How do I do I calculate the curve of best fit with the following data points given?

How Do I Do I Calculate The Curve Of Best Fit With The Following Data Points Given?

Answers

Answer 1

To determine the curve of best fit, let's look at the x-intercepts of the curve.

Based on the graph, the x-intercepts are at x = -7 and x = -1.

Since -7 and -1 are the x-intercepts, we can say that the factors of this curve are:

[tex](x+7)(x+1)[/tex]

Now, we can also see that the graph is opening downward, therefore, the leading coefficient of the equation of this graph must be negative. For this, we will multiply the factors above by -1.

[tex]-(x+7)(x+1)[/tex]

All we have to do now is multiply the factors above in order to get the curve of best fit.

[tex]-(x^2+x+7x+7)[/tex]

Combine similar terms like x and 7x.

[tex]-(x^2+8x+7)[/tex]

Then, distribute the negative sign.

[tex]-x^2-8x-7[/tex]

Therefore, the curve of best fit is y = -x² - 8x - 7.

How Do I Do I Calculate The Curve Of Best Fit With The Following Data Points Given?

Related Questions

Which Venn diagram correctly shows the relationships between the subsets of rational numbers?

Answers

By definition, consider that natural numbers are all numbers from 1 to infinity. Whole numbers are the same natutal numbers plus zero. Integers are all numbers from minus infinity to infinity and rational are all number with finite decimals, and periodic infinite decimals.

Then, based on the previous description, the diagram which correctly shows the subsets of rational numbers is:

diagram F.

Consider the scenario: A town’s population has been decreasing at a constant rate. In 2010 the population was 5800. By 2012 the population had dropped to 4,600. Assume the trend continues predict the population in 2016.

Answers

Given:

In 2010 the population was 5800.

2012 the population had dropped to 4,600.

Let 't=0' be the year 2010.

P(t) represents the year population of the town t years after 2010.

Slope of a function P(t) is

[tex]\begin{gathered} m=\frac{4600-5800}{2012-2010} \\ m=-600 \end{gathered}[/tex]

Population of town t years after 2010.

[tex]P(t)=-600(t)+5800[/tex]

Population in the year 2016 that is t=6

[tex]\begin{gathered} P(6)=-600(6)+5800 \\ =2200 \end{gathered}[/tex]

Population in the year 2016 is 2200

which measurement could create more than one triangle measuring 20 cm / 9 cm and 10cm be a triangle with sides measuring 10 cm and 20 cm and included angle measurement 65 C a right angle with acute angles measuring 45 and 45 d a triangle with sides measuring 15 in 20 in and 25 in

Answers

Input data

The triangles created by the measurements of options A, B and D have specific side lengths. Therefore, you cannot create more than one triangle.

However, for a triangle with acute angles measuring 45° and 45°, a countless number of similar triangles (triangles with the same shape but different sizes) can be created.

The correct choice is C.

A toy factory makes 5.7 x 10³ toys each day.At this rate, how many toys will be made in 9 days?Express the answer in scientific notation.

Answers

First We will put the number of toys per day in simple form:

[tex]5.7\times10^3=5.7\times1000=5700[/tex]

Then, to know how many toys will be made in 9 days, let's multiply the number of toys per day by the given number of days:

[tex]5700\times9=51300[/tex]

Now We will put the number in scientific notation:

[tex]5.13\times10^4[/tex]

The graph of a quadratic function with vertex (-1,4) is shown in the figure below. Write the domain and range in interval notation.

Answers

Background:

• Domain,: a set of all possible values of the independent variable (,x,, in this case).

,

• Range,: a set of all possible values of the dependent variable (,y,, in this case), after substituting the domain.

Based on the arrows of the function, we can conclude that those extend to infinity (negative and positive).

Also, based on the coordinates of the vertex given we can see that the first value of y is 4.

Answer:

• Domain

[tex](-\infty,\infty)[/tex]

• Range

[tex](4,\infty)[/tex]

1. Find the surface area and volume of box where: L = 31.59ft, W = 24.98ft and H = 43.23ft.

Answers

ANSWER

[tex]\begin{gathered} A=6469.28ft^2 \\ V=34113.58ft^3 \end{gathered}[/tex]

EXPLANATION

The surface area of the box (rectangular prism) is:

[tex]A=2(LW+WH+LH)[/tex]

where L = length; W = width; H= height

Therefore, we have that the surface area of the box is:

[tex]\begin{gathered} A=2\lbrack(31.59\cdot24.98)+(24.98\cdot43.23)+(31.59\cdot43.23)\rbrack \\ A=2\lbrack(789.1182)+(1079.8854)+(1365.6357)\rbrack \\ A=2(3234.6393) \\ A\approx6469.28ft^2 \end{gathered}[/tex]

The volume of the box is:

[tex]V=L\cdot W\cdot H[/tex]

Therefore, the volume of the box is:

[tex]\begin{gathered} V=31.59\cdot24.98\cdot43.23 \\ V\approx34113.58ft^3 \end{gathered}[/tex]

Simplify. Assume that all variables result in nonzero denominators.

2n^3 y−8n^2 y/3y^4 * 12/n-4

Answers

The simplified form of given expression 2n^3 y−8n^2 y/3y^4 * 12/n-4 is 8n^2/y^3

In this question, we have been given an expression.

2n^3 y−8n^2 y/3y^4 * 12/n-4

We need to simplify given expression.

2n^3 y − 8n^2 y/3y^4 * 12/n-4

= [2n^2y (n - 4)] / 3y^4  *  12/(n - 4)

= 4 * (2n^2y)/y^4

= 8n^2/y^3

Therefore, the simplified form of given expression 2n^3 y−8n^2 y/3y^4 * 12/n-4 is 8n^2/y^3

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what is the surface area, in square centimeters, of the pyramid ?

Answers

[tex]\begin{gathered} \text{surface area of the pyramid = 4 triangle area + }square\text{ area} \\ \text{triangle area=}\frac{5.1\cdot5.95}{2}=15.1725\operatorname{cm} \\ \\ squarearea=(5.1)^2=26.01\operatorname{cm} \\ \text{surface area of the pyramid = 4 }\cdot(15.1725)\text{ + }26.01 \\ \end{gathered}[/tex]

Algebraically determine whether each of the following functions is even, odd or neither. then graph it B. y = x^3 – 3 C. y = 2x^3 - x

Answers

According to the even and odd function rules, we found out that the function [tex]y=x^{3}-3[/tex] is neither even nor odd and the function [tex]y=2x^{3}-x[/tex] is an odd function.

It is given to us that the functions are -

B. [tex]y=x^{3}-3[/tex]

C. [tex]y=2x^{3}-x[/tex]

We want to determine each of the following functions is even, odd or neither.

To see if the function is even, we have to check if [tex]f(-x)=f(x)[/tex]

To see if the function is odd, we have to check if [tex]f(-x)=-f(x)[/tex]

B. Here, we have

[tex]y=x^{3}-3\\= > f(x)=x^{3}-3\\= > f(-x)=(-x)^{3}-3\\= > f(-x)=-x^{3}-3[/tex]

We see that [tex]f(-x)\neq f(x)[/tex]. This implies that the function is not even.

Also, [tex]f(-x)\neq -f(x)[/tex]. This implies that the function is not odd.

Therefore, this function is neither even nor odd.

C. Here, we have

[tex]y=2x^{3}-x\\= > f(x)=2x^{3}-x\\= > f(-x)=2(-x)^{3}-(-x)\\= > f(-x)=-2x^{3}+x[/tex]

We see that [tex]f(-x)\neq f(x)[/tex]. This implies that the function is not even.

However,

[tex]f(-x)=-2x^{3}+x\\= > f(-x)= -(2x^{3}-x)\\ = > f(-x)=-f(x)[/tex]

This implies that the function is odd.

Therefore, this function is odd.

Thus, the function [tex]y=x^{3}-3[/tex] is neither even nor odd and the function [tex]y=2x^{3}-x[/tex] is an odd function.

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the circumference of a circular garden is 109.9 feet. what is diameter of the garden? use 3.14 and do not round your answer.

Answers

The circumference of a circle is given by the formula:

[tex]C=\pi d[/tex]

Where d is the diameter of the circle.

If the circumference is 109.9 ft, we have:

[tex]\begin{gathered} 109.9=3.14\cdot d \\ d=\frac{109.9}{3.14} \\ d=35\text{ ft} \end{gathered}[/tex]

So the diameter of the garden is 35 feet.

Perform the indicated operation -27÷-9

Answers

-27/9 = -3

answer is -3

Find the values of x and y in the equation below.a³b4a²b= a*b²X=

Answers

[tex](\frac{a^3b^4}{a^2b})^6[/tex]

To divide, subtract exponents to same base variables.

[tex](ab^3)^6[/tex]

Multiply exponents of exponents

[tex]a^6b^{18}[/tex]

x= 6

y= 18

Hello I need help with this I’m in a rush thanks

Answers

Recall that:

[tex]\frac{f}{g}(x)=\frac{f(x)}{g(x)},[/tex]

and that the domain of a rational function consists of all real numbers such that the denominator is different from zero.

If f(x)=5x+3 and g(x)=4x-5 we get that:

[tex]\frac{f}{g}(x)=\frac{5x+3}{4x-5}\text{.}[/tex]

The domain of the above rational function is:

[tex]\begin{gathered} \mleft\lbrace x|g(x)\ne0\mright\rbrace=\lbrace x|4x-5\ne0\rbrace \\ =\lbrace x|4x\ne5\rbrace=\lbrace x|x\ne\frac{5}{4}\rbrace\text{.} \end{gathered}[/tex]

Answer: Last option.

17. In trapezoid FGJK, what is the value of x? N CO 18.6 L K 23.6 9.3 11.8 ET O 13.6

Answers

Given data:

The given figure is shown.

The expression for the trapezium is,

[tex]\begin{gathered} \frac{x}{18.6}=\frac{18.6}{23.6} \\ 23.6x=18.6^2 \\ x=14.6 \\ =15 \end{gathered}[/tex]

Thus, thi

Which graph represents the function f(x) = -x + 31?

Answers

Answer:

Step-by-step explanation:

I hope this helps! :) If it does could you please mark me brainliest?

Answer:

Slope : -1

y = intercept : (0,31)

Step-by-step explanation:

find x=, if x-3=13 please

Answers

Answer:

[tex]x - 3 = 13 \\ \\ x = 13 + 3 \\ \\ x = 16[/tex]

-3 goes to other side and changes into +3

Question content area topPart 1A medical researcher administers an experimental medical treatment to patients. The patients in the study are categorized by blood types A, B, AB, and O. The researcher observed that the treatment had a favorable outcome for of the patients with blood type A, of the patients with blood type B, of the patients with blood type AB, and none of the patients with blood type O. Use this information to complete parts (a) through (d).

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

total patients = 300

type A:

total patients = 90

favourable patients = 27

type B:

total patients = 124

favourable patients = 31

type AB:

total patients = 6

favourable patients = 6

type O:

total patients = 80

favourable patients = 0

Step 02:

empirical probability:

probability = favourable outcomes / total outcomes

probability (A) = 27/ 90 = 0.3

probability (B) = 31 / 124 = 0.25

probability (AB) = 6 / 6 = 1

probability (O) = 0 / 80 = 0

That is the full solution.

find the area, to the nearest thousandth, of the standard normal distribution between the given z-scores. z= 1 and z= 1.9

Answers

The area, to the nearest thousandth, of the standard normal distribution between the z-scores z= 1 and z= 1.9​ is 0.130

Determine the equation of the graphed circle below!Equation should look like the example below!

Answers

Step 1:

Write the formula for the equation of a circle.

[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ \text{Center = ( a , b )} \\ \text{Radius = r} \end{gathered}[/tex]

Step 2:

Locate and write the center and radius of the circle.

Step 3:

Write the equation of the circle with center (-7, -2) and radius r = 2

[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ (x-(-7))^2+(y-(-2))^2=2^2 \\ (x+7)^2+(y+2)^2=\text{ 4} \end{gathered}[/tex]

Final answer

[tex](x+7)^2+(y+2)^2=\text{ 4}[/tex]

Suppose a binomial trial has a probability of success of 0.3 and 450 trials are performed. What is the standard deviation of the possible outcomes?6.3614.8511.629.72

Answers

The standard deviation of a binomial distribution with n trials and a probability of success of p is given by the formula:

[tex]\sigma=\sqrt[]{n\cdot p\cdot(1-p)}[/tex]

From the problem, we identify:

[tex]\begin{gathered} n=450 \\ p=0.3 \end{gathered}[/tex]

Then:

[tex]\begin{gathered} \sigma=\sqrt[]{450\cdot0.3\cdot(1-0.3)}=\sqrt[]{450\cdot0.3\cdot0.7} \\ \sigma\approx9.72 \end{gathered}[/tex]

in DEF, K is the centroid. If KH=12 find DH

Answers

the lines that cross the centroid are divided into 2 by this the short line corresponds to 1/3 of the complete line and the long line corresponds to 2/3 of the complete line

so KH is 1/3 of DH

if KH=12, then

[tex]\begin{gathered} DH=3KH \\ DH=3\times12 \\ DH=36 \end{gathered}[/tex]

the value of DH is 36

I tested positive for covid yesterday so i have no motivation to do this problem. Please don’t be slow when answering, I am every tired.

Answers

The value of  sector KL is 52

If JM and KN are two diamters of the circle,

then they intersect at the center

The sector JK and NM are equal

Thus,

The sector JN and KM are also equal

sector KM = sector KL + sector LM

Sector JN = Sector KM

sector JN = sector KL + sector LM

125 =  6x + 4 + 8x + 9

125 = 14x + 13

14x = 125 - 13

14x = 112

x = 8

sector KL = 6x + 4

= 6(8) + 4 = 48 + 4 = 52

Therefore, the sector KL is 52

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Hi!A particle moves along a straight line, so its speed is () = ^2 − + 6, where t is the time measured in seconds and the speed is measured in meters timessecond.a) Calculate the distance traveled between the seconds t=1 and t=3

Answers

In this problem

the distance traveled between the seconds t=1 and t=3 is given by

[tex]\int_1^3(t^2-t+6)dt=\frac{50}{3}\text{ m}[/tex]

The answer is

50/3 metersor 16.67 meters

Explanation of integrals

In this problem we have

[tex]\int_1^3(t^2-t+6)dt=\int_1^3t^2dt-\int_1^3tdt+\int_1^36dt[/tex][tex]\begin{gathered} \int_1^3t^2dt=\frac{t^3}{3} \\ Evaluate\text{ at 3 and 1} \\ \frac{(3)^3}{3}-\frac{1^3}{3}=\frac{27}{3}-\frac{1}{3}=\frac{26}{3} \end{gathered}[/tex][tex]\begin{gathered} -\int_1^3tdt=-\frac{t^2}{2} \\ evaluate\text{ at 3 and 1} \\ -\frac{3^2}{2}+\frac{1^2}{2}=-\frac{9}{2}+\frac{1}{2}=-4 \end{gathered}[/tex][tex]\begin{gathered} \int_1^36dt=6t \\ evaluate\text{ at 3 and 1} \\ 6(3)-6(1)=12 \end{gathered}[/tex]

substitute

[tex]\int_1^3t^2dt-\int_1^3tdt+\int_1^36dt=\frac{26}{3}-4+12=\frac{50}{3}[/tex]

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 6z​

Answers

Answer:

(-1, 7, - 4)(1, -1, 4)

=====================

Given system

x² + z² = 174x + y = 3y + z = 3

Rearrange the last two equation

4x = 3 - yz = 3 - y

This gives us:

z = 4x

Substitute the value of z into fist equation

x² + (4x)² = 17x² + 16x² = 1717x² = 17x² = 1x = 1 and x = - 1Find values of z and y

x = 1     ⇒ z = 4*1 = 4         ⇒  y = 3 - 4 = - 1 x = - 1   ⇒ z = 4*(-1) = - 4    ⇒ y = 3 - (-4) = 7

Answer:

[tex](x,y,z)=\left(\; \boxed{-1,7,-4} \; \right)\quad \textsf{(smaller $x$-value)}[/tex]

[tex](x,y,z)=\left(\; \boxed{1,-1,4} \; \right)\quad \textsf{(larger $x$-value)}[/tex]

Step-by-step explanation:

Given system of equations:

[tex]\begin{cases}x^2+z^2=17\\\;4x+y=3\\\;\;\;y+z=3\end{cases}[/tex]

To solve by the method of substitution, first rearrange the third equation to make y the subject:

[tex]\implies y=3-z[/tex]

Substitute this into the second equation and solve for z:

[tex]\begin{aligned}\implies 4x+(3-z)&=3\\3-z&=3-4x\\-z&=-4x\\z&=4x\end{aligned}[/tex]

Substitute the found expression for z into the first equation and solve for x:

[tex]\begin{aligned}\implies x^2+(4x)^2&=17\\x^2+16x^2&=17\\17x^2&=17\\x^2&=1\\x&=\pm1\end{aligned}[/tex]

Substitute the found values of x into the second equation and solve for y:

[tex]\begin{aligned}\implies x=-1 \implies 4(-1)+y&=3\\-4+y&=3\\y&=7\end{aligned}[/tex]

[tex]\begin{aligned}\implies x=1 \implies 4(1)+y&=3\\4+y&=3\\y&=-1\end{aligned}[/tex]

Substitute the found values of x into the derived expression for z and solve for z:

[tex]\begin{aligned}\implies x=-1 \implies z&=4(-1)\\z&=-4\end{aligned}[/tex]

[tex]\begin{aligned}\implies x=1 \implies z&=4(1)\\z&=4\end{aligned}[/tex]

Therefore, the solutions are:

[tex](x,y,z)=\left(\; \boxed{-1,7,-4} \; \right)\quad \textsf{(smaller $x$-value)}[/tex]

[tex](x,y,z)=\left(\; \boxed{1,-1,4} \; \right)\quad \textsf{(larger $x$-value)}[/tex]

14. John rides his motorcycle for 0.2 hours with a constant speed of 68 km/h and then foranother 13 minutes with a constant speed of 102 km/h. What is his average speed for thetotal trip?

Answers

We must calculate the weighted average as follows:

[tex]\begin{gathered} \frac{68\cdot0.2+102\cdot\frac{13}{60}}{0.2+\frac{13}{60}} \\ \frac{13.6+22.1}{0.416}=85.68 \\ \end{gathered}[/tex]

Therefore, the average speed is 85.68 km/h

I need help with triangles

Answers

[tex]\begin{gathered} To\text{ solve the question, then i have to use the trig function.} \\ \text{Hy}potenuse\text{ = 21 , Adjacent = 15} \\ Using\text{ Cos x = }\frac{Adj}{\text{Hyp}} \\ \text{ cos x = }\frac{15}{21} \\ \text{ cos x = 0.714} \\ \text{ x = cos}^{-1}(0.714) \\ \text{ x = 44.42} \end{gathered}[/tex]

Josslyn has nickels and dimes in her pocket. The number of nickels is three more than seven times the number of dimes let d represent the number of dimes. Write the expression for the number of nickels

Answers

[tex]7d+3[/tex]Explanation

to solve this we need to translate into math terms, so

Step 1

a) let d represents the number of dimes

let n represents the number of nickles

so

re write the expressions

[tex]\begin{gathered} number\text{ of dimes=d} \\ seven\text{ times the number of dimes = 7d} \\ \end{gathered}[/tex]

The number of nickels is three more than seven times the number of dimes in other words you have to add 7 to seven times the number of dimes to obtain the number of nickles

hence

[tex]n=7d+3[/tex]

therefore , the expression for the number of nickles is

[tex]7d+3[/tex]

I hope this helps you

How do I get to the answer of this question?

Answers

Okay, here we have this:

Considering the provided information, and that we must identify which of the provided options allow us to determine that the two triangles are similar, we obtain the following:

As the angle-angle similarity says that if two angles of one triangle are congruent with two angles of another triangle, then the triangles are similar.

Finally, we see that the only option that satisfies this statement is option D, since it indicates that two angles of the triangles are congruent. Therefore the correct option is D.

The graph of f(x) = x² is translated to formg(x) = (x-2)2-3.--5-4-3-2-1-2+Which graph represents g(x)?#

Answers

Step 1

Plot the graph of f(x)

[tex]f(x)=x^2[/tex]

Step 2

The function of g(x) suggests that f(x);

[tex]\begin{gathered} 1)\text{ it was moved 2 units towards the right} \\ 2)\text{ It was then moved 3 units down} \end{gathered}[/tex]

Thus, the graph of g(x) will look like this;

Answer;

At t seconds after launch is given by the function… how long will it take the rocket to reach its maximum height? What is the maximum height?

Answers

Given:

The height equation is,

[tex]h(t)=-16t^2+144t+6[/tex]

Explanation:

For maximum/minimum of a function, the first derivative of function is 0.

Differentiate the function with respect to x.

[tex]\begin{gathered} \frac{d}{dt}h(t)=\frac{d}{dt}(-16t^2+144t+6) \\ =-32t+144 \end{gathered}[/tex]

For maximum and minimum,

[tex]\begin{gathered} -32t+144=0 \\ t=\frac{144}{32} \\ =4.5 \end{gathered}[/tex]

So rocket reach it maximum height after 4.5 seconds of launch.

Substitute 4.5 for t in the equation to determine the maximum reached by rocket.

[tex]\begin{gathered} h(4.5)=-16(4.5)^2+144\cdot4.5+6 \\ =-324+648+6 \\ =330 \end{gathered}[/tex]

So maximum height of rocket is 330 feet.

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