose 1)
- a printer that is not connected
- your cellphone, when you make a call to someone
Another example of an object that has pressure energy
Answer:
A balloon?
Explanation:
it inflates because of the air pressure inside
what determines the color of light?
1. wavelength
2. wave height
3. wave speed
4. wave amplitude
Answer:
wave length
Explanation:
The hot resistance of a 125V filament lamp is 500Ω. Determine the current taken by the lamp and its power rating.
Answer:
0.25 amps
Explanation:
V = IR
125 = I(500)
I = 0.25 amps
Use Gauss's Law to find the electric field produced by an infinite plane of uniformly distributed charge Q, with charge density σ. Draw the appropriate Gaussian Surface
Answer:
Explanation:
Consider an endless sheet of uniform charge thickness per unit area [tex]\sigma[/tex]
For a boundless sheet of charge, the electric field will be opposite to the surface. In this way, just the closures of a round and hollow Gaussian surface will add to the electric transition. For this situation, around and hollow Gaussian surface opposite to the charge sheet is utilized. The subsequent field is a large portion of that of a conductor at harmony with this surface charge thickness.
By balance, we expect the electric field on one or the other side of a plane to be an element of x just to be guided typical to the plane and to point away from/towards the plane contingent upon whether, [tex]\sigma[/tex] is positive/negative.
According to the law;
[tex]2EA = \dfrac{q_{enc}}{\varepsilon_o}[/tex]
[tex]where; \ q_{enc} = total \ enclosed charge = \sigma A \\ \\ thus; \\ \\ 2EA = \dfrac{\sigma A}{\varepsilon_o} \\ \\ E = \dfrac{\sigma}{2 \varepsilon _o}[/tex]
Please help ill give out brainliest?!!!
Help please!!! Physics circular motion
Answer:
2. 3.1415 m/s
3. 0.63m
4. 0.006 m/s^2
Explanation:
2. v=(2*pi*r))/T, put in values and solve.
3. Circumference=2*pi*radius, radius is 0.1m, plug in and solve.
4. a=(v^2)/r, (don't worry about converting to meters, since units are the same in kilometers, they will cancel out) plug in values and solve.
That's it!
Helppp!!!!! Please!!
A 0.144 kg baseball approaches a batter with a speed of 20m/s . The batter lines the ball directly back to the pitcher with a speed of 30m/s . Find the impulse exerted on the ball . If the bat and ball were in contact for 0.012 sec , find the average force exerted on the ball by the bat
Answer:
The impulse exerted by the ball is 7.2 kg.m/sThe average force exerted on the ball by the bat is 600 N.Explanation:
Given;
mass of the baseball, m = 0.144 kg
velocity of the baseball, v₁ = 20 m/s
velocity of the batter, v₂ = -30 m/s (opposite direction to the ball's speed)
The impulse exerted by the ball is calculated as follows;
J = ΔP = mv₁ - mv₂
ΔP = m(v₁ - v₂)
ΔP = 0.144 [20 - (-30)]
ΔP = 0.144 ( 20 + 30 )
ΔP = 0.144 (50)
ΔP = 7.2 kg.m/s
The average force exerted on the ball by the bat is calculated as;
[tex]F = \frac{\Delta P }{t} \\\\where; t \ is \ time \ of \ contact= 0.012 \ s\\\\F = \frac{7.2}{0.012} \\\\F = 600 \ N[/tex]
In your own words explain why the thickness and length of a wire could effect the flow of electrons
Answer:
(you can use my exact words) The length and thickness would make it so that the electrons move differently than they would a shorter and thinner wire because with the wire being longer the electrons would have a longer trip and with the wire being thicker the electrons would be more spread out and move be able to move more freely
For an object falling at the terminal velocity, list all the forces (magnitude and direction) acting it?
Answer:
Three stages of falling
There are three stages as an object falls through a fluid:
at the start, the object accelerates downwards due to the force of gravity
as the object's speed increases, frictional forces such as air resistance or drag increase
at terminal velocity, the weight of the object due to gravity is balanced by the frictional forces, and the resultant force is zero
Explanation:
6. What is the resultant force on each car below? Remember TWO pieces of
information are needed.
7. What additional statement could we make about each car? Think about what key
words we could use
Explanation:
In first case, the forces on LHS and on RHS is the same i.e. 3 N. The force acting on the car is balanced force. As a result, the car will not move at all.
In second case,
Force on RHS = 2000 N
Force on LHS = -6000 N
Net force acting on it is given by :
F = 2000+(-6000)
= -4000 N
Hence, this is the required solution.
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Sutt S
Kam Scheela MARIO MARTINEZ-HTPhysics.pdf
Test BGK
HW#10
Question: A pinball machine's plunger has a spring constant of 22
N/m and is compressed by 0.04 m to start a 0.006 kg pinball.
1. What is the elastic potential energy before the ball is released?
2. What is the kinetic energy of the pinball the instant it leaves the
spring?
3. What is the speed of the pinball the instant it leaves the spring?
4. If the pinball is moving at 1.3 m/s as it is deflected horizontally
across the top of the pinball machine, how much higher above the
ground is this part of its path when compared to its starting
position?
Squation
Drawing
Ta
Signature
Instructions.
Answer:
1. The elastic potential energy is 0.0176 Joules
2. The kinetic energy of the pinball the instant it leaves the spring is 0.0176 Joules
3. The speed of the pinball the instant it leaves the spring is approximately 2.42212 m/s
4. The height of the part where the pinball is located on the machine above the ground is approximately 0.213 meters
Explanation:
The spring constant of the pinball machine's plunger, k = 22 N/m
The amount by which the pinball machine's plunger is compressed, x = 0.04 m
The mass of the pinball ball, m = 0.006 kg
1. The elastic potential energy, P.E. = 1/2·k·x²
By substitution, we get;
P.E. = 1/2 × 22 N/m × (0.04 m)² = 0.0176 J
The elastic potential energy, P.E. = 0.0176 J
2. At the instant the pinball leaves the spring, the plunger and therefore the force of the plunger no longer acts on the pinball
Since there are no external forces acting on the pinball to increase the speed of the pinball after it leaves the spring, the velocity reached is its maximum velocity, and therefore, the kinetic energy, K.E. is the maximum kinetic energy which by the conservation of energy, is equal to the initial potential energy
Therefore;
K.E. = P.E. = 0.0176 J
The kinetic energy of the pinball the instant it leaves the spring, K.E.= 0.0176 J
3. The kinetic energy, K.E., is given by the following formula;
K.E. = 1/2·m·v²
Where;
v = The speed or velocity of the object having kinetic energy K.E.
Therefore, from K.E. = 0.0176 J, and by plugging in the values of the variables, we have;
K.E. = 0.0176 J = 1/2 × 0.006 kg × v²
v² = 0.0176 J/(1/2 × 0.006 kg) = 88/15 m²/s²
v = √(88/15 m²/s²) ≈ (2·√330)/15 m/s ≈ 2.42212 m/s
The speed of the pinball the instant it leaves the spring, v ≈ 2.42212 m/s
4. The height of the pinball is given by the following kinematic equation of motion;
[tex]v_h[/tex]² = u² - 2·g·h
Where;
[tex]v_h[/tex] = The velocity of the pinball at the given height = 1.3 m/s
u = v ≈ 2.42212 m/s (The initial velocity of the pinball as it the spring)
g = The acceleration due to gravity ≈ 9.8 m/s²
h = The height of the pinball above the ground
We get;
[tex]v_h[/tex]² = 1.3² = 2.42212² - 2 × 9.8 × h
∴ h = (2.42212² - 1.3²)/(2 × 9.8) ≈ 0.213
The height of the part where the pinball is located on the machine above the ground, h ≈ 0.213 m
PLEASE HELP I HAVE FINALSSS
Answer: 26.67 m/s
Explanation:
Given
Length traveled by the ball [tex]s=40\ m[/tex]
Time taken to reach the goal post is [tex]t=3\ s[/tex]
Initial velocity [tex]u=0\ m/s[/tex]
Using the second equation of motion
[tex]\Rightarrow s=ut+\frac{1}{2}at^2\\\Rightarrow 40=0+\frac{1}{2}a(3)^2\\\Rightarrow a=\frac{80}{9}\ m/s^2\\[/tex]
Now using
[tex]\Rightarrow v^2-u^2=2as\\\\\Rightarrow v^2-0=2\times \frac{80}{9}\times 40\\\\\Rightarrow v=\sqrt{\dfrac{80\times 80}{9}}=\dfrac{80}{3}\\\Rightarrow v=26.67\ m/s[/tex]
The velocity of ball will be 26.67 m/s
a wagon of mass 42 kg is pushed by a student a distance of 12.2 meters, and 297 j of work was sone on the wagon how much force did the student apply assuming that it was constant
Answer:
Force=2.484 N
Explanation:
[tex]f = \frac{w}{gh} \\ = \frac{297}{9.8 \times 12.2} \\ f = 2.484 \: n [/tex]
Hope it helped
PLS mark BRAINLIEST
A wagon of mass 42 kg is pushed by a student a distance of 12.2 meters, and 297 j of work was done on the wagon force did the student apply is 24.34 N.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
work = force*distance
force = work/distance
force = 297/12.2
force = 24.34 N
A wagon of mass 42 kg is pushed by a student a distance of 12.2 meters, and 297 j of work was done on the wagon force did the student apply is 24.34 N.
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The Escape speed at the surface of a certain planet is twice that of the earth. If the planet has radius twice of the Earth. what is its mass in unit of earth's mass?
Answer:
1.32 × 1022 short tons
Explanation:
hope this helps
The required mass of the planet is 8 times the mass of the earth.
Given that,
The Escape speed at the surface of a certain planet is twice that of the earth. The planet has a radius twice of the Earth. what is its mass in unit of earth's mass is to be determined.
An object with this velocity at the earth's surface will completely escape the earth's gravitational field, even after accounting for atmospheric losses.
here,
The escape velocity of the planet = 2 Escape velocity of the earth
[tex]\sqrt{{2GM_p}/r_p} = 2\sqrt{2GM_e/r_e}[/tex]
Substitute the values and square both sides,
[tex]{{2GM_p}/2r_e} = 4*{2GM_e/r_e}\\M_p = 8M_e[/tex]
Thus, the required mass of the planet is 8 times the mass of the earth.
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a car is traveling north on the interstate. They cover 645 miles in 9 hours. What is the car's average velocity ?
Answer:
71.6 mph
Explanation:
you would do 645 divided by 9 which would give you 71.6
PLEASE HELPP IL GIVE BRAINLY AND HEART
if the land warms faster than the sea during the day, which breeze is experienced ( Assume during the day and that the land asd sea do not have the same temperature. )
A) Sea breeze
B ) Land breeze
C ) No breeze
Answer:
sea breeze
Explanation:
Answer:
A sea breeze
Explanation:
Calculating net force
Answer:
0N.
Explanation:
Net force is the sum total of forces acting on an object.
The Fn which is the net force is
450+ (-250) + (-600)+ 600+ 0 + 250 + (-450)
= 450-250+(-600)+ 600+0+250-450
= 0N
The net force is 0
HELP!! AM I CORRECT?? PLS TELL ME, IF U ANSWER PROPERLY I'LL GIVE U BRAINLIEST!!
Answer:ur right I think
Explanation:
Answer:
HON, i'm going to be honest, i'm not sure but it sounds like it is the Universal Expansion from what I learned about space
I'm sure this helps but if it doesn't DON'T GIVE ME BRAINLIEST, if it does then do
The faster an object moves:
A the more potential energy it has.
B the more kinetic energy it has.
C the faster its particles vibrate.
D the cooler it gets.
Answer:
b the more genetic energy
What is the geocentric angle of the earthquake focus?
Answer:
epicenter
Explanation:
the epicenter Is d point directly above it at the structure of the earth
While standing at home plate, a batter swung a 2.5kg bat at 2.5 m/s toward an incoming mass. The mass was a 0.4 kg blob of clay, thrown toward the batter at 26 m/s, which stuck the the bat in an inelastic collision. What velocity of the velocity of the bat and blob of clay (which are stuck together) after the collision? Help fast will give brainliest
Show work
Answer:
5.74 m/s
Explanation:
m1v1+m2v2=(m1+m2)*vf
2.5*2.5+0.4*26=(2.9)vf
16.65=2.9vf
vf=5.74 m/s
Investigation to find out relationship between the current in the coil and the force on the iron disc
Answer:
Electromagnets are made of coils of wire with electricity passing through them. Moving charges create magnetic fields, so when the coils of wire in an electromagnet have an electric current passing through them, the coils behave like a magnet.
Explanation:
CAN A BRAINLEST HELP PLEASE!!!
The diagram below represents a rope along which
two wave pulses of equal amplitude, A, approach
point P