Elizabeth wraps a gift box in the shape of a square pyramid. The figure below shows a net for the gift box. 6 in 6.8 in
Answers
The wrapping paper used by Elizabeth is equal to the area of the square pyramid which is 127.84 in.².
Dimension of the square base:
Side = 6.8 in.
Area of the base = 6.8 in. × 6.8 in.
A = 46.24 in.²
Dimension of the triangle:
Base = 6.8 in.
Height = 6 in.
Area of 1 triangle = 1/2 × 6.8 in. × 6 in.
A (triangle) = 20.4 in.²
Area of 4 triangles = 4 × 20.4 in.²
A' = 81.6 in.²
Total area of the square pyramid = A + A'
T = 46.24 in.² + 81.6 in.²
T = 127.84 in.²
Therefore, the wrapping paper used by Elizabeth is equal to the area of the square pyramid which is 127.84 in.².
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Your question is incomplete. Please refer the content below:
Elizabeth wraps a gift box in the shape of a square pyramid.
The figure below shows a net for the gift box.
How much wrapping paper did she use?
Related Questions
Fill in the following values for a 45-45-90 triangle Leg Leg Hypotenuse 5 А B C С D 32 Fill in the following values for a 30-60-90 triangle Short Leg Long Leg Hypotenuse 6 E H 20 G
Answers
First Part 45-45-90 Triangle
first triangle
where the two angles different to 90° are same, the measure of the legsof the triangle are the same
then
[tex]A=5[/tex]and to calculate B or the hypotenuse we use pythagoras
[tex]a^2+b^2=h^2[/tex]where a and b are legs and h the hypotenuse
replacing
[tex]\begin{gathered} 5^2+5^2=h^2 \\ 25+25=h^2 \\ 50=h^2 \\ h=\sqrt[]{50} \\ h=5\sqrt[]{2} \end{gathered}[/tex]the hypotenuse or B is
[tex]B=5\sqrt[]{2}[/tex]Second triangle
legs of the triangle have the same value then if we apply pythagoras
[tex]a^2+b^2=h^2[/tex]and replace the legs with the same value(a)
[tex]\begin{gathered} a^2+a^2=h^2 \\ 2a^2=h^2 \end{gathered}[/tex]we can replace the hypotenuse and solve a
[tex]\begin{gathered} 2a^2=(3\sqrt[]{2})^2 \\ 2a^2=18 \\ a^2=\frac{18}{2} \\ \\ a=\sqrt[]{9} \\ a=3 \end{gathered}[/tex]value of each leg is 3 units, then
[tex]C=D=3[/tex]Second part 30-60-90 triangle
First triangle
we use trigonometric ratios to solve, for example I can use tangent for the angle 60 to find E
[tex]\tan (\alpha)=\frac{O}{A}[/tex]where alpha is the angle, O the oppiste side of the angle and A the adjacet side of the angle
using angle 60°
[tex]\begin{gathered} \tan (60)=\frac{E}{6} \\ \\ E=6\tan (60) \\ \\ E=6\sqrt[]{3} \end{gathered}[/tex]now using sine we calculate F or the hypotenuse
[tex]\sin (\alpha)=\frac{O}{H}[/tex]where alpha is the angle, O the opposite side from the angle and H the hypotenuse
using angle 60°
[tex]\begin{gathered} \sin (60)=\frac{E}{F} \\ \\ F=\frac{E}{\sin (60)} \\ \\ F=\frac{6\sqrt[]{3}}{\sin (60)} \\ \\ F=12 \end{gathered}[/tex]Second triangle
we use sine with 60° to find H
[tex]\begin{gathered} \sin (\alpha)=\frac{O}{h} \\ \\ \sin (60)=\frac{H}{20} \\ \\ H=20\sin (60) \\ H=10\sqrt[]{3} \end{gathered}[/tex]use cosine with 60° to find G
[tex]\begin{gathered} \cos (\alpha)=\frac{A}{h} \\ \\ \cos (60)=\frac{G}{20} \\ \\ G=20\cos (60) \\ \\ G=10 \end{gathered}[/tex]Final Values
[tex]\begin{gathered} A=5 \\ B=5\sqrt[]{2} \\ C=3 \\ D=3 \\ E=6\sqrt[]{3} \\ F=12 \\ G=10 \\ H=10\sqrt[]{3} \end{gathered}[/tex]Convert the Cartesian equation x^2 + y^2 + 3y = 0 to a polar equation.r^2 = -3 sin θr = √3 sin θr = -3 sin θ
Answers
SOLUTION
From the question
[tex]x^2+y^2+3y=0[/tex]This becomes
[tex](x^2+y^2)+3y=0[/tex]In polar,
[tex]\begin{gathered} x^2+y^2=r^2 \\ \\ \text{and } \\ \\ y=r\sin \theta \end{gathered}[/tex]So, this becomes
[tex]\begin{gathered} r^2+3r\sin \theta=0 \\ \\ \frac{r^2}{r}=\frac{-3r\sin \theta}{r} \\ \\ r=-3\sin \theta \end{gathered}[/tex]Eli and her sister are buying a present for their father. They want to buy him a tie that sings jingle bells. The Thai which is regularly $35 is on sale for 40% off because it is after the winter holidays. The girls will split the cost evenly and their mother gave them $15 to help with the cost of the tie. If the tax is 8%, how much will Eli and her sister each have to spend on their father's tie?
Answers
Answer:
Explanation:
The regular cost of the tie = $35
There is a sale for 40% off.
[tex]\text{Discount}=40\%\text{ of \$35}=\frac{40}{100}\times35=14[/tex]Thus, the price after the discount will be:
[tex]35-14=\$21[/tex]Next, the tax is 8%.
[tex]\text{Tax}=8\%\text{ of 21=}\frac{8}{100}\times21=\$1.68[/tex]Therefore, the total price at which the tie is purchased will be:
[tex]21+1.68=\$22.68[/tex]Since their mother gave them $15 to help with the cost of the tie, subtract 15.
[tex]22.68-15=\$7.68[/tex]This amount, $7.68 is the split between Eli and her sister.
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Use the given information to create the equation for the rational function. The function is written in factored form to help you see how the given information shapes our equation. If the leading coefficient is not an integer enter the value as a fraction.Vertical asymptote at x=-1, double zero at x=2, y-intercept at (0,2).The numerator is: Answer (x-Answer )(x-Answer )The denominator is: (x+Answer )
Answers
Given:
• Vertical asymptote at : x = -1
,• Double zero at: x = 2
,• y-intercept at: (0, 2)
Let's create the equation for the rational function using the given properties.
Since the vertical asymptote is at x = -1, to find the deominator of the equation, equate the vertical asymptote to zero.
Add 1 to both sides:
[tex]\begin{gathered} x+1=-1+1 \\ x+1=0 \end{gathered}[/tex]Therefore, the denominator of the function is ==> x + 1
Since it has a double zero at x = 2, we have the factors:
[tex]\Longrightarrow(x-2)(x-2)[/tex]We now have the equation:
[tex]y=\frac{a(x-2)(x-2)}{x+1}[/tex]Also, the y-intercept is at: (0, 2)
To find the value o a, substitute 2 for y and 0 for x then evaluate:
[tex]\begin{gathered} 2=\frac{a(0-2)(0-2)}{0+1} \\ \\ 2=\frac{a(-2)(-2)}{1} \\ \\ 4a=2 \\ \\ a=\frac{2}{4} \\ \\ a=\frac{1}{2} \end{gathered}[/tex]Therefore, the rational function is:
[tex]y=\frac{\frac{1}{2}(x-2)(x-2)}{x+1}[/tex]ANSWER:
[tex]y=\frac{\frac{1}{2}(x-2)(x-2)}{x+1}[/tex][tex]\begin{gathered} \text{Numerator: }\frac{1}{2}(x-2)(x-2) \\ \\ \\ \text{Denominator: (x + 1)} \end{gathered}[/tex]Evaluate the input/output table for the expression x - 9.Хy-101
Answers
x - 9
when x = -1
out put is -1 -9 = -10
when x = 0
Output is 0-9 = -9
when x = 1
output = 1-9 = -8
x y
-1 -10
0 -9
1 -8
determine whether the triangle with the given side lengths is a right triangle4 ,7, 11
Answers
For the a triangle to be a right angle triangle, the length of the three sides must form a pythagorean triple. This means that if we apply pythagoras theorem, the square of the length of the longest side must equal the sum of the squares of the length of the other sides. This means that
11^2 must be equal to 4^2 + 7^2
11^ = 121
4^2 + 7^2 = 16 + 49 = 65
Since they are not equal, then the triangle with the given sides, 4, 7, 11 cannot form a right angle triangle.
Find a standard deviation of the binomial for which N = 420 and P = 0.90. Answer choices 37.86.153786.2
Answers
The standard deviation σ is given by:
[tex]\begin{gathered} \sigma=\sqrt{np(1-p)} \\ \text{ Where} \\ p=\text{ the probability of success} \\ n=\text{ number of trials} \end{gathered}[/tex]Substitute n = 420 and p = 0.90 into the formula:
[tex]\sigma=\sqrt{420\cdot0.90(0.10)}\approx6.15[/tex]Hence the correct answer is 6.15
Second Choice
Matt drew the two rectangles shown in thediagram below.ABD16 in.ABD12 inсMatt dilated Rectangle ABCD to createRectangle A'B'CD'.What scale factor did Matt use todilate Rectangle ABCD?
Answers
Not sure how to figure this out.Options:A. 49 square feet B. 7 square feet. C. 28 square feet. D.14 square feet
Answers
According to the information given in the exercise, the pen for his rabbit is square and each side is 7 feet long.
You know that the formula for calculating the area of a square is:
[tex]A=s^2[/tex]Where "s" is the length of each side of the square.
In this case:
[tex]s=7ft[/tex]Then, you need to substitute this length into the formula and then evaluate, in order to find the area. You get:
[tex]\begin{gathered} A=(7ft)^2 \\ A=49ft^2 \end{gathered}[/tex]Hence, the answer is: Option A.
Find the mean, median, and mode for the data set. If there is no mode, write none. If there is more than one mode,write your solutions from least to greatest, separated by a comma.50,30,40,10,20,80,60,90,10,30,110, 70mean:median:mode:
Answers
Answer:
• Mean: 50
,• Median: 45
,• Mode: 10,30
Explanation:
Given the data set:
[tex]50,30,40,10,20,80,60,90,10,30,110,70[/tex]Before we begin, arrange the numbers from the least to the greatest.
[tex]10,10,20,30,30,40,50,60,70,80,90,110[/tex](a)Mean
To find the mean, add up the numbers and divide by the number of items (12 in this case).
[tex]\begin{gathered} Mean=\frac{10+10+20+30+30+40+50+60+70+80+90+110}{12} \\ =\frac{600}{12} \\ Mean=50 \end{gathered}[/tex]The mean of the dataset is 50.
(b)Median
The median is the number in the middle of the dataset when arranged in ascending order.
• There are two numbers in the middle: 40 and 50
,• Take the average to find the median.
[tex]Median=\frac{40+50}{2}=\frac{90}{2}=45[/tex]The median of the dataset is 45.
(c)Mode
The mode is/are the number(s) that appear the most number of times..
[tex]10,10,20,30,30,40,50,60,70,80,90,110[/tex]In the dataset:
• 10 appears twice
,• 30 appears twice
The modes of the dataset are 10 and 30.
Hi, I need help with this problem please. No explanations/steps required. Just need the final answer
Answers
To simplify the expression we fist need to express each trigonometric function in terms of sines and cosines; to do this we need to remember that:
[tex]\begin{gathered} \sec x=\frac{1}{\cos x} \\ \csc x=\frac{1}{\sin x} \end{gathered}[/tex]With this in mind we have:
[tex]\begin{gathered} \frac{\csc x}{\sec x}=\frac{\frac{1}{\sin x}}{\frac{1}{\cos x}} \\ =\frac{\cos x}{\sin x} \end{gathered}[/tex]Finally we need to remember that:
[tex]\cot x=\frac{\cos x}{\sin x}[/tex]Therefore, we have that:
[tex]\frac{\csc x}{\sec x}=\cot x[/tex]John is a salesman for a company. he earns a straight commission at a rate of 4 and 1/2% . last month his total says were $82,969. what is his gross monthly income for last month?
Answers
hello
his gross income was = $82,969
commission = 4 1/2% or 4.5%
since we have the gross income, we can use that data to find his actual salary for the month.
all we need to do is find 4.5% of 82969 and subtract the value from it
[tex]\begin{gathered} 4.5\text{ \% of 82969} \\ \frac{4.5}{100}=\frac{x}{82969} \\ \text{cross multiply both sides and solve for x} \\ 100\times x=4.5\times82969 \\ 100x=373360.5 \\ \text{divide both sides by 100} \\ \frac{100x}{100}=\frac{373360.5}{100} \\ x=3733.605 \end{gathered}[/tex]the commission pay was $3733.605
to find his actual salary, subtract 3733.605 from 82969
[tex]\text{ income}=82969-3733.605=79235.395[/tex]from the calculations above, his income for last month was $79235.395
Coordinate R (1,5) S (6,-1) and T (1,-4) are connected to form ∆ RST if ∆ RST is congruent to ∆ RWT what are the coordinates of W
Answers
The triangles are similar, then ratio of corresponding sides of triangle are equal. The ratio of corresponding sides of two triangle RST and triangle RWT is,
[tex]\begin{gathered} \frac{RS}{RW}=\frac{RT}{RT} \\ \frac{RS}{RW}=1 \\ RS=RW \end{gathered}[/tex]Determine the length of side RS.
[tex]\begin{gathered} RS=\sqrt[]{(1-6)^2+(5+1)^2} \\ =\sqrt[]{25+36} \\ =\sqrt[]{61} \end{gathered}[/tex]So the distance between point RW is also equal to square root 61.
For option (-4,2),
[tex]\begin{gathered} RW=\sqrt[]{(-4-1)^2+(5-2)} \\ =\sqrt[]{25+9} \\ =\sqrt[]{36} \end{gathered}[/tex]For o(-6,-1),
[tex]\begin{gathered} RW=\sqrt[]{(-6-1)^2+(5+1)^2} \\ =\sqrt[]{49+36} \\ =\sqrt[]{85} \end{gathered}[/tex]For (-4,-1),
[tex]\begin{gathered} RW=\sqrt[]{(1+4)^2+(5+1)^2} \\ =\sqrt[]{25+36} \\ =\sqrt[]{61} \end{gathered}[/tex]So coordinate of point W is (-4,-1) as it give same distance of RS and RW.
Answer: (-4,-1)
Is the ordered pair (3,-4) a solution to : 5x-2y=17
Answers
Given
[tex]5x-2y=17[/tex]Set x=3 and solve for y, as shown below
[tex]\begin{gathered} x=3 \\ \Rightarrow5*3-2y=17 \\ \Rightarrow15-2y=17 \\ \Rightarrow-2y=2 \\ \Rightarrow y=-1 \end{gathered}[/tex]Therefore, a solution to the equation is the ordered pair (3,-1).
(3,-4) cannot be a solution to the equation.Solve the quadratic equation by completing the square.4a²- 48a +52 = 0a= _,_
Answers
Given
[tex]4a^2-48a+52=0[/tex]Solution
[tex]\begin{gathered} 4a^2-48a+52=0 \\ So\text{ divide both sides by 4} \\ \frac{4a^2}{4}-\frac{48a}{4}+\frac{52}{4}=0 \\ which\text{ gives } \\ a^2-12a+13=0 \\ Keep\text{ a on LHS} \\ a^2-12a=-13 \\ Take\text{ the half of coefficient of a and square it} \\ (-\frac{12}{2})^2=36 \\ \\ rewrite\text{ as perfect square} \\ \\ (a-6)^2=-13+36 \\ (a-6)^2=23 \\ \end{gathered}[/tex][tex]\begin{gathered} a-6=\pm\sqrt{23} \\ a=6\pm\sqrt{23} \end{gathered}[/tex][tex]\begin{gathered} a=10.79583\text{ ,}a=1.20416 \\ or \\ a=6+\sqrt{23},\:a=6-\sqrt{23}\quad \\ \\ \end{gathered}[/tex]What is the output value for the following function, f(x) = 5x - 2 if the input value is 3?options:1751131
Answers
Solution:
Given the function below
[tex]f(x)=5x-2[/tex]Where
[tex]\begin{gathered} x\text{ is the input value} \\ f(x)\text{ is the output value} \end{gathered}[/tex]If the input value is 3, i.e. x = 3, the output value will be
[tex]\begin{gathered} f(x)=5x-2 \\ f(3)=5(3)-2=15-2=13 \\ f(3)=13 \end{gathered}[/tex]Hence, the output value is 13
If a population isa sample of the population could be
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REQUIRED;
To identify which of the statements given properly depicts the population and the sample.
Explanation:
In statistics and research processes, a population ideally refers to the entire group that we want to study and reach conclusions about. It can best be described as all-inclusive.
On the other hand, a sample is a portion taken out of an entire population for the purpose of studies or research and the appropriate data is collected from these.
We shall now examine the options given one after the other.
(A) Registered state voters randomly collected for a poll; all citizens of the state. This represents SAMPLE and POPULATION
(B) All professional football players; all professional athletes. This represents POPULATION and POPULATION
(C) All customers at a shopping mall; people who purchased shoes. This represents POPULATION and SAMPLE.
(D) Passengers with window seats; all passengers on an airplane. This represents SAMPLE and POPULATION.
ANSWER:
Therefore, the correct answer is OPTION C.
"If a population is all customers at a shopping mall, a sample of the population could be peole who purchased shoes.
Which expression is a factor of 9r2 – 4r + 1? F3r-1 Gr 1 H 9741 3 There are no real factors.
Answers
There are no real factors
Here, we want to factorize the given expression
To check if there are real factors, we will need to get the determinant
mathematically, we have this as;
[tex]D=b^2-4ac[/tex]where a is 9, b is -4 and c is 1
Substituting these values;
[tex]D=(-4)^2-4(9)(1)\text{ = 16-36 = -20}[/tex]As we can see, the value of the determinant is negative
Whenever the determinant value is negative, there are no real roots
Complete the explanation of whether the graph represents a proportional oa neno relationship 5 5 5 relationship The graph represents a (select) (select) proportional nonproportional
Answers
We are given the graph of a line, and we are asked to determine if it is a proportional or non-proportional relationship. Let's remember the general form of the equation of a line, that is:
[tex]y=mx+b[/tex]where "m" is the slope and "b" the y-intercept. The y-intercept is the value where the line touches the y-axis. According to the graph, the value of "b" is b = 1, therefore, the equation of the line would be:
[tex]y=mx+1[/tex]A proportional relationship is of the form:
[tex]y=kx[/tex]since the value of "b" is different from zero the relationship is non-proporsional.
The relationship is non-proportional
I know the answer to fill i is -24 but how do I simplify ??
Answers
[tex]a^{-24\text{ }}=\frac{1}{a^{24}}[/tex]
The first expression es the simplified expression using the property of negative exponents.
simplify 2a x a x 3a + b x 4b
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Explanation:
[tex]\begin{gathered} 2a\text{ *a *a * 3a = 2 * 3 * a *a * a } \\ 6\text{ * a}^3\text{ = 6a}^3 \end{gathered}[/tex][tex]\begin{gathered} \text{b * 4b = 4 *b * b } \\ \text{4 * b}^2\text{ = 4b}^2 \end{gathered}[/tex]Put them together
[tex]2a*a*a*3a\text{ + b * 4b = 6a}^3+4b^2[/tex]A local road rises 33 feet for every 423 feet of pavement. What is the slope of the road? Simplify your answer.
Answers
If a local road rises 33 feet for every 423 feet of pavement, the slope of the road will be rate of change of pavement with respect to the road. This is expressed as;
slope of the road = 423/33
Slope of the road = 12.82
Hence the slope of the road is 12.82
Write an inequality to match the statement.The difference of a number x and 7 is less than or equal to the sum of the same number x and 5
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The difference of a number x and 7 is less than or equal to the sum of the same number x and 5
The difference means subtraction.
A number is x
Less than or equal is represented with the symbol ≤
So:
The difference of a number x and 7
x-7
is less than or equal to the sum of the same number x and 5
≤ x+5
Altogether:
x-7≤ x+5
1Convert without rounding:8into a decimal (no need to show work)Τ Τ Τ ΤParagraphVArialV3 (12pt)V
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Given: the fraction 1/8.
Objective is to convert this fraction in to decimal.
[tex]\frac{1}{8}=0.125[/tex]Answer: 0.125
Triangle JKL is rotated 270° counterclockwise about the origin to form triangle J'K'L'. What is the y-coordinate of point J'? y 6 5 4 K 3 2. 1 -6 -5 -4 -3 -2 1 2 3 4 0 -1 6 Jo -2 3 4 -5 L -6 Type the answer in the box.
Answers
Rotation of 270° ,counterclockwise
Find center point of triangle
JK = √ 9^2 +5^2
. = √ 106
JL = √9^2 + 3^2
. = √90
KL = 8
Then now find point J'
Distance from J to origin = JO = √4^2+2^2 =√20
Angle is arctan (2/4) = 26.56°
Then new coordinates J' are
Angle 270+26.56 = 296.56°
From origin trace a line perpendicular to JO
then
y = √20• Cos 26°
y = 4
Answer:
-4
Step-by-step explanation:
good luck kiddos :)
Which lists all of the x-intercepts of the graphed function? A. (0,6)B. (1,0) and (2,0)C. (1,0), (2, 0), and (-3,0)D. (1,0), (2,0), (-3, 0), and (0, 6)
Answers
From the graph, the points at which the curve touch the x-axis is the intercepts on x
looking at the graph, the curve cut through the x axis at points -3, 1 and 2
hence the points will be
(-3, 0), (1, 0) and (2, 0)
Thus, the correct option is C;
(1, 0), (2, 0) and (-3, 0)
The graph of a function f is given. Use the graph to estimate the following. (Enter your answers using interval notation) PLEASE HELP!! confused on whole problem
Answers
From the graph
Domain = [ -1 , 4]
Range = [ -1 , 3 ]
b) When you look at the graph, the function f
Increasing = [ -1, 1 ] , [ 2, 4 ]
Decreasing = [ 1 , 2 ]
Keico is selling rattle tickets to raise money for the sancol band. The odds againet winning a prize in the raffleare 121. What is the probability of winning a prize? Express your anewer as a decimal. if necessary, round youranower to the nearest thousandth.0 130 0.923O 0.083O 0.0777
Answers
Given:
The odds against winning a prize in the raffle are 12:1
[tex]\begin{gathered} \text{Probability of winning a prize=}\frac{1}{13} \\ \text{Probability of winning a prize=}0.077 \end{gathered}[/tex]0.077 is the probability of winning a prize.
find the volume for the spear shown to The Right. Use 3.14 for pi sphere is 5.8
Answers
Semicircle perimeter is 5.8 m
THEN
2π • R + 2R = 5.8
R = 5.8/(2π + 2) = 0.7 meters
Now find Volume
Volume V = (4/3)•π•R^3
V= (4/3)•π•(0.7^3) = 1.438 cubic meters
V=. 1.438 m^3
Mixture of 40 liters of paint is 25% red tint, 30% yellow tint and 45% water. Five liters of red tint and five liters of yellow tint are added to the original mixture. What is the percent of water in this new mixture?
Answers
Step 1
25% of 40 litres is;
[tex]\frac{25}{100}\times40=10\text{ litres of red tint}[/tex]Step 2
30% of 40 litres;
[tex]\frac{30}{100}\times40=\text{ 12 litres of yellow tint}[/tex]Step 3
45% of 40 litres;
[tex]\frac{45}{100}\times40=18\text{ litres}[/tex]Step 4
5 liters of red tint are added and 5 liters of yellow tint are added to the original mixtures
[tex]\begin{gathered} 10\text{ +5=15 litres of red tint} \\ 12+5=17\text{ liters of yellow tint} \\ 18\text{ liters of water} \end{gathered}[/tex]Answer; What is the percent of water in this new mixture?
[tex]\begin{gathered} Total=15+17+18=50\text{ liters} \\ \frac{18}{50}\times100=36\text{\%} \end{gathered}[/tex]