Heather invested $19,400 in a growth fund at 3.16% compounded quarterly for 9 years and 6 monthsA) calculate the maturity value of this amount at the end of the termB) Calculate the amount of compounded interest earned

Heather Invested $19,400 In A Growth Fund At 3.16% Compounded Quarterly For 9 Years And 6 MonthsA) Calculate

Answers

Answer 1

GIVEN:

We are given the details of an investment as follows;

Initial investment = $19,400

Interest rate = 3.16%

Period of investment = 9 years and 6 months

Required;

To use the information given to calculate

(a) The maturity value at the end of the term

(b) The amount of compound interest earned.

Step-by-step solution;

The formula applied in calculating the maturity value is as follows;

[tex]A=P(1+r)^t[/tex]

Where the variables are;

[tex]\begin{gathered} A=Maturity\text{ }value \\ \\ P=Initial\text{ }investment\text{ }(19400) \\ \\ r=rate\text{ }of\text{ }interest\text{ }(0.0316) \\ \\ t=time\text{ }in\text{ }years\text{ }(9.5) \end{gathered}[/tex]

However, for an investment whose interest is compounded at different intervals within 1 year, the formula becomes modified as shown below;

[tex]A=P(1+\frac{r}{n})^{tn}[/tex]

Where the variable n is the number of times interest is compounded annually. For an investment whose interest is compounded quarterly, that is, four times a year, the formula becomes;

[tex]A=P(1+\frac{r}{4})^{4t}[/tex]

We can now calculate as follows;

[tex]\begin{gathered} A=19400(1+\frac{0.0316}{4})^{4\times9.5} \\ \\ A=19400(1+0.0079)^{38} \\ \\ A=26161.6208681 \\ \\ A\approx26161.62 \end{gathered}[/tex]

We can now determine the amount of compound interest earned by deducting the initial amount invested from the maturity value. Thus we have;

[tex]\begin{gathered} Interest=A-P \\ \\ Interest=26161.62-19400 \\ \\ Interest=6761.62 \end{gathered}[/tex]

Therefore,

ANSWER:

[tex]\begin{gathered} Maturity\text{ }value=26,161.62 \\ \\ Interest=6,761.62 \end{gathered}[/tex]


Related Questions

Parts of a CircleFor this assignment, you will draw and label the parts of a circle. Follow the directions below to construct your circle. When you are finished, you may scan your drawing and upload it. If you do not have a scanner, you may take a picture with a digital camera or cell phone and then embed the image into a Word document.Draw circle A.Draw radius AB.Draw diameter CD.Draw chord EF.Draw central angle GAH.

Answers

It's important to consider that a radius is a segment from the center of the circle to the circumference, diameter is a segment that crosses the center of the circle and divides the circle into two equal parts, a chord is a segment that goes from one point on the circumference to another without intersecting the center of the circle, at last, a central angle is an angle formed by two radii and it has the center as the vertex.

First, let's draw circle A.

Second, let's draw radius AB.

Third, let's draw diameter CD.

Fourth, let's draw chord EF.

At last, let's draw angle GAH.

At East Zone University (Ezu) thereare 564 students taking College Algebra or English Comp . 454 are taking college Algebra ,148 are taking English Comp and 38 are taking both College Algebra and English Comp . How many are taking Algebra but Not English Comp?

Answers

Step 1: Write the information given in a set notation.

[tex]\begin{gathered} n(U)=564,U\Rightarrow\mleft\lbrace The\text{ entire students}\mright\rbrace \\ E\Rightarrow\mleft\lbrace e\text{nglish comp.}\mright\rbrace \\ C\Rightarrow\mleft\lbrace\text{college algebra}\mright\rbrace \\ \end{gathered}[/tex]

Step 2: State the number of students that partake in each subject.

[tex]\begin{gathered} n(C\cap E)=38 \\ n(C\cap E^{\prime})=454-38=416 \\ n(E\cap C^{\prime})=148-38=110 \\ n(C\cup E)^{\prime}=x \end{gathered}[/tex]

Step 3: Draw a Venn diagram showing the information above

Step 4: To find the number of students that College Algebra but not English comp., we will check for the number of students that take only College Algebra. This is shown below

[tex]n(C\cap E^{\prime})=416[/tex]

Hence, the number of students that are taking Algebra but Not English Comp is 416

Will give brainliest if someone answers this problem correctly

Answers

The equation of the line in fully simplified slope intercept form is y = -5x + 8.

From the graph:

Take any two points:

suppose (1,3) and (2,-2)

slope m = y2 - y1 / x2 - x1

= -2 - 3 / 2 - 1

= -5/1

= -5

substitute m and (1,3) in y = mx + c

3 = -5*1 + c

3 = -5 + c

c = 3+5

c = 8

y = mx+c

y = -5x + 8.

Therefore the equation of the line in fully simplified slope intercept form is y = -5x + 8.

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multiply or divide as indicated. be sure to reduce all answers to lowest terms. ( the numerator and denominator of the answer should not have any factors in common)

Answers

we have the expression

[tex]\frac{3a^2+3a}{a^2-36}\cdot\frac{a^2-6a}{12a}[/tex]

Simplify

we have that

a^2-36=(a+6)(a-6)

3a^2+3a=3a(a+1)

a^2-6a=a(a-6)

substitute in the given expression

[tex]\frac{3a(a+1)}{(a+6)(a-6)}\cdot\frac{a(a-6)}{12a}[/tex]

Simplify

[tex]\frac{(a+1)}{(a+6)}\cdot\frac{a}{4}[/tex]

therefore

the answer is

[tex]\frac{(a^2+a)}{(4a+24)}[/tex]

What rule describes a dilation with a scale factor of 1/2 and the center of dilation at orgin.

Answers

Explanation:

When we dilate a point by a scale factor "a" and the center of the dilation is the origin, the original point (x,y) changes as follows:

[tex](x,y)\rightarrow(ax,by)[/tex]

Each coordinate value is multiplied by the scale factor.

In this case, the scale factor is 1/2:

[tex]a=\frac{1}{2}[/tex]

Therefore, the transformation rule is:

[tex](x,y)\rightarrow(\frac{1}{2}x,\frac{1}{2}y)[/tex]

This rule is shown in option C.

Answer:

C.

[tex](x,y)\operatorname{\rightarrow}(\frac{1}{2}x,\frac{1}{2}y)[/tex]

f(x) = 4x - 3g(x) = x^3 + 2xFind (f-g)(4)

Answers

Given:

Two functions are given as below

[tex]\begin{gathered} f(x)=4x-3 \\ g(x)=x^3+2x \end{gathered}[/tex]

Find:

we have to find the value of (f - g)(4).

Explanation:

we will find the value of (f - g)(4) as following

[tex]\begin{gathered} (f-g)(x)=f(x)-g(x)=4x-3-(x^3+2x)=2x-x^3-3 \\ (f-g)(4)=2(4)-(4)^3-3=8-64-3=-59 \\ (f-g)(4)=-59 \end{gathered}[/tex]

Therefore, the value of (f - g)(4) = -59

Out of 200 people eating at a diner, 70% ordered sandwiches. How many people ordered sandwiches? Select one: 130 people

Answers

if 70% of 200 people ordered sandwiches then the number of people who ordered sandwiches

= 70% * 200

= 70/100 * 200

= 140 People

The 3rd option

. Noah may choose between two accounts in which to invest $4000. Account A offers 2.2% annual interest
compounded monthly. Account B offers continuous compound interest. Noah plans to leave his investment
untouched (no further deposits and no withdrawals) for 15 years.
(a) Which account will yield the greater balance at the end of 15 years?
(b) How much more money does Noah earn by choosing this more profitable account?
Answer:

Answers

Using the compound amount formula, account B will yield the greater balance at the end of 15 years and Noah earn $4 more money by choosing this more profitable account.

In the given question,

Noah may choose between two accounts in which to invest $4000.

Principal Amount(P) = $4000

Account A offers 2.2% annual interest compounded monthly.

Rate(r) = 2.2% = 0.022

In a year have twelve month so n=12

Account B offers continuous compound interest.

Noah plans to leave his investment untouched for 15 years.

Time(t) = 15

Formula for amount after t years = P(1+ r/n)^nt

Amount after 15 years = 4000(1+ 0.022/12)^12*15

Simplifying

Amount after 15 years = 4000(1+0.00183)^180

Amount after 15 years = 4000(1.00183)^180

Amount after 15 years = 4000*1.39

Amount after 15 years = $5560

Account B offers compounded continuously.

So formula used = Pe^(rt)

Amount after 15 years = 4000*e^(0.022*15)

Amount after 15 years = 4000*e^(0.33)

Amount after 15 years = 4000*1.391

Amount after 15 years = $5564

(a) We have to find which account will yield the greater balance at the end of 15 years.

As we can see in Account A amount after 15 years is $5550 and in Account B amount after 15 years is $5564.

So account B will yield the greater balance at the end of 15 years.

(b) We have to find how much more money does Noah earn by choosing this more profitable account.

Noah earn money more by profitable account=Account B amount-Account A amount

Noah earn money more by profitable account=$5564-$5560

Noah earn money more by profitable account=$4

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Part of the proceeds from a garage sale was $305 worth of $5 bills if there were ) more bills than $20 bills find the number of each denomination

Answers

We are asked how many $20 bills and $5 bills can make up $305. To do that we will first divide 305 and 20, like this:

Now, we need to find a number that when multiplied by 20 is the closest to 305, that number is 15, since:

[tex](15)(20)=300[/tex]

Therefore:

Now, subtract 300 from 305 and we get:

E:Given f(x) = log x and g(x) = -x + 1,which is the graph of (fog)(x)?-2-2COMPLETEThe domain of (fog)(x) isDONEX>0x < 0X > 1x <1

Answers

Given data:

The first function is f(x) = log x .

The second function is g(x) = -x + 1.

The expression for (fog)(x) is,

[tex]\begin{gathered} \mleft(fog\mright)\mleft(x\mright)=f(g(x)) \\ =f(-x+1) \\ =\log (-x+1) \end{gathered}[/tex]

The domain of the above function is x<1.

Rebecca was comparing various sizes of canned applesauce. A 16-oz can of one brand costs $7.78 and a 12-oz can of the same brand costs $6.85. Find the savings to thenearest cent on buying 96 ounces of applesauce in 16-oz. cans compared to 12-oz. cans.$6.98$7.87$8.12$9.06None of these choices are correct.

Answers

To do the comparison, we need to calculate the cost of buying 96 ounces using both options.

For 16-oz can

The number of cans required to get 96 ounces will be

[tex]\begin{gathered} \frac{96}{16} \\ =6\text{ cans} \end{gathered}[/tex]

The cost will be

[tex]\begin{gathered} 6\times7.78 \\ =46.68 \end{gathered}[/tex]

The cost of 96 ounces of applesauce in 16-oz cans is $46.68.

For 12-oz can

The number of cans required to get 96 ounces will be

[tex]\begin{gathered} \frac{96}{12} \\ =8\text{ cans} \end{gathered}[/tex]

The cost will be

[tex]\begin{gathered} 8\times6.85 \\ =54.80 \end{gathered}[/tex]

The cost of 96 ounces of applesauce in 16-oz cans is $54.80.

The savings on buying in 16-oz cans will be

[tex]\begin{gathered} 54.80-46.68 \\ =8.12 \end{gathered}[/tex]

The savings will be $8.12.

the radius of a circle is 1 what is the length of an arc that subtends an angle of 10pi/9 radians

Answers

To convert from radians to degrees, you have to know that 180 degrees is equal to one pi

[tex]\frac{10\text{ pi}}{9}\text{ = }\frac{10X180^{\circ}}{9}=200^{\circ}[/tex]

Angle 360 -200 = 160

[tex]\begin{gathered} lengthofarc=\frac{\emptyset}{360}X\frac{2\pi\text{ r}}{1} \\ =\text{ }\frac{160}{360}X\frac{2\pi\text{ X 1 }}{1} \end{gathered}[/tex]

length of arc =2.7925

The length of the arc is approximately 2.8

Which expressions simplify to a rational answer?Select each correct answer. 3√⋅2√52⋅−√2√9√⋅16−−√11−−√⋅5√

Answers

Among the given options, [tex]5\sqrt{2}.\sqrt{2}[/tex] and [tex]\sqrt{9}.\sqrt{16}[/tex] gives us a rational number.

The given options are -

1.  [tex]\sqrt{3}. \sqrt{2}[/tex]

2. [tex]5\sqrt{2}.\sqrt{2}[/tex]

3. [tex]\sqrt{9}.\sqrt{16}[/tex]

4. [tex]\sqrt{11} .\sqrt{5}[/tex]

Now, Considering the 1st option, that is,  [tex]\sqrt{3}. \sqrt{2}[/tex]

3 and 2, both are nonperfect squares,

[tex]\sqrt{3}. \sqrt{2} =\sqrt{6}[/tex] which is an irrational number.

Now, Considering the 2nd option, that is, [tex]5\sqrt{2}.\sqrt{2}[/tex]

[tex]5\sqrt{2}.\sqrt{2} = 5*2 = 10[/tex] which is a rational number.

Now, Considering the 3rd option, that is, [tex]\sqrt{9}.\sqrt{16}[/tex]

9 and 16, both are perfect squares,

So, [tex]\sqrt{9}.\sqrt{16} = 3*4 = 12[/tex] which is a rational number.

Considering the 4th option, that is,  

3 and 2, both are nonperfect squares, [tex]\sqrt{11} .\sqrt{5}[/tex]

[tex]\sqrt{11} .\sqrt{5} = \sqrt{55}[/tex] which is an irrational number.

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Answer correctly and I will give Brainly

Answers

Answer:

y= 5/6x+4

Step-by-step explanation:

you go up 5

over 6

so 5/6

then its already on positive 4 so its +4

Slope-intercept form is the form of a line where y equals the product of the slope and the input plus the y-intercept, or:

y = mx + b

[tex]m = \frac{y_2 - y_1}{x_2-x_1}\\m = \frac{9 - 4}{6-0}\\m = \frac{5}{6}[/tex]

b = 4

The final equation of the line is:

y = 5/6x + 4

Consider 4 consecutive odd integers. What is the sum of the 2nd and the 4th numbers if the first number is n?1. 2n+82.4n+123. n+64. 3n+6

Answers

4 consecutive odd integers

the next consecutive odd number is only 2 more than the first number so: n+2

n = first number

n + 2 = second number

n + 4 = third number

n + 6 = fourth number

the sum of the 2nd and the 4th numbers is:

n + 2 + n + 6 = n + n + 2 + 6 = 2n +8

2n + 8

Hence, option 1 is the correct answer

Ron made a scale drawing of a hotel the scale of the drawing was 7 inches and 5 feet the actual length of a room in the hotel is 20 ft how long is the room in inches

Answers

Given data:

The given lengthof room is R=20 ft.

Th

During World War I, mortars were fired from trenches 3 feet below ground level. The mortars had a velocity of150 ft/sec. Determine how long it will take for the mortar shell to strike its target.• What is the initial height of the rocket? -3 ft.• What is the maximum height of the rocket? 348.56 ft• How long does it take the rocket to reach the maximum height ? 4.68750 sec.• How long does it take the rocket to hit the ground (ground level)? 9.35 sec.• How long does it take the rocket to hit a one hundred feet tall building that is in it's downward path?[ Select]• What is the equation that represents the path of the rocket? Select]

Answers

[tex]\begin{gathered} y=-\frac{g}{2}t^2+v_0t+y_0 \\ g\text{ in feets per seconds is 32} \end{gathered}[/tex][tex]\begin{gathered} \text{Now the height of the bilding is 100 hence y must be 100, i.e., y=100, hence one has} \\ 100=-16t^2+150t-3 \\ or \\ -16t^2+150t-103=0 \\ \text{the solutions are given by:} \end{gathered}[/tex][tex]\begin{gathered} t_1=\frac{-150+\sqrt[]{150^2-4(-16)(-103)}}{2(-16)} \\ t_2=\frac{-150-\sqrt[]{150^2-4(-16)(-103)}}{2(-16)} \end{gathered}[/tex][tex]\begin{gathered} t_1=\frac{-150+\sqrt[]{22500-6592}}{-32} \\ t_1=\frac{-150+\sqrt[]{15908}}{-32} \\ t_1=\frac{-150+126}{-32} \\ t_1=\frac{24}{-32}\text{ This solution is negative, it doesnt work. Let us s}ee\text{ the other solution:} \end{gathered}[/tex][tex]\begin{gathered} t_2=\frac{-150-\sqrt[]{150^2-4(-16)(-103)}}{2(-16)} \\ t_2=\frac{-150-\sqrt[]{22500^{}-6592}}{-32} \\ t_2=\frac{-150-\sqrt[]{15908}}{-32} \\ t_2=\frac{-150-126}{-32} \\ t_2=\frac{-276}{-32} \\ t=\frac{276}{32} \\ t=8.6\text{seg} \\ It\text{ takes 8.6 second to hit the bilding} \end{gathered}[/tex][tex]\begin{gathered} \text{the general equation of the parabolic motion is }y=-\frac{g}{2}t^2+v_0t+y_0\text{. In this case, this is} \\ y=-16t^2+150t-3 \end{gathered}[/tex]

Find mZCEF if mZCEF= 2x + 30,mZDEC = x + 102, and mZDEF = 132°DEFA) 30°C) 410B) 29°D) 320

Answers

1) Gathering the data

m∠CEF=2x +30

m∠DEC=x+102

m∠DEF=132

2) From the picture we infer that

m∠DEF = m∠CEF+m∠DEC

132 = m∠CEF +x +102

132-x-102=m∠CEF

m∠CEF=30

-9(10-6r) help please

Answers

Given the expression :

[tex]-9\mleft(10-6r\mright)[/tex]

using the distributive property to simplify the expression :

[tex]\begin{gathered} -9\mleft(10-6r\mright) \\ =-9\cdot10-9\cdot-6r \\ =-90+54r \end{gathered}[/tex]

So, the result will be = -90 + 54r

is 53 prime or composite numberhow can I find the numbers for 58

Answers

Answer:

Factors of 58: 1,2,29 and 58

58 It is a composite number.

Step-by-step explanation:

The factors of 58 are the numbers that divide 58 leaving 0 as the remainder.

For example, 58/29=2, the remainder of 0.

Factors of 58: 1,2,29 and 58

58 It is a composite number.

Helppppppppppp test helppppp for today plssss help 6 and 7

Answers

7)

The triangles ABC and JGH are similar figures.

For two figures to be simmilar, the coresponding angles must be congruent and the corresponding sides must be proportional.

For these triangles:

The corresponding sides of the simimilar figures are proportional, you can express this as:

[tex]\frac{JH}{AC}=\frac{JG}{AB}=\frac{GH}{BC}[/tex]

This expression indicates that the proportion between the corresponding sides is the same for all three pairs of sides. Using this information, we can determine the value of side GH

The proportion between the corresponding sides of the triangles is:

[tex]\frac{JH}{AC}=\frac{5.8}{11.6}=\frac{1}{2}[/tex]

Now calculate GH as:

[tex]\begin{gathered} \frac{GH}{BC}=\frac{1}{2} \\ \frac{x}{6}=\frac{1}{2} \\ x=(\frac{1}{2})\cdot6 \\ x=3 \end{gathered}[/tex]

Now the corresponding angles of the similar figures must be congruent, i.e. have the same measure so that:

[tex]\begin{gathered} \angle A=\angle J=31º \\ \angle C=\angle H=59º \end{gathered}[/tex]

So a and y are

x=3

y=59º

Find the length of the arc in terms of pi. AB=

Answers

We will determine the arc length as follows:

*First: We transform the angle to radians:

[tex]\alpha=144\cdot\frac{\pi}{180}\Rightarrow\alpha=\frac{4}{5}\pi[/tex]

*Second: We will determine the arc length:

[tex]s=(10)(\frac{4}{5}\pi)\Rightarrow s=8\pi[/tex]

So, the arc length from A to B is 8*pi.

James received 60 texts yesterday. Of those texts 3/5 were from his friend Chris. Of the texts from Chris 1/3 referenced football. How many texts did James receive about football?

Answers

Out of the 60 texts that James recieved,

[tex]60\cdot\frac{3}{5}\cdot\frac{1}{3}=12[/tex]

12 were about football.

Determine the slope of the line represented by the equation: y=3/10x+6

Answers

The slope intercept form is given by the equation

[tex]\begin{gathered} y=mx+b \\ \text{where} \\ m\text{ is the slope} \\ b\text{ is the y-intercept} \end{gathered}[/tex]

Given:

[tex]y=\frac{3}{10}x+6[/tex]

Based on the given, it is already in the slope intercept form, and by inspection, we can determine the slope of the line is equal to 3/10.

Go5. Given functions f(x) = 9x – 2, g(x) = 5 – 3x/2, and h(x) = 4x – 7/4(a) Find g(-8).(b) Find the value of x that makes g(x) = -7.(c) Find the value of x that makes f(x) = g(x).(d) Find the value of x that makes f(x) = h(x)(e) Find the x-intercept of h(x).

Answers

Answer

a) g(-8) = 17

b) When g(x) = -7, x = 8

c) When f(x) = g(x), x = (2/3)

d) When f(x) = h(x), x = (1/20)

e) x-intercept of h(x) = (7/16)

Explanation

f(x) = 9x - 2

g(x) = 5 - 3x/2

h(x) = 4x - 7/4

(a) Find g(-8).

g(x) = 5 - 3x/2

g(-8) means the value of g(x) when x = -8

g(-8) = 5 - [3×-8/2]

= 5 - (-12)

= 5 + 12

= 17

(b) Find the value of x that makes g(x) = -7.

g(x) = 5 - 3x/2

When g(x) = -7,

5 - 3x/2 = -7

5 - (3x/2) - 5 = -7 - 5

-(3x/2) = -12

[tex]\begin{gathered} \frac{-3x}{2}=-12 \\ \text{Cross multiply} \\ -3x\text{ = 2}\times-12 \\ -3x\text{ = -24} \\ \text{divide both sides by -3} \\ \frac{-3x}{-3}=\frac{-24}{-3} \\ x\text{ = 8} \end{gathered}[/tex]

(c) Find the value of x that makes f(x) = g(x).

f(x) = 9x - 2

g(x) = 5 - 3x/2

When f(x) = g(x)

9x - 2 = 5 - (3x/2)

9x + (3x/2) = 5 + 2

(21x/2) = 7

[tex]\begin{gathered} \frac{21x}{2}=7 \\ \text{Cross multiply} \\ 21x\text{ = 2}\times7 \\ 21x=14 \\ \text{Divide both sides by 21} \\ \frac{21x}{21}=\frac{14}{21} \\ x=\frac{14}{21}=\frac{2}{3} \end{gathered}[/tex]

(d) Find the value of x that makes f(x) = h(x)

f(x) = 9x - 2

h(x) = 4x - 7/4

When f(x) = h(x)

9x - 2 = 4x - (7/4)

9x - 4x = 2 - (7/4)

5x = (1/4)

[tex]\begin{gathered} 5x=\frac{1}{4} \\ \text{Divide both sides by 5} \\ \frac{5x}{5}=\frac{1}{4\times5} \\ x\text{ =}\frac{1}{20} \end{gathered}[/tex]

(e) Find the x-intercept of h(x).

h(x) = 4x - 7/4

The x-intercept is the value of x when h(x) = 0

When h(x) = 0

4x - (7/4) = 0

4x = (7/4)

[tex]\begin{gathered} 4x=\frac{7}{4} \\ \text{Divide both sides by 4} \\ \frac{4x}{4}=\frac{7}{4\times4} \\ x=\frac{7}{16} \end{gathered}[/tex]

Hope this Helps!!!

The mean mark of 10 boys is 58.If the mean mark of 7 of them is 61, what is the mean mark of the remaining 3 boys

Answers

As for the 10 boys altogether,

[tex]\begin{gathered} \operatorname{mean}=58 \\ \text{and} \\ \operatorname{mean}=\frac{1}{10}\sum ^{10}_{i=1}\text{mark}_i \end{gathered}[/tex]

Thus,

[tex]\Rightarrow580=\sum ^{10}_{i=1}\text{mark}_i[/tex]

On the other hand, as for seven of the boys

[tex]\begin{gathered} \operatorname{mean}=61=\frac{1}{7}\sum ^7_{j=1}\text{mark}_j \\ \Rightarrow427=\sum ^7_{j=1}\text{mark}_j \end{gathered}[/tex]

Thus, regarding the remaining three boys,

[tex]\Rightarrow\sum ^3_{k=1}mark_k=580-427=153[/tex]

Finally, the mean of those remaining three kids is

[tex]\begin{gathered} \text{MEAN}=\frac{1}{3}\sum ^3_{k=1}mark_k=\frac{1}{3}\cdot153=51 \\ \Rightarrow\text{MEAN}=51 \end{gathered}[/tex]

Thus, the mean mark of the remaining 3 boys is 51

Which value is equivalent to -7?A. -(-7)B. |-71C. 171D.-|-71

Answers

Check Option A.

[tex]-(-7)=+7[/tex]

Not equivalent to -7.

Check Option B.to -7.

[tex]|-7|=7[/tex]

Not equivalent to -7.

Check Option C.

[tex]|7|=7[/tex]

Not equivalent to 7.

Check Option D.

[tex]-|-7|=-7[/tex]

Therefore, Option D is right.

find the slopes of the line that goes thru the following points

Answers

Given:

Find-: Slope of the line.

Sol:

The slope of line is:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Where,

[tex]\begin{gathered} (x_1,y_1)\text{ = First point} \\ \\ (x_2,y_2)=\text{ Second point} \end{gathered}[/tex]

Choose any point:

[tex]\begin{gathered} (x_1,y_1)=(-1,-4) \\ \\ (x_2,y_2)=(0,-1) \end{gathered}[/tex]

So, the slope of the line is:

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \\ m=\frac{-1-(-4)}{0-(-1)} \\ \\ m=\frac{-1+4}{0+1} \\ \\ m=\frac{3}{1} \\ \\ m=3 \end{gathered}[/tex]

Slope of line is 3.

These data are the number of on campus burglaries reported in a given year for nine western Pennsylvania universities.15 11 4 15 9 7 12 5 15For the data find the mean median mid range in the mall round to one decimal place if necessary.

Answers

Recall how to find the mean, the median, the midrange and the mode of a data set.

To find the mean, add all the values and divide the result over the amount of values:

[tex]\frac{15+11+4+15+9+7+12+5+15}{9}=\frac{93}{9}=10.333...\approx10.3[/tex]

To find the median, list the data from smallest to largest and identify the number that is placed at the middle of the list. If the number of data points is even, the median is the average of the two middle data points in the list:

[tex]4,5,7,9,11,12,15,15,15[/tex]

In this case, the median is 11 because there are 4 numbers before it and 4 numbers after it.

To find the midrange, calculate the mean between the minimum and maximum numbers of the data set:

[tex]\frac{4+15}{2}=9.5[/tex]

The mode is the value that appears most frequently in the data set. In this case, the number 15 appears three times and the rest just 1. Then, the mode is 15.

Therefore, the answers are:

Mean: 10.3

Median: 11

Midrange: 9.5

Mode: 15

Which equation represents a line which is parallel to y=0?A. x=1B. y=x+3C. y=xD. y=6

Answers

ANSWER

D. y = 6

EXPLANATION

Parallel lines have the same slope.

In this problem, the given line is y = 0, which is a horizontal line at y = 0. Because it is a horizontal line, its slope is 0. From the options, we have to find which line has a slope of 0.

• Option A: x = 1 is a vertical line passing through x = 1. Its slope is undefined → ,not parallel,.

,

• Option B: the slope of this line is 1 → ,not parallel.

,

• Option C: the slope of this line is also 1 → ,not parallel.

,

• Option D:, y = 6 is also a horizontal line, so its slope is 0 → ,this line is parallel ,to the given line.

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