graph the system of quadratic Inequalities. (please show how you find the points to graph)
Answers
Points you need to find to graph quadratic inequalities:
Vertex of each parabola:
1-Write each ineqaulity as an equation:
[tex]\begin{gathered} y=x^2-4x+8 \\ y=-x^2+4x+2 \end{gathered}[/tex]Vertex:
[tex]\begin{gathered} f(x)=ax^2+bx+c \\ x-coordinate\text{ of the vertex:} \\ x=-\frac{b}{2a} \\ \\ y-coordinate\text{ of the vertex:} \\ f(-\frac{b}{2a}) \end{gathered}[/tex]First equation: the leding coefficient is 1 then the parabola opens up.
Vertex of first equation:
[tex]\begin{gathered} x=-\frac{-4}{2(1)}=\frac{4}{2}=2 \\ \\ y=2^2-4(2)+8 \\ y=4-8+8 \\ y=4 \\ \\ \text{Vertex: (2,4)} \end{gathered}[/tex]Second equation: the leading coefficient is -1 then the parabola opens down.
Vertex of the second equation:
[tex]\begin{gathered} x=-\frac{4}{2(-1)}=\frac{-4}{-2}=2 \\ \\ \\ y=-(2)^2+4(2)+2 \\ y=-4+8+2 \\ y=6 \\ \\ \text{Vertex: (2,6)} \end{gathered}[/tex]Points of interception:
Equal the equations and solve x:
[tex]\begin{gathered} x^2-4x+8=-x^2+4x+2 \\ \\ x^2+x^2-4x-4x+8-2=0 \\ 2x^2-8x+6=0 \\ \\ \text{Quadratic formula:} \\ ax^2+bx+c=0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \\ \\ x=\frac{-(-8)\pm\sqrt[]{(-8)^2-4(2)(6)}}{2(2)} \\ \\ x=\frac{8\pm\sqrt[]{64-48}}{4} \\ \\ x=\frac{8\pm\sqrt[]{16}}{4} \\ \\ x=\frac{8\pm4}{4} \\ \\ x_1=\frac{8+4}{4}=\frac{12}{4}=3 \\ \\ x_2=\frac{8-4}{4}=\frac{4}{4}=1 \end{gathered}[/tex]The parabolas intersect in x=1 and x=3 (use one of the equations to find the y-value of the intersection):
[tex]\begin{gathered} y=1^2-4(1)+8 \\ y=1-4+8 \\ y=5 \\ \\ \text{point: (1,5)} \\ \\ y=3^2-4(3)+8 \\ y=9-12+8 \\ y=5 \\ \\ \text{point: (3,5)} \end{gathered}[/tex]Then, you have the next points:
Vertex: (2,4) opens up; (2,6) opens down
Intersection points: (1,5) and (3,5)
First parabola has the inequality sing > : the border line is a dotted line and the shadow area is under the parabola.
Second parabola has the inequality sing ≤ : the border line is a full line and the shadow area is over the parabola
Graph:
Related Questions
In a box there a total of four prizes: Two of them are worth $4, a single prize worth $26, and a single prize worth $241. A player will reach into the box and draw one of the prizes at random. What is the fair price for this game?
Answers
So,
First of all, the player has a 1/4 chance of drawing any of the 4 prizes.
This means that the probability of drawing a prize of $4 is 1/2 because there are 2 prizes worth of $4. The probability of drawing a prize of $26 is 1/4 and the probability of drawing a prize of $241 is also 1/4.
To find the fair price, we need to find the expected value of this problem:
This can be obtained by multiplying any possible value of a price for the probability of drawing a prize of that value and adding all these Hvalues together.
This is:
[tex]\begin{gathered} 4\cdot\frac{1}{2}+26\cdot\frac{1}{4}+241\cdot\frac{1}{4} \\ \\ =\frac{275}{4}=68.75 \end{gathered}[/tex]Therefore, the fair price of this game is $68.75.
The function f(x) = =+ 1 has a vertical asymptote atA. I = 0OB. I = 1OC. A=-1OD. f(x) = -1Reset Selection
Answers
The function is given to be:
[tex]f\left(x\right)=\frac{-4}{x}+1[/tex]The vertical asymptote is when the denominator is equal to 0. T
Therefore, we have the vertical asymptote to be at:
[tex]x=0[/tex]OPTION A is the correct option.
solving the formula for the indicated variable-s = lw + wh + lh, for whow do i start this problem?
Answers
The first step we need to take in order to solve the formula for w is changing the side of all the terms that have a w in it to the left side.
[tex]\begin{gathered} s=lw+wh+lh \\ s-lw-wh=lh \end{gathered}[/tex]Then we change switch all the terms that don't have w from the left to the right.
[tex]-lw-wh=lh-s[/tex]Since we have two terms on the left with a "w" we can factor then using the common term:
[tex]w(-l-h)=lh-s[/tex]Now we divide both sides by (-l-h).
[tex]\begin{gathered} w=\frac{lh-s}{-l-h} \\ w=\frac{-lh+s}{l+h} \end{gathered}[/tex]For an arch length s, area of sector A, and central angle θ of a circle of radius r, find the indicated quantity for the given value. r=4.28 ft, θ= 2.79, s=?
Answers
The area of a sector S follows the equation:
[tex]S=\frac{1}{2}r^2\theta[/tex]Where θ is the angle and r the radius.
In this case, we have:
• r = 4.28ft
,• θ = 2.79
We write:
[tex]\begin{gathered} S=\frac{1}{2}(4.28)^2\cdot2.79 \\ S\approx25.554168 \end{gathered}[/tex]Then, the answer, rounded up to two decimal places is
[tex]S=25.55[/tex]Mrs worthy estimate the weight of her puppy to be 20 pounds. The actual weight of the puppy is 25.4 pounds. what is the percent error of Mrs worthy estimation?round to the nearest tenth
Answers
Given data:
The estimate weight of the puppy is E=20 pound.
The actual weight is A=25.4 pounds.
The expression for the percentage error is,
[tex]e=\frac{A-E}{A}\times100[/tex]Substitute the given values in the above expression.
[tex]\begin{gathered} e=\frac{25.4-20}{25.4}\times100 \\ =\frac{5.4}{25.4}\times100 \\ =21.26 \end{gathered}[/tex]Thus, the percentage error is 21.26%.
A gold bar is similar in shape to a rectangular prism. A gold bar is approximately 7 1 6 in. x2 in. x 1 in. If the value of gold is $1,417 per ounce, about how much 8 2 is one gold bar worth? Use the formula w ~ 11.15n, where w is the weight in ounces and n= volume in cubic inches, to find the weight in ounces. Explain how you found your answer.
Answers
ANSWER and EXPLANATION
We want to find how much the gold bar is worth.
First, we have to find the volume of the gold bar.
The volume of a rectangular prism is:
[tex]\begin{gathered} V=L\cdot W\cdot H \\ L=\text{length;} \\ W=\text{width;} \\ H=\text{height} \end{gathered}[/tex]Therefore, the volume of the gold bar is:
[tex]\begin{gathered} V=6\cdot2\frac{7}{8}\cdot1\frac{1}{2} \\ V=6\cdot\frac{23}{8}\cdot\frac{3}{2} \\ V=25.88\text{ cubic inches} \end{gathered}[/tex]Now, convert the volume to weight y using:
[tex]\begin{gathered} w\approx11.15n \\ \text{where w = weight in ounces; n = volume in cubic inches} \end{gathered}[/tex]Therefore, its weight is:
[tex]\begin{gathered} w\approx11.15\cdot25.88 \\ w\approx288.56\text{ ounces} \end{gathered}[/tex]Finally, multiple the weght by the value of gold:
[tex]\begin{gathered} \text{Worth}=288.56\cdot1417 \\ \text{Worth}=\text{ \$}408,889.52 \end{gathered}[/tex]Therefore, the volume of the gold bar is about 25.88 in³, so the weight is approximately 288.56 ounces. So one gold bar is worth about $408,889.52
Find the area of a circle with a diameter of 15 units round your answer to the nearest whole
Answers
The area of the circle is 177 units^2
Explanation:Given:
diameter of the circle = 15 units
To find:
the area of the circle
The formula for the area of a circle = πr²
let π = 3.14
diameter = 2(radius)
radius = diameter/2
radius = 15/2 = 7.5 units
[tex]\begin{gathered} Area\text{ of the circle = 3.14}\times7.5^2 \\ \\ Area\text{ of the circle = 176.625} \\ \\ To\text{ the nearest whole number, the area of the circle is 177 units}^2 \end{gathered}[/tex]without using a calculator prove whether 1728 is a perfect cube
Answers
Since the prime factors of 1728 can be grouped into triples of equal factors, it is a perfect cube.
Given that every tenth person in line will get a coupon for a free box of popcorn at the movies what is the probability that you don't get a coupon when your in line
Answers
SOLUTION:
Step 1:
In this question, we are given the following:
Given that every tenth person in line will get a coupon for a free box of popcorn at the movies.
We are meant to find the probability that you don't get a coupon when you are in the line.
Step 2:
We can see that the probability that the person was in the line and got a coupon is:
[tex]\frac{1}{10}[/tex]Then, the probability that the person did not get a coupon when he was in the line is:
[tex](\text{ 1 -}\frac{1}{10})\text{ = }\frac{9}{10}[/tex]Math Literacy measurements G11 only do 5 and 6 both question are similar
Answers
Question 5:
If we divide the total length of the trip by the rate of consumption of the vehicle, we're going to find the amount of liters needed for the trip.
[tex]\frac{250}{9.4}=26.5957447...[/tex]This is the amount of liters needed.
Question 6:
Just as we did in the previous question, first we need to find the amount of liters needed for the trip.
[tex]\frac{2500}{33}=75.7575758...[/tex]Then, using the cost per liter, we can find the total cost of the trip:
[tex]\frac{2500}{33}\times20.20=1530.30303...[/tex]The trip is going to cost R1530.30.
Hello, how do I factorize this expression 1-36x^ { 2 } +y ^ { 2 } . Thanks :3
Answers
Solution:
Given the expression:
[tex]1-36x^2+y^2[/tex]To obtain the result of the factoring of the above expression, we factor out the common factor.\
In the above expression, there is no common factor.
Hence, the expression cannot be factored.
Calculate the average (mean) of the data shown, to two decimal placesx8.325.313.423.9129.312.31.4
Answers
Given the set of of data:
x
8.3
25.3
13.4
23.9
12
9.3
12.3
1.4
We are to find the average (mean).
To find the means of a set of data, we first add up the data and divide by the total number of data.
The Formular for mean (m)
Mean (m) = sum of the terms
number of terms
number of terms = 8
Mean (m) = 8.3 + 25.3 + 13.4 + 23.9 + 12 + 9.3 + 12.3 + 1.4
8
Mean (m) = 105.9
8
Mean (m) = 13.2375
Mean (m) = 13.24 ( two decimal places).
The table gives the temperature in degrees Fahrenheit in five cities at 6 AM on the same day used to table to answer the questions.
Answers
Looking at the table, the temperature in Boston at 6 AM is -8°F.
(a)
If the temperature had risen by 17°F at noon, then the new temperature is:
[tex]-8\degree F+17\degree F=9\degree F[/tex](b)
The 6 AM temperature in Toronto was -16°F, and -25°F in Fairbanks. The difference is:
[tex]-16\degree F-(-25\degree F)=-16\degree F+25\degree F=9\degree F[/tex]Choose all of the options below that are expressions.
5t +1
9+4t
16=t
2-17t
6-t
3t=0
Answers
Answer:
here are the answers
Step-by-step explanation:
5t +1 2-17 3t=0 so yeah those are the answers
I think?
a) Rotation, then reflectionb) Translation, then rotationc) Rotation, then translationd) Translation, then reflection
Answers
the answer is the option
d) Translation, then reflection
because
First translation
the rule is
(x,y) -------> (x+6, y-3)
6 units at righ and 3 units down
Second Reflection
the reflection is across the vertical line locate 3 units at left figure 2
see the attached figure to better understand the problem
please wait a minute
( pleassee help asap ! ) what is the solution (11.4 - 10) ÷2 ?
Answers
what is the solution (11.4 - 10) ÷2 ?
[tex]\begin{gathered} \frac{11.4-10}{2} \\ \frac{1.4}{2} \\ 0.7 \end{gathered}[/tex]The answer would be 0.7
Question 22 ptsYou pay $5 to play a game. To play the game you spin a spinner with 3 colors. If the spinnerlands on blue you earn $20. If the spinner lands on green, you get your $5 back. If the spinnerlands on red, you loose your money. The probabilities of the spinner landing on each color isgiven in the chart below.What is the expected value of this game, given to the nearest penny?Spinner ColorProbabilityBlue0.19Green0.14Red?
Answers
GIVEN:
You pay $5 to play a game. To play the game you spin a spinner with 3 colors.
If the spinner lands on blue you earn $20. If the spinner lands on green, you get your $5 back. If the spinner lands on red, you loose your money.
The probabilities of the spinner landing on each color is given in the chart below.
[tex]\begin{gathered} Color----------Probabilities \\ \\ Blue-----------0.19 \\ \\ Green-----------0.14 \\ \\ Red------------0.67 \end{gathered}[/tex]Required;
What is the expected value of this game, given to the nearest penny?
Step-by-step solution;
To solve the question, note that the probability distribution has a blank space. We have the probabilities of landing on a blue color and on a green color. The probability of an event is usually between 0 and 1.00. Therefore, for an experiment with 3 outcomes, the probabilities would all be equal to 1 (regardless of the value given to each outcome). Hence, we are able to calculate the probability of landing on a red color as;
[tex]\begin{gathered} Red=1-(0.19+0.14) \\ \\ Red=0.67 \end{gathered}[/tex]To solve for the expected value of this event, we now have to multiply each probability distribution by the reward attached to each outcome/probability.
For landing on a blue;
[tex]\begin{gathered} Expected\text{ }value=P(x)\times x \\ \\ Expected\text{ }value=0.19\times(\text{\$}20-\text{\$}5) \\ \\ Expected\text{ }value=0.19\times15 \\ \\ EV=2.85 \end{gathered}[/tex]For landing on a green;
[tex]\begin{gathered} EV=0.14\times(\text{\$5}-\text{\$5\rparen} \\ \\ EV=0.14\times0 \\ \\ EV=0 \end{gathered}[/tex]For landing red;
[tex]\begin{gathered} EV=0.67\times(\text{\$0}-\text{\$}5) \\ \\ EV=0.67\times(-5) \\ \\ EV=−3.35 \end{gathered}[/tex]Now we can calculate the expected earnings from playing this game.
We sum up the individual expected earnings as follows;
[tex]\begin{gathered} Expected\text{ }earnings=\Sigma[xP(x)] \\ \\ Expected\text{ }earnings=2.85+0+(-3.35) \\ \\ Expected\text{ }earnings=−0.5 \end{gathered}[/tex]We now have a negative value which means based on the conditions given, the expected earnings from playing this game is a loss of $0.50
ANSWER:
Expected value
[tex]Expecetd\text{ }value=\text{\$}-0.50[/tex]Evaluate. Write your answer as an integer or as a decimal rounded to the nearest hundredth. sin 5° = ____
Answers
we want to calculate the following value
[tex]\sin (5)[/tex]Using a calculator, we have that
[tex]\sin (5)=0.08715574274765817[/tex]so, rounded to the nearest hundredth, we have that
[tex]\sin (5)\approx0.09[/tex]Solve the equation for t:8t - r = 12t
Answers
ANSWER
[tex]t=-\frac{r}{4}[/tex]EXPLANATION
We want to solve the given equation for t:
[tex]8t-r=12t[/tex]To do this, separate the variables of the equation and simplify it:
[tex]\begin{gathered} 8t-12t=r \\ -4t=r \\ t=\frac{r}{-4} \\ t=-\frac{r}{4} \end{gathered}[/tex]That is the solution to the equation for t.
x = Round to the nearest hundredth or keep as a s
Answers
x=6.67
1) Examining that figure, we can state that we have two similar triangles with proportional sides and congruent angles.
2) So let's write a proportion so that we can find the measure of x
[tex]\begin{gathered} \frac{hipotenuse}{hipotenuse\text{ 2}}=\frac{\text{Leg}}{\text{leg 2}} \\ \frac{18}{10}=\frac{12}{x} \\ 18x=120 \\ x=\frac{120}{18} \\ x=\frac{20}{3}\text{ }\cong6.66667 \end{gathered}[/tex]3) Since the answer must be rounded to the nearest hundredth we have
the answer as x=6.67
Refer to the line for Exercises 17-22.SU17. If RS 19 and RV = 71, find SV.18. If UV = 17 and SU17 and SUI = 38, find SV.13 and SX 30, find SV.19. If VX =20. If TW81 and VW = 35, find TV.21. If SW = 44.5 and SV44.5 and SV 37.1, find VW.22. If TU 15.9 and UW = 28.3, find TW.R====TVWX
Answers
Given:
RS=19 and RV=71
Find: SV
Explanation: SV= RV-RS
=71-19
=52
Final answer: the required value of SV is 52.
Write 11/80 as decimal Round to four decimal places as needed
Answers
The fraction is given
[tex]\frac{11}{80}[/tex]ExplanationTo determine the decimal form .
[tex]\frac{11}{80}=0.1375[/tex]AnswerHence the answer in decimal form is 0.1375.
#13 how many seconds will it take for a ball dropped from a window 144 feet high to hit the ground below?
Answers
Question 13.
Given:
Height = 144 feet.
Let's determine how many seconds it will take for a ball dropped from a window of the given height to hit the ground.
Here, we have the equation:
[tex]y=-16x^2+144[/tex]Where:
y represents the height of the ball after x seconds.
Now, when the ball hits the ground, the height will be 0 ft.
Thus, to find the time at 0 ft, substitute 0 for y and solve for x:
[tex]\begin{gathered} 0=-16x^2+144 \\ \\ 16x^2=144 \end{gathered}[/tex]Divide both sides by 16:
[tex]\begin{gathered} \frac{16x^2}{16}=\frac{144}{16} \\ \\ x^2=9 \end{gathered}[/tex]Take the square root of both sides:
[tex]\begin{gathered} \sqrt{x^2}=\sqrt{9} \\ \\ x=3 \end{gathered}[/tex]Therefore, it will take the ball 3 seconds to hit the ground.
ANSWER:
• (a). y = -16t² + 144
• (b). 3 seconds
-15-3r=6r+3c Solve for r.
Answers
Answer:
[tex]r=\frac{-c-5}{3}[/tex]Explanation:
We want to solve for r in the equation below;
[tex]-15-3r=6r+3c[/tex]We need to move all terms of r to one side and divide both sides by the coefficient of r.
firstly subtract 6r from both sides;
[tex]\begin{gathered} -15-3r-6r=6r-6r+3c \\ -15-9r=3c \end{gathered}[/tex]then add 15 to both sides;
[tex]\begin{gathered} -15+15-9r=3c+15 \\ -9r=3(c+5) \end{gathered}[/tex]divide both sides by -9;
[tex]\begin{gathered} \frac{-9r}{-9}=\frac{3(c+5)}{-9} \\ r=\frac{-(c+5)}{3} \\ r=\frac{-c-5}{3} \end{gathered}[/tex]Therefore;
[tex]r=\frac{-c-5}{3}[/tex]for the function y=1/2-x at what values of x will the rate of change of y with respect to x equal 1/16
Answers
Given:
[tex]y=\frac{1}{2-x}[/tex]To Determine: Using the increament method the rate of change of y with respect to x
[tex]\begin{gathered} y+\Delta y=\frac{1}{2-(x+\Delta x)} \\ \Delta y=\frac{1}{2-(x+\Delta x)}-y \end{gathered}[/tex]Substitute for y
[tex]\begin{gathered} \Delta y=\frac{1}{2-(x+\Delta x)}-\frac{1}{2-x} \\ \Delta y=\frac{2-x-(2-(x+\Delta x)}{(2-(x+\Delta x)(2-x)} \\ \Delta y=\frac{2-x-(2-x-\Delta x)}{(2-(x+\Delta x)(2-x)} \\ \Delta y=\frac{2-x-2+x+\Delta x}{(2-(x+\Delta x)(2-x)} \\ \Delta y=\frac{\Delta x}{(2-(x+\Delta x)(2-x)} \end{gathered}[/tex][tex]\begin{gathered} \text{Divide through by }\Delta x \\ \frac{\Delta y}{\Delta x}=\frac{\Delta x}{(2-(x+\Delta x)(2-x)}\times\frac{1}{\Delta x} \\ \frac{\Delta y}{\Delta x}=\frac{1}{(2-(x+\Delta x)(2-x)} \end{gathered}[/tex][tex]\frac{dy}{dx}=\frac{1}{(2-x)(2-x)}[/tex]Hence, the rate of change of y with respect to x is
[tex]\frac{dy}{dx}=\frac{1}{(2-x)^2}[/tex]Then he drove home at a speed of 5 blocks every 4 minutes. How do I graph that?
Answers
We have to graph the position versus time.
We start by identifying the segments.
1) The initial position (x=0, y=0) is his house.
2) He drove for 4 minutes at a speed of 1 block/min. This means that we have a line with slope m=1 from x=0 to x=4. The value of y when x=4 is also 4.
Then, the final point of this segment is (4,4).
3) He spent 3 minutes in the store. This means that y=4 between x=4 and x=4+3=7.
The final point of this segment is (7,4).
4) He drove at a speed of 2 blocks/minute (slope m=2) for 6 blocks until he got to the bank. Then, the new position is y=7+6=13. If the slope is m=2, then he will spent 6/2=3 minutes to reach the bank. As he already spent 7 minutes, he arrived to the bank at x=7+3=10.
Then, the final position of this segment will be (10,13).
5) Then, he returns at a speed of 5 blocks every 4 minutes. This correspond to a slope m=-5/4. This slope is negative as he is now returning to his house and, then, y is decreasing.
1. The price p (in dollars) and the quantity x sold of a certain product obey the demand equation p = -8x + 600. What quantity x maximizes revenue (R= xp)? What is the maximum revenue? What price should the company charge to maximize revenue?2. Jeff invested some money at 7% simple interest and $5000 more than that amount at 15% simple interest. After 1 year, his total interest from the two accounts was $1300. How much did he invest at each rate?
Answers
1.The quantity x maximizes revenue is 80 , the price should be company charge to maximize revenue is 9 or 11.
2. $11875 he invest at each rate.
Given that,
In the question there are 2 question.
1.The market equation p = -8x + 600.
We have to determines how much a specific product costs in dollars and how many units are sold. What value of x optimizes profit (R=xp)?
We know,
R = px
R = p(-8p+160)
R= -8p² +160p
R(16) = -8(16)² +160(16)
R(16) = -2048 + 2560
R(16) = 512
R'= -16p + 160 = 0
Revenue maximizing price p= 160/16 = 20/2 = 10
Maximum revenue R(10) = -8(10)² + 160(10) = -800 + 1600 = 800
x=-8p+160
x =-8(10)+160
x = -80 + 160
x = 80
We get,
792 = -8p² +160p
8p² -160p + 792 = 0
2p² - 40p + 198 = 0
p² -20p + 99 = 0
(p-9)(p-11) = 0
p = 9 or 11 as the prices that give at least 792 in revenue
Therefore, The quantity x maximizes revenue is 80 , the price should be company charge to maximize revenue is 9 or 11.
2. Jeff put some money into investments at 7% simple interest and another $5,000 at 15% simple interest. His combined interest from the two accounts after a year was $1300.
We have to find at which rate did he invest how much.
Let C represent the sum Bryan invested in the CD. Then he made a savings account deposit of $5,000 C. Add the interest amounts to reach $1300.00: 15% of the amount in the certificate of deposit is 0.15C, and 7% of the amount in the savings account is 0.07(5,000-C). As a result, we can construct and settle the equation:
0.15C+0.07(5000-C)=1300
0.15C+350-0.07C=1300
0.08C+350=1300
0.08C=1300-350
0.08C=950
C=950/0.08
C=11875.
Therefore, $11875 he invest at each rate.
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Is 2/9 equal to a terminating decimal or a repeating decimal?
Answers
Since the denominator of 2/9 is 9, 2/9 is equal to a repeating decimal.
[tex]\frac{2}{9}=0.222222\ldots=0.\bar{2}[/tex]Answer: repeating decimal
[tex]1 + ( - 2)[/tex]what is answer this
Answers
This problem involves the addition of integers. When we add up a positive number and a negative number, it results in subtraction. The final answer will have a sign the same as the higher number.
In this problem, the negative number has a higher value than the positive number, hence, the final answer is a negative number. Doing the operation, we get
[tex]1+(-2)=-1[/tex]Answer: -1
Which number is located between 8710and95?
Answers
-8 7/10 and -9 2/10
-8-7/10 = -87/10
-9 - 2/10= -92/10
Answer is -9 1/10 = -91/10
because -91 is between -87 and -92
Answer is OPTION B))