Answer:
-7/24
Explanation:
Given the expression:
[tex]-\frac{5}{8}+\frac{1}{3}[/tex]Step 1: Find the lowest common multiple of the denominators.
The L.C.M. of 8 and 3 = 24
Step 2: Use the LCM to combine the fractions.
[tex]=\frac{-5(3)+1(8)}{24}[/tex]Step 3: Simplify:
[tex]\begin{gathered} =\frac{-15+8}{24} \\ =-\frac{7}{24} \end{gathered}[/tex]The result of the sum is -7/24.
Figure 1 and figure 2 below are similar. which po8nt corresponds to point U.
SOLUTION
Step 1 :
In this question, we have that Figure 1 and Figure 2 are similar.
The point that corresponds to point U is Point E.
10. Write the slope-intercept form of the equation of the line through the given points. Write answer as y=mx+b. 1 po through: (0, 2) and (-5, -5) Your answer
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
First, let's find what m is, the slope of the line...
[tex]\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ m=\frac{-5-2}{-5-0} \\ m=\frac{-7}{-5} \\ m=\frac{7}{5} \\ \end{gathered}[/tex]Now, what about b, the y-intercept?
[tex]\begin{gathered} b=y-mx \\ b=2-\frac{7}{5}(0) \\ b=2 \end{gathered}[/tex]The equation of the line that passes through the points
[tex]y=\frac{7}{5}x+2[/tex]can someone please help me find the valu of X?
We are asked to find the value of x.
As you can see, the two sides are parallel and when these parallel sides intersect sides of overlapping triangles then the intercepted segments are proportional.
So, we can set up the following proportion.
[tex]\frac{15}{6}=\frac{(3x+10)-8}{8}[/tex]Let us solve the above equation for x.
[tex]\begin{gathered} \frac{15}{6}=\frac{3x+10-8}{8} \\ \frac{15}{6}=\frac{3x+2}{8} \\ 15\cdot8=6\cdot(3x+2) \\ 120=18x+12 \\ 120-12=18x \\ 108=18x \\ \frac{108}{18}=x \\ 6=x \\ x=6 \end{gathered}[/tex]Therefore, the value of x is 6
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Convert the following equation
into slope intercept form.
x-13y = 26
y = x -
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10
Enter
Answer:
y=x+2
Step-by-step explanation:
x-13y=26
Bring the x to the other side
-13y=x+26
To get y by itself divide both sides by -13
-13y = x-26
----------- -----------
-13 -13
y=x+2
Round each number to the nearest ten. 24=311=107=
Round each number to the nearest ten. 24=
311=
107=
When rounding to the nearest ten, use these rules:
A) Round the number up to the nearest ten if the last digit in the number is 5, 6, 7, 8, or 9.
B) Round the number down to the nearest ten if the last digit in the number is 1, 2, 3, or 4.
C) If the last digit is 0, then we do not have to do any rounding, because it is already to the ten.
Step 1
24, the last digit is 4, so we round to the number down to the nearest ten
[tex]24\Rightarrow20[/tex]311. the last digit is 1, so we round to the number down to the nearest ten
[tex]311\Rightarrow310[/tex]107. the last digit is 7, so we round to the number up to the nearest ten
[tex]107\Rightarrow110[/tex]write the equation of a circle given the center (-4, 4) and radius r = 5
Given : the center of the circle = (-4 , 4)
And the radius of the circle = r = 5
The general equation of the circle is :
[tex](x-h)^2+(y-k)^2=r^2[/tex]Where (h,k) is the center of the circle and r is the radius of the circle
So, ( h , k ) = ( -4 , 4 ) and r = 5
so, the equation of the circle will be :
[tex]\begin{gathered} (x-(-4))^2+(y-4)^2=5^2 \\ \\ (x+4)^2+(y-4)^2=25 \end{gathered}[/tex]In ABCD, the measure of ZD=90°, CB = 53, BD = 45, and DC = 28. What ratiorepresents the sine of ZB?|
SOLUTION
Step 1 :
In this question, we asked to find the value of
[tex]\sin \text{ B}[/tex][tex]\begin{gathered} \text{where }\angle D=90^0 \\ BD\text{ = 45} \\ DC\text{ = 28} \\ BC\text{ = 53} \end{gathered}[/tex]Step 2 :
We can are see clearly that 28 , 45, 53 ) iPythagoras' Triple, since:
[tex]28^2+45^2=53^2[/tex]Step 3 :
[tex]\begin{gathered} \sin \text{ B = }\frac{28}{53} \\ =\text{ 0.5283} \end{gathered}[/tex]CONCLUSION :
[tex]\sin \text{ B = 0.5283}[/tex](G.11a, 1 point) Points A, C, D, and E are on circle P. 136° 1340 Ε E If arc AD measures 136° and 2 ABD measures 134º, what is the measure of arc CE? o A 152 O B. 67 o C. 116 D. 132
D. 132º
1) Given that in this circle crossed by two secant lines we can state the following Theorem:
2) then we can write:
[tex]\begin{gathered} m\angle ABD=\frac{AD\text{ +CE}}{2} \\ 134=\frac{136+CE}{2} \\ 134\text{ }\times2=136+CE \\ 268=136+CE \\ CE\text{ =268-136} \\ CE=132 \end{gathered}[/tex]So the measure of the arc CE = 132º (D)
the top of a rectangular box has an area of 42cm^2. The sides of the box have areas of 30cm^2 and 35cm^2. what are the dimensions of the box?
We have a rectangular box where we know the area of the faces and we have to find the width w, length l and height h.
The area of the top of the box is equal to the length times the width (l*w) and we also know that it is 42 cm², so we can write:
[tex]l\cdot w=42[/tex]With the same logic, we can write the equations for the other two areas:
[tex]\begin{gathered} l\cdot h=30 \\ w\cdot h=35 \end{gathered}[/tex]NOTE: the area we choose for l or w is indistinct,so we can relate it as we like.
Then, we can solve this system of equations substituting variables as:
[tex]\begin{gathered} l\cdot h=30\longrightarrow l=\frac{30}{h} \\ w\cdot h=35\longrightarrow w=\frac{35}{h} \\ l\cdot w=(\frac{30}{h})(\frac{35}{h})=\frac{1050}{h^2}=42 \\ h^2=\frac{1050}{42} \\ h^2=25 \\ h=\sqrt[]{25} \\ h=5 \end{gathered}[/tex]With the value of h, we can calculate l and w:
[tex]\begin{gathered} l=\frac{30}{h}=\frac{30}{5}=6 \\ w=\frac{35}{h}=\frac{35}{5}=7 \end{gathered}[/tex]Answer:
The dimensions of the box are: length = 6 cm, width = 7 cm and height = 5 cm.
Give two examples that illustrate the difference between a compound interest problem involving future value and a compound interest problem involving presentvalue.Choose the correct answer below.A. In a compound interest problem involving present value the goal is to find how much money has to be invested initially in order to have a certain amount inthe future. In a problem involving future value the goal is to find how much money there will be after a certain amount of time has passed given an initialamount to invest.B. In a compound interest problem involving present value the goal is to find how much money there will be after a certain amount of time has passed given aneffective annual yield. In a problem involving future value the goal is to find how much money has to be invested initially in order to have a certain effectiveannual yield in the future.OC. In a compound interest problem involving present value the goal is to find how much money there will be after a certain amount of time has passed given aninitial amount to invest. In a problem involving future value the goal is to find how much money has to be invested initially in order to have a certain amountin the future.
From the list of statements, let's select the examples that illustrate the difference between a compound interest problem involving future value and a compound interest problem involving present value.
Apply the compound interest formula:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where:
A represents the future value which is the final amount after a given period of time.
P represents the present value which is the initial amount invested.
When you are required to find the present value, the goal is to find how much money has to be invested initially in order to have a certain amount in the future. Here, the future value is always given.
When you are required to find the future value, the goal is to find how much money there will be after a certain amount of time has passed given an initial amount to invest. Here, the present value is always given.
Therefore, the correct examples are:
In a compound interest problem involving present value the goal is to find how much money has to be invested initially in order to have a certain amount in
the future. In a problem involving future value the goal is to find how much money there will be after a certain amount of time has passed given an initial
amount to invest.
ANSWER: A.
In a compound interest problem involving present value the goal is to find how much money has to be invested initially in order to have a certain amount in
the future. In a problem involving future value the goal is to find how much money there will be after a certain amount of time has passed given an initial
amount to invest.
Use the regression calculator to compare the teams’ number of runs with their number of wins.
A 2-column table with 9 rows. Column 1 is labeled R with entries 808, 768, 655, 684, 637, 619, 613, 609, 563. Column 2 is labeled W with entries 93, 94, 66, 81, 86, 75, 61, 69, 55.
What is the y-intercept of the trend line, to the nearest hundredth?
The y-intercept of the trend line is equal to -23.08.
How to determine the y-intercept of the trend line?In order to determine a linear equation of the trend line that models the data points contained in the table, we would have to use an Excel regression calculator (scatter plot).
In this scenario, the teams’ number of runs would be plotted on the x-axis of the scatter plot while the teams’ number of wins would be plotted on the y-axis of the scatter plot.
On the Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display an equation for the trend line on the scatter plot.
From the scatter plot (see attachment) which models the relationship between data points in the table, a linear equation of the trend line is given by:
y = 0.15x - 23.08
In conclusion, a standard linear equation is given by:
y = mx + c
Where:
m represents the slope i.e 0.15.x and y are the points.c represents the y-intercept i.e -23.08.Read more on scatter plot here: brainly.com/question/28605735
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I need to use the formula for a trapezoid and find the area and perimeter
Hello there. To solve this question, we'll have to remember some properties about trapezoids and right triangles.
Given the following trapezoid:
We have to determine its area and perimeter.
For this, remember that:
The area of a trapezoid with bases B and b (larger and smaller, respectively) and height h can be found by the formula
[tex]A=\dfrac{(B+b)\cdot h}{2}[/tex]The perimeter is the sum of the measures of all sides of the figure.
For the perimeter, we'll use the pythagorean theorem to determine the measure of the legs of the trapezoid.
Okay. Notice that in the trapezoid, the larger base B measures 41, the smaller base measures 21 and the height is 18.
By the formula for area, we get
[tex]A=\dfrac{(41+21)\cdot18}{2}=62\cdot9=558[/tex]Now, notice we can determine a right triangle on the left:
To determine the legs of the triangle, we make
[tex]\dfrac{41-21}{2}=\dfrac{20}{2}=10[/tex]Now we have a right triangle with legs 10 and 18.
Using the Pythagorean theorem:
[tex]a^2+b^2=c^2[/tex]For a triangle with legs a and b and hypotenuse c, the sum of the squares of the legs is equal to the square of the hypotenuse.
Using a = 10 and b = 18, we get
[tex]\begin{gathered} 10^2+18^2=c^2 \\ 100+324=c^2 \\ 424=c^2 \\ 4\cdot106=c^2 \\ c=2\sqrt{106} \end{gathered}[/tex]Since the other right triangle is the same, the other leg have the same measure, hence we add
[tex]\text{ Perimeter }=21+41+2\cdot2\sqrt{106}=62+4\sqrt{106}[/tex]We can approximate this value using a calculator
[tex]\text{ Perimeter }\approx103.18[/tex]Which equation represents the vertical line passing through (1,-9)?
A. x = -9
B.x = 1
C. y=-9
D. y = 1
Answer:
B is the correct equation.
find the 8th term of geometric sequence where a1=5, r= -2
for Given:
[tex]\begin{gathered} a_1=5 \\ r=-2 \end{gathered}[/tex]You need to remember that "r" is the Common ratio between the terms of the Geometric Sequence and this is the first term:
[tex]a_1_{}_{}[/tex]The formula the nth term of a Geometric Sequence is:
[tex]a_n=a_1\cdot r^{(n-1)}[/tex]Where "n" is the number of the term, "r" is the Common Ratio, and the first term of the sequence is:
[tex]a_1[/tex]In this case, since you need to find the 8th term, you know that:
[tex]n=8[/tex]Then, you can substitute all the values into the formula:
[tex]a_8=(5)(-2)^{(8-1)}[/tex]Evaluating, you get:
[tex]\begin{gathered} a_8=(5)(-2)^{(7)} \\ a_8=(5)(-128) \\ a_8=-640 \end{gathered}[/tex]Hence, the answer is:
[tex]a_8=-640[/tex]
Which picture below represents ?
5 2
10
Pls help
Answer:
b
Step-by-step explanation:
43 pointThe length of a rectangular box is 5 inches longer than twice the width (x).The height is 6 inches.Which is the volume (y) when the width (x) is 9 inches
L = 2*9+5=23
Pls help: find the rational expression state any restrictions on the variable
Simplification of Rational Expressions
Given the rational expression:
[tex]\frac{n^4-10n^2+24}{n^4-9n^2+18}[/tex]Simplify and state the restriction for the variable n.
Let's work on the numerator and denominator independently. Factoring the numerator:
[tex]\begin{gathered} n^4-10n^2+24=n^4-4n^2-6n^2+24 \\ n^4-10n^2+24=n^2(n^2-4)-6(n^2-4) \\ n^4-10n^2+24=(n^2-6)\mleft(n^2-4\mright) \end{gathered}[/tex]The denominator can be factored in a similar way:
[tex]\begin{gathered} n^4-9n^2+18=n^4-3n^2-6n^2+18 \\ n^4-9n^2+18=n^2(n^2-3)-6(n^2-3) \\ n^4-9n^2+18=\mleft(n^2-3\mright)(n^2-6) \end{gathered}[/tex]Thus, rewriting the expression:
[tex]\frac{n^4-10n^2+24}{n^4-9n^2+18}=\frac{(n^2-4)(n^2-6)}{(n^2-3)(n^2-6)}[/tex]Before simplifying, we must state the restrictions for the variable. The denominator cannot be 0, thus:
[tex]\begin{gathered} n^2-3\ne0\Rightarrow n\ne\pm\sqrt[]{3} \\ n^2-6\ne0\Rightarrow n\ne\pm\sqrt[]{6} \end{gathered}[/tex]Now simplify:
[tex]\frac{n^4-10n^2+24}{n^4-9n^2+18}=\frac{(n^2-4)}{(n^2-3)}[/tex]Combining the final expression with the restrictions, we stick with choice a.
Find the direction angle of vector v to the nearest tenth of a degree.Equation editor does not include the grouping symbols "<" and ">" that are necessary for writing avector in component form. For this question, use braces to write a vector in component form. Forexample, the vector < 2,3> should be written as {2,3}.
The direction angle is approximately 9.5 degrees
Explanation:The vectors are {-5, 0} and {7, 2}
Direction vector is {7 - (-5), 2 - 0 } = {12, 2}
Direction angle is:
[tex]\tan^{-1}(\frac{2}{12})\approx9.5^o[/tex]Part a: How many pieces are in the step functionpart b: how many intervals make up the step function? What are the interval valuespart c: why do we use open circles in some situations and closed in otherspart e are the pieces of this piecewise function linear or non linear?part f what is the range of this piecewise function?
a) The step function seen in the figure has 6 pieces, one for each step
b) There are 6 intervals, one for each piece. Their values are:
(0, 1]
(1, 2]
(2, 3]
(3, 4]
(4, 5]
(5, 6]
c) The open circles indicate that the endpoint is not included in the interval. The closed circles indicate the endpoint is included in the interval.
For example, in the second interval, 1 is not included (open circle) and 2 is included (closed circle).
d) This is a function because for eac value of x there iss one and only one of y. If the open circles were closed circles, then thi wouldnot be a function.
e) All the pieces are linear because their graph is a line (flat horizontal line)
f) The range of the function is the set of output values:
Range = {46, 48, 50, 32, 54, 56}
PLEASE ANSWER Given: a = 7 and b = 2 Then the m∠A=_?_ . ROund to the nearest degree. Enter a number answer only.
Answer:
A = 74 degrees
Step-by-step explanation:
a = b tan A
tan A = a/b
tan A = 7/2
A = arctan 7/2
A = 74 degrees
I need the answer to this use fractions and pi
We are to find the positive and negative angles that are coterminal with
[tex]\frac{2\pi}{3}[/tex]By definition
Coterminal Angles are angles that share the same initial side and terminal sides. Finding coterminal angles is as simple as adding or subtracting 360° or 2π to each angle, depending on whether the given angle is in degrees or radians
Hence,
The positive coterminal angle is
[tex]\frac{2\pi}{3}+2\pi[/tex]Simplifying this we get
[tex]\begin{gathered} \frac{2\pi}{3}+2\pi \\ =\frac{2\pi+6\pi}{3} \\ =\frac{8\pi}{3} \end{gathered}[/tex]Therefore, the positive coterminal angle is
[tex]\frac{8\pi}{3}[/tex]The negative coterminal angle is
[tex]\begin{gathered} \frac{2\pi}{3}-2\pi \\ =\frac{2\pi-6\pi}{3} \\ =-\frac{4\pi}{3} \end{gathered}[/tex]Therefore, the negative coterminal angle is
[tex]-\frac{4\pi}{3}[/tex]8. Find the area of the shaded portion of the figure. 10.5cm
The area = area of the big rectangel - sum of the areas of the two circles
the diameter of each of the circles is 10.5cm
Hence, each circle has a radius of 10.5cm / 2 = 5.25cm
The length of the rectangle = the sum of the diameters of the circles
Therefore
The length of the rectangle = 10.5cm + 10.5cm = 21cm
The width of the rectangle = 10.5cm
Hence,
[tex]\begin{gathered} \text{area of shaded portion = 21}\times10.5\text{ - (}\pi\times5.25^2+\pi\times5.25^2) \\ =220.5-(55.125\pi)\approx47.32 \end{gathered}[/tex]Hence the area of the shaded portion is 47.32 square centimeters
The width of a rectangular slab of concrete is 16 m less than the length. The area is 80m^2Part 1 of 3(a) What are the dimensions of the rectangle?The length of the slab is?
width = w
length = l
w = l - 16
area = w*l
(l - 16)*l = 80
l^2 - 16l = 80
l^2 - 16l - 80 = 0
(l + 4)(l - 20) = 0
then length = 20
w = 20 - 16 = 4
the width is 4
use the given graph to find the mean, median and mode of the following distribution: the mean is _______the median is _______the mode(s) is/are: __________Note: when the data is presented in a frequency table, the formula to find the mean is:
Solution:
Given:
From the graph above, a frequency table can be made as shown below;
To calculate the mean;
[tex]\begin{gathered} \text{Mean}=\frac{\Sigma fx}{\Sigma f} \\ \text{Mean}=\frac{189}{20} \\ \text{Mean}=9.45 \end{gathered}[/tex]Therefore, the mean is 9.45
To calculate the median;
Median is the middle term when the data is arranged in rank order.
Since we have 20 terms, then the middle terms will be the 10th and 11th terms.
The median will be the mean of these two numbers.
[tex]\begin{gathered} 10th\text{ term=9} \\ 11th\text{ term=10} \\ \text{Median}=\frac{9+10}{2} \\ \text{Median}=\frac{19}{2} \\ \text{Median}=9.5 \end{gathered}[/tex]Therefore, the median is 9.5
To calculate the mode;
The mode is the data that appears most in the set. It is the data with the highest frequency.
From the graph
From the graph
find the slope/rate of the line represented by each table
The correct answer is 1/2 or 0.5
Pick 2 points in the table; (x = -10, y = 1) and ( x = 0, y = 6)
The Rate of Change is given by;
[tex]\text{slope = }\frac{y_2-y_1}{x_2-x_1}=\frac{6-1}{0--10}=\frac{5}{10}=\frac{1}{2}[/tex]The rate of change is 1/2 or 0.5
Hence, the correct answer is 1/2 or 0.5
Find an equation of a parabola that satisfies the given conditions.
Focus at (8,0), directrix x = -8
The equation of a parabola for the focus at (8,0), directrix x = -8 is found as y² = 32x.
What is meant by the term parabola?A parabola is an open plane symmetrical curve created by the intersection of the a cone and a plane parallel towards its side. A projectile's path under the effect of gravity ideally continues to follow a curve of the this shape.The standard equation of parabola,
(y−n)² = 4p(x−m),
In which,
Vertex is (m,n)Axis of symmetry is y = mFocus is (p+m,n)Directrix is x =m−p.For the given value in question;
p+m = 8
n = 0
m−p = -8
m = 0
p = 8
Put the obtained values in general equation;
y² = 4×8(x+0)
y² = 32x
Thus, the equation of a parabola for the focus at (8,0), directrix x = -8 is found as y² = 32x.
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Triangle A B C has vertices (1,4),(5,6) and (3,10) It is reflected across the y axis forming triangle A’B’C’. What are the vertices of the new triangle?
Given:
The coordinates of triangle ∆ABC are (1,4), (5,6) and (3,10).
The triangle is reflected across y axis forming ∆A'B'C'.
The objective is to find the vertices of the new triangle.
Explanation:
If a triangle with coordinate (a,b) is reflected across y axis, then the change in reflected coordinate will be (-a,b).
If a triangle with coordinate (a,b) is reflected across x axis, then the change in reflected coordinate will be (a,-b).
To find vertices:
Since, the given triangle is reflected across y axis, then the vertices of new triangle will be,
[tex]\begin{gathered} A^{\prime}=(-1,4) \\ B^{\prime}=(-5,6) \\ C^{\prime}=(-3,10) \end{gathered}[/tex]Hence, the vertices of the new triangle are (-1,4), (-5,6) and (-3,10).
A meteorologist collected data about wind speed in a city, in miles per hour, on consecutive days of a month. Her data is shown using the dot plot. Create a box plot to represent the data. (1 point)
dot plot titled Monthly Wind Speed and number line from 9 to 10 in increments of 1 tenth labeled Wind Speed (in miles per hour) with zero dots over 9, 1 dot over 9 and 1 tenth, 2 dots over 9 and 2 tenths, 1 dot over 9 and 3 tenths, 3 dots over 9 and 4 tenths, zero dots over 9 and 5 tenths, 1 dot over 9 and 6 tenths, 2 dots over 9 and 7 tenths, 1 dot over 9 and 8 tenths, zero dots over 9 and 9 tenths, and zero dots over
box plot with minimum value 9 and 2 tenths, lower quartile 9 and 3 tenths, median 9 and 5 tenths, upper quartile 9 and 8 tenths, and maximum value 9 and 9 tenths
box plot with minimum value 9 and 1 tenth, lower quartile 9 and 2 tenths, median 9 and 4 tenths, upper quartile 9 and 7 tenths, and maximum value 9 and 8 tenths
box plot with minimum value 9 and 1 tenth, lower quartile 9 and 3 tenths, median 9 and 4 tenths, upper quartile 9 and 6 tenths, and maximum value 9 and 8 tenths
box plot with minimum value 9 and 1 tenth, lower quartile 9 and 2 tenths, median 9 and 5 tenths, upper quartile 9 and 7 tenths, and maximum value 9 and 8 tenths
The correct box plot to represent the data on wind speed is: minimum at 9.1, first quartile at 9.2, median at 9.4, 3rd quartile at 9.7, maximum at 9.8.
What is a boxplot?
A boxplot refers to a type of chart that can be used to graphically represent and show the five-number summary of a data set with respect to locality, skewness, and spread. Thus, the five-number summary include the following:
Minimum
First quartile
Median
Third quartile
Maximum
Based on the data on wind speed in a city, the minimum should be at 9.1, first quartile at 9.2, median at 9.4, 3rd quartile at 9.7, and maximum at 9.8.
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Answer:
I believe the answer is C.
Step-by-step explanation:
The point starts at 91 then goes up all the way to 94 making that the line thing (I cant remember the terms) then the end of the box would be 97 because you want the line to end at the last dot thats on 98
I hope this isnt confusing thats just how I got C
¿Qué es 1/3 x5 / 6? ¿Qué es 2/5 x 3/7?
La primera expresión es
[tex]\frac{1}{3}\times\frac{5}{6}[/tex]Para resolver esta multiplicación de fracciones, tenemos que multiplicar numerador con numerador y denominador con denominador.
[tex]\frac{1\times5}{3\times6}=\frac{5}{18}[/tex]Hence, the first product is 5/18.La segunda expresión es
[tex]\frac{2}{5}\times\frac{3}{7}[/tex]Repetimos el mismo proceso para multiplicar.
[tex]\frac{2\times3}{5\times7}=\frac{6}{35}[/tex]Hence, the second product is 6/35.While your family is visiting Deep Creek Lake, you and your mother decide to go to boating. The rangers charge $6.50 per hour in addition to a $25 deposit to rent a canoe. If the total cost to rent the canoe from 12:30 pm to 3:30pm, write and solve a linear equation to find the total cost to rent the canoe.
Given: The cost of renting a canoe is $6.50 per hour in addition to a $25 deposit.
Required: If the family rented the canoe from 12:30 PM-3:30 PM, write and solve a linear equation to find the total cost to rent the canoe.
Explanation: Let x denote the number of hours the family rented the canoe. Then the linear equation representing the total cost of renting the canoe is given by-.
[tex]Cost,\text{ }C=6.50x+25[/tex]Now, since the family rented the canoe for 3 hours. Putting x=3 in the above equation gives,
[tex]\begin{gathered} Cost=6.50\times3+25 \\ Cost=\text{\$}44.50\text{ } \end{gathered}[/tex]Final Answer: The equation representing the total cost of renting the canoe is-
[tex]C=6.50x+25[/tex]And the total cost of renting the canoe for 3 hours is $44.50.