A real-world example that can demonstrate the relationship between the variables temperature and volume is, for example, when we inflate a balloon for a party.
- First, we fill the ballon with a gas (air).
- Second, if we tie the balloon and heat it with some source of heat, we will see that the ballon begins to increase in volume.
So, as we increase the temperature of the gas inside the ballon, the balloon increases in volume.
This happens because temperature and volume are variables directly proportional through the Ideal Gas Law, whose formula is:
[tex]P\mathrm{}V=n\mathrm{}R\mathrm{}T[/tex]In the formula:
P is the pressure of the gas.
V is the volume of the gas.
n is the number of moles.
R is the constant of the gases.
T is the temperature of the gas.
what is the logic behind drawing lewis fomrulas for like harder and weird compounds like how can you figure it out easy.harder compounds like ch3och3
Answer:
The logic behind drawing Lewis formulas is to use the valence electrons of the elements and complete the Octet rule.
Explanation:
The logic behind drawing Lewis formulas is to use the valence electrons of the elements and complete the Octet rule.
Valence electrons are the electrons of an atom that are located in the last shell. We represent the valence electrons using dots between covalent bonds.
The Octet rule says that an element loses or gains electrons in order to achieve the electron configuration of the nearest noble gas, it means that it will try to have 8 electrons in the last shell.
For example: CH3OCH3
1st) It is necessary to find the total number of valence electrons. We can find the electrons of valence of each atom in the Periodic Table, and then we have to multiply it by the number of atoms in the molecule:
- Total number of valence electrons of C: 4e * 2 = 8e
- Total number of valence electrons of H: 1e * 6 = 6e
- Total number of valence electrons of O: 6e * 1 = 6e
Total number of valence electrons of CH3OCH3 = 20e (8 + 6 + 6 = 20)
2nd) Now we have to start drawing with the least electronegative atom in the center. In this case, we have to draw the O in the center (even though it is not the least electronegative atom in the molecule), because it is the only one that has only 1 atom in this molecule, and hydrogen atoms always go on the outside:
We have to start drawing the electrons, trying to complete the octets on the outside atoms, in this case, hydrogen, then carbon, and finally oxygen.
Hydrogen atom only needs 2 valence electrons to complete the last sheel.
in the periodic table how would you group copper, chlorine, iodine, vanadium, astatine ? (based on columns) A. (copper, vanadium) (chlorine, iodine, astatine)B. (copper, astatine) (chlorine, iodine, vanadium)C. (copper, chlorine, iodine) (vanadium, astatine)D. (copper, astatine, vanadium) (chlorine, iodine)
1) Characteristics of the elements mentioned.
Chlorine, Iodine, and Astatine are nonmetals. They are in the 17th group the halogens. They're in the p-block
Copper and Vanadium are transition metals. They're in the d-block.
We can group these elements in metals (Copper and Vanadium) and nonmetals (Chlorine, Iodine, and Astatine)
edAnswersweredQuestion 6How many H atoms are in 3.4 mol C21H23NO5?1.3 x 10³2.9 x 1042.0 x 10244.7 x 10254.7 x1025. This was the correct answer.↓0/1 pts0/1 ptc
Given the following parameters
moles of C21H23NO5 = 3.4 moles
Since there are 23 atoms of hydrogen in the compound, hence the moles of hydrogen in the compound is given as:
[tex]\begin{gathered} moles\text{ of H}=23\times3.4 \\ moles\text{ of H}=78.2moles \end{gathered}[/tex]According to the Avogadro's constant
[tex]1mole\text{ of a substance}=6.02\times10^{23}atoms[/tex]Convert the moles of hydrogen to atoms
[tex]\begin{gathered} atoms\text{ of H}=78.2\times6.02\times10^{23} \\ atoms\text{ of H}=470.764\times10^{23} \\ atoms\text{ of H}=4.70764\times10^{25} \\ atoms\text{ of H}=4.7\times10^{25}atoms \end{gathered}[/tex]I don't know how to solve this. Thank you.An iron cube 20 cm on each side is completely submerged in water. If you have a mass of 5.60kg,Calculate the density of the block and the mass of water displaced (the density of water is 1000kg/m3).
a) Calculate the density of the block.
The density of any substance is defined as the mass divided the volume.
Density of the block = mass of the block/volume of the block.
We are given the mass of the block.
mass of the block = 5.60 kg
Since the it is an iron cube, we can find its volume.
Side = 20 cm = 0.20 m
Volume of the block = (side)³
Volume of the block = (20 cm)³ = (0.20 m)³
Volume of the block = 8000 cm³ = 0.008 m³
Now that we know the mass and the volume we can find the density of the block.
Density of the block = Mass of the block / Volume of the block
Density of the block = 5.60 kg / 8000 cm³
Density of the block = 0.0007 kg/cm³
Density of the block = 5.60 kg / 0.008 m³
Density of the block = 700 kg/m³
Answer: The density of the block is 0.0007 kg/cm³ or 700 kg/m³
b) Calculate the mass of water displaced:
If we consider that the cube is completely submerged (as the problem says) it will displace some water. How much water does it displace? Archimedes' says: "The volume of displaced fluid is equivalent to the volume of an object fully immersed in a fluid". That means that the block completely submerged in water (fluid) will displace its volume of water.
volume of water displaced = volume of the block
volume of water displaced = 8000 cm³ = 0.008 m³
Now that we know the volume of water displaced, and since we are given the density of water, we can find the mass of water displaced.
Density of water = mass of water / volume of water
mass of water = volume of water * density of water
mass of water = 0.008 m³ * 1000 kg/m³
mass of water displaced = 8.0 kg
Answer: Supposing that the block is completely submerged it displaces 8.0 kg of water.
You have 2.7 x10^24 particles of C3H8:. How many grams are present?
Step 1 - Understanding molar mass
As we have previously seen, one mole corresponds to 6*10^23 particles.
When we weight one mole of something, we obtain what is called the molar mass: the mass of one mole of particles.
Each element has his own molar mass, which can be found in the periodic table. We can use them to calculate the molar mass of a molecule.
Let's see an example. Water is H2O. Looking at a periodic table, we find the molar masses 1 g/mol for H and 16 g/mol for O. Therefore, the molar mass of water will be:
[tex]M_{H2O}\rightarrow2H+1O=2\times1+1\times16=18\text{ g/mol}[/tex]Which means that 1 mole of water weights 18g.
Step 2 - Solving the exercise
Let's start by calculating the molar mass of C3H8. The molar mass for C is 12 g/molj, so:
[tex]M_{C3H8}=3C+8H=3\times12+8\times1=44\text{ g/mol}[/tex]44g corresponds thus to one mol of C3H8. Since one mole is 6.10^23 particles, we can set the following proportion:
[tex]\begin{gathered} 6.10^{23^\text{ }}particles\text{ of C3H8 ------ 44g} \\ 2.7\times10^{24}\text{ particles of C3H8 ----- x} \\ \\ x=\frac{2.7\times10^{24}\times44}{6.10^{23}}=\frac{1188}{6}=198g \\ \end{gathered}[/tex]Answer: 198g of C3H8 are present.
on4Suppose that the pressure of 1.23 L of gas is 300.6 mm Hg when the temperature is 218.5 K. At what temperature is the volume 8.32 L and the pressure 802.75 mm Hg?O a. 3950O b. 8610O c. 1250O d. 12.1Check
Answer:
The final temperature is 3,952K. (The closest option is 3,950K).
Explanation:
The given information from the exercise is:
- Initial pressure (P1): 300.6mmHg
- Initial volume (V1): 1.23L
- Initial temperature (T1): 218.5K
- Final volume (V2): 8.32L
- Final pressure (P2): 802.75mmHg
We can calculate the final temperature (T2), by replacing the values of P1, V1, T1, V2 and P2 in the following formula of Ideal Gases:
[tex]\begin{gathered} \frac{P_1*V_1}{T_1}=\frac{P_2*V_2}{T_2} \\ \frac{300.6mmHg*1.23L}{218.5K}=\frac{802.75mmHg*8.32L}{T_2} \\ 1.69\frac{mmHgL}{K}=\frac{6,678.88mmHgL}{T_2} \\ T_2=\frac{6,678.88mmHgL}{1.69\frac{mmHgL}{K}} \\ T_2=3,952K \end{gathered}[/tex]So, the final temperature is 3,952K. (The closest option is 3,950K).
24.How is a supersaturated solution prepared?Select one:a. Heat a solution to the boiling point and continue to boil for 15 minutes.b. Add solute to a saturated solution and heat until all of the solute dissolves. Then, slowly cool to the original temperature.c. Add solute to cold solvent and then heat the solution to room temperature.d. Stir the solution until all of the solid dissolves and then heat the solution.
Answer
b. Add solute to a saturated solution and heat until all of the solute dissolves. Then, slowly cool to the original temperature.
Explanation
A supersaturated solution contains more dissolved solute than required for preparing a saturated solution and can be prepared by heating a saturated solution, adding more solute, and then cooling it gently. Excess dissolved solute crystallizes by seeding supersaturated solution with a few crystals of the solute.
Therefore, a supersaturated solution is prepared by:
b. Add solute to a saturated solution and heat until all of the solute dissolves. Then, slowly cool to the original temperature.
How much heat is released when a 50 g piece of paraffin cools from 55⁰C to 18⁰. Specific heat of paraffin = 2.9J/gC
Answer:
Q = -5,365 J
Explanation:
To find the amount of heat released, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = heat (J)
-----> m = mass (g)
-----> c = specific heat capacity (J/g°C)
-----> ΔT = T₂ - T₁ = change in temperature (°C)
"T₂" represents the final temperature and "T₁" represents the initial temperature. You can plug the given values into the equation and solve to find "Q".
Q = ? J c = 2.9 J/g°C
m = 50 g ΔT = 18°C - 55°C = -37°C
Q = mcΔT <----- Given equation
Q = (50 g)(2.9 J/g°C)(-37°C) <----- Insert values
Q = -5,365 J <----- Multiply
*the answer is negative because the reaction is exothermic (heat is being released from the system)
If an ideal gas does not really exist, why do scientists use this this concept?
The ideal gas model was created to summarize some laws and study the behaviour of the gases, that depends on the properties.
It is really helpful and it is the first approach to the real behaviour of the gases, because all the other equations that came out after it, they have a basis on it. Historically, the ideal gas model was one of the first and most suitable ways to describe and calculate the properties of the gases.
It is also important that it's one of the easiest ways to relate the properties that are in the model, and it's very useful under certain conditions (specially temperature and pressure).
Write and balance the equation for the combustion of the fatty acid lauric acid, (C12H24O2)Write and balance the equation for the combustion of the fatty acid stearic acid, (C18H36O2).
1) Write the chemical equation.
[tex]C_{12}H_{24}O_2+O_2\rightarrow CO_2+H_2O[/tex]List the elements in the reaction.
Reactants
C: 12
H: 24
O: 4
Products
C: 1
H: 2
O: 3
2) Balance C.
[tex]C_{12}H_{24}O_2+O_2\rightarrow12CO_2+H_2O[/tex]List the elements in the reaction.
Reactants
C: 12
H: 24
O: 4
Products
C: 12
H: 2
O: 25
3) Balance H.
[tex]C_{12}H_{24}O_2+O_2\rightarrow12CO_2+12H_2O[/tex]List the elements in the reaction.
Reactants
C: 12
H: 24
O: 4
Products
C: 12
H: 24
O: 36
4) Balance O.
[tex]C_{12}H_{24}O_2+17O_2\rightarrow12CO_2+12H_2O[/tex]List the elements in the reaction.
Reactants
C: 12
H: 24
O: 36
Products
C: 12
H: 24
O: 36
5) Balanced chemical equation.
[tex]C_{12}H_{24}O_2+17O_2\rightarrow12CO_2+12H_2O[/tex]It was determined that 1.4 x 1024 carbon dioxide molecules are produced when propane is combusted according to the equation below. Calculate the number of moles of propane that was burned.C 3H 8 + 5O 2 ----> 3CO 2 + 4H 2O
First, we have to convert the number of molecules to the number of moles of CO2 (carbon dioxide), and to do this we can do the Avogadro's number:
The Avogadro's number helps us to determine the number of moles based on the number of molecules or atoms of a compound. This number is 6.022 x 10 ^(23) /mol.
So, the conversion from molecules to moles would be:
[tex]1.4\cdot10^{24}moleculesCO_2\cdot\frac{1molCO_2}{6.022\cdot10^{23}moleculesCO_2}=2.325molCO_2.[/tex]Now, using this data we can calculate the number of moles needed for propane (C3H8).
In the chemical reaction, you can see that 1 mol of propane produces 3 moles of CO2, so the calculation would be:
[tex]2.325molCO_2\cdot\frac{1molC_3H_8}{3molesCO_2}=0.775molC_3H_8.[/tex]The answer is that 0.78 moles of C3H8 were burned and produced 2.325 moles of CO2 which is 1.4 x 10 ^(24) molecules of CO2.
write the chemical structure of 2 ethyl pentanoic acid
Hope this answer helps you
5
Which of the following shows kinetic energy being converted into potential energy?
A-a boulder rolling across the ground
B-a rock being tossed high into the air
C-a boulder falling off the edge of a cliff
D-a rock sitting in the grass
Answer:
c
Explanation:
boulder was at rest on top of a hill so it contains abundant potentialenergy. When the boulder falls, its potential energy will change to kinetic energy, the energy of motion. When the boulder stops moving, its kinetic energy will transform back to potential energy
\Which of the following should be broken into ions when writing a complete ionic equation? Select all that apply.
Step 1 - How to tell whether a given substance is ionic or covalent
To decide whether a substance is ionic or covalent, we must look for metals in its formula. If the substance is composed of both metals and non metals, it is an ionic susbtance.
If it's, on the other hand, composed solely by non-metals, it is a covalent substance.
Covalent substances do not produce ions in aqueous solution. Therefore, they can't be "broken into ions".
Step 2 - Analysing the given substances
H2O --> composed of H and O; both non-metals, so covalent
LiF --> composed of a metal (Li) and a non-metal (F), so ionic
K3PO4 --> composed of a metal (K) and non-metals (P, O), so ionic
AgCl --> composed of a metal (Ag) and non-metal (Cl), so ionic
Step 3 - Answering the exercise
All substances except H2O should be broken into ions when writing a complete ionic equation.
Answer: all except H2O
The G base of a DNA molecule has the molecular formula C10H12O6N5P. Which two elements in the given formula exhibit show similar chemical and physical properties?A) C and H B) O and PC) N and O D) N and P
Explanation:
The question requires us to identify the two elements present in the molecular formula C10H12O6N5P which present similar chemical and physical properties.
First, we need to identify all elements present in the molecule C10H12O6N5P:
- carbon (C)
- hydrogen (H)
- oxygen (O)
- nitrogen (N)
- phosporus (P)
Next, we can analyze the position of these elements in the periodic table:
Note that H is on the left side of the table, while the other elements (C, N, O and P) are closer together on the right side of the table.
We can see that although there are some elements close on the table, only N and P are part of the same group of the periodic table. Based on this, we can say that N and P should present similar properties because they are part of the same group.
Final answer: N and P should present similar chemical and physical properties (letter D).
What is the 238 U enrichment required for the following applications?
Naturally occurring Uranium: _____ %
Nuclear fuel for power generation: _____ %
Nuclear bombs: _____ %
Naturally occurring Uranium: 99.2745 %
Nuclear fuel for power generation: 97%
Nuclear bombs: 90 %
With a relative abundance of 99%, uranium-238 (238U or U-238) is the most prevalent isotope of uranium to be discovered in nature. It is non-fissile, unlike uranium-235, hence it cannot support a chain reaction in a thermal-neutron reactor.
A 1000 MWe pressurized water reactor needs about 27 tonnes of uranium per year, or over 18 million fuel pellets contained in more than 50,000 fuel rods. In contrast, a coal power plant of comparable scale would require more than 2.5 million tonnes of coal to generate the same amount of electricity.
15 kilograms: weight of a solid sphere of 100 percent uranium-235, just large enough to reach a critical mass with a beryllium reflector, nuclear weapons normally use a concentration of more than 90 percent.
Hence, the percentages are 99.27, 97 and 90% respectively.
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A 0.19 mole sample of nitrogen gas occupies a volume of 2.25 L. What is the volume of 0.27 mol of nitrogen gas under the same conditions?
Step 1 - Discover the relation between moles and volume
The gas state equation states that:
[tex]pV=\text{nRT}[/tex]Since the exercise says that both pressure and temperature will remain the same ("under the same conditions"), and R is already a constant, we can obtain a direct relation between moles and volume:
[tex]V=n(\frac{RT}{P})\rightarrow V\propto n[/tex]Since R, T and P will not vary, the quocient in parenthesis is a constant. Therefore, the volume will be directly proportional to the number of moles of gas.
Step 2 - using the relation to solve the problem
Since, as we saw, volume and moles are directly proportional to each other, we can set the following proportion to discover the new volume:
[tex]\begin{gathered} 0.19\text{ moles of N2----2.25 L} \\ 0.27\text{ moles of N2-----x} \\ \\ x=\frac{0.27\times2.25}{0.19}=3.19\text{ L} \end{gathered}[/tex]So, the volume of 0.27 moles of N2 gas, under the same conditions, will be 3.19 L.
I have homework to do please I need help with number 7
The mass number of an atom is defined as the sum of the number of protons and the number of neutrons in that atom.
So, if m is the mass number, p is the number of protons and n is the number of neutrons, we have:
[tex]m=p+n[/tex]We have that:
[tex]\begin{gathered} p=30 \\ n=34 \\ m=30+34=64 \end{gathered}[/tex]So, the mass number is 64.
PLEASE HELPPPP CHEMISTRY
There are 1.02391×1024 no. of atoms in 1.70 moles of Calcium (Ca)
What is a Avogadro number?The approximate number of nucleons (protons or neutrons) in a gram of common stuff is known as the Avogadro number. 1 mole of any material contains the no of particles equal to the Avogadro number, that is, 6.023×1023particles.
What is Calcium?The chemical element calcium has the atomic number 20 and the letter Ca as its symbol. Calcium is an alkaline earth metal that reacts with air to create a black oxide-nitride coating. Its heavier homologues barium and strontium are most similar to it in terms of physical and chemical characteristics.
Now,
Acc. to the Avogadro Number principal every 1 mole of any material contains the no of particles equal to the Avogadro number, that is, 6.023×1023particles.
So, the given amount of Calcium contains atom as follows:
1.70×6.023×1023 =1.02391×1024 atoms
Hence, There are 1.02391×1024 no. of atoms in 1.70 moles of Calcium (Ca)
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Part A identify club soda as an element, compound, or mixture part B explain why you chose the answer for part A.
EXPLANATION:
PART
Soda drink is a mixture
PART B
Soda drink is a mixture and not a compound. This is because it contains different constituents and they are mixed together in the right proportion. Also, the composition of the constituents is uniform throughout the mixture.
The reaction of 192g of Fe2O3 with 82.5g of CO produces 72.9 of Fe Fe2O3 + 3CO => 2Fe + 3CO2 Calculate the theoretical yield of iron in grams.
ANSWER
The theoretical yield of Fe is 109.64 grams
EXPLANATION
Given that;
The mass of Fe2O3 is 192 grams
The mass of CO is 82.5 grams
Follow the steps below to find the theoretical yield of Iron
Steps 1; Find the number of moles of Fe2O3 and CO using the below formula
[tex]\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}[/tex]Recall, that the molar mass of Fe2O3 and CO are 159.69 g/mol and 28.01 g/mol
[tex]\begin{gathered} \text{ For Fe}_2O_3 \\ \text{ mole = }\frac{\text{ 192}}{\text{ 159.69}} \\ \text{ mole = 1.202 moles} \\ \\ \text{ For CO} \\ \text{ mole = }\frac{\text{ 82.5}}{\text{ 28.01}} \\ \text{ mole = 2.945 moles} \end{gathered}[/tex]Step 2; Determine the limiting raectant of the reaction
To determine the limiting reactant, divide the number of moles by the co-efficient of each reactant
[tex]\begin{gathered} \text{ For Fe}_2O_3 \\ \text{ mol/wt of Fe}_2O_3\text{ = }\frac{\text{ 1.201 }}{\text{ 1}} \\ \text{ mol/wt of Fe}_2O_3\text{ = 1.202 mol} \\ \\ \text{ for CO} \\ \text{ mol/wt of CO = }\frac{\text{ 2.945}}{\text{ 3}} \\ \text{ mol/wt of CO = 0.982 mol} \end{gathered}[/tex]From the calculations, the limiting reactant of the reaction is CO
Step 3; Find the number of moles of Fe using a stoichiometry ratio
Let x represents the number of moles of Fe
[tex]\begin{gathered} \text{ 3 moles CO }\rightarrow\text{ 2 moles Fe} \\ \text{ 2.945 moles CO }\rightarrow\text{ x moles Fe} \\ \text{ cross multiply} \\ \text{ 3 moles CO}\times\text{ x moles Fe = 2 moles Fe }\times\text{ 2.945 moles CO} \\ \text{ x moles Fe = }\frac{\text{ 2 moles Fe}\times2.945mole\cancel{CO}}{3moles\cancel{CO}} \\ \\ \text{ x mole Fe = }\frac{\text{ 2 }\times\text{ 2.945}}{\text{ 3}} \\ \\ \text{ x mole Fe = }\frac{\text{ 5.89}}{\text{ 3}} \\ \text{ x mole Fe = 1.963} \end{gathered}[/tex]The number of moles of Fe is 1.963 moles
Step 4; Find the theoretical yield of Fe
[tex]\begin{gathered} \text{ mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \text{ cross multiply} \\ \text{ mass = mole }\times\text{ molar mass} \end{gathered}[/tex]Recall, molar mass of Fe is 55.845 g/mol
[tex]\begin{gathered} \text{ mass = 1.963 }\times\text{ 55.845} \\ \text{ mass = 109.64 grams} \end{gathered}[/tex]Therefore, the theoretical yield of Fe is 109.64 grams
Local winds are produced by geographic freatures true or false
Explanation:
Hey! The answer is True!
Ksp= 2×10−19 for LaF3 Calculate the solubility of LaF3 in grams per liter in a solution that is 0.011 M in KF
Solubility of LaF3: "S"
First, we need to write the reaction of solubility:
LaF3 (s) <=> La+3 + 3 F-
Initial - 0 +0.011 (F-, from KF)
Change +S +3.S
Equilibrium S 0.011 + 3.S
Now, we know:
Ksp = [La³⁺]x[F⁻]³ = 2×10^−19 = S x (0.011+3.S)³
We work with: 2×10^−19 = S x (0.011+3.S)³, and we clear the "S"
=> S = 1.5x10^-13 mol/L x (195.9 g/mol) = 2.93x10^-11 g/L
The molar mass of LaF3 = 195.9 g/mol
Answer: S = 2.93x10^-11 g/L
Can you help me how do I get the grams?
Answer:
[tex]1290g\text{ NaBr}[/tex]Explanation:
Here, we want to get the number of grams in 12.5 moles NaBr
To get this, we have to multiply the number of moles by the molar mass of NaBr
The molar mass of NaBr is 103 g/mol
Thus, we have the mass as:
[tex]\begin{gathered} Mass\text{ = number of moles }\times\text{ molar mass} \\ =\text{ 12.5 }\times\text{ 103 = 1,287.5 g} \end{gathered}[/tex]This can be approximated to 1290 which is the nearest whole number
A gas occupies 3.8 L at -18° C and 975. torr. What volume would this gas occupy at STP?
To solve the question we will assume that the gas behaves like an ideal gas, that is to say, that there is no interaction between the molecules. Assuming ideal gas we can apply the following equation:
[tex]PV=nRT[/tex]Where,
P is the pressure of the gas
V is the volume of the gas
n is the number of moles
R is a constant
T is the temperature
Now, we have two states, an initial state, and a final state. The conditions for each state will be.
Initial state (1)
P1=975Torr=1.28atm
V1=3.8L
T1=-18°C=255.15K
Final state(2), STP conditions
P2=1atm
T2=273.15K
V2=?
We will assume that the number of moles remains constant, so the nR term of the first equation will be constant. For each state, we will have:
[tex]\begin{gathered} \frac{P_1V_1}{T_1}=nR \\ \frac{P_2V_2}{T_2}=nR \end{gathered}[/tex]Since nR is the same for both states, we can equate the equations and solve for V2:
[tex]\begin{gathered} \frac{P_{2}V_{2}}{T_{2}}=\frac{P_1V_1}{T_1} \\ V_2=\frac{P_{1}V_{1}}{T_{1}}\times\frac{T_2}{P_2} \end{gathered}[/tex]We replace the known values:
[tex]V_2=\frac{1.28atm\times3.8L}{255.15K}\times\frac{273.15K}{1atm}=5.2L[/tex]At STP conditions the gas would occupy 5.2L. First option
Perform the followingmathematical operation, andreport the answer to thecorrect number of significantfigures.16.52 x 5.8 = [?]=Enter
For multiplication and division operations, we perform the operations normally, and the final result must be written with the same number of significant figures as the factor that has the fewest significant figures.
16.52 x 5.8 = 95.816
The result obtained in the above multiplication must be rounded to two significant figures, which correspond to the number of significant figures of the number 5.8. Therefore, we must round the result, giving as answer 96.
Answer: 96
2. Sodium Na has an electronegativity = 0.9 and nitrogen N is 3.0. which is correct about the bond between Na and N
Polar covalent because the difference is 2.1
Ionic because the difference is 2
. nonpolar covalent because the difference is 2.1
they cannot form a bond because the difference is 2.1
3.. which is correct about ionic bond ?
Based on loss and gain of electrons
Based on sharing electrons
. Takes place between nonmetals
. Found between noble gase
4. In a polar covalent bond, the bonded atoms.(1 Point)
Share the electrons equally
Share the electrons unequally.
One atom loses and the other gains.
Both atoms gain electrons
Answer:
2. Ionic because the difference is 2
3. Based on loss and gain of electrons
4. Share the electrons unequally.
24. Predict the Products
a. Ca + H3N→
b. KF→
c. NaBr + MgO→
i,ii&iii only the alkanes forms 3-bromo-3-methylpentane as the major product when it's react with hbr.
What is alkane forms?
Alkanes are the series of a compounds that is contain carbon and hydrogen atoms of the with single covalently bonds. Theses are knowns as saturated if hydrocarbons. This group of the compounds consists of a carbon and hydrogen and atoms with single covalent bonds. Also it is comprises a homologous series of having a molecular formula of NaBr+MgO.
Sol-this problem which of the following Elkins yields three bromo three metal painting as the major product upon addition of HBR. So let me just write an equation right? I'm writing here directly. So when HBR is reacted, so what will be the compound here? We will be getting a compound like this. Alright, so this is B. R. Again, we are processing here with H beyond right.
This is it. So now organic compound is going to be seen. This is beard. Right? So here you can point one more when you add here it's B. R. We will be getting here. Yeah, again, for this when weird it's beard. So again we will be getting to come home like this. So same compound we're getting that means this is this is nothing but three Bromo three metal contains as the major product. So all are having the same product and option is all of them is correct. Right? No next question it is asked at which of the following cardboard signs bill undergo At 1 2 metal shift. Right? So None of them ever was the correct answer because none of them will undergo 12 m shift.
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Calculate the concentration of H3O + ions in a solution of NaoH whose concentration is 0.62M at 25 ° C.
The pH of this solution is 0.207
Hello
To solve this question, we need to use the formula of solving pH of a solution from hydrogen or hydronium ion.
[tex]\begin{gathered} pH=-\text{log\lbrack{}H}_3O^+\rbrack \\ \end{gathered}[/tex]Now, we would proceed to substitute the given value and solve for it.
[tex]\begin{gathered} pH=-\log \lbrack0.62\rbrack \\ pH=0.207 \end{gathered}[/tex]NB: we did not use the value of temperature because it is not needed in this solution.
From the calculation above, the pH of this solution is 0.207
4 Which protective measure is 100 percent effective at reducing the risk of sexually transmitted disease? A. Use a condom during intercourse. B. Keep the number of partners to a minimum. C. Use birth control pills correctly. D. Abstain from sexual activity.
Which protective measure is 100 percent effective at reducing the risk of sexually transmitted disease is . and Abstain from sexual activity.
The protective measure is 100 percent effective at reducing the risk of sexually transmitted disease is only Abstain from sexual activity. The other methods that is keep number of partners to a minimum , use birth control pills correctly are for reducing risk for pregnancy. Use a condom during intercourse is reduce the risk for sexually transmitted disease but not 100 % effective.
Thus, Which protective measure is 100 percent effective at reducing the risk of sexually transmitted disease is Abstain from sexual activity.
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