From the point of view of conductive heat loss, which adaptations would be beneficial to animals living in extremely cold climates? A. Large surface area
B. Lots of tissues, like fat, with low thermal conductivity
C. Lots of tissues, like muscle, with high thermal conductivity
D. Thick skin
E. Thin skin
F. Small surface area

Answers

Answer 1

The Correct answer is B, D, F. From the point of view of conductive heat loss, which adaptations would be beneficial to animals living in extremely cold climates

rate of heat loss = K*A*delta T / L

where A: surface area

L: the thickness of the tissue

K: thermal conductivity

High K, A value increases the rate

High L will decrease the rate

the rate should be low.

In thermodynamics, heat is defined as the shape of power crossing the boundary of a thermodynamic gadget through the distinctive features of a temperature difference across the boundary. A thermodynamic device does not contain warmness. nonetheless, the time period is also regularly used to consult the thermal electricity contained in a system as an element of its internal electricity and that is contemplated inside the temperature of the device. For each makes use of the time period, heat is a shape of strength.

Warmth is power in the switch to or from a thermodynamic gadget, by a mechanism that includes the microscopic atomic modes of movement or the corresponding macroscopic properties.

The measurement of strength transferred as heat is referred to as calorimetry, done via measuring its impact on the states of interacting bodies. for example, warmness may be measured by means of the quantity of ice melted, or through trade in the temperature of a frame inside the environment of the machine.

inside the international gadget of units (SI) the unit of dimension for heat, as a shape of electricity, is the joule (J).

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Related Questions

find the net gravitational force fnet acting on the earth in the sun-earth-moon system during the full moon (when the earth is located directly between the moon and the sun).

Answers

During the new moon, the net gravitational force acting on the Earth in the Sun-Earth-Moon system is approximately 3.502 × 10²² Newtons.

Given data:

Mass of the Sun (M(S)) = 1.989 × 10³⁰ kg

Mass of the Earth (M(E)) = 5.972 × 10²⁴ kg

Mass of the Moon (M(M)) = 7.342 × 10²² kg

Distance between the Sun and the Earth (r(SE)) = 1.496 × 10¹¹ meters

Distance between the Moon and the Earth (r(ME)) = 3.844 × 10⁸ meters

The gravitational force between two objects is given by Newton's Law of Universal Gravitation:

F = (G × (m₁ × m₂)) ÷ r²

Gravitational force due to the Sun on the Earth:

F(SE) = G × (M(S) × M(E)) ÷ r(SE)²

Gravitational force due to the Moon on the Earth:

F(ME) = G × (M(M) × M(E)) ÷ r(ME)²

The net gravitational force on the Earth during the new moon is the vector sum of these forces:

F(net) = F(SE) - F(ME)

Gravitational force due to the Sun on the Earth

F(SE) = (6.67430 x 10⁻¹¹) × ((1.989 × 10³⁰) × (5.972 × 10²⁴)) ÷ (1.496 × 10¹¹)²

F(SE)= 3.52 × 10²² N

F(ME) = (6.67430 x 10⁻¹¹) × ((7.342 × 10²²) × (5.972 × 10²⁴)) ÷ (3.844 × 10⁸)²

F(ME) = 1.98 × 10²⁰ N

F(net) = F(SE) - F(ME)

F(net) = 3.52 × 10²² - 1.98 × 10²⁰ N

F(net) =  3.502 × 10²²

So, during the new moon, the net gravitational force acting on the Earth in the Sun-Earth-Moon system is approximately 3.502 × 10²² Newtons.

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The Table Below Gives The Masses Of The Earth, The Moon, And The Sun. Name Mass (Kg) Earth 5.97×10²⁴ Moon 7.35×10²² Sun 1.99×10³⁰ The Average Distance Between The Earth And The Moon Is 3.84×10⁸ m. The Average Distance Between The Earth And The Sun Is 1.50×10¹¹ m. Use

The table below gives the masses of the Earth, the Moon, and the Sun.

Name Mass (kg)

Earth 5.97×10²⁴

Moon 7.35×10²²

Sun          1.99×10³⁰

Find the net gravitational force Fnet acting on the Earth in the Sun-Earth-Moon system during the new moon (when the moon is located directly between the Earth and the Sun).

Express your answer in newtons to three significant figures.

white light is incident on a diffraction grating that is 600 lines/mm. at what angle relative to the center line will light with a wavelength of 650 nm exit the grating for the first order spectrum (m

Answers

The wavelength fringe is 0.431 m.

Diffraction grating with split space d, to find the fringe position ym, we must to find the angle from

d Sinα = mλ

A grating with N slits or lines per mm has slit spacing of

d = 1/N

d = (1/600mm)

d = 1.67×10⁻³mm

For 400nm wavelength:

α = Sin⁻¹(mλ/d)

α = Sin⁻¹(400*10⁻⁹/1.67*10⁻⁶)

α = 13.910°

And the position of first order lowest wavelength fringe on the screen is:

y₁ = L.tanα

y₁ = 2tan(13.910)

y₁ = 0.49445 m

For 700nm wavelength:

α = Sin⁻¹(mλ/d)

α = 24.83°

And the position of first order highest wavelength fringe on the screen is:

y₂ = L.tanα₂

y₂ = 0.925595 m

The difference between the first order lowest and highest wavelength fringe is

Δy = (0.925595 - 0.49445)m

Δy = 0.431m

Therefore, the wavelength fringe is 0.431 m.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: White light (400–700 nm) is incident on a 600 line/mm diffraction grating. What is the wavelength of the first-order rainbow on a screen 2.0 m behind the grating?]

monochromatic light falls on a screen 1.75 m from two slits separated by 2.10 mm. the first- and second-order bright fringes are separated by 0.552 mm. what is the wavelength of the light?

Answers

The wavelength of light is calculated to be 662.4 nm.

Monochromatic light is nothing but the single wavelength light where mono refers to single and chroma refers to colour. Visible light of a narrow band of wavelengths is classified as monochromatic lights.

Given that, width of fringe β = 0.552 * 10⁻³ m

Distance of screen, D = 1.75 m

Separation of slits, d = 2.10 mm = 2.1 * 10⁻³ m

The formula for fringe width is:

β = (λ* D)/d

Making λ as subject,

λ = β*d/D

λ = (0.552 * 10⁻³ * 2.1 * 10⁻³)/ 1.75 = 0.6624 * 10⁻⁶ = 662.4 nm

Thus, the wavelength of light is 662.4 nm.

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What is the acceleration of a 1500 kg car when 3000 N of force are applied?

Answers

The acceleration of a 1500 kg car when 3000 N of force is applied is

2 m/s².

According to Newton's second law of motion, acceleration of a body depends on two variables, the net force acting on the object and mass of the object. The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body.

If the force acting on an object increases, the acceleration of the body also increases. Likewise, if mass of an object is increased, the acceleration of the body decreases.

The equation of Newton's second law of motion is given as,

F = m*a

where, F is net force

m is mass

a is acceleration

Given that, m = 1500 kg

F = 3000 N

Making ' a ' as subject for the above equation, we have

a = F/ m = 3000/1500 = 2 m/s²

Thus, the acceleration of the car is 2 m/s².

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A newly discovered planet has a mass that is 4 times the mass of the Earth. The radius of the Earth is R . If the gravitational field strength at the surface of the new planet is equal to that at the surface of the Earth, what is the radius of the new planet?

A. R/2
B. 4R
C. R/4
D. 2R

Answers

The radius of the new planet is equal to 2R. Therefore, option D is correct.

What is gravitational force?

Newton’s gravitation law can be demonstrated as every particle with mass in the universe attracts every other particle having mass with a definite force. The magnitude of gravitational force can be represented as:

[tex]\displaystyle F =G\frac{M_1M_2}{r^2}[/tex]

The gravitational field of the earth can be represented as:

[tex]\displaystyle g =G\frac{M}{R_e^2}[/tex]

Given, the new planet has mass, M' = 4 M

[tex]\displaystyle g' =G\frac{M'}{R^2}[/tex]

g' = g

[tex]\displaystyle g' = g=G\frac{4M}{R^2}[/tex]

[tex]\displaystyle {R^2} = \frac{4GM}{g}[/tex]

[tex]\displaystyle {R^2}= 4R_e^2[/tex]

[tex]R = 2 R_e[/tex]

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communication satellites are placed at an altitude of about 25,000 mi above the surface of the earth. find the acceleration due to gravity at this altitude. (

Answers

The acceleration due to gravity at this altitude is  1.26×10¹⁹m/s².

What kind of acceleration results from gravity?

Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational field. It has the SI unit m/s². It is a vector quantity because it has both magnitude and direction. g is a unit used to measure gravitational acceleration. 9.8 m/s² is the standard value of g at sea level on the surface of the earth.

Newton's law of gravitation states that the acceleration can be calculated by

a = G M/r², where G is the Universal Gravitational constant 6.67 x 10⁻¹¹, M is the mass of the Earth 5.97 x 10²⁴ kg, and r is the distance from the center of the Earth 6.38 x 10⁶ m.

The attitude above the surface must be multiplied by the Earth's radius to determine r.

r = 25km + 6.38 x 10⁶ = 31.38x10⁶

a =  6.67 x 10⁻¹¹ × 5.97 x 10²⁴/ 31.38x10⁶

a = 3.98×10¹⁴/ 31.38x10⁶

a = 1.26×10¹⁹m/s².

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describe the transformation from snow to ice by arranging the following steps in order.

Answers

Refreezing the liquid results in the formation of more densely packed upper layers (1/4 air by volume), and eventually, a solid mass of interconnecting ice.

How does snow become solid?

Firn is typically understood to be snow that is least a year old and it has avoided turning into glacier ice during one melt season.The pressure from above causes fluffy snow to pack together and melt in some spots when it is sufficiently deep.

Whatever happens to snow over time when it accumulates?

Snow is present.If there is snow on the ground for an extended period of time, the texture, size, and form of the individual grains will change, whether or not the temperature of the snow is below freezing. They may also gradually melt and refreeze before being compacted by consecutive snowfalls.

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a person can see clearly up close, but cannot focus on objects beyond 72.0 cm. she opts for contact lenses to correct her vision. part a part complete is she nearsighted or farsighted? is she nearsighted or farsighted? she is nearsighted. she is farsighted. previous answers correct part b part complete what type of lens (converging or diverging) is needed to correct her vision? what type of lens (converging or diverging) is needed to correct her vision? converging lens. diverging lens. previous answers correct part c what focal-length contact lens is needed ? templatessymbols undoredoresetkeyboard shortcutshelp f

Answers

She has poor vision. She needs a divergent lens of some kind, either converging or diverging. given that divergent lenses are often prescribed with a -1.33 D diopter strength, the lens strength is 1.33 D.

(A) The person is nearsighted if they have trouble seeing objects farther away than 75 cm.

(b) The type of corrective lens must be divergent in order to balance out the excessive converging power of the wearer's eye (which by the way carries by convention a negative focal length)

(c) The equation f = 1/d = 1/0.75 = 1.33D gives the focal length's absolute value (f).

As a result, it would typically be written with a negative sign indicating a contrasting lens.

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How do you calculate frequency?

Answers

Answer:

divide the number of times the event occurs by the length of time.

Explanation:

Q1 What is the velocity of the "Right" ball after the elastic collision below? Left ball heading rightwards btw.
Before: Left Ball Velocity= 2.0 m/s Left Ball Mass 0.25 kg; Right Ball Velocity= 0 m/s Right Ball Mass= 0.25 kg

After:?

Answers

Answer:

In an elastic collision, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision. This means that we can use the conservation of momentum to determine the velocity of the right ball after the collision.

The momentum of an object is equal to its mass multiplied by its velocity, so the initial momentum of the left ball is 0.25 kg * 2.0 m/s = 0.5 kgm/s. Since the initial velocity of the right ball is 0, the total initial momentum of the two balls is 0.5 kgm/s.

After the collision, the total momentum of the two balls must still be 0.5 kg*m/s. Since the mass of the two balls is the same, this means that the velocity of the right ball after the collision must be 2.0 m/s, which is the same as the initial velocity of the left ball.

Therefore, the velocity of the right ball after the elastic collision is 2.0 m/s.

a lens produces an inverted image of a candle on the wall. the distance between the candle and the lens is 32 cm and the distance between the lens and the wall is 30 cm . what is the power of the lens? express your answer in diopters. enter a positive value if the lens is converging and a negative value if the lens is diverging.

Answers

It is determined that the lens has 6.7 power.

What is the lens's focal length?

We are aware that a refracting surface is what a lens is. In light of this, if we have a surface capable of refraction, it follows that such a surface must be a lens.

It is necessary to carefully read the question in order to determine the image distance and the object distance.

Image distance =  30 cm

Object distance =  32 cm

Using;

1/f = 1/v + 1/u

f = focal length

v = image distance

u object distance

1/f = 1/30 + 1/32

f = (0.033 + 0.032)^-1

f = 14.9 cm

Power of the lens = 100/f

= 100/14.9

= 6.7

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Hope it helps.

If you have any query, feel free to ask.

A 2100-kg car is traveling at 25 m/s when it crashes into the rear end of a 1650-kg car traveling at 21 m/s in the same direction on nearly frictionless ice. The two cars become stuck together and slide on the ice. How fast do the two cars move together immediately after the collision?.

Answers

The two cars will move together immediately after the collision at a speed of = 23 m/s

For solving this question, firstly we need to know the formula for Linear momentum,

⇒ Linear Momentum (p) = mass x velocity

⇒ p = m x v

m = body mass

v = velocity

NOTE- both cars are moving in the same direction

Car 1 weighs 2100 kg and was moving with a velocity of 25 m/s

⇒ Momentum = 2100 x 25

⇒ Momentum = 52500 kg-m/s

Car 2 weighs 1650 kg and was moving with a velocity of 21 m/s

⇒ Momentum = 1650 x 21

⇒ Momentum =  34650 kg-m/s

Total momentum before collision = 52500 + 34650

= 87150 kg-m/s

Momentum after collision = (2100 + 1650)v

= 3750v

By the law of conservation of linear momentum,

⇒ Momentum before collision = Momentum after collision

⇒ 87150 = 3750v

⇒ v = [tex]\frac{87150}{3750}[/tex]

⇒ v = 23 m/s

Therefore, The two cars will move together immediately after the collision at a speed of = 23 m/s

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The growth hormone axis contains at least one example of a negative feedback loop.
True
False

Answers

At least one instance of a negative feedback loop can be found in the growth hormone axis So this claim is True.

Control of thyroid hormone secretion is an important example of a negative feedback loop. Thyroxine and triiodothyronine, also known as "T4 and T3," are thyroid hormones  produced and secreted by the thyroid gland that affect metabolism throughout the body.

The female menstrual cycle is controlled by a negative feedback loop involving the brain. The  hypothalamus of the brain contains glands that secrete gonadotropin-releasing hormone (GnRH). The pituitary gland in the brain produces follicle-stimulating hormone (FSH) under command from GnRH.

The use of negative feedback loops in processes is found in homeostatic systems such as: Thermoregulation (changes in body temperature induce mechanisms that restore normal temperature levels).

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The engine of a car is developing a power of
90kW when it is moving on a horizontal road at
a constant speed of 100kmh. Estimate the total
horizontal force opposing the motion of the car.

Answers

With the use of power formula in dynamics, the magnitude of the opposing force is 3240 N

What is Power ?

Power is the rate at which work is done. Power can also be the product of force and velocity. It is measured in Watt.

Given that the engine of a car is developing a power of 90kW when it is moving on a horizontal road at a constant speed of 100kmh.

Power = work / Time

P = F × s/t

P = FV

Where

P = 90 KWV = 100 Km/hF = ?

Convert Km/h to m/s

100/3.6 = 27.77 m/s

Substitute all in the formula

90000 = F × 27.78

F = 90000/27.78

F = 3240 N

Therefore, the total horizontal force opposing the motion of the car is 3240 N

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Weighing a Bacterium Scientists are using tiny, nanoscale cantilevers 4 micrometers long and 500 nanometers wide-essentially miniature diving boards-as a sensitive way to measure mass. The cantilevers oscillate up and down with a frequency that depends on the mass placed near the tip, and a laser beam is used to measure the frequency. A single E. coli bacterium was measured to have a mass of 710 femtograms = 7.10×10−16 kg with this device, as the cantilever oscillated with a frequency of 17.1 MHz .Required:Treating the cantilever as an ideal, massless spring, find its effective force constant.

Answers

The effective force constant while Treating the cantilever as an ideal, massless spring is 8.19 N

What is the effective force constant?

The term "spring constant" refers to the proportional constant k. It gauges the stiffness of the spring. A spring exerts a force F = -kx in the direction of its equilibrium position when it is stretched or compressed to a length that differs by an amount x from its equilibrium length.

This question requires us to find the effective force constant.

The frequency f is given as

[tex]f=\frac{1}{2\pi } (\sqrt{\frac{k}{m}) }[/tex]

from the equation that we have above, we have

[tex]k = 4\pi ^2*f^2*m[/tex]

we have the values as

f =  17.1 MHz

m = 7.10×10−16 kg

put these values in the equation

[tex]k = 4 * 3.14^2 * (17.1*10^6)^2*(7.10*10^-^1^6)[/tex]

k = 8.19N/m

The effective force constant has been calculated as 8.19N/m

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Weighing a Bacterium Scientists are using tiny, nanoscale cantilevers 4 micrometers long and 500 nanometers wide-essentially miniature diving boards-as a sensitive way to measure mass. The cantilevers oscillate up and down with a frequency that depends on the mass placed near the tip, and a laser beam is used to measure the frequency. A single E. coli bacterium was measured to have a mass of 710 femtograms = 7.10×10−16 kg with this device, as the cantilever oscillated with a frequency of 17.1 MHz .

Treating the cantilever as an ideal, massless spring, find its effective force constant.

Covalent bonds are most likely to form between atoms of which types of elements?.

Answers

Answer:

Non-metals

a covalent bond is a bond where atoms share electrons

Nonmetals are most likely to form this type of bond

how much energy is required to remove a proton from 157n ? the masses of the atoms 157n , 146c and 11h are 15.000109 u , 14.003242 u and 1.007825 u , respectively.

Answers

Energy is required to remove a proton from ¹⁵N₇ with the masses of the atoms ¹⁵N₇, ¹⁴C₆ and H are 15.000109 u, 14.003242 u, and 1.007825 u, respectively is 10.2046375 MeV.

The energy required to remove a proton from ¹⁵N₇ is

The reaction to remove the proton is given as follows :

¹⁵N₇  ---->   ¹⁴C₆  +  H

The mass of ¹⁵N₇   =  15.000109

the mass of ¹⁴C₆ = 14.003242

The mass of H = 1.007825

The energy requires to remove a proton is given as:

E = ( 14.003242 + 1.007825 - 15.000109) u

E = 0.010958 × 9312.5 MeV

E = 10.2046375 MeV

A proton is a subatomic particle discovered within the nucleus of every atom. The particle has a fine electrical charge, identical and contrary to that of the electron. If isolated, a single proton might have a mass of the most effective 1.673. 10-27 kilogram, just barely less than the mass of a neutron.

A strong subatomic particle that has a positive rate equal in significance to a unit of electron fee and a relaxation mass of one.67262 × 10−27 kg, that's 1,836 times the mass of an electron. The proton become observed by Ernest Rutherford in the early 1900s. throughout this period, his research resulted in a nuclear response that led to the first 'splitting' of the atom, where he determined protons. He named his discovery “protons” based totally on the Greek word “protos” because of this first. Protons incorporate two up quarks and one down quark. Neutrons include one up quark and down quarks.

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A 2. 0 kg body is initially traveling at a velocity of 40 m/s east. If a constant force of 10 n due east is applied to the body for 5. 0 s, the final speed of the body is.

Answers

The final speed of a 2.0 kg body that is initially traveling at 40 m/s east and has a constant force of 10 N applied to the object for 5.0 s is 65 m/s.

The concept of momentum-impulse

This problem can be solved using the concept of momentum-impulse. Where the magnitude of the impulse is equal to the change in momentum.

The equation is:

F x Δt = m x v

We have,

The constant force = 10 N ⇒ F

Δt = 5.0 s ⇒ t

Mass of the body = 2.0 kg ⇒ m

And, the change in velocity is:

10 x 5 = 2.0 x v

v = 25 m/s

so, the final speed of the body is:

Initial velocity + change in velocity

= 40 m/s + 25 m/s

= 65 m/s

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Object A has a mass of 6 kg and is moving at a velocity of 5 m/s. Object B has
a mass of 4 kg and is moving at a velocity of 3 m/s. What is the Pnet of the
two objects?

Answers

∴ p = 13.2 kgms⁻¹. As a result, the ball has a momentum of 13.2 kgms1.

What is the Pnet of the two objects?

Given conditions ⇒

Mass of the ball = 6 kg.

Velocity = 2.2 m/s.

Using the Formula,

Momentum = mass × velocity

∴ p = mv

⇒ p = 6 × 2.2

∴ p = 13.2 kgms⁻¹.

Hence, the momentum of the ball is 13.2 kgms⁻¹.

∴ p = 13.2 kgms⁻¹. As a result, the ball has a momentum of 13.2 kgms1.

Velocity (v) is a vector quantity that measures displacement (or change in position, Δs) over the change in time (Δt), represented by the equation v = Δs/Δt.

momentum = 5x2 = 10 kg m/s.

Any object's velocity is a measurement of how swiftly it moves. Therefore, it can be described as the change in an object's position divided by time.

Both a magnitude (a value) and a direction are associated with velocity. Meters per second (meter/second) is the unit used to measure velocity.

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the formation ionic bond involves the _ of electrons

Answers

Answer--  The formation ionic bond involve the transfer of valence electron.

What is ionic bond?

-- Ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound.

Dependence  

1. THe ease of formation  fo the positive and negative ions from the respective neutral atoms.

2. The arrangements of the positive and negative ions in the solids , that is  the lattice of the crystalline compounds.

-- The formation of a positive ion involves ionisation i.e. removal of electron from the neutral atom and that of the negative ion involves the addition of electron to the neutral atoms..

( Ionic bonds will be formed more easily between elements with comparatively low ionization enthalpies and elements with comparatively high negative value of electron gain enthalpy.)

What is electron gain enthalpy?

--The electron gain enthalpy is the enthalpy change, when a gas phase atom in its ground state gain an electron.

-- EGE process may be exothermic or endothermic.

What is ionisation energy?

Ionisation energy is the minimum amount of energy required to remove the most loosely bound electron, the valence electron, of an isolated neutral gaseous atom or molecule

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what is the x -coordinates of the center of mass? hint: divide the triangle into vertical strips of width dx , then relate the mass dm of a strip at position x to the values of x and dx .

Answers

The centre of mass's x-coordinates are 1/M(x)dm.

To determine the triangle's centre of mass, we place a strip with a width of dx at a distance of x from the vertex of the triangle. To determine the length of this strip dx, comparable triangles like

Mass of the strip = dm

vertical strips of width = dx

l = x . (a/b)

The mass of the strip is dm=(2M/ab)ldx

The distance of the center of mass from the vertexs of the triangle is

            xCM     = 1/M∫(x)dm

In a uniform gravity field, the "centre of mass" or "centre of gravity" is the distinctive place within an object or system that can be used to characterise how the system responds to external forces and torques. The centre of mass is thought to be the average of all the masses divided by their respective separations. The torques generated are analogous to balancing a seesaw around a pivot in one plane.

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John is swinging a 100 g mass on a string around his head.
On one end of the string is a spring scale that says he is
exerting 5 N of centripetal force. Attached to the mass is a
speedometer that tells him the mass is moving at 4 m/s. How
long is the string?

Answers

Answer:25 feet

Explanation:

a 900 kg car moving at 10 m/s takes a turn around a circle with a radius of 25.0 m. determine the centripetal force acting on the car.

Answers

The centripetal force acting on the car is  36,000 N.

Centripetal force is the force that is directed towards the center of a circle and is necessary to keep an object in a curved path.

Step 1: Find the mass of the car.

Mass = 900 kg

Step 2: Find the velocity of the car.

Velocity = 10 m/s

Step 3: Find the radius of the circle.

Radius = 25.0 m

Step 4: Calculate the centripetal force.

Centripetal force = m*v2/r

Centripetal force = 900 kg * (10 m/s)2 / 25.0 m

Centripetal force = 36,000 N

Centripetal force is the force that is directed inward and is responsible for the circular motion of an object. It is directed towards the center of the circle and is perpendicular to the velocity of the object. It is usually caused by a combination of gravitational and/or electro-magnetic forces. It is the force that keeps an object in orbit around a larger object and keeps the moon in its orbit around the Earth.

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how much energy (in j) must the shock absorbers of a 1140 kg car dissipate in order to damp a bounce that initially has a velocity of 0.850 m/s at the equilibrium position? assume the car returns to its original vertical position.

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-384 jewels energy (in j) must the shock absorbers of a 1140 kg car dissipate in order to damp a bounce that initially has a velocity of 0.850 m/s at the equilibrium position

In a damped system, oscillatory motion is suppressed by frictional forces. The increase in the internal energy of the damping system makes up for the decrease in kinetic energy connected to oscillatory motion according to the law of conservation of energy.

We specify that the car's vertical equilibrium position is where the potential energy zero is located. The car's initial total mechanical energy is There has been a decrease of -384 jewels in energy.

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a string (with uniform mass density) is attached to a wave generator with variable frequency to create standing wave patterns. the string goes over a pulley and is connected to a mass (which can be varied) to create tension in the string. 1) if the frequency is changed (while the mass is held fixed), what else will change? the wavelength of the wave will change. the speed of propogation of the wave will change.

Answers

The speed at which a wave travels is unaffected by its wavelength. Waves C and D move forward at the same rate. Only changes in the characteristics of the medium a wave travels through can change its speed.

Does wavelength depend on propagation rate?

In a particular medium, the speed of propagation is constant; only the wavelength varies as the frequency does.

What influences a wave's propagation speed?

The characteristics of the medium have an impact on most waves' wave propagation speed in addition to frequency and wavelength variations. Tension, density, rigidity, and temperature are some of the variables that influence the speed of wave propagation.

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A revolutionary war era cannon is used in a demonstration. If the 200 kg cannon is on wheels when it's fired, it recoils. if the recoil speed is 0.8 m/s, what is the speed of the 9 kg cannon ball?

Answers

Answer:

17.8 m/s

Explanation:

This is a conservation of momentum problem.

Momentum = p = mv

x =  speed of the cannon ball

(200 kg)(0.8 m/s) = (9 kg)(x)

x = (160 kg·m/s) / (9 kg) = 17.8 m/s

a dentist's mirror is placed 2.4 cm from a tooth. the enlarged image is located 6.5 cm behind the mirror. (a) what kind of mirror (plane, concave, or convex) is being used? (b) determine the focal length of the mirror. (c) what is the magnification? (d) how is the image oriented relative to the object?

Answers

a) The kind of mirror it is concave.

b) to find the focal length we use the formula,

V  = uf/(u-f)

6.5 = -2.4f/(-2.4-f)

f = 3.8

c) magnification = v/u

=6.5/2.4

=2.7

d) image which is oriented to the object is  virtual and erect

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You place a 500 g block of an unknown subtance in an insulated container filled 2 kg of water. the block has an initial temperature of 50 degrees c. the water is initially at 20 degrees c. if the equilibrium temperature of the block and water is 25 degrees c, what is the specific heat of the block?

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The specific heat of the block is 3349J/kg C if a 500 g block of an unknown substance in an insulated container.

We know very well that if a system is in equilibrium state, it means that Heat loss = Heat gained

Also, Quantity of heat gained or released is given by = mcΔ∅

where m is defined as  mass of substance

c  is defined as the specific heat capacity

and Δ∅ is defined as the change in temperature

Therefore, applying the above formula by assuming heat lost by water will be heat gained by the block.

=>m₁×c₁×(∅₂-∅₁) = m₂×c₂×(∅₁-∅₃)

where m₁ is defined as the mass of block = 500g = 0.5kg

c₁ is defined as the specific heat capacity of unknown substance

∅₂ is defined as block initial temperature = 50°C

∅₁ is defined as equilibrium temperature of block and water after mix= 25°C

Also, we have m₂ as mass of water = 2kg

c₂ as specific heat capacity of water = 4186J/kg C

∅₃ as initial temperature of water = 20°C

Therefore, on putting the above quantities on above formula, we get

=>0.5×c₁×(50-25) = 2 x 4186×(25-20)

And we can find c₁ which is the unknown specific heat capacity

=>0.5×c₁×25=41860

=> c₁×12.5=41860

=>c₁=41860/12.5

=>c₁ =  3348.8J/kg C≅ 3349J/kg C

Hence, specific heat of the block is 3349J/kg C.

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What is the energy in a moving vehicle of mass 1500 kg at 60km hr?

Answers

The energy of the moving vehicle is 208.41 KJ.

The energy of a moving object or the energy possessed by an object in motion is called as the kinetic energy.

The kinetic energy formula is formulated as K.E. = (1/2)*m*v²

Where,

mass of the object/vehicle = m,

the speed at which the body is moving is v.

Kinetic energy is expressed in Kgm²/s²It has the SI unit as joule(J).

Mass of the vehicle = 1500 kg

Velocity of the vehicle = 60 km/hr

1 km/hr = 0.277 m/sec

60 Km/hr = 16.67 m/sec

Kinetic energy of the vehicle =  (1/2)*m*v²

K.E. =  (1/2)*1500*(16.67)²

K.E. = (1/2)*1500*277.88

K.E. = 208416.67 J

K.E. = 208.41 KJ

The energy in a moving vehicle of mass 1500 kg at 60km/hr is 208.41KJ.

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sodium vapor light averaging 589 nm inwavelength falls on a single slit of width. at what angle does it produces itssecond minimum? (b) what is the highest-orderminimum produced?

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a) The angle the sodium vapor light produces its second minimum is at 9.032°

b) The highest-order minimum produced is 12

D sin θ = n λ

D = Slit width

θ = Angle at which minimum is present

n = Order of minimum

λ = Wavelength of light

λ = 589 nm = 589 * 10⁻⁹ m

D = 7.5 μm = 7.5 * 10⁻⁶ m

n = 2

sin θ = n λ / D

sin θ = ( 2 * 589 * 10⁻⁹ ) / ( 7.5 * 10⁻⁶ )

sin θ = 0.157

θ = 9.032°

The highest order minimum is produced when θ = 90°.

n = D sin θ / λ

n = ( 7.5 * 10⁻⁶ sin 90° ) / ( 589 * 10⁻⁹ )

n = 12.7

n ≈ 12

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