[tex]{ \underline{ \red{ \sf{preparation \: f \: diborane}}}}[/tex]
Diborane is prepared by the reduction of boron trichloride with lithium aluminium hydride.
[tex]{ \blue{ \sf{4BF3 + 3LiAlH4 → 2B2H6 + 3AlF3 + 3LiF}}}[/tex]
It can be also prepared by reducing trifluoride with sodium hydride at 180°C.
[tex]{ \red{ \tt{2BF3 + 6NaH \: —(180°C)→ \: B2H6 + 6NaF}}}[/tex]
How do I calculate each of these?- Fractional uncertainty in mass of liquid sample - Fractional uncertainty in volume of liquid sample - Fractional uncertainty in density of liquid sample - Uncertainty in density of liquid sample
Fractional uncertainty is found by dividing the absolute uncertainty by the quantity itself. It is always the same for every measure: mass, volume, density, etc.
For example, if we have this measure 7.5+-0.1kg. The fractional uncertainty is:
[tex]\frac{0.1}{7.5}=0.013[/tex]Part III: Percent Yield1. If the reaction of 80 grams of Pb(NO3)2 produces 21.3 grams of NO2, what is thepercent yield?2Pb(NO3)2 → 2PbO + 4NO₂ +0₂2I
Explanation:
We determine the mass of NO2 from the mass of Pb(NO3)2:
m is the mass, M is the molar mass
[tex]\begin{gathered} m(NO2)\text{ = }\frac{m(Pb(NO3)2)}{M(Pb(NO3)2)}\text{ }\times\text{ }\frac{mol\text{ \lparen NO2\rparen}}{mol(Pb(NO3)2)}\text{ }\times\text{ M\lparen NO2\rparen} \\ \\ \text{ =}\frac{80}{331.2}\text{ }\times\frac{4}{2}\text{ }\times\text{ 46.0055} \\ \\ \text{ = 22.22g} \end{gathered}[/tex]Percent yield:
[tex]\begin{gathered} percent\text{ yield = }\frac{Actual\text{ yield}}{Theoretical\text{ yield}} \\ \\ \text{ =}\frac{21.3}{22.22} \\ \\ \text{ = 0.9586 }\times\text{ 100} \\ \\ \text{ = 95.86\%} \end{gathered}[/tex]Answer:
Percent yield = 95.86%
Calculate the concentration of the solution in mass percent 178mg C6H12O6 in 4.91g H2O
In this question, we need to calculate the percent mass concentration of one solute in one solvent, and we have:
178mg of C6H12O6
4.91g of H2O
To calculate the mass percent concentration, we can use the following formula:
%mass = (mass of solute/mass of solution)*100
But first, we need to have both compounds in the same unit, so 178mg will be equal to 0.178g
Now we add these values into the formula:
%mass = (0.178/5.088) * 100
mass = 3.50%
The 5.088 is because 4.91 + 0.178
How many atoms are in 140 moles of Gold?
Answer:862470.84
Explanation:
1 mole of substance is exactly equal to 6.023 × 10 ²³ molecules. 843.22 × 10²³ atoms are in 140 moles of Gold.
What do you mean by mole ?The term mole is defined as the amount of substance of a system which contains as many elementary entities.
1 mole is equal to 6.023 × 10 ²³ molecules.
One mole of any substance is equal to 6.023 × 10²³ units of that substance such as atoms, molecules, or ions. The number 6.023 × 10²³ is called as Avogadro's number or Avogadro's constant.
The mole concept can be used to convert between mass and number of particles.
1 mole = 6.023 × 10²³ molecules ( Avogadro number )
Then 1 mole of gold = 6.023 × 10²³ molecules
140 moles of gold = 140 × 6.023 × 10²³
= 843.22 × 10²³ atoms
Thus, 843.22 × 10²³ atoms are in 140 moles of Gold.
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Which of the following describes how difficult it is to remove a valence electron from an atom of a particular element?
A: Electron Affinity
B: Ionization energy
C: Atomic Radius
D: Electronegativity
The term that describes how difficult it is to remove a valence electron from an atom of a particular element is electron affinity (option A).
What is electron affinity?Electron affinity is the energy released when an electron is attached to an atom or molecule; used as a measure of its ability to form an anion.
It becomes harder to remove an electron when an atom has a net positive charge because the attraction that the nuclear charge exerts per electron gets larger.
It takes a large amount of energy to remove electrons from an element with high electron affinity, hence, electron affinity determines how difficult it is to remove a valence electron from an atom.
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This number: 4.188x10^22 particles —-1cm ^3 x particles —-14.374cm^3 is about is about to number of silicon atoms this number: 6.20x10^23 particles is about the expected number of particles the silicon cube what are the differences of the two numbers ?
We are given two volume values, each volume has a certain number of molecules. The second number 6.20 x10^23 corresponds to the avogadro number and is equivalent to one mole of silicon. The first number does not make a molecule, so it must be only a fraction of the molecule of silicon being measured.
That will be the diference between the two number. 6.20 x10^23 is equivalent to one molecule while 4.188x10^22 is not.
10. 1.29 dag of sodium chloride is reacted with 25.0 dag of silver nitrate10. Balanced Chemical Equation: Reaction Type:At completion of reactions: Formula of Reactant A: Grams of Reactant A: Formula of Reactant B:Grams of Reactant B: Formula of Product C:Grams of Product C: Formula of Product D:Grams of Product D:
So,
Let's first convert some units:
[tex]\begin{gathered} 1.29dag\cdot\frac{10g}{1dag}=12.9g \\ \\ 25.0\text{dag}\cdot\frac{10g}{1\text{dag}}=250g \end{gathered}[/tex]So,
There's a reaction between 12.9g of sodium chloride and 250g of silver nitrate.
The reaction that occurs here, is the next one:
[tex]NaCl+AgNO_3\to AgCl+NaNO_3[/tex]Sodium chloride reacts with silver nitrate to form silver chloride and sodium nitrate.
This reaction is a displacement reaction.
Now, let's complete the information:
Formula of Reactant A: NaCl
Grams of Reactant A: 12.9g
Formula of Reactant B: AgNO3
Grams of Reactant B: 250g
Formula of Product C: AgCl
Grams of Product C: ?
Formula of Product D: NaNO3
Grams of Product D: ?
We need to find the amount of grams of the formed products.
So, let's first convert the grams of each reactant in moles. Remember that the number of moles (n) can be found if we divide the given mass of the given compound by its molar mass. So,
[tex]\begin{gathered} n_{NaCl}=\frac{12.9gNaCl}{\frac{58.5gNaCl}{\text{mol}}}=0.22\text{molesNaCl} \\ _{} \\ n_{AgNO_3}=\frac{250gAgNO_3}{\frac{169.87gAgNO_3}{mol}}=1.47molesAgNO_3 \end{gathered}[/tex]The limiting reactant in this reaction is NaCl. So, we're going to use the reaction's stoichiometry to find the amount of the products as follows:
[tex]0.22mol\text{NaCl}\cdot\frac{1\text{molAgCl}}{1\text{molNaCl}}\cdot\frac{143.32\text{gAgCl}}{1\text{molAgCl}}=31.53\text{gAgCl}[/tex]Thus, there are 31.53g of AgCl formed.
Finally, let's find the amount of grams of product D (NaNO3):
[tex]0.22mol\text{NaCl}\cdot\frac{1\text{molNaNO}3}{1\text{molNaCl}}\cdot\frac{84.99\text{gNaNO}3}{1\text{molNaNO}3}=18.69\text{gNaNO}3[/tex]Therefore,
There were formed 31.53g of AgCl (product C) and 18.69g of NaNO3 (product D)
Please assist with following question Which of the following statements is correct?A. A heterogeneous mixture is also known as a solution.B. A pure substance may be separated by filtration or distillation into two or more components.C.A heterogeneous mixture is composed of two or more substances in the same phase.D. The composition is uniform throughout a homogeneous mixture.
In this question we have the concept of solutions and mixtures, let's analyze each option in order to find the one that best fits with reality:
A. Heterogeneous mixtures and solutions aren't the same thing, a mixture is when you have two or more compounds mixed together in a container, and a mixture can be heteregenous (which will form two or more phases), or homogeneous (which will be uniform throughout the mixture), and a solution will be the same as a homogeneous mixture.
B. A pure substance will not be separated by any method, since there is nothing the separate, it is all the same substance
C. As I said in letter A, a heteregeneous mixture will not have the same phase, but it will have different phases
D. The composition of a homogeneous mixture will be uniform, just a as a solution
The correct one will be letter D
7.Write separate, balanced equations for the following double displacement neutralization reactionsa.Hydrochloric acid and sodium hydroxideb.Acetic acid and sodium hydroxide.
a)
Hydrochloric acid: HCl
Sodium hydroxide: NaOH
In the neutralization, an acid and a base react to neutralize the H⁺ and OH⁻, forming water.
In a displacement reaction, an atom in one of the components is displaced to another component in the reaction.
In the case of HCl and NaOH, we can see this as a double displacement, where H⁺ from HCl is exchanged by the Na⁺ of the NaOH, forming NaCl and H₂O:
[tex]HCl+NaOH\to NaCl+H_2O[/tex]b)
Acetic acid: CH₃COOH
Sodium hydrocide: NaOH
In this case, the NaOH is the same. the Aceitc acid dissociates in the following way:
[tex]CH_3COOH\to CH_3COO^-+H^+_{}[/tex]So, we just need to visualize the CH₃COO⁻ as the Cl⁻ of item a.
That is, we will have the reaction exchanging H⁺ and Na
27) Suppose object A has double the specific heat and triple the mass of object B. If the same amount of heat is applied to both objects, how will the temperature change of A be related to the temperature change of B? Enter your answer to three significant figures.
The absorbed or released by a system is given by the following formula:
[tex]Q=m\cdot Cp\cdot\Delta T[/tex]Where Q is the heat absorbed or released, m is the mass of the system, Cp is the specific heat and ΔT is the change in the temperature.
Let mA and mB be the mass of objects A and B, let CpA and CpB be the specific heats of objects A and B and let ΔTA and ΔTB be the specific heats of objects A and B. We will have that:
[tex]\begin{gathered} mA=3mB \\ CpA=2CpB \end{gathered}[/tex]If the same amount of heat is applied to both object, we will have that:
[tex]\begin{gathered} QA=QB \\ mA\cdot CpA\cdot\Delta TA=mB\cdot CpB\cdot\Delta TB \end{gathered}[/tex]Replace mA and CpA for their equivalences in terms of mB and CpB:
[tex]\begin{gathered} 3mB\cdot2CpB\cdot\Delta TA=mB\cdot CpB\cdot\Delta TB \\ \Delta TA=\frac{mB}{3mB}\cdot\frac{CpB}{2CpB}\cdot\Delta TB \\ \Delta TA=\frac{1}{3}\cdot\frac{1}{2}\Delta TB \\ \Delta TA=\frac{1}{6}\Delta TB \end{gathered}[/tex]It means that the change in temperature of A is 1/6 of the change of temperature of B.
[tex]\Delta TA=\frac{1}{6}\Delta TB[/tex]Select the structure that correspondsto the molecule name:propylamineA.NH₂B. CH3CH₂CH₂NH₂C. both
Explanation:
Propylamine is characterized by 3 carbons, 9 hydrogens, and 1 nitrogen.
According to the given picture, B is the correct answer.
Answer:
B is the correct answer.
Determine the percentage by mass of each element in the following compounds. (Round your answers to one decimal place.)(a)milk of magnesia, Mg(OH)2Mg:____%O:______%H:______%(b)lye, NaOHNa:____%O:_____%H:_____%
Firstly we will calculate the mass of the molecule by adding the together the atomic mass of each element:
[tex]\begin{gathered} Mg:24.31g \\ O:16.00g \\ H:1.00g \\ _mMg(OH)_2=24.31+(16.00\times2)+(1.01\times2) \\ _mMg(OH)_2=58.33gmol^{-1} \\ \\ \\ Na:22.99g \\ O:16.00g \\ H:1.01g \\ _mNaOH=22.99+16.00+1.01 \\ _mNaOH=40gmol^{-1} \end{gathered}[/tex]Now we will determine the percentage mass of each of element:
[tex][/tex]Bromination of isobutane is a two‑step reaction. Step 1 reaction is: a coumpound with a central carbon atom with three single bonded C H 3 groups and one single bonded hydrogen plus radical bromine react to form a compound with a central carbon atom with a single electron and three single bonded C H 3 groups plus bromine with a single bonded hydrogen atom. Step 2 reaction is: a compound with a central carbon atom with a single electron and three single bonded C H 3 groups plus bromine single bonded to bromine react to form a coumpound with a central carbon atom with three single bonded C H 3 groups and one single bonded bromine plus radical bromine. The overall reaction is: a coumpound with a central carbon atom with three single bonded C H 3 groups and one single bonded hydrogen plus bromine single bonded to bromine react to form a coumpound with a central carbon atom with three single bonded C H 3 groups and one single bonded bromine plus bromine with a single bonded hydrogen atom. Using the table of bond dissociation energies for A−B⟶A+B, calculate the enthalpy of each step and the enthalpy of the overall reaction.
Bromination of isobutane is a two‑step reaction.
The enthalpy of each step : step 1: ΔH = 34 kJ/mol. step 2 : ΔH = -99 kJ/mol enthalpy of the overall reaction , ΔH = 65 kJ/mol.
Bond dissociation energy :
H - H = 436 kJ/mol
H - Br = 366 kJ/mol
Br - Br = 193 kJ/mol
(CH₃)₃C - H = 400 kJ/mol
(CH₃)₃C - Br = 292 kJ/mol
Step 1 : (CH₃)₃C - H + Br ------> (CH₃)₃C° + H - Br
ΔH = ∑ Bond broken - ∑ Bond form
ΔH = 400 kJ/mol - 366 kJ/mol
ΔH = 34 kJ/mol
Step 2: (CH₃)₃C° + Br - Br ----> (CH₃)₃ - Br + Br
ΔH = ∑ Bond broken - ∑ Bond form
ΔH = 193 - 292
ΔH = - 99 kJ/mol
overall reaction :
(CH₃)₃ - H + Br - Br ----> (CH₃)₃ - Br + H- Br
ΔH = ( 400 + 193 ) - ( 292 + 366 )
ΔH = 593 - 658
ΔH = - 65 kJ/mol
Thus, Bromination of isobutane is a two‑step reaction.
The enthalpy of each step : step 1: ΔH = 34 kJ/mol. step 2 : ΔH = -99 kJ/mol enthalpy of the overall reaction , ΔH = 65 kJ/mol.
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Which of the following statements is FALSE? In its interaction with hemoglobin, oxygen is:
bound at the 6th coordination position of the Fe(II) ion in the heme.
a ligand.
homoallosteric effector.
a prosthetic group.
reversibly bound.
The statement in its interaction with hemoglobin, oxygen is a prosthetic group is False (Option 4).
What is the hemoglobin protein of the red blood cells?The hemoglobin protein of the red blood cells is a protein that binds to oxygen in order to transport this reactant of cellular respiration to all cells of the body.
Therefore, with this data, we can see that the hemoglobin protein of the red blood cells is required to bind oxygen which does not act as a prosthetic group and is a reactant of cellular respiration.
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Which of the following are spectator ions in the reaction shown below? Select all that apply.
In this question, we have to find which ions are classified as spectator ions. The definition of spectator ions is the ones that will not participate directly in any change in the reaction.
In a reaction we usually have 2 main changes for the ions, they can change their oxidation number, in a reaction called redox reaction. They can also change their physical state, going from aqueous to solid.
The spectator ions will not have their oxidation number changed and they will not change their physical state.
The 2 ions that can be classified as spectator ions are Na+ and NO3-
Answer: son Na+ y NO3-
Explanation:
The volume of a gas was 63 mL when the temperature was 162.1 °C. If thetemperature was initially 6.5 °C, and there was no change in the pressure, whatwas the initial volume of the gas?
To answer this question we have to use Charles' Law:
[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]Before replacing for the given values, we have to convert the given temperatures to Kelvin:
[tex]\begin{gathered} 162.1+273.15=435.25 \\ 6.5+273.15=279.65 \end{gathered}[/tex]Now replace for the given values, V1 and V2 are the initial and final volumes respectively and T1 and T2 are the initial and final temperatures. Solve for V1 and find its value:
[tex]\begin{gathered} V1=\frac{V2T1}{T2} \\ V1=\frac{63mL\cdot279.65K}{435.25K} \\ V1=40.4mL \end{gathered}[/tex]It means that the initial volume was approximately 40mL.
The correct answer is c. 40.
A species whose oxidation number decreases in a reaction is said to be which of the following?electrolyzedoxidizedauto-oxidizedreduced
Answer
Reduction
Procedure
A redox reaction is a reaction that involves the transfer of electrons between chemical species. During a redox reaction, some species undergo oxidation, or the loss of electrons, while others undergo reduction or the gain of electrons.
An atom’s oxidation number is the charge that the atom would have if all of the bonds to the atom were completely ionic. An increase in oxidation number during a reaction corresponds to oxidation, while a decrease corresponds to reduction.
Which statement is NOT true? 1. Sodium chloride and other conducting solutes are called electrolytes. 2. Sugar and other non-conducting solutes are called non-electrolytes. 3. A solution in which water is the solvent is known as an aqueous solution. 4. A solute dissolves other substances that are called solvents. The resultant mixture is known as a solution.
1. True ; an electrolyte is a substance that conducts electric current.
2. True ; a non eletrolyte, like sugar and ethanol, is a compound that doesnt conduct electic current .
3. True; An aqueous solution is a solution in which water is the solvent.
4. False; A solute is the substnce that dissolves in a solvent to produce a homogeneous mixture.
midterm 3 In an effort to stretch already thin educational budgets, a county’s school cut home economics from their offered programs. Fast forward to 10 years down the road, which statement shows the MOST likely consequence of that choice? A. The county now has a generation of young adults who eat mostly fast food and take out. B. The county has a higher rate of college graduates and the median income has risen. C. The county has seen little to no change that can be traced back to the decision to cut the program. D. The county now has a generation of young adults who are opening new bars, breweries, and restaurants. wellness & nutrition
In an effort to stretch already thin educational budgets, a county’s school cut home economics from their offered programs fast forward to 10 years down the road then the county has a higher rate of college graduates and the median income has risen
Home economics be thought in the school again because student all over the world can be empowered by home economics programs by learning essential life skills that, occasionally, cannot be gained from textbooks or parents
And most significantly the knowledge and ability acquire on the home economic class give every student the confidence and positive reinforcement they require
Due to fact that it cover important concepts related to the family house, clothes, and food, this subject aids society in advancing human growth
Human advancement is essential to the development of society and also building essential life skills
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Are chemical reactions reversible? Explain your answer in at least 3 sentences.
Chemical reactions are reversible, which means that the reaction that occurs from the reactants to form products can be also from the products to form the reactants again, this is widely studied in Chemical Equilibrium and Le Chantelier's principleons are
A sample of gas has temperature of 25 Celsius and a volume of 122 ml. If the volis decreased to 50 ml, what is the new temperature?
So,
We could use the Charles law:
In this case, we have:
V1=122ml
T1=25°C
V2=50ml
T2=?
Let's replace these values in the equation in order to find T2:
The final temperature is about 10.2459°C.
What concentration of NO−3 results when 885 mL of 0.463 M NaNO3 is mixed with 731 mL of 0.787 M Ca(NO3)2?
The concentration of NO−3 will be 1.99 M
NaNO3 ionizes as follows:
NaNO3 ⇒ Na+ + [tex]NO^{3-}[/tex]
Moles NaNO3 dissolved ⇒ (0.463 mol/L) /(0.885 L) = 0.5231 mol
From the chemical equation, one mole of NaNO3 dissolving yields one mole of [tex]NO^{3-}[/tex]in solution.
Moles [tex]NO^{3-}[/tex] = 0.5231 mol
Ca(NO3)2 dissolves as follows:
Ca(NO3)2 ⇒ Ca2+ + 2 [tex]NO^{3-}[/tex]
Moles Ca(NO3)2 dissolved ⇒ (0.787 mol/L)/ (0.731 mL) = 1.07 mol
From the chemical equation, one mole of Ca(NO3)2 dissolving yields two moles of [tex]NO^{3-}[/tex] in solution.
Moles NO3^- = 1.07 molx 2 = 2.14mol
Total moles [tex]NO^{3-}[/tex]in solution=2.14 mol + 1.07 mol = 3.21 mol
Total volume of solution ⇒ 0. 731 L + 0.885 L = 1.61 L
Molarity of [tex]NO^{3-}[/tex]⇒ 3.21 mol / 1.61 L = 1.99 M
Therefore, concentration will be 1.99 M.
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How many moles of water are in a 39.2 L container at 6.32 atm and 486 °C?
Step 1
Water is supposed to be in the gas phase and it is assumed that it is an ideal gas.
Therefore, it can be applied:
p x V = n x R x T (1)
p = pressure = 6.32 atm
V = volume = 39.2 L
n = moles = unknown
R = gas constant = 0.082 atm L/mol K
T = absolute temperature = 486 °C + 273 = 759 K
-------------------
Step 2
n is cleared from (1):
p x V/R x T = n
(6.32 atm x 39.2 L)/(0.082 atm L/mol K x 759 K) = n
3.98 moles = n
Answer: number of moles = 3.98 moles
How many grams of Iron are produced if 0.576 moles of Carbon dioxide are produced when Fe3O4 react with CO to form Fe and CO₂?
The mass of Iron produced by the reaction of given reactants will be 64.3 grams.
The balanced reaction is given as,
Fe₂O₃ + 3CO= 2Fe + 3CO₂
According to the chemical equation, 3 moles of carbon monoxide, CO, will react with 1mole of ferric oxide, Fe₂O₃, and produce 3 moles of carbon dioxide, CO₂
Now, we are given moles of carbon monoxide and asked for moles of Iron. This means that we will have to convert the aforementioned mole ratio that exists between carbon monoxide and carbon dioxide to a gram ratio.
If one mole of Iron has the mass of 55.845 g and one mole of carbon dioxide has a mass of 44.01 g, it follows that reaction produces
44.01g of carbon dioxide for the every 55.845 g of Iron.
So for 1 moles of carbon dioxide the mass will be 44.01 g
For 3 moles it is 3× 44.01 =132.03 gram
1 mole carbon dioxide has 55.845 g iron
0.576 moles has 55.845×0.576
44.01×3 g of carbon dioxide = 132.03 g
55.845×2 g of Iron = 111.69 g
So in 0.576 moles it will get 111.69×0.576
=64.3 grams of Iron are produced.
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What is the molecular geometry of the XeF2 molecule?Group of answer choiceslinearnone of the answers are correctbenttrigonal bipyramid
ANSWER
The molecular geometry of XeF2 is linear
EXPLANATION:
The compound given is called Xenon Difluoride
It is very important to know the following features of Xenon
1. Xenon has two bond pairs and three lone pairs of electrons
2. During hybridization, Xenon will form two sigma bonds with two fluorine atoms
The bond angle of Xenon Difluoride is 180 degrees, hence, the molecular geometry is linear
Aqueous solutions of all the salts are neutral in nature i.e. neither acidic nor basicin nature.T or F
In nature it is possible to find aqueous solutions of salts in both basic and acidic forms, for the basic salts, which can also be called Alkali salts, we have a few, for example, Sodium carbonate, Sodium sulfide, Sodium hydroxide. For the acidic salts we can have NaHSO4, Sodium bisulfate. Therefore this is a false statement.
Radium decays according to the functionQC) - Qewhere Q represents the quantity remaining after tyears and kis the decayconstant 0.00043. How long will take for 40g of radium to decay to 10g?A. Approx. 93 yearsB. Approx 3224 yearsC. Approx 8579 yearsD. Approox. 2144 years
First, we have the next data:
Q(t) = final mass at time t = 10 g
Qo = initial mass = 40 g
v = decay constan = 0.00043 1/years
This kind of process like decay, follow a first-order reaction, and the formula used for this:
[tex]\begin{gathered} Q(t)=Qoxe^{-vxt} \\ \text{Clearing t:} \\ \frac{Q(t)}{Qo}=e^{-vxt} \\ \ln (\frac{Q(t)}{Qo})=-\text{vxt} \\ \frac{\ln (\frac{Q(t)}{Qo})}{-\text{v}}=t \end{gathered}[/tex][tex]\begin{gathered} \frac{\ln (\frac{10}{40})}{-0.00043\text{ 1/years}}=\text{ t} \\ \end{gathered}[/tex]Answer: t = 3224 years
Overall oxidation reduction reaction for calcium battery
The battery works by using electrochemical processes known as oxidation and reduction. Electrons are exchanged between chemical entities in these reactions. Oxidation occurs when a chemical species loses one or more electrons. The opposing process, electron gain, is known as reduction.
The oxidation Reaction in Calcium Batteries is?An oxidation process occurs at the positive electrode during discharge, whereas a reduction reaction occurs at the negative electrode. Electrons from an external power source induce a reverse electrochemical reaction in the rechargeable battery.
Calcium does not readily oxidize in dry air at normal temperatures, but it oxidizes fast in wet air or dry oxygen at around 300°C. Calcium interacts with fluorine at ambient temperature and with the other halogens at 400°C. Calcium is a great reducing agent and is extensively employed for this purpose.
Note that the question seems incomplete hence the general answer.
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I wanted to know the units or if the units I put on the table is right. For example the unit for mass of solid or the unit for volume of water
Answer
All the units were correct.
The unit of part b can either be any of milliliter or cubic centimeter
Density = 12446.71 g/mL
Explanation
All the units were correct.
Note:
1 milliliter = 1 cubic centimeter
g = grams
mL = milliLiter
The unit of part b can either be any of milliliter or cubic centimeter
The unit of the mass is g
The unit of the volume is mL
The unit of density is g/mL
The density of the solid = mass/volume = 87127/7 = 12446.71 g/mL
Classify the following amine as 1°, 2°, 3° or 4°(primary, secondary, tertiary, quaternary).CH3NH2A. primaryB. secondaryC. tertiaryD. quarternary
Explanation:
The degree of amines is determined by the number of carbons attached to the nitrogen.
According to the given picture, the answer is A.
Answer:
The answer is A.