Answers
In this case, we have an isosceles triangle, in this kind of figures the height (segment that goes from the vertex E to the base) bisects the upper angle, then the angle
[tex]m=\frac{50}{2}=25[/tex]Then, the measure of the upper angle of the triangle formed to the left equals 25°, the height of the triangle forms a right angle with the base of the triangle, then the measure of the angle on the right (next to y°) equals 90°. The sum of the internal angles of a triangle always equals 180°, then we can formulate the following expression:
x° + 25° + 90° = 180°
x° + 115° = 180°
x° + 115° - 115° = 180° - 115°
x° = 65°
Then x° equals 65°
As mentioned, the height forms a right angle with the base of the triangle, then the measure of the angle y° equals 90°
The length of the side LN equals twice the length of the base of the left triangle, then we get:
LN = 2*7 = 14
Then, the length of LN equals 14 cm
Related Questions
Given that: 100 = 2^2 * 5^2, how is 400 written as a product of its prime factors?
Answers
Answer:
400 written as a product of it's prime factors is 2^4 * 5²
Step-by-step explanation:
We have to factore the number, dividing by prime factors(2, 3, 5, 7, ...)
400|2
200|2
100
We already have the factorization of 100. So
400 = 2²*100 = 2²*2²*5² = 2^4 * 5²
400 written as a product of it's prime factors is 2^4 * 5²
2^2*10^2=400
2^2=4
10^10=100
4*100=400
You are going to paint your door on the outside. Your door is 7 feet 2 inches tall and 32inches wide. You need to know the surface area of the front of your door to determine howmuch paint to buy. The hardware store sells paint by how much covers a square foot. What isthe surface area you should report to the hardware store?
Answers
Data
height = 7 ft 2 in
width = 32 in
1.- Convert height into inches
1 ft ------------ 12 in
7 ft ------------ x
x = 84 in
total height = 84 + 2
= 86 in
2.- Calculate the area
Area = height x width
Area = 84 x 32
Area = 2688 in 2
If AABC = ADEC,ZB = 44º and ZE = 4xx= [?]
Answers
Solution
Given that Triangle, ABC is congruent to Triangle DEC
=> ∠A = ∠D; ∠B = ∠E; ∠C = ∠C
Given that ∠B = 44, ∠E = 4x
=> 44 = 4x
=>x = 44/4 = 11
Hence, x = 11
The product of two whole numbers is 592 and their sum is 53. What are the two numbers?
Answers
To solve this problem, we have to build two equations with the given information. Using x and y to represent the two numbers:
• Equation 1
[tex]x\times y=592[/tex]• Equation 2
[tex]x+y=53[/tex]Now that we have to equations, we have to isolate one variable from one equation and replace it in the other.
[tex]x=53-y[/tex]Then, we will replace this value of x in Equation 1:
[tex](53-y)\cdot y=592[/tex]Solving for y we get:
[tex]53y-y^2=592[/tex][tex]-y^2+53y-592=0[/tex]As we got this expression, we will have to use the General Quadratic Formula. With the help of a calculator, we get both values:
[tex]y_1=16[/tex][tex]y_2=37[/tex]Finally, we have to replace these values in Equation 1 to evaluate which meets the condition:
[tex]x_1=\frac{592}{y_1}[/tex][tex]x_1=\frac{592}{16}=37[/tex][tex]x_2=\frac{592}{y_2}[/tex][tex]x_2=\frac{592}{37_{}}=16[/tex]We have to evaluate the values in each equation:
[tex]\begin{gathered} 37+16=53 \\ 53=53 \end{gathered}[/tex][tex]37\cdot16=592[/tex]The first numbers meet the condition.
Answer: 37 and 16
Write the equation in slope-intercept form through the point (2, -1) and is perpendicular to the line y = -5x + 1 and graph.
Answers
First, we are going to calculate the perpendicular slope. The condition for perpendicular lines is the following:
[tex]m1m2=-1[/tex]First, m1 = -5
[tex]m2=\frac{-1}{m1}=\frac{-1}{-5}\rightarrow m2=\frac{1}{5}[/tex]Now, for b
[tex]b=y-m2x[/tex]For the point (2,-1)
[tex]b=-1-\frac{1}{5}\cdot(2)[/tex][tex]b=-\frac{5}{5}-\frac{2}{5}=\frac{-7}{5}[/tex][tex]y=\frac{1}{5}x-\frac{7}{5}[/tex]write a polynomial function in standard form with the given zeros x= -1,-2,-3,-4
Answers
Explanation: For this question we have 4 zeros so x can be as follows
x = -1 or x = -2 or x = -3 or x = -4
We can turn the equalities above into factors as follows
[tex]\begin{gathered} x=-1\rightarrow x+1=0 \\ x=-2\rightarrow x+2=0 \\ x=-3\rightarrow x+3=0 \\ x=-4\rightarrow x+4=0 \end{gathered}[/tex]Step 1: Now that we have the factors we can build a function and simplify it as follows
[tex]\begin{gathered} y=(x+1)(x+2)(x+3)(x+4) \\ y=(x^2+2x+x+2)(x^2+4x+3x+12) \\ y=(x^2+3x+2)(x^2+7x+12) \\ y=x^4+7x^3+12x^2+3x^3+21x^2+36x+2x^2+14x+24 \\ y=x^4+7x^3+3x^3+12x^2+21x^2+2x^2+36x+14x+24 \\ y=x^4+10x^3+35x^2+50x+24 \end{gathered}[/tex]Final answer: So the final answer is
[tex]y=x^4+10x^3+35x^2+50x+24[/tex].
katie has 5.455 apples and sadie has 10.31 how many apples do they have in all
Answers
Katie has 5.455
Sadie has 10.31
To find how many apples they have in all add the two numbers
They have = 5.455 + 10.31
They have = 5.455 + 10.310
0 + 5 = 5
1+ 5 = 6
3 + 4 = 7
10 + 5 = 15
They have = 15.765 apples in all
Triangle A'B'C' is apparently - у А A' B C С B' O A clockwise 90 degree rotation of Triangle ABC O A reflection across the y-axis of Triangle ABC O A translation of Triangle ABC right 7 units O A clockwise 270 degree rotation of Triangle ABC
Answers
Since all coordinates of the transformated triangle are changed like this:
[tex](x,y)\rightarrow(y,-x)[/tex]Triangle A'B'C' is a clockwise 270 degree rotation of triangle ABC
A counterclockwise rotation of 90º is the same that a clockwise rotation of 270º
Determine the height of the ball after 4 seconds *Height of Ball over Time160144128112Height (in feet)96NO643216O1 2 3 4 5 6Time (in seconds)
Answers
80 ft
1) In the graph, we can find out the height after 4 seconds simply locating the point when the x-axis at t=4
2) Hence, after 4 seconds the height of the ball is:
3) Hence, the answer is 80 ft (the blue dot) (4,80)
A. Step 1B. Step 2C. Priya did not make a mistake
Answers
We will have the following:
[tex]\frac{f}{0.25}=16\Rightarrow f=16\cdot0.25[/tex][tex]\Rightarrow f=4[/tex]From this we can see that there was no mistaky on Priya's side. [Option 3]
The line M is parallel to the line y=-2x+2 and goes through the origin. Which of these points is on the line M? (-2,-4)(1,1)(2,-2)(-2,4)
Answers
Answer:
(-2,4)
Explanation:
Two lines are said to be parallel if their slopes are the same.
Comparing the line y =-2x+2 to the slope-intercept form y=mx+b, the slope of the line is -2.
Therefore, the slope of line M that is parallel to it is also - 2.
Since the line M goes through the origin, the y-intercept of line M is 0.
Therefore, the equation of line M is:
[tex]y=-2x[/tex]Therefore, the point which is on line M is the point that satisfies the equation above.
This point is (-2,4).
Check
[tex]\begin{gathered} \text{When }x=-2,y=4 \\ y=-2x \\ 4=-2(-2) \\ 4=4 \end{gathered}[/tex]l A golf ball is hit in the air. The table shown describes y, the height of the ball, in feet, given the time elapsed, x, in seconds, since the time the ball was hit.Based on the information in the table, which statements are true? Select each correct statement.
Answers
Given:
y is the height of the ball in feet
x is the time in seconds
In the given table you can identify the next maximum:
x=3
y=30
The ball has height 0 when it is in the earth so it is hit at second 0 and will be back in the earth at second 6
Then, from the given statements the next are true:
The maximum height of the ball was 30 feetThe ball was in the air for only 6 seconds1 block: 11 houses = 2 blocks : ??? houses
Answers
Determine the probability of being dealt 4 Aecs of cards, from a deck of 52 playing cards, with a replacement.
Answers
Given:
4 Aces of cards from a deck of 5 playing cards.
[tex]\begin{gathered} \text{Probability of drawing 4 Aces }=\frac{4}{52}\times\frac{4}{52}\times\frac{4}{52}\times\frac{4}{52}\times4! \\ \text{Probability of drawing 4 Aces }=\frac{1}{13}\times\frac{1}{13}\times\frac{1}{13}\times\frac{1}{13}\times24 \\ \text{Probability of drawing 4 Aces }=\frac{24}{28561} \end{gathered}[/tex]True or false the function f(x) = -3(x+10)^2 has a minimum
Answers
Notice that:
[tex]\begin{gathered} f^{\prime}(x)=-6(x+10), \\ f^{\prime\prime}(x)=-6. \end{gathered}[/tex]Since for all x, f''(x)<0, by the second derivative criteria we get that f(x) reaches a maximum.
Answer: False.
a cellular phone company charges a base rate of $15.00 per month and $0.05 per minute,m, which equation could be used to find the total monthly charge in dollars,c?
Answers
Suppose you use "m" minutes in a month and each minute is $0.05, so your minute bill would be:
0.05 * m
Per month, there is a fixed rate of $15 , no matter how many minutes you use.
So, that's a fixed cost.
Total monthly charge would be:
15 + 0.05m
The cost, c, is:
[tex]c=0.05m+15[/tex]Correct Answer Choice is Option B
Solve the system of equations.y = x2 - 2y = -2x + 1A. (-3,7) and (-1,3)B. (-3,7) and (1, -1)C. (1.-1) and (3,-5)D. (-1,3) and (3, -5)
Answers
Answer
Option B is correct.
the solutions to the system of equations include
(-3, 7) and (1, -1)
Step-by-step Explanation
The question is to solve the system of equations
y = x² - 2 ..... equation 1
y = -2x + 1 ..... equation 2
To solve this, we can just equate the expression given for y in equation 1 to the expression given for y in equation 2.
y = x² - 2
y = -2x + 1
Since
y = y
x² - 2 = -2x + 1
x² + 2x - 2 - 1 = 0
x² + 2x - 3 = 0
This gives a quadratic equation which we will now solve
x² + 2x - 3 = 0
x² + 3x - x - 3 = 0
x (x + 3) - 1 (x + 3) = 0
(x - 1) (x + 3) = 0
So,
x - 1 = 0 or x + 3 = 0
x = 1 or x = -3
If x = 1,
y = x² - 2
= 1² - 2
= 1 - 2
= -1
x = 1, y = -1
If x = -3
y = x² - 2
= (-3)² - 2
= 9 - 2
= 7
x = -3, y = 7
So, the solutions to the system of equations include
x = -3, y = 7, that is, (-3, 7)
And
x = 1, y = -1, that is, (1, -1)
Hope this Helps!!!
What is this expression in simplest form?
+2
4x² + 5x + 1
Ο Α.
О в.
O C.
O D.
4x + 1
²-4
(x + 1)(x − 2)
-
I
(z = 2)
1
4x + 1
(x + 1)(x-2)
ww
4x+1
#12
Answers
Answer:
[tex] \frac{x + 2}{4 {x}^{2} + 5x + 1 } . \frac{4x + 1}{ {x}^{2} + 4} \\ \frac{x + 2}{4 {x}^{2} + (4 + 1)x + 1 } . \frac{4x + 1}{ {(x + 2)}^{2} } \\ \frac{1}{4 {x}^{2} + 4x + x + 1}. \frac{4x + 1}{x + 2} \\ \frac{1}{x(4x + 1) + 1(4x + 1)} . \frac{4x + 1}{x + 2} \\ \frac{1}{(4x + 1)(x + 1)} . \frac{4x + 1}{x + 2} \\ \frac{1}{(x + 1)}. \frac{1}{(x + 2)} \\ \frac{1}{(x + 1)(x + 2)} [/tex]
A. is the answer!!
The value of 0.36 when converted to a fraction in the simplest form is 9/25.
What is fraction?A fraction represents a part of a whole or, more generally, any number of equal parts. When spoken in everyday English, a fraction describes how many parts of a certain size there are, for example, one-half, eight-fifths, three-quarters.
here, we have,
to calculate fractions in simplest form:
Your information is incomplete. Therefore, an overview will be given. It should be noted that a fraction is in its simplest form when the numerator and denominator are prime.
From example, let's convert 0.36 to a fraction on its simplest form. This will be:
0.36 = 36/100 = 9/25
In conclusion, 0.36 is 9/25 in the simplest form.
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How to do 2 step equations Can you solve 2x + 5=21?
Answers
Given
The equation,
[tex]2x+5=21[/tex]To find the value of x or to solve for x.
Explanation:
It is given that,
The equation is,
[tex]2x+5=21[/tex]That implies,
[tex]\begin{gathered} 2x+5=21 \\ 2x=21-5 \\ 2x=16 \\ x=\frac{16}{2} \\ x=8 \end{gathered}[/tex]Hence, the value of x is 8.
A phone company charges for service according to the formula: C(n) = 19 + 0.08n , where n is the number of minutes talked , and C(n) is the monthly charge, in dollars .The rate of change in this equation is:The initial value in this equation is:
Answers
In a linear equation, the coefficient of the variable is the rate of change and the constant term is the initial value.
For example, a linear function with rate of change m and initial value b is:
[tex]f(x)=mx+b[/tex]In the given formula, the variable is n, its coefficient is 0.08 and the constant term is 19.
Since n is measured in minutes and C is measured in dollars (as well as the initial value), then, the coefficient 0.08 must have the units necessary for the minutes to cancel out, leaving dollars as the unit of 0.08n. Then, the units of the rate of change must be dollars per minute.
Since the constant term is 19, then the initial value is 19.
Therefore, the answers are:
The rate of change in the equation is 0.08 dollars per minute.
The initial value in the equation is 19 dollars.
sec40+ sec20 tan2 0 - 2 tan4 0 =3 sec² 0 -2Sect0-210
Answers
Given:
[tex]sec^4\theta+sec^2\theta tan^2\theta-2tan^4\theta=3sec^2\theta-2[/tex]Required:
We need to prove the given equation.
Explanation:
Consider the left-hand side of the equation.
[tex]Add\text{ and subtract }3tan^4\theta.[/tex][tex]sec^4\theta+sec^2\theta tan^2\theta-2tan^4\theta=sec^4\theta+sec^2\theta tan^2\theta-2tan^4\theta+3tan^4\theta-3tan^4\theta[/tex][tex]=sec^4\theta+sec^2\theta tan^2\theta+tan^4\theta-3tan^4\theta[/tex][tex]Add\text{ and subtract -2}sec^2\theta tan^2\theta.[/tex][tex]=sec^4\theta+sec^2\theta tan^2\theta+tan^4\theta-3tan^4\theta-2sec^2\theta tan^2\theta+2sec^2\theta tan^2\theta[/tex][tex]=sec^4\theta-2sec^2\theta tan^2\theta+tan^4\theta-3tan^4\theta+sec^2\theta tan^2\theta+2sec^2\theta tan^2\theta[/tex][tex]=sec^4\theta-2sec^2\theta tan^2\theta+tan^4\theta-3tan^4\theta+3sec^2\theta tan^2\theta[/tex][tex]Use\text{ }sec^4\theta-2sec^2\theta tan^2\theta+tan^4\theta=(sec^2\theta-tan^2\theta)^2[/tex][tex]=(sec^2\theta-tan^2\theta)^2-3tan^4\theta+3sec^2\theta tan^2\theta[/tex][tex]=(sec^2\theta-tan^2\theta)^2+3tan^2\theta(sec^2\theta-tan^2\theta)[/tex][tex]Use\text{ }sec^2\theta-tan^2\theta=1.[/tex][tex]=1^2+3tan^2\theta(1)[/tex][tex]=1+3tan^2\theta[/tex][tex]Use\text{ }tan^2\theta=sec^2\theta-1.[/tex][tex]=1+3(sec^2\theta-1)[/tex][tex]=1+3sec^2\theta-3[/tex][tex]=3sec^2\theta-2[/tex]We get the right-hand side of the equation.
Final answer:
[tex]sec^4\theta+sec^2\theta tan^2\theta-2tan^4\theta=3sec^2\theta-2[/tex]Justin earned $600 last week fixing computers.Is it possible to determine how many hours Justin worked?explain
Answers
Since Justin earned $600 last week
If we want to find the number of hours that he worked, we must have how much he earned per hour
But we do not have how much did he earn per hour, so
It is impossible to find how many hours did he work from the given information
The answer is
No, it is impossible to find that
A hot air balloon is flying above Groveburg. To the left side of the balloon, the balloonist measure the angle of depressionto the Groveburg soccer fields to be 20° 15'. To the right side of the balloon, the balloonist measures the angle ofdepression to the high school football field to be 62° 30'. The distance between the two athletic complexes is 4 miles.What is the distance from the balloon to the football field?a.b.>3.6 miC.~6.2 mi>2.2midy1.4 miPlease select the best answer from the choices providedOAOBOCOD
Answers
The distance from the balloon to the football field will be 1.4 miles.
Angle of depression to the Grove burg soccer fields = 20° 15'.
Use 1' = 1 / 60° :
15' = 1 / 4 ° = 0.25 °
20° 15' = 20.25°
Angle of depression to the high school football field = 62° 30'.
30' = 0.5°
62° 30' = 62.5°
the distance from the balloon to the football field will be:
Let the distance be a
a / sin a = c / sin c
a / sin (20.25) = 4 / sin (97.5)
a = 4 sin (20.25) / sin (97.5)
a = 1.4 miles.
Therefore, we get that, the distance from the balloon to the football field will be 1.4 miles.
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how do u knwo which way to face the inequality sign in the answer of these questions like 1>x<3 how do u know which way to face them. i put some examples os u cna use them to explain
Answers
Using the graph identify the intervals:
a) Function being less than or equal to 0: In which x interval is the graph under the x-axis (the functions are less than 0 when they are under x-axis)
As the ineqaulity sing is less than or equal to 0, the interval includes those x-values for which the function is 0:
Solution: Interval from x=1 to x=3
[tex]\begin{gathered} x^2-4x+3\leq0 \\ 1\leq x\leq3 \\ \lbrack1,3\rbrack \end{gathered}[/tex]b) Function being greater than or equal to 0: In which x interval is the graph over the x-axis.
As the ineqaulity sing is greater than or equal to 0, the interval includes those x-values for which the function is 0:
Solution: Interval from - infinite to 1 and from 3 to infinite
[tex]\begin{gathered} x^2-4x+3\ge0 \\ 1\ge x\ge3 \\ (-\infty,1\rbrack\cup\lbrack3,\infty) \end{gathered}[/tex]c) Function being greater than 0: In which x interval is the graph over the x-axis.
As the ineqaulity sing is greater than to 0, the interval does not include those x-values for which the function is 0.
[tex]\begin{gathered} x^2-4x+3>0 \\ 1>x>3 \\ (-\infty,1)\cup(3,\infty) \end{gathered}[/tex]d) Function being less than 0: In which x interval is the graph under the x-axis.
As the ineqaulity sing is less than 0, the interval does not include those x-values for which the function is 0:
[tex]\begin{gathered} x^2-4x+3<0 \\ 1find the value of the term in the arithmetic sequence 1,6,11,16...(8th term)
Answers
We need to find the 8th term of the following arithmetic sequence:
[tex]1,6,11,16,...[/tex]The formula to find the n-th term an of aₙ arithmetic sequence is:
[tex]a_n=a_1+(n-1)d[/tex]where a₁ is the first term and d is the difference between two consecutive terms.
The first term of this sequence is a₁ = 1, and d is given by:
[tex]\begin{gathered} d=a_2-a_1 \\ \\ d=6-1 \\ \\ d=5 \end{gathered}[/tex]Then, for n = 8, we obtain:
[tex]\begin{gathered} a_8=1+(8-1)5 \\ \\ a_8=1+7(5) \\ \\ a_8=1+35 \\ \\ a_8=36 \end{gathered}[/tex]Answer:
The 8th term is 36.
Draw the image of the figure under thegiven transformation.6.reflection across the x-axis7. (X,y) - (x - 4, y + 1)8. reflection across the y-axis
Answers
6.
While transformation with the reflection across the x-axis, the absicssa (x-coordinate) remains the same but ordinate (y-coordinate) changes its sign.
The coordinate of point A is (3,0), coordinate of point B is (1,4) and the coordinate of point C is (5,3).
After transformation the, coordinate with the image can be shown as,
Thus, the coordinates of the image after transformation is A'(3,0), B'(1,-4) and C'(5,-3).
Hi, can you help me answer this question please, thank you!
Answers
Given that
[tex]\begin{gathered} \mu_1=sample\text{ of soda in the coke can} \\ \mu_2=sample\text{ of soda in the pepsi can} \end{gathered}[/tex]Therefore, in the first statement, we are to test how accurate the companies package these cans.
Mathematically it can be expressed as,
[tex]H_0\colon\mu_1\leq\mu_2[/tex]In the second statement, we wish to test the claim that the mean of the amount of liquid in coke cans is greater than the amount of liquid in pepsi cans. This can be expressed mathematically as,
[tex]H_a\colon\mu_1>\mu_2[/tex]Hence, the correct option is Option 1.
Find the general solution to dy/dx = 2y passing through the point (5, 1)
Answers
We will have the following:
[tex]\frac{\partial y}{\partial x}=2y\Rightarrow\frac{1}{2y}\partial y=\partial x[/tex][tex]\Rightarrow\int (\frac{1}{2y})\partial y=\int \partial x\Rightarrow\frac{\log (y)}{2}=x+c[/tex]Then we find "c":
[tex]\frac{\log(1)}{2}=5+c\Rightarrow c=-5[/tex]Thus, the general solution passing through (5, 1) is:
[tex]\frac{\log(y)}{2}=x-5[/tex]Write the expression and simplifyThe difference of -10 and the product of p and q
Answers
We start with a subtraction, where we want to subtract the second term from - 10. The second term consists in a multiplication between p and q. Writing this as a mathematical expression we have
[tex]-10-pq[/tex]This expression is already on simplest form.
Determine the independent and dependent quantities in each scenario include when possible Part A: A lamp manufacturing company produces 750 lamps per shift Part B:a grocery store sells pears by the pound. A customer purchases 3 pounds by $5.07
Answers
Here, we want to establish the independent and independent quantities in each of the parts
The independent quantities are simply the quantities that do not depend on the dependent quantity. The dependent quantity are the quantities that depend on the independent quantity
a) Here, we have 750 lamps produced per shift
This is obtained by dividing the number of lamps produced by the number of shifts it took to produce them
In this case, the number of lamps produced is dependent on the number of shifts'
Number of shifts is the independent variable while the number of lamps is the dependent variable
b) Here, the cost per pair is 5.07/3 = 1.69
So here, the cost is dependent on the number of pears
The number of pears is the independent variable while the cost of the pears is the dependent variable