Rolling the barrel is more work.
What is work?Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance traveled for a constant force directed in the direction of motion.
Work = force x distance. In units, Joules = Newtons x meters.
When a body is lift than angle is right angle so work done is zero as force and displacement is perpendicular while in case of rolling it is at theta angle so work is done in this case.
Rolling the barrel is more work.
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Stir the liquid occasionally to release the _______________.
Using the concept of thermodynamics, we got heat as an output when we stir the liquid occasionally.
Actually, according to the Clausius statement of the second law of Thermodynamics: Heat can transfer from a hot body to a cold body, but it cannot transfer from a cold body to a hot body unless any external work has been done on the system.
Thus when you stir a hot liquid, due to the phenomenon of the convection (It is a heat transfer process that can occur only in fluids), part of the heat from the hot liquid goes to the medium which you are stirring (Eg. spoon) and another part of heat flows to the surrounding which is at a room temperature. Thus due to these things heat energy is liberated at a higher rate
But when you went on to stir a cold liquid (let’s say it is at 19 °C), you are giving mechanical work on the system. As mentioned in the second law of Thermodynamics the heat gets transferred from cold liquid to the surrounding air (let's say 30 °C ) due to the work given (stir). But the transfer of heat is very small which could make the liquid warm only to a little amount due to which the temperature of the liquid increases (let’s say it is at 25 °C), and convection (heat transfer process in fluids. In here it is from a cold liquid to at air) also occurs a little amount. So to make this hot even more work has to be done on the system (cold liquid) if the system is closed the work to be done can also be reduced.
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a sample of a gas is compressible; i.e., its volume can be significantly decreased. this is because multiple choice question. there are attractive forces between particles in the gas phase, whereas in the liquid and solid phases there are not. particles in the gas phase are smaller than they are in the liquid and solid phases. particles in the gas phase are separated by relatively large distances.
A sample of a gas is compressible; i.e., its volume can be significantly decreased because the particles in the gas phase are separated by relatively large distances.
A gas is a substance that has no constant size or form. Whilst inside a closed container, gasoline will amplify to fill the field. An instance of gas is the air you breathe. The gas interior of your digestive tract is fabricated from the air and different gases.
Traits of Gases :
* Gases have neither definite shape nor particular volume. They expand to the dimensions of their container.
* Gases are fluid and go with the flow effortlessly.
* Gases have low density, except compressed.
* Gases diffuse (mix and unfold out) and effuse (tour thru small holes).
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A spring has a equilibrium length of 0. 100 m. When a force of 40. 0 n is applied to the spring, the spring has a length of 0. 140 m. What is the value of the spring constant of this spring?.
The value of the spring constant of this spring will be 50,000 N/m, which has a equilibrium length of 0.100m applied by 40N force.
Formula for the spring force is given as-
F = (1/2) kx²
where, F = force, k= spring constant and x = change in length of the spring.
Change in length of the spring = Changed length - equilibrium length
Change in length of the spring(x) = 0.140m - 0.100m = 0.040m
Putting the values as F = 40.0 N, x = 0.040m, k =?
F = (1/2) kx²
40 = (1/2) × k × (0.040)²
k = 80/0.0016
k = 50,000 N/m
Hence, the value of the spring constant of this spring will be 50,000 N/m.
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True or false. A small amount of mass can produce a large amount of energy
The satement is true.
This comes from the fact that, according to Einstein:
[tex]E=mc^2[/tex]and since c² is a very large number then, if we find a way to convert all the mass in energy a small amount will produce a large amount of energy.
The element magnesium has 12 electrons. In how many energy levels are the electrons of magnesium?
Answer: energy level 2
Explanation:
i did this before
Answer: Magnesim’s electrons are in 3 energy levels .
Explanation: since magnesium has 12 electrons and first shell can only accommodate up to 2 electrons , as shown in picture too, magnesium will have 2 electrons in this first shell or energy level.
Now about rest 10 electrons, 8 will be in 2nd energy level and remaining 2 will be valance electrons and will occupy 3rd shell.
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A 1000 n crate is lifted to a height of 3. 0 m. How much work is done to lift the crate?.
The work done in lifting a 1000 N crate 3.0 m high is 3000 Joules (J).
Here, we have been told that the mass of the crate is = 1000 N (i)
We have to lift up the crate to a height of = 3.0 m (ii)
The mass of the crate is given here in Newtons which is also the SI unit of Force.
We know that work is the product of force and distance moved in the direction of the force. The formula used for calculating the work done is
= W = Force * Distance moved (iii)
Using the values of (i), (ii) and putting them in the given formula (iii), we get = W = (1000)*(3)
= W = 3000 Joules
Therefore, we know that the work done in lifting a crate of mass/force to a height of 3.0 m is 3000 J.
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where is thermocouple thermometer used
Explanation:
Thermocouples are used in applications that range from home appliances to industrial processes, to electric power generation, to furnace monitoring and control, to food and beverage processing, to automotive sensors, to aircraft engines, to rockets, satellites and spacecraft.
At 2:00 p. M. Two cars start toward each other from towns 240 miles apart. If the rate of one car is 10 mph faster than the other, how fast does each car go if they meet at 5:00 p. M. ? if 3x represents the distance that the slower car traveled, then which expression represents the distance the faster car traveled? 3 x + 10 3 x + 30 3(240).
135 miles represents the distance the faster car traveled.
Just what is distance?Distance is an object's overall movement, regardless of direction. Regardless of an object's starting or ending point, distance can be defined as the amount of ground it has travelled.
If we call the slower vehicle's speed S, the other vehicle's speed is S + 10 mph.
They've been on the road for three hours as of 5:00 p.m. The faster car travels 3(S+10) miles, while the slower one travels 3S miles.
However, the sum of the two distances has to be 240 miles, so 3S+3(S+10)=240,
3S+3S+30=240,
6S=210, and
S=35 mph.
The faster vehicle travels at 45 mph. We can see that 3S is equal to 3x, which means that x=S=35 mph and that the faster vehicle travels 3×45=135 miles.
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34. What temperature in the graph below indicates that heat is being used to "break links" binding liquid molecules--that is, the region where the substance is vaporizing?Select one:a. 120°b. 80°c. 60°d. 20°
We know that in a change of state heat is used to break the links between the molecules or atoms of the substance but the temperature remains the same; in the graph shown we notice that we have two portions where the temperature remains constant 20° and 120°. Since vaporizing happens at greater temperature that solid to liquid change of state we conclude that the region where this happens is 120°; therefore, the answer is A.
An object is moving to the right at a constant velocity. What will happen if a force of 20 n starts acting on it in the opposite direction?.
If a force of 20 n begins acting on the object in the opposite direction, its velocity will rise.
What happens when things are moving at a constant speed?If there are no forces acting to accelerate or decelerate an object that is already moving with a constant speed, it will continue to move at that speed in a straight line. By defining force as a vector quantity, Newton helped to clarify the aforementioned statement.
Newton's first law of motion states that any object moving at a constant speed experiences no net external forces, so the total amount of forces acting on the object must be zero.
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A football is punted at an angle with a velocity of 29.2 m/s. If the ball has a total hangtime of 6.7 how long does it take to reach the top of the trajectory?
Answer:
So your gonna have to calculate the speed
Explanation:
How much work is done pushing a block 200 m with a force of 30 newtons?
During an autumn storm, a 0.012-kg hail stone traveling at 20.0 m/s made a0.20-cm-deep dent in the hood of Darnell's new car. What average force didthe car exert to stop the damaging hail stone?
Answer:
1200 N
Explanation:
First, we need to calculate how much time the force was applied. If the stone traveled at 20.0m/s and made a 0.20 cm deep dent, the time is equal to
[tex]\text{ Avg }speed=\frac{distance}{time}\Rightarrow time=\frac{distace}{Avg\text{ }speed}[/tex]Where the distance is 0.20 cm = 0.0020 m and the average speed can be calculated as:
[tex]\text{ avg speed = }\frac{v_i+v_f}{2}=\frac{20\text{ m/s + 0 m/s}}{2}=10\text{ m/s}[/tex]Therefore, the time is equal to
[tex]time=\frac{0.0020\text{ m}}{10\text{ m/s}}=0.0002\text{ s}[/tex]Then, the force can be calculated using the following equation for impulse
[tex]\begin{gathered} Ft=mv \\ F=\frac{mv}{t} \end{gathered}[/tex]Where m is the mass, v is the speed and t is the time, so replacing m = 0.012 kg, v = 20 m/s and t = 0.0001 s, we get
[tex]F=\frac{0.012\text{ kg \lparen20 m/s\rparen}}{0.0002\text{ s}}=1200N[/tex]So, the average force was 1200 N
During autumn, the storm travels at a speed of 20 m/s, then the average force the car has to exert to stop the damaging hail storm is 1200 N.
What is Force?A force in physics is an effect that has the ability to modify an object's motion. A bulk object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can be used to describe force. Being a vector quantity, a force also has magnitude and direction. The SI unit of newton is used to measure it (N). The letter F symbolizes for force.
As per Newton's second law's original formulation, an object's net force is equal to the speed at which momentum is changing over time.
According to the given information in the question,
Speed, s= 20 m/s
Average speed, s = Distance/Time
s = [v(i) + v(f)] / 2
s = (20 + 0)/2
s = 10 m/s
Now calculate the time,
Time, t = 0.0020/10
t = 0.0002 seconds.
Use the equation for impulse,
f × t = mv
⇒f = mv/t
f= (0.012 × 20)/0.0002
f = 1200 N
Therefore, the force applied is 1200 N.
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two objects of identical mass begin from rest at the same height at the top of two different hills - hill a and hill b. the hills are inclined at two different angles. the objects are released from rest and slide to the bottom; resistance forces can be considered to be negligible. from which hill will the ball have the greatest speed at the bottom of the incline?
When two objects of identical mass begin from rest at the same height at the top of two different hills - hill a and hill b, then both of the balls will have the same speed at the bottom of the incline. It is because, earth provides same amount of gravity to both of the balls. Therefore both will have same speed.
In Physics, the relation between gravity and mass is described as that both mass and gravity are directly proportional to each other.
In other words, if an object has less mass it will experience lesser amount of gravity and vice versa.
In our case, we are provided with two balls having same mass, as both have same mass so both will experience same amount of gravity which means the gravity will have zero effect on the speed with which they move.
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What is the maximum speed at which a car can safely travel around a circular track of radius 142 meters if the coefficient of friction between the tires and the road is 1.07? Include units in your answer. Answer must be in 3 significant digits.
Given that the radius of the circular path is r = 142 m and the coefficient of the friction is
[tex]\mu=1.07[/tex]The condition for the car to travel safely is
Frictional force = centrifugal force
[tex]\mu mg=\frac{mv^2}{r}[/tex]Here, m is the mass of the car and the acceleration due to gravity is g = 9.8 m/s^2.
v is the maximum speed of the car.
[tex]\begin{gathered} v=\sqrt[]{ugr} \\ =\sqrt[]{1.07\times9.8\times142} \\ =38.58\text{ m/s} \end{gathered}[/tex]Object 1 has a mass (M1) and a velocity (V1). Object 2 has a mass half the size of object 1 and a velocity that is 3 times the speed, but in the opposite direction. They collide in a linear elastic collision. Find the final velocity of both objects in terms of M1 and V1. (reduce the final answer to one term, reduced as much as possible with no fractions or decimals in major divisions)
Mass of object 1 = m₁
Velocity of object 1, = u₁
The mass of object 2 is half that of object 1
m₂ = m₁/2
The velocity of object 2 is three times the speed of object 1 but in the opposite direction
u₂ = -3u₁
The final velocity of both object is represented by v
Applying the principle of momentum conservation
[tex]\begin{gathered} m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ \\ m_1u_1+\frac{1}{2}m_1(-3u_1)=m_1v_1+\frac{1}{2}m_1v_2 \\ \\ m_1u_1-\frac{3(m_1u_1)}{2}=\frac{2m_1v_1+m_1v_2}{2} \\ \\ \frac{2m_1u_1-3m_1u_1}{2}=\frac{2m_1v_1+m_1v_2}{2} \\ \\ -m_1u_1=2m_1v_1+m_1v_2 \\ \\ m_1v_2=-m_1u_1-2m_1v_1 \\ \\ v_2=\frac{-m_1(u_1+2v_1)}{m_1} \\ \\ v_2=-(u_1+2v_1) \\ \\ \end{gathered}[/tex]From the last equation, make v₁ the subject of the formula instead
[tex]\begin{gathered} v_2=-(u_1+2v_1) \\ \\ v_2=-u_1-2v_1 \\ \\ 2v_1=u_1-v_2 \\ \\ v_1=\frac{u_1-v_2}{2} \\ \\ \end{gathered}[/tex]how far could you pedal a bicycle at 15 km/hkm/h on the energy in 3.0 galgal of gas? (1 galgal of gas has a mass of 3.2 kgkg .)
The amount of effort or energy transferred over a given period of time is referred to as an object's mechanical power. The SI unit for mechanical power is WATT. It is a scalar number.
What does a gallon of gasoline cost?3.7855 litres
A gallon is equal to 3.785 liters, 128 fluid ounces, 4 quarts, 8 pints, or 16 cups in American measures.
What's the weight of a gallon of gas?A gallon of regular fuel (like gasoline) weighs six pounds, according to the Science and Technology Desk Reference. Contrarily, a gallon of water weighs around 8.4 pounds.
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How are testes and ovaries different?
The testicles are the female gonads, whereas the ovaries are the male gonads. The production of gametes is one of the special traits and functions of gonads.
What distinguishes the ovaries and testes?The gonads in males are the testes, whereas those in females are the ovaries. They both work to produce sex hormones and gametes (eggs and sperm). The ovaries are responsible for producing progesterone and estrogen as well as eggs. Sperm and the hormone testosterone are produced by the testes.
What features do ovaries and testes have in common?By secreting steroid hormones and creating gametes, adult testes and ovaries both perform crucial functions in the reproductive system (Hossain et al., 2012). The healthy growth of both the gonadal somatic cells and germ cells is necessary for gonadal functional maintenance and gametogenesis.
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QUESTION 4 A 200 kg rock lies on the surface of a planet with mass, M. The gravitational force, F exerted by the planet on the rock is 1200 N. The radius of the the planet is 700 Calculate the mass, M of the planet
4.4 kg is the mass, M of the planet.
m=200 kg
M=?
F= 1200 N.
r= 700m
G=6.674×10^−11
F=GMm/r²
M=Fr²/Gm
M=5.8×10^8/1.310^−8
M=4.4 kg
Mass is used in physics to express inertia, a fundamental characteristic of all matter. Essentially, it is a mass of matter's resistance to changing its direction or speed in response to the application of a force. The change that an applied force produces is smaller the more mass a body has. The kilogram, the unit of mass in the International System of Units, corresponds to 6.62607015 1034 joule seconds using Planck's constant (SI). One joule is produced by multiplying one kilogram by one square meter per second. The kilogram is determined by exact measurements of Planck's constant since the second and the meter have previously been defined in terms of other physical constants.
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Now, consider the special case where the block of mass m1 is not present. find the magnitude, t , of the tension in the rope. try to do this without equations; instead, think about the physical consequences.
Since the mass is not present, the tension in the rope T = 0 N.
What is tension in physics?Tension, in physics, is be defined to be the pulling force transmitted axially by the means of a string, a rope, chain, or similar object. The opposite of tension could be compression.
At the atomic level, when atoms/molecules are pulled apart from each other and gain potential energy with a restoring force still existing, the restoring force might create tension.
Tension is a pulling force since it is exerted when a mass being pulled by a rope or a similar object. If the mass is not present, then there is no tension (pulling force) exerted by the rope, hence T = 0 N.
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Electron cloud definition
ANSWER:
STEP-BY-STEP EXPLANATION:
[tex][/tex]The energy of the metal d orbitals _________ due to an increase in electrostatic repulsion?.
The energy of the metal d orbitals increases due to an increase in electrostatic repulsion.
What is electrostatic repulsion?Silica nanoparticles that are hydrophilic by themselves are not surface active. However, they establish a potent electrostatic contact with ionic surfactants, which influences the surface behavior of those substances. We describe the interactions between n-heptane and anionic surfactant solutions when hydrophilic silica nanoparticles are present. The utilized particles' sizes are 9 and 30 nm, and the surfactants are sodium dodecyl sulfate (SDS) and dodecyl benzene sulfonic acid (DBSA).
We demonstrate via experimental tensiometry that, in the presence of surfactants, nanoparticles maintain their non-surface-active nature, and that the surface activity of the surfactant directly rises with the concentration of nanoparticles. This phenomenon was explained by the electrostatic repelling contact between the molecules of anionic surfactant and the negatively charged nanoparticles.
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Hello, I needed help with the question boxes on what to fill in.
Given:
To find:
Fill in the blanks
Explanation:
1) Energy can undergo conversion, changing from one form to another. For example, a wind turbine converts the mechanical energy of the wind into electric energy in the power grid. This power grid can then be converted into thermal energy by an electric heater.
2) Solar panels generate electrical energy by taking radiant energy from the sun and having it undergo conversion. This process does obey the law of conservation of energy because energy isn't randomly created, but it is simply converted.
A baby elephant trots in a straight line along river. The horizontal position of the elephant in meters over time is shown below. Questions: 1. What is the displacement of the elephant between 8 s and 24 s ?2. What is the distance traveled by the elephant between 8s and 24s?
looking at the graph,
1) Displacement includes direction
Displacement from 8s to 16s = 15 - 6 = 9
Displacement fbetween 16s and 24s = 0 - 15 = - 15
Displacemet between 8s and 24s = 9 - 15
Displacemet between 8s and 24s = - 6m
2)
Distance does not include direction
from 8s to 16s,
distance travelled = 15 - 6 = 9 m
From 16s to 24s,
distance travelled = 15 - 0 = 15
Total distance between 8s and 24s = 9 + 15
Total distance between 8s and 24s = 24 m
Last question please help!!!!!
Answer:
it is true
Explanation:
Answer:
True, changes of heat can be Endothermic or Exothermic only.
Explanation:
Hi can someone help me please ,Let d= 1 for second part
2)
[tex]F=2.3097\cdot10^{48}\text{ Newtons}[/tex]Explanation
the electrostatic force between two forces is given by:
[tex]\begin{gathered} F=k\frac{q_1q_2}{d^2_{}} \\ where\text{ } \\ k\text{ is a constant}(in\text{ this case we n}eed\text{ asume k=1)} \\ q_1\text{ is the charge 1} \\ q_2\text{ is the charge }2 \\ \text{and d is the distance betw}en\text{ them} \end{gathered}[/tex]then, complete the table we need to use this equation
where
[tex]F=k\frac{q_1q_2}{d^2_{}}[/tex]k, q1 and q2 are ginven in the table, so
Step 1
Let
[tex]\begin{gathered} charge_1=\frac{1}{4} \\ charge_2=1 \\ \text{distance}=1 \end{gathered}[/tex]so,replace
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=1\frac{\frac{1}{4}\cdot1}{1_{}}=\frac{1}{4} \end{gathered}[/tex]hence, for tha row
[tex]\begin{gathered} \frac{1}{4}F_e \\ \end{gathered}[/tex]Step 2
now, do the same for the next Fe, so
b)Let
[tex]\begin{gathered} charge_1=1 \\ charge_2=\frac{1}{2} \\ \text{distance}=1 \end{gathered}[/tex]so,replace
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=1\frac{1\cdot\frac{1}{2}}{1_{}}=\frac{1}{2} \end{gathered}[/tex]hence, for tha row
[tex]\begin{gathered} \frac{1}{2}F_e \\ \end{gathered}[/tex]Step 3
now, do the same for the next Fe, so
c)Let
[tex]\begin{gathered} charge_1=1 \\ charge_2=\frac{1}{4} \\ \text{distance}=1 \end{gathered}[/tex]so,replace
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=1\frac{1\cdot\frac{1}{4}}{1_{}}=\frac{1}{4} \end{gathered}[/tex]hence, for that row
[tex]\begin{gathered} \frac{1}{4}F_e \\ \end{gathered}[/tex]Step 4
now, do the same for the next Fe, so
c)Let
[tex]\begin{gathered} charge_1=\frac{1}{2} \\ charge_2=\frac{1}{2} \\ \text{distance}=1 \end{gathered}[/tex]so,replace
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=1\frac{\frac{1}{2}\cdot\frac{1}{2}}{1_{}}=\frac{1}{4} \end{gathered}[/tex]hence, for tha row
[tex]\begin{gathered} \frac{1}{4}F_e \\ \end{gathered}[/tex]Step 5
now, do the same for the next Fe, so
c)Let
[tex]\begin{gathered} charge_1=\frac{1}{8} \\ charge_2=\frac{1}{4} \\ \text{distance}=1 \end{gathered}[/tex]so,replace
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=1\frac{\frac{1}{8}\cdot\frac{1}{4}}{1_{}} \\ F=1\frac{\frac{1}{32}}{1_{}}=\frac{1}{32} \end{gathered}[/tex]hence, for that row
[tex]\begin{gathered} \frac{1}{32}F_e \\ \end{gathered}[/tex]Step 6
find the electrostastic force betweeen electrons
let
[tex]\begin{gathered} q_1=q_2=-\text{1}.602\cdot10^{19}\text{ C} \\ k=9\cdot10^9\frac{Nm^2}{C^2} \end{gathered}[/tex]as the distance is not give, let's use
distance =1
replace in the formula
[tex]\begin{gathered} F=k\frac{q_1q_2}{d_{}} \\ F=9\cdot10^9\frac{Nm^2}{C^2}\frac{(^2-\text{1}.602\cdot10^{19}C)}{1_{}} \\ F=2.3097\cdot10^{48}\text{ N} \end{gathered}[/tex]therefore, the electrostaic force is
[tex]F=2.3097\cdot10^{48}\text{ Newtons}[/tex]I hope this helps you
Consider the diagram below, showing the locations of 6 people in front of a mirror.
Draw ray lines to show:
a. Whose image is person A able to see?
b. Whose image can’t person B see?
Answer: b and c
Explanation: most scientific naswer
what is the apparent weight of a 95 KG astronaut on this rocket
Given:
• Acceleration of rocket = 28.0 m/s²
,• Mass of astronaut = 95 kg
Let's find the apparent weight of the astranaut.
In a direct rocket motion, as we are coming towards the Earth the weight reduces while as the rocket is going up, you feel more weighted.
Now, to find the apparent weight of the astranaut, apply the formula:
[tex]A_w=m(g+a)[/tex]Where:
Aw is the apparent weight
m is the mass = 95 kg
g is acceleration due to gravity = 9.8 m/s²
a is the acceleration of the rocket = 28.0 m/s²
Thus, we have:
[tex]\begin{gathered} A_w=95(9.8+28) \\ \\ A_w=95(37.8) \\ \\ A_w=3591\text{ N }\approx3.591\text{ kN} \end{gathered}[/tex]Therefore, the apparent weight of the astranaut is 3.591 kN
ANSWER:
3.591 kN
A climbing chain pulls a roller coaster with a force of 29,738N to the top of the roller coaster 102m high. How many joules of work has it done
Answer:
3,033,276 J
Explanation:
The work can be calculated as
W = Fd
Where F is the force and d is the distance.
Replacing F by 29,738 N and d by 102 m, we get:
W = (29,738 N)(102 m)
W = 3,033,276 J
Then, it has done 3,033,276 J
Conditions for uniform circular motion are constant speed and circular path. (True or false)
Uniform circular motion is a motion that is uniform in terms of speed and circular in terms of its path.
Uniform means constant speed and its path is circular.
Thus, the statement is true.