Answers
2)
[tex]F=2.3097\cdot10^{48}\text{ Newtons}[/tex]Explanation
the electrostatic force between two forces is given by:
[tex]\begin{gathered} F=k\frac{q_1q_2}{d^2_{}} \\ where\text{ } \\ k\text{ is a constant}(in\text{ this case we n}eed\text{ asume k=1)} \\ q_1\text{ is the charge 1} \\ q_2\text{ is the charge }2 \\ \text{and d is the distance betw}en\text{ them} \end{gathered}[/tex]then, complete the table we need to use this equation
where
[tex]F=k\frac{q_1q_2}{d^2_{}}[/tex]k, q1 and q2 are ginven in the table, so
Step 1
Let
[tex]\begin{gathered} charge_1=\frac{1}{4} \\ charge_2=1 \\ \text{distance}=1 \end{gathered}[/tex]so,replace
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=1\frac{\frac{1}{4}\cdot1}{1_{}}=\frac{1}{4} \end{gathered}[/tex]hence, for tha row
[tex]\begin{gathered} \frac{1}{4}F_e \\ \end{gathered}[/tex]Step 2
now, do the same for the next Fe, so
b)Let
[tex]\begin{gathered} charge_1=1 \\ charge_2=\frac{1}{2} \\ \text{distance}=1 \end{gathered}[/tex]so,replace
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=1\frac{1\cdot\frac{1}{2}}{1_{}}=\frac{1}{2} \end{gathered}[/tex]hence, for tha row
[tex]\begin{gathered} \frac{1}{2}F_e \\ \end{gathered}[/tex]Step 3
now, do the same for the next Fe, so
c)Let
[tex]\begin{gathered} charge_1=1 \\ charge_2=\frac{1}{4} \\ \text{distance}=1 \end{gathered}[/tex]so,replace
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=1\frac{1\cdot\frac{1}{4}}{1_{}}=\frac{1}{4} \end{gathered}[/tex]hence, for that row
[tex]\begin{gathered} \frac{1}{4}F_e \\ \end{gathered}[/tex]Step 4
now, do the same for the next Fe, so
c)Let
[tex]\begin{gathered} charge_1=\frac{1}{2} \\ charge_2=\frac{1}{2} \\ \text{distance}=1 \end{gathered}[/tex]so,replace
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=1\frac{\frac{1}{2}\cdot\frac{1}{2}}{1_{}}=\frac{1}{4} \end{gathered}[/tex]hence, for tha row
[tex]\begin{gathered} \frac{1}{4}F_e \\ \end{gathered}[/tex]Step 5
now, do the same for the next Fe, so
c)Let
[tex]\begin{gathered} charge_1=\frac{1}{8} \\ charge_2=\frac{1}{4} \\ \text{distance}=1 \end{gathered}[/tex]so,replace
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=1\frac{\frac{1}{8}\cdot\frac{1}{4}}{1_{}} \\ F=1\frac{\frac{1}{32}}{1_{}}=\frac{1}{32} \end{gathered}[/tex]hence, for that row
[tex]\begin{gathered} \frac{1}{32}F_e \\ \end{gathered}[/tex]Step 6
find the electrostastic force betweeen electrons
let
[tex]\begin{gathered} q_1=q_2=-\text{1}.602\cdot10^{19}\text{ C} \\ k=9\cdot10^9\frac{Nm^2}{C^2} \end{gathered}[/tex]as the distance is not give, let's use
distance =1
replace in the formula
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=9\cdot10^9\frac{Nm^2}{C^2}\frac{(^2-\text{1}.602\cdot10^{19}C)}{1_{}} \\ F=2.3097\cdot10^{48}\text{ N} \end{gathered}[/tex]therefore, the electrostaic force is
[tex]F=2.3097\cdot10^{48}\text{ Newtons}[/tex]I hope this helps you
Related Questions
Which of the following is NOT an example of energy converting
a kid swinging on a swing
a bouncing ball
a sandwich on a table
a falling acorn
Answers
Answer:
A sandwich on a table.
Explanation:
The sandwich isn't in motion like the other options.
after being struck by the bullet, the disk rotates at 4.00 rad/srad/s . what is the horizontal velocity of the bullet just before it strikes the disk?
Answers
The component of horizontal velocity of bullet is 8m/s for 4 radians per second.
Given - Rotation rate = 4 rad per sec.
This means 4 radians for one seconds . i.e. one seconds is equivalent to 60min.
To resolve the velocity following equation can be employed-
[tex]\beta =vt+\frac{\alpha t^2}{2}\\ \\\beta = rotation\\\\v= velocity\\\\t= time\\\\\alpha =acceleration[/tex]
Now substituting all values in this equation
4= 0+α/2
α=4 x 2 ⇒8m/s²
since the rotation is for one seconds so velocity = acceleration.
[tex]acceleration=\frac{dv}{dt}[/tex]
dt =1
so α=v=8m/s
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a collection of hydrogen atoms in the ground state is illuminated with ultraviolet light of wavelength 75.0 nm. find the kinetic energy of the emitted electrons.
Answers
The kinetic energy of the emitted electrons is 11.24 eV.
What is kinetic energy?The following is the physics definition of kinetic energy:
The amount of effort that a moving object may accomplish is measured by its kinetic energy.
Kinetic energy is a scalar quantity that can only be fully explained by its magnitude.
Given parameters:
Wavelength of ultraviolet light : λ = 75.0 nm.
Energy of the ultraviolet light: E = hc/λ = 1242/75.0 eV= 22.84 eV
Potential energy of a electron of hydrogen atoms in the ground state is -13.6 eV.
This energy of light supplies required potential energy to the emitted electron and kinetic energy of electron.
So, the kinetic energy of the emitted electrons = 22.84 eV - 13.6 eV = 11.24 eV.
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Which one of the following is true for a chemical reaction?
a) The number of protons and/or neutrons in the atoms char
b) The electron clouds of atoms change.
C) Matter can be converted into energy.
D) The number of atoms can change.
Answers
Main answer- C (matter can be converted into energy)
supporting answer-Nuclear fission is a reaction in which particles or atoms split into two smaller and lighter nuclei, which can then be converted into energy.
final answer -hence final answer is C
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A wheel rolls without slipping. Which is the correct velocity vector for point p on the wheel?.
Answers
The velocity vector for the point P will be the resultant velocity. So, option (C) is correct.
What do we mean by plane of motion?Plane motion is the movement of an item when all of its pieces move in a straight line along a set plane. Two different types of plane motion are listed below:
1. Pure rotational motion: In this motion, the rigid body revolves around a fixed axis that is parallel to a fixed plane. In other words, with respect to an inertial frame of reference, the axis is stationary and does not move or change direction.
2. The overall plane motion: In this case, the motion can be characterized as a combination of pure translational motion in a plane that is fixed and pure rotational motion along an axis perpendicular to the plane.
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I need help with question 3 you don’t have to explain it I just need the answers thank you.
Answers
Weight of the bag of sugar on the moon = 3.34 N
Weight of the bag of sugar on Venus = 18.09 N
Mass of the bag of sugar on the Earth = 2.04 kg
Mass of the bag of sugar on the moon = 2.04 kg
Mass of the bag of sugar on venus = 2.04 kg
Explanation:The weight of the object on the earth
[tex]\begin{gathered} W_E=4.50\text{ lb} \\ 1\text{ lb = }4.45\text{ N} \\ W_E=4.50\text{ }\times4.45 \\ W_E=20.03N \end{gathered}[/tex]The acceleration due to gravity on the earth:
[tex]g_E=9.81m/s^2[/tex][tex]\begin{gathered} W_E=m_Eg_E_{} \\ 20.03=m_E\times9.81 \\ m_E=\frac{20.03}{9.81} \\ m_E=2.04\operatorname{kg} \end{gathered}[/tex]The mass of the bag of sugar on the earth = 2.04 kg
Note that the mass of the sugar is the same everywhere
Acceleration due to gravity on the moon is one-sixth of acceleration due to gravity on the earth
[tex]\begin{gathered} g_m=\frac{1}{6}g_E \\ g_m=\frac{1}{6}(9.81) \\ g_m=1.635 \end{gathered}[/tex]The weight of the bag of sugar on the moon is:
[tex]\begin{gathered} W_m_{}=m_mg_m_{} \\ W_m=2.04\times1.635 \\ W_m=3.34N \end{gathered}[/tex]The acceleration due to gravity on the Venus is 0.904 times that of the earth
[tex]\begin{gathered} g_v=0.904g_E \\ g_v=0.904(9.81) \\ g_v=8.87m/s^2 \end{gathered}[/tex]The weight of the bag of sugar on the venus is:
[tex]\begin{gathered} W_v=m_vg_v \\ W_v=2.04(8.87) \\ W_v=18.09\text{ N} \end{gathered}[/tex]Mass of the bag of sugar on the Earth = 2.04 kg
Mass of the bag of sugar on the moon = 2.04 kg
Mass of the bag of sugar on venus = 2.04 kg
What was the tension in the cable when the craft was being lowered to the seafloor?.
Answers
Assuming that the "craft" refers to an early submersible craft, the tension in the cable, when it was being lowered to the seafloor, would be the tension when it was stationary minus the drag force.
Say, for example, the tension in the cable when an early submersible craft was 7000 N. When the craft was either lowered to or raised from the seafloor at a steady raid, the motion in through the water it experienced added a 1500 N drag force.
When it's being lowered, the tension in the cable would be the difference between the two forces = 7000 N - 1500 N = 5500 N.
When it's being raised, the tension in the cable would be the sum of the two forces = 7000 N + 1500 N = 8500 N.
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Please help me, I am following along diligently. V(t) = t^2 -9t+18, with distance, s measured in meters, left or right of 0, and t measured in seconds, with t between 0 and 8 seconds inclusive. The position at time t=0 sec is 1 meter right of 0, that is s(0)= 1Part I: Average velocity over the interval 0 to 8 secondsPart II: The instantaneous velocity and speed at time 5 secsPart III: The time intervals when the particle is moving rightPart IV: The time intervals when the particle is going faster, and slowing downPart V: Total distance the particle has traveled between 0 and 8 seconds
Answers
Given that the velocity at any time t is
[tex]v(t)=t^2-9t+18[/tex]Also, the time interval is from t = 0 to t = 8 seconds
The position at time t = 0 s is s(0) = 1 m towards right of zero.
The initial time is t = 0 s, so the initial velocity will be
[tex]\begin{gathered} v_i(t=0)=0^2-9\times0+18\text{ } \\ v_i(0)\text{ = 18 m/s} \end{gathered}[/tex]The final time is t = 8 s, so the final velocity will be
[tex]\begin{gathered} v_f(t=8)=8^2-9\times8+18 \\ v_f(8)\text{ = 64-72+18} \\ =\text{ 10 m/s} \end{gathered}[/tex]The average velocity will be
[tex]\begin{gathered} v_{av}=\frac{v_i+v_f}{2} \\ =\frac{18+10}{2} \\ =14\text{ m/s} \end{gathered}[/tex]Thus, the average velocity is 14 m/s.
Part II:
The instantaneous velocity at time t =5 s will be
[tex]\begin{gathered} v(t=5)=5^2-9\times5+18 \\ =25-45+18 \\ =-2\text{ m/s} \end{gathered}[/tex]The instantaneous speed is the magnitude of instantaneous velocity.
Thus, the instantaneous speed will be 2 m/s.
Part III:
The particle will move towards the right when v(t) > 0
The time intervals will be
[tex]\begin{gathered} t^2-9t+18>0 \\ t^2-6t-3t+18>0 \\ t(t-6)-3(t-6)>0 \\ (t-6)(t-3)>0 \\ t-6>0\text{ or t>6} \\ t-3>0\text{ ot t>3} \end{gathered}[/tex]Thus, time intervals are t > 3 and t > 6 when the particle is moving towards the right.
Part IV :
The particle will move faster if the acceleration, a(t) > 0
The particle will slow down if the acceleration, a(t) < 0
So, first, we need to find the acceleration, it can be calculated as
[tex]\begin{gathered} a(t)=\text{ }\frac{d(v(t))}{dt} \\ =\frac{d(t^2-9t+18)}{dt} \\ =2t-9 \end{gathered}[/tex]For the particle moving faster,
[tex]\begin{gathered} a(t)>0 \\ 2t-9>0 \\ 2t-9+9>9+0 \\ 2t>9 \\ \frac{2t}{2}>\frac{9}{2} \\ t>\frac{9}{2} \\ t>4.5\text{ s} \end{gathered}[/tex]For particle slowing down,
[tex]\begin{gathered} a(t)<0 \\ 2t-9<0 \\ 2t-9+9<9+0_{} \\ 2t<9 \\ \frac{2t}{2}<\frac{9}{2} \\ t<4.5\text{ s} \end{gathered}[/tex]The total distance can be calculated as
[tex]\begin{gathered} s(t)=\int ^8_0v(t)dt \\ =\text{ }\int ^8_0(t^2-9t+18)\mathrm{d}t \\ =\lbrack\frac{t^3}{3}\rbrack^8_0-9\lbrack\frac{t^2}{2}\rbrack^8_0+18\lbrack t^{}\rbrack^8_0 \\ =\frac{1}{3}\lbrack512-0\rbrack-9\lbrack64-0\rbrack+18\lbrack8-0\rbrack \\ =\text{ 170.67-576+144} \\ =-261.33\text{ m} \end{gathered}[/tex]Here, the negative symbol indicates it is towards the left from zero.
wave is approaching the beach. As the wave travels from
the deep ocean to the shore where it is shallower, which of the following will be a
result? Circle all that apply.
a. The wave will have a longer wavelength.
b. The wave will have a lower frequency.
c. The wave will have a higher velocity.
d. The wave will have a greater amplitude.
Answers
As the wave travels from the deep ocean to the shore where it is shallower, the following which will be a result include the following:
a. The wave will have a longer wavelength.
b. The wave will have a lower frequency.
What is a Wave?This is referred to as the propagation of disturbances which carries energy without a net movement of the particles.
Wavelength and frequency have an inverse relationship and we were told that the wave traveled from the deep ocean to the shore means it has a long wavelength which therefore means that it will also have a low frequency.
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Which of the following accurately describes a property of an insulator?
a. An insulator will inhibit the flow of neutrons,
b. An insulator will inhibit the flow of electrons.
c. An insulator will allow the flow of neutrons.
d. An insulator will allow the flow of electrons.
Answers
A rock is placed into a graduated cylinder and the volume of water increases from 50 ml to 60 ml. If the rock has a mass of 25 grams, what is its density?
Answers
The density of the rock, having a mass of 25 grams which increases the volume of water from 50 mL to 60 mL is 2.5 g/mL
How do I determine the density of the rock?To obtain the density of the rock, we must know the volume of the rock. The volume of the rock can be obatined as follow:
Volume of water = 50 mL Volume of water + rock = 60 mL Volume of rock =?Volume of rock = (Volume of water + rock) - volume of water
Volume of rock = 60 - 50
Volume of rock = 10 mL
Now, we shall determine the density of the rock. This is illustrated below:
Volume of rock = 10 mL Mass of rock = 25 grams Density of rock = ?Density = mass / volume
Density of rock = 25 / 10
Density of rock = 2.5 g/mL
Thus, we can say that the density of the rock is 2.5 g/mL
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an electron is traveling radially toward a wire carrying current to the left. what direction is the force felt by the electron?
Answers
A negatively charged particle is an electron. They are only weakly connected to the metal atoms that make up the wire, which allows them to migrate through the wire.
What direction is the force pushing the wire in?Fleming's left-hand rule determines the direction of force exerted on a current-carrying wire when it is placed in a magnetic field. It always runs counter to the direction of the magnetic field and electric current.
How are the magnetic field's direction and the force acting on a wire carrying current related?According to the right-hand rule, the magnetic force acting on a wire carrying current is perpendicular to both the wire and the magnetic field.
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A wave has a velocity of 24 m/s and a frequency of 4.3 Hz. What is the wavelength of the wave? (type your answer including your units.
Answers
Taking into account the definition of wavelength, frecuency and propagation speed, the wavelength of a wave with a frequency of 4.3 Hz and a velocity of 24 m/s is 5.581 m.
WavelengthWavelength is the distance between two points corresponding to the same phase in two consecutive waves. It is expressed in units of length (m).
FrequencyFrequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
Propagation speedThe propagation speed is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.
The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f×λ
Wavelength of the wave in this caseIn this case, you know:
v= 24 m/sf= 4.3 Hzλ= ?Replacing in the definition of propagation speed:
24 m/s= 4.3 Hz× λ
Solving:
λ= 24 m/s÷ 4.3 Hz
λ= 5.581 m
In summary, the wavelength of the wave is 5.581 m.
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A force of F= 45 N is used to drag a crate 3 m across a floor.
Answers
ANSWER:
(a) 108 J
(b) 0 J
(c) 108 J
STEP-BY-STEP EXPLANATION:
(a)
Express the relation between horizontal component of work done and force on the crate:
[tex]W_h=F_h\cdot d[/tex]Here Wh is the horizontal component of the work done on the crate and Fh is the horizontal component of force and d is the distance of the crate across the floor.
Replacing:
[tex]\begin{gathered} W_h=36\cdot3 \\ W_h=108\text{ J} \end{gathered}[/tex](b)
Express the relation between vertical component of work done and force on the crate:
[tex]W_v=F_v\cdot d[/tex]Here Wv is the vertical component of the work done on the crate and Fv is the vertical component of force and d is the distance of the crate across the floor.
Replacing:
[tex]\begin{gathered} W_h=27\cdot0 \\ W_h=0\text{ J} \end{gathered}[/tex](c)
Express the relation for total work done by the 45 N force:
[tex]\begin{gathered} W_{\text{total}}=W_h+W_v \\ \text{ replacing} \\ W_{\text{total}}=108+0 \\ W_{\text{total}}=108\text{ J} \end{gathered}[/tex]A rocket moves straight upward, starting from rest with an acceleration of 129. 4 m/s2. It runs out of fuel at the end of 4. 00 s and continues to coast upward, reaching maximum height before falling back to earth. Find the velocity the instant before the rocket crashes on the ground.
Answers
Velocity of rocket instant before the rocket as it crashes is 135.81 m/s.
What is Velocity?The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity.In essence, velocity is a vector quantity. It is the speed at which distance changes.It is the displacement change rate.Velocity can be defined as the rate at which something moves in a specific direction as the speed of a car driving north on a highway or the pace at which a rocket takes off.Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s), over change in time (t).To learn more about Velocity from the given link :
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What should be the nature of fuse wire?
Answers
Answer: a fuse wire is a wire of high resistance and low melting point.
you hold a bucket in one hand. in the bucket is a 540 g rock. you swing the bucket so the rock moves in a vertical circle 2.6 m in diameter. part a what is the minimum speed the rock must have at the top of the circle if it is to always stay in contact with the bottom of the bucket? express your answer to two significant figures and include the appropriate units.
Answers
The minimum speed at the bucket so the rock always stays in contact with the bottom of the bucket is 3.6 m/s.
When the bucket is at the top of the circle, two forces are working on the bucket. The force of gravity and the rope tension. If the rock must have at stay in contact with the bottom of the bucket the rope tension equal to zero (T = 0). All force in the vertical circle is equal as centripetal force.
∑F = Fc
T + w = Fc
0 + w = Fc
w = Fc
m × g = m × v²/R
g = v²/R
v² = gR
[tex]v = \sqrt{gR}[/tex]
where
Acceleration due to gravity = 9.8 m/s²Mass of the object = m (kg)R = radius of a circle (m)T = rope tension (N)w = weight of the object (N)v = velocity (m/s)Fc = centripetal force (N)From the problem, given
Mass of the rock = m = 540 grams = 0.54 kgDiameter circle = D = 2.6 mRadius of circle = R[tex]R = \frac{D}{2} = \frac{2.6}{2}[/tex]
R = 1.3 m
[tex]v = \sqrt{gR}[/tex]
[tex]v = \sqrt{9.8 \times 1.3}[/tex]
[tex]v = \sqrt{12.74}[/tex]
v = 3.6 m/s
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what happens to the brightness of light emitted by a light bulb when the current flowing through it increases?
Answers
A wide range of applied voltages will allow it to function; as the voltage rises, the current rises as well, making the light bulb brighter.
When the current rises, what happens to the bulb's brightness?The quantity of electrons passing through the circuit each second determines the current that runs across it. When employing batteries, raising voltage also causes the circuit's current to grow. When the brightness of the bulb rises, the current is seen to rise.
What takes place when there is current?When electric current runs, electrons pass through a conductor. All substances restrict the flow of electric current to some degree. Resistance is the name given to this quality.
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what is the magnitude of the force per meter of length on a straight wire carrying an 8.50- a current when perpendicular to a 0.80- t uniform magnetic field?
Answers
The magnitude of the force per meter of length on the straight wire is 6.8N.
The force on any current carrying conductor due to magnetic field is given as,
F = BiL
Where,
B is the magnetic field,
i is the current,
L is the lenght of the conductor. In this case it is asked for the force per unit length, so we will consider it as 1 meter.
Now, it is given that the magnetic field is 0.80T and the current is 8.50 A.
So, putting values,
F = 8.50 x 0.80
F = 6.8N.
The force per meter length on the wire is 6.8N.
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in terms of the torque needed to rotate your leg as you run, would it be better to have a long calf and short thigh, or vice versa?
Answers
Running torque is the amount of torque required by a device to maintain the constant angular velocity of a rotating part while in operation. This value provides important operating information for rotation machinery and must be determined through testing.
What is running torque ?Running torque is also known as "friction torque." It is the torque required to turn the nut or bolt while the nut is "loose." A locking nut's locking feature (typically a plastic insert or a distorted bore section of the threads that directly squeezes together on them) requires some effort to overcome.
Since torque value is an attempt to measure the stretch in a bolt as the rotary sliding wedge of the threads is applied to pull the two ends apart, any rotational resistance forces that are added, not directly applying the clamping force to the part, will skew the final result.
If you torque to 100 inlbs and it takes 30 inlbs of torque just to turn the nut because it's a lock nut, you'll only have applied 70 inlbs of "stretch" to the bolt when the wrench trips at 100 inlbs. So, if you measure 30 inlb while spinning the nut down before it clamps down, add it to the 100 inlb value, turn the wrench to 130, and you'll have the correct 100 inlb application to the bolt or stud.
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I already did part a and the magnitude for all the parts. I need help finding the direction.
Answers
b)
Given that,
A=10 N at 0°
B=20 N at 180°
As we can see these two vectors are in opposite directions.
Thus the resultant vector will be in the direction of the vector with the higher magnitude.
In vector addition we can write,
[tex]C=10\cos 0^0+20\cos 180^0[/tex]Where C is the resultant vector.
Thus magnitude of R will be equal to,
[tex]R=-10\text{ N}[/tex]The negative sign indicates that the direction of the C is along the negative x-axis.
Thus the magnitude of C is 10 N and the direction of the C is 180°
a)
Given,
A= 10 N at 0°
B=20 N at 0°
The the vector C is
[tex]C=10\cos 0^0+20\cos 0^0=30\text{ N}[/tex]The direction of R will be along the direction of these two vectors, as they are in the same direction.
Thus the magnitude of the vector C will be 30 N and the direction of the vector C is 0°
c)
Given,
A=10 N at 180°
B=20 N at 180°
Thus the vector C is
[tex]C=10\cos 180^0+20\cos 180^0=-30\text{ N}[/tex]The direction of the vector C will be along the direction of the negative x-axis, as these two vectors are along the negative x-axis.
Thus the magnitude of the vector C is 30 N and the direction of the vector C is 180°
d)
Given,
A= 10 N at 0°
B=20 N at 90°
The x-component of the vector C will be,
[tex]C_x=10\cos 0^0+20\cos 90^0=10\text{ }\hat{\text{i}}[/tex]The y- component of C will be,
[tex]C_y=10\sin 0^0+20\sin 90^0=20\text{ }\hat{j}[/tex]The magnitude of vector C is given by,
[tex]\begin{gathered} C=\sqrt[]{C^2_x+C^2_y}_{} \\ =\sqrt[]{10^2+20^2} \\ =22.36\text{ N} \end{gathered}[/tex]The direction of the vector C will be,
[tex]\begin{gathered} \theta=\tan ^{-1}\frac{C_y}{C_x} \\ =\tan ^{-1}\frac{20}{10} \\ =63.43^0 \end{gathered}[/tex]Thus the magnitude of C will be 22.36 N and the direction of C will be 63.43°
e)
Given that
A= 10 N at 90°
B=20 N at 0°
The x-component of the vector C will be
[tex]C_x=10\cos 90^0+20\cos 0^0=20\text{ }\hat{\text{i}}[/tex]The y-component of the vector C will be
[tex]C_y=10\sin 90^0+20\sin 0^0=10\text{ }\hat{j}[/tex]The magnitude of the vector C will be
[tex]\begin{gathered} C=\sqrt[]{C^2_x+C^2_y}_{} \\ =\sqrt[]{20^2+10^2} \\ =22.36\text{ N} \end{gathered}[/tex]The direction of vector C will be,
[tex]\begin{gathered} \theta=\tan ^{-1}\frac{C_y}{C_x} \\ =\tan ^{-1}\frac{10}{20} \\ =26.56^0 \end{gathered}[/tex]Thus the magnitude of the vector C will be 22.36 N and the direction of the vector C will be 26.56°
If the winch applies a force of 1200N, what is the rescuer and victim's [m=120kg]accceleration? make sure to draw a free body diagram of the rescuer and victim
Answers
The rescuer and victim's accceleration when 1200N of force is applied will be 0.2m/s².
forces in the y direction: upward force + down force
Due to the downward weight, this is bad. The weight of the people
W = mg
W = 120 kg × (-9.8 )m/s²
W = -1176 Nt
Force up. This is positive because the helicopter is lifting the two people.
F = 1200 Nt
∴ F + W = 24 Nt
The direction is positive, meaning that the people are being moved up.
∵ F = ma
24 Nt = 120 kg × a
acceleration (a) = 24 Nt / 120 kg = 0.2 m/s²
What is force?
A push or pull that an object experiences as a result of interacting with another object is known as a force.
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What change could be made in the setup in diagram 1 to increase the amount of force necessary to move the block of wood?
Answers
Answer:
Add mass or weight to the block, roughen the surface of the table or the bottom of the block, increase the surface area of the wood, etc.
The acceleration due to gravity on Mimas a moon on Saturn, is 0.066m/s^2 . Starting from rest how much time does it take for an object to fall 10m on Mimas?
Answers
The equation to obtain the vertical distance cobered by the object is,
[tex]h=ut+\frac{1}{2}gt^2[/tex]The acceleration due to gravity on saturn is 0.066 m/s2.
Plug in the known values,
[tex]\begin{gathered} 10\text{ m=(0 m/s)t+}\frac{1}{2}(0.066m/s^2)t^2 \\ t^2=\frac{2(10\text{ m)}}{0.066m/s^2} \\ t=\sqrt[]{303.03s^2} \\ \approx17.4\text{ s} \end{gathered}[/tex]Thus, the time taken by object to fall is 17.4 s.
A ball is projected upwards from a bridge and hits the ground 5 seconds after it was originally projected its initial velocity is 15 m/s and it’s final velocity is 34 m/s calculate the height of the bridge.Max height = 11.48 m
Answers
Given:
• Time, t =5 seconds
,• Initial velocity, u = 15 m/s
,• Final velocity, v = 34 m/s
Given that the ball is projected upwards from a bridge, let's find the height of the bridge.
Let's first find the height from the top of the bridge to the maximum height.
To find the height apply the formula:
[tex]v^2=u^2-2as[/tex]Where:
v is the final velocity = 0 m/s (velocity at max height).
u is the initial velocity = 15 m/s
a is acceleration due to gravity = 9.8 m/s²
s is the height.
[tex]\begin{gathered} 0^2=15^2-2(9.8)s \\ \\ 0=225-19.6s \\ \\ 19.6s=225 \\ \\ s=\frac{225}{19.6} \\ \\ s=11.48\text{ m} \end{gathered}[/tex]The distance from the bridge to the maximum height is 11.48 m.
Now, let's find the maximum height to the ground.
[tex]v^2=u^2+2as[/tex]Where:
v is the final velocity = 34 m/s
u is the initial velocity = 0 m/s (velocity at the top).
a is acceleration due to gravity = 9.8 m/s²
s is the maximum height.
Thus, we have:
[tex]\begin{gathered} 34^2=0^2+2(9.8)s \\ \\ 1156=19.6s \\ \\ s=\frac{1156}{19.6} \\ \\ s=58.9\approx59\text{ m} \end{gathered}[/tex]The maximum height is 59 meters.
To find the height of the bridge, we have:
Height of bridge = Maximum height - Distance from top of bridge to max height.
Height of bridge = 59m - 11.48m = 47.52 m
Therefore, the height of the bridge is 47.52 meters.
• ANSWER:
47.52 meters.
Which fact is true during a fission chain reaction?(1 point)The total number of protons will increase over time.The total number of protons will increase over time.The total number of protons will decrease over time.The total number of protons will decrease over time.The number of freely-moving neutrons decreases over time.The number of freely-moving neutrons decreases over time.The number of freely-moving neutrons increases over time.
Answers
Answer:
The number of freely moving neutrons decreases over time.
Explanation:
During a fission reaction, the total number of protons remains the same. In other words, the charge is conserved. It is the neutron number that decreases during a fission reaction.
Therefore, 'The number of freely moving neutrons decreases over time' is the correct answer.
can some help me find the slope of the line / graph?
Answers
The given points are
(0.47, 0.4905)
(0.52, 0.6867)
(0.58, 0.8829)
(0.64, 1.0791)
The formula for calculating slope is expressed as
slope = (y2 - y1)/(x2 - x1)
where
y2 and y1 are final and initial coordinates of y
x2 and x1 are final and initial coordinates of x
Picking these points from the given points, we have
when x1 = 0.52, y1 = 0.6867
when x2 = 0.58, y2 = 0.8829
slope = (0.8829 - 0.6867)/(0.58 - 0.52) = 0.1962/0.06
slope = 3.27
We would plot the corresponding x and y values on the line. The graph is shown below
A wheel of diameter 26 cm turns at 1500 rpm. How far will a point on the outer rimmove in 2.0 s?1) 3.1 m12) 41 m3) 90 m4) 180 m
Answers
Given,
The diameter of the wheel, d=26 cm=0.26 m
Therefore the radius of the wheel, r=d/2=0.13m
Time period, t=2.0 s
Frequency of the revolution, f=1500 rpm
1 relovution=2π radian.
Therefore the angular velocity is calculated as,
[tex]\omega=\frac{1500\times2\pi}{60}=157.1\text{ rad/s}[/tex]The angular velocity and angular displacement are related as,
[tex]\omega=\frac{\theta}{t}[/tex]On rearranging the above equation and substituting the known values,
[tex]\theta=\omega t=157.1\times2.0=314.2\text{ rad}[/tex]We can calculate how far the rim has moved by using the following relationship,
[tex]s=r\theta[/tex]Where 's' is the distance of the movement of the rim,
On substituting the known values in the above equation,
[tex]s=0.13\times314.2=40.8\text{ m}\approx41\text{ m}[/tex]Therefore the correct answer is option 2, 41 m
Aircraft carriers use catapults to launch jets from their deck. One such catapult accelerates a 18,900 kg aircraft from rest to 61 m/s in 3.3 s. What is the magnitude of the force (in N) required to do this?
Answers
Given that the mass of catapult, m = 18900 kg
The initial velocity is
[tex]v_o=\text{ 0 m/s}[/tex]As the body is at rest initially.
The final speed is
[tex]v_f=\text{ 61 m/s}[/tex]The time taken is t = 3.3 s
We have to find the force.
According to Newton's second law, the formula to calculate force is
[tex]\begin{gathered} F=\text{mass}\times acceleration \\ =m\times\frac{(v_f-v_o)}{t} \end{gathered}[/tex]Substituting the values, the force will be
[tex]\begin{gathered} F=18900\times\frac{61-0}{3.3} \\ =349363.63\text{ N} \end{gathered}[/tex]Thus, the force is 349363.63 N
PLEASE HELP WILL MARK BRAINLIEST IF YOU EXPLAIN HOW YOU GOT THE ANSWER!!!!
I NEED TO FIGURE OUT TENSION!!!
Answers
(a) The acceleration of the system is 28.55 m/s².
(b) The tension in the rope is 285.5 N.
What is the acceleration of the box?The acceleration of the box is determined by applying Newton's second law of motion as follows;
F(net) = ma
where
F(net) is the net force on the blockm is the mass of the blocka is the acceleration of the blockweight of 30 kg mass - force of friction due to 10 kg = tension in the rope
Fg - μmgcosθ = ma
(30 kg x 9.8 m/s²) - (0.1 x 10 kg x 9.8 x cos30) = 10a
294 - 8.49 = 10a
285.51 = 10a
a = 285.51/10
a = 28.55 m/s²
The tension in the rope is calculated as follows;
T = ma
T = 28.55 m/s² x 10 kg
T = 285.5 N
Thus, the acceleration of the system depends on the masses and force of friction on the blocks
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