help me please I want to learn how to solve this

Help Me Please I Want To Learn How To Solve This

Answers

Answer 1

SOLUTION

In this question, we are meant to find the slope of the line represented

by 5x - 12 y = 24.

Re-arranging the equation, we have: 12 y = 5x - 24

Dividing both sides by 12,

[tex]\begin{gathered} y\text{ = }\frac{1}{12}(\text{ 5x -24 )} \\ y\text{ = }\frac{5}{12}x\text{ - 2} \\ \text{CONCUSION: The slope of the line is }\frac{5}{12}\text{ ------OPTION J} \end{gathered}[/tex]


Related Questions

For the rectangle shown below, which can be used to find the value of x?A. 3^2 + x^2 = 15^2B. (x + 3)^2 = 15^2C. 3^2 + 15^2 = x^2D. 3 + 15 = x^2

Answers

Since the rectangle is composed of 2 right triangles, we can apply the Pythagorean theorem to one of the triangles:

c^2 = a^2 +b^2

Where:

c= hypotenuse (longest side) = 15

a & b = the other two legs of the triangle ( x , 3 )

Replacing:

15^2 = 3^2 + x ^2

Solve for x

225 = 9 + x^2

225-9 = x^2

216 = x^2

√216 = x

x= 14.69

So, to find the value of x, we can use:

A. 3^2 + x^2 = 15^2

Can you pls help me with this question thank you

Answers

The expression we have is:

[tex]2x+5[/tex]

In this expression, we have two terms: 2x and 5.

The elements in these terms are variables, coefficients, and constants.

A variable is a letter that can take different values, a coefficient is a number that accompanies the variable, and a constant is a number that does not have any variable next to it (its value will not change).

In this case:

2 is the coefficient,

x is the variable,

and 5 is the constant.

Answer: a) 5

A new model of shirt at the clothing store comes in 4 colors: black, white, red, and blue

Answers

The data provided of the 16 sold shirts can be used to count the frequency of each color.

The results are shown below:

White = 5

Black = 2

Blue = 4

Red = 5

We can check the total is 5 + 2 + 4 + 5 = 16

Now we are ready to draw the bar graph, where each color must have a height that equals its frequency.

✓ 2 ✓ 3 ✓4 Find the missing side length. Assume that all intersecting sides meet at right angles. Be sure to include the correct unit in your answer. 16 A 9 A 13 A Check PLUS EGEE E Com. Tune here to

Answers

the given diagram:

We have to find the value of DE

Since all the lines intersect at right angle

[tex]\begin{gathered} \text{Here, AC + DE = BF} \\ 5\text{ + DE =13} \\ DE=13-5 \\ DE=8\text{ ft} \end{gathered}[/tex]

Answer : DE = 8ft

Volume of the box with the cone shape cut out of it. What are the side lengths of the box and what is the volume of the box/cube only?

Answers

Answer:

Side length of the box: 6 cm

Volume of the box/cube: 216 cm³

Volume of the box without cone: 190.88 cm³

Explanation:

The sides of a cube are all equal, so in this case, the side length of the box is 6 cm.

Then, the volume can be calculated as

Volume = side x side x side

Volume = 6 cm x 6 cm x 6 cm

Volume = 216 cm³

To know the volume of the box with the cone shape cut of it, we need to calculate the volume of the cone with the following equation

[tex]Volume=\frac{1}{3}\pi r^2h[/tex]

Where π = 3.14, r is the radius and h is the height. The diameter of the cone is 4 cm, so the radius is

r = 4 cm/2 = 2 cm

Then, replacing r = 2 cm and h = 6 cm, we get

[tex]\begin{gathered} Volume=\frac{1}{3}(3.14)(2\text{ cm\rparen}^2(6\text{ cm\rparen} \\ Volume=\frac{1}{3}(3.14)(4\text{ cm}^2)(6\text{ cm\rparen} \\ Volume=25.12\text{ cm}^3 \end{gathered}[/tex]

Now, the volume of the box without the cone shape is

V = 216 cm³ - 25.12 cm³

V = 190.88 cm³

So, the answers are

Side length of the box: 6 cm

Volume of the box/cube: 216 cm³

Volume of the box without cone: 190.88 cm³

Target is having a sale on bath towels usually bath towels cost $15 today I paid only $12 what percent of the original price did I pay for the bath towels

Answers

80%

1) Since the prices on Target dropped from $15 to $12 to find the equivalent percentage of $12 in comparison to $15 we need to write down the following ratio:

[tex]\begin{gathered} 15----100\% \\ 12----x\% \\ \frac{15}{12}=\frac{100}{x} \\ 15x=12\cdot100 \\ \frac{15x}{15}=\frac{1200}{15} \\ x=80\% \end{gathered}[/tex]

Note that we cross multiplied that ratio and then on the second step we have divided both sides by 15.

2) Hence, I paid 80% of the original price that day

The pollution of Linton is 12 times as great as a pollution of Ellmore. The combine population of both sounds is 9,646 people. What is the population of Linton?

Answers

Explanation

[tex]\begin{gathered} 12x+x=9646 \\ 13x=9646 \\ x=\frac{9646}{13} \\ x=742 \end{gathered}[/tex]

The population of Linton is 742*12=8904

Answer

8904

What is the slope of LaTeX: f\left(x\right)=3x-1

Answers

To find the slope of the expression:

[tex]f(x)=y=3x-1[/tex]

We need to remember that this is the Slope-intercept Form of the line equation:

[tex]y=mx+b[/tex]

Where

m = slope

b is the y-intercept.

Therefore, the slope of the line equation above is m = 3.

Write an equation for a line perpendicular to y=-5x-3 and passing through the point (15,4)

Answers

[tex]y=\frac{1}{5}x+1[/tex]

1) We need to consider the fact that perpendicular lines described by linear functions have opposite and reciprocal slopes when compared to the original linear function.

2) So we can state that the perpendicular line to y=-5x-3 has a slope of :

[tex]m=\frac{1}{5}[/tex]

3) Now, the next step is to plug into the Slope-intercept form the following point (15,4) and then find the y-intercept:

[tex]\begin{gathered} y=mx+b \\ 4=\frac{1}{5}(15)+b \\ 4=3+b \\ 4-3=b \\ b=1 \end{gathered}[/tex]

4) Thus, the equation of a perpendicular line to the line described by the linear function y=-5x-3 is:

[tex]y=\frac{1}{5}x+1[/tex]

Arlene buys a phone case and charging cord for 15% off. The original cost of the phone case is $18. Her total discount is $4.20.Write and solve an equation to find the original price of the charging cord

Answers

The total discount in Arlene's purchase was 4.20, this includes the discount applied over both, the case and the charging cord. We already know the original price of the phone case, the discount applied and the value of the discount, use it to find the original price of the chargind cord:

[tex]\begin{gathered} 0.15(18+x)=4.20 \\ 18+x=\frac{4.20}{0.15} \\ 18+x=28 \\ x=28-18 \\ x=10 \end{gathered}[/tex]

The original price of the charging cord is $10

Rewrite barrel as a unit rate. hour O A. barrel/hour B. 10 barrels/hour O C. To barrel/hour OD. 1 barrels/hour

Answers

Then the correct answer is A. 5/8 barrel/hour

A committee has seven men and four women. If four people are selected to go to a conference, what is the chance that the group is two men and two women?

Answers

Given:

A committee has seven men and four women.

four people are selected to go to a conference

We will use the combinations as follows

the number of ways to choose the four people are:

[tex]7C4+7C3+7C2+7C1+7C0[/tex]

The rule of combinations is:

[tex]\text{nCr}=\frac{n!}{(n-r)!\cdot r!}[/tex]

so, the number of ways will be:

[tex]35+35+21+7+1=99[/tex]

The number of ways to make a group of two men and two women will be:

[tex]7C2=21[/tex]

So, the chance that the group is two men and two women =

[tex]\frac{21}{99}=\frac{7}{33}[/tex]

so, the answer will be 7/33

A biologist records the number and types of fish caught in a local lake during a 2-yearperiod. The biologist reports that 796 of the fish caught during this period were trout,whereas 43% of the fish caught were bass. These reports of the number of trout andbass at this lake are examples ofcumulative frequencies.percentile ranks.relative frequencies.smooth curves.

Answers

Record for the number and types of fish caught in a local lake during a 2-year

period

Fish caught during this period were trout = 796

Fish caught during this period were bass = 43%

Total percentile = 100%

Fish caught during this period were trout = 100 - percentage of fish caught during this period were bass

fish caught during this period were trout = 100 - 43 = 57%

Hence the reports of the number of trout and

bass at this lake are examples of percentile ranks

RIn this figure, sin ZQOP = cos 2and cos ZROQ = sin 2

Answers

So, Sin QOP = QP/OQ = OPPOSITE/ Hyp

Then, cos PQO = QP/OQ = Adjacent/ Hyp

Using the same logic, Cos ROQ = RO/OQ = Adj/Hyp

Then, sin QPO = RO/OQ = Opp/Hyp

Are The Ratios 2:4 and 1:3 equivalent?Yes or No

Answers

Equivalent ratios

The ratio 2:4 is equivalent to and 1:3 if both numbers are obtained by the same multiplication:

Since

1 x 2 = 2 and

3 x 2 = 6 (instead of 4)

then they are NOT equivalent

I would like to know the answer for this question it’s very confusing

Answers

As the first step, let us say that the velocity of the boat in relation to a fixed point in the map of this travel is equal to its velocity in relation to the water PLUS the water velocity in relation to the fixed point WHEN it is in the same direction (travel downstream), and MINUS when traveling in the opposite direction (upstream).

From this, we will remember the definition of velocity by:

[tex]V=\frac{\Delta S}{\Delta t}[/tex]

The ΔS is the distance ran by the boat, which is 60 miles. Δt is 4h for the upstream case, and 3h for the downstream case.

From this, we say that the value of V is for the boat in relation to the water (which is what we need here) and v for the water. Now, we have the following system of equations.

[tex]\begin{gathered} V-v=\frac{60}{4}=15 \\ V+v=\frac{60}{3}=20 \\ \\ V-v=15 \\ V+v=20 \end{gathered}[/tex]

Now, to proceed with the solution, we will sum up the equations, which will result in the following:

[tex]\begin{gathered} V-v+(V+v)=15+20 \\ 2V=35 \\ V=\frac{35}{2} \\ \\ V=17.5mph \end{gathered}[/tex]From the solution developed above, we are able to conclude that the rate of the boat in still water, what is the velocity the boat reaches in relation to the water, is equal to 17.5 miles per hour.

Photo attached. Total cost as function of x = Domain of total cost function =

Answers

1. Identify the given from the statements.

• Let the side of the square base= s

• Height of the rectangular box be= h

,

• Given that :

s^2h = 20ft^3

solving for sh: s^2h = 20

s^2=20/h

s*s/s = 20/h /s

s = 20/hs

• Therefore sh = 20/s

Expandingthe given statements , we learn that :

• Material cost for base per square foot = 20 cents

,

• Material cost for sides per square foot = 18 cents

,

• Material cost for the top per square foot = 14 cents

2. Calculate Total cost

Total cost = {(s^2*20) + 4(sh)*18 +s^2*14}cents

= 20s^2 + 72*20/s + 14s^2

=34s^2 + 1440/s

• Expressing Total cost in terms of x , let s = x .

• Then Total cost (x) = 34x^2 +1440/x

2. Calculating the domain of TC(x) =34x^2 +1440/x

x <0 or x> 0

Domain (-∞;0) U(0;∞)

Paxton did the following multiplication problem. Where should he put the decimal point in his product? 9.18 % 73 2754 64260 67014 6.701.4 67.014 6.7014 670.14

Answers

We have the multiplication of 9.18 * 7.3 and want to know where the decimal point has to be.

In the multiplication we have to sum the decimal position of the numbers and taht is the position of the decimal point of the result.

In this case, the decimal point of 9.18 is 2 places and for 7.3 is one place, so the final result will have 2+1=3 places. The decimal point has to be 3 places.

The number is 67014 and the decimal point is three places from rigth, 67.014

[tex] {a}^{12} {b}^{ - 9} \ \: {c}^{ - 6} [/tex]what is the answer ?

Answers

We have the following expression:

[tex](a^{12}b^{-9})\frac{c^{-6}}{\square}[/tex]

Now let's recall two properties of the exponents that will help to solve this exercise:

[tex]x^{-1}=\text{ }\frac{1}{x}\Rightarrow4^{-3\text{ }}=\text{ }\frac{1}{4^3}[/tex]

Then we have:

[tex]a^{12}c^6/b^9[/tex]

Now, we have all the exponents with positive sign

The base of the exponents is different (a,b and c), therefore there is no additional step we can take

Student became unresponsive. Closing the session

7. Find the value of x in the figure below. Justify your answer. 4 pts 20° (x - 15)° X = Reason:

Answers

Answer

x = 85°

Explanation

The image of this question shows that the two angles 20° and (x - 15)° both sum up to give a right angle (90°). So,

20° + (x - 15)° = 90°

20° + x - 15° = 90°

x° + 20° - 15° = 90°

x + 5° = 90°

x = 90° - 5°

x = 85°

Hope this Helps!!!

3(t - 24) = 8t - 4(t + 15)

Answers

We need to solve the equation:

[tex]3(t-24)=8t-4(t+15)[/tex]

Then:

[tex]\begin{gathered} 3(t-24)=8t-4(t+15) \\ 3t-72=8t-4t-60 \\ 3t-72=4t-60 \\ 3t-4t=-60+72 \\ -t=12 \\ t=-12 \end{gathered}[/tex]

Therefore, t=-12.

simplify: 9x^4-27x^6/3x^3

Answers

simplify: 9x^4-27x^6/3x^3​

we have the expression

[tex]\begin{gathered} 9x^4-\frac{27x^6}{3x^3} \\ \\ 9x^4-9x^{(6-3)} \\ 9x^4-9x^3 \end{gathered}[/tex]

we have the expression

[tex]\begin{gathered} \frac{9x^4-27x^6}{3x^3} \\ \frac{9x^4}{3x^3}-\frac{27x^6}{3x^3} \\ 3x-9x^3 \end{gathered}[/tex]

this is the answer

Kinsley measured a city park and made a scale drawing the scale of the drawing was 13 millimeters and 5 meters if the actual width of the soccer field is 65 meters how wide is the field in millimeters

Answers

Kinsley measured a city park

Scale of drawing : 13 milimeter and 5 meter

Actual width is 65 meter

Let the field in Milimeter is x

So,

[tex]\begin{gathered} 13\text{ milimeters and 5 meters=x milimeters and 65 meters} \\ \frac{13}{5}=\frac{x}{65} \\ \text{Apply cross multiplication} \\ x=\frac{13\times65}{5} \\ x=\frac{13\times13}{1} \\ x=169 \\ Park\text{in milimeters = 169} \\ So, \\ 13\text{ milimeters and 5 meters=169 milimeters and 65 meters} \end{gathered}[/tex]

Answer: 13 milimeters and 5 meters = 169 milimeters and 65 meters

Select all of the ordered pairs that are solutions to the equation y= -6x + 7

Answers

We must substitute each pair into our equation:

A. If we substitute point (1,1), we have

[tex]\begin{gathered} 1=-6(1)+7 \\ 1=-6+7 \\ 1=1 \end{gathered}[/tex]

then, this point is a solution.

B. If we substitute point (-1,1), we have

[tex]\begin{gathered} 1=-6(-1)+7 \\ 1=6+7 \\ 1=13\text{ !!!} \end{gathered}[/tex]

this means that this point is not a solution.

C. If we substitute point (-6,7), we have

[tex]\begin{gathered} 7=-6(-6)+7 \\ 7=36+7 \\ 7=43\text{ !!!} \end{gathered}[/tex]

this means that this point is not a solution.

D. If we substitute point (3,-11), we have

[tex]\begin{gathered} -11=-6(3)+7 \\ -11=-18+7 \\ -11=-11 \end{gathered}[/tex]

then, this point is a solution.

Therefore, the solutions are option A and D

Find the zeros of each function by using a graph and a table. f(x)=x^2+2x–24.

Answers

Explanation

Step 1

[tex]f(x)=x^2+2x-24[/tex]

Zeros

A(-6,0) B(4,0)

because

[tex]\begin{gathered} f(x)=x^2+2x-24 \\ f(-6)=(-6)^2+2(-6)-24=36-12-24=0 \\ f(4)=4^2+2\cdot4-24=16+8-24=0 \end{gathered}[/tex]

Step 2

table

[tex]\begin{gathered} (-6,0) \\ (4,0) \\ f(-1)=-1^2+2\cdot-1-24=1-2-24=-25 \\ (1,-25) \\ \end{gathered}[/tex]

I hope this helps you

1/4+3/8 in simplest term

Answers

[tex]\frac{1}{4}+\frac{3}{8}=\frac{1\cdot2+3\cdot1}{8}=\frac{5}{8}[/tex]

X-4-3-2-1012f(x)-6-4-1-2-5-8-16Which is a possible turning point for the continuousfunction f(x)?O(-3,-4)O (-2,-1)O (0,-5)O (1,-8)

Answers

Solution

[tex](-2,-1)[/tex]

The final answer

Option B

If f(5)=2 and g(5)=9, what is (f+g)(5)

Answers

Answer:

11

Step-by-step explanation:

You have an equation [tex]f(x)[/tex] and you set [tex]x=5[/tex], and the result is 2.

You have another equation [tex]g(x)[/tex] and you set [tex]x=5[/tex], and the result is 9.

Therefore, if you add both equations, represented by [tex](f+g)(x)[/tex], and you set [tex]x=5[/tex], the result is simply 2 + 9 = 11.

I have this question and I can’t figure it out

Answers

Hello!

First, let's remember about the integers numbers.

These numbers can be positive or negative (and include the number 0). The main characteristic is that these numbers don't have a decimal part.

Knowing it, we can say that are integers:

• -1,

,

• 0,

,

• 2,

,

• -2.

In the number line, we'll have:

I will show you a pic

Answers

Answer

The red line represents y = x + 1

The blue line represents y = 2x - 7

We can see that the two lines and equation intersect at (8, 9)

Solution

x = 8

y = 9

Explanation

The two equations are

y = x + 1

y = 2x - 7

To solve this graphically, we will plot the two equations on the same graph and the solution will exist at the point where the two lines meet.

To plot the lines for each of these equations, we will use intercepts to obtain two points on each line and then connect the two points to get each of the lines.

y = x + 1

when x = 0

y = x + 1

y = 0 + 1

y = 1

First point on the line is (0, 1)

when y = 0

y = x + 1

0 = x + 1

x = -1

Second point on the line is (-1, 0)

The two points are (0, 1) and (-1, 0)

y = 2x - 7

when x = 0

y = 2x - 7

y = 2(0) - 7

y = 0 - 7

y = -7

First point on the line is (0, -7)

when y = 0

y = 2x - 7

0 = 2x - 7

2x = - 7

Divide both sides by 2

(2x/2) = (-7/2)

x = -3.5

Second point on the line is (-3.5, 0)

The two points are (0, -7) and (-3.5, 0)

The graph of this question will now be presented under answer and the point of intersection will bw evident.

Hope this Helps!!!

Other Questions
39. Mice only store a small amount of energy from the the plants they eat. State what might happen to some ofthe remaining energy they obtain from their food. The term "sociocentric" is best thought of as the opposite of the term: DAC BAD.What is the length of BD?Round to one decimal place. A spring with a spring constant of 30.0N/m Is compressed 5.00m. What is the force that the spring would apply What was the relationship between henry viiis desire to divorce and the onset of the english reformation?. Find the x-intercept(s) and the coordinates of the vertex for the parabola y=x + 4x - 5. If there is more than one x-Intercept, separate them with commas.DD:x-intercept(s):5?vertex:00 c and 217 more is equal to 198 "The sum of 5 and a number results in 14." Line c passes through the points (3, - 5) and (6, 1) . Line d passes through the points (6, - 4) and (2, - 2) Find the slope of each line and determine whether lines c and d are parallel , perpendicular , or neither . Explain your answer ... Critical thinking and problem solving at Mr.neelys farm, there were 75 sheep and 60 cows what is the ratio number of cows to the number of sheep's at Mr.neelys farm Calculate the X value a. 4: 7 = x: 5x: 8 = 99 :5 Obtain the potential on the x-axis at x = 0 for the following point charge distributions on the x-axis: 200 C at x = 20 cm, -3 00 C at x = 30 cm and - 400 C at x = 40 cm. 1 2 3 4 -5 4 13 22 31 An elevator uses 100 000J of electrical energy to raise a load of 800 N through a height of 40m in a time of 20s. What fraction of the energy input was NOT transferred to the load? A) 32% B) 68% C) 80%D) 97% k= 12, r=4%, po=$10,000, n=25 using the compound interest formula 2.90change repeating decimal to fraction? select the features that would be compared. select all that apply. select the features that would be compared.select all that apply. photosynthetic pigments cytological features aspects of physiology type of motion type of nutrition morphological traits If 180 270 and S(A) = 4 then determine the exact values of cos(A) and tan(A) name three ways Indians resisted the division of their property