East High School has 540 students. There are 220 girls in the school. What is the ratio of girls to boys at East High School?
Answers
11/16
1) Gathering the data
540 students
220 girls
540-220= 320
320 boys
2) Let's find out the ratio of girls to boys
Placing the number of girls in the numerator, and subsequently the number of boys as the denominator
Then simplify :
So we can state there's a ration of 11/16
There are 11 girls to 16 boys in that school
Related Questions
Thursday: Word Problems 1 The plant growth is proportional to time. When Tia bought the plant, it measured 2 cm. It measured 2.5 cm exactly one week later. If the plant continues to grow at this rate, determine the function that represents the plant's growth.
Answers
We have the next informtion
initial measure = 2 cm
after
7. Let f(x) = 3x and g(x) = (x + 2)^2. Find the value of (f og)(-5)A.135B. -27 C. 169. D.27.
Answers
f(x)= 3x
g(x)= (x+2)²
From the graph identify the zeros of the quadratic function
Answers
The zeros of the function are the points where it crosses the x axis:
Answer: (1,0) and (3,0)
What is the sum of the first 19 terms of the sequence 9,2,-5,-12....2SEE ANSWERS
Answers
ANSWER
-1026
EXPLANATION
The sum of the first n terms in an arithmetic sequence is,
[tex]S_n=\frac{n(a_1+a_n)}{2}[/tex]As we can see, we have to find the nth term of the sequence,
[tex]a_n=a_1+(n-1)d[/tex]In this case, the first term is 9 and the common difference is -7 - note that each term is the previous one minus 7. So the formula for the nth term is,
[tex]a_n=9-7(n-1)[/tex]We have to find the 19th term,
[tex]a_{19}=9-7(19-1)=9-7\cdot18=9-126=-117[/tex]So the sum of the first 19 terms is,
[tex]S_{19}=\frac{19\cdot(9+(-117))}{2}=\frac{19\cdot(9-117)}{2}=\frac{19\cdot(-108)}{2}=\frac{-2052}{2}=-1026[/tex]Hence, the sum of the first 19 terms of the given sequence is -1026.
3. A savings account is started with an initial deposit of $1500.The account earns 1.8% interest compounded annually.(a) Write an equation to represent the amount of money inthe account as a function of time in years. 5 Points(B) how much more interest would be earned if the initial deposit is allowed to earn interest for 20 years vs 10 years
Answers
a) We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
where
A = the total amount in the account at the end of t years
r = interest rate
n = the periodic interval at which it was compounded
P = the principal or initial amount deposited
From the information given,
P = 1500
r = 1.8/100 = 0.018
n = 1 because it is compounded once in a year
Thus, an equation to represent the amount of money in the account as a function of time in years ia
A = 1500(1 + 0.018/1)^1 * t
A = 1500(1.018)^t
B) If t = 20, then
A = 1500(1.018)^20
A = 2143.12
The interest earned would be the total amount - the principal
Interest earned after 20 years = 2143.12 - 1500 = 643.12
If t = 10, then
A = 1500(1.018)^10
A = 1792.95
Interest earned after 10 years = 1792.95 - 1500 = 292.95
Thus, the difference in interest earned between both years is
643.12 - 292.95
= $350.17
In a direct variation, y = -18 when x = -3. Write a direct variation equation that shows therelationship between x and y.Write your answer as an equation with y first, followed by an equals sign.Submit
Answers
The direct variation between y and x has the following
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in tall, and the initial velocity of the ball is 30 ft per sec. The height s of the ball in feet isgiven by the equation s= -2.7t^2 + 30t + 6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b.a. After how many seconds is the ball 18 ft above the moon's surface?After ____ seconds the ball will be 18 ft above the moon's surface.(Round to the nearest hundredth as needed. Use a comma to separate answers as needed.)
Answers
In order to find when the ball will be 18 ft above the moon's surface, we need to equal the expression to 18
[tex]18=-2.7t^2+30t+6.5[/tex]then, solve the associated quadratic expression
[tex]\begin{gathered} 0=-2.7t^2+30t+6.5-18 \\ 0=-2.7t^2+30-11.5 \\ using\text{ }the\text{ }quadratic\text{ }formula \\ x=\frac{-30\pm\sqrt{(30)^2-4\ast(-2.7)\ast(-11.5)}}{2\ast(-2.7)} \\ x_1\cong0.40 \\ x_2\cong10.72 \end{gathered}[/tex]answer:
after 0.40 seconds the ball will be 18 ft above the surface
What is the perimeter of the dinning room? Perimeter is distance around the room, rounded to the nearest hundredth
Answers
To answer this question, we will use the following formula to determine the perimeter of the dining room:
[tex]P=2w+2l,[/tex]where w is the width and l is the length.
Substituting w=9 feet and l=10feet 8 inches=, we get:
[tex]P=2(9ft)+2(10ft8in)=18ft+2(10ft+\frac{8}{12}ft)\text{.}[/tex]Simplifying the above result, we get:
[tex]P=18ft+20ft+\frac{16}{12}ft=38ft+\frac{16}{12}ft=\frac{118}{3}ft\text{.}[/tex]Answer: The perimeter is 39.33ft.
Write in descending order.420t + 201 to the 3rd power -210t to the 2nd power
Answers
To answer this, we need to see the polynomial. Descending order is in a way that the first term of the polynomial will be three, the second (in descending order, two....and so on).
420t+20t3-210t2
In descending order is:
20t^3 - 210t^2 + 420t
So, the option is number two.
Barry spent 1/5 of his monthly salary for rent and 1/7 of his monthly salary for his utility bill. If $1012 was left, what was his monthly salary?
Answers
Given:
1/5 of Barry's salary was going for his rent.
1/7 of Barry's salary was going for his utility bill.
1012 dollars was left after all the payments.
Required:
What was his monthly salary?
Explanation:
Let us assume that Barry's monthly salary is 'x'
So the sum of his payments and the balance amount will give us his total salary.
[tex]total\text{ }salary=rent\text{ }payment+utility\text{ }payment+money\text{ }left[/tex]Now Barry uses 1/5 of his salary in rent, that is
[tex]\begin{gathered} rent\text{ }payment=\frac{1}{5}\times his\text{ }total\text{ }salary \\ \\ rent\text{ }payment=\frac{1}{5}\times x \end{gathered}[/tex]Barry uses 1/7 of his salary in utility bill, that is
[tex]\begin{gathered} utility\text{ }bill=\frac{1}{7}\times his\text{ }total\text{ }salary \\ \\ utility\text{ }bill=\frac{1}{7}\times x \end{gathered}[/tex]And after all the payments the money he is left with is 1012 dollars.
[tex]money\text{ }left=1012[/tex]Now let's calculate his total salary
[tex]\begin{gathered} total\text{ }salary=rent\text{ }payment+utility\text{ }bill+money\text{ }left \\ \\ x=\frac{1}{5}\times x+\frac{1}{7}\times x+1012 \\ \\ x=\frac{x}{5}+\frac{x}{7}+1012 \\ \\ x=\frac{7x+5x}{35}+1012 \end{gathered}[/tex]Simplifying it further we get
[tex]\begin{gathered} x=\frac{12x}{35}+1012 \\ \\ x-\frac{12x}{35}=1012 \\ \\ \frac{35x-12x}{35}=1012 \\ \\ \frac{23x}{35}=1012 \end{gathered}[/tex][tex]\begin{gathered} 23x=1012\times35 \\ \\ 23x=35420 \\ \\ x=\frac{35420}{23} \\ \\ x=1540 \end{gathered}[/tex]x = 1540 dollars
Final Answer:
Barry's monthly salary is 1540 dollars.
if a=5x-2 and b=5x-22 , what is the value of x ?
Answers
Trigonometry
We are given the following condition:
sin (a) = cos (b)
Since both angles are acute, the following relationship must apply:
a = 90° - b
Both angles must be complementary
Substituting the values for each angle:
a = 5x - 2
b = 5x - 22
We have:
5x - 2 = 90 - (5x - 22)
Removing brackets:
5x - 2 = 90 - 5x + 22
Adding 5x:
5x - 2 + 5x = 90 + 22
Adding 2:
5x + 5x = 90 + 22 + 2
Simplifying:
10x = 114
Dividing by 10:
x = 114/10
x = 11.4
Correct choice: C)
Suppose that the functions g and h are defined for all real numbers x as follows. 9g(x) = 2x ^ 2 h(x) = x - 3Write the expressions for (hg)(x) and (h + g)(x) and evaluate (h - g)(- 3) .
Answers
Given
[tex]\begin{gathered} g(x)=2x^2 \\ h(x)=x-3 \end{gathered}[/tex]To write the expressions of
[tex]\begin{gathered} (h\cdot g)(x) \\ (h+g)(x) \end{gathered}[/tex]And to evaluate,
[tex](h-g)(-3)[/tex]Explanation:
It is given that,
[tex]\begin{gathered} g(x)=2x^2 \\ h(x)=x-3 \end{gathered}[/tex]Then,
[tex]\begin{gathered} (h\cdot g)(x)=h(x)\cdot g(x) \\ =\left(x-3\right)\cdot\left(2x^2\right) \\ =2x^3-6x^2 \end{gathered}[/tex]Also,
[tex]\begin{gathered} (h+g)(x)=h(x)+g(x) \\ =(x-3)+2x^2 \\ =2x^2+x-3 \end{gathered}[/tex]And,
[tex]\begin{gathered} (h-g)(-3)=h(-3)-g(-3) \\ =(-3-3)-2(-3)^2 \\ =-6-(2\times9) \\ =-6-18 \\ =-24 \end{gathered}[/tex]Hence, the answer is,
[tex]\begin{gathered} (h\cdot g)(x)=2x^3-6x^2 \\ (h+g)(x)=2x^2+x-3 \\ (h-g)(-3)=-24 \end{gathered}[/tex]which statement is true if the graph of the linear function passes through the points (-1, -6)and (5,6) function first if needed
Answers
The correct option is C
Explanation:We check through each of the options to see if they are true
Option A is not true
The slope of the graph is as follows:
(6 - (-6))/((5 - (-1))
= (6 + 6)/(5 + 1)
= 12/6
= 2
Option B is not true
The zero of the graph is the point on the x-axis where y = 0, this is x = 2
Option C is true
The x-intercept is the point where the graph crosses the x-axis. This is (2, 0)
Option D is not true
6x-(2x+5) need help please
Answers
we have the expression
6x-(2x+5)
remove the parenthesis
6x-2x-5
Combine like terms
4x-5
therefore
the answer is 4x-5Here is a system of linear equations: Which would be more helpful for solving the system: adding the two equations or subtracting one from the other? Explain your reasoning. Solve the system without graphing. Show your work.
Answers
Okay, here we have this:
Considering the provided system we obtain the following:
The option more helpful for solving the system is add one equation to the other because in this way we can cancel the term of the "y", if we solve the system we obtain the following:
[tex]\begin{bmatrix}2x+\frac{1}{2}y=7 \\ 6x-\frac{1}{2}y=5\end{bmatrix}[/tex]Adding the equations:
[tex]\begin{gathered} 8x=12 \\ x=\frac{12}{8} \\ x=\frac{3}{2} \end{gathered}[/tex]Now, let's replacing in the first equation with x=3/2:
[tex]\begin{gathered} 2(\frac{3}{2})+\frac{1}{2}y=7 \\ 3+\frac{1}{2}y=7 \\ \frac{y}{2}=4 \\ y=8 \end{gathered}[/tex]Finally we obtain that the solution to the system is x=3/2 and y=8.
you are pouring canned soda into a cylinder cylinder that is 12 cm tall and a diameter of 6.5 cm The picture is 36 cm tall and has a diameter of 20 cm how many cans of soda will the picture hold
Answers
We are going to assume that the picture of 36 tall and has a diameter of 20 cm is also a cylinder.
To answer this question, we need to know the formula to find the volume of a cylinder:
[tex]V_{\text{cylinder}}=\pi\cdot r^2\cdot h[/tex]Where
• r is the radius of the base of the cylinder.
,• h is the height of the cylinder.
,• pi = 3.14159265358979...
From the question, we have:
The dimensions of the first cylinder are:
h = 12cm
D = 6.5cm.
Since the radius of a circle is half of its diameter, then, we have that the radius of this cylinder is 6.5cm/2 = 3.25cm.
Then, r = 3.25cm.
Then, the volume of this cylinder is:
[tex]V_{\text{cylinder}}=\pi\cdot(3.25\operatorname{cm})^2\cdot12\operatorname{cm}=\pi\cdot10.5625\operatorname{cm}\cdot12\operatorname{cm}=126.75\pi cm^3[/tex]Now, we need to find the volume of the cylinder of the picture following the same procedure:
h = 36cm
D = 20cm ---> r = D/2 ---> r = 20cm/2 ---> r = 10cm
[tex]V_{\text{cylinderpicture}}=\pi\cdot(10\operatorname{cm})^2\cdot36\operatorname{cm}=\pi\cdot100\operatorname{cm}^2\cdot36\operatorname{cm}[/tex]Then, we have that the volume of the cylinder of the picture is:
[tex]V_{\text{cylinderpicture}}=3600\pi cm^3[/tex]Thus, we have that we poured a canned soda into a cylinder of 147pi cm^3. How many cans of soda will hold the cylinder of the picture? We need to divide the total volume of the cylinder of the picture by the volume of the first cylinder (the one which contains the canned soda). Then, we have:
[tex]N_{\text{cannedsoda}}=\frac{V_{\text{cylinderpicture}}}{V_{\text{cylinder}}}=\frac{3600\pi cm^3}{126.75\pi cm^3}\Rightarrow N_{cannedsoda}=28.402367[/tex]Therefore, the cylinder of the picture will hold about 28.40 canned sodas.
Part 1Carson is g year old Haley is 2 yrs younger than Carson. find the sum of their ages in terms of gPart 2Find some of their ages in "g" years time, in terms of g
Answers
Part 1
Carson is "g" years old.
Haley is 2 years younger than Carson, you can express her age as "g-2"
To sum their ages you have to add both expressions:
[tex]\begin{gathered} \text{AgeCarson}+\text{AgeHaley} \\ g+(g-2) \end{gathered}[/tex]To simplify the expression, you have to erase the parentheses and add the like terms, i.e., add both "g-terms"
[tex]\begin{gathered} g+g-2 \\ 2g-2 \end{gathered}[/tex]The sum of their ages in terms of g is: Age(g)=2g-2
Part 2
You need to find some of their ages, this means that you have to choose any value for "g" and determine the age of Carson and Haley
For example:
For g=10 years:
Carson's age: g= 10 years-old
Haley's age: g-2=10-2= 8 years-old
The sum of their ages is: 2g-2=(2*10)-2= 20-2= 18 years
For g=15 years:
Carson's age: g= 15 years-old
Haley's age: g-2= 15-2= 13 years-old
The sum of their ages is: 2g-2= (2*15)-2= 30-2= 28 years
I need help please Question 9 Help for my homework
Answers
Given the figure of a triangular prism.
We will find the amount of wood to make the wooden play block
So, we will find the volume of the given block
As shown: the triangular side has a base of 4 cm and a height of 6 cm
The area of the triangular base =
[tex]\frac{1}{2}*4*6=12\text{ }cm^2[/tex]the length between the triangular sides = 12 cm
So, the volume = base area * length =
[tex]12*12=144\text{ }cm^3[/tex]So, the answer will be the first option 144 cm³
Help Please!!use the drawing to form the correct answers on the graph complete the function table for the given domain and plot the points on the graph
Answers
The Solution:
The given function is
[tex]f(x)=-x^2+2x+5[/tex]Step 1:
We shall complete the table.
Explanation of how the table was completed:
Substituting each value of x to obtain the corresponding value of y.
[tex]\begin{gathered} f(-1)=-(-1)^2+2(-1)+5=-1-2+5=2 \\ f(0)=-(0)^2+2(0)+5=5 \\ f(1)=-(1)^2+2(1)+5=-1+2+5=6 \\ f(2)=-(2)^2+2(2)+5=-4+4+5=5 \\ f(3)=-(3)^2+2(3)+5=-9+6+5=2 \end{gathered}[/tex]If each side of an equilateral triangle is 2 inches long, then what is the area of the triangle?
Answers
Solution:
The image below represents the equilateral triangle of 2 inches long
From the triangle above, the given values include
[tex]\begin{gathered} a=2in \\ b=2in \\ c=2in \end{gathered}[/tex]Concept:
To calculate the area of the triangle, we will use Heron's formula below
[tex]\begin{gathered} A=\sqrt[]{s(s-a)(s-b)(s-c)} \\ \text{where,s = semi perimter} \\ s=\frac{a+b+c}{2} \end{gathered}[/tex]Step 1:
Calculate the semi perimeter s
[tex]\begin{gathered} s=\frac{a+b+c}{2} \\ s=\frac{2in+2in+2in}{2} \\ s=\frac{6in}{2} \\ s=3in \end{gathered}[/tex]Step 2:
Substitute the value of s,a,b,c in the heron's formula
[tex]\begin{gathered} A=\sqrt[]{s(s-a)(s-b)(s-c)} \\ A=\sqrt[]{3(3-2)(3-2)(3-2)} \\ A=\sqrt[]{3\times1\times1\times1} \\ A=\sqrt[]{3} \\ A=1.73in^2 \end{gathered}[/tex]Hence,
The area of the triangle = 1.73 squared inches
1. At first street elementary school, about 21% of the 645 students ride bicycles to school. About how many students ride bicycles to school? 2. A team of biologists captured and tagged 50 deer in a forest. Two weeks later, the biologists captured a sample of 20 deer from the same forest, and found that 5 of them were tagged. How many deer would they estimate are in the forest.
Answers
1 Given that about 21% of the 645 students ride bicycles to school
The number of students that ride bicycles to school
= 21% * 645
= 21/100 * 645
= 135.45
Hence about 135 students ride bicycles to school.
Which is not a true equation?O A. -12 · 4 = -3O B. 100 = -25 = -4O C. -72 = -9 = 80 D. –32 - 0 = 32
Answers
In the last option:
-32 / 0 = 32
But we can not divide by 0, it is undefined in mathematics, so this is not a true equation.
Answer: Option D
differentiate y=4x√3x²-8x
Answers
Okay, here we have this:
Considering the provided function, we are going to perform the requested operation, so we obtain the following:
[tex]\begin{gathered} y=4x\sqrt{3}x^2-8x \\ \\ y=4\sqrt{3}x^3-8x \\ \\ \frac{dy}{dx}=\frac{d}{dx}(4\sqrt{3}x^3)-\frac{d}{dx}(8x) \\ \\ \frac{dy}{dx}=12\sqrt{3}x^2-8 \end{gathered}[/tex]Finally we obtain that dy/dx is equal to: 12sqrt(3)x^2-8
Finding zeros of the function -x^3+2x^2+5x-6
Answers
SOLUTION:
Step 1:
In this question, we are meant to find the zeros of the function:
[tex]x^3+2x^2+\text{ 5 x -6}[/tex]Step 2:
The details of the solution are as follows:
The graph solution of this function is as follows:
CONCLUSION:
The only real zero of the function:
[tex]x^3+2x+5x\text{ - 6}[/tex]is at:
[tex]x\text{ = 0. 82 ( 2 decimal places)}[/tex]State the solution in terms of x 4^x+6 = 20
Answers
We have the question as
[tex]4^{x+6}=20[/tex]Let us introduce logarithms to base 4 to both sides of the equation:
[tex]\log _44^{x+6}=\log _420[/tex]Applying the law of logarithm that states
[tex]\log A^B=B\log A[/tex]we have
[tex](x+6)\log _44=\log _420[/tex]Applying the law that states
[tex]\log _nn=1[/tex]we have
[tex]\begin{gathered} (x+6)\times1=\log _420 \\ x+6=\log _420 \end{gathered}[/tex]Collecting like terms, we have
[tex]x=-6+\log _420[/tex]Therefore, the answer is OPTION C.
Where would 5pi be located on a number line? Show all thoguhts.
Answers
In order to locate 5π in a number line, you consider that π = 3.141516...
When this irrational number is multiplied by 5 you obtain:
5 x π = 5 x 3.141516... = 15.70796...
Then, if you have a number line with ten subdivisions between units, the position of 5π on the number line can be as follow:
Given:Circle B with tangent AD and tangent DC. Arc AC has a measure of 85. What is the relationship between m
Answers
Answer:
They are supplementary
Explanation:
If AD is tangent to circle B, then the measure of ∠BAD is 90°. In the same way, if DC is tangent to circle B, the measure of ∠DCB is 90°.
So, we can complete the graph as:
Then, the sum of the interior angles of a quadrilateral is 360°, so we can calculate the m∠ADC as:
m∠ADC = 360 - 90 - 90 - 85
m∠ADC = 95°
Now, the sum of m∠ABC and m∠ADC is equal to:
m∠ABC + m∠ADC = 85 + 95 =180
Since the sum is 180, we can say that ∠ABC and ∠ADC are supplementary angles.
Create an expression that can be used to find the value of x
Answers
There are two possible expressions that can help to calculate "x"
First
[tex]\begin{gathered} \text{ cos 28 = }\frac{42}{x} \\ \text{ } \end{gathered}[/tex]Second
[tex]\text{ sec 28 = }\frac{x}{42}[/tex]Both are possible to find "x".
46. Identify the center and radius of a circle given the equation is (x - 2)^2 + (y + 4)^2= 36
Answers
Answer: Center: (2, –4); Radius: 6.
Explanation
The equation of a circle in standard form is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]where (h, k) is the center and r is the radius. Thus, in our given equation:
[tex]\left(x-2\right)^2+(y+4)^2=36[/tex]• h = 2
,• k = –4 (it is negative as negative sign times negative sign equals positive sign)
,• r² = 36
Therefore, the center is (2, –4) and the radius is:
[tex]r^2=36[/tex][tex]\sqrt{r^2}=\sqrt{36}[/tex][tex]r=6[/tex]guys please help
60% of = 45
Answers
Answer:
Step-by-step explanation:
Answer: 75
Use the equation is/of = %/100
Plug in the numbers to get 45/x = 60/100
Cross Multiply and you get 60x = 4500
Divide both sides by 60
X = 75.