Since the given function is
[tex]f(x)=3x-2[/tex]We want to evaluate it at some values of x
a) To find f(0), substitute x by 0
[tex]\begin{gathered} x=0 \\ f(0)=3(0)-2 \\ f(0)=0-2 \\ f(0)=-2 \end{gathered}[/tex]b) To find f(5), substitute x by 5
[tex]\begin{gathered} x=5 \\ f(5)=3(5)-2 \\ f(5)=15-2 \\ f(5)=13 \end{gathered}[/tex]c) To find f(b), substitute x by b
[tex]\begin{gathered} x=b \\ f(b)=3(b)-2 \\ f(b)=3b-2 \end{gathered}[/tex]d) To find f(x-1), substitute x by (x - 1)
[tex]\begin{gathered} x=(x-1) \\ f(x-1)=3(x-1)-2 \end{gathered}[/tex]Simplify it by multiply 3 by the bracket
[tex]\begin{gathered} f(x-1)=3(x)-3(1)-2 \\ f(x-1)=3x-3-2 \end{gathered}[/tex]Add the like term
[tex]\begin{gathered} f(x-1)=3x+(-3-2) \\ f(x-1)=3x+(-5) \\ f(x-1)=3x-5 \end{gathered}[/tex]Help me please don’t use me for pointsthis answer well be 12×
Answer:
9x + 3
Explanation:
Given the below expression;
[tex]1x-7+8x+10[/tex]The 1st to solving the above is to group like terms;
[tex]1x+8x-7+10[/tex]Let's go ahead and evaluate;
[tex]9x+3[/tex]Simplify and then evaluate the equation when x=4 and y =2
We need to plug in
x = 4
y = 2
into the expression and simplify/evaluate.
Let's evaluate:
[tex]\begin{gathered} 5x+2(9y-x)-y \\ x=4,y=2 \\ So, \\ 5(4)+2(9(2)-(4))-(2) \\ =20+2(18-4)-2 \\ =20+2(14)-2 \\ =20+28-2 \\ =46 \end{gathered}[/tex]Answer46Find the measure of the numbered angles in the rhombus (m1, m2, and m3).
The diagonals of a rhombus intersect at right angles. So, the m<1 is 90 degrees.
The diagonals of a rhombus bisect each vertex angle.
Therefore, the angle of vertex of 24 degree angle angle is 24x2=48.
The opposite angle of 48 degree angle is also 48 degrees. Since the angle is bisected by diagonal,m<2=24 degree.
The sum of opposite angles, 48+48=96.
The sum of other two equal opposite angles, 360-96=264.
The half of 264 is one angle, So, 264/2=132. Again <3=132/2=66.
m<1=90, m<3=66, m<2=24
Factor. x2 − x − 72 (x − 8)(x + 9) (x − 6)(x + 12) (x + 8)(x − 9) (x + 6)(x − 12)
The solution of the given equation are; (x + 8)(x − 9)
What is a quadratic equation?A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
We have been given the quadratic equation as;
x² − x − 72
Solving;
x² − (9-8)x − 72
x² − 9x +8x− 72
The factors are;
(x + 8)(x − 9)
Therefore, the solution of the given equation are; (x + 8)(x − 9)
Learn more about quadratic equations;
https://brainly.com/question/17177510
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Given: AB - BC, ZA ZC and BD bisects ABC. Prove: A ABD ~ ACBD.
Since BD bisects ABC, then angles ADB and BDC are congruent. Now that we have that both triangles ABD and CBD have the same two sides and angle, we have that they are congruent (because the side-angle-side postulate)
line AB and CD intersect at E. if the measurement of angle AEC = 12x+5 and the measurement of angle DEB = x+49, find the measurement of angle DEB
We will start by drawing the lines and angles:
By the properties of the angles that are opposed by the vertex, we know that the measure of the angle AEC and the measure of the angle DEB are the same.
So we can express:
[tex]\begin{gathered} m\text{AEC}=m\text{DEB} \\ 12x+5=x+49 \\ 12x-x=49-5 \\ 11x=44 \\ x=\frac{44}{11} \\ x=4 \end{gathered}[/tex]So we can calculate DEB as:
[tex]\text{DEB}=x+49=4+49=53[/tex]The angle DEB has a measure of 53 degrees.
=Volume of a cylinderThe diameter of a cylindrical construction pipe is 6 ft. If the pipe is 25 ft long, what is its volume?Use the value 3.14 for it, and round your answer to the nearest whole number.Be sure to include the correct unit in your answer.
The volume of a cylinder is given by the following formula:
[tex]V=\frac{\pi\cdot h\cdot d^2}{4}[/tex]Where h is the height and d is the diameter.
We can consider the length of the pipe as the height of the cylinder.
Then h=25 ft and d=6 ft. Replace these values in the formula and solve for V:
[tex]\begin{gathered} V=\frac{3.14\cdot25ft\cdot(6ft)^2}{4} \\ V=\frac{3.14\cdot25ft\cdot36ft^2}{4} \\ V=\frac{2826ft^3}{4} \\ V=706.5ft^3 \\ V\approx707ft^3 \end{gathered}[/tex]The volume is 707 ft^3
What is the mean absolute deviation (MAD) of the dada set? 2, 5, 6, 12, 15 Enter your answer as a decimal in the box.
To get the mean absolute deviation, we first need the mean of the set. The mean is calculated by the sum of the values divided by the number of data:
[tex]\begin{gathered} \mu=\frac{2+5+6+12+15}{5} \\ \mu=\frac{40}{5} \\ \mu=8 \end{gathered}[/tex]To get the means absolute deviation, we have to get the absolute difference between each data and the mean, sum them up and divide by the number of data:
[tex]\begin{gathered} d_1=|2-8|=|-6|=6 \\ d_2=|5-8|=|-3|=3 \\ d_3=|6-8|=|-2|=2 \\ d_4=|12-8|=|4|=4 \\ d_5=|15-8|=|7|=7 \\ MAD=\frac{6+3+2+4+7}{5}=\frac{22}{5}=4.4 \end{gathered}[/tex]2. Write the equation of the graph shown below. 3 1 -2 0 2 1-
The function in the graph is V shaped, this indicates that it corresponds to a function of an absolute value of x:
[tex]f(x)=|x|[/tex]The V opens downwards, which means that the coefficient that multiplies the module (a) is negative:
[tex]f(x)=-|x|[/tex]→ This means rthat when we calculate the value of "a", this value has to be negative
As you can see in the graph, the vertex of the function is (0,3)
Following the vertex form:
[tex]f(x)=a|x-x_v|+y_v[/tex]Where xv represents the x-coordinate of the vertex and yv represents the y-coordinate of the vertex. Replace them in the formula and we get that:
[tex]\begin{gathered} f(x)=a|x-0|+3 \\ f(x)=a|x|+3 \end{gathered}[/tex]Now all we need to do is determine the value of "a", for this we have to use one point of the function and replace it in the formula, this way "a" will be the only unknown.
Lets take for example one of the roots (points where the function crosses the x-axis)
Point (1, 0)→ replace it in the formula
[tex]\begin{gathered} 0=a|1|+3 \\ 0=a+3 \\ a=-3 \end{gathered}[/tex]Now that we know the value of a, we can determine the wquation of the function as
[tex]f(x)=-3|x|+3[/tex]The circle at the right represents a planet. The radius of the planet is about 6600 km. Find the distance to the inizon that a person can seeon a clear day from the following heighth above the planeth 7 km
need help converting point slope form equation to slope intercept form(y+10)=1/3(x+9)
The slope-intercept form is
→ y = m x + b
→ m is the slope
→ b is the y-intercept
∵ The given equation is
[tex]y+10=\frac{1}{3}(x+9)[/tex]First, multiply the bracket (x + 9) by 1/3
[tex]\begin{gathered} \because y+10=\frac{1}{3}(x)+\frac{1}{3}(9) \\ \therefore y+10=\frac{1}{3}x+3 \end{gathered}[/tex]Subtract 10 from both sides
[tex]\begin{gathered} \because y+10-10=\frac{1}{3}x+3-10 \\ \therefore y+0=\frac{1}{3}x-7 \\ \therefore y=\frac{1}{3}x-7 \end{gathered}[/tex]The equation in the slope-intercept form is y = 1/3 x - 7
how do i solve for d ?3(2d-4) = 6(d-2)
Solution:
Given the equation;
[tex]3(2d-4)=6(d-2)[/tex]SImplify:
[tex]6d-12=6d-12[/tex]Since the two sides of the equation are equal, d has infinitely many solutions.
_+_=10.5 _-3.25=_help me pls
These questions can have multiple answers
for instance,
a)
_+_=10.5
8.5 + 2 = 10.5
5.5 + 5 = 10.5
3.5 +7 = 10.5
5.25 + 5.25 = 10.5
b)
_-3.25 =_
7 - 3.25 = 3.75
7.25 - 3.25 = 4
10. 5 - 3.25 = 7.25
c)
if each _ have the same value
x + x = 10.5
2x= 10.5
x= 5.25
d)
if each _ have the same value
_-3.25 =_
x -3.25= x
x-x = 3.25
0= 3.25
In this case, each x cannot be the same, it would have to be a number that you subtract 3. 25 and it remains the same number. That is not possible.
but if i use x= 5.25
5.25- 3.25= 2
Ben earned $400 dollars last month.He worked 3 days in the first week andalso worked 2 days in the secondweek. How much does he earn eachday?
Given Data:
Ben earned $400 last month.
Since in the academic calendar the last month was July consisting of 31 days.
Therefore the amount earned per day can be calculated as
[tex]\frac{400}{31}[/tex]Now, He worked 3 days in the first week and 2 days in the second week.
So the total number of working days is 5.
Therefore the amount earned for 5 days will be
[tex]\frac{400}{31}\times5=64.51[/tex]Therefore the amount for 6 days is approximate $65.
And Hence for each day it is $13.
a vector w has initial point (0,0) and terminal point (-5,-2) write w in the form w=ai+bj
The initial point is (0,0) and the terminal point (-5,-2).
First, graph the points:
Lets say that A= (0,0) and B = (-5,-2)
So my vector w= line(AB)
Use the component form
Replace the values <-5-0, -2-0>
Then <-5,-2>
In the form w=ai+bj
w = -5i -2j
Looking at the graph we have -2 on the y-axis and -5 on the x-axis.
Use a proportion to find the missing side length, x.
Answer:
The measure of angle ABC is;
[tex]m\measuredangle ABC=72^0[/tex]Explanation:
Given the triangle ABC.
Recall that the sum of angles in a triangle is 180 degrees;
[tex]8x+6x+6x=180[/tex]solving for x, we have;
[tex]\begin{gathered} 8x+6x+6x=180 \\ 20x=180 \\ x=\frac{180}{20} \\ x=9 \end{gathered}[/tex]From the diagram,
[tex]\begin{gathered} \measuredangle ABC=8x \\ \measuredangle ABC=8(9) \\ \measuredangle ABC=72^0 \end{gathered}[/tex]Therefore, the measure of angle ABC is;
[tex]m\measuredangle ABC=72^0[/tex]Once Farid spends 15 minutes on a single level in his favorite video game, he loses a life. Hehas already spent 10 minutes on the level he's playing now.Let x represent how many more minutes Farid can play on that level without losing a life.Which inequality describes the problem?
If he spends 15 minutes on a single level, he loses his life.
He has already spent 10 minutes on the level he is playing now.
x = the number of minutes he can play without losing a life.
The inequalities that can be use to represent this scenario will be
[tex]10+x<15[/tex]Which equation can be used to find the solution of (1/4)y+1=64 ? −y−1=3y−1=3−y+1=3y + 1 = 3
1/4 and 64 can be expressed as follows:
[tex]\begin{gathered} \frac{1}{4}=4^{-1} \\ 64=4^3 \end{gathered}[/tex]Substituting into the equation:
[tex]\begin{gathered} (4^{-1})^{y+1}=4^3 \\ 4^{(-1)(y+1)}=4^3 \\ 4^{-y-1}=4^3 \\ -y-1=3 \end{gathered}[/tex]Can someone please help me do #6 and #8 please
#6:
As it's a rhombus, the diagonal is a bisector, so:
med 2 = 27
med 3 = 27
and
med 5 = 27
med 4 = med 1
Also, the sum of interior angles of a triangle is 180 degrees. Then:
27 + 27 + med 1 = 180
med 1 = 126
med 4 = 126
A shipment of 10 computers contains 4 with defects. Find the probability that a sample of size 4, drawn from the 10, will not contain a defective computer,The probability is:
ANSWER
[tex]P=\frac{81}{625}[/tex]EXPLANATION
There are 4 defects out of 10 total computers. This means that there are 6 computers without defects.
The probability that 1 computer selected will not be defective is the total number of non-defective computers divided by the total number of computers:
[tex]P(one-without-defect)=\frac{6}{10}[/tex]Therefore, if a sample of 4 computers is selected, the probability that the sample will not contain a defective computer is:
[tex]\begin{gathered} P=\frac{6}{10}\cdot\frac{6}{10}\cdot\frac{6}{10}\cdot\frac{6}{10}=(\frac{6}{10})^4 \\ P=\frac{81}{625} \end{gathered}[/tex]Use the graph to write an equation for f(x).Oy=1(12)Oy=3(4)*Oy=12(4)*Oy=4(3)*
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[tex]\begin{gathered} g(x)=36x-24 \\ g(1)=36(1)-24=36-24=12 \\ g(2)=36(2)-24=72-24=48 \end{gathered}[/tex][tex]y=36x-24[/tex]Solve the equation, give the exact solution then approximate the solution to the nearest hundredth
Given the expression:
[tex]10-3x^2=4[/tex]We can find its solution by solving like a linear equation up until the exponent:
[tex]\begin{gathered} 10-3x^2=4 \\ \Rightarrow-3x^2=4-10 \\ \Rightarrow-3x^2=-6 \\ \Rightarrow x^2=\frac{-6}{-3}=2 \\ x^2=2 \end{gathered}[/tex]now, we can apply the square root on both sides to get the following:
[tex]\begin{gathered} \sqrt[]{x^2}=\sqrt[]{2} \\ \Rightarrow x=\pm\sqrt[]{2=} \\ x=\pm1.41 \end{gathered}[/tex]therefore, the solutions of the equation are x=1.41 and x=-1.41
Graph the line x= -3 on the axes shown below. Type of line: Choose one
due to the equation that represents the line is a line with no slope defined and is drawn up and down and are parallel to the y-axis.
in this case, since x=-3 it means that this value won't change along the y-axis
find the total and the interestprincipal $3200rate 5 1/2 yearscompounded semiannually for 6 years
Remember that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
P=$3,200
r=5 1/2 %=5.5%=0.055
t=6 years
n=2
substitute the given values
[tex]A=3,200(1+\frac{0.055}{2})^{2\cdot6}[/tex]A=$4,431.31 ------> the totalFind out the interest
I=A-P
I=4,431.31-3,200
I=$1,231.31 -----> interestSimplify (3^z)^6 leave your answer in exponential notation
[tex](3^z)^6[/tex][tex]3^{6z}[/tex]
What is the future value of an ordinary annuity of ₱38,000 per year, for 7 years, at 8% interest compounded annually?
Annuities
The future value (FV) of an annuity is given by:
[tex]FV=A\cdot\frac{(1+i)^n-1}{i}[/tex]Where:
A is the value of the annuity or the regular payment
i is the interest rate adjusted to the compounding period
n is the number of periods of the investment (or payment)
The given values are:
A = $38,000
n = 7 years
i = 8% = 0.08
Substituting:
[tex]\begin{gathered} FV=\$38,000\cdot\frac{(1+0.08)^7-1}{0.08} \\ FV=\$38,000\cdot\frac{(1.08)^7-1}{0.08} \\ \text{Calculate:} \\ FV=\$38,000\cdot\frac{0.7138243}{0.08} \\ FV=\$38,000\cdot8.9228 \\ FV=\$339,066.53 \end{gathered}[/tex]The future value is $339,066.53
With cell phones being so common these days, the phone companies are all competing to earn business by offering various calling plans. One of them, Horizon, offers 700 minutes of calls per month for $45.99, and additional minutes are charged at 6 cents per minute. Another company, Stingular, offers 700 minutes for $29.99 per month, and additional minutes are 35 cents each. For how many total minutes of calls per month is Horizon’s plan a better deal?
For the Horizon offer
There is a cost of $45.99 for 700 minutes plus 6 cents for each additional minute
Since 1 dollar = 100 cents, then
6 cents = 6/100 = $0.06
If the total number of minutes is x, then
The total cost will be
[tex]C_H=45.99+(x-700)0.06\rightarrow(1)[/tex]For the Stingular offer
There is a cost of $29.99 for 700 minutes plus 35 cents for each additional minute
35 cents = 35/100 = $0.35
For the same number of minutes x
The total cost will be
[tex]C_S=29.99+(x-700)0.35\rightarrow(2)[/tex]For Horizon to be better that means, it cost less than the cost of Stingular
[tex]\begin{gathered} C_HSubstitute the expressions and solve for x[tex]\begin{gathered} 45.99+(x-700)0.06<29.99+(x-700)0.35 \\ 45.99+0.06x-42<29.99+0.35x-245 \\ (45.99-42)+0.06x<(29.99-245)+0.35x \\ 3.99+0.06x<-215.01+0.35x \end{gathered}[/tex]Add 215.01 to both sides
[tex]\begin{gathered} 3.99+215.01+0.06x<-215.01+215.01+0.35x \\ 219+0.06x<0.35x \end{gathered}[/tex]Subtract 0.06x from both sides
[tex]\begin{gathered} 219+0.06x-0.06x<0.35x-0.06x \\ 219<0.29x \end{gathered}[/tex]Divide both sides by 0.29 to find x
[tex]\begin{gathered} \frac{219}{0.29}<\frac{0.29x}{0.29} \\ 755.17Then x must be greater than 755.17The first whole number greater than 755.17 is 756
The total minutes should be 756 minutes per month for Horizon's to be the better deal.
Which answer choice represents a simplified form of the expression 2.5 + 7 1 - 2.3 - 4?* O (2.5 + 2.3) - 7-4 0 (2.5 - 2.3) - (7-4) O (2.5 - 2.3) + (7 - 4) 4 + 7 + (2.5 - 2.3)
The sum of sixteen times a number and twelve is 172. Find the number.
Answer:
Step-by-step explanation:
1. (16 · x) + 12 = 172
2. x= 172-12/16
3. x = 10
4. The number is 10.
Suppose that the functions f and g are defined as follows.f(x) = x² +78g(x) =3x5x70Find the compositions ff and g9.Simplify your answers as much as possible.(Assume that your expressions are defined for all x in the domain of the composition. You do not have to indicate the domain.)
ANSWER
[tex]\begin{gathered} (f\cdot f)(x)=x^4+14x^2+49 \\ (g\cdot g)(x)=\frac{64}{9x^2} \end{gathered}[/tex]EXPLANATION
We are given the two functions:
[tex]\begin{gathered} f(x)=x^2+7 \\ g(x)=\frac{8}{3x} \end{gathered}[/tex]To find (f * f)(x), we have to find the product of f(x) with itself.
That is:
[tex](f\cdot f)(x)=f(x)\cdot f(x)[/tex]Therefore, we have:
[tex]\begin{gathered} (f\cdot f)(x)=(x^2+7)(x^2+7) \\ (f\cdot f)(x)=(x^2)(x^2)+(7)(x^2)+(7)(x^2)+(7)(7) \\ (f\cdot f)(x)=x^4+7x^2+7x^2+49 \\ (f\cdot f)(x)=x^4+14x^2+49 \end{gathered}[/tex]We apply the same procedure to (g * g)(x):
[tex]\begin{gathered} (g\cdot g)(x)=(\frac{8}{3x})(\frac{8}{3x}) \\ (g\cdot g)(x)=\frac{64}{9x^2} \end{gathered}[/tex]Those are the answers.