Can you please help me out with a question

Answers

Answer 1

ANSWER:

[tex]\text{center}=(\frac{3}{2},-\frac{1}{2})[/tex]

STEP-BY-STEP EXPLANATION:

The center of the circle would be the mean value between the end points, and we can calculate it like this:

[tex]\begin{gathered} (M_1,M_2)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ \text{replacing} \\ (M_1,M_2)=(\frac{-2+5_{}}{2},\frac{-4+3_{}}{2}) \\ (M_1,M_2)=(\frac{3_{}}{2},-\frac{1_{}}{2}) \end{gathered}[/tex]


Related Questions

Question 1.) d.) how to find instantaneous rate of change if x= 2pi

Answers

Explanation

We are given the following function:

[tex]f(x)=3\cos2x[/tex]

We are required to determine the instantaneous rate of change at x = 2π.

This is achieved thus:

[tex]\begin{gathered} f(x)=3\cos2x \\ \frac{\triangle f(x)}{\triangle x}=3\cdot-2\sin2x \\ \frac{\operatorname{\triangle}f(x)}{\operatorname{\triangle}x}=-6\sin2x \\ \text{ At the point }x=2\pi \\ \frac{\operatorname{\triangle}f(x)}{\operatorname{\triangle}x}=0 \end{gathered}[/tex]

Hence, the answer is:

[tex]\frac{\operatorname{\triangle}f(x)}{\operatorname{\triangle}x}=0[/tex]


HiThe scatter plot shows a hiker's elevation above sea level during a hike from the base to the
top of a mountain. The equation of a trend line for the hiker's elevation is y = 7.96x +676, where x
represents the number of minutes and y represents the hiker's elevation in feet. Use the equation of
the trend line to estimate the hiker's elevation after 170 minutes.

Answers

Answer:

2029.2 ft

Step-by-step explanation:

If x represents the number of minutes, then all you have to do is plug in 170 ( the number of minutes ) into the equation.

y = 7.96 (170) + 676

y = 1353.2 + 676

y = 2029.2

y represents the hiker's elevation in feet, so the answer would be 2029.2 ft.

let me know if anything is confusing :-))

What is the total paymentrequired to pay off a promissorynote issued for $700.00 at 12%ordinary interest and a 180-dayterm?A. $760.00B. $742.00C. $712.00D. $721.60

Answers

Given:

Promissory note issued for $700 at 12%.

[tex]P\text{ayment of 12\% for 700=}\frac{700\times\frac{6}{12}\times12}{100}[/tex][tex]\text{Payment for 12\% for 700= \$}42[/tex][tex]\text{Total payment required to pay off=}700+42[/tex][tex]\text{Total payment required to pay off= \$742}[/tex]

Therefore, Option B is the correct answer.

can anyone give me an example of plotting points with a real life word problem

Answers

Let's have an example of a seller that sells phones.

His salary have a fixed part of $50, and it increases by $2 by each phone he sells.

We want to find out how much will be his salary if he sells 5, 10 and 15 phones.

If we use the variable x to represent the number of phones sold, his salary (variable y) will be defined by the equation:

[tex]y=50+2x[/tex]

Now, using the values of x we want to calculate, we have that:

[tex]\begin{gathered} x=5\colon \\ y=50+2\cdot5=50+10=60 \\ \\ x=10\colon \\ y=50+2\cdot10=50+20=70 \\ \\ x=15\colon \\ y=50+2\cdot15=50+30=80 \end{gathered}[/tex]

We can plot these points to see how much his salary increases for each phone sold, and also we can have an idea of any point we want to find out:

Find the exact coordinates of the HOLE in this rational function: R (x)=×+1/×+(-1)

Answers

[tex]R(x)=\frac{x+1}{x-1}[/tex]

14. Log(x)=2meansa. x=10b. x=2^10c. x=10^2d. x=0e. none of the above

Answers

[tex]x=10^2\text{ (option C)}[/tex]Explanation:[tex]\begin{gathered} \log (x)\text{ = 2} \\ \log (x)\text{ }is\text{ }the\text{ }same\text{ }as\text{ }log_{\mleft\{10\mright\}}x \end{gathered}[/tex][tex]\begin{gathered} \log _{10}(x)\text{ = 2} \\ converting\text{ to exponential form:} \\ \text{the base 10 on the left side becomes the exponent on the other side of the equation} \\ x=10^2 \end{gathered}[/tex][tex]\begin{gathered} x\text{ = 100} \\ \text{From the options, the value of x is in exponents:} \\ x=10^2\text{ (option C)} \end{gathered}[/tex]

1)Lin solved the equation incorrectly. Find all the errors in her solution. (Select all appropriate answers.)Given to Step 1: Lin calculated 4 - 17 incorrectly; should be -13.Step 1 to Step 2: Lin distributed 8(x - 3) incorrectly; should be 8x - 3.Step 2 to Step 3: Lin calculated 8x - 24 + 7 incorrectly; should be 8x - 31.Step 3 to Step 4: Lin should have subtracted 8x from each side; should be 18x.What should Lin's answer have been ?8 ( x - 3 ) + 7 = 2x ( 4 - 17 )answer choices :x = 3/2 x = 1/2x = 1/5x = 1/3

Answers

Answer:

Given to Step 1: Lin calculated 4 - 17 incorrectly; should be -13.

Step 3 to Step 4: Lin should have subtracted 8x from each side; should be 18x.

Lin's answer should be x = 1/2

Explanation:

The initial expression is:

8(x - 3) + 7 = 2x(4 - 17)

So, the first error is in step 1, because 4 - 17 = - 13, then step 1 should be:

8(x - 3) + 7 = 2x(-13)

Then, we can apply the distributive property as:

8x - 8(3) + 7 = -26x

8x - 24 + 7 = -26x

We need to add similar terms:

8x - 17 = - 26x

Then, we can subtract 8x from both sides as follows:

8x - 17 - 8x = - 26x - 8x

-17 = -34x

Finally, we can divide by -34 as follows:

-17/(-34) = -34x/(-34)

1/2 = x

Therefore, the answers are:

Given to Step 1: Lin calculated 4 - 17 incorrectly; should be -13.

Step 3 to Step 4: Lin should have subtracted 8x from each side; should be 18x.

Lin's answer should be x = 1/2

What is the equation of a line that passes through the point (8, -4) and is parrallel to the line 6x + 2y = 9

Answers

The equation of a line that passes through the point (8, -4) and is parallel to the line 6x + 2y = 9 is 3x+y-20=0.

6x + 2y - 9 = 0

2y = -6x + 9

divide by 2 on both sides

y = -3x + 9/2

slope m = -3 and c = 9/2.

Line equation through point(8, -4) is y-y1 = m(x-x1)

y - (-4) = -3(x-8)

y+4=-3x+24

3x+y-20=0.

Therefore the equation of a line that passes through the point (8, -4) and is parallel to the line 6x + 2y = 9 is 3x+y-20=0.

Learn more about the equation and parallel here:

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High school band perform a concert on four different days bandsaw tickets each day as a fun raiser below the table shows the number of tickets sold in the amount collection of from sales slove with tablesHELPPP PLEASSEEEEEE

Answers

From the table given, Let's consider the third day

On the third day, 62 tickets were sold and $ 341 was collected

Then we can obtain the cost of a single ticket, which will be =

[tex]\frac{341}{62}[/tex]

= $ 5.5

So 1 ticket cost $5.5

Then we can fill in the table

PART A

PART B

The equation that can be used to find y, the amount of money collected can be obtained since we know the cost of a single ticket which is $ 5.5

[tex]\begin{gathered} y\text{ = 5.5x} \\ \text{where x is the number of tickets sold} \end{gathered}[/tex]

PART C

A dependent variable represents a quantity whose value depends on how the independent variable is manipulated.

From the equation

y = 5.5 x

y = Amount of money collected

x = Number of tickets

Since y (Amount collected) depends on x (the number of tickets sold)

y is the dependent variable

x is the independent variable

Part D

The relationship is that:

The amount of money that will be collected is dependent on the number of tickets sold.

since each ticket costs $5.5, then the amount realized is $5.5 multiplied by the number of tickets

Entrance Ticket on Translations Sarah graphed a triangle with vertices X (3,3) Y (4,1) Z (1,1). She asked her classmate Paul to translate the triangle (x-4) (y+2). Paul stated that the triangle will move down by 4 and right by 2 putting the triangle in the 4th quadrant. Graph the translation to see if Paul is correct? Explain your reasoning. Your explanation should include: • What is a translation? • Is Paul correct? Why or why not • Which direction should you move the triangle? • Which quadrant is the translation located?

Answers

The coordinates of the triangle XYZ are:

X(3,3)

Y(4,1)

Z(1,1)

The translation to perform is (x-4) and (y+2)

Translations are rigid transformations of a figure, this means that the triangle will move but won't change its shape or size.

A translation over the x axis results in a horizontal movement.

If you subtract a factor k x-coordinate, the movement will be to the left.

If you add the factor k x-coordinate, the movement will be to the rigth.

In this example the translation over the x-coordinate is (x-4) → 4 unit are being subtracted to the x-coordinate of each point, this results in a horizontal movement 4 units to the left

A translation over the y axis results in a vertical movement.

If you subtract a factor m from the y-coordinate, the movement will be downwards.

If you add the factor m from the y-coordinate, the movement will be upwards

In this example the translation over the y-coordinate is (y+2)→ 2 units were added to the y-coordinate, this results in a vertical movement 2 units up.

Paul moved the triangle 4 units down and 2 units right, he performed the wrong translation.

THe triangle was moved "left" and "up", the translation will be located in the second quadrant

Lauren uses1/3cup of carrot juice for every2/3cup of apple juice to make a fruit drink.Enter the number of cups of carrot juice Lauren uses for 1 cup of apple juice,

Answers

1/3 cup of carrot juice ---------------------------------->2/3 cup of apple juice

x cups of carrot juice ----------------------------------->1 cup of apple juice

Using cross multiplication:

[tex]\frac{\frac{1}{3}}{x}=\frac{\frac{2}{3}}{1}[/tex]

solve for x:

[tex]\begin{gathered} x=\frac{\frac{1}{3}}{\frac{2}{3}} \\ x=\frac{3}{6} \\ x=\frac{1}{2} \end{gathered}[/tex]

She uses 1/2 cups of carrot juice for 1 cup of apple juice

i need help with question 2

Answers

To find the vertex (h,k), we have to find h using the following formula

[tex]h=-\frac{b}{2a}[/tex]

Where a = 1 and b = -10.

[tex]h=-\frac{-10}{2\cdot1}=5[/tex]

Then, we find k by evaluating the function when x = 5.

[tex]y=5^2-10\cdot5+9=25-50+9=-16[/tex]Hence, the vertex is (5,-16).

The axis of symmetry is given by the h coordinate of the vertex.

Hence, the axis of symmetry is x = 5.

The y-intercept is found when x = 0.

[tex]y=0^2-10\cdot0+9=9[/tex]The y-intercept is (0,9).

The x-intercepts are found when y = 0.

[tex]x^2-10x+9=0[/tex]

To solve this expression, we have to look for two numbers which product is 9, and which addition is 10. Those numbers are 9 and 1.

[tex](x-9)(x-1)=0[/tex]

Then, we use the zero product property to express both solutions

[tex]\begin{gathered} x-9=0\rightarrow x=9 \\ x-1=0\rightarrow x=1 \end{gathered}[/tex]Hence, the x-intercepts are (9,0) and (1,0).

The minimum value is defined by the k coordinate of the vertex.

Therefore, the minimum value of the function is -16.

The domain of the function would be all real numbers because quadratic functions don't have any domain restrictions.

[tex]D=(-\infty,\infty)[/tex]

The range of the function is determined by the vertex, given that the parabola opens upwards, then the range is

[tex]R\colon\lbrack-16,\infty\rbrack[/tex]

What is the location of the vertex on the parabola defined by f(x) = 2x2 + 14x + 11 and in what direction does the parabola open?

Answers

Vertex of a parabola

The point where the parabola intersects its axis of symmetry is called the "vertex" and is the point where the parabola is most sharply curved.

The given function is,

[tex]f(x)=2x^2+14x+11[/tex]

We will apply graphical method to obtain the solution to the vertex of the parabola

From the graph above, the vertex of the parabola is (- 3.5, - 13.5) which can also be represented into fraction as

[tex](-\frac{7}{2},-\frac{27}{2})[/tex]

And finally, the parabola opens upward.

Hence, the correct option is Option 2.

If you were to solve the following system by substitution, what would be the best variable to solve for and from what equation? 3x + 6v=9 2x – 10v=13

Answers

The best variable to solve is x=3-2v, after dividing the first equation by 3.

x=4, and v=-1/2

1) Solving that system by Substitution

2) Making then

x=3-2v

2x-10v=13

3) Plugging into the 2nd equation

2(3-2v)-10v=13

6-4v -10v=13

6-14v=13

-14v=13-6

-14v=7

v=-1/2

Plugging into the first equation

x=3-2v

x=3-2(-1/2)

x=3+1

x=4

48. Mrs. Dalton is selling pieces of cake at the school carnival. She baked 8 cakes and cut them
each into 12 pieces. If she sold 81 slices of cake, how many total cakes does she have left?
Circle the correct option.

Answers

Total  number of cakes left is 1.25 i.e. 1 and quarter.

Given,

Number of cakes = 8

Number of  pieces of each cake =12

Number of slices sold = 81

Then,

Total number of slices of cake = [tex]12*8=96[/tex]

Now,

number of remaining slices =[tex]96-81=15[/tex]

To find number of remaining cake left, divide number of remaining slices to the pieces of each cake.

Number of remaining cake = [tex]\frac{15}{12} =1.25[/tex]

Thus, total number of cakes left is 1.25 i.e. 1 and quarter.

To learn more about fractions refer here

brainly.com/question/25415062

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Hello, I'm stuck on this.Question: Calculate the slant height of this come, identified by letter X. Give your answer to the nearest whole number.

Answers

The right triangle formed is shown below

To find the slant height, x, we would apply the pythagorean theorem which is expressed as

hypotenuse^2 = one leg^2 + other leg^2

Looking at the triangle,

hypotenuse = x

one leg = 12

other leg = 7

By applying the pythagorean theorem,

x^2 = 12^2 + 7^2 = 144 + 49 = 193

x = square root of 193

x = 13.89

Rounding to the nearest whole number,

x = 14

-4 5/9 + (-1 2/3)[tex] - 4 \frac{5}{9} + ( - 1 \frac{2}{3} )[/tex]

Answers

Answer:

-6 2/9

Explanation:

Given the expression:

[tex]-4\frac{5}{9}+(-1\frac{2}{3})[/tex]

First, open the brackets:

[tex]=-4\frac{5}{9}-1\frac{2}{3}[/tex]

Next, change the fractions to improper fractions:

[tex]=-\frac{41}{9}-\frac{5}{3}[/tex]

Then, take the lowest common multiple of 9 and 3 to combine the fractions:

[tex]\begin{gathered} =\frac{-41-5(3)}{9} \\ =\frac{-41-15}{9} \\ =\frac{-56}{9} \\ =-6\frac{2}{9} \end{gathered}[/tex]

The result is -6 2/9.

write the er exponent expression forty-one to the seventh power

Answers

Write the exponential expression, forty one to the seventh power;

[tex]41^7[/tex]

Can you please help me with 28 Please give all end behavior such as limits and as_,_

Answers

Problem 28

We must describe the local and end behaviour of the function:

[tex]f(x)=\frac{x^2-4x+3}{x^2-4x-5}.[/tex]

First, we rewrite the polynomials in numerator and denominator in terms of their roots:

[tex]f(x)=\frac{(x-1)\cdot(x-3)}{(x+1)\cdot\mleft(x-5\mright)}\text{.}[/tex]

Local behaviour

We see that f(x) has a zero in the denominator for x = -1 and x = 5. The function f(x) has vertical asymptotes at these values. To analyze the local behaviour, we must compute the lateral limits for x → -1 and x → 5.

Limit x → - 1 from the left

Computing the limit from the left when x → -1, is equivalent to replacing x by -1 - ε and computing the limit when ε → 0:

[tex]\begin{gathered} \lim _{x\rightarrow-1^-}f(x)=\lim _{\epsilon\rightarrow0}f(-1-\epsilon) \\ =\lim _{\epsilon\rightarrow0}\frac{(-1-\epsilon-1)\cdot(1-\epsilon-3)}{(-1-\epsilon+1)\cdot(-1-\epsilon-5)} \\ =\lim _{\epsilon\rightarrow0}\frac{(-2)\cdot(-2)}{(-\epsilon)\cdot(-6)}\rightarrow+\infty. \end{gathered}[/tex]

In the last step, we can't throw the ε in the parenthesis different to zero.

Limit x → - 1 from the right

Computing the limit from the left when x → -1, is equivalent to replacing x by -1 + ε and computing the limit when ε → 0:

[tex]\begin{gathered} \lim _{x\rightarrow-1^+}f(x)=\lim _{\epsilon\rightarrow0}f(-1+\epsilon) \\ =\lim _{\epsilon\rightarrow0}\frac{(-1+\epsilon-1)\cdot(1+\epsilon-3)}{(-1+\epsilon+1)\cdot(-1+\epsilon-5)} \\ =\lim _{\epsilon\rightarrow0}\frac{(-2)\cdot(-2)}{(+\epsilon)\cdot(-6)}\rightarrow-\infty. \end{gathered}[/tex]

In the last step, we can't throw the ε in the parenthesis different to zero.

Limit x → 5 from the left

Computing the limit from the left when x → 5, is equivalent to replacing x by 5 - ε and computing the limit when ε → 0:

[tex]\begin{gathered} \lim _{x\rightarrow-1^-}f(x)=\lim _{\epsilon\rightarrow0}f(-1-\epsilon) \\ =\lim _{\epsilon\rightarrow0}\frac{(5-\epsilon-1)\cdot(5-\epsilon-3)}{(5-\epsilon+1)\cdot(5-\epsilon-5)} \\ =\lim _{\epsilon\rightarrow0}\frac{(+4)\cdot(+2)}{(+4)\cdot(-\epsilon)}\rightarrow-\infty. \end{gathered}[/tex]

In the last step, we can't throw the ε in the parenthesis different to zero.

Limit x → 5 from the right

Computing the limit from the left when x → 5, is equivalent to replacing x by 5 + ε and computing the limit when ε → 0:

[tex]\begin{gathered} \lim _{x\rightarrow-1^-}f(x)=\lim _{\epsilon\rightarrow0}f(-1-\epsilon) \\ =\lim _{\epsilon\rightarrow0}\frac{(5+\epsilon-1)\cdot(5+\epsilon-3)}{(5+\epsilon+1)\cdot(5+\epsilon-5)} \\ =\lim _{\epsilon\rightarrow0}\frac{(+4)\cdot(+2)}{(+4)\cdot(+\epsilon)}\rightarrow+\infty. \end{gathered}[/tex]

In the last step, we can't throw the ε in the parenthesis different to zero.

End behaviour

To describe the end behaviour of the function, we must compute the limits of the function when x → -∞ and x → +∞.

Limit x → -∞

[tex]\begin{gathered} \lim _{x\rightarrow-\infty^{}}f(x)=\lim _{x\rightarrow-\infty^{}}\frac{x^2-4x+3}{x^2-4x-5} \\ =\lim _{x\rightarrow-\infty}\frac{x^2-4x+3}{x^2-4x-5}=\frac{\lim _{x\rightarrow-\infty}\frac{x^2-4x+3}{x^2}}{\lim _{x\rightarrow-\infty}\frac{x^2-4x-5}{x^2}}=\frac{1}{1}=1. \end{gathered}[/tex]

To compute the limit we have divided numerator and denominator by x² and distributed the limit. The result of each limit is given by the leading term, which has the highest power of x.

Limit x → +∞

[tex]\begin{gathered} \lim _{x\rightarrow+\infty^{}}f(x)=\lim _{x\rightarrow+\infty^{}}\frac{x^2-4x+3}{x^2-4x-5} \\ =\lim _{x\rightarrow+\infty}\frac{x^2-4x+3}{x^2-4x-5}=\frac{\lim_{x\rightarrow+\infty}\frac{x^2-4x+3}{x^2}}{\lim_{x\rightarrow+\infty}\frac{x^2-4x-5}{x^2}}=\frac{1}{1}=1. \end{gathered}[/tex]

To compute the limit we have divided numerator and denominator by x² and distributed the limit. The result of each limit is given by the leading term, which has the highest power of x.

Answers

Local behaviour

The function f(x) has vertical asymptotes at x = -1 and x = 5.

[tex]\begin{gathered} \lim _{x\rightarrow-1^-}f(x)=+\infty \\ \lim _{x\rightarrow-1^+}f(x)=-\infty \\ \lim _{x\rightarrow5^-}f(x)=-\infty \\ \lim _{x\rightarrow5^+}f(x)=+\infty \end{gathered}[/tex]

End behaviour

[tex]\begin{gathered} \lim _{x\rightarrow-\infty^{}}f(x)=1 \\ \lim _{x\rightarrow+\infty^{}}f(x)=1 \end{gathered}[/tex]

Can you please help me

Answers

Step 1

A rectangle is a quadrilateral with the parallel opposite two sides being equal and with each vertex being 90°. The sum of angles in a rectangle is 360°. It has 2 diagonals.

Step 2

Derive an answer from the statement in step 1

The consecutive sides are perpendicular is the only right option.

Hence option D

Without graphing, identify the vertex, axis of symmetry, and transformations from the parent function f(x)= |x|y = |x-5|-1

Answers

Answer:

• Vertex: (5, –1)

,

• No symmetry

,

• Transformations: 5 units to the right, and 1 unit down.

Explanation

We are given the parent function f(x)= |x| and the transformed function:

[tex]y=|x-5|-1[/tex]

Thus, we can get the vertex considering that a function in the form:

[tex]y=|x\pm a|\pm b[/tex]

has a vertex at (+a, ±b).

Therefore, our vertex is at (5, –1). Additionally, as an absolute function has the form of a 'v', and as the vertex is at (5, –1) then it has no symmetry about the x-axis, nor y-axis, and nor about the origin, meaning it has no symmetry.

Finally, the transformation from the parent function is a shift 5 units to the right and one unit down.

Answer:

Answer:

• Vertex: (5, –1)

,

• No symmetry

,

• Transformations: 5 units to the right and 1 unit down.

Explanation

We are given the parent function f(x)= |x| and the transformed function:

Thus, we can get the vertex considering that a function in the form:

Has a vertex at (+a, ±b).

Therefore, our vertex is at (5, –1). Additionally, as an absolute function has the form of a 'v', and as the vertex is at (5, –1) then it has no symmetry about the x-axis, nor y-axis, nor about the origin, meaning it has no symmetry.

Finally, the transformation from the parent function shifts 5 units to the right and one unit down.

Step-by-step explanation:

If anyone can answer this question I will be surprised

Answers

A reflection through x-axis is the property to get a point and transform it like this:

[tex]\begin{gathered} P\rightarrow P^{\prime} \\ (x,y)\rightarrow(x,-y) \end{gathered}[/tex]

If we have point P = (3,4), its reflexion through x-axis will be:

[tex]\begin{gathered} P\rightarrow P^{\prime} \\ (x,y)\rightarrow(x,-y) \\ (3,4)\rightarrow(3,-4) \end{gathered}[/tex]

So our final answer will be:

[tex](3,-4)[/tex]

The table shows the predicted growth of bacteria after various numbers of hours. Write an explicit formula for the number of bacteria after n hours.Hours1 2 3 4 5(n)Numberof 33 57 81 105 129BacteriaΟ Α.a= 24+9O B. a = 9n+ 24OC. a, = 24n+33OD. a = 9n +33

Answers

Let a be the number of bacteria after one hour.

From the table, we get a=33.

The difference between 57 and 33 is 57-33= 24.

The difference between 81 and 57 is 81-57=24

Hence we get the common difference d=24.

The given data is in the arithmetic progression.

The formula for the nth term in the arithmetic progression is

[tex]a_n=a+(n-1)d[/tex]

Substitute a=33 and d=24, we get

[tex]a_n=33+(n-1)24[/tex]

[tex]a_n=33+24n-24[/tex]

[tex]a_n=24n+9[/tex]

Hence the required recursive equation is

[tex]a_n=24n+9[/tex]

Option A is correct.

BC and DE are chords of circle A, and BC DE. Which statement cannot be verifiedfrom the information that is given?BC DEBZBACZ ZDAEAABC = AADEZDAE CAD

Answers

Let's start in the first information:

[tex]arcBC\cong arcDE[/tex]

This can be verified, because, AC, AB, AD and AE are all congruent, because they are the radius of A and, since BC and DE are congruent, triangles ABC and ADE are also congruent.

Thus, the angles mBAC and mDAE are congruent. The measure of thesee angles are the same as the arcs BC and DE, so we verified this alternative.

In the explanation above, we also verified the second alternative:

[tex]\angle BAC\cong\angle DAE[/tex]

And we verified the third alternative:

[tex]\Delta ABC\cong\Delta ADE[/tex]

We are left with the last alternative:

[tex]\angle DAE\cong\angle CAD[/tex]

This can't be verified. One way of seeing that is that we can rotate triangle ABC around the circle without changing any of the given information, however this changes mCAD.

So the only statement that cannot be verified from the given information is the last one:

[tex]\angle DAE\cong\angle CAD[/tex]

Find the first five terms of the sequence
defined recursively as follows: t₁ = 1,
tn = 3(t(n-1)), n≠1, n is a natural number.

Answers

Answer:

1, 3, 9, 27, 81

Step-by-step explanation:

using the recursive rule

[tex]t_{n}[/tex] = 3 [tex]t_{n-1}[/tex] with t₁ = 1 , then

t₂ = 3 × t₁ = 3 × 1 = 3

t₃ = 3 × t₂ = 3 × 3 = 9

t₄ = 3 × t₃ = 3 × 9 = 27

t₅ = 3 × t₄ = 3 × 27 = 81

the first 5 terms are 1, 3, 9, 27, 81

Write an equation for the line parallel to g(x)= -2x-6 and passing through the point (7, 4) Write the answer in slop intercept form.

Answers

The slope-intercept form is:

[tex]y=mx+c[/tex]

So first we will find the gradient:

Parallel lines have the same gradient:

[tex]\begin{gathered} g(x)=-2x-6 \\ \text{The gradient from the equation above is -2} \end{gathered}[/tex]

So now that we know the gradient of the line as -2, we will then find the equation of the line using the formula below as it passes through (7,4):

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{From (7,4)} \\ x_1=7,y_1=4 \\ y-4=-2(x-7) \\ y-4=-2x+14 \\ y=-2x+14+4 \\ y=-2x+18 \end{gathered}[/tex]

For a given geometric sequence, the common ratio, r, is equal to 5, and the 7th term, an, is equal to -43. Find the value of the 9thterm, a9. If applicable, write your answer as a fraction.a9=

Answers

Given:

it is given that common ration of a geometric sequence is r = 5 and 7th term is - 43.

Find:

we have to find the value of 9th term.

Explanation:

we know the formula for nth term of a geometric sequence is

[tex]a_n=ar^{n-1}[/tex]

since, 7the term is - 43,

Therefore, we have

[tex]\begin{gathered} a_7=-43 \\ ar^{7-1}=-43 \\ ar^6=-43 \\ a(5)^6=-43 \\ a(15625)=-43 \\ a=-\frac{43}{15625} \end{gathered}[/tex]

The 9the term of the geometric sequence is

[tex]\begin{gathered} a_9=-\frac{43}{15625}\times(5)^{9-1} \\ =-\frac{43}{15625}\times(5)^8 \\ =-\frac{43}{(5)^6}\times(5)^8 \\ =-43\times25 \\ a_9=-1075 \end{gathered}[/tex]

Therefore, 9th term of given geometric sequence is -1075.

List each real zero of f according to the behavior of the graph at the x-axis near that zero. Zero(s) where the graph crosses the x-axis:Zero(s) where the graph touches, but does not cross the x-axis:

Answers

In the graph, there are 2 zeros, one for each type.

The zero where the graph crosses the x axis is 1. When x=1, the function intercepts the x axis and crosses it.

The zero where the graph touches but does not cross the x axis is -1. When x=-1, the function touches x axis but goes back to the quadrant.

There can be no more than 100 people in the movie theater. There are already 22 people in the movie theater.What inequality represents the number of additional people, p, that can enter the movie theater?Drag and drop the appropriate symbols to correctly complete the inequality.

Answers

Answer:

[tex]p\text{ + 22}\leq\text{ 100}[/tex]

Explanation:

Here, we want to drop the appropriate symbols

When we add the given number 22 to p, it would give a number which is at most 100

That means the number must be less than or equal to 100

mathematically, we have that as:

[tex]p\text{ + 22}\leq\text{ 100}[/tex]

Write the following ratio as a fraction in lowest terms. 36 to 38

Answers

Given:

Write the following ratio as a fraction in the lowest terms.

36 to 38

the ratio will be as follows:

[tex]36\text{ }to\text{ }38=\frac{36}{38}=\frac{2*18}{2*19}=\frac{18}{19}[/tex]

So, the answer will be: 18/19



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