Answer:
a. NO is added to the reaction mixture ⇒ to the left
b. BrNO is added to the reaction mixture ⇒ to the right
c. Br₂ is removed from the reaction mixture ⇒ to the right
d. Pressure is increased ⇒ to the left
Explanation:
The reaction at equilibrium is the following:
2BrNO (g) → 2NO (g)+ Br₂ (g)
The left side is the reactants side (2 BrNO) and the right side is the products side (2 NO + Br₂).
a. NO is added to the reaction mixture
NO is a product, in the right side of the equation. If a product is added, the equilibrium will shift to the opposite side, to the left, to form more reactants and compensate for the addition.
b. BrNO is added to the reaction mixture
BrNO is a reactant, in the left side of the equation. If a reactant is added to a reaction at equilibrium, more product will be formed in compensation. Therefore, the equilibrium will shift to the right.
c. Br₂ is removed from the reaction mixture
Br₂ is a product, in the right side. If it is removed, the system will compensate for the remotion by forming more product, so the reaction will shift to the right.
d. Pressure is increased
Since both reactants and products are in the gas phase, the equilibrium is affected by pressure. If pressure is increased, the equilibrium will shift to the side of the reaction with the fewest number of moles. The reactants side (left) has 2 moles of BrNO while the products side (right) has 3 moles (1 mol NO + 1 mol Br₂ = 3 moles of gas). Therefore, the reactants side has the fewest number of moles, so the equilibrium will shift to the left.
Which of the following involves a change in chemical properties
Answer: A chemical change occurs when the substance's composition is changed. When bonds are broken and new ones are formed a chemical change occurs.
ibigay ang kahulugan nito ayun sa paliliwanag
konduktor piloto drayber makinista
Answer:
konduktor
- ang konduktor ay maaaring isang konduktor nga koryente, train o isang taong namumuno sa isang orkestra o isang grupo ng mga mang-aawit.
piloto
-isang tao na tagalipad ng ereplano
drayber
- isang tao na nagmamaniho ng sasakyan
makinista
-ay isang tao na nagpapakilos o nagpapagana ng makina
please give me brainliest.
When water is boiling in a pot, heat energy is being transferred throughout the water by which type of heat transfer?
O Convection
O Conduction
O Radiation
Answer:
it would be Convection.
A gas has a volume of 6.00 liters at a temperature of 300 K and a pressure of 1.00 atm what is the volume of the gas in liters at a temperature of 600 K and a pressure of 3.00 atm
Answer:
V₂ = 4.00 L
Explanation:
Given that:
Volume (v1) = 6.00 L
Temperature (T1) = 300 K
Pressure (P1) = 1.00 atm
VOlume (V2) = unknown???
Temperature (T2) = 600 K
Pressure (P2) = 3.00 atm
Using combined gas law equation:
[tex]\dfrac{P_1V_1}{T_1}= \dfrac{P_2V_2}{T_2}[/tex]
[tex]\dfrac{1 \times 6}{300} = \dfrac{3 \times V_2}{600}[/tex]
[tex]\dfrac{1}{50} = \dfrac{1 \times V_2}{200}[/tex]
200 = 50V₂
V₂ = 200/50
V₂ = 4.00 L
Jonathan raised 60 goats, then entered into a series of business transactions. He traded all the goats for sheep at an exchange rate of 5 goats for 7 sheep. Next, he exchanged all the sheep for hogs at a rate of 4 sheep for 2 hogs. How many hogs did he get?
Answer:
just awser
eeww
Explanation:
3. If an item of trash is described as highly biodegradable, is that a physical property or
chemical property?.
which molecule is butene
Answer:
Option C is the answer
Butene, also called Butylene, 4 isomeric compound belonging to the series of olefinic hydrocarbons. The chemical formula is C4H8, option c is correct.
What are the 4 isomers of butene?Butene, also called Butylene, four isomeric Combinations belong to the series of olefinic hydrocarbons. The chemical formula is C4H8.
The isomeric forms are 1-butene, cis-2-butene, trans-2-butene, and isobutylene.
Thus, option "C" is correct. the chemical formula is C4H8.
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In an effort to maintain homeostasis, the organ systems of the human body work to keep the body's internal water level constant. Which of the following statements describe how the human body responds when its internal water level drops too low?
A. The skeletal system produces more circulating blood cells that insecure the body’s water intake
B. The excretory system signals the kidneys to retain more water and produce more concentrated urine to decrease water loss.
C. The nervous system signals the muscles to constrict , holding more water in the digestive track and decreasing water loss .
D.The excretory system signals the kidneys to release more water into the bladder to increase water loss .
If you have a solution that is 15 percent by mass of KCl in benzene, what is the new boiling point?
Answer:
https://www.chegg.com/homework-help/questions-and-answers/1-10-points-solution-15-percent-mass-kcl-benzene-new-boiling-point--901-c-b-921-c-c-821-c--q63751186
Explanation: Thats your answer
What molecule represents this structure
A)NH4
B)NH3
C)NH4+
D)NH3+
Explanation:
As I think Option C is correct i.e. NH4+.
what is the ph of a 8.4x10^-6 M H+ solution?
4.3 x 10^2 - 7.0 x 10^2 in scientific notation
In a nuclear equation:??
convert 113 Fahrenheit to celcius do full process
[tex]\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}[/tex]
45° Celsius
Formula (113°F − 32) × 5/9 = 45°C
ThanksHope it helpshow many moles of Li2SO4 molecules are in 12.71g?
Answer:
₰₮₤₳V₤
Explanation:
First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.
For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.
Bolt can run at a top speed of 28 mph.
How many grams of water can be heated from 15.0 oC to 55oC using 4250.0 J.
Answer:
25.42 grams
Explanation:
The specific heat of water is 4.18 J/g •°C, so that means that it takes 4.18 joules of energy to raise one gram of water 1 °C.
Change in temp = 55 - 15 = 40°C
So we can calculate how much energy it would take to raise the temp of one gram of water by one degree using the following
(4.18 J/g•°C) * (40°C) * (1 gram) = 167.2 J
So if it takes 167.2 J of energy to raise on gram of water 40°C, we now we can calculate the amount of grams of water that can heated with 4250 J of energy
(4250 J) ÷ (167.2 J) = 25.42 grams of water can be heated from 15°C to 55°C
How many liters of phosphine are produced when 34 L of hydrogen reacts with an excess of phosphorus under STP?
Answer:
22.67 L of PH₃
Explanation:
The balanced equation is:
[tex]P_4 (s) + 6H_2(g) \to 4PH_3(g)[/tex]
From the equation:
[tex]34 L \times \dfrac{1 \ mol \ of H_2 }{22.4 \ L \ H_2} \times \dfrac{4 \ mol \ of \ PH_3}{6 \ mol \ H_2} \times \dfrac{22.4 \ L \ PH_3}{1 \ mol \ PH_3}[/tex]
= 22.67 L of PH₃
. Explain why some desert animals excrete uric acid rather than ammonia.
(2 marks)
Answer:
AFAIK
Explanation:
uric acid is much less toxic than ammonia, hence bigger concentrations of it are tolerated in the body. This means you can excrete it while excreting very little water - beneficial wherever water's not abundant.
There's a tradeoff though, uric acid requires more energy to synthesize than ammonia, so pretty much all fish, say, excrete ammonia rather than uric acid - it's no problem to dilute ammonia since there's no water shortage.
How many moles of nitrogen are required to produce 13.5 g of NH 3?
Answer:
number of moles of (N) = 0.794 moles
Explanation:
From the given information:
no of moles of nitrogen (N) = (unknown)???
mass of nitrogen = 13.5 g
molar mass of NH3 = 14 +( 1 × 3) = 17 g/mol
To calculate the no of moles of N, we have:
number of moles of (N) = mass of N/molar mass
number of moles of (N) = 13.5 g/17 g/mol
number of moles of (N) = 0.794 moles
Colligative properties of solutions include all of the following except: a. an increase in the osmotic pressure of a solution upon the addition of more solute b. elevation of the boiling point of a solution upon addition of a solute to a solvent c. an increase of reaction rate with increase in temperature d. depression of the freezing pont of a solution upon addition of a solute to a solvent e. depression of vapor pressure upon addition of a solute to a solvent
Answer:
Option C, an increase of reaction rate with increase in temperature
Explanation:
Colligative properties are as follows
a) Decrease of vapor pressure
b) Increase of boiling point
c) Reduction of freezing point
d) Increase of osmotic pressure
There is no impact on reaction rate and hence it is not a colligative property.
Thus, option c is the right choice
An increase of reaction rate with increase in temperature isn't an example
of colligative properties of solutions
Colligative properties of solutions depend on the ratio of the number of
solutes to that of the solvent(concentration) and not on the nature of the
substances involved.
Examples of colligative properties include vapor pressure lowering, boiling
point elevation, freezing point depression, and osmotic pressure. Increase of
reaction rate with increase in temperature is therefore not an example of
colligative properties of solutions.
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How/what do I answer this?--> "heat of the chemical reactions"
like this is the question :/
Answer:
The heat of reaction is the energy that is released or absorbed when chemicals are transformed in a chemical reaction. It describes the change of the energy content when reactants are converted into products.
Explanation:
Yeah, that would confuse me a bit but then you read it and then you will get that answer above! Have a great rest of your day!
What type of compound is a salt
Answer: Salt is an ionic compound.
Explanation:
A compound formed by transfer of electrons from one atom to another is called an ionic compound.
For example, chemical formula of salt is NaCl (also called table salt).
Salt is formed when sodium (atomic no. 11) donates its one valence electron to chlorine (atomic no. 17). As a result, sodium ion and chlorine ion chemically combine together and form the compound NaCl.
Thus, we can conclude that salt is an ionic compound.
What are the components of DNA?
A. ribose sugar, cytosine, guanine, adenine, thymine, and phosphate group
B. ribose sugar, cytosine, guanine, adenine, uracil, and phosphate group
C. deoxyribose sugar, cytosine, guanine, adenine, thymine, and phosphate group
D. deoxyribose sugar, cytosine, guanine, adenine, uracil, and phosphate group
Answer:
C
Explanation:
A-T G-C
Answer:
C
Explanation:
EDGE 2022
Write the balanced half-reaction that occurs at the anode in a lead-acid (storage) battery during discharge. Phases are optional. anode half-reaction: Write the balanced half-reaction that occurs at the cathode in a lead-acid (storage) battery during discharge. Phases are optional. cathode half-reaction: Write the balanced overall cell reaction that occurs in the lead-acid (storage) battery during discharge. Phases are optional. overall cell reaction:
Answer: Anode: [tex]Pb+SO_4^{2-}\rightarrow PbSO_4+2e^-[/tex]
Cathode: [tex]PbO_2+4H^++SO_4^{2-}+2e^-\rightarrow PbSO_4+2H_2O[/tex]
Overall cell reaction : [tex]Pb+2SO_4^{2-}+PbO_2+4H^+\rightarrow 2PbSO_4+2H_2O[/tex]
Explanation:
Lead storage battery is a secondary cell used in automobiles and invertors. The anode is made up of lead and undergoes oxidation during discharging and cathode is made up of lead oxide and acts as cathode during discharging. The electrolyte used is dilute .
Lead storage battery acts as electrochemical cell while discharging.
Discharging reaction for Anode:
Discharging reaction for Cathode: [tex]PbO_2+4H^++SO_4^{2-}+2e^-\rightarrow PbSO_4+2H_2O[/tex]
Overall cell reaction : [tex]Pb+2SO_4^{2-}+PbO_2+4H^+\rightarrow 2PbSO_4+2H_2O[/tex]
A lead storage battery is an energy storage device. At the anode lead and sulfate ion reacts to produce Lead(II) sulfate and release two electrons.
What are anode and cathode?In secondary cells or the recharge-discharge cells during recharge, the positive electrode is the anode, while during discharge cathode is the positive electrode.
The anode (lead) of the cell undergoes an oxidation reaction during the discharge, whereas the lead oxide or the cathode undergoes reduction.
The discharging reaction at the anode of the cell is given as,
[tex]\rm Pb + SO_{4}^{2-} \rightarrow PbSO_{4} + 2e^{-}[/tex]
The discharging reaction at the cathode of the cell is given as,
[tex]\rm PbO_{2} + 4H^{+} + SO_{4}^{2-} + 2 e^{-} \rightarrow PbSO_{4} + 2H_{2}O[/tex]
The overall cell reaction is given as,
[tex]\rm Pb + 2SO_{4}^{2-} + PbO_{2} + 4H^{+} \rightarrow 2PbSO_{4} + 2H_{2}O[/tex]
Therefore, the gain and loss of electrons are represented at the cathode and the anode of the cell.
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For a chemical reaction, the activation energy for the forward reaction is +181 kJ and the activation energy for the backward reaction is +62 kJ. What is the overall energy change for the forward reaction?
Given :
For a chemical reaction, the activation energy for the forward reaction is +181 kJ and the activation energy for the backward reaction is +62 kJ.
To Find :
The overall energy change for the forward reaction.
Solution :
The overall energy change for the forward reaction is :
[tex]\Delta E_f = E_f - E_b\\\\\Delta E_f = 181 - 62 \ Kj\\\\\Delta E_f = 119 \ Kj[/tex]
Therefore, the overall energy change for the forward reaction is 119 Kj.
Ethyne or acetylene can be hydrogenated to change from the triple bonded C2H2 to the double-bonded C2H4. Adding hydrogens in organic chemistry is called reduction. Adding and removing hydrogens are important steps in chemical manufacturing. Calculate the value of ΔS° for the catalytic hydrogenation of acetylene to ethene,
C2H2 (g) + H2 (g) --> C2H4 (g)
A. +18.6 J/mol K
B. -18.6 J/mol K
C. -112.0 J/mol K
D. +112.0 J/mol K
The correct answer is
C. -112.0 J/mol K
Calculate the maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V. Al(s) |Al3+(aq) || H+(aq) | O2(g) |Pt. Note that O2 is reduced to H2O.
Answer:
W = 615.91 kJ
Explanation:
We need to use the following expression:
W = ΔG° * mol (1)
But in order to determine the ΔG° we need the following expression:
ΔG° = -n * F * E° (2)
Where F is a constant and is 96,500 J/V mol
n is the number of transferred electrons in the reaction. As we are passing from Al to Al³⁺ we can say that the number of electrons are 3.
Finally to get the moles, we need the the atomic weight of aluminum which is 26.98 g/mol, so the moles:
moles = m/MM (3)
Let's calculate the moles of aluminum:
moles = 50 / 26.98 = 1.85 moles of aluminum
Now let's calculate the gibbs energy using (2):
ΔG° = -3 * 96,500 * 1.15
ΔG° = -332,925 J or simply -332.925 kJ/mol
Finally, using (1) we can determine the work done:
W = 332.925 * 1.85
W = 615.91 kJHope this helps
The maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V will be 615.91 kJ
What is cell potential ?The cell potential, Ecell, is the measure of the potential difference between two half cells in an electrochemical cell.
Expression for work done ;
W = ΔG° x mol (1)
But, to determine the ΔG°
ΔG° = -n x F x E° (2)
Where,
F is a constant and is 96,500 J/V moln is the number of transferred electrons in the reaction.(As there is variation from Al to Al³⁺ the change in number of electrons are 3)
To get the moles,
moles = m/MM (3)
moles = 50 / 26.98 = 1.85 moles of aluminum
Now,
ΔG° = -3 x 96,500 x 1.15
ΔG° = -332,925 J
= -332.925 kJ/mol
Now, using (1) we can determine the work done:
W = 332.925 x 1.85
W = 615.91 kJ
Hence, The maximum work available from 50.0 g of aluminum in the following cell when the cell potential is 1.15 V will be 615.91 kJ
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intermolecular forces between particles are
Explanation:
Intermolecular forces hold multiple molecules together and determine many of a substance's properties. All of the attractive forces between neutral atoms and molecules are known as van der Waals forces, although they are usually referred to more informally as intermolecular attraction.
Intermolecular forces are the forces of attraction or repulsion which act between neighboring particles (atoms, molecules, or ions ). These forces are weak compared to the intramolecular forces, such as the covalent or ionic bonds between atoms in a molecule.
Question 4 (10 points)
If a sollition has a pOH of 5.2 the [OH-] of the solution is
оа
6x 10-6 M
Ob
6.3 x 10-6 M
Oc
1.58 x 10-5M
Od
2x10-5M
Answer:
Explanation: