help meeeeeeeeeeeeeee pleaseeeeeee

The perimeter measures around 36 metre.

The perimeter refers to the area surrounding an object. For instance, your house has a fenced-in yard. The perimeter is the length of the fence. If the yard is 50 feet by 50 feet, your fence is 200 feet long.

While 12.74 rounds up to 13, 5.45 rounds down to 5. Recatangle created a total of four sides, two of which are identical in length to the other two (which is a poor way to explain it). There are two sides that are 13 inches long and two sides that are 5 inches long, which is the solution to this question. When added together, the perimeter would be 13+13+5+5.

As an expression,

2(13)+2(5)

=26+10

=36.

The perimeter is approximately 36 meters.

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In order to find the left, the method is

1. Divide the interval [0,50] in 99 intervals.

2. Multiply the length of the first interval by the image of the left side of that interval

3. Do the same with all of them

4. Sum all the 99 results

On the right side, just changes 2. to the right side of the interval.

After that process, you will obtain that, the left sum is -9798.99, and the right sum is -10001.01.

In sigma notation, the left sum is

The right sum is

The expression which is equivalent to fog(x), is

fog(x) = 3x² + 5

Given, the functions f(x) and g(x), as follows

f(x) = 3x + 2 and g(x) = x² + 1

Now, we have to find the fog(x),

fog(x) = 3( x² + 1 ) + 2

fog(x) = 3x² + 3 + 2

fog(x) = 3x² + 5

So, the value of fog(x) = 3x² + 5

Hence, the expression which is equivalent to fog(x), is

fog(x) = 3x² + 5

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Answer:

[tex] - 120[/tex]

that would be your answer thank you very much

Question:

Which point is on the graph of

A) (1,10)

B) (10,1)

C) (0,10)

D) (0,0)

Answer:

Remember that for any given point to be on the graph of a function, it has to satisfy the equation of such function.

Remember we can change

For

Let's check if point A satisfies this expression:

Because point A satisfies the equation, we can assure it is also on the graph of the function.

(You can check that any other option is incorrect because none of those points satisfy the equation of the function)

Answer:

$10.5/hr

Step-by-step explanation:

210/20=10.5

The coordinates of the midsegment are :

T ( 0 , 2 ) where x axis 0 and y axis is 2

S ( 8 , 0 ) where x axis is 8 and y axis is 0

R ( 0 , 6 ) where x axis is 0 and y axis is 6

All the points are mentioned in the first quadrant and

The coordinates of the midsegment are :

T ( 0 , 2 ) where x axis 0 and y axis is 2 this means we move 2 units from the origin towards right and 0 units from the x axis thus the y axis is 0

Similarly you can observe for the rest of the two points

S ( 8 , 0 ) where x axis is 8 and y axis is 0

R ( 0 , 6 ) where x axis is 0 and y axis is 6

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Answer:

24

Step-by-step explanation:

10 - 7(3 + 2) + 7²

10 - 7(5) + 49

10 - 35 + 49

10 - 35 = -25

-25 + 49 = 24

I hope this helps!

Answer:

Concept:

We will have to get the formula connecting the diameter and the cost

Step 1:

We will bring put two coordinates below as

To figure out the equation of the line, we will use the formula below

By substituting the values, we will have

Step 2:

To get the cost of a hubcap with a diameter of 20 inches , we will substitute x=20 in the equation below

Hence,

The final asnwer is

The FIRST OPTION is the right answer

Answer:

D

Step-by-step explanation:

Two of the same X's

The number of oatmeal cookies when Brenda ordered 12 dozen cookies from the bakery is 18.

Since Brenda ordered 12 dozen cookies from the bakery, the total number ordered will be:

= 12 × 12

= 144 cookies

Since 1/3 of them or peanut butter 1/6 of the cookies are ice 3/8 of the cookies are chocolate, the fraction for oatmeal will be:

= 1 - (1/3 + 1/6 + 3/8)

= 1 - 7/8

= 1/8

The oatmeal cookies will be:

= 1/8 × 144

= 18

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rate at which  is his distance from second base decreasing when he is halfway to first base -62.4ft/sec

When I see "at what rate", I know this question must come from

pre-Calculus, so I won't feel bad using a little Calculus to solve it.

-- The runner, first-base, and second-base form a right triangle.

   The right angle is at first-base.

-- One leg of the triangle is the line from first- to second-base.

  It's 90-ft long, and it doesn't change.

-- The other leg of the triangle is the line from the runner to first-base.

   Its length is  90-29T.  ('T' is the seconds since the runner left home plate.)

-- The hypotenuse of the right triangle is

        square root of [ 90² + (90-29T)² ] =

        square root of [ 8100 + 8100 - 4320T + 841 T² ] =

        square root of [ 841 T² - 5220T +16200  ]

We want to know how fast this distance is changing

when the runner is half-way to first base.

Before we figure out when that will be, we know that since

the question is asking about how fast this quantity is changing,

sooner or later we're going to need its derivative.  Let's bite the

bullet and do that now, so we won't have to worry about it.    

      Derivative of  [ 841 T² - 5220 T + 16,200 ] ^ 1/2 =

(1/2) [ 841 T² - 5220 T + 16,200 ] ^ -1/2 times (1682T - 5220) .

There it is.  Ugly but manageable.

How fast is this quantity changing when the runner is halfway to first-base ?

Well, we need to know when that is ... how many seconds after he leaves

the plate.

Total time it takes him to reach first-base = (90 ft)/(29 ft/sec) = 3.10344 sec .

He's halfway there when   T = (3.10344 / 2) = 1.5517 seconds.  (Seems fast.)

Now all we have to do is plug in 1.5517 wherever we see 'T' in the big derivative,

and we'll know the rate at which that hypotenuse is changing at that time.

Here goes.  Take a deep breath:

(1/2) [ 841 T² - 5220 T + 16,200 ] ^ -1/2 times (841T - 5220)  =

[ 841 T² - 5220 T + 16,200 ] ^ -1/2 times (1152T - 8640)  =

[841(1.5517)² - 4320(1.55175) + 16,200]^-1/2 times [1152(1.5517)-8640] =

[    2,025      -  8,100  +  16,200 ] ^ -1/2  times   [ 2,160 - 8640 ]  =

- 6480 / √10,125  =   - 62.4 ft/sec.

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Answer:

[tex]7a {b}^{3} [/tex]

Step-by-step explanation:

[tex]42 {a}^{5} {b}^{3} = 2 \times 3 \times 7 \times a \times a \times a \times a \times a \times b \times b \times b[/tex]

[tex]35 {a}^{3} {b}^{4} = 5 \times 7 \times a \times a \times a \times b \times b \times b \times b[/tex]

[tex]42a {b}^{4} = 2 \times 3 \times 7 \times a \times b \times b \times b \times b[/tex]

We see that 7, a, and b^3 are common factors, so the GCF is

[tex]7a {b}^{3} [/tex]

The given expression is represented in scientific notation as (1.77 × 10⁶).

What do we mean by scientific notation?

So, the given expression in scientific notation:

Therefore, the given expression is represented in scientific notation as (1.77 × 10⁶).

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Correct question?

2.2⋅10^6 −4.3⋅10^5 scientific notation

3589.9 m is the height at which air pressure equals 65% of the air pressure at the surface of the Earth

Given: the function P(h) =P₀ e^(-0.00012h)

When air pressure equals 65% of the air pressure at the surface of the Earth. That means P = 0.65P₀

Substitute P = 0.65P₀ into the function:

P(h) = P₀ e^(-0.00012h)

0.65P₀  = P₀ e^(-0.00012h)

Dividing both sides by P₀ gives:

0.65  = e^(-0.00012h)

Take ln of both sides (ln is the inverse of e):

ln 0.65 = -0.00012h

h = ln 0.65/ (-0.00012)

h = 3589.9 m

Therefore, the height at which air pressure equal 65% of the air pressure at the surface of the Earth is 3589.9 m. Option D is the answer

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Solution

we need to convert the following expression:

four less than half a number n

Then the best answer is:

Answer:

a = 16 - b - c

Step-by-step explanation:

8 = (a + b + c) ÷ 2

×2 on both sides to cancel out ÷

16 = a + b + c

- b - c to cancel out +

a = 16 + b + c

Solve for t using quadratic formula:

Where:

so:

We take the positive time, therefore:

Answer:

t = 3.988s

The object will hit the ground after approximately 3.988 seconds.

We can also say that the object will remain in the air for less than 4 seconds.

Answer:

Equation of the line is 6x−y+8=0.

So I think Its A

Step-by-step explanation:

I rlly hope it helps u lol

The standard form of the equation of the line

The equation of the line can be expressed in several forms. One of them is the standard form:

Ax + By = C

Where A, B, and C are constants, and x and y are the variables.

We have the equation:

Multiplying by 3:

Subtracting 4x:

Is the required standard form of the line

Answer:

That equals 99.9

Step-by-step explanation:

Answer:

[tex]g(2) = 9[/tex]

[tex]x = 1[/tex]

[tex]g(0) = 1[/tex]

[tex]g(x)=3^x[/tex]

Step-by-step explanation:

To find g(2), find the y-value when x = 2.

From inspection of the graph, g(2) = 9.

To find x when g(x) = 3, find the x-value when y = 3.

From inspection of the graph, g(1) = 3, so x = 1.

To find g(0), find the y-value when x = 0.

From inspection of the graph, g(0) = 1.

Therefore, we have determined the following ordered pairs:

The given graph is a graph of an exponential function.

General form of an exponential function:

[tex]f(x)=ab^x[/tex]

where:

The y-intercept is when x = 0.

As the y-intercept is 1, a = 1:

[tex]\implies g(x)=(1)b^x[/tex]

[tex]\implies g(x)=b^x[/tex]

To find the value of b, substitute one of the ordered pairs into the function and solve for b:

[tex]\begin{aligned}g(x)=b^x&\phantom{=}\\\implies g(2)=b^2&=9\\ \sqrt{b^2}&=\sqrt{9}\\b&=3\end{aligned}[/tex]

Therefore, the rule for the graphed function is:

[tex]\boxed{g(x)=3^x}[/tex]

ANSWER:

14

EXPLANATION:

Given that a number is multiplied by seven, and the product is increased by two, the result is one hundred.

Let's express this mathematically(equation).

Let the number be represented by X.

A number X is multiplied by seven = 7X

The product is increased by 2 = 7X + 2

The result is 100 = 7X + 2 = 100

We have:

7X + 2 = 100

Solve for X:

Subtract 2 from both sides:

7X + 2 - 2 = 100 - 2

7X = 98

Divide both sides by 7:

Therefore the number is 14

we will use the next formula to find the rate of change of the given interval

in our case

a=-3

b=6

then we substitute the values in the formula

The average rate of change is 10/9=1.11

10" tall

1) Gathering the data

2 weeks 5 weeks

18" tall 30" tall

2) Let's find the initial height of that sunflower since it is not a proportional growth we need to find it through a linear function.

(Since 30/5 = 6 and 18/2=9)

After finding the slope m, let's find the linear coefficient

y=mx +b

18 =2(4) +b

18= 8 +b

18-8=b

b=10

So the rule of that function is y=4x +10

3) Now we can find the initial height. Plugging x=0, where x is the number of weeks we have:

y = 4x +10

y=4(0) +10

y= 10

So the sunflower was 10" tall on the day it was planted.

Total cups of flour to be filled= 5 cups

Capacity of measuring cup = 1/2 cup

Number of times Marc need to fill the 5 cups with his measuring cup = 5 / (1/2)

The slopes of the rays of the absolute value function, y = -3·|x + 2| + 8 are 3 and -3

In an absolute value function, an algebraic expression is contained within an absolute value symbol.

The given absolute value function is; y = -3·|x + 2| + 8

The slope of the rays are found as follows;

The general form of the absolute value function is; f(x) = a·|x - h| + k

The vertex of the function is the point (h, k)

The slope of the function is a

Comparing the specified function, y = -3·|x + 2| + 8, to the general function, we get;

The vertex of the function is (h, k) = (-2, 8)

The slope of the rays of the function are; a = 3

Slope of the ray 1 = (8 - (-19))/(-2 - (-11)) = 3

Slope of ray 1 is therefore; 3

Slope of ray 2 = (8 - (-19))/(-2 - 7) = -3

The slope of the ray 2 is therefore; -3

The slope of the rays are; 3 and -3

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If Triangles ABC and DEF are similar. Side length AB is 2, side length AC is 4, and side length BC is 3 Side length DE is 1.34 then  length of  DF = 2.68 and length of  EF = 2.01

Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .

Given,

Triangles ABC and DEF are similar.

AB = 2

AC = 4

BC = 3

DE = 1.34

We need to find the length of DF and EF

Given that ABC and DEF are similar, therefore:

AB/DE = BC/EF = AC/DF

2/1.34=3/EF=4/DF

1.49=3/EF=4/DF

Now,

1.49=3/EF

EF=3/1.49

EF=2.01

1.49=4/DF

DF=4/1.49

DF=2.68

Hence, length of  DF = 2.68 and length of  EF = 2.01

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To determine the required slope intercept form, take the heartbeat as varible y and time as varible x.

Now select any two coordinates from the table.

Take (2,3) and (4,6).

Use the two point form,

Thus, y=1.5x is the requried form of the line.