help please will give brainly if right

Answer:

The particles' kinetic energy is increased, allowing the gas to expand. When a gas is heated the volume will increase when gas is increased....

Answer:

Explanation:

We shall find volume of gas at NTP or at 273 K , 760 mm of Hg .

Pressure of given gas = 1.06 x 760 mm of Hg less vapor pressure of water .

= 805.6 - 23.76 = 781.84 mm of Hg

For it we use gas law formula ,

P₁V₁ / T₁ = P₂V₂ / T₂

781.84 x 136.1 / ( 273 + 25 ) = 760 x V₂ / 273

= 128.26 mL .

= 128.26  x 10⁻³ L .

22.4 L of oxygen will have mass of 32 g

128.26 x 10⁻³ L of oxygen will have mass of 32 x 128.26 x 10⁻³ / 22.4 g

= 183.22 mg .

Answer:

D no. is the answer of your question

Answer:

Elecric charge/ Electricity  

Explanation:

Electric charge is the net gain or loss of electrons

I hope im right!!

Answer:

See explanation

Explanation:

In the periodic table, hydrogen is placed in group 1 for convenience. Hydrogen is not a metal, however, its common oxidation state is +1. It easily forms a univalent positive ion just like group 1 elements.

So, when hydrogen is combined with strongly electropositive metals such as sodium, lithium, etc, hydrogen accepts one electron and exhibits an oxidation state of -1 in those compounds.

Such compounds in which hydrogen is combined with strongly electropositive metals to give a binary compound is called a hydride.

Answer:

Less in the top

your well wisher

Answer:

6.46×10²² formula units

Explanation:

From the question given above, the following data were obtained:

Mass of MgCl₂ = 10.2 g

Number of formula units =?

From Avogadro's hypothesis,

1 mole of MgCl₂ = 6.02×10²³ formula units

But,

1 mole of MgCl₂ = 24 + (35.5×2) = 24 + 71 = 95 g

Thus, we can say:

95 g of MgCl₂ = 6.02×10²³ formula units

Finally, we shall determine the formula units in 10.2 g MgCl₂. This can be obtained as follow:

95 g of MgCl₂ = 6.02×10²³ formula units

Therefore,

10.2 g of MgCl₂ = (10.2 × 6.02×10²³) / 95

10.2 g of MgCl₂ = 6.46×10²² formula units

Thus, 10.2 g of MgCl₂ contains 6.46×10²² formula units

Answer:

gimme that chocky milk.....

Explanation:

Answer:

m i l k

Explanation:

Answer:

immiscible

Explanation:

Answer:

C. soluble

Explanation:

Remember that a substance that dissolves in a solvent is said to be soluble in that solvent. A substance that does not dissolve in a solvent is insoluble. Process of Dissolving: Solvent particles surround solute particles to form a solution in a process called solvation.

Answer:

A 70%

B 92%

C 87%

D 79%

Explanation:

This excercise is about dividing water by liquid.

Answer:

hope this helps

Explanation:

72

Answer:

B: Barnacles ride on a gray whale's back to obtain food, and the hale is not harmed.

Explanation:

I got it right on Edge.

Answer:

B

Explanation:

Answer:

c) 2-methylbut-1-enyl-benzene

Explanation:

From the information given:

Wittig reaction is essential for the creation of carbon-carbon bonds which results in the production of alkenes. The presence of the ketone compound ( 2-butanone) is because of its high electrophilic character of the carbonyl carbon. The reaction between 2-butanone with triethylamine in the presence of potassium salt is to catalyze the reaction. This reaction proceeds to yield the product 2-methylbut-1-enyl-benzene.

Answer:

(1) Cl₂ is the limiting reactant.

(2) 8.18 g

Explanation:

First we convert the given masses of reactants into moles, using their respective molar masses:

0.070 moles of Cl₂ would react completely with (2 * 0.070) 0.14 moles of Na. There are more Na moles than that, so Na is the reactant in excess while Cl₂ is the limiting reactant.

Then we calculate how many moles of NaCl are formed, using the limiting reactant:

Finally we convert NaCl moles into grams:

Answer and Explanation:

The molar mass of a substance is all of the weights from the elements combined.

So, we have the elements

CU, S, and [tex]O_{4}[/tex]

CU has a mass is 65

S mass is 32

O has a mass of 16, but there's 4 atoms of O, so we do 16 times 4, which is 64.

Now we add.

65 + 32 + 64 is 161.

So, the answer is 160, or answer choice A.

#teamtrees #PAW (Plant And Water)

Answer:

neutralization reaction

Explanation:

This reaction involve an acid (HCl) reacting with a base (NaOH), producing a salt (NaCl) and water. Therefore it's a neutralization reaction

Answer:

The correct answer is - 733.69 mg.

Explanation:

given:

The volume of ascorbic acid = 50 ml

The volume of NaOH = 20.74 ml

Molarity of NaOH = 0.201 M

formula = C6H8O6

Solution:

moles of NaOH for titration = molarity of NaOH × The volume of NaOH

= 0.201 × 20.74 × 10^-3

=4.16874 × 10^-3

then molecular weight of ascorbic acid

= 6 × 12+ 8×1+ 6× 16

=176g/mol

the molecular mass would be

= 4.16874 × 10^-3 × 176

= 733.69 × 10^-3 g

=733.69 mg

Answer:

Longer bonds have lower attractive force

Answer:

No

Explanation:

No, but the total mass of reactants must equal the total mass of products to be a balanced equation.

Example: Consider the following reaction ...

3H₂ + N₂ => 2NH₃ and 'amu' is atomic mass units (formula weights from periodic table)

In terms of molecules, there are 4 molecules on the left (3 molecular hydrogens (H₂) and 1 molecular nitrogen (N₂) and 2 molecules of ammonia on the right side of equation arrow. ∑reactant molecules ≠ ∑product molecules.

In terms of mass of reactants & mass of products, the 3H₂ + N₂ => 6amu + 28amu = 34amu & mass of products (2NH₃) => 2(14amu) + 6(1amu) = 34amu for sum of product masses.

∑mass reactants = ∑mass products <=> 34amu = 34amu.

The expression '∑mass reactants = ∑mass products' as applied to chemical equations is generally known as 'The Law of Mass Balance'.

Answer:

True

Explanation:

yes magnetic feild lines is always combined

Answer:

V = 5.97 L

Explanation:

Hello!

In this case, according to the ideal gas law:

[tex]PV=nRT[/tex]

We would need to solve for V as we know the temperature and pressure as the gas it at STP conditions (273 K and 1 atm respectively):

[tex]V=\frac{nRT}{P}[/tex]

Next, we compute the moles in 8 g of NO, given its molar mass of 30.01 g/mol:

[tex]n=\frac{8g}{30.01g/mol}=0.267mol[/tex]

Therefore, we obtain the following volume:

[tex]V=\frac{0.267mol*0.08206\frac{atm*L}{mol*K}*273K}{1atm}\\\\V=5.97 L[/tex]

Best regards!

Answer:

A. 0.027 M

B. 0.0054 M

C. 31 cm³

Explanation:

A. Determination of the final concentration (Molarity)

Initial Volume (V₁) = 27 cm³

Initial concentration (C₁) = 0.150 M

Final volume (V₂) = 150 cm³

Final congratulation (C₂) =?

C₁V₁ = C₂V₂

0.150 × 27 = C₂ × 150

4.05 = C₂ × 150

Divide both side by 150

C₂ = 4.05 / 150

C₂ = 0.027 M

Thus, the final concentration of the solution is 0.027 M

B. Determination of the final concentration (Molarity)

Initial Volume (V₁) = 35.71 cm³

Initial concentration (C₁) = 0.0756 M

Final volume (V₂) = 500 cm³

Final congratulation (C₂) =?

C₁V₁ = C₂V₂

0.0756 × 35.71 = C₂ × 500

Divide both side by 500

C₂ = (0.0756 × 35.71) / 500

C₂ = 0.0054 M

Thus, the final concentration of the solution is 0.0054 M

C. Determination of the final volume.

Initial Volume (V₁) = 10 cm³

Initial concentration (C₁) = 0.155 M

Final congratulation (C₂) = 0.05 M

Final volume (V₂) =?

C₁V₁ = C₂V₂

0.155 × 10 = 0.05 × V₂

1.55 = 0.05 × V₂

Divide both side by 0.05

V₂ = 1.55 / 0.05

V₂ = 31 cm³

Thus, the final volume of the solution is 31 cm³