From a window 100ft above the ground in building A, the top and bottom of building B are sighted so that the angles are 70 degrees and 30 degrees respectively. Find the height of building B?
Answers
Given:-
From a window 100ft above the ground in building A, the top and bottom of building B are sighted so that the angles are 70 degrees and 30 degrees respectively.
To find:-
The height of building B.
So now, the image of the given data is,
So now we find the value of PS. so we get,
[tex]\begin{gathered} \tan \text{ 30=}\frac{100}{PS} \\ \frac{1}{\sqrt[]{3}}=\frac{100}{PS} \\ PS=100\sqrt[]{3} \end{gathered}[/tex]So now we find the height of QS,
[tex]\begin{gathered} \tan \text{ 70=}\frac{QS}{PS} \\ 2.7474=\frac{QS}{100\sqrt[]{3}} \\ QS=100\sqrt[]{3}\times2.7474 \\ QS=475.84 \end{gathered}[/tex]So the total height is,
[tex]100+475.84=575.84[/tex]So the height of building B is 575.84
Related Questions
A line passes through (1, -1) and (3, 5).What is the equation of the line in slope-intercept form?
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Step 1 : Let's find the points given in the cartesian plane and let's draw the line.
Step 2: Let's calculate m (slope), as follows:
m = (Y - Y1)/((X -X1)
Replacing with the values we already know, we have:
m = (5 - (-1)/ 3 - 1
m = 6 /2 = 3
Step 3: Now, we can write the equation, as follows:
y - y1 = m (x -x1)
y - (-1) = 3 (x - 1)
y + 1 = 3x - 3
y = 3x -4
This is the equation that solves the question: y = 3x - 4
g(x)= 6/x find (g°g). and domain in set notation.
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We have to find the expression for the composition
[tex]g\circ\text{ g\lparen x\rparen}[/tex]Where
[tex]g(x)=\frac{6}{x}[/tex]And express its domain in set notation. We will start by finding the expression for the composition
[tex]g\circ\text{ }g(x)=g(g(x))=g(\frac{6}{x})[/tex]that is we firsts evaluate the inner functions that in this case is g, now taking as argument y=6/x, we evaluate the outer function that in this case also is g, as follows:
[tex]g\text{ \lparen }\frac{6}{x})=\frac{6}{\frac{6}{x}}=\frac{6}{6}=x[/tex]That is, the composition g*g is equal to x, the identity.
Now we will find the domain of g*g:
Note that the domain of a composition is an interception, as follows:
[tex]Domain\text{ }g\circ\text{ g=\textbraceleft Domain of }g\text{ \textbraceright }\cap\text{ \textbraceleft Image of }g\text{ \textbraceright}[/tex]Therefore, we have to find the domain and image of g, and intercept both sets. We start with the domain of g_
[tex]Domain\text{ of }g\text{ }=\text{ }\mathbb{R}\text{ - \textbraceleft0\textbraceright}[/tex]That is all the real numbers except the 0. Now note that the image of g is
[tex]Image\text{ g= }\mathbb{R}\text{ - \textbraceleft0\textbraceright}[/tex]Finally, the domain of the composition g*g, can be obtained by the formula above:
[tex]Domain\text{ of }g\circ\text{ g=}\mathbb{R}\text{ -\textbraceleft0\textbraceright }\cap\text{ }\mathbb{R}\text{ - \textbraceleft0\textbraceright= }\mathbb{R}\text{ - \textbraceleft0\textbraceright=}(-\infty\text{ },0)\text{ }\cup\text{ }(0,\infty)\text{ }[/tex]Therefore, the domain of the composition are all the real numbers excluding the 0.
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my work is saying solve for the value of a
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Using the definition of suplementary angles we know that the angle that contains a and the 75° added together are 180°
[tex]75+(9a+6)=180[/tex]solve the equation for a
[tex]\begin{gathered} 81+9a=180 \\ 9a=180-81 \\ 9a=99 \\ a=\frac{99}{9} \\ a=11 \end{gathered}[/tex]create 3 equivalent fractions for the fraction 2/7 . Explain how all of those are equivalent
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create 3 equivalent fractions for the fraction 2/7 . Explain how all of those are equivalent
we have the fraction
2/7
Remember that equivalent fractions are fractions that the quotient is the same
If you multiply a number by 1 or 1/1 the result is the same number
Example
if you have 2/7 and you multiply by (3/3)
(2/7)*(3/3)
remember that 3/3=1
so
(2/7)*(3/3)=6/21
2/7 and 6/21 are equivalent fractions
because
2/7=0.2857
6/21=0.2857
second equivalent fraction
2/7 multiply by 5/5
(2/7)(5/5)=10/35
2/7 and 10/35 are equivalent
because
2/7=0.2857
10/35=0.2857
third equivalent fraction
2/7 multiply by 4/4
(2/7)(4/4)=8/28
2/7 and 8/28 are equivalent
because
2/7=8/28
multiply in cross
2*28=7*8
56=56 ----> is true
that means
fractions are equivalent
Remember
If you multiply the numerator and denominator of a fraction, by the same number, you obtain a equivalent fraction
Right angle ABC is taken by dilation with center P and scale factor 1/2 to angle A’B’C’. What is the measure of angle A’B’C’
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The measure of angle A'B'C' will be 90 degree.
What is Translation?
A transformation that occurs when a figure is moved from one location to another location without changing its size or shape is called translation.
Given that;
Right angle ABC is taken by dilation with center P and scale factor 1/2 to angle A’B’C’.
Now,
Since, We know that;
When a figure is dilated by a scale factor then the shape of the figure is not change.
Thus, The measure of ABC is same as the measure of A'B'C'.
Here, The measure of angle ABC = 90 degree
Hence, The measure of angle A'B'C' = 90 degree.
Therefore, The measure of angle A'B'C' will be 90 degree.
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14 Find the percent increase or decrease for each of the following values (indicate whether each is an increase or a decrease). a. 4x to x/ b. 0.25m to 0.5m 5 c. + 2p to d.y to 0.687 8 р 15 Consider the following relationships. TI. 1
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The percentage increase or decrease is given by
[tex]\frac{final\: \text{amount}-original\: \text{amount}}{original\: \text{amount}}\times100\%[/tex]Let us find the percentage increase or decrease for the given cases.
a) 4x to x
[tex]\begin{gathered} \frac{x-4x}{4x}\times100\% \\ \frac{-3x}{4x}\times100\% \\ -0.75\times100\% \\ -75\% \end{gathered}[/tex]Therefore, it is a percentage decrease (-75%) since it is negative.
b) 0.25m to 0.5m
[tex]\begin{gathered} \frac{0.5m-0.25m}{0.25m}\times100\% \\ \frac{0.25m}{0.25m}\times100\% \\ 1\times100\% \\ 100\% \end{gathered}[/tex]Therefore, it is a percentage increase (100%) since it is positive.
c) 1/2p to 5/8p
[tex]\begin{gathered} \frac{\frac{5}{8}p-\frac{1}{2}p}{\frac{1}{2}p}\times100\% \\ \frac{\frac{1}{8}p}{\frac{1}{2}p}\times100\% \\ \frac{1}{8}\times\frac{2}{1}\times100\% \\ \frac{2}{8}\times100\% \\ \frac{1}{4}\times100\% \\ 25\% \end{gathered}[/tex]Therefore, it is a percentage increase (25%) since it is positive
d) y to 0.68y
[tex]\begin{gathered} \frac{0.68y-y}{0.68y}\times100\% \\ \frac{-0.32y}{0.68y}\times100\% \\ -0.47\times100\% \\ -47\% \end{gathered}[/tex]Therefore, it is a percentage decrease (-47%) since it is negative.
The following two-way table describes student'safter school activities. Find the probability that arandomly selected student is in sports.GradeMusic/DramaWorkSports20Sophomore73Junior2013255SeniorP(Sports) = [? ]%25
Answers
Solution
The Probability that a random selected students is in sports is
[tex]P(Sports)=\frac{65}{Total}=\frac{65}{20+20+25+7+13+5+3+2+5}=0.65=65\%[/tex]The answer is 65%
On his way home from school board meeting , Keith fills up his car. He like the idea of using gasoline with ethanol , but think his car only handle 40% ethanol. At the gas station , he can use regular gas with 10% ethanol or E85 fuel with 85% ethanol. How many gallons of each type of fuel should Keith use if he wants to fill up his car with 10 gallons of fuel containing 40% ethanol ?
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ANSWER:
6 gallons regular gas with 10% ethanol and 4 gallons E85 fuel with 85% ethanol
STEP-BY-STEP EXPLANATION:
In this case, we must test with values for each fuel class to arrive at the correct answer.
For example, 6 gallons of 10% ethanol and 4 gallons of 85% ethanol:
[tex]\begin{gathered} 10\text{\% of 6 =}\frac{10}{100}\cdot6=0.6\text{ gallons of ethanol in it} \\ 85\text{\% of 4 =}\frac{85}{100}\cdot4=3.4\text{ gallons of ethanol in it} \\ \text{ Total ethanol in 10 gallons is 0.6 + 3.4 = 4 gallons }\rightarrow\text{ 4 gallons is 40\% of 10} \\ \text{Therefore, we have 10 gallons of fuel containing 40\% ethanol } \end{gathered}[/tex]The length of cell A is 3x10-5 m. The length of cell B is 0.000001 m.What is the ratio of cell A's length to cell B's length? Use pencil and paper. Is it easier to find the ratiowhen the numbers are expressed in scientific notation or in standard form? Explain your reasoning.The ratio of cell A's length to cell B's length is(Type the ratio as a simplified fraction.)
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we have the following:
[tex]\begin{gathered} r=\frac{L_A}{L_B} \\ r=\frac{3\cdot10^{-5}}{0.000001}=\frac{3\cdot10^{-5}}{1\cdot10^{-6}} \\ r=30 \end{gathered}[/tex]the rario is 30
The length of a rectangle is 5 yd more than twice the width x. The area is 462 yd".
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The given problem is about rectangle areas.
The area of a rectangle is defined as
[tex]A=w\cdot l[/tex]Where w is width and l is the length.
In this case, we know that the length is 5 yards more than twice the width, where the last one is expressed as x.
[tex]l=2x+5,w=x[/tex]We also know by given that
[tex]A=462yd^2[/tex]Using all the given information, we have
[tex]462=x(2x+5)[/tex]Where we solve for x, first, we apply the distributive property.
[tex]462=2x^2+5x[/tex]Now, we move all terms to one side only
[tex]2x^2+5x-462=0[/tex]Using a calculator, we have
[tex]x_1=14,x_2=-\frac{33}{2}[/tex]Where 14 represents the width because distances cannot be expressed by negative numbers.
[tex]l=2(14)+5=28+5=33[/tex]Therefore, the width of the rectangle is 14 yards, and its length is 33 yards.the total amounts of rainfall at various points And time during a thunderstorm are shown in the table. time(hours) 0.4 | 1.1 | 2.9 | 3.2 | 3.7 | 4.4Rainfall(cm) 0.3 | 0.6 | 1.8 | 2.0 | 2.2 | 2.6According to a regression calculator, what is the equation of the line of best fit for the data?answers: a y= 0.06x+0.03 | b y= 0.06x+0.29 | c y=0.59x+0.03 | d y= 0.59x+0.29Please help!
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I need help with this geometry question can someone help me the first one says parallelogram with non perpendicular and non congruent adjacent sides, trapezoid with exactly one pair of parallel sides, rectangle with non congruent adjacent sides, and rhombus with non perpendicular adjacent sides
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a) rhombus with no perpendicular adjacent sides.
b) kite
Data: x y 4 1 5 2 6 3 7 4 y = x - ?
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In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
x y
4 1
5 2
6 3
7 4
y = x - ?
Step 02:
equation of the line:
y = x - ?
y = mx + b
m = slope = 1
point ( 4 , 1)
Point-slope form of the line
(y - y1) = m (x - x1)
(y - 1) = 1 (x - 4)
y - 1 = x - 4
y = x - 4 + 1
y = x - 3
The answer is:
y = x - 3
10.Find the approximated circumference of a circle whose area is 136.46
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The area of a circle is given by the following formula:
[tex]A=\pi r^2[/tex]Where r is the radius.
We know the area of the circle, then we can replace it in the formula and find r:
[tex]\begin{gathered} 136.46=\pi\cdot r^2 \\ r^2=\frac{136.46}{\pi} \\ r^2=43.44 \\ r=\sqrt[]{43.44} \\ r=6.59 \end{gathered}[/tex]The circumference of a circle is given by the formula:
[tex]C=2\pi r[/tex]By replacing the r-value that we found, we can solve for C:
[tex]\begin{gathered} C=2\cdot\pi\cdot6.59 \\ C=41.41 \end{gathered}[/tex]The approximated circumference of the circle is 41.41
The graph shows the number of centimeters a particular plant grows over time. What is the slope of the line? Reasoning What does the slope mean?
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We have the following:
The slope is about 1
The slope is the increment per unit, in this case it would be the increment in cm per week.
[tex]undefined[/tex]use the equation of a parabola in standard form having a vertex at (0, 0), x^2= 8y.Solve the equation for "p" and then describe the focus (0, p), the directrix, and the 2 focal chord endpoints.
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Solution
We have the following equation:
[tex]x^2=8y[/tex]the general formula for a parabola is given by:
[tex](x-h)^2=4p(y-k)[/tex]Where (h,k) =(0,0) represent the vertex, so then our equation is:
[tex]x^2=4py[/tex]By direct comparison we have this:
4p= 8
p = 2
Then the focus is given by:
(0,p) = (0,2)
the directrix is given by:
y= 0-p = 0-2= -2
y=-2
And finally the 2 focal chord endpoints are:
[tex](|2p|,p)=(4,2),(-|2p|,p)=(-4,2)[/tex]Solve the inequality: 4x + 8 - 5x > 13
Answers
4x+8-5x > 13
Combine like terms
4x-5x+8> 13
-x +8 > 13
Subtract 8 from both sides:
-x+8-8 > 13-8
-x > 5
Multiply both sides by -1
x < -5
2) Tell whether each relationship is a direct variation. If it is a direct variation, find the constant of variation. (Remember, the constant of variation is the k.) Explain.
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2a) it is not a direct variation
2b) it is a direct variation; k = -4
Explanantion:For the relationship to be a direct variation, it must follow the formula:
y = kx
where k = constant of variation
k = y/x
The value of k must be constant for all
for 2a:
when y = 0, x = -3
k = 0/-3 = 0
when y = 3, x = 1
k = 3/1 = 3
when y = 6, x = 3
k = 6/3 = 2
From the above, the value of k is not constant. hence, it is not a direct variation
for 2b:
when y = -10, x = 2.5
k = -10/2.5 = -4
when y = -20, x = 5
k = -20/5 = -4
when y = -30, x = 7.5
k = -30/7.5 = -4
From the above, the value of k is constant. Hence, it is a direct variation
The constant of variation, k = -4
which does not name an integer a.-35 b. 0 c. 3/15d. 10/2
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The integer numbers are the whole numbers or the numbers that are not written as a/b
For the given question
-35 is an integer number
0 is an integer number
10/2 = 5 is an integer number
3/15 = 1/5 is not an integer number
So, the answer will be option c. 3/15
Find the x and y intercept then use them to graph the line
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The x-intercept = (7, 0)
The y-intercept = (0, -3.5)
Explanation:The given equation is:
-2x + 4y = -14
Find the x-intercept by setting y = 0
-2x + 4(0) = -14
-2x + 0 = -14
-2x = -14
x = -14/-2
x = 7
Therefore, the x-intercept = (7, 0)
Find the y-intercept by setting x = 0
-2(0) + 4y = -14
0 + 4y = -14
4y = -14
y = -14/4
y = -3.5
Therefore, the y-intercept = (0, -3.5)
Considering the x and y-intercepts, the graph is plotted
What is a formula for the nth term of the given sequence?135, -225,375...
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Step 1: Write out the formula for a geometric sequence
[tex]\begin{gathered} T_n=ar^{n-1} \\ \text{Where} \\ T_n=\text{ the nth term} \\ a=\text{ the first term} \\ r=\text{ the common ratio} \end{gathered}[/tex]Step 2: Write out the given values and find the formula
[tex]\begin{gathered} a=135, \\ r=-\frac{225}{135}=-\frac{5}{3} \end{gathered}[/tex]Therefore the formula is given by
[tex]T_n=135(-\frac{5}{3})^{n-1}[/tex]Hence, the correct choice is the first choice
Hello! I’m struggling badly! I need to find the x, y and z
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Let O be the point where the height about point C intercepts the segment AB:
Assume that CO is perpendicular to AB, C is a right angle, the length CO is equal to 4 and the length CB is equal to 5.
Since COB is a right angle, its sides must satisfy the Pythagorean Theorem:
[tex]y^2+4^2=5^2[/tex]Solve for y:
[tex]\Rightarrow y=\sqrt[]{5^2-4^2}=\sqrt[]{25-16}=\sqrt[]{9}=3[/tex]Notice that COB, AOC and ACB are similar triangles because they are all right angles and they have the same acute angles.
Then, the quotients between corresponding parts of the triangles are the same.
The legs of AOC are x and 4, and the corresponding legs of COB are 4 and 3. Then:
[tex]\begin{gathered} \frac{x}{4}=\frac{4}{3} \\ \Rightarrow x=\frac{4}{3}\times4=\frac{16}{3} \end{gathered}[/tex]Notice that z must be equal to the sum of x and y. Then:
[tex]z=x+y=\frac{16}{3}+3=\frac{16}{3}+\frac{9}{3}=\frac{25}{3}[/tex]Therefore, the values of x, y and z are:
[tex]\begin{gathered} x=\frac{16}{3} \\ y=3 \\ z=\frac{25}{3} \end{gathered}[/tex]Warning:
We have found this solution ignoring that the length AC was set to be equal to 15. That cannot be true, since the construction of the triangle ACB and the point O already tells us the values of x, y and z if CB=5 and CO=4. Using this construction, it is possible to deduce that the length AC must be 20/3.
Solve the following inequality for kk. Write your answer in the simplest form.8k - 3 > 9k + 10
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Given:
[tex]8k-3>9k+10[/tex]To solve for k:
Solving we get,
[tex]\begin{gathered} 8k-3>9k+10 \\ 8k-9k>10+3 \\ -k>13 \\ k<-13 \end{gathered}[/tex]Hence, the answer is,
[tex]k<-13[/tex]What is the total area patty can reach? What is the total grazing area?
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as patty can not reach the square, we have that she can reach 3/4 parts of a circle with radius equal to 12 feet. Therefore the area she can reach is :
[tex]A_p=\frac{3}{4}\pi\cdot r^2=\frac{3}{4}\pi\cdot144=108\pi\approx339.3[/tex]and the gazzing area is the area of the square so we get:
[tex]A_g=12^2=144[/tex]change to y=mx+b form 3x-y=6
Answers
Starting with the equation:
[tex]3x-y=6[/tex]Isolate the variable y. Substract 3x from both sides of the equation:
[tex]-y=6-3x[/tex]Multiply both sides of the equation by -1:
[tex]y=-6+3x[/tex]Use the commutative property of the sum to rewrite the right hand side of the equation:
[tex]y=3x-6[/tex]This equation is written in the form y=mx+b.
7. Zak buys 6 gallons of fruit punch. He hascoupons for $0.55 off the regular price ofeach gallon of fruit punch. After using thecoupons, the total cost of the fruit punch is$8.70. Find the regular price of a gallon offruit punch. (Example 2)
Answers
Zak buys 6 gallons of fruit punch.
He has coupons for $0.55 off the regular price of each gallon of fruit punch.
This means that $0.55 will be subtracted from the regular price of each gallon.
After using the coupons, the total cost of the fruit punch is $8.70.
Let x be the regular price of each gallon of fruit punch.
[tex](x-\$0.55)\times6=\$8.70[/tex]Now let us solve this equation for x.
[tex]\begin{gathered} (x-\$0.55)\times6=\$8.70 \\ 6x-\$3.3=\$8.70 \\ 6x=\$8.70+\$3.3 \\ 6x=\$12 \\ x=\frac{\$12}{6} \\ x=\$2 \end{gathered}[/tex]Therefore, the regular price of each gallon of fruit punch is $2
Find XFind yThe trapezoids shown below are similar. Find the length of x and y.10x 14Solve for X4 holy/2 1014Solve for y4(4x4) 11977 (10x2) 142Х[X=1.616/10l y- 2014y = 519) X1.6520) y=21) What scale factor was used to create the image of the new trapezoid? (figure 1+figure 2)Record your answer and fill in the bubbles. Be sure to use the correct place value.
Answers
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor
so
Find the value of x
applying proportion
4/x=10/4
or
x/4=4/10
x=16/10
x=1.6
Find the value of y
y/2=10/4
y=5
Find the scale factor
In this problem we have an enlargement,
that means ------> the scale factor is greater than 1
Divide 10/4=2.5
the scale factor is 2.5
A community boating center had $12,500. It bought 3 surf skis and 1 keelboat and had $265 left over. The keelboat cost $6,455 more than a surf ski. How much did the keelboat cost?
Answers
The cost of one keelboat is $7950
Given, A community boating center had $12,500.
It bought 3 surf skis and 1 keelboat and had $265 left over.
The keelboat cost $6,455 more than a surf ski.
Let the cost of one surf ski be x,
According to question,
cost of one keelboat = x + 6455
also, 3x + (x + 6455) + 265 = 12500
4x + 6520 = 12500
4x = 5980
x = 1495
So, the cost of one surf ski is $1495
and the cost of one keelboat is 1495 + 6455
= $7950
Hence, the cost of one keelboat is $7950
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about 120 out of every 320 people are left-handed. if 3,360 students attended Davis High School, about how many are left handed
Answers
Using the rule of 3
120 - 320
x - 3360
120*3,360 = 320x
403,200 = 320x
403,200/320 = x
x = 1,260
About 1,260 students are left handed.
1. A ball is thrown with an initial velocity of 86 feetper second 4 feet from the ground. The functionn(t) = -16t2 + 86t + 4 represents the height, h, of theball t seconds after it was thrown. After how manyseconds will the ball hit the ground?A. 4.7 secondsB. 4.9 secondsC. 5.2 secondsD. 5.4 secondsА A
Answers
D. 5.4 seconds
1) Since the course of that ball is described by the function h(t) = -16t² +86t +4.
So we can sketch out:
When the ball hits the ground, we'll have to find out the 2nd root of that function since when t=0, h =4. So let's find out the roots:
[tex]\begin{gathered} h(t)\text{ =-16t²+86t+4} \\ \Delta=(86)^2-4(-16)(4) \\ \Delta=7396+256 \\ x=\frac{-86\pm\sqrt[]{7652}}{2(-16)} \\ x_1=5.42 \\ x_2=-0.046 \end{gathered}[/tex]3) Since just the positive answer is interesting, then we can state that the answer is D (rounded off to the nearest tenth