So we need to compare two numbers. This means telling which is smaller and which is greater or if they are equal. In this case we have decimal numbers but it's more comfortable to work with integers so I'm going to multiply both by the same number in order to make them integers:
[tex]\begin{gathered} A=0.432\cdot1000=432 \\ B=0.437\cdot1000=437 \end{gathered}[/tex]Since both a and b where multiplied by the same number then the result of the comparison between A and B is the same as that between a and b. So we have 432 and 437. Let's make a substraction:
[tex]A-B=432-437=-5[/tex]The result is a negative number which means that:
[tex]A-B<0[/tex]Then we add B at both sides of this inequality:
[tex]\begin{gathered} A-B+B<0+B \\ AAs I said before the comparison between A and B is the same as that between a and b which means that:[tex]aAnd that last inequality is the answer.A recipe that uses 1/2 pound of almonds makes 5/6 cup of almond butter. Which is a reasonable estimate for the amount of almond butter the recipe makes per pound of almonds?What amout of almond butter does the recipe make per pound of almonds?____ cup(s) of almond butter per pound of almonds
The given information is:
1/2 pound of almonds makes 5/6 of almond butter.
Since 1 pound is double of 1/2 pound, we will need to multiply the amount of almond butter by 2 to find the almond butter that 1 pound can make.
Multiply the amount of almond butter by 2:
[tex]2\times\frac{5}{6}[/tex]The reason for this multiplication is that to find the amount of almond butter that 1 pound makes, we need double of what 1/2 can make.
Solving the multiplication:
[tex]2\times\frac{5}{6}=\frac{2\times5}{6}[/tex]Since 2x5 is equal to 10:
[tex]2\times\frac{5}{6}=\frac{10}{6}[/tex]1 pound of almonds makes 10/6 cups of almond butter.
Answer: 10/6 cups of almond butter per pound of almonds
Use prime factorization to reduce each fraction 1. 22/165 2. 35/210
Lets find the prime factorization of 22, 165, 35 and 210. Prime factorization of a number is breaking a number down into the set of prime numbers which multiply together to result in the original number.
The prime factorization of the number 22 is:
[tex]22=2\times11[/tex]Similarly, for 165, 35 and 210 we have
[tex]\begin{gathered} 165=3\times5\times11 \\ 35=5\times7 \\ 210=2\times3\times5\times7 \end{gathered}[/tex]Then, we can solve the given questions.
Question 1.
[tex]\frac{22}{165}=\frac{2\times11}{3\times5\times11}[/tex]so we can cancel out the number 11 and get
[tex]\frac{22}{165}=\frac{2}{3\times5}=\frac{2}{15}[/tex]Then, the answer is
[tex]\frac{2}{15}[/tex]Question 2.
[tex]\frac{35}{210}=\frac{5\times7}{2\times3\times5\times7}[/tex]and we can cancel out the number 5 and 7, then we obtain
[tex]\frac{35}{210}=\frac{1}{2\times3}[/tex]then, the answer is
[tex]\frac{1}{6}[/tex]I need help with a graph problem please that I am stuck on.
Solution:
First we have to derive the equation of the graph plot.
The general equation of an absolute value function is expressed as
[tex]\begin{gathered} y=a|x-h|+k\text{ --- equation 1} \\ \text{where} \\ (h,k)\text{ is the coordinate of the vertex of the function } \end{gathered}[/tex]step 1: Determine the coordinates (h,k) of the vertex of the graph.
The vertex of the function is the point at which the graph changes direction.
In tha above plot, the vertex of the plot is (-3,4).
Thus,
[tex]\begin{gathered} h=-3 \\ k=4 \end{gathered}[/tex]step 2: Substitute the respective values of -3 and 4 for h and k into equation 1.
Thus,
[tex]\begin{gathered} y=a|x-h|+k \\ \Rightarrow y=a|x-(-3)|+4\text{ ---- equation 2} \\ \end{gathered}[/tex]step 3: Select any point (x,y) on the graph plot, to evaluate a.
Thus, using the point (1,0), we have
[tex]\begin{gathered} y=a|x+3|+4 \\ x=1,\text{ y=0} \\ \Rightarrow0=a|1+3|+4 \\ -4=|4|a \\ \Rightarrow a=-1 \end{gathered}[/tex]step 4: Substitute the obatined value of a into equation 2.
Thus,
[tex]y=-|x+3|+4\text{ ----- equation 3}[/tex]Thus, the equatioin of the graph is evaluated to be
[tex]y=-|x+3|+4[/tex]A) Evaluate f(4).
To evaluate f(4), substitute the value of 4 for x into the derived equation.
Thus,
[tex]\begin{gathered} y=-|x+3|+4 \\ x=4 \\ \Rightarrow y=-|4+3|+4 \\ \therefore y=-3 \end{gathered}[/tex][tex]f(4)=-3[/tex]B) Solve for f(x)=2.
To solve, we have
[tex]\begin{gathered} -|x+3|+4=2 \\ \text{subtract 4 from both sides of the equation} \\ -|x+3|+4-4=2-4 \\ -|x+3|=-2 \\ \text{divide both sides by -1} \\ \frac{-|x+3|}{-1}=-\frac{2}{-1} \\ \Rightarrow|x+3|=2 \\ \text{When }x+3=-2 \\ x=-2-3 \\ \Rightarrow x=-5 \\ \text{when }x+3=2 \\ x=2-3 \\ \Rightarrow x=-1 \end{gathered}[/tex]Thus, we have
[tex]x=-5;-1[/tex]Hello! I got -560 just want to confirm my answer. Thanks!
Explanation
We are given the following series:
[tex]12+4-4-12-20-...[/tex]We are required to determine the sum of the first 14 terms of the given series.
This is achieved thus:
We know that the sum of n terms of a series is given as:
[tex]\begin{gathered} S_n=\frac{n}{2}[2a+(n-1)d] \\ where \\ a=first\text{ term} \\ d=common\text{ difference} \\ n=number\text{ of terms} \end{gathered}[/tex]Therefore, we have:
[tex]\begin{gathered} S_n=\frac{n}{2}[2a+(n-1)d] \\ where \\ a=12 \\ d=4-12=-8 \\ n=14 \\ \\ \therefore S_{14}=\frac{14}{2}[2\cdot12+(14-1)-8] \\ S_{14}=7[24+(13)-8] \\ S_{14}=7(24-104) \\ S_{14}=7\cdot-80 \\ S_{14}=-560 \end{gathered}[/tex]Hence, the answer is:
[tex]S_{14}=-560[/tex]Which problem could be solved with the expression 5 (2 + 4) = 6?Choose 1 answer:Hayden made 2 bracelets before school and 4 after school each day for 5 days. Then he split thebracelets into 6 equal groups. How many bracelets did Hayden have in each group?(вShadi is building a new back deck. He puts 2 nails and 4 screws in each board. He did this to 5boards. How many total screws and nails did he use?Khai, the dog, ate 2 bones on Monday, 4 bones on Tuesday and 6 bones on Wednesday. OnThursday, she ate 5 times more bones than the other days combined. How many bones did Khai eaton Thursday?Stuck? Review related articles/videos or use a hint.Report a problem
Let us attempt to solve the options to check which one will give the expression
[tex]5\times(2+4)\div6[/tex]OPTION A:
If Hayden makes 2 bracelets before school and 4 after school daily, then the bracelets she makes daily is gotten by
[tex]2+4[/tex]In 5 days, the number of bracelets will be the expression above multiplied by 5:
[tex]5\times(2+4)[/tex]If she breaks the total bracelets into 6 groups, this means that we divide the expression above by 6:
[tex]5\times(2+4)\div6[/tex]This tallies with the expression in the question.
Hence, OPTION A is correct.
The markings on the number line are evently spaced. Label the other markings on the number line. + + А B C -30 0 F 45 A= B = C = D = E = F=can someone please tell me the answers
The points are evenly spaced at a distance of 15 units between each other, then when we go to the right side of the graph from 0 we increase 15 units until we reach the point E, 15 units further we get to the point F, then we have the following labels:
E = 15
F = 15 + 15 = 30
As we got the left side from 0, we subtract 15 units for each marking, then we get:
D = 0 -15 = -15
C = -30 -15 = -45
B = -45 - 15 = -60
A = -60 - 15
Write the equation containing the points (-2,4) and (1,10).
Answer:
y=2x+8
Explanation:
Given the two points:
[tex]\begin{gathered} (x_1,y_1)=(-2,4) \\ \mleft(x_2,y_2\mright)=\mleft(1,10\mright) \end{gathered}[/tex]In order to find the equation of the line connecting them, we employ the use of the two-points formula given below:
[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]Substitute the values:
[tex]\frac{y-4}{x-(-2)}=\frac{10-4}{1-(-2)}[/tex]Next, simplify:
[tex]\begin{gathered} \frac{y-4}{x+2}=\frac{6}{3}=2 \\ \implies y-4=2(x+2) \\ \implies y=2(x+2)+4 \\ \implies y=2x+4+4 \\ \implies y=2x+8 \end{gathered}[/tex]The equation containing the points (-2,4) and (1,10) is y=2x+8.
Celine is playing a game at the school carnival. There is a box of marbles, and each box has a white, a green, a blue, and an orange marble. There is also a fair 12-sided die labeled with the numbers 1 through 12. How many outcomes are in the sample space for pulling a marble out of the box and rolling the die?4832168
Multiply the number of possible outcomes of pulling a marble out times the number of possible outcomes o rolling the die to find the total amount of outcomes in the sample space.
There are 4 different possibilities of pulling a marble out of a box: white, green, blue and orange. Since the die has 12 outcomes, then the total amount of outcomes in the sample space is:
[tex]4\times12=48[/tex]The shaded area is 120T cm?, and the radius is 24 cm. Find X.
We will have the following:
[tex]A=(\frac{x}{2})\cdot r^2\Rightarrow120\pi=(\frac{x}{2})(24)^2[/tex][tex]\Rightarrow\frac{x}{2}=\frac{5\pi}{24}\Rightarrow x=\frac{5\pi}{12}[/tex][tex]\Rightarrow x\approx1.31[/tex]So, the value of x is approximately 1.31.
During a job interview, Pam Thompson is offered a salary of $32,000. The company gives annual raises a 4%. What will be Pam’s salary during her fifth year on the job? (Round time value factor to three decimal places and final answer to the nearest whole number.)
We will have the following:
First, we construct the equation that describes the scenario:
[tex]P(x)=32000(1+0.04)^x[/tex]Now, we will determine her salary at the 5th year at her job:
[tex]P(x)=32000(1+0.04)^5\Rightarrow P(5)=38932.89288[/tex][tex]\Rightarrow P(5)\approx38932.893[/tex]So, her salary after 5 years would be approximately $38933.
I have been struggling with this problem for around 2 hours and can’t seem to get it
the quotient rule say:
[tex](\frac{f(x)}{g(x)})^{\prime}=\frac{g(x)\cdot f^{\prime}(x)-f(x)\cdot g^{\prime}(x)}{(g(x))^2}[/tex]now we defined:
[tex]\begin{gathered} f(x)=-4x^2+16 \\ g(x)=(x^2+4)^2 \end{gathered}[/tex]and the derivative:
[tex]\begin{gathered} f^{\prime}(x)=-8x \\ g^{\prime}(x)=2\cdot(x^2+4)\cdot2x \\ g^{\prime}(x)=4x(x^2+4) \end{gathered}[/tex]so now we can replace on the quotient rule:
[tex]\frac{(x^2+4)^2\cdot(-8x)-4x(x^2+4)\cdot(-4x^2+16)}{(x^2+4)^4}[/tex]now we can use properties, like:
[tex](x^2+4)^2=x^4+8x+16[/tex]An ostrich ran 4,200 meters to the west at a constant velocity. it ran that distance in 1,200 seconds. what was it's velocity?
distance : 4,200 meters
time : 1,200 seconds
To find the velocity we have to apply the next formula:
Velocity = Distance / time
Replacing with the values given:
Velocity = 4,200 m / 1,200 sec = 3.5 meters per second
Velocity = 3.5 m/sec
9Find the percentage change from the first quantity to the second quantity:From 60 km/h to 45 km/h.Answer:%
To calculate the percentage change;
From 60km/h to 45km/h is a decrease
So we will calculate the decrease = 60 - 45 =15
Divide 15 by the original value which is 60 and then multiply by 100%
That is;
Percentage change = 15/60 x100%
=25%
Can you please help me out with a question
To find the point S we first need to find the equation of the circle which is given by:
[tex](x-h)^2+(y-k)^2=r^2[/tex]where (h,k) is the center and r is the radius.
In this case we don't have the radius but we know that the radius is the distance between the center and any point on the circle, then the radius is equal to the distance:
[tex]\begin{gathered} r=d(A,R)=\sqrt[]{(5-3)^2+(4-(-1))^2} \\ =\sqrt[]{4+25} \\ =\sqrt[]{29} \end{gathered}[/tex]hence the equation of the circle is:
[tex](x-3)^2+(y+1)^2=29[/tex]Now that we have this equation we need to determine which of the options given fullfil the equation. From the options given we conclude that the only point that fullfils the equation is the point D, this come from the fact that:
[tex]\begin{gathered} (1-3)^2+(-6+1)^2=29 \\ 4+25=29 \\ 29=29 \end{gathered}[/tex]Therefore this point is in the circle. Therefore we conclude that the coordinates of point D are (1,-6) and the answer is D.
This can be seen in the graph below:
Pressure (torr)Volume (mL)Which statement accurately represents the relationshipbetween pressure and volume ?75030O As pressure increases, volume increases.As pressure decreases, volume decreases.95022O As pressure increases, volume decreases.As pressure increases, volume stays constant.115019135015150013165010
The equation that describes the relationship between pressure and volume is
[tex]P=\frac{n\cdot R\cdot T}{V}[/tex]As you can observe, the pressure and the volume are inversely proportional, which means, as pressure increases, volume decreases.
Therefore, the answer is As pressure increases, volume decreases.which statement is true?6 is 4 times as many as 26 is 3 times as many as 26 is 2 times as many as 26 is 12 times as many as 2
6 is 3 times as many as 2, because:
[tex]\begin{gathered} 6=3+2 \\ 6=3+3 \end{gathered}[/tex]I am confused. Please help. Give answer options and simple explanation. Thanks!
Given the functions
[tex]\begin{gathered} f(x)=2x^2+4x-5 \\ g(x)=6x^3-2x^2+3 \end{gathered}[/tex][tex]\begin{gathered} (f-g)(x)=f(x)-g(x) \\ =2x^2+4x-5-(6x^3-2x^2+3) \\ =2x^2+4x-5-6x^3+2x^2-3 \\ =-6x^3+2x^2+2x^2+4x-5-3 \\ =-6x^3+4x^2+4x-8 \end{gathered}[/tex]The final answer is OPTION C
9) 59 is 93 percent of what?
93 Let the unknown number be X,
( 59/ X ) = 93 /100
Cross - multiply,
59 x 100 = 93 x x
x = ( 59 x100) divided by 93
x= 5900 / 93
x = 63.44 _
Answer:
Step-by-step explanation:
59 = 93%(X)
59 = 93/100*(x)
59*100 = 93(x)
5900/93 = x
63.44 = x
Hence 59 is 93 percent of 63.44
Given the following graph of f (x), what is f (4)?
*graph included*
When function of x is the line on the graph with the equation function of x =-3/2x+1, the value of f(4) is -5.
Given that,
In the picture we have graph with a line function of x.
We have to find what is the value of f(4).
By seeing the graph,
We have points (-2,4) and (-4,7)
We must determine the line's equation.
That is y=mx+b
Slope of the line m is rise/run
m=7-4/-4-(-2)
m=3/-2
m=-3/2
Now,
4=-3/2(-2)+b
4=3+b
b=4-3
b=1
The equation of the line is y=-3/2x+1
We can write as function of x =-3/2x+1
Then Take x=4
f(4)=-3/2(4)+1
f(4)=-6+1
f(4)=-5
Therefore, The value of f(4) is -5 when the function of x is the line on graph that is function of x =-3/2x+1.
To learn more about line visit: https://brainly.com/question/17188072
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Hi i need some help on question 11 b and c. I have already done a
ANSWER:
a. 16.27 cm^3
b. 4.3 cm
c. 325.4 seconds
STEP-BY-STEP EXPLANATION:
The first thing is to calculate the value of the volume, which is the sum of the volume of each part, like this:
[tex]\begin{gathered} V=V_t+V_c+V_s \\ r=\frac{d}{2}=\frac{2.6}{2}=1.3 \\ V_t=A_b\cdot\frac{h}{3}=\pi\cdot(r)^2\cdot\frac{h}{3}=3.14\cdot(1.3)^2\cdot\frac{1.2}{3}=2.12cm^3 \\ V_c=A_b\cdot h=\pi\cdot(r)^2\cdot h=3.14\cdot(1.3)^2\cdot1.8=9.55m^3 \\ V_s=\frac{4}{6}\cdot\pi\cdot r^3=\frac{4}{6}\cdot3.14\cdot(1.3)^3=4.6cm^3 \\ V=V_t+V_c+V_s \\ V=2.12+9.55+4.6 \\ V=16.27cm^3 \end{gathered}[/tex]The volume of the upper container is 16.27 cm^3, and being symmetrical, it is the same for the bottom container.
At the moment that all the sand finishes going to the bottom container, the height will be the sum of the heights in each case.
Then:
[tex]\begin{gathered} h=1.2+1.8+1.3 \\ h=4.3\text{ cm} \end{gathered}[/tex]Therefore, the height is 4.3 centimeters
To reach that height, all the sand had to be passed from one side to the other, therefore, we can calculate the time as follows:
[tex]\begin{gathered} t=\frac{16.27cm^3}{0.05\frac{cm^3}{s}} \\ t=325.4\text{ sec} \end{gathered}[/tex]It would take a time of 325.4 seconds
I need help with a math homework0.25kg=______g
We know that 1 kilogram is equivalent to 1,000 grams. This our conversion factor, knowing this, we transform 0.25 kg.
[tex]0.25\operatorname{kg}\cdot\frac{1,000gr}{1\operatorname{kg}}=250gr[/tex]Therefore, the answer is 250 grams.suppose they are a T V cost in an election between three Canadians then who is Garza and we see to be decided by polarity of the first 55 votes are counted the Titleist are as followed
a) We have the votes for 55 people out of 80.
We have to find the minimum number of votes needed by Donahue to be sure that he will win the election.
There are 80 - 55 = 25 votes remaining.
Donahue has 24 votes already. The second candidate in number of votes has 18 votes, which is a difference of 6 votes.
We can think of a situation where the remaining votes are given to this two candidates and both have the same votes.
This would mean an amount of 24 + 18 + 25 = 67 votes.
Then, they won't have the same votes but we can think of Donahue having 67/2 = 33.5 ≈ 34 votes, and Garza having 33.
Then, this is the most extreme situation where Donahue wins by one vote.
We can then calculate the difference of votes he needs as 34 - 24 = 10 votes.
b) We can think again the same situation, but with Garza having 34 votes and Donahue having 33 votes.
This the extreme situation where Garza wins by the minimum difference.
Then, Garza would have to add 34 - 18 = 16 votes at least to win in this situation.
Answer:
a) Donahue needs 10 more votes to be sure he wins the election.
b) Garza needs at least 16 votes to be sure he wins the election.
Which of the following would be the best equation for the function of the values for Janet’s reading?A) p = 6hB) p = 20hC) h = 20pD) 20 + p = h
In order to obtain the best equation for the function of the values for Janet’s reading, we will apply the equation of a straight line between two points.
The formula to calculate the equation of a line between two points is,
[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]Let us now pick any two points from the table given
[tex]\begin{gathered} (x_1,y_1)=(1,20) \\ (x_2,y_2)=(6,120) \end{gathered}[/tex][tex]\begin{gathered} \text{where,} \\ p=y \\ h=x \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} \frac{y-20}{x-1}=\frac{120-20}{6-1} \\ \end{gathered}[/tex]Simplify
[tex]\begin{gathered} \frac{y-20}{x-1}=\frac{100}{5} \\ \frac{y-20}{x-1}=20 \\ y-20=20(x-1) \\ y=20(x-1)+20=20x-20+20=20x \\ y=20x \\ \therefore p=20h \end{gathered}[/tex]Hence, the answer is
[tex]p=20h\text{ (OPTION B)}[/tex]The following is the cost function for natural gas for the city where Greg lives. Greg's natural gas bill last month was $51.54. How many therms did Greg use last month? Round the answer to the nearest tenth of a therm (one decimal place). Only input the number. Do not input any unit. Example: 89.3
Kauro, this is the solution:
This is the cost function for natural gas for the city where Greg lives:
• c (t) = 16.74 + 0.742t
Now we replace c (t) by 51.54 to solve for t, as follows:
51.54 = 16.74 + 0.742t
Subtracting 16.74 at both sides:
51.54 - 16.74 = 16.74 + 0.742t - 16.74
34.8 = 0.742t
Dividing by 0.742 at both sides:
0.742t/0.742 = 34.8/0.742
t = 46.9 therms
The correct answer is 46.9
What is the solution to the equation -6 = x/8
Given equation is
[tex]\frac{x}{8}=-6[/tex]Performing the cross multiplication,
[tex]\begin{gathered} x=(-6)\times8 \\ =-48 \end{gathered}[/tex]Hence, the solution of the given equation is x=-48.
Solve the equation x(x+6) = 91 using completing the square, finding the square root, and solving. Put the equivalent equations in the appropriate order. |x+3 = 10 7 x² + 6x = 91 x= 7 or x = -13 x² - 6x +9 = 91 +9 x + 3 = 10 or x + 3 = -10 (x+3)² = 100
Solution
Given the equation below:
[tex]x(x+6)=91[/tex]Using the completing the square:
[tex]\begin{gathered} x(x+6)=91 \\ x^2+6x-91=0 \\ half\text{ the coefficient of x, square and add to both side} \\ x^2+6x=91 \\ x^2+6x+(3)^2=91+(3)^2 \\ (x+3)^2=91+9 \\ (x+3)^2=100 \end{gathered}[/tex]Square root both side of the equation
[tex]\begin{gathered} (x+3)^2=100 \\ \sqrt{(x+3)^2}=\pm\sqrt{100} \\ x+3=\pm10 \\ x=\pm10-3 \\ x=7,x=-13 \end{gathered}[/tex]Therefore the equivalent equations in the appropriate order is
At a flea market, used computer games are sold at the prices shown in the table below.Number of Games/Price ($)2/9.005/22.507/31.50Do the number of games and price form a proportional relationship?Choose the correct response.A.Yes. There is a constant of proportionality of $11.25.B.Yes. There is a constant of proportionality of $4.50.C.No. There is not a constant of proportionality.D.No. The slope is 4.5.
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y=kx
where k is the constant of proportionality
where k is the constant of proportionality
so
Verify
Let
x -----> numb
Find out the value of k in each case
er of games
y ----> price
Find out the value of k in each case
For x=2, y=9
k=y/x
k=9/2=$4.5 per game
For x=5, y=22.50
k=22.5/5=$4.50 per game
For x=7, y=31.50, because the value ok is the smaamef K
k=31.50/7=$4.50 per game
that means
Yes , Irs a proportional relationship
the answer is the option BPR = 9x -31 and QR = 43: Find xQ is the midpoint of PR
We can model the situation as:
Since Q is the midpoint of PR, QR and PQ have the same length, so PQ is also equal to 43.
Now, we can formulate the following equation:
PR = PQ + QR
So, replacing PR by 9x-31, PQ by 43 and QR by 43, we get:
9x - 31 = 43 + 43
9x - 31 = 86
Solving for x:
9x - 31 + 31 = 86 + 31
9x = 117
9x/9 = 117/9
x = 13
Answer: x = 13
With the enthusiasm for statistics at an all-time high, students were found sprinting from their vehicle to the classroom just to be the first person to grab a seat. The times of the students were recorded (in seconds) and given in the stemplot below.What is the 9th fastest time a student took to go from his/her vehicle to a seat in the classroom? Make sure to use labels and avoid the use of abbreviations
The 9th fastest time is 28 seconds
Explanation:We have been given a stem plot diagram of the time it took the students to grab a seat.
We need to find the 9th fastest time
To do this, we first need to list out the time in seconds:
13, 14, 15, 19, 19
21, 27, 27, 28
32
45, 49, 49
Since the right side is empty, there is no list of 50 plus
62, 62
combining the list (all in seconds):
13, 14, 15, 19, 19, 21, 27, 27, 28, 32, 45, 49, 49, 62, 62
The lower the number, the faster the time. Since the list is ordered in ascending order, we will count to the 9th place
The ninth place on the list = 28
The 9th fastest time a student took to go from his/her vehicle to a seat in the classroom is 28 seconds
Factor completely 6x^2 -7x-20
Solution:
Given the expression;
[tex]6x^2-7x-20[/tex][tex]\begin{gathered} 6x^2-7x-20=6x^2-15x+8x-20 \\ \\ 6x^2-7x-20=3x(2x-5)+4(2x-5) \\ \\ 6x^2-7x-20=(2x-5)(3x+4) \end{gathered}[/tex]FINAL ANSWER:
[tex]\begin{equation*} (2x-5)(3x+4) \end{equation*}[/tex]