A = P ( 1 + r/n ) ^ nt
P is the principle which is 36000
r is the rate which is 13.7 % or .137 in decimal form
n is the number of time per year, semi annual means 2 times per year
t is the time = 2
A = 36000( 1 + .137/2) ^ (2*2)
36000( 1 + .137/2) ^ (4)
Find the measure of ZGHJ and ZGI.68°H31°.K115°angle GHJ =degreesangle GIJ =degrees
We are asked to determine angles GHJ and GIJ. To do that we need to have into account that these two angles are half the measure of their respective intercepted arc. Since both intercepted arcs are the same then the angles are equal. The intercepted arc is given by:
[tex]\begin{gathered} \theta=360-68-31-115 \\ \theta=146 \end{gathered}[/tex]Therefore, the angles are:
[tex]\angle GHJ=\angle GIJ=\frac{\theta}{2}=\frac{146}{2}=73[/tex]what two intergers does the square root of 15 fall between
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
2 integers ===> √15
Step 02:
[tex]\sqrt[]{15}=\text{ }3.87[/tex]integer 1 = 3
integer 2 = 4
That is the solution.
Correctnomial function with the stated properties. Reduce all fractions to lowest terms.Third-degree, with zeros of - 3, - 1, and 2, and passes through the point (3, 5).
We must construct a polynomial with the following characteristics:
0. degree: 3,
,1. zeros: x₁ = -3, x₂ = -1 and x₃ = 2,
,2. passes through the point (3, 5).
The general form for this polynomial is:
[tex]p(x)=a*(x-x_1)(x-x_2)(x_{}_{}-x_3).[/tex]Where a is a constant factor and x₁, x₂ and x₃ are the zeros of the polynomial.
Replacing the values of the zeros, we have:
[tex]p(x)=a*(x+3)(x+1)(x-2).[/tex]Using the condition that the polynomial passes through (3, 5), we have:
[tex]y=a*(3+3)(3+1)(3-2)=a*24=5.[/tex]Solving for a, we get a = 5/24. Replacing this value in the equation above, we get:
[tex]p(x)=\frac{5}{24}(x+3)(x+1)(x-2).[/tex]Answer[tex]p(x)=\frac{5}{24}(x+3)(x+1)(x-2)[/tex]which inequality is shown in the graph below? A x<2 B x>2 C y>2 S y<2
In the picture, we can see that the solution to the inequality are those x-values greater than 2 (2 is not included) no matter which value the y-variable has. This corresponds to: x > 2.
Identify the transformations for the function below. Check all that applyf (x) = 2(x – 3)^3 + 2DilationHorizontal ShiftVertical ShiftReflection
The given function is,
[tex]f(x)=2(x-3)^3+2[/tex]The parent function of the given function can be identified as,
[tex]f(x)=x^3[/tex]A transformed function can be represented as,
[tex]f(x)=a(bx-h)^3+k[/tex]If k is a positive or a negative number, then function is shifted k units vertically.
So, comparing the equations, we find that in the given function k=2.
Hence, the function is vertically shifted.
A function f(x) is shifted h units horizontally if h is a positive or a negative number.
So, in the given function h=3.
Hence, the function is horizontally shifted.
If |a| >1 or 0<|a|<1, the function f(x) is dilated vertically by a scale factor of a units and if a is a negative number , the function is also reflected across the x axis.
In the given function, a=2.
So, f(x) is dilated, but not reflected.
If |b| >1 or 0<|b|<1, the graph of function f(x) is dilated by a scale factor of b units horizontally and if b is a negative number, the function is also reflected across the y axis.
In the given function, b=1.
So, f(x) is not dilated or reflected.
Hence, f(x) has undergone the transformations:
Dilation
Horizontal Shift
Vertical Shift
Solve the problem below, inputting your answer in decimal form.32 3/4 + 12 1/2
Answer:
45.25
Explanation:
To find the value of the expression given, we first convert the mixed numbers into fractions .
[tex]32\frac{3}{4}=32+\frac{3}{4}[/tex]multiplying 32 by 4/4 gives
[tex]undefined[/tex]Difference of Squares gives which complex factors for the expression x2 +11?A. (x + W11)(x - 111)B. (x+in/11)(x +111)C. (x + 111)2(x - in 11)D. (x - iw/11)(x-in 11)SUBMIT
we have that
[tex](x+i\sqrt[\square]{11})\cdot(x-i\sqrt[\square]{11})=x^2-(i^2)(11)=x^2+11[/tex]answer is the first option
option A
Express the given equation in standard form by solving for x. Simplify your answer
SOLUTION
Recall that a linear equation in one variable is in standard form if it is in the form:
[tex]ax+b=0[/tex]Hence the equation:
[tex]x+1=0[/tex]Is in tandrd form
Solving for x gives
'
[tex]x=-1[/tex]Pleaseeeeee help
2x+7y=-5;(a,1)
Answer:
x= −5a/2 - 7y/2
I think. correct if wrong!!!
Solve the equation for X. Round the answer to three decimal places. 4^x = 6
Answer:
c. x =1.293
Explanation:
To solve the expression, we will apply the properties of the logarithms, so
[tex]\begin{gathered} 4^x=6 \\ \log 4^x=\log 6 \\ x\log 4=\log 6 \\ x=\frac{\log 6}{\log 4} \\ x=1.293 \end{gathered}[/tex]Therefore, the value for x is
c. x =1.293
Karmahhaze09 Can i have your number
Answer: irdk u yet so no
Step-by-step explanation:
Can you help me with this assignment
Those are vertical angles, therefore:
[tex]\begin{gathered} m\angle ONB=m\angle MNK \\ so\colon \\ m\angle ONB=85 \end{gathered}[/tex]A study compared five different methods for teaching descriptive statistics. The five methods were traditional lecture and discussion, programmed textbook instruction, programmed text with lectures, computer instruction, and computer instruction with lectures. 45 students were randomly assigned, 9 to each method. After completing the course, students took a 1-hour exam.
a. What are the null and alternative hypotheses for addressing the research question, "are average test scores different between the different teaching methods?"
b. What are the degrees of freedom associated with the F distribution for evaluating these hypotheses?
c. Suppose the p-value for this test is 0.0168. What would you conclude? (Be sure to specify your significance level.)
a. The hypotheses are:
Null hypothesis: the average test scores are the same for the different teaching methods.
Alternative hypothesis: the average test scores are different for the different teaching methods.
b. To determine the degree of freedom for the F test: we must find two sources of variation such that we have two variances. The two sources of variation are: Factor (between groups) and the error (within groups) and add this up. Or use (N - 1). N is number in sample
c. With a p value of of 0.0168 and using a standard significance level of 0.05, we will reject the null hypothesis as 0.0168 is less than 0.05 and conclude that the average test scores are different for the different teaching methods.
Hence we get the required answer.
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people leaving a football match with acid be supported in Manchester United or Newcastle
How many people were asked the questions in total?
40 + 2 + 8 + 20 = 70.
Given Point A, what is the coordinate for A' after the following transformation has occurred?A (5,7)AC
Using the following given,
[tex]\begin{gathered} (x,y)\Rightarrow(x-5,-y+2) \\ (5,7) \end{gathered}[/tex]substitute the given coordinates to the new coordinates.
[tex](5,7)\Rightarrow(5-5,-7+2)[/tex]Simplify the coordinates.
[tex](5,7)\Rightarrow(0,-5)[/tex]Thus, the coordinates of A' is (0, -5).
A card is drawn randomly from a standard deck of cards. You win $5 if the card is adiamond or a king. What is the probability that you will win 5 dollars?
EXPLANATION
Let name event A as the event of drawing a Diamond and let us name event B as the event of drawing an King.
Now, we are required to find P(A union B)
We know that P(A union B) = P(A) + P(B) - P(A intersection B) … (i)
Let's suppose there are 52 cards in a standard deck.
A standard deck of cards has 13 diamonds and 4 kings
We have P(A) = 13/52 = 1/4, P(B) = 4/52 = 1/13
A intersection B denotes the case of the King of Diamonds whose probability = 1/52
Now plugging in these values to equation (i) and simplifying, we obtain the required probability as P(A union B) = 1/4 + 1/13 - 1/52 = 4/13
The probability is 4/13 or 0.307 or 30.7%
4. Enter the total area of the figure ABCD in square centimeters 8 cm А 6 cm F C 15 cm 8 cm D O 268 O 336 168 O 37
The figure ABCD has the shape of a Rhombus with diagonals AC and BD.
To determine the area of a Rhombus you have to multiply the length of both diagonals and divide the result by 2, following the formula:
[tex]A=\frac{pq}{2}[/tex]Where
p represents the horizontal diagonal
q represents the vertical diagonal
For the quadrilateral ABCD, the lengths of the diagonals are:
AC=6cm + 15cm =21cm
BD= 8cm + 8cm=16cm
[tex]\begin{gathered} A=\frac{AC\cdot BD}{2} \\ A=\frac{21\cdot16}{2} \\ A=\frac{336}{2} \\ A=168\operatorname{cm}^2 \end{gathered}[/tex]The area of the figure is 168cm²
⁰which of the following is the volume of a hemisphere with a radius of 8 inches?
The general expression for the volume of hemisphere is :
[tex]\text{ Volume = }\frac{2}{3}\Pi\text{ }\times radius^3\text{ }^{}^{}[/tex]In the given question we have radius = 8 inches
Substitute the value of r = 8 in the expression for the volume of hemisphere :
[tex]\begin{gathered} \text{ Volume = }\frac{2}{3}\Pi\text{ }\times radius^3\text{ }^{} \\ \text{Volume}=\frac{2}{3}\times3.14\times8^3 \\ \text{Volume =}1071.78666 \\ Volume\text{ = 1071.70 inches cubed} \end{gathered}[/tex]B) 1071.79 inches cube
Answer
Find the equation of the line that has a slope of -2 and passes through point (-3 ,4)
Let's use the slope-point form to find the equation:
[tex]\begin{gathered} y-4=-2(x-(-3)) \\ \rightarrow y-4=-2(x+3) \\ \rightarrow y-4=-2x-6 \\ \rightarrow y=-2x-2 \\ \end{gathered}[/tex]Thereby, the equation of the line is:
[tex]y=-2x-2[/tex]Suppose that $4000 is placed in a savings account at an annual rate of 9%, compounded monthly. Assuming that no
withdrawals are made, how long will it take for the account to grow to $6216?
Do not round any intermediate computations, and round your answer to the nearest hundredth.
_ years
Answer:
below
Step-by-step explanation:
The equation to use
FV = PV ( 1 + i)^n FV = 6216 PV = 4000
i = decimal interest per period = .09/12
n = how many months?
6216 = 4000 ( 1 + .09/12)^n
6216/4000 = (1 + .09/12)^n
1.554 = 1.0075 ^n
log 1.554 / log(1.0075) = n = 59 months (approx 5 years )
Solve the system of two linear inequalities graphically.ſr<62-3Step 2 of 3 : Graph the solution set of the second linear inequality.AnswerKeyboThe line will be drawn once all required data is provided and will update whenever a value is updated. The regions will be added once the line is drawn.Enable Zoom/PanChoose the type of boundary line:Solid (-) Dashed (-)Enter two points on the boundary line:510-35Select the region you wish to be shaded:
Answer and Explanation:
Given the system of two linear inequalities;
[tex]\begin{gathered} x<6 \\ x\ge-3 \end{gathered}[/tex]To solve the above system of inequalities graphically, we follow the below steps;
Step 1: Graph the first inequality;
Since the first inequality has a less than sign, we'll shade the region to the left of the line.
Also, the first inequality does not have an equality sign, so the line will be a dashed line.
See below the graph of the first inequality;
Step 2: Graph the second inequality on the same grid;
Since the inequality has an equality sign, the line will be a solid line.
Also, the inequality has the greater than sign, so we'll shade the region to the right of the line
See below the image of the graph;
Step 3: The solution set of the two systems of inequalities is the region where the shading overlaps.
As can be seen in the above graph, the shaded region between the dashed line and the solid line is the solution of the system of inequalities.
The graph of the solution set of the second inequality is as shown below;
On the boundary line we can select the below points;
[tex]\begin{gathered} \lparen-3,5) \\ \lparen-3,-5) \end{gathered}[/tex]Benjamin invested an amount of $12,000.00 in a mutual fund. After 4 years and 6 months the accumulated value of his investment was $13,407.58. What is the nominal interest rate of the investment if interest is compounded semi-annually?__________%
Given the following parameters
[tex]\begin{gathered} PV\Rightarrow\text{Present value}\Rightarrow12000.00 \\ T\Rightarrow\text{time}\Rightarrow4\text{years and 6 month} \\ FV\Rightarrow\text{Future Value}\Rightarrow13407.58 \\ n=2 \end{gathered}[/tex]To calculate the nominal rate, we will have to calculate the interest rate and the compounded period, the following formula will be used to find the interest rate and the compounded period.
[tex]\begin{gathered} i=(\frac{FV}{PV})^{\frac{1}{n}}-1 \\ m=\frac{n}{t} \end{gathered}[/tex]To find the value of the interest, we have
[tex]\begin{gathered} i=(\frac{13407.58}{12000.00})^{\frac{1}{2}}-1 \\ i=(1.117298333)^{\frac{1}{2}}-1 \\ i=1.057023336-1=0.05702336 \end{gathered}[/tex]To find the compounded period we will have that
[tex]\begin{gathered} m=\frac{n}{t} \\ n=2 \\ t=4.5 \\ m=\frac{2}{4.5} \\ m=0.4444444444 \end{gathered}[/tex]Thus, the nominal rate formula is given as;
[tex]\begin{gathered} j=m\times i \\ \end{gathered}[/tex]Substitute for m and i to find the nominal rate
[tex]\begin{gathered} i=0.05702336 \\ m=0.4444444444 \\ j=0.05702336\times0.4444444444 \\ j=0.02534371556\approx0.0253 \end{gathered}[/tex]The nominal rate in percentage is
[tex]\begin{gathered} j=0.0253\times100\text{ \%} \\ j=2.53\text{ \%} \end{gathered}[/tex]Hence, the nominal rate of the investment if interest is compounded semi-annually is 2.53%
How many solutions does the system of equations below have?4x − 8y = –17x − 14y = 4No solutionOne solutionInfinitely solutions
start clearing the x in the first equation
[tex]\begin{gathered} 4x=-1+8y \\ x=-\frac{1}{4}+2y \end{gathered}[/tex]insert this equation into the second one
[tex]\begin{gathered} 7\cdot(-\frac{1}{4}+2y)-14y=4 \\ -\frac{7}{4}+14y-14y=4 \\ -\frac{7}{4}\ne4 \end{gathered}[/tex]the system has no solution
A company wants to decrease their energy use by 15%. If their electric bill is currently $1,700 a month, what will their bill be if they are successful? Give your answer accurate to at least the nearest dollar.$
We will determine it as follows:
[tex]x=1700-1700(0.15)\Rightarrow x=1445[/tex]So, they will pay $1445 if they manage to decrease the consumption by 15%.
James’ dealership uses a one-price, “no haggle” selling policy. The dealership averages 13% profit on new car sales. If the dealership pays $15,600 for a Rancho Turbo, find the selling price after adding the profit to the dealer’s cost.
Help me and I will give you 5 stars!!!:):):)
The selling price after adding the profit to the dealer’s cost is $17628
The dealership averages 13% profit on new car sales
If the dealership pays $15,600 for a Rancho Turbo,
The profit is 13% of the dealership
profit =(13/100) 15600
profit = 2028
Selling proce = cost price + profit
= 15600 + 2028
= 17628
Therefore, the selling price after adding the profit to the dealer’s cost is $17628
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Find the magnitude of the vector (-4,-4).Write your answer in simplified radical form.030/0 (0,0)ХX6?
Given the vector < -4, 4 >
The magnitude of the vector =
[tex]\sqrt[]{(-4)^2+(4)^2}=\sqrt[]{2\cdot4^2}=4\sqrt[]{2}[/tex]so, the answer will be:
[tex]4\sqrt[]{2}[/tex]State if the triangles in each pair are similar. If so, state how you know they are similar andcomplete the similarity statement.1) 2)
Triangles Similarity
For two shapes to be similar, two conditions must be satisfied:
* They must have the same angles.
* The side lengths must be in proportion
Let's focus on the image provided in problem 1.
We must try to find if the length sides of ABU and VWU are in proportion.
To do it, we find the ratio of the sides. If we find the same ratio of two pairs of sides, then the second condition is met.
The tin can shown below has the indicated dimensions.1.5in.3.25in.A cylinder is shown. The radius of the top circular base is labeled (1 .5) inches and the altitude is labeled (3.25) inches.Estimate the number of square inches of tin required for its construction. (Hint: Include the lid and the base in the result. Use your calculator value of . Round your answer to two decimal places.)in2
Given:
A cylinder having radius 1.5 inches and a height of 3.25 inches
Required:
Estimate the number of square inches of tin required for its construction.
Explanation:
To calculate the number of square inches of tin required for its construction we have to calculate the area of the lid and base and the curved surface then add them all.
[tex]\begin{gathered} \pi r^2+\pi r^2+2\pi rh \\ \Rightarrow\frac{22}{7}\times1.5^2+\frac{22}{7}\times1.5^2+2\times\frac{22}{7}\times1.5\times3.25 \\ =44.76769531\text{ in}^2 \\ =44.77\text{ in}^2 \end{gathered}[/tex]Final Answer:
44.77 inches square
The lengths of the four sides of a quadrilateral (in inches) are consecutive integers. If the perimeter is 110 inches, find the value of the longest of the four side lengths.
The value of the longest side of the quadrilateral is 29 inch when its perimeter is 110 inches.
Perimeter of quadrilateral
The sum of all length of sides of a quadrilateral is known as the Perimeter of quadrilateral.
For example, if ABCD is the quadrilateral, then its perimeter is calculated as,
P = AB + BC + CD + AD
Where
AB, Bc, CD, and Ad are the values of the sides of ABCD.
Given,
The lengths of the four sides of a quadrilateral (in inches) are consecutive integers.
Here we need to find the longest side value when the perimeter is 110 inches.
We know that, the lengths of the four sides of a quadrilateral (in inches) are consecutive integers.
So, let us consider the length of quadrilateral are x, x + 1, x + 2 and x + 3
Through this we have identified that the longest length = x + 3
We know that the perimeter is 110 inches.
So, it can be written as,
=> x + (x + 1) + (x + 2) + (x + 3) = 110
=> x + x + 1 + x + 2 + x + 3 = 110
=> 4x + 6 = 110
=> 4x = 110 - 6
=> 4x = 104
Therefore, the vale of x is 26 inch
Hence, longest length is calculated as,
=> x + 3
=> 26 + 3
=> 29 inch
Therefore, the value of the longest side of the quadrilateral (in inches) is 29 inch.
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221/34 simplifyed........................................
Consider the given expression,
[tex]\frac{3}{x+1}-\frac{1}{x-1}-\frac{2x}{x^2-1}[/tex]Consider the algebraic identity,
[tex]a^2-b^2=(a+b)(a-b)[/tex]Simplify the expression as,
[tex]\begin{gathered} \frac{3}{x+1}-\frac{1}{x-1}-\frac{2x}{(x-1)(x+1)} \\ \frac{3(x-1)-1(x+1)-2x(1)}{(x-1)(x+1)} \\ \frac{3x-3-x-1-2x}{(x-1)(x+1)} \\ \frac{-4}{(x-1)(x+1)} \\ \frac{-4}{x^2-1} \end{gathered}[/tex]Thus, the given expression is in simplified form gives,
[tex]\frac{3}{x+1}-\frac{1}{x-1}-\frac{2x}{x^2-1}=\frac{-4}{x^2-1}[/tex]