From the list of world record track events in the table, calculate the average speeds for each race. Assume the length of each event is known to the nearest 0.1 m. Calculate only the last one, for 10,000 m.

 From The List Of World Record Track Events In The Table, Calculate The Average Speeds For Each Race.

Answers

Answer 1

Answer:

0.095 m/s

Explanation:

The average speed can be calculated as

Avg speed = distance/time

For the last one, we get that distance is 10000 m and the time 29 hours, 17 min, and 45 seconds.

So, first, we need to convert 29:17.45 to seconds as follows

29 hours x 3600 s/ 1 hour = 104400 s

17 min x 60 s / 1 min = 1020 s

45 s = 45 s

Total time = 104400 s + 1020 s + 45 s

Total time = 105,465 s

Then, the average speed is equal to

Avg speed = 10,000 m/105,465 s

Avg speed = 0.095 m/s

Therefore, the answer is 0.095 m/s


Related Questions

Traumatic brain Injury such as concussion results when the undergoes very large acceleration Generally an than 800 m/s ^ 2 lasting for any length of time will not , whereas an acceleration greater than 1, 000 m/s ^ 2 for at least 1 injury. Suppose a small child rolls off a bed that is 0.47 m above the floor. If the floor is hardwood the child’s head is brought to rest in approximately 2.1 mm. If the floor is carpeted,this stopping distance is increased to about 1.3 cm . Calculate the magnitude and duration of the deceleration in both cases, to determine the risk of injury. Assume the child remains horizontal during the fall to the floor. Note that a more complicated fall could result in a head velocity greater or less than the speed you calculate. Hardwood floor magnitude m/s^2Hardwood floor duration msCarpeted floor magnitude m/s^2Carpeted floor duration ms

Answers

ANSWER:

Hardwood floor magnitude: 2193.15 m/s^2

Hardwood floor duration: 1.38 ms

Carpeted floor magnitude: 354.27 m/s^2

Carpeted floor duration: 8.56 ms

STEP-BY-STEP EXPLANATION:

We have the following information:

Distance of the bed from the floor: 0.47 m

Stopping distance by hardwood: 2.1 mm

Stopping distance by carpet: 1.3 cm

We must find the speed of the child when he hits the ground using the following formula:

[tex]v^2=u^2+2gh[/tex]

Where v is the final velocity, u is the initial velocity, g is the gravitational acceleration and h is the distance traveled.

Replacing and solving for v

[tex]\begin{gathered} v^2=0^2+2\cdot9.8\cdot0.47 \\ v=\sqrt[]{9.212} \\ v=3.035\text{ m/s} \end{gathered}[/tex]

We can find the deceleration provided by the hardwood when stopping the child using the formula:

[tex]v^2=u^2-2aS[/tex]

Since the child will stop, the final speed will be 0, the initial speed will be the speed gained by the child while falling that we found in the first step, and the distance S to stop is given in the question.

Replacing and solving for a:

[tex]\begin{gathered} 2.1\text{ mm }\cdot\frac{1\text{ m}}{1000\text{ mm}}=2.1\cdot10^{-3}m \\ 0^2=3.035^2-2\cdot a\cdot(2.1\cdot10^{-3}) \\ 2\cdot a\cdot(2.1\cdot10^{-3})=9.211 \\ a=\frac{9.211}{2\cdot(2.1\cdot10^{-3})} \\ a=2193.15\text{ }\frac{m}{s^2} \end{gathered}[/tex]

From the calculated deceleration, we can find the time it takes for the child to stop after hitting the hardwood using the formula:

[tex]\begin{gathered} v=u-at \\ \text{replacing and solving for t:} \\ t=\frac{v-u}{-a} \\ t=\frac{0-3.035}{-2193.15} \\ t=0.00138\text{ s} \\ t=1.38\text{ ms} \end{gathered}[/tex]

We repeat the same procedure but now with the data of the carpet, therefore:

[tex]\begin{gathered} 1.3\text{ cm }\cdot\frac{1\text{ m}}{100\text{ cm}}=1.3\cdot10^{-2}m \\ 0^2=3.035^2-2\cdot a\cdot(1.3\cdot10^{-2}) \\ 2\cdot a\cdot(1.3\cdot10^{-2})=9.211 \\ a=\frac{9.211}{2\cdot(1.3\cdot10^{-2})} \\ a=354.27\text{ }\frac{m}{s^2} \end{gathered}[/tex]

Time for stopping by the carpet:

[tex]\begin{gathered} t=\frac{v-u}{-a} \\ t=\frac{0-3.035}{-354.27} \\ t=0.00856\text{ s} \\ t=8.56\text{ ms} \end{gathered}[/tex]

Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.00 ✕ 105 kg on springs that have adjustable force constants. Its function is to dampen wind-driven oscillations of the building by oscillating at the same frequency as the building is being driven—the driving force is transferred to the object, which oscillates instead of the entire building.(a) What effective force constant (in N/m) should the springs have to make the object oscillate with a period of 2.10 s? N/m(b) What energy (in J) is stored in the springs for a 1.80 m displacement from equilibrium? J

Answers

ANSWERS

(a) 3.58 x 10⁶ N/m

(b) 5.8 x 10⁶ J

EXPLANATION

Given:

• The mass of the object hanging from the spring, m = 4.00 x 10⁵ kg

Find:

• (a), The force constant the springs should have to make the object oscillate with a period of 2.10 s

,

• (b), The energy stored in the springs for a 1.80 m displacement from equilibrium.

(a) The period of an object in a spring is,

[tex]T=2\pi\sqrt{\frac{m}{k}}[/tex]

Where m is the mass of the object and k is the spring constant.

We want to find k for T = 2.10 s, so we have to solve this equation for k, which gives us,

[tex]k=m\cdot\left(\frac{2\pi}{T}\right)^2[/tex]

Replace the known values and solve,

[tex]k=4\cdot10^5\cdot\frac{4\pi^2}{(2.1)^2}\approx3,580,808.85N/m\approx3.58\cdot10^^6N/m[/tex]

Hence, the force constant is 3.58 x 10⁶ N/m.

(b) The energy stored in a spring with force constant k when the mass is displaced x meters from equilibrium is,

[tex]U_s=\frac{1}{2}kx^2[/tex]

Replace the known values and solve to find the energy stored in this spring,

[tex]U_s=\frac{1}{2}\cdot3.58\cdot10^6N/m\cdot1.8^2m^2\approx5.8\cdot10^6J[/tex]

Hence, the energy stored in the spring for a 1.80 m displacement from equilibrium is 5.8 x 10⁶ J.

A turkey with a mass of 9kg is running straight at you with a velocity of 5 m/s.What is the momentum of the turkey?

Answers

Given,

The mass of the turkey, m=9 kg

The velocity of the turkey, v=5 m/s

The momentum of a body is given by the product of the mass of the body and its velocity.

Thus the momentum of the turkey is given by,

[tex]p=mv[/tex]

On substituting the known values,

[tex]p=9\times5=45\text{ kg}\cdot\frac{m}{s}[/tex]

Thus, the momentum of the turkey is 45 kg·m/s

6m because of you multiply you will end up getting 6 m

The volume of a cylinder with height h and radius r can be found using the formula V = πr2hFind the volume of a cylinder with radius 8 feet and height 7 feet.__ ft3

Answers

In order to calculate the volume of this cylinder, let's use the given values of radius and height in the formula.

Using π = 3.1416, we have:

[tex]\begin{gathered} V=\pi r^2h \\ V=3.1416\cdot8^2\cdot7 \\ V=1.407.44 \end{gathered}[/tex]

So the volume is 1407.44 ft³.

Is science physics? If so I have a question on it

Answers

Inner Planets:

A planet whose orbit lies within the asteroid belt is called inner planets. Mercury, Venus, Earth and Mars are called th inner planets.

Outer Planets:

A planet whose orbit lies outside the asteroid belt is called outer planets. Jupiter, Saturn, Uranus and Neptune are called Outer Planets.

The potential difference across the ends of a wire is doubled in magnitude. If Ohm's law is obeyed, which one of the following statements concerning the resistance of the wire is true?a- The resistance is one half of its original value.b- The resistance decreases by a factor of four.c- The resistance is twice its original value.d- The resistance is not changed.e- The resistance increases by a factor of four.

Answers

Given:

The potential difference across the ends of a wire is doubled in magnitude

To find:

which one of the following statements concerning the resistance of the wire is true

Explanation:

The potential difference is doubled in magnitude. We know, according to Ohm's law,

[tex]V=IR[/tex]

I is the current and R is the resistance.

If the potential difference increases, the product of I and R also increases.

Now the resistance depends as,

[tex]\begin{gathered} R=\frac{\rho l}{A} \\ \rho\text{ is the resistivity, l is the length and A is the area of the conductor.} \end{gathered}[/tex]

The resistance is independent of potential differences. When the potential difference increases, the current also increases and the resistance remains the same.

Hence, The resistance is not changed.

URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!!

Answers

Answer:

First option

Explanation:

The battery contains chemicals and the electrical energy will be produced FROM those chemicals and then when it goes into the bell the bell uses that energy to turn into sound using an electromagnet

Answer: chemical energy from the battery will be transformed into electricity energy which is this Transformer by the Dell to the security energy

Explanation:

URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!!

Answers

the answer would be A

Bluetooth and Wi-Fi use the same frequency band. Give one reason why Bluetooth signal does not interfere with Wi-Fi signal.

Answers

There is interference between both signals especially if they are operated in same time and space. The technology that bluetooth uses helps reduce interference from wifi signals. This technoogy is called the frequency hopping spread spectrum which changes channel frequency. This only reduces interference.

You have been given 3.152 g of copper from which you are to fashion a wire whose resistance is 2,473.562 ohms. The density of copper is 8900 kg/m 3 and the resistivity of copper is 1.7 x 10 -8 ohm m. What will the diameter, in mm, of the wire be that you fashion?

Answers

Given:

Mass of copper, m = 3.152 g = 0.003152 kg

Resistance = 2,473.562 ohms

Density of copper = 8900 kg/m³

Resistivity of copper = 1.7 x 10⁻⁸ ohm.m

Let's find the diameter of the wire.

Apply the density formula to find the volume:

[tex]\begin{gathered} \rho=\frac{m}{v} \\ \\ v=\frac{m}{\rho}=\frac{0.003152}{8900} \\ \\ v=3.54*10^{-7}\text{ m}^3 \\ \\ (\pi r^2)l=3.54*10^{-7}\text{ m}^3 \end{gathered}[/tex]

Now, apply the formula:

[tex]\begin{gathered} R=\frac{\rho l}{A} \\ \\ l=\frac{RA}{\rho} \\ \\ l=\frac{2473.562*\pi r^2}{1.7*10^{-8}} \\ \\ \frac{l}{\pi r^2}=\frac{2473.562}{1.7*10^{-8}} \\ \\ \frac{l}{\pi r^2}=1.455*10^{11} \\ \\ l=1.455*10^{11}*\pi r^2 \end{gathered}[/tex]

Now, combine both expressions for L:

[tex]1.455*10^{11}*\pi r^2*\pi r^2=3.54*10^{-7}[/tex]

Solving further:

[tex]\begin{gathered} (\pi r^2)^2=\frac{3.54*10^{-7}}{1.455*10^{11}} \\ \\ (\pi r^2)=\sqrt{2.434*10^{-18}} \\ \\ \pi r^2=1.56*10^{-9} \\ \\ r^2=\frac{1.56*10^{-9}}{\pi} \\ \\ r=\sqrt{\frac{1.56*10^{-9}}{\pi}} \\ \\ r=2.228*10^{-5} \end{gathered}[/tex]

r is the radius.

We know that:

Diameter = 2 x radius

Thus, we have:

[tex]\begin{gathered} d=(2.228*10^{-5})*2 \\ \\ d=4.4569*10^{-5}\text{ m} \\ \\ d=0.044569*10^{-3}m \\ \\ d=0.0446\text{ mm} \end{gathered}[/tex]

Therefore, the diameter in mm will be 0.0446 mm

ANSWER:

0.0446 mm

a car travels 680 km in a time of 4 h calculate its speed​

Answers

Hello..!

To calculate its speed we apply the following data.

Data:

D = 680kmT = 4hrsV = ?

Then, we apply the formula that is.

Formula:

V = D/T

Finally we develop the problem.

Developing:

V = 680km / 4hV = 170km/h

The speed of the car is 170 kilometers per hour.

Jack is selling lemonade at a stand outside his house. He is charging $1.50 per cup. He needs to make at least enough money to cover the cost of his supplies, which were $15.25.What is the minimum number of cups of lemonade Jack needs to sell?

Answers

Given,

Charge of one cup of lemonade, c=$1.50

The amount Jack needs, T=-$15.25

The number of cups Jack needs to sell in order to have the given amount can be calculated as,

[tex]N=\frac{T}{c}[/tex]

On substituting the known values,

[tex]\begin{gathered} N=\frac{15.25}{1.5} \\ =10.17 \end{gathered}[/tex]

The number of cups of lemonade that can be sold should be a whole number. If Jack sells 10 cups, which is lesser than the answer, he will have less amount than he wanted.

Thus he has to sell 11 cups.

Therefore the minimum number of cups Jack needs to sell is 11.

Answer: I have all answers in screen shots

Hope this helps

When you describe a metal surface as smooth, what property are youdescribing?7O A. ColorO B. HardnessO C. ShapeO D. TextureSUBMIT

Answers

Answer: D. Texture

Explanation:

Texture is used to describe the characteristics of a surface. A surface can be described as smooth or rough. Thus, the correct option is

D. Texture

The barrel of a rifle has a length of 0.983m. A bullet leaves the
muzzle of a rifle with a speed of 602m/s. What is the
acceleration of the bullet while in the barrel? A bullet in a rifle
barrel does not have constant acceleration, but constant
acceleration is to be assumed for this problem.
Answer in units of m/s^2

Answers

According to the solving, the acceleration of the bullet while in the barrel is 184335.7 m/s^2.

What is acceleration?

Any action where the velocity changes are said to it as acceleration. There are only two ways to accelerate: altering your speed or altering your direction, or altering both. This happens because velocity is both a speed and a direction.

According to the given data,

The length of the barrel of the rifle is 0.983 m.

The speed of the bullet is 602m/s.

We know,

v^2 = u^2+ 2aS

Initial velocity, u=0

v=602m/s.

S= 0.983 m.

So,

v^2=u^2+2aS

(602)^2= 0+ 2*a*0.983

1.966a=362404

a=362404/1.966

a= 184335.7 m/s^2.

According to the solving, the acceleration of the bullet while in the barrel is 184335.7m/s^2.

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An aluminum sphere is 8.55 cm in diameter. What will be it's % change in volume if it is heated from 30 C to 155 C?

Answers

We know that

• The sphere diameter is 8.55 cm.

,

• The temperature change is from 30 C to 155 C.

First, we have to find the radius of the sphere. The radius is the half diameter.

[tex]\begin{gathered} r=\frac{d}{2}=\frac{8.55\operatorname{cm}}{2} \\ r=4.275\operatorname{cm} \end{gathered}[/tex]

Now we have to find the volume of the sphere using the following formula.

[tex]V=\frac{4}{3}\pi(r)^3[/tex]

Where r = 4.275 cm.

[tex]\begin{gathered} V=\frac{4}{3}\pi(4.275\operatorname{cm})^3 \\ V\approx327.26(cm)^3 \end{gathered}[/tex]

Then, we use the following formula

[tex]V_2-V_1=BV_0(T_2-T_1)[/tex]

Where the initial volume is 327.26 cubic cm, B is a constant about thermal expansion for aluminum, and we have to find the final volume to then calculate the percentage change.

[tex]\begin{gathered} \Delta V=75\times10^{-6}\cdot327.26(155-30) \\ \Delta V=75\times10^{-6}\cdot327.26(125) \\ \Delta V\approx3.07(cm)^3 \end{gathered}[/tex]

This means that the volume change is 3.07 cubic centimeters.

At last, we have to divide the volume change by the initial volume, and then we have to multiply it by 100% to express it as a percentage.

[tex]\frac{\Delta V}{V_1}\times100=\frac{3.07}{327.26}\times100\approx0.938[/tex]Therefore, the percentage change is 0.938%.

Match each expression on the left with an equivalent expression on the right. Some answer choices on the right will not be used.1/50.451/80.6259/203/40.1250.24/55/8

Answers

Answer:

1/5 = 0.2

1/8 = 0.125

9/20 = 0.45

3/4 = 0.75

4/5 = 0.8

5/8 = 0.625

Explanations:

This exercise is to convert the given fractions to decimals

Let us find the decimal equivalents of each of the fractions first, then the equivalent choices can be matched together

1/5 = 0.2

1/8 = 0.125

9/20 = 0.45

3/4 = 0.75

4/5 = 0.8

5/8 = 0.625

A strobe-light series of pictures is taken of a red ball and a blue ball. The red ball was allowed to drop straight down, and the blue ball was given an initial horizontal velocity. Lines are drawn connecting each red ball image with the corresponding blue ball image. Describe the lines connecting the images.1) The lines slope down from the red ball to the corresponding blue ball.2) The lines slope up from the red ball to the corresponding blue ball.3) The lines are vertical.4) The lines are horizontal.

Answers

The lines are horizontal.

Horizontal velocity doesn't have any effect on the acceleration or speed of falling. In every picture, the red and the blue are both at the same HEIGHT, even though the blue one is pulling away horizontally.

This week we discuss injuries to the head, neck and spine. There are so many long term affects of so many different head injuries. One of the biggest changes to head injuries that we have seen in the last decade is the implementation of concussion protocol. No matter the age or activity, the medical world has a recommended protocol for possible concussions and any head injury.

This weeks assignment. Research concussion protocol and submit the following in a written paper format.

-What is a concussion?

-Why do we need to have a concussion protocol?

-Who needs a concussion protocol? This is in regards to caring for injuries, not the injured person itself,

-Is there a standard concussion protocol should you follow? What is it?

-At a minimum, concussion protocol steps should include the what people in the process?

-Have you or anyone you know had to follow concussion protocol for a head injury? Tell me about it.

This is due Sunday I want to get started on it please someone help me ?

Answers

Answer:

Concussion is the most common type of mild traumatic brain injury and can have serious consequences

Explanation:

b)= combined resistance of the 2 Ω and 4 Ω resistors connected in series

Answers

R1=6 Ω

R2=3 Ω

R3=2 Ω

R4=4 Ω

6 Ω and 3Ω resistances are connected in parallel.

First, find the equivalent resistance:

ER1 = R1*R2/(R1+R2)= 6*3/6+3 = 18/9 =

The resistances of 2 Ω and 4 Ω are connected in series:

TR2 = R3+R4 = 2 Ω+4 Ω= 6 Ω (b)

ER1 and TR2 are connected in parallel.

RT = ER1*TR2/ ER1+TR2= 2*6/2+6=12/8 = 1.5 Ω

Now, we can calculate the I (current)

On parallel circuits, Voltage is always the same. (12V)

But for series is VT=V1+V2

We have to find the current flowing across R3 and R4 (TR2)

V= I*R

I= V/R = 12/TR2= 12/6 = 2 A

With that current, we can calculate the voltage (potential difference) on R3 (2 Ω)

V=I*R= 2*2 = 4V (ai)

(aii) potential difference across the 3 Ω resistor

Since it is a parallel circuit , potential difference is always the same = 12V

b.combined resistance of the 2 Ω and 4 Ω resistors connected in series

R3+R4 = 2 Ω+4 Ω= 6 Ω (b)

A cyclist advances 38 km in 1 hour and 30 minutes. Your average speed was: Select one: 47 0 25.3 km/h OR 22 km/h OR 18 km/h OR 38 km/h​

Answers

Hello..!

We initially apply the data to the problem.

Data:

D = 38kmT = 1.5hV = ?

Then, we apply the formula that is.

Formula:

V = D/T

Finally we develop the problem.

Developing:

V = 38km / 1.5hV = 25.3km/h

Therefore the correct option is 25.3 kilometers per hour.

Answer:

Formula

V = d/t

Resolve

V = 38km / 1.5hV = 25.3 km/h

Hope this helped

Question 24 (1 point)—A beam of white light hits a prism and is dispersed into the its spectral componentsred, orange, yellow, green, blue, indigo, and violet. If a second prism is placed so thatonly the red band of light can pass through, what will happen?No light will pass through the second prism because red light does not haveenough energyThe prism will disperse the red light into many shades of redThe prism will polarize the red lightThe prism will refract the red light but it will still be the same color of red

Answers

prism can disperse a compound light

red is a single coloured light

when it will pass through the prism it will get refracted again but the output will be the red one

so the answer is

The prism will refract the red light but it will still be the same color of red

Gamma rays require _____ to be stopped.1) paper2) glass3) aluminum4) lead

Answers

The gamma rays are having very large frequency. Thus, the energy acquired by the gamma ray photons is very large.

To stop the gamma ray, highly dense material is required.

The density of the lead is more than any other element in the given opitons.

Thus, the lead is used to stop the gamma rays.

Hence, 4th option is the correct answer.

Can you help me with this question? Find the sum of -2x^2 - 4x - 12 and - x^2 - 2x The answer I got was -3x^2 - 6x - 12 Just want to see if I did it correctly*Last tutor got disconnected

Answers

You have the following sum of expression:

(-2x^2 - 4x - 12) + (-x^2 - 2x)

In order to find the sum, simplify like terms (terms with the same variable and same exponent). Then, you have:

(-2x^2 - 4x - 12) + (-x^2 - 2x) =

-2x^2 - x^2 - 4x - 2x -12 =

-3x^2 - 6x - 12

Hence, the answer is -3x^2 - 6x - 12

It is hard to see the motion of stars because of their extreme distance from us.

Answers

It is hard to see the motion of stars because of their extreme distance from us is a True statement.

The locations of the stars in the sky remain largely constant with respect to one another. Taurus is constantly close to Orion. Draco is continually around Ursa Minor. The stars are a continuous backdrop painting when we observe the sky; they don't move much in relation to one another.

While we orbit the sun throughout the year, there are some minute movements. Stars farther away move slightly more left and right than stars closer to us. Even if it has a minor effect, it makes sense. You'll notice that distant items move less in relation to you than nearer ones if you stare out into the distance while you go along the street.

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I need help with questions number 2 I have the answer to number 1

Answers

Given,

the distance from Redd's door to the park, s=15 m

The total distance is the sum of the distance from her door to the park and the distance from the park to her door.

That is,

[tex]\begin{gathered} \text{total distance}=s+s \\ =15+15 \\ =30\text{ m} \end{gathered}[/tex]

The displacement is defined as the shortest distance from the starting and ending point of a path. The starting and ending point of Redd's path is the door.

Therefore the total displacement is zero meters.

Therefore, distance = 30 m

and displacement = 0 m

How much work must you do to stretch the spring 0.030 m ? and how much work must you do to compress it 0.030m ?

Answers

Given:

The force constant of spring is

[tex]k\text{ =2.5}\times10^4\text{ N/m}[/tex]

To find the work done when spring is stretched to 0.03 m and work done when compressed to 0.03 m.

Explanation:

The work done to stretch the spring will be

[tex]\begin{gathered} W\text{ =}\frac{1}{2}kx^2 \\ =\frac{1}{2}\times2.5\times10^4\times(0.03)^2 \\ =\text{ 11.25 J} \end{gathered}[/tex]

The work done to compress the spring will be

[tex]\begin{gathered} W\text{ =-}\frac{1}{2}kx^2 \\ =-\frac{1}{2}\times2.5\times10^4\times(0.03)^2 \\ =-11.25\text{ J} \end{gathered}[/tex]

You call out in a loud voice and hear an echo of your voice. Where are you most likely located?A.In a boat on a lakeB.In an open fieldC.In a canyonD.In a forest

Answers

We will have the following:

Since sound bounces off of surfaces particularly ones that are perpendicular, then in this scenario you are most likely located in a canyon.

A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat. From this data, calculate the specific heat of aluminum.Group of answer choices2.11 J/g °C4.29 J/g °C0.213 J/g °C

Answers

213 J/g °C is  the specific heat of aluminum when a block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat.

C=Specific heat

Q=heat energy (J)0.14 K

M =Mass (Kg)

∆T= change in temperature (K)

   M= 140 g = 0.14Kg

   Q - 1080 Joules.

   ∆T=98.4 – 62.2 = 36.2

Q=MC∆T

C =Q/M∆T

C= 1080÷0.14×36.2

C=213 J/g °C

The term "specific heat" refers to the quantity that quantifies how a substance's additional heat energy affects its temperature. The unit is  J/g °C. It is generally used in Thermodynamics.

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A girl weighs 58kg and runs up a staircase 52m high in 23seconds. Find her minimum power output

Answers

Given,

The mass of the girl, m=58 kg

The height of the staircase, h=52 m

The time she takes to run up the staircase, t=23 s

The work the girl does to climb up the staircase is equal to the change in the potential energy of the girl.

Thus the work done is given by,

[tex]W=\text{mgh}[/tex]

Where g is the acceleration due to gravity.

On substituting the known values,

[tex]\begin{gathered} W=58\times9.8\times52 \\ =29.56\times10^3\text{ J} \end{gathered}[/tex]

The power output is equal to the rate at which the work is done

Thus the power output is given by,

[tex]P=\frac{W}{t}[/tex]

On substituting the known values,

[tex]\begin{gathered} P=\frac{29.56\times10^3}{23} \\ =1285.22\text{ W} \end{gathered}[/tex]

Thus the maximum power output is 1285.22 W

The picture below shows a skateboarder just before he drops down a ramp. Assume the skateboarder does not experience any friction.Which correctly shows the potential energy and kinetic energy of the skateboarder as he moves down the left side of the ramp and up to the top of the right side?

Answers

We are given that a skater is on top of a ramp. At this point the skater has the maximum gravtitaional potential energy "PE" and a minimum kinetic energy "KE". The gravitational potential enery depends on the height of the skater and the kinetic energy depends on his velocity.

When the skater is at the bottom of the ramp his gravitational potential energy is minimum since his height is the lowest and his kientic energy is maximum since all the gravitational potential eerngy has turn into kinetic energy. This means that at the lowest point the velocity is also maximum.

Whe teh sketer reaches the highest point in the right side his kinetic energy has converted again into gravitational potential energy since the height has increased. Now, the kinetic energy is minimum and the gravitational potential energy is maximum.

This can be seen represented next:

The graph should be a representation of the fluctuations in kinetic and potential energy, therefore, the only graph that represetns this is B.

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