Answer:
Explanation:
First of all, we know that
[tex]\sin \frac{\pi}{4}=\frac{\sqrt[]{2}}{2}[/tex]And knowing the unit circle, we know that the sine takes negative values in 3rd and 4th quadrants. Therefore, from the above value of the angle, If we go π radians counterclockwise, we encounter negative values of sine; hence,
[tex]\sin \lbrack\frac{\pi}{4}+\pi\rbrack=-\frac{\sqrt[]{2}}{2}[/tex][tex]\rightarrow\sin \frac{5\pi}{4}=\frac{-\sqrt[]{2}}{2}[/tex]The second value of the angle that yields the above value for sine is found by adding π/2 radians to the angle above (we are now in the 4th quadrant)
[tex]\sin \frac{5\pi}{4}+\frac{\pi}{2}=-\frac{\sqrt[]{2}}{2}[/tex][tex]\rightarrow\sin \frac{7\pi}{4}=-\frac{\sqrt[]{2}}{2}[/tex]Hence, the two values of angles between 0 and 2π are 5π/4 and 7π/4.
I am thinking of a number. It has two digits. When I reverse the digits and then add the new number to the original number I get 33. What is my number?
I am thinking of a number. It has two digits. When I reverse the digits and then add the new number to the original number I get 33. What is my number?
Let
the number xy
so
Reverse the digits yx
xy+yx=33
10x+10y=30 ------> equation 1
y+x=3 ----> equation 2
solve the system by graphing
the syste
on a grid 2/3 of the squares are shaded with a color 1/4 of the squares on the grid is shaded blue what fraction of the Shaded squares are blue squares
Given:
a grid 2/3 of the squares are shaded with color.
And 1/4 of the squares on the grid is shaded blue
So, to Find the fraction of the Shaded squares are blue squares
Multiply both fractions
So,
[tex]\frac{2}{3}\times\frac{1}{4}=\frac{2}{12}=\frac{2}{2\cdot6}=\frac{1}{6}[/tex]so, the answer will be 1/6 of the Shaded squares are blue squares
Line Segment AC is 10 centimeters (cm) long, Point M is the midpoint of AC.What will happen to the length of AC if Point A is moved so that the length of AM is squared and the length of MC remains the same?The length of AC will triple.The length of AC will double.The length of AC will be squared.The length of AC will be five times as large.
We know that AC is 10 centimeters long, and M is the midpoint of AC.
If we move point A as the problem says, we have.
As you can observe, the length of AC is triple.
Hence, the right answer is the first option: The length of AC will triple.Solve 2sin (2x) + 2 = 0 on the interval [0, 27).π 3π 9π 11π8' 85π 7π4 4π 9π8' 85π 7π 13π 15π8' 8' 8' 8
Which number line shows the solutions to n -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
The expression
[tex]n<-3[/tex]means "n takes values less than -3 but without taking the 3", for the symbol <.
Then, the number line that shows the solutions of the expression is
which of the following describes the area of a circle?
The area of the circle is given by:
[tex]A=\pi r^2[/tex]So, the area of a circle is basically:
[tex]A=\frac{1}{2}\times2\pi r\times r[/tex]It can be seen as the number of squares inside of the circle
I need to know the new equation, I’ve provided a picture
Hello there. To solve this question, we'll simply have to make x => x + 5 in the function.
Given the function:
[tex]f(x)=4x^2-3^{}[/tex]We have to determine f(x + 5)
By making x => x + 5 in this function, we get:
[tex]f(x+5)=4\cdot(x+5)^2-3[/tex]Now remember the binomial expansion of order 2:
[tex](a+b)^2=a^2+2ab+b^2[/tex]Therefore we have:
[tex]f(x+5)=4\cdot(x^2+2\cdot x\cdot5+5^2)-3[/tex]Multiply the terms inside parentheses and calculate the square.
[tex]f(x+5)=4\cdot(x^2_{}+10x+25)-3[/tex]Apply the distributive property
[tex]f(x+5)=4x^2+4\cdot10x+4\cdot25-3[/tex]Multiply and add the numbers
[tex]\begin{gathered} f(x+5)=4x^2+40x+100-3 \\ \boxed{f(x+5)=4x^2+40x+97} \end{gathered}[/tex]This is the answer we're looking for.
A way of showing this is the correct answer is to make x = 1 and x = 6 in the former function:
[tex]\begin{gathered} f(1)=4\cdot1^2-3=4\cdot1-3=4-3=1 \\ f(6)=4\cdot6^2-3=4\cdot36-3=144-3=141 \end{gathered}[/tex]Then making x = 1 in the expression we found after:
[tex]f(1+5)=f(6)=4\cdot1^2+40\cdot1+97=4+40+97=141[/tex]As expected.
Find the volume of the rectangular prism O 8 cubic units O 4 cubic units 6 cubic units O 3 cubic units
Given data:
The given rectangular prism.
The volume of the given prism is,
[tex]\begin{gathered} V=6(\text{volume of a cube)} \\ =\text{ 6(1 cubic-units)} \\ =\text{ 6 cubic-unis} \end{gathered}[/tex]Let's say you have a bag with 12 cherries, 4 of the cherries are sweet and 8 are sour. If you pick a cherry atrandom, what is the probability that it will be sweet? Write your answer as a reduced fraction.Pot)
1) A rolled die has just 6 outcomes; from 1 to 6
[tex]\text{Probability = }\frac{number\text{ of required events}}{nu\text{mber of total events}}[/tex]Number of total events for a die = 6
[tex]\begin{gathered} a)\text{ p(6) } \\ \text{for this the number of required events = 1 because there can and there is only one six showing at a time} \\ p(6)\text{ =}\frac{1}{6} \end{gathered}[/tex][tex]\begin{gathered} b)\text{ p(even)} \\ Here\text{ number of total events are 1,2,3,4,5 and 6} \\ \text{The number of even numbers = 3} \\ \\ p(\text{even) =}\frac{3}{6}=\frac{1}{2} \end{gathered}[/tex][tex]\begin{gathered} c)p(\text{greater than 1)} \\ \text{Here total number of outcomes are 1,2,3,4,5 and 6} \\ \text{numbers greater than 1 are 2,3,4,5 and 6}\ldots..\text{ Th}ere\text{ are 5 of them} \\ \text{Hence} \\ p(\text{greater than 1) =}\frac{5}{6} \end{gathered}[/tex][tex]\begin{gathered} 2)\text{ Total number of cherries = 12} \\ p(\text{sweet) =}\frac{number\text{ of sw}eet\text{ cherries}}{Total\text{number of cherries}} \\ \text{number of swe}et\text{ cherries= 4} \\ p(\text{sweet) =}\frac{4}{12}=\frac{1}{3} \end{gathered}[/tex]Can you just tell me the answer to this problem I need to finish it quickly I don’t need to work lol sorry it’s #6 I need help in
The combined triangles will look as shown below:
It can be observed that the lengths of the three sides fit alongside one another perfectly. This means that the lengths are equal.
Also, the middle piece of the three triangles has no space when it aligns with the other two triangles. This means that all the angles add up to 180°.It would also be a safe assumption that the angles are equal to each other, therefore the measure of each angle will be:
[tex]\Rightarrow\frac{180}{3}=60\degree[/tex]Therefore, it can be observed that the sides and angles of the three triangles are equal.
Art wants to calculate the diagonal distance across opposite corners of a rectangular parcel. The parcel is 161’ by 326’ . How long is the diagonal measurement?
Recall that the formula for the length of the diagonal of a rectangle is:
[tex]l=\sqrt[]{a^2+b^2}.[/tex]Where a, and b are the lengths of the sides of the rectangle.
Substituting a=161´, b=326´ in the above formula we get:
[tex]\begin{gathered} l=\sqrt[]{(161^{\prime})^2+(326^{\prime})^2}, \\ l=363.5890537^{\prime}\text{.} \end{gathered}[/tex]Answer: 363.5890537 ´.
grandma has $250000 to invest. she divides her money into two accounts. one account is in ultra-safe treasury bills paying 4% interest, and the other is in riskier corporate bonds paying 6%. if she needs $12,000 per year in income from her investments, how much should she invest in each account
for the ultra-safe treasury bills:
[tex]\begin{gathered} I_1=PV\cdot r\cdot t \\ I_1=x\cdot0.04\cdot1 \\ I_1=0.04x \\ \text{where:} \\ x=\text{amount 1} \end{gathered}[/tex]For riskier corporate bonds:
[tex]\begin{gathered} I_2=PV\cdot r\cdot t \\ I_2=y\cdot0.06\cdot1 \\ I_2=0.06y \\ \text{Where:} \\ y=\text{amount 2} \end{gathered}[/tex]she needs $12,000 per year, so:
[tex]\begin{gathered} I_1+I_2=12000 \\ 0.04x+0.06y=12000 \end{gathered}[/tex]grandma has $250000 to invest, therefore:
[tex]x+y=250000[/tex]Let:
[tex]\begin{gathered} x+y=250000\text{ (1)} \\ 0.04x+0.06y=12000\text{ (2)} \\ \text{From (1) solve for x:} \\ x=250000-y\text{ (3)} \\ \text{ Replace (3) into (2)} \\ 0.04(250000-y)+0.06y=12000 \\ 10000-0.04y+0.06y=12000 \\ 0.02y=12000-10000 \\ 0.02y=2000 \\ y=\frac{2000}{0.02} \\ y=100000 \end{gathered}[/tex]Replace y into (3):
[tex]\begin{gathered} x=250000-100000 \\ x=150000 \end{gathered}[/tex]Therefore, grandma needs to invest $150000 in ultra-safe treasury bills, and
Find quotient of 5,433 % 8
Find the quotient of 5,433 by 8.
8 | 5,433
Divide 54 by 8. The quotient is 6. 6x8 = 48. 54 - 48 = 6.
6
8 | 5433
-48
-------
63
63 by 8 is 7. 7x8 = 56. 63 - 56 = 7.
67
8 | 5433
-48
-------
63
-56
--------
73
73 by 8 is 9. 9x8 = 72. 73 - 72 = 1. The final step is:
679 <== Quotiet
8 | 5433
-48
-------
63
-56
--------
73
-72
-------------
1 <== Remainder
ring×heart=hathat×2=heartheart-ring=1/4
Let's begin by identifying key information given to us:
[tex]undefined[/tex]Given: AB = CB, LABD= LABD= LCBD Prove: LA= LCStatement Reason
Explanation:
We know that AB = CD and that ∠ABD = CBD because it is given information.
Then, we have that BD = BD because a side is congruent to itself. It is called the reflexive property of congruence.
Now, we can say that ΔABD = ΔBDC by SAS (Side - Angle - Side) because we have two congruent sides and the angle between them is also congruent
Finally, ∠A = ∠C because the corresponding sides of congruent triangles are congruent
Answer:
Therefore, the answer is
how many people are :9 or younger ?At most 60 years old ?40 to 59 ?
Given the table represents the ages of people :
We need to find the following:
1. how many people are : 9 or younger ?
As shown in the table : the ages 0 - 9 has a frequency of 8
So, the answer is : 8 people
2. How many people at most 60 years old ?
From the table : the age 60 - 69 the frequency is 10
But there is no information to specify the age 60
The answer is : NEI
3. How many people are : 40 to 59 ?
From the table :
the age 40-49 has a frequency = 9
the age 50-59 has a frequency = 6
So, the answer is 9 + 6 = 15 people
Your friend subtracts to find
44 - 18 = 26. He uses 26+ 18 to check his work. Your
cousin tells him he should use 18 + 26. Who is correct?
Explain how you know.
Answer:
technically it's both
Step-by-step explanation:
because if you have the answer plus 18 and if it works and you get 44 that will be the answer
6x-4>23what two values solve for x
Given:
[tex]6x-4>23[/tex][tex]\begin{gathered} 6x-4+4>23+4 \\ 6x>27 \\ x>\frac{27}{6} \\ x>4.5 \end{gathered}[/tex]Dane is using two differently sized water pumps to clean up flooded water. The larger pump can
remove the water alone in 240 min. The smaller pump can remove the water alone in 400 min.
How long would it take the pumps to remove the water working together?
minutes
The rate of work obtained from the 240 and 400 minutes it takes for the large and small pumps to remove the water alone respectively, gives the duration it takes for the two pumps to remove the water working together as 150 minutes.
What is the rate of work formula?The rate of work in completing a project is given by the reciprocal of the time it takes to complete the project.
The given parameters are;
The time it takes the larger pump to remove the water, A = 240 minutes
The time it takes the smaller pump to remove the water, B = 400 minutes
The rate of doing work by the larger pump = [tex]\frac{1}{240}[/tex]
The work rate of the smaller pump = [tex]\frac{1}{400}[/tex]
The rate of work of the two pumps combined, [tex]\frac{1}{r}[/tex], is therefore;
[tex]\dfrac{1}{A} +\dfrac{1}{B} = \dfrac{1}{r}[/tex]
Where;
r = The time it takes for the two pumps to remove the water together
Which gives;
[tex]\dfrac{1}{240} +\dfrac{1}{400} = \dfrac{1}{150} = \dfrac{1}{r}[/tex]
∴ r = 150
The time it takes for the two pumps to remove the water together is 150 minutes
Learn more about rate of work here:
https://brainly.com/question/29242115
#SPJ1
Answer: 150 min
(I completed the question)
12. What is the equation of a circle with center (6,-4) and radius 6?(x - 6)2 + (y + 4)2 = 6(x + 6)2 + (y - 4)2 = 36(x + 6)2 + (y - 4)2 = 6(x - 6)2 + (y + 4)2 = 36
The equation of a circle with center (h, k) and radius r is given by the following expression:
[tex](x-h)^2+(y-k)^2=r^2[/tex]In this case, the center of the circle is located at (6, -4), and its radius equals 6, then by replacing 6 for h, -4 for k and 6 for r, we get:
[tex]\begin{gathered} (x-6)^2+(y-(-4))^2=6^2 \\ (x-6)^2+(y+4)^2=36 \end{gathered}[/tex]Then, the last option is the correct answer: (x - 6)^2 + (y + 4)^2 = 36
The figure below is composed of squares and semi-circles. Find the perimeter of this shape. Show your work.
Problem
Solution
For this case we can find the perimeter of the figure with the following operation
[tex]P=(2\cdot4)+\pi(4)+(2\cdot4)+\pi(4)=2\pi(4)+8+8[/tex]Then the final answer would be:
[tex]P=16+8\pi[/tex]evaluate the following expression 2 * 1 + 2 * 24/4
using PEDMAS/ BODMAS
division is executed first followed by multiplication then addition
What is the vertex for the graph of y– 4 = - (x+1)^2??O A. (4,-1)O B. (1,-4)O c. (-1,4)O D. (-4,1)
The equiation of parabola in vertex form is:
[tex]y\text{ = a}\cdot(x-h)^2\text{ + k}[/tex]where (h, k) are the coordinates of the vertex and a is a constant. In our case we have:
[tex]y-4=-(x+1)^2[/tex]add 4 to both sides:
[tex]y\text{ -4 +4 = -}(x+1)^2\text{ + 4}[/tex]Resolving:
[tex]y=-(x+1)^2\text{ + 4}[/tex]Therefore we already have it in the vertex form and we have to:
[tex]\begin{gathered} h\text{ = -1 } \\ k\text{ = 4} \end{gathered}[/tex]Therefore the answer is c. (-1, 4)
5 Ramon sched 13 -6 She said she thought about taking away and then 3 more from 13. CanRamon do this? Show a diagram and write an equation to show what this solution path would look like
we know that
14-7=7 --------> given problem
so
we have
14-8
Rewrite the expression
14-(7+1)
14-7-1
Remember that
14-7=7
substitute
7-1
6
we have
12-6=6
so
12-7
rewrite
12-(6+1)
12-6-1
substitute
6-1
5
we have
13-6
13-(3+3)
13-3-3
10-3
7
Please help me with these 2 questions they are both solved problems that go together with one huge problem so please answer both thank you
1).
r = 11 in
The diameter is twice the radius, so:
d = 2*11 = 22 inches
2).
d = 18 inches
The radius is half the diameter, so:
r = 18/2 = 9 inches
Select all the statements below that are true for the following graph
From the graph given,
It is an absolute function
The following statements are true about the graph
i) The vertex is located at (2, -2)
ii) The graph has two zeros
ii) The range is [-2, ∞)
Use the Distance and Slope Formulas to complete the tables below. Round to the nearest tenth,1. Find the length of MN, given the coordinates M (4,- 4) and N (2.0).imImMN:
Given the coordinates;
[tex]\begin{gathered} M(4,-4) \\ N(2,0) \end{gathered}[/tex]The slope m of the line MN is;
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \text{Where x}_1=4,y_1=-4,x_2=2,y_2=0 \end{gathered}[/tex][tex]\begin{gathered} m=\frac{0-(-4)}{2-4} \\ m=\frac{4}{-2} \\ m=-2 \end{gathered}[/tex]The slope of a line parallel to the line MN must have a slope equal to line MN, that is;
[tex]\mleft\Vert m=-2\mright?[/tex]The slope of a line perpendicular to line MN has a slope of negative reciprocal of line MN, that is;
[tex]\begin{gathered} \perp m=-\frac{1}{-2} \\ \perp m=\frac{1}{2} \end{gathered}[/tex]Using the distance formula to find the length of MN, the formula is given as;
[tex]D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex][tex]\begin{gathered} \text{Where x}_1=4,y_1=-4,x_2=2,y_2=0 \\ |MN|=\sqrt[]{(0-(-4)^2+(2-4)^2} \\ |MN|=\sqrt[]{16+4} \\ |MN|=\sqrt[]{20} \\ |MN|=4.5 \end{gathered}[/tex]If Rolle's Theorem can be applied, find all values of c in the open interval (a, b) such that f '(c) = 0. (Enter your answers as a comma-separated list. If Rolle's Theorem cannot be applied, enter NA.)
Since we can apply Rolle's Theorem:
[tex]\begin{gathered} f^{\prime}(x)=-\sin (x) \\ so\colon \\ f^{\prime}(x)=0 \\ -\sin (x)=0 \end{gathered}[/tex]Take the inverse sine of both sides:
[tex]\begin{gathered} x=\sin ^{-1}(0) \\ x=\pi n \\ n\in\Z \end{gathered}[/tex]Since it is for the interval:
[tex]\lbrack\pi,3\pi\rbrack[/tex]The solutions are:
[tex]x=\frac{3\pi}{2},\frac{5\pi}{2}[/tex]Answer:
[tex]\begin{gathered} c=\frac{3\pi}{2},\frac{5\pi}{2} \\ or \\ c\approx4.71,7.85 \end{gathered}[/tex]please help me 60 points please show all work this is due in 15 minutes5x-(3x-6)=182(3x-4)=102x+7=5x+16x/3-8=-23x – 6 = -12x/-3=8
I need help question
[tex]f(x)=x^2-4x-94[/tex]
The diffrentiated function will be
[tex]2x-4[/tex]RULES FOR DIFFERENTIATION
[tex]\begin{gathered} y=x^n \\ \frac{dy}{dx}=nx^{n-1} \end{gathered}[/tex]Also
[tex]\begin{gathered} y=kx \\ \frac{dy}{dx}=k \end{gathered}[/tex]Also
[tex]\begin{gathered} y=k \\ \frac{dy}{dx}=0 \end{gathered}[/tex]