Graph the parabola.Y = -2x^2 - 16x - 34Plat five points on a parable the vertex ,two points to the left of the vertex ,and two points to the right of the vertex . then click on the graph a function button.
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The graph is shown below:
• The point (-4, -2) is the vertex
,• The points to the left are (-5, -4) and (-6, -10)
,• The points to the right are (-3, -4) and (-2, -10)
Related Questions
Find the GCF : (7x^2y ,x^2y^2,21x^4y^2)
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The given expressions are
[tex]7x^2y,x^2y^2,21x^4y^2[/tex]We have to find the greatest common factor of the coefficients and variables.
The Greatest Common Factor between coefficients is 7 because that's the highest factor that's common.
The Greatest Common Factor between variables is
[tex]x^2y[/tex]Hence, the GCF is[tex]7x^2y[/tex]Find the infinite sum of the geometric sequence with a=3,r=3/6 if it exists.S∞=
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ANSWER
[tex]S_{\infty}=6[/tex]EXPLANATION
Given:
1. First term (a) = 3
2. Common ration (r) = 3/6
Desired Outcome:
Infinite sum of the geometric sequence.
The formula to calculate the infinite sum of the geometric sequence
[tex]S_{\infty}=\frac{a(1-r^n)}{1-r}[/tex]Now, as n approaches infinity,
[tex]1-r^n\text{ approaches 1}[/tex]So,
[tex]\frac{a(1-r^n)}{1-r}\text{ approaches }\frac{a}{1-r}[/tex]Therefore,
[tex]S_{\infty}=\frac{a}{1-r}[/tex]Substitute the values
[tex]\begin{gathered} S_{\infty}=\frac{3}{1-\frac{3}{6}} \\ S_{\infty}=\frac{3}{1-\frac{1}{2}} \\ S_{\infty}=\frac{3}{\frac{1}{2}} \\ S_{\infty}=6 \end{gathered}[/tex]Hence, the infinite sum of the geometric sequence is 6.
If tan theta = 4/3 and pi
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Given that tan theta = 4/3 and theta lies in the third quadrant.
[tex]\pi<\theta<\frac{3\pi}{2}[/tex]Divide the compound inequality by 2.
[tex]\frac{\pi}{2}<\frac{\theta}{2}<\frac{3\pi}{4}[/tex]This means theta/2 lies in the second quadrant. So, cos theta/2 and sec theta/2 are negative.
Use trigonometric identities to find sec theta.
[tex]\begin{gathered} \sec \theta=\sqrt[]{1+\tan ^2\theta} \\ =\sqrt[]{1+(\frac{4}{3})^2} \\ =\sqrt[]{1+\frac{16}{9}} \\ =\sqrt[]{\frac{25}{9}} \\ =-\frac{5}{3} \end{gathered}[/tex]we know that cosine is the inverse of secant. So, cos theta = -3/5.
now, using the half-angle formula, we have to find cos theta/2,
[tex]\begin{gathered} \cos (\frac{\theta}{2})=-\sqrt[]{\frac{1+\cos x}{2}} \\ =-\sqrt[]{\frac{1-\frac{3}{5}}{2}} \\ =-\sqrt[]{\frac{\frac{2}{3}}{2}} \\ =-\sqrt[]{\frac{1}{3}} \end{gathered}[/tex]Determine whether triangle DEF with vertices D(6, -6), E(39, -12), and F(24, 18) isscalene (no congruent sides), isosceles (two congruent sides), or equilateral (threecongruent sides).
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We have three given points. We need to graph them, and then find the distances between them.
We need to remember that we can classify the triangles according to their sides:
1. A triangle with three congruent sides is an equilateral triangle.
2. A triangle with two congruent sides is an isosceles triangle.
3. A triangle with no congruent sides is a scalene triangle.
Additionally, we know that a segment is congruent to other when it has the same size as the other.
Then we can graph the three points as follows:
Now, we need to find the distances between the sides of the triangle using the distance formula as follows:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]This is the distance formula for points (x1, y1) and (x2, y2).
Finding the distance between points D and EThe coordinates for the two points are D(6, -6) and E(39,-12), and we can label them as follows:
• (x1, y1) = (6, -6) and (x2, y2) = (39, -12)
Then we have:
[tex]\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ d=\sqrt{(39-6)^2+(-12-(-6))^2} \\ \\ d=\sqrt{(33)^2+(-12+6)^2} \\ \\ d=\sqrt{33^2+(-6)^2}=\sqrt{1089+36}=\sqrt{1125} \\ \\ d_{DE}=\sqrt{1125}\approx33.5410196625 \end{gathered}[/tex]Therefore, the distance between points D and E is √1125.
And we need to repeat the same steps to find the other distances.
Finding the distance between points E and FWe can proceed similarly as before:
The coordinates of the points are E(39, -12) and F(24, 18)
• (x1, y1) = (39, -12)
,• (x2, y2) = (24, 18)
Then we have:
[tex]\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ d=\sqrt{(24-39)^2+(18-(-12))^2} \\ \\ d=\sqrt{(-15)^2+(18+12)^2}=\sqrt{(-15)^2+(30)^2}=\sqrt{225+900} \\ \\ d_{EF}=\sqrt{1125}\approx33.5410196625 \end{gathered}[/tex]Then the distance between points E and F is √1125.
Finding the distance between F and D
The coordinates of the points are F(24, 18) and D(6, -6)
• (x1, y1) = (24, 18) and (x2, y2) = (6, -6)
Then we have:
[tex]\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ d=\sqrt{(6-24)^2+(-6-18)^2}=\sqrt{(-18)^2+(-24)^2}=\sqrt{324+576} \\ \\ d=\sqrt{900}=30 \\ \\ d_{FD}=30 \end{gathered}[/tex]Now, we have the following measures for each of the sides of the triangle:
[tex]\begin{gathered} \begin{equation*} d_{DE}=\sqrt{1125}\approx33.5410196625 \end{equation*} \\ \\ d_{EF}=\sqrt{1125}\approx33.5410196625 \\ \\ d_{FD}=30 \end{gathered}[/tex]Therefore, in summary, according to the results, we have two sides that are congruent (they have the same size). Therefore, the triangle DEF is an isosceles triangle.
Solve the following system of equations by graphing. y = –1∕2x – 2 y = –3∕2x + 2
Answers
We can see the solution in the graph as follows:
A loan of $43,000 is made at 5.25% interest, compounded annually. After how many years will the amount due reach $64,000 or more? (Use the calculator provided if necessary.)Write the smallest possible whole number answer.
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Answer:
8 years
Explanation:
For a compound interest loan compounded annually, the amount due after t years is calculated using the formula:
[tex]A(t)=P(1+r)^t\text{ where }\begin{cases}P={Loan\;Amount} \\ {r=Annual\;Interest\;Rate}\end{cases}[/tex]We want to find when the amount due will reach $64,000 or more.
[tex]43000(1+0.0525)^t\geq64,000[/tex]The equation is solved for t:
[tex]\begin{gathered} \text{ Divide both sides by }43000 \\ \frac{43,000(1+0.0525)^t}{43000}\geqslant\frac{64,000}{43000} \\ (1.0525)^t\geq\frac{64}{43} \\ \text{Take the log of both sides:} \\ \log(1.0525)^t\geqslant\log(\frac{64}{43}) \\ \text{By the power law of logarithm:} \\ \implies t\operatorname{\log}(1.0525)\geq\operatorname{\log}(\frac{64}{43}) \\ \text{ Divide both sides by }\operatorname{\log}(1.0525) \\ t\geq\frac{\operatorname{\log}(\frac{64}{43})}{\operatorname{\log}(1.0525)} \\ t\geq7.77 \end{gathered}[/tex]The number of years when the amount due will reach $64,000 or more is 8 years.
1. In which number is the value of the 4 one thousand times more than the value of the 4 in 45? 43,853 458,329 894,256 34,914
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The answer is 43 853
If we multiply 45 times 1000, we have:
[tex]45\text{ }\times\text{ 1000 = 45000}[/tex]The value of 4 in 45000 is similar to the value of 4 in 43853
Hence, the choice
Use the Factor Theorem to find all real zeros for the given polynomial function and one factor. (Enter your answers as a comma-separated list.)f(x) = 4x3 − 19x2 + 29x − 14; x − 1
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Given:
The polynomial and one factor
[tex]f(x)=4x^3-19x^2+29x-14[/tex]Required:
Use the Factor Theorem to find all real zeros for the given polynomial function and one factor.
Explanation:
We have one factor, we will us that
[tex]\begin{gathered} =\frac{4x^3-19x^2+29x-14}{x-1} \\ \text{ It can be written as } \\ =(x-1)(4x^2-15x+14) \\ \text{ So, roots are} \\ =1,2,\frac{7}{4} \end{gathered}[/tex]Answer:
answered the question.
1. Determine the domain and range of the quadratic function shown in the graph and represent the domainand range using inequalities.
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Domain: [ -5 , 4.5 )
Range: ( -7 , 6 ]
Using inequalities:
[tex]\text{Domain: }\lbrace-5\leq x<4.5\}[/tex][tex]\text{Range: }\mleft\lbrace-7A ball is thrown in the air from a platform. The path of the ball can be modeled by the function h(t)=-16 t^{2}+32t+4 where h(t) is the height in feet and t is the time in seconds.How long does the ball take to reach its maximum height?
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Answer:
1 second
Explanation:
The equation that models the path of the ball is given below:
[tex]h\mleft(t\mright)=-16t^2+32t+4[/tex]To determine how long it takes the ball takes to reach its maximum height, we find the equation of the line of symmetry.
[tex]\begin{gathered} t=-\frac{b}{2a},a=-16,b=32 \\ t=-\frac{32}{2(-16)} \\ =-\frac{32}{-32} \\ t=1 \end{gathered}[/tex]Thus, we see that it takes the ball 1 second to reach its maximum height.
PLEASE HELP DUE SOON ONLY Q6 I have the work for the rest.
Answers
Given:
Diameter=40 feet
so radius=20 feet(d=2r)
Height of 2nd tank= 130 feet
Required:
Volume of sphere
Volume of cylinder
Explanation:
First of all we are going to calculate volume of sphere=
[tex]\begin{gathered} \frac{4}{3}\pi r^3 \\ =\frac{4}{3}\times3.14\times20\times20\times20 \\ =33,493.33feet^3 \end{gathered}[/tex]Then we are going to calculate volume of cylinder=
[tex]\begin{gathered} =\pi r^2h \\ =3.14\times20\times20\times130 \\ 163,280feet^3 \end{gathered}[/tex]and the vertically cross- section of tank 2 is a rectangle.
Required answer:
volume of sphere is 33,493.33
volume of cylinder=163,280
and the shape is rectangle.
I just need the first one thanks
Answers
If the vector is pointing in the opposite direction of [-4,3], we can say it is pointing in the same direction of the vector [4,-3]. We just flipped the direction of the vector by changing the sign of the components.
We have now a vector that is pointing in the same direction of the vector we are looking for. Let's find the length of that vector to see how much it has to be scaled, or if it does not need to be scaled.
The length of the vector is calculated as the square root of the sum of the square of its components:
[tex]\text{Length}=\sqrt[]{x^2+y^2}[/tex]Then, the length of the vector is:
[tex]\begin{gathered} \text{Length}=\sqrt[]{4^2+(-3)^2}=\sqrt[]{16+9}=\sqrt[]{25} \\ \\ \text{Length}=5 \end{gathered}[/tex]Then the length of the vector [4,-3], which is pointing opposite to the vector [-4,3], happens to have a length of 5, then, that is the vector we were looking for. There is no need to scale it.
Then, the components of the vector are 4 and -3. [4,-3]
10. Explain how you would prove the following.Given: HY = LY:WH LFProve: A WHY = AFLY
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It is being proved that triangle Δ WHY ≅ Δ FLY by ASA rule.
In triangle Δ WHY and Δ FLY, we have that:
HY ≅ LY ( given)
∠WHY = ∠ FLY (alternate interior angles as WH || LF)
∠WYH = ∠ FYL ( Vertically opposite angles)
We get that:
Δ WHY ≅ Δ FLY ( ASA rule)
It is proved that Δ WHY ≅ Δ FLY by ASA rule.
Therefore, we get that, it is being proved that triangle Δ WHY ≅ Δ FLY by ASA rule.
Learn more about triangle here:
https://brainly.com/question/17335144
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a cylindrical container with an 8 in. diameter and an 2 in. height is completely filled with water. all of its contents are poured into another cylindrical container that is 32 in. tall. if the water completely fills the second container, the second container's diameter is ___ in.
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Volume of a cylinder: π r^2 h
Where:
r = radius
h= height
Calculate the volume of the first cylindrical container:
radius = diameter/2
Volume = π (8/2)^2 (2) = 100.5 in3
Second container
Volume = 100.5
heigth = 32 in
100.5 = π r^2 32
Solve for r
100.5/ (π 32 ) = r^2
1 = r^2
√1 = r
r=1
Diameter = 2 r = 2 (1) = 2 in
) Which ratios hiqve a unit rate greater than 1: 7 Choose ALL that apply. 1 >) 4 miles: 3- hours 33 1 3 mile : 2-hours 8 2 1 0) 2 miles : 3 hours 2 3 0) 7 miles : hour 4 13 9 miles : 3 hours 9 5 miles: hour 8 6
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To calculate the ratio or the unit rate, we have to divide each ratio:
[tex]\frac{4\text{ miles}}{3+\frac{1}{3}\text{ hours}}=\frac{4}{\frac{10}{3}}\frac{\text{ miles}}{\text{ hour}}=4\cdot\frac{3}{10}=\frac{12}{10}=1.2\frac{\text{ miles}}{\text{ hour}}[/tex][tex]\frac{\frac{1}{3}}{2+\frac{3}{8}}=\frac{\frac{1}{3}}{\frac{16+3}{8}}=\frac{\frac{1}{3}}{\frac{19}{8}}=\frac{1}{3}\cdot\frac{8}{19}=\frac{8}{57}\approx0.14\frac{\text{ miles}}{\text{ hour}}[/tex][tex]\frac{2+\frac{1}{2}}{3}=\frac{\frac{5}{2}}{3}=\frac{5}{2}\cdot\frac{1}{3}=\frac{5}{6}\approx0.83\frac{\text{ miles}}{\text{ hour}}[/tex][tex]\frac{7}{\frac{3}{4}}=7\cdot\frac{4}{3}=\frac{28}{3}\approx9.33\frac{\text{ miles}}{\text{ hour}}[/tex][tex]\frac{\frac{9}{5}}{3}=\frac{9}{5}\cdot\frac{1}{3}=\frac{3}{5}=0.6\frac{\text{ miles}}{\text{ hour}}[/tex][tex]\frac{\frac{9}{8}}{\frac{5}{6}}=\frac{9}{8}\cdot\frac{6}{5}=\frac{54}{40}=1.35\frac{\text{ miles}}{\text{ hour}}[/tex]Answer:
The ratios that are greater than 1 are:
4 miles : 3 1/3 hours
7 miles : 3/4 hour
9/8 miles : 5/6 hours
Find the simple interest on a $4,719 principal deposited for
six years at a rate of 6.11%.
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Answer:
The answer is 1,729.99
Step-by-step explanation:
The formula for calculating Simple interest is
Simple interest (A) = P×R×T
where,
P = Principal
R = Rate
T = Time
So after adding the values to the formula
we get
=4719×6.11×6/100
=1,72,998.54/100
=1,729.9854
So The simple interest is 1,729.99
For more Information search Simple Interest in Brainly.com
Find the next term of the geometric sequence 3/2, 3/4, 3/8 , ...
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Given:
Geometric sequence:
[tex]\frac{3}{2},\frac{3}{4},\frac{3}{8},.....[/tex]Find-: Next term of the geometric.
Sol:
Common ratio of a geometric sequence.
[tex]r=\frac{a_n}{a_{n-1}}[/tex]A common ratio is:
[tex]\begin{gathered} r=\frac{\frac{3}{4}}{\frac{3}{2}} \\ r=\frac{3}{4}\times\frac{2}{3} \\ r=\frac{1}{2} \end{gathered}[/tex]The next term is:
[tex]a_n=ra_{n-1}[/tex][tex]\begin{gathered} =\frac{1}{2}\times\frac{3}{8} \\ =\frac{3}{16} \end{gathered}[/tex]URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!
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Suppose you found a CD that pays 2.1% interest compounded monthly for 6 years. If you deposit $12,000 now, how much will you have in the account in 6 years? (Rounded to the nearest cent.) What was the interest earned? Now suppose that you would like to have $20,000 in the account in 6 years. How much would you need to deposit now?
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The interest earned is the difference between the initial amount that was deposited in the bank and the amount that is in the account after six years.
[tex]\begin{gathered} A\text{ = 12000\lparen1+}\frac{2.1\%}{12})^{6*12} \\ This\text{ is from the compound interest formula.} \\ A\text{ = 13609.89} \end{gathered}[/tex]Amount in the account: $13609.89
The interest earned is therefore: 13609.89 - 12000 = $1609.89
[tex]\begin{gathered} 20000\text{ = P\lparen1+}\frac{2.1\%}{12})^6*12 \\ 17634.24\text{ = P} \end{gathered}[/tex]To earn $20000 in six years he should invest $17634.24.
simplifyx^-1 X (y^-8 X z^5)^3------------------------------x^-4 X y^-3 X z^6
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Given:
[tex]\frac{x^{-1}\left(y^{-8}z^5\right)^3}{x^{-4}y^{-3}z^6}[/tex]Simplify:
[tex]\frac{x^{-1}y^{-24}z^{15}}{x^{-4}y^{-3}z^6}[/tex]And:
[tex]x^{-1-(-4)}y^{-24-(-3)}z^{15-6}=x^3y^{-21}z^9[/tex]Re order:
[tex]\frac{x^3z^9}{y^{21}}[/tex]Answer:
[tex]\frac{x^{3}z^{9}}{y^{21}}[/tex]I am thinking of a number. It has two digits. When I reverse the digits and then add the new number to the original number I get 33. What is the number?
Answers
Let x and y be the digits.
The original number has two digits that means that one is the tens and the other the ones, in this case let x be the tens and y the ones, then we have the number:
[tex]10x+y[/tex]if we reverse it this means that the y become the tens and x becomes the ones then we have the number:
[tex]10y+x[/tex]And if we add them the result is 33, then we have the equation:
[tex]\begin{gathered} (10x+y)+(10y+x)=33 \\ 11x+11y=33 \\ x+y=3 \\ y=3-x \end{gathered}[/tex]This means that y has to be 3-x. Now, since we both numbers to have two digits x can't be zero nor 3. Then has to be 1 or 2.
If x=1 then y=2 and the original number is 12.
If x=2 then y=1 and the original number is 21.
Notice how in both cases we get the other one when reversed, therefore the numbers we are looking for are 12 and 21.
Which of the following functions are linear? Select all that apply. A The function that assigns to each number r the value 9x2. 3 B The function that assigns to each positive number x the value The function that assigns to each positive number 2 the value 5V2r. D The function that assigns to each number 2 the value 78. 1 E The function that assigns to each number the value 2. F|The function that assigns to each number 2 the value x + 8.
Answers
The answers are D, E, F
Being linear has one dependent variable and one independent variable, similar to a straight line.
only D,E and F satisfy this.
#32 At 10am, a green car leaves a house at a rate of 60 mph. At the same time, a blue carleaves the same house at a rate of 50 mph in the opposite direction. At what time will the carsbe 330 miles apart?#3b. Two bicyclists ride in the same direction. The first bicyclist rides at a speed of 8 mph.One hour later, the second bicyclist leaves and rides at a speed of 12 mph. How long will thesecond bicyclist have traveled when they catch up to the first bicyclist?
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The map above is a road map of Learner County. Each centimeter on the map represents 30 miles. About how far is it from the town of Presley to Mt. Sametone on the road shown in red?A. 270 milesB. 180 milesC. 360 milesD. 390 miles
Answers
Scaling
Each centimeter on the map represents 30 miles in Learner County.
The town of Presley and Mt. Samerone are separated by a horizontal distance of 8 centimeters,
If we only consider the horizontal component of the distance, then both points are separated by 8 * 30 = 240 miles.
Since there is not an option for this number, we choose the closest, considering they are including a smaller vertical distance in the calculations, thus the answer is:
A. 270 miles
Answer:
A. 270 miles
Step-by-step explanation:
To get around a small pond, a local electrical utility must lay two sections of underground cable that are 371 m and 440 m long. The two sections meet at an angle of 145°. How much extra cable is needed due to going around the pond?
Answers
If the cable could went through the pond there would be only one straight section conecting the two points. If we draw this new section in the picture we'll form a triangle:
In order to find how much extra cable is needed because of the pond we must find the length of the imaginary cable that connects the points through the dot, for this length we are going to use x.
The cosine rule will help as find it. Let's assume that we have a triangle with an angle A which has an opposite side with a length a and the lengths of the other two sides are b and c. Then the cosine rule states the following:
[tex]a^2=b^2+c^2-2bc\cos A[/tex]We can apply this to our triangle. The 145° angle that we know is A, its opposite side a is x and the remaining sides b and c are the two cable sections of 371 m and 440 m. Then we get:
[tex]\begin{gathered} x^2=371^2+440^2-2\cdot371\cdot440\cdot\cos145^{\circ} \\ x^2=598677.7594 \end{gathered}[/tex]Then we apply a square root to both sides of this equation:
[tex]\begin{gathered} \sqrt{x^2}=\sqrt{598677.7594} \\ x=773.74 \end{gathered}[/tex]So without the pond the length of the cable would have been of 773.74 m. In order to find the amount of extra cable needed we must take the total length of both sections and substract 773.74 m from it. Then we get:
[tex]371+440-773.74=37.26[/tex]AnswerThen the answer is 37.26m.
What is the equation of the line that passes through the point (-2,-4) and has a slope of 1/2
Answers
Answer:
[tex]y=\frac{1}{2}x-3[/tex]
Step-by-step explanation:
[tex]y+4=\frac{1}{2}(x+2) \\ \\ y+4=\frac{1}{2}x+1 \\ \\ y=\frac{1}{2}x-3[/tex]
You pick a card at random put it back and then pick another card at random what is the probability of picking a number greater than 5 and then picking a 5 right and then picking a 5 write your answer as a percentage
Answers
You have four cards numbered 4, 5, 6, and 7.
Step 1
To calculate the probability of picking a card at random, and that this card has a number greater than 5, you have to divide the number of successes by the number of possible outcomes.
Successes: You want to pick a card with a number greater than 5, there are only two cards that meet this condition, the card numbered 6 and the card numbered 7, so for this scenario, there are 2 successes.
Total outcomes: The number of outcomes is equal to the total number of cards you can pick from, in this case, the total number of outcomes is 4.
Next, calculate the probability of picking a card with a number greater than 5:
[tex]\begin{gathered} P(X>5)=\frac{nºsuccesses}{Total\text{ }outcomes} \\ P(X>5)=\frac{2}{4} \\ P(X>5)=\frac{1}{2}=0.5 \end{gathered}[/tex]The probability of picking a card with a number greater than 5 is 0.5.
Step 2
Next, you put the card back and pick another one at random.
You have to calculate the probability that this time you will pick the card numbered 5.
To calculate this probability you have to divide the number of successes by the total number of outcomes.
Successes: there is only one card with the number 5, so the number of successes is 1.
Total outcomes: since the first card that was drawn was returned to the deck, the total number of outcomes is still 4.
Calculate the probability of drawing a 5:
[tex]\begin{gathered} P(X=5)=\frac{nºsuccesses}{Total\text{ }outcomes} \\ P(X=5)=\frac{1}{5}=0.2 \end{gathered}[/tex]The probability of drawing a 5 is 0.2.
Finally, the probability that you have to determine is to "draw a card with a number greater than 5 and then pick a 5"
The event described is the intersection of both events "drawing a card greater than 5" and "picking a 5". Since the first card was returned to the deck before drawing the second card, both events are independent, which means that the probability of their intersection is equal to the product of the individual probabilities of the events, so that:
[tex]P(X>5\cap X=5)=P(X>5)*P(X=5)=0.5*0.2=0.1[/tex]The probability is 0.1.
Multiply the result by 100 to express it as a percentage:
[tex]0.1*100=10\%[/tex]The probability of picking a number greater than 5 and then picking a 5 is 10%.
clarify each of the following triangles by their angles in sides
Answers
SOLUTION
From the diagram below,
Triangle A is right isosceles, since two angles are equal, two sides are equal, and there is a right-angle (90 degrees angle) present.
Triangle B is obtuse scalene, since none of the sides are equal, and one of the angles is greater than 90 degrees.
Triangle C is acute scalene, since none of the sides are equal, and all the angles are less than 90 degrees.
Triangle D is acute isosceles, since two angles and two sides are equal, and all the angles are less than 90 degrees.
2 1' 15 = 1 2. 2 1 1 = 1 5 . (Type a whole number, fraction, or mixed number.)
Answers
Step 1
Write out your question.
[tex]1\frac{2}{5}\frac{.}{.}\text{ 1}\frac{1}{2}[/tex]Step 2
Convert mixed fractions to improper fractions.
[tex]\frac{7}{5}\text{ }\frac{.}{.}\text{ }\frac{3}{2}[/tex]Step 3
Convert division to multiplication and invert the fraction after the division.
[tex]\begin{gathered} =\text{ }\frac{7}{5}\text{ x }\frac{2}{3} \\ =\text{ }\frac{7\text{ x 2}}{5\text{ x 3}} \\ =\text{ }\frac{14}{15} \end{gathered}[/tex]Solve the systems using subsitution for 1 and 2Solve the system using elimination for question 3
Answers
3x+y=2 (a)
6x+2y= 11 (b)
Solve equation (a) for y :
3x+y = 2
y= 2-3x
Replace the y value on (b)
6x+2(2-3x) =11
6x+4-6x=11
4=11
the system has no solution.