For what value of x must ABCD be a parallelogram? 14-7=12x+1

The Maximum Revenue, R for the food truck will be $528.056.

Maximum revenue is the highest value of a function within a given set of ranges. The maximum value of the function under the entire range is known as the absolute maxima, and the minimum value is recognized as the absolute minima.

Total Guests = 100

Each guest orders 1 of 2 dishes

Salad price = $10 - 0.06x

Turkey price = $12 - 0.02y²

So x + y = 100S = 10 - 0.06x

T = 12 - 0.02y²

Revenue = sx + ty

Revenue = (10 - 0.06x)x + (12 - 0.02y²)y

y = 100 - x

Therefore, Revenue = (10 - 0.06x)² + (12 - 0.02*(100 - x)²)*(100 - x)

R = 10x - 0.06[tex]x^{2}[/tex] + (12 - 0.02*(10000 - 200x + x²))*(100 - x)

R = 10x - 0.06[tex]x^{2}[/tex] + (12 - 200 + 4x -0.02x² )*(100 - x)

R = 10x - 0.06[tex]x^{2}[/tex] + (-188 + 4x -0.02 x² )*(100 - x)

R = 10x - 0.06[tex]x^{2}[/tex] + (-188 + 4x -0.02x² )*100 -x (-188 + 4x -0.02x²)R = 10x - 0.06[tex]x^{2}[/tex] + -18800 + 400x -2x² -x (-188 + 4x -0.02x²)

R = 10x - 0.06[tex]x^{2}[/tex] + -18800 + 400x -2x² + 188x - 4x² +0.02x³ R = 10x - 0.06[tex]x^{2}[/tex] + -18800 + 588x -6x² + 0.02x³

R = -18800 + 598[tex]x[/tex] - 6.06[tex]x^{2}[/tex] + 0.02[tex]x^{3}[/tex]

Using differentiation,dR/dx = 598 - 12.12x + 0.06x²

Equating to zero,598 - 12.12x + 0.06x² = 0Dividing both sides by 2, we have:299 - 6.06x + 0.03x² = 0x = -(-6.06)/(2*0.03) + root((-6.06)² - 4*0.03*299) / 2*0.03x = 101 - root(36.7236 - 35.88) / 0.06x = 101 - 14x = 86.94 ≅ 87

Therefore, when you sell 87 salad plates and 13 turkey dishes, that is where you will make Revenue.

Revenue = (10 - 0.06*87)*87 + (12 - 0.02(13)²)*13

Revenue = 416 + 112

R ≅ $528

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Answer:

x=12

Step-by-step explanation:

5x-22=4x-10

5x-4x=-10+22

x=12

Answer:

between $10 and $20 for undecorated cookies; or between $12 and $25 for cookies

Step-by-step explanation:

 You can buy  8 hardbacks and 4 paperback textbooks.

This refers to two or more algebraic equations that have common variables and are resolved at the same time.

From the question:

Hardback books cost, H =$45

paperback books cost, P = $20.

The total amount to spend on textbooks =  $440.

The total amount of textbooks needed for the school year is Hardback  books+  paperback books= 12.

Solving Simultaneously we have:

H    +   P      = 12 ..............(i)

45H + 20P  = 440...........(ii)

Equation (i) * -20

-20H  - 20P = -240............(iii)

Add Equation (iii) and Equation (ii)

  45H + 20P  = 440...........(ii)

+   -20H  - 20P = -240............(iii)

We have:

25H = 200

H =200/25

H = 8

Substitute H = 8 into Equation (ii)

45(8) + 20P  = 440...........(ii)

360    +  20P = 440

collecting like terms:

20P =440 - 360  

20P = 80

Divide both sides by the coefficient of P

20P/20 =80/20

P= 4

Hence, You can buy  8 hardbacks and 4 paperback textbooks.

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Given

Graph

Procedure

Without doing any calculations, do you think Cylinder 1 and Cylinder 2 will have the same volume?

No, because the radius are different. In the first cylinder the radius is 4cm and 7cm in the second one.

The volume V of a cylinder is given by

where Pi is 3.1416, r is the radius and h is the height.

Then, the volume of cylinder 1 is

which gives

Now, the volume of cylinder 2 is

which gives

Therefore, the answer are

SOLUTIONS

Giving that f(x)=3x^2-x-5, g(x)=-1 what is (f+g)(x)

Adding up the two function:

Therefore the correct answer is:

1 1/2 cups of walnuts she will need for eight people.

In the given question,

It is Nadine’s birthday, and she is making walnut brownies for her sleepover.

She invited eight of her friends to her party.

The recipe that she is using makes twenty-four brownies, but she only wants to make eight.

The recipe for twenty-four calls for [tex]4\frac{1}{2}[/tex] cups of walnuts.

We have to find how many cups of walnuts she needs for eight people.

From the question we know that the recipe that she is using makes twenty-four brownies.

For making twenty-four brownies she needs [tex]4\frac{1}{2}[/tex] cups of walnuts.

We can write [tex]4\frac{1}{2}[/tex] in simplified form by multiplying the 4 by 2 then add the result of multiplying 4 by 2 to 1.

So [tex]4\frac{1}{2}[/tex] = 9/2

24 brownies = 9/2 cups of walnuts

So 1 brownies = (9/2)/24 cups of walnuts

We can write it as

1 brownies = 9/2×1/24 cups of walnuts

Simplifying

1 brownies = 9/48 cups of walnuts

Since she have to make eight brownies.

So 8 brownies = 9/48×8 cups of walnuts

Simplifying

8 brownies = 9/6 cups of walnuts

8 brownies = 3/2 cups of walnuts

8 brownies =1 1/2 cups of walnuts

Hence, 1 1/2 cups of walnuts she will need for eight people.

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Explanation:

Let 'x' be the number of paint colors Maddie can buy.

She buys 4 paintbrushes that cost $3 each. This means that she already spent 4x3=$12 in paintbrushes. This amount plus the amount of money she'll spend in the paint colors must be at most $40:

Solving for x:

Since x must be a whole number (is the amount of paint colors) and it has to be less than 4.666... then Maddie can afford 4 paint colors

Answer:

Maddie can afford 4 paint colors

Answer:

y=2/5x-3

Step-by-step explanation:

So, first, let's find the slope. m=y1-y2/x1-x2. We will use our points and plug them into this equation. -9-(-7)/-5-(-10)=2/5. Our slope is 2/5. Now, let's find the y-intercept. We only need 1 point, I will choose (-10,-7). y=mx+b will help us find the y-intercept. -7=2/5(-10)+b. B is the y-intercept. -7=-4+b. -7-(-4)=-3. Our y-intercept is -3. So, using our y-intercept and slope, the equation is: y=2/5x-3

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]4x+3y=21\implies 3y=-4x+21\implies y=\cfrac{-4x+21}{3} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}}x+7\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-4}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-4}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-4}\implies \cfrac{3}{4}}}[/tex]

so we're really looking for the equation of a line whose slope is 3/4 and it passes through (4 , 2)

[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{ \cfrac{3}{4}}(x-\stackrel{x_1}{4}) \\\\\\ y-2=\cfrac{3}{4}x-3\implies {\Large \begin{array}{llll} y=\cfrac{3}{4}x-1 \end{array}}[/tex]

Given

Flavored:

A: Apple

P: Peach

G: Grape

S: Strawberry

Procedure

Combinatios

Answer:

You have to use the formula:

(y-y1)/(y2-y1) =(x-x1)/(x2-x1). So draw a graph and place the points A and B on the Graph, then put the numbers in the formula. A(-8=x1, 3= y1), B(-4=x2,6=y2). You will get the formula and consequently the slope.

For the given isosceles triangle LMK, the distance between the points L and K is found as 5 units.

For the given question,

The coordinates of the points L and K taken from the graph are-

L = (-7, 4)

K = (-4, 8)

The distance between the points are found by the distance formula given as;

d = √(x₂ - x₁)² + (y₂ - y₁)²

Where x and y are the respective coordinates of two given points.

put the value;

LK = √(-4 + 7)² + (8 - 4)²

LK = √(3)² + (4)²

LK = √25

Taking square root both sides.

Lk = 5 units.

Thus, for the given isosceles triangle LMK, the distance between the points L and K is found as 5 units.

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x=3 , 8

remember the square of a binomyal

Step 1

given

we need to isolate x, so

a) rise each side to power 2

Step 2

solve the quadratic equation:

b) use the quadratic formula

so

i)let

ii) now, replace in the formula

therefore, the solutions are x= 3 and x= 8

so, the answer is

x=3 , 8

I hope this helps you

ANSWER

(7, -2)

EXPLANATION

We want to know the image point after a translation.

A translation is basically a shift in the position of the object.

The object point is (5, -5) and it translates 2 units right and 3 units up.

That means there is a shift +2 units on the x axis and +3 units on the y axis.

Therefore, the image point is:

(5 + 2, -5 + 3)

= (7, -2)

That is the image point.

Answer:

-8b + 70

Step-by-step explanation:

4(1 − 2b) + 76 – 10.

4 - 8b + 76 - 10

-8b + 70

I hope this helps!

Answer:

814 + 64 = 878

Step-by-step explanation:

just take the # from the previous day and add the 64.

When it says more, add when it says less, subtract.

Answer:

P=22 a=30

Step-by-step explanation:

a= L x W

6x5=30

the right side is the same size as the top line so both are 5.

Perimeter is adding every number, and the line between 3 and 2 is smaller than both so it would equal less, 1.

5+5+6+2+3+1

R y= x(x, y) —> (y, x) The rule for a reflection over the y -axis is (x,y)→(−x,y) After reflection we get DGFE.

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To solve the presented question for X, every change we make in one of the sides of the equality, we must do the same to the other. This way, the equality remains. In the present case, we will subtract 15.09 in both sides, as it follows:

Let's solve the following equation to see where Maya made a mistake:

2 (3x + 6) = 3 (x - 10)

Step 1: Solving parenthesis

6x + 12 = 3x - 30

Step 2: Like terms

6x - 3x = -30 - 12

Step 3: Complete the subtractions at both sides

3x = -42

Step 4: Dividing by 3 at both sides

3x/3 = -42/3

x = -14

Maya didn't multiply correctly 3 * - 10

Yes, Javionery, option B is the correct one.

First we have to visualize the points in a graph:

as we can see, the data is not symmetrical with respect the mean of the data, therefore, this data is not symmetric nor mound shaped

Answer:

[tex]x=\frac{289\pm \sqrt{1873}}{42}[/tex]

HOPE IT HELPS YOU

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The average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1.

The average rate of change of the given quadratic function on the interval 0 ≤ x ≤1 is the slope of the secant line connecting the points (0,f(0)) and (1,f(1)).

That is the average rate of change is:

[tex]\frac{f(1)-f(0)}{1-0}[/tex]

From the graph, f(0) is 0 and f(1) is -1

We plug in these values to obtain

= [tex]\frac{(-1)-0}{1-0}[/tex]

This simplifies to;

= [tex]\frac{-1}{1}[/tex]

= -1

Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1.

A quadratic function is a polynomial function that has one or more variables and the largest exponent of the variable is two. Since the term of the highest degree of a quadratic function is the term of the second degree,  it is also called a polynomial of degree 2. A quadratic function has at least one term that is a square term. This is an algebraic function.

The upper function of the square is of the form f(x) = x2 and  connects  points whose coordinates are of the form (number, number2). Transformations can be applied to this function, where it usually shows the form f(x) = a (x - h)2 k and can further  be transformed to f(x) = ax2 bx c. We will explore each of them in detail in the following sections.

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Answer:

number is 4

Step-by-step explanation:

let n be the number then twice the number is 2n and the difference of the number and 3 is n - 3 , so

2n + 3(n - 3) = 11 ← distribute parenthesis and simplify left side

2n + 3n - 9 = 11

5n - 9 = 11 ( add 9 to both sides )

5n = 20 ( divide both sides by 5 )

n = 4

As a check

twice the number is 2 × 4 = 8

increased by 3 times the difference of n and 3 is

8 + 3(4 - 3) = 8 + 3(1) = 8 + 3 = 11 ← Correct

The graph of the Evan's data is attached below.

Dylan noted the time of day and the temperature, in degrees Fahrenheit, and his findings are as follows: At 6 a.m., the temperature was 58° F. For the next 3 hours, the temperature rose 1° per hour. For the next 4 hours, it rose 2° per hour. The temperature then stayed steady until 6 p.m. For the next 3 hours, the temperature dropped 2° per hour. The temperature then dropped steadily until the temperature was 62° at midnight. The data points are in the form of time and temperature. The data points are 6 AM = 58, 7 AM = 59, 8 AM = 60, 9 AM = 61, 10 AM = 63, 11 AM = 65, 12 PM = 67, 1 PM = 69, 6 PM = 69, 7 PM = 67, 8 PM = 65, 9 PM = 63, and 12 AM = 62.

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We want to make a four digit number using numbers 1, 3, 5 and 8 and allowing repetition.

Therefore, there is four possibilities each for the units, tens houndreds and thousands.

Then, the total number of possibilities is: