Construct a Venn diagram where U={a,b,c,d,e,f,g}, A={b,d,f,g}, and B={b}.Move each of the lettered points to an appropriate region on the Venn diagram.

Construct A Venn Diagram Where U={a,b,c,d,e,f,g}, A={b,d,f,g}, And B={b}.Move Each Of The Lettered Points

Answers

Answer 1

Explanation:

Given the universal set, U and subsets A and B as follows:

• U={a,b,c,d,e,f,g}

,

• A={b,d,f,g}

,

• B={b}

Answer:

The Venn diagram representing the sets is given below:

Note:

• The ,letter b is common to both A and B,, so we put it in the intersection of both sets.

,

• The ,letters a, c, and e do not belong to either A or B,, so we place it outside of the two sets.

Construct A Venn Diagram Where U={a,b,c,d,e,f,g}, A={b,d,f,g}, And B={b}.Move Each Of The Lettered Points

Related Questions

Ryan earns $20 for every lawn that he mows. Which equation can be used to find t, the total amount Ryan will earn after mowing n lawns?

Answers

Ryan earns $20 for every lawn that he mows.

Let t represents the total amount Ryan will earn.

Let n repreents the number of laws Ryan will mow.

So, the equation becomes

[tex]t=20n[/tex]

For example:

How much Ryan will earn if he mows 5 lawns?

Let us substitute n = 5 into the equation

[tex]\begin{gathered} t=20n \\ t=20(5) \\ t=\$100 \end{gathered}[/tex]

Therefore, Ryan will earn $100 if he mows 5 lawns.

A 4-pint carton of soy milk costs $0.96. What is the price per cup?

Answers

The cost of per cup milk cartons is $ 0.24

Given price of a 4 pint carton = $ 0.96
thus to calculate the price of 1 carton

we would have to use unitary method

in unitary method ,

the cost of multiple or the cost of an item is given and we are supposed to find the cost of a single or multiple items respectively.

Here since the cost of 4 pint cartons are given

we will find the cost of 1 carton by dividing :

the cost of 4 pint cartons / number of cartons

thus we will get 0.96/4 = $ 0.24

Thus the cost of 1 carton is $ 0.24

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Septima invests $3,000 in an account with an annual interest rate of 5.2% compounded monthly for 3 years.What is the return on investment for Septima's account?16.8%1.3%14.4%5.3%

Answers

Given:

Principal, P=$3000

Interest rate, r=0.052

Years, t=3 years

To find the return amount is compounded monthly:

Using the formula,

[tex]\begin{gathered} A=P(1+\frac{r}{12})^{12t}_{} \\ =3000(1+\frac{0.052}{12})^{12\times3} \\ =3000(1+0.00433)^{36} \\ =3505.30 \end{gathered}[/tex]

Hence, the return amount on investment is $3505.30.

In percentage,

The return on investment is,

[tex]\begin{gathered} \frac{3505.3}{3000}\times100=16.84 \\ \approx16.8\text{ \%} \end{gathered}[/tex]

Hence, the answer is 16.8%.

6 cm Find the missing dimension of each figure. Round your answer to the nearest tenth. 5. V=252 ft 4. V=100 in 6 ft 12 in 14 ft rin. eft Find the volume of each composite figure. Round your answer to the nearest tenth. 6. 6 in. 7. A cylindrical-shaped hole is cut from 11 in. the center of a cube. 2.5 cm 15 in.solve #5 please

Answers

The volume of cuboid is V = 252 ft^3.

The width of cuboid is w = 14 ft.

The height of cuboid is h = 6 ft.

The formula for the volume of cuboid is,

[tex]V=l\cdot w\cdot h[/tex]

Substitute the values in the formula to determine the length of cuboid.

[tex]\begin{gathered} 252=l\cdot14\cdot6 \\ l=\frac{252}{84} \\ =3 \end{gathered}[/tex]

So length (missing dimension) of the cuboid is 3 ft.

1. Predict what will happen when a tape diagram has a large number of squares, some squares are removed, and thenthe same amount of squares are added back on.Build a tana diagram mit 10

Answers

When some squares are removed, the number of squares in the tape diagram are reduced but when the same number of squares are added back, then we will find out that the number of squares in the tape diagram remain the same.

Using Euler’s formula, how many edges does a polyhedron with 9 faces and 14 vertices have? Thank you

Answers

[tex]F+V=E+2[/tex]

Solve the Euler's formula above to E (Edges)

[tex]\begin{gathered} \text{Substract 2 in both sides of the equation;} \\ \\ F+V-2=E+2-2 \\ F+V-2=E \\ \\ \text{ Rewrite the equation:} \\ \\ E=F+V-2 \end{gathered}[/tex]

Use the given data;

Faces; F=9

Vertices: V=14

[tex]\begin{gathered} E=9+14-2 \\ E=21 \end{gathered}[/tex]The polyhedron has 21 edges

The ratio of short to pants is 1:2 if there are eight shorts how many pants are there? 16,4,6,or 8

Answers

Answer:

There are 16 pants

Explanation:

Ratio of short to pants = 1:2

There are 8 shorts

Let x be the number of pants, then

8/x = 1/2

x = 8 * 2

= 16

There are 16 pants

Which additional piece of information would you need to prove these two triangles are congruent using the side-side-side or SSS triangle congruence postulate?

Answers

By using congruency of triangles, the result obtained is

The additional information needed to make [tex]\Delta STU \cong \Delta SHU[/tex] by SSS axiom is

TU = SH

Side SH is congruent to side TU

Third option is correct

What is Congruency of triangles?

Two triangles are said to be congruent if the corrosponding sides and corrosponding angles are same.

The different axioms of congruency are SSS axiom, SAS axiom, ASA axiom, AAS axiom, RHS axiom

In [tex]\Delta STU[/tex] and [tex]\Delta SHU[/tex]

ST = HU [Given]

SU is common.

The additional information needed to make [tex]\Delta STU \cong \Delta SHU[/tex] by SSS axiom is

TU = SH

Side SH is congruent to side TU

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Evaluate the expression when a=-5 and c=27c-a

Answers

Given:

7c - a

a=-5 and c = 2

Substitute the values into the expression

7(2) - (-5)

=14 + 5

= 19

The tree diagram below represents the relationships between the sets and subsets of real numbers. Real Numbers Rational Numbers {..., V2, e, , ...) ? Non-integer Rational Numbers {0, 1, 2, 3, ---) Whole Number Opposites Which group of numbers could replace the question mark in the tree diagram

Answers

The diagram starts with Real Numbers which comprehend all numbers except for complex numbers.

The second level is formed by rational numbers and irrational numbers.

The third level is formed by subsets of rational numbers non-integers rational numbers and integers rational numbers.

Therefore, the right answer is C. -7, 8, -4, since these numbers are rational and integers.

I need help with this practice I am having trouble with it The subject is trig

Answers

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given range

[tex](-\infty,-9\rbrack\cup\lbrack5,\infty)[/tex]

STEP 2: Find the cosecant function

[tex]\begin{gathered} \text{The range of a cosecant function normally excludes the interval }(-1,1)\text{.} \\ The\text{ range in the question excludes the interval }(-9,5)\text{, which has a width 7 times as great.} \\ \text{Thus, we know the vertical factor is 7.} \\ \\ T\text{he midpoint of the excluded interval of the given function is }\frac{(-9+5)}{2}=-\frac{4}{2}=-2 \\ so\text{ that is the vertical translation.} \\ \text{The cosecant function normally has vertical asymptotes at }x=0\text{ and }x=\pi\text{ so the function is } \\ \text{expanded horizontally by a factor of }2. \end{gathered}[/tex]

Hence, the cosecant function is

[tex]undefined[/tex]

If cos A = 35/37 and sin B = 9/41 and angles A and B are in Quadrant I, find the valueof tan(A - B).

Answers

The given expression is tan(A - B)

Since tan (A - B) is equal to

[tex]\tan (A-B)=\frac{\tan A-\tan B}{1+\tan A\tan B}\rightarrow(1)[/tex]

Since the values of cos A and sin B are

[tex]\begin{gathered} \cos A=\frac{35}{37} \\ \sin B=\frac{9}{41} \end{gathered}[/tex]

We will use the rules

[tex]\begin{gathered} \tan ^2A=\sec ^2A-1\rightarrow(2) \\ \cot ^2B=\csc ^2B-1\rightarrow(3) \end{gathered}[/tex]

csc B = 1/sin B, cot B = 1/tan B, sec A = 1/cos A

[tex]\begin{gathered} \csc B=\frac{1}{\frac{9}{41}}=\frac{41}{9} \\ \sec A=\frac{1}{\frac{35}{37}}=\frac{37}{35} \end{gathered}[/tex]

Substitute the value of csc B in rule (3) to find cot B

[tex]\begin{gathered} \cot ^2B=(\frac{41}{9})^2-1 \\ \cot ^2B=\frac{1600}{81} \\ \sqrt[]{\cot^2B}=\pm\sqrt[]{\frac{1600}{81}} \\ \cot B=\frac{40}{9} \end{gathered}[/tex]

Reciprocal it to find tan B

[tex]\tan B=\frac{1}{\cot B}=\frac{9}{40}[/tex]

Substitute the value of sec A in rule (2) to find tan A

[tex]\begin{gathered} \tan ^2A=(\frac{37}{35})^2-1 \\ \tan ^2A=\frac{144}{1225} \\ \sqrt[]{\tan^2A}=\pm\sqrt[]{\frac{144}{1225}} \\ \tan A=\frac{12}{35} \end{gathered}[/tex]

Substitute the values of tan A and tan B in rule (1) above

[tex]\begin{gathered} \tan (A-B)=\frac{\frac{12}{35}-\frac{9}{40}}{1+(\frac{12}{35})(\frac{9}{40})} \\ \tan (A-B)=\frac{165}{1508} \end{gathered}[/tex]

The value of tan(A - B) is 165/1508

Which equation has (1,1),(2,4),(3,7) and (4,10) as solutions?A)y=2x - 1.B)y= 2x+3.C)y=3x-2.D)y=3x+1.

Answers

Answer:

y=3x-2

Explanation:

The equation that has the given solutions is the equation that satisfies all the given (x, y) pairs.

From the given options:

[tex]\begin{gathered} \text{When x=1} \\ y=3x-2 \\ y=3(1)-2=1 \\ \implies(1,1) \end{gathered}[/tex]

Likewise:

[tex]\begin{gathered} \text{When x=}2 \\ y=3x-2 \\ y=3(2)-2=4 \\ \implies(2,4) \end{gathered}[/tex]

Also when x=3:

[tex]\begin{gathered} y=3\mleft(3\mright)-2=7 \\ \implies(3,7) \end{gathered}[/tex]

Finally, when x=4

[tex]\begin{gathered} y=3\mleft(4\mright)-2=10 \\ \implies(4,10) \end{gathered}[/tex]

Thus, since y=3x-2 satisfies all four points, it is the right equation.

Simple probabilityYou draw a card at random from a deck that contains 3 black cards and 7 red cards.If necessary, round your answer to 2 decimal places.

Answers

The question says you draw a card at random from a deck that contains 3 black cards and 7 red cards.

What is the probability of drawing a black card?

Recall,

Probability = Number of possible outcome

Number of favorable outcome

There are 3 favorable outcomes (the 3 black cards)

There are 10 possible outcomes ( the 3 + 7 = 10 cards)

Therefore,

P(draw a black card) = 3/10

P(draw a black card) = 0.30 (to 2 decimal places)

Select the correct choice and fill in the blank if necessary

Answers

Given

[tex]f(x)=\frac{x+6}{x-7}[/tex]

Recall

The horizontal line test can be used to determine if a function is one-to-one given a graph. Simply superimpose a horizontal line onto a graph and see if it intersects the graph at more than one point. If it does, the graph is not one-to-one and if it only intersects at one point, it will be one-to-one.

The graph

It passed the horizontal line test, therefore is one to one function

Part B

[tex]f(x)=\frac{x+6}{x-7}[/tex]

Step 1

Replace f(x) with y

[tex]y=\frac{x+6}{x-7}[/tex]

Step 2

Inter change y and x

[tex]x=\frac{y+6}{y-7}[/tex]

Step 3

Make y the subject

[tex]\begin{gathered} x=\frac{y+6}{y-7} \\ x(y-7)=y+6 \\ xy-7x=y+6 \\ xy-y=6+7x \\ y(x-1)=6+7x \\ divide\text{ both sides by x-1} \\ y=\frac{6+7x}{x-1} \end{gathered}[/tex]

Step 4

Replace y with f^-1

[tex]f^{-1}(x)=\frac{6+7x}{x-1}[/tex]

The final answer

[tex]f^{-1}(x)=\frac{6+7x}{x-1}[/tex]

The sale Price of a swing set is $90. What is the original price?Sale:75% Round your answer to the whole dollar

Answers

To solve this problem we can use the expression that defines percents. What price has a 75% of $90?

[tex]\text{Total}\cdot\frac{\text{percent}}{100}=\text{equivalent number to the percent}[/tex]

With the information given, we know that the equivalent number to the percent is $90 and the percent is 75%.

Then, substitute and solve for the total variable:

[tex]\begin{gathered} \text{Total}\cdot\frac{75}{100}=90 \\ \text{Total}=\frac{90\cdot100}{75} \\ \text{Total}=120 \end{gathered}[/tex]

The original price of the swing set is $120.

1) Find the equation of the line through the points (-2, 5) and (3, 1). Also, graph this line.

Answers

Answer

The equation of the line is

y - 5 = -0.8 (x + 2)

We can then simplify further

y - 5 = -0.8x - 1.6

y = -0.8x - 1.6 + 5

y = -0.8x + 3.4

Explanation

The general form of the equation in point-slope form is

y - y₁ = m (x - x₁)

where

y = y-coordinate of a point on the line.

y₁ = This refers to the y-coordinate of a given point on the line

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

x₁ = x-coordinate of the given point on the line

So, for this, we just need to solve for the slope and use one of the two points given to find the equation of the line.

For a straight line, the slope of the line can be obtained when the coordinates of two points on the line are known. If the coordinates are (x₁, y₁) and (x₂, y₂), the slope is given as

[tex]Slope=m=\frac{Change\text{ in y}}{Change\text{ in x}}=\frac{y_2-y_1}{x_2-x_1}[/tex]

For this question,

(x₁, y₁) and (x₂, y₂) are (-2, 5) and (3, 1)

x₁ = -2

y₁ = 5

x₂ = 3

y₂ = 1

[tex]\text{Slope = }\frac{1-5}{3-(-2)}=\frac{-4}{3+2}=\frac{-4}{5}=-0.8[/tex]

Recall

y - y₁ = m (x - x₁)

m = slope = -0.8x

(x₁, y₁) = point = (-2, 5)

x₁ = -2

y₁ = 5

y - y₁ = m (x - x₁)

y - 5 = -0.8 (x - (-2))

y - 5 = -0.8 (x + 2)

We can then simplify further

y - 5 = -0.8x - 1.6

y = -0.8x - 1.6 + 5

y = -0.8x + 3.4

Hope this Helps!!!

In a circle of radius 10 cm, there are two parallel chords (in different sides of a circle) of lengths 16 cm and 12 cm. Calculate the distance between the chords.

Answers

The distance between the chords is 14 cm

Given that AB=16 cm and CD=12 cm

So, AL=8 cm and CM=6 cm (⊥ from the centre to the chord bisect the chord)

In right triangles OLA and OMC,

By Pythagoras theorem,

OA² = OL²+AL²

and OC² = OM²+CM²

⇒ 10² = OL²+8²

and 10² = OM²+6²

⇒ OL²=100-64

and OM² = 100 - 36

⇒ OL² = 36 and OM² = 64

⇒ OL = 6 cm

and OM = 8 cm

In the second case distance between AB and CD is:

LM=OM+OL

= 8+6

= 14 cm

Hence distance between the chords is 14 cm,

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A group have in their families. The bar graph of adults were asked how many children they below shows the number of adults who indicated each number of children.How many adults were questioned?

Answers

If we add the frequencies of the histogram ( vertical axis), we get that the number of adults questioned is:

[tex]4+7+5+3+1=20.[/tex]

Now, out of those 20, only 5 have 2 children, therefore:

[tex]\frac{5}{20}*100=25\%[/tex]

have 2 children.

Answer:

20 adults were questioned,

25% have 2 children.

Gary and his four friends wish to share 45 cards equally. how many cards will each person get

Answers

The number of persons including Gary and four friends is 5.

Determine the number of cards that each person get.

[tex]\begin{gathered} n=\frac{45}{5} \\ =9 \end{gathered}[/tex]

So each person get 9 cards.

Scores on a standardized reading test for fourth-gradestudents form a normal distribution with µ = 60 ando = 20. What is the probability of obtaining a sample mean greater than M = 65 for each of the following?a. A sample of n = 16 studentsb. A sample of n = 25 studentsc. A sample of n = 100 students

Answers

If scores on a standardized reading test form a normal distribution with       (µ = 60) and (σ = 20), then the probability of obtaining a sample mean greater than (M = 65) for a sample size of (n = 16) will be .

As per the question statement, Scores on a standardized reading test for fourth-grade students form a normal distribution with (µ = 60) and (σ = 20),

And we are required to calculate the probability of obtaining a sample mean greater than (M = 65) for a sample size of (n = 16).

To solve this question, let us assume that, a random variable "X" follows normal distribution with mean (μ = 60), standard deviation (σ = 20) and a sample size of (n = 16).

Then the probability that a sample of size (n = 16) is randomly selected with a mean greater than 65 can be calculated as follows:

P(M > 65) = [1 - P(M < 65)]

= [1 - P{(M - μ)/(σ/√n) < (65 - 60/(20/√16)}]

= [1 - P{(M - μ)/(σ/√n) < (65-60)/(20/4)}]

= [1 - P{Z < (5/5)}]

= [1 - P(Z < 1)]

= (1 - 0.841344746069)...[Using Excel Function "NORMSDIST (1)]

= 0.158655253931

≈ 0.16

Probability: Probability is the branch of mathematics that deals with the numerical descriptions on the extent to which an event is likely to occur, or how likely it is, that a proposition is true, being calculated by the ratio of the favorable cases to the total number of cases possible.

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Question 3 1 pts A pair of designer sneakers was purchased for $120. Since they were purchased their price has increased by 15%. What is the new price, in dollars?

Answers

The new price after the increase of 15%

=120(100 + 15)%

=120 * 115%

= 120 * 115/100

= 138

The new price is $138

Both customers spent same amount of money. customer one bought 8 chicken wings and left a tip of four dollars. second customer bought 10 chicken wings and left a tip of $2.50. how much is each chicken wing?

Answers

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the representation of the chicken wings

Let the chicken wing be represented by x

[tex]\begin{gathered} For\text{ Customer 1, he spent;} \\ 8x+4 \\ From\text{ second customer, he spent} \\ 10x+2.50 \end{gathered}[/tex]

STEP 2: Equate the two amounts

Since they both spent same amount of money, this means that;

[tex]8x+4=10x+2.50[/tex]

STEP 3: Solve for x

[tex]\begin{gathered} Collecting\text{ like terms:} \\ 8x-10x=2.50-4 \\ -2x=-1.5 \\ Divide\text{ both sides by -2} \\ \frac{-2x}{-2}=\frac{-1.5}{-2} \\ x=0.75 \end{gathered}[/tex]

Hence, each chicken wing costs $0.75

Select the correct answer. Describes the zeros of the graphed function.

Answers

Answer

The function has 3 distinct roots (OPTION A)

SOLUTION

Problem Statement

The question gives us a graph and we are required to find the number of zeros the function has.

Method

- The number of zeros a function has corresponds to the number of times the graph crosses the x-axis. If the graph crosses the x-axis once then there is one zero. If it crosses the x-axis twice, then it has 2 zeros.

- The number of zeros a function has also depends on the way the graph touches the x-axis. If the graph touches the x-axis like a quadratic, then there are 2 zeros or zeros that are multiples of 2, that have the same value.

Implementation

The following can be observed from the figure given to us:

- The graph crosses the x-axis twice at x = -2 and x = 2. This means that the graph has at least 2 zeros.

- The graph curves like a quadratic at x = 0. This means that there are at least 2 zeros of the same value or zeros of the same value.

Thus, we can predict that the function must be:

[tex]x^2\mleft(x-2\mright)\mleft(x+2\mright)[/tex]

Final Answer

The answer is:

The function has 3 distinct roots (OPTION A)

In a lottery, the top cash prize was $629 million, going to three lucky winners. Players pick four different numbers from 1 to 56 and one number from 1 to 41.A player wins a minimum award of$525 by correctly matching three numbers drawn from the white balls (1 through 56) and matching the number on the gold ball (1 through 41).What is the probability of winning the minimum award?

Answers

Step 1

Given;

[tex]\begin{gathered} Top\text{ cash prize is \$629} \\ Players\text{ pick four different numbers from 1 to 56 and 1 to 41} \end{gathered}[/tex]

Step 2

Probability is given as;

[tex]undefined[/tex]

convert 62°F to degree Celsius if necessary round to the nearest 10th of a degreeC=5/9 (F-32)F=9/5 C + 32

Answers

Given the following question:

Using the formula:

[tex]undefined[/tex]

Please help with this . I am really stuck on it.The graph shows how time required to ring up a customer is related to the number of items being purchased.If it takes 80 seconds to ring up a customer, how many items are purchased?

Answers

First, we have to find the slope of the line. Let's use the points (30, 60) and (40, 80). Using the slope formula, we have.

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Let's replace the points.

[tex]m=\frac{80-60}{40-30}=\frac{20}{10}=2[/tex]

Then, we use one point, the slope, and the point-slope formula to find the equation.

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-60=2(x-30) \\ y-60=2x-60 \\ y=2x-60+60 \\ y=2x \end{gathered}[/tex]

Then, we use this equation to find the items purchased for 80 seconds.

[tex]y=2\cdot80=160[/tex]Therefore, if it takes 80 seconds to ring up a customer, the number of items purchased is 160.

Line segment EF is shown on the coordinate grid:A coordinate grid is shown from positive 6 to negative 6 on the x-axis and from positive 6 to negative 6 on the y-axis. A line segment EF is shown with E as ordered pair 1, negative 4 and F as ordered pair 5, negative 4.The line segment is rotated by 270 degrees counterclockwise about the origin to form E′F′. Which statement describes E′F′? (1 point)E′F′ is equal in length to EF.E′F′ is half the length of EF.E′F′ is parallel to EF.E′F′ is twice the length of EF.

Answers

the initial coordinates of EF are:

[tex](1,-4),(5,-4)[/tex]

then the segment is rotate 270 degrees counterclockwise so:

In a rotation the length do not change so the answer is A) E'F' is equal in length to EF

You must show your work.

Answers

Could the table please be added as an addition picture?

What was the total length of all the scarves put together?

Answers

ANSWER :

37.8 feet

EXPLANATION :

From the problem, each scarf is 50.4 inches long.

Since there's a total of 9 scarfs.

The total length will be :

[tex]9(50.4)=453.6\text{ }in[/tex]

There are 12 inches in 1 foot.

Divide the result by 12 to get the number of feet.

[tex]\frac{453.6}{12}=37.8\text{ }feet[/tex]

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