First, let's take a look at the point-slope form of a line:
[tex]y-y_0=m(x-x_0)[/tex]Where:
• m, is the ,slope, of the line
,• (Xo,Yo) ,is a point that belongs to the line
Now, let's calculate the slope of our line with the poins given:
[tex]\begin{gathered} m=\frac{6-(-6)}{-1-5}\rightarrow m=\frac{6+6}{-6}\rightarrow m=\frac{12}{-6} \\ \\ \rightarrow m=-2 \end{gathered}[/tex]Using this slope and point (5,-6), we'll get the equation of our line in the point-slope form.
[tex]y-y_0=m(x-x_0)\rightarrow y-(-6)=-2(x-5)\rightarrow y+6=-2(x-5)[/tex]The equation of the line is the following:
[tex]y+6=-2(x-5)[/tex]13.3x + 8.1 = 74.6 solve for x
Answer:
x = 5
Step-by-step explanation:
1) Get rid of the 8.1
Whenever you are given a question like this you have to try get rid of any other numbers on the side with the x that don't include the x.
We can see that we can first get rid of the 8.1 to do this we have to subtract 8.1 from both sides.
13.3x + 8.1 -8.1 = 13.3x
74.6 - 8.1 =66.5
2) Isolate the x
To get our final value of x you have to divide both sides from 13.3! This is because we were previously left with 13.3x = 66.5 and we can see that you have to multiply 13.3 by x to get 66.5, in return to find x you should have to do the inverse.
66.5 ÷ 13.3 = 5
HINT:
For every question like this you have to do the inverse of whatever you are given. For example, we had to take away 8.1 because in the question it says add!
Hope this helps, have a great day!
Needed help to catch up before summer come any help will be good thank you
We have the following set of inequations
[tex]\begin{cases}y-2<-5{} \\ y-2>{5}\end{cases}[/tex]Let's solve both for y, it will give us
[tex]\begin{cases}y<-5{+2} \\ y>{5}+2\end{cases}\Rightarrow\begin{cases}y<-3 \\ y>7\end{cases}[/tex]Therefore y must be smaller than -3 and bigger than 7, then, the set between -3 and 7 is not part of the solution. the solution in fact is
[tex]S=(-\infty,-3)\cup(7,+\infty)[/tex]Let's do it in the graph!
The solution to the inequations is in blue on the graph.
Find the degree of the polynomial – 3x + x² +3.
The degree of the polynomial is the largest power of the variable
The degree of the polynomial is 2
I don’t know if I’m right I need to know
ANSWER
[tex]x=3[/tex]EXPLANATION
We want to identify the positive solution to the graph.
The solutions to a quadratic graph are the points where the graph touches the x-axis on the coordinate plane. The positive solution to the graph is the point where the graph touches the positive x-axis.
Hence, the positive solution to the given graph is x = 3.
3 x 1 + 4 x 1/100 + 7 x 1/1000 as a decimal number
Answer:
3.047
Step-by-step explanation
Find the value of 2[3(x2 – 5) + 5y] when x = 9 and y = 3.
Answer
The value of the expression is 486
Step-by-step explanation
Given the expression
2[3(x^2 - 5) + 5y]
To solve this, we will be applying the PEMDAS rule
Where x = 9 and y = 3
Step 1: solve the smaller parenthesis first
2[3(9^2 - 5) + 5*3]
2 [ 3(81 - 5) + 15]
2 [ 3(76) + 15]
2 [ 228 + 15]
Solve the larger parenthesis
2 [ 243] = 486
Hence, the value of the expression is 486
the circle graph shown above represents the distribution of the grades of 40 students in a certain geometry class. How many students received Bs or Cs?
Given:
Total number of students = 40
From the circle graph given, let's determine the number of students that received Bs or Cs.
Given:
Percentage of students that received Bs = 30%
Percentage of students that received Cs = 40%
Percentage of student that received Bs or Cs = 40% + 30% = 70%
Thus, to find the number of students who received Bs or Cs, we have the equation below:
No of students who received Bs or Cs = (% of students who received Bs or Cs) x (Total n0 of students)
[tex]\text{ No of student who received Bs or Cs = 70\% of 40}[/tex]Thus, we have:
[tex]\begin{gathered} \text{ No of students who received Bs or Cs = }\frac{70}{100}\ast40 \\ \\ =0.70\ast40 \\ \\ =28 \end{gathered}[/tex]Therefore, the number of students who received Bs or Cs are 28
ANSWER:
C. 28
Fill out the blank to make the given table a probability distribution.
Answer:
[tex]0.06[/tex]Explanation:
Here, we want to fill out the blank
For us to have a probability distribution, the sum of the individual probabilities should be one
Mathematically, for us to get the value of the blank, we have to subtract the sum of the probabilities from 1. This is because the value of the area under the probability distribution is 1 square unit
Thus,we have it that:
[tex]\begin{gathered} P(-1)\text{ = 1 - (0.11 + 0.25 + 0.36 + 0.18 + 0.04)} \\ P(-1)\text{ = 0.06} \end{gathered}[/tex]Which is not a correct description of the graph below? nh -2TT -TK 2TT The graph of y = cos & shifted to the left by 34 units. Зл 2 The graph of y = sin e shifted to the left by n units. O y = sin(0 + 21) = O y = cos(0+ y = 3 Зл 2
Verify each statement
N 1 -----> is true
because
y=cosx , shifted to the left by 3pi/2 is y=cos(x+3pi/2)
N 2 ----> is false
N 3 -----> is true
N4 ----> is true
therefore
the answer is option N 2Which functions are inverses of each other?a. Both Pair 1 and Pair 2b. Pair 1 onlyc. Pair 2 onlyd. neither Pair 1 nor Pair 2
Solution
For pair 1
[tex]\begin{gathered} f(x)=2x-6,g(x)=\frac{x}{2}+3 \\ \mathrm{A\: function\: g\: is\: the\: inverse\: of\: function\: f\: if\: for}\: y=f\mleft(x\mright),\: \: x=g\mleft(y\mright)\: \end{gathered}[/tex][tex]\begin{gathered} f(x)=2x-6 \\ f(x)=y \\ y=2x-6 \\ x=2y-6 \\ x+6=2y \\ \text{divide both side by 2} \\ \frac{x+6}{2}=\frac{2y}{2}_{} \\ y=\frac{x}{2}+3 \end{gathered}[/tex]They are inverse of each other
For pair 2
[tex]\begin{gathered} f(x)=7x,g(x)=-7x \\ \text{Inverse of f(x) = x/7} \end{gathered}[/tex][tex]\begin{gathered} f(x)=7x \\ y=7x \\ x=7y \\ y=\frac{x}{7} \end{gathered}[/tex]They are not inverse of each other
Therefore only pair 1 are inverse of each other
Hence the correct answer is Option B
for a school science project, john noted the temperature at the same time every day for 1 week the high temperature for the week was 27 Fahrenheit and the low temperature for the week was -3 Fahrenheit what is the difference between the high and low temperatures down recorded
To answer the question we shall use a number line that begins with zero and moves in the right direction for positive values and then towards the left direction for negative values.
The high temperature recorded was 27 (positive). The low temperature was -3 (negative). The difference therefore is, 30. That is 27 to the right and from zero to the left, 3, altogether the difference is 30 on the number line.
This can better yet be expressed as follows;
[tex]\begin{gathered} \text{Difference}=27-\lbrack-3\rbrack \\ \text{Difference}=27+3 \\ \text{Difference}=30 \end{gathered}[/tex]Find an equation of variation in which y varies directly as x and y=28 when x=7. Then find the value of y when x=16.
are the triangles similar? if so what is the scale factor?
a) Yes, The scale factor is 3/2
Explanation
Step 1
to check if the triangles are similar, we need to prove that the ratios of the longest side and one sideof the triangle are similar
so
let
[tex]ratio=\frac{longest\text{ side}}{side}[/tex]hence
[tex]\begin{gathered} ratio_1=\frac{8}{5}=1.6 \\ ratio_2=\frac{12}{7.5}=1.6 \end{gathered}[/tex]therefore, the triangles are similar
Step 2
now, to find the scale factor we use the formula
[tex]scale\text{ factor =}\frac{final\text{ length }}{original\text{ length}}[/tex]so, let's take the longest side on each triangle
[tex]\begin{gathered} final\text{ length=12} \\ original\text{ length=8} \end{gathered}[/tex]replace and calculate
[tex]\begin{gathered} scale\text{ factor =}\frac{final\text{ length }}{original\text{ length}} \\ scale\text{ factor =}\frac{12}{8}=\frac{3}{2} \end{gathered}[/tex]therefore, the answer is
a) Yes, The scale factor is 3/2
I hope this helps you
May I please get help finding this. I can’t seem to get the correct solution for the length.
Triangle ABE is similar to traingle ACD; in similar triangles, corresponding sides are always in the same ratio:
[tex]\frac{DC}{EB}=\frac{AC}{AB}[/tex]Use the equation above to find the length of x:
[tex]\begin{gathered} \frac{x}{4}=\frac{6+9}{6} \\ \\ \frac{x}{4}=\frac{15}{6} \\ \\ x=4\cdot\frac{15}{6} \\ \\ x=\frac{60}{6} \\ \\ x=10 \end{gathered}[/tex]Then, the length of x is 10In a group of 60 students, the probability that at most 30 of them like to swimis 56%. What is the probability that at least 31 of them like to swim?
Answer= 44%
P(A)= the probability that at most 30 of them like to swim
P(B)= the probability that at least 31 of them like to swim
Notice that P(A)+P(B) have to add up 100%
P(A)+P(B)=100% then solving for P(B)
P(B)= 100% - 56%= 44%
factor as the product of two binomial x^2+3x+2= _____
We are given the trinomial
[tex]x^2+3x+2[/tex]We can factor it as the product two binomials as
[tex](x+a)(x+b)[/tex]Where
a and b are two numbers that has
• a product of 2
,• a sum of 3
So, which two numbers multiplied gives us "2" and added gives us "3"?
It is "+2" and "+1".
Thus, we can factor the trinomial as:
[tex]\begin{gathered} x^2+3x+2 \\ =(x+2)(x+1) \end{gathered}[/tex]Graph x + 4y = 8The y-intercept is ___ (I got this already its 8)
Answer
The y-intercept = 2
Explanation
The slope and y-intercept form of the equation of a straight line is given as
y = mx + b
where
y = y-coordinate of a point on the line.
m = slope of the line.
x = x-coordinate of the point on the line whose y-coordinate is y.
b = y-intercept of the line.
So, we just have to write the given equation in this form and the y-intercept will become apparent.
x + 4y = 8
4y = -x + 8
Divide through by 4
(4y/4) = (-x/4) + (8/4)
y = -0.25x + 2
Comparing this with y = mx + b
We can see that
b = y-intercept = 2
Hope this Helps!!!
what is x? how would i find the value of
Given the Right Triangle ABC, you know that:
[tex]\begin{gathered} AB=29 \\ BC=9 \end{gathered}[/tex]In order to find the measure of the angle "x", you need to use the following Inverse Trigonometry Function:
[tex]\theta=sin^{-1}(\frac{opposite}{hypotenuse})[/tex]In this case, you can identify that:
[tex]\begin{gathered} \theta=x \\ opposite=BC=9 \\ hypotenuse=AB=29 \end{gathered}[/tex]Therefore, when you substitute values and evaluate, you get:
[tex]x=sin^{-1}(\frac{9}{29})[/tex][tex]x\approx18\text{\degree}[/tex]Hence, the answer is:
[tex]x\approx18\text{\degree}[/tex]Which of the following statements are true of this equation select all that apply. 5 1/6 ÷ 2 5/12 = 2 4/29
The left hand side of the equation is equal to right hand side.
What is an equation? What is a coefficient?An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values. In a equation say : ax + b, [a] is called coefficient of [x] and [b] is independent of [x] and hence is called constant.
We have a equation :
5 1/6 ÷ 2 5/12 = 2 4/29
We can write -
5 1/6 ÷ 2 5/12 = 2 4/29
31/6 ÷ 29/12 = 62/29
31/6 x 12/29 = 62/29
62/29 = 62/29
Therefore, the left hand side of the equation is equal to right hand side.
To solve more questions on equation solving, visit the link below-
brainly.com/question/18067015
#SPJ1
List all possible rational zeros for the function. (Enter your answers as a comma-separated list.)f(x) = 2x3 + 3x2 − 8x + 5
We will list all the possible rational zeros for the polynomial
[tex]f(x)=2x^3+3x^2-8x+5[/tex]to find it we will apply the Rational root theorem. It states that each rational zero(s) of a polynomial with integers coefficients is of the form
[tex]\frac{p}{q}[/tex]where:
* p is a factor of the coefficient of the zero order term in the polynomial ( in our case this coefficient is 5)
* q is a factor of the leading coefficient , that is the coefficient that multiply the variable to the biggest power (in our case that coefficient is 2)
* p and q are relative primes, that is , they does not have common factors.
Finding the possibilities for rational roots:
Just summarizing the information until now, we have:
[tex]p=5\text{ and q=2}[/tex]
we also have that:
[tex]factors\text{ of 5= \textbraceleft1,5,-1,-5\textbraceright}[/tex]and
[tex]factors\text{ of 2 = \textbraceleft1,-1,2,-2\textbraceright}[/tex]So, on the right of the equations above, we have all the possible values that can take p and q, respectively. It only rests to construct all the possibilities, we do
The table shows conversions of common units of capacity.Units of CapacityCustomary System UnitsMetric System Units1 gallon3.79 liters1 quart0.95 liters1 pint0.473 liters1 cup0.237 litersApproximately how many centiliters are in 3 quarts? Round answer to the nearest unit.
Given data:
The value o 1 quart is 1 quart=0.95 liters.
Multiply the above expression with 3 on both sides.
3(1 quart)=3(0.95 liters)
3 quarts =2.
Question 3 of 5 Shayla spent $260 on 4 chairs. To find out how much she spent on each chair, she did the following work in long division. 15 4) 260 60 0 Did she do the problem correctly? Why or why not?
we know that
To find out how much she spent on each chair
Divide the total cost by the number of chairs
so
[tex]\frac{260}{4}=65[/tex]therefore
She spent on each chair $65
show how the quadratic formula can be used to rewrite : f(x) = 9x^2 - 149x - 234IN FACTORED FORM
To factor the function using the quadratic formula we equate it to zero and solve for x:
[tex]\begin{gathered} 9x^2-149x-234=0 \\ x=\frac{-(-149)\pm\sqrt[]{(-149)^2-4(9)(-234)}}{2(9)} \\ x=\frac{149\pm\sqrt[]{30625}}{18} \\ x=\frac{149\pm175}{18} \\ \text{then} \\ x=\frac{149+175}{18}=18 \\ or \\ x=\frac{149-175}{18}=-\frac{26}{18}=-\frac{13}{9} \end{gathered}[/tex]Now we write the function as:
[tex]f(x)=(x-a)(x-b)[/tex]where a and b are the roots we found above, then we have:
[tex]\begin{gathered} f(x)=(x-18)(x-(-\frac{13}{9})) \\ f(x)=(x-18)(9x+13) \end{gathered}[/tex]Therefore:
[tex]f(x)=(x-18)(9x+13)[/tex]If 12(5r + 6t) = x, then in terms of w, what is 48(30r + 361)?
w=12(5r+6t)
Using distributive property:
w=60r+72t
and
48(30r+36t)=1440r+1728t
Now, let's multiply both sides of w=60r+72t by 24:
24*w=24*(60r+72t)
Using distributive property again:
24w=1440r+1728t
Therefore, 48(30r + 361) is equal to 24w.
Hi I need help solving for each of the sides in this equation.CDABSolve to the nearest hundredth
Length of CD
From the picture, we know two sides and an angle of the triangle CDE. We define the sides and angle:
• a = EC = 440.68,
,• b = ED = 470.43,
,• c = CD = ?,
,• γ = 60° 06' 09''.
From trigonometry, we know that the Law of Cosines states that:
[tex]\begin{gathered} c^2=a^2+b^2-2ab\cdot\cos\gamma, \\ c=\sqrt{a^2+b^2-2ab\cdot\cos\gamma}. \end{gathered}[/tex]Where the angle γ and the sides a, b and c are defined by:
Replacing the values from above in the equation for side c, we get:
[tex]c=\sqrt{(440.68)^2+(470.43)^2-2\cdot440.68\cdot470.43\cdot\cos(60\degree06^{\prime}09^{\prime}^{\prime})}\cong457.10.[/tex]Length of AB
To compute the length of AB, first, we must compute the length of sides AE and EB.
Side EB
From the picture, we see a triangle ECA. Using the data of the picture, we have:
• EC = 440.68,
,• ∠E = 60° 06' 09'',
,• EA = ?,
,• ∠A = ?.
,• ∠C = 97° 17' 42''.
Angles ∠A, ∠E and ∠C are the inner angles of triangle ECA, so they must sum up 180°, so we have:
[tex]\begin{gathered} ∠A+∠E+∠C=180\degree, \\ ∠A=180\degree-∠E-∠C, \\ ∠A=180\degree-60\degree06^{\prime}09^{\prime\prime}-97\degree17^{\prime}42^{\prime\prime}=22°36^{\prime}9^{\prime\prime}. \end{gathered}[/tex]Now, we define the following sides and angles:
• c' = EC = 440.68,
,• γ' = ∠A = 22° 36' 9''
,• a' = EA = ?,
,• α = ∠C = 97° 17' 42''.
Now, from trigonometry, we know that the Law of Sine states that:
Using the equation that relates a' and c', we have:
[tex]\begin{gathered} \frac{a^{\prime}}{\sin\alpha^{\prime}}=\frac{c^{\prime}}{\sin\gamma^{\prime}}, \\ a^{\prime}=c^{\prime}*\frac{\sin\alpha^{\prime}}{\sin\gamma^{\prime}}. \end{gathered}[/tex]Replacing the values from above, we get:
[tex]EA=a^{\prime}=440.68*\frac{\sin(97°17^{\prime}42^{\prime\prime}^)}{\sin(22°36^{\prime}9^{\prime\prime})}[/tex]Side AE
From the picture, we see a triangle EDB. Using the data of the picture, we have:
• b' = ED = 470.43,
,• ∠E = 60° 06' 09'',
,• a' = EB = ?,
,• α' = ∠D = 180° - 87° 20' 24'' = 92° 39' 36'',
,• β' = ∠B = 180° - ∠D - ∠E = 180° - 92° 39' 36'' - 60° 06' 09'' = 27° 14' 15''.
Applying the law of sines, we have that:
[tex]\begin{gathered} \frac{a^{\prime}}{\sin(\alpha^{\prime})}=\frac{b^{\prime}}{\sin(\beta^{\prime})}, \\ EB=a^{\prime}=b^{\prime}*\frac{\sin(\alpha^{\prime})}{\sin(\beta^{\prime})}. \end{gathered}[/tex]Replacing the values from above, we get:
[tex]undefined[/tex]s
Answer
s
Write the equation 4x + 8y = -24 in slope-intercept form. Then graph the equation. O None of the other answers are correct
4x + 8y = - 24
8y = -4x - 24
divide both sides by 8
y = -1/2x - 3
[tex]y\text{ = }\frac{-1}{2}x\text{ - 3}[/tex]Using y = mx + c
To obtain y intercept, make x = 0
so y = -1/2(0) -3
y = -3
(0,-3)
To obtain x intercept, make y = 0
so that 0 = -1/2x -3
1/2x = -3
x = -6
(-6,0)
Taking the points (0,-3) and (-6,0) to plot the graph
[tex]8 \sqrt[5]{11} - 4 \sqrt[5]{11} [/tex]Simplify the expression
mr. emmer gave a test in his chemistry class. the scores were normally distributed with a mean of 82 and a standard deviation of 4. what percent of students would you expect to score between 78 and 36?
Where:
[tex]\begin{gathered} X1=36 \\ X2=78 \\ \mu=82 \\ \sigma=4 \end{gathered}[/tex]So:
[tex]\begin{gathered} P(36\le X\le78)=P(\frac{78-82}{4}\le Z\le\frac{86-82}{4}) \\ P(36\le X\le78)=P(-1\le Z\le1) \\ P(36\le X\le78)=0.6827\approx0.68 \end{gathered}[/tex]As a percentage: 68%
Hi I need help with a couple of questions. It's math algebra
The equation above is the formula of the speed (s) in terms of the distance (d) and the time (t).
For the distance 132 mi
With a speed of 8 miles per hour it takes the next hours:
[tex]\begin{gathered} \\ \text{Solve t:} \\ s\cdot t=d \\ t=\frac{d}{s} \\ \\ t=\frac{132mi}{8\frac{mi}{h}}=16.5h \end{gathered}[/tex]With a speed of 12 miles per hour it takes the next hours:
[tex]t=\frac{132mi}{12\frac{mi}{h}}=11h[/tex]Then, the possible number of hours that take to the kayaker to travel 132 miles is between 11 and 16.5
in a recent survey, 60% of the community favored building a health center in their neighborhood. If 14 citizens are chosen, find the probability that exactly 11 of them favor the building of the health center. Round to the nearest thousandth.
Answer:
0.085
Explanation:
To find the probability, we will use the binomial distribution because there are n identical events ( 14 citizens), with a probability of success (p = 60%). Then, the probability can be calculated as:
[tex]P(x)=\text{nCx}\cdot p^x\cdot(1-p)^{n-x}[/tex]Where nCx is equal to
[tex]\text{nCx}=\frac{n!}{x!(n-x)!}[/tex]So, to find the probability that exactly 11 of them favor the building of the health center, we need to replace x = 11, n = 14, and p = 0.6
[tex]14C11=\frac{14!}{11!(14-11)!}=\frac{14!}{11!(3!)}=364[/tex][tex]\begin{gathered} P(11)=364(0.6)^{11}(1-0.6)^{14-11} \\ P(11)=0.085 \end{gathered}[/tex]Therefore, the probability that exactly 11 of them favor the building of the health center is 0.085