Answers
Given data
*The given power is P = 2000 MW = 2000 × 10^6 W
*The given distribution voltage is V = 22 kV = 22 × 10^3 V
The formula for the current needed to carry the 2000 MW generated at a large power station is given as
[tex]I=\frac{P}{V}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} I=\frac{2000\times10^6}{22\times10^3} \\ =90.90\times10^3\text{ A} \end{gathered}[/tex]Hence, the current needed to carry the 2000 MW generated at a large power station is I = 90.90 × 10^3 A
Related Questions
What is the equation for finding the gravitational force of an object? (1 point)
Answers
The equation for finding the gravitational force of an object is F = mg.
option D is the correct answer.
What is gravitational force of an object?Gravitational force is an attractive force that exists between all objects with mass due to the influence of the Earth's gravitational pull.
An object with mass attracts another object with mass.
The magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects according to Newton's law of universal gravitation.
Mathematically, the formula for gravitational force is given as;
F = mg
where;
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A diagram of a student on a playground swing is shown below. At which point is the kinetic energy the greatest?A. Point 1B. Point 2C. Point 3D. Point 4
Answers
To find:
The point where the kinetic energy is the greatest.
Explanation:
The kinetic energy of an object is the energy possessed by the object due to its motion. Thus the kinetic energy of an object is proportional to the square of the velocity of the object.
The velocity of the wing will be zero at the extreme points of the path of the swing. But as the swing approaches the mean point, i.e., point 3, the velocity of the swing increases. The velocity will be maximum at the mean point.
Thus the kinetic energy will be the greatest at point 3.
Final answer:
Therefore the correct answer is option C.
Classify the types of forces below into four groups in the table provided. Write only the letters to represent the forces. Give a heading for each group in the table.
A The force which prevents a glass bottle from slipping out of your hand
B The force which makes it difficult to climb a steep mountain
C The force which gives you weight
D The force which makes it difficult for you to push down a float in water
E The force which causes a parachutist to fall when he jumps out of a helicopter
F The force which slows down an airplane moving in air
G The force which makes a compass turns
Answers
Gravity force, friction force and buoyant force are the types of forces given below.
A) The force which prevents a glass bottle from slipping out of your hand- friction force
B) The force which makes it difficult to climb a steep mountain- gravity
C) The force which gives you weight- gravity
D) The force which makes it difficult for you to push down a float in water- buoyant force
E) The force which causes a parachutist to fall when he jumps out of a helicopter- gravity
F) The force which slows down an airplane moving in air- friction force
G) The force which makes a compass turns- gravity
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A capacitor is constructed of two large, identical, parallel metal plates separated by a small distance d. A battery fully charges the capacitor and is then disconnected. If, instead of separating the plates, the empty space between the plates is filled with a slab of insulating material that has a dielectric constant κ= 2, which of the following correctly describes the change, if any, of the voltage across the capacitor, the electric field between the plates, and the energy stored in the capacitor? 1) Voltage halvesElectric field halves Energy halves 2. Voltage halves Electric field halves Energy does not change 3. Voltage does not change Electric field does not change Energy halves 4. Voltage does not changeElectric field halves Energy halves 5. Voltage does not change Electric field does not change Energy does not change
Answers
The capacitance of a capacitor of a parallel plate is given by:
[tex]C=\frac{kA\cdot\epsilon_o}{d}[/tex]Where:
[tex]\begin{gathered} \epsilon_o=_{\text{ }}Vacuum_{\text{ }}permittivity \\ k=_{\text{ }}Dielectric_{\text{ }}constant=2 \\ A=_{\text{ }}Area_{\text{ }}of_{\text{ }}the_{\text{ }}plates \\ d=_{\text{ }}distance_{\text{ }}betwen_{\text{ }}the_{\text{ }}plates \end{gathered}[/tex]We also know:
[tex]\begin{gathered} Q=\frac{q}{V} \\ so\colon \\ \frac{q}{V}=\frac{kA\cdot\epsilon_o}{d} \\ V=\frac{qd}{kA\cdot\epsilon_o} \\ if \\ k=2 \\ V=\frac{1}{2}(\frac{qd}{kA\cdot\epsilon_o}) \end{gathered}[/tex]As we can see the voltage halves
And since:
[tex]\begin{gathered} E=\frac{V}{d} \\ W=qV \end{gathered}[/tex]We can conclude that electric field and also the energy halve
I need help with this practice problem. Observe what happens in each of these three spheres with rain?Give at least two sentences each HYDROSPHERE:BIOSPHERE:GEOSPHERE:
Answers
The hydrosphere is the amount of water that there is on the planet. Water follows a cycle called the cycle of water where the heat from the sun evaporates water and is collected in clouds that eventually condensate and precipitates back to the surface in form of rain.
The biosphere is the part of the earth where there is life. When it rains this life receives the water and is used for various cycles that sustain life.
The geosphere is the soil of the earth. This soil receives the water and usually, this sinks in the soil sometimes accumulating and eventually evaporating again. This water is essential to sustain life.
How far will a bike travel if you pedal at 13 m/s for 7 seconds?
Answers
Given
[tex]\begin{gathered} v=13\text{ m/s} \\ t=7\text{ s} \end{gathered}[/tex]The distance covered is given as,
[tex]s=vt[/tex]Here, s is the distance travelled, v is the speed and t is the time .
Substituting all known values,
[tex]\begin{gathered} s=(13\text{ m/s)}\times(7\text{ s)} \\ =91\text{ m} \end{gathered}[/tex]Therefore, the bike will travel 91 m is 7 second.
Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy source is to store antimatter charged particles in a vacuum chamber, circulating in a magnetic field, and then extract them as needed. Antimatter annihilates with normal matter, producing pure energy. What strength (in T) magnetic field is needed to hold antiprotons, moving at 6.10 ✕ 107 m/s in a circular path 1.70 m in radius? Antiprotons have the same mass as protons but the opposite (negative) charge. (Enter the magnitude.)
Answers
Data:
B=?, v=6.10*10^7 m/s, R=1.70m, m=1.67*10^(-27)kg, q=-1.6*10^(-19)C
Answer:
Firstly, we need to remember the formula for the Magnetic force, which is:
[tex]F_m=|q|vB[/tex]However, in this scenario the magnetic force will act as a centripetal force, thus:
[tex]F_m=\frac{mv^2}{R}[/tex]If we equal both of them:
[tex]|q|vB=\frac{mv^2}{R}\Rightarrow B=\frac{mv}{|q|R}[/tex]Replacing our values:
[tex]B=\frac{1.67*10^{-27}*6.1*10^7}{1.6*10^{-19}*1.7}=0.3745T[/tex]Then, our magnetic field will be B=0.3745T
The wire feed controls the amperage during the welding process. A control knob labeled in metric units shows a maximum wire-feed speed of 160 mm/sec. What is this maximum speed in inches per minute?The maximum speed is ___ inches per minute.
Answers
Answer: 378 inches per minute
Explanation:
We want to convert 160 mm/sec to inches per minute.
Recall,
1 mm = 0.03937 inches
1 second = 0.01667 minutes
Thus,
160 mm/sec = 160 x 0.03937 inches/0.01667 minutes
= 378 inches per minute
A deuteron particle consists of one proton and one neutron and has a mass of 3.34x10^-27 kg. A deuteron particle moving horizontally enters uniform, vertical 0.0800 T magnetic field and follows a circular arc of radius of 38.5 cm. What would be the radius of the arc followed by a proton that entered the field with the same velocity as the deuterium?
Answers
_dThe radius of curvature of a subatomic particle under a magnetic field is given by the following formula:
[tex]r=\frac{mv}{qB}[/tex]Where:
[tex]\begin{gathered} r=\text{ radius} \\ v=\text{ velocity} \\ q=\text{ charge} \\ B=\text{ magnetic field} \end{gathered}[/tex]We can determine the quotient between the velocity and the charge of the deuteron particle from the formula. First, we divide both sides by the mass:
[tex]\frac{r_d}{m_d}=\frac{v}{q_B_}[/tex]Now, we multiply both sides by the magnetic field "B":
[tex]\frac{Br_d}{m_d}=\frac{v}{q}[/tex]Since the charge of the deuterion is the same as the charge of the proton and the velocity we are considering are the same this means that the quotient between velocity and charge is the same for both particles. Therefore, we can apply the formula for the radius again, this time for the proton:
[tex]r_p=\frac{m_pv}{qB}[/tex]And substitute the quotient between velocity and charge:
[tex]r_p=\frac{m_p}{B}(\frac{Br_d}{m_d})[/tex]Now, we cancel out the magnetic field:
[tex]r_p=\frac{m_pr_d}{m_d}[/tex]Now, we substitute the values:
[tex]r_p=\frac{(1.67\times10^{-27}kg)(0.385m)}{(3.34\times10^{-27}kg)}[/tex]Solving the operations:
[tex]r_p=0.193m=19.3cm[/tex]Therefore, the radius is 19.3 cm.
Two 4.952 cm by 4.952 cm plates that form a parallel-plate capacitor are charged to +/- 0.576 nC. What is the electric field strength inside the capacitor if the spacing between the plates is 2.97 mm?
Answers
In order to solve this question, we will need to know the E-field of a capacitor
E = sigma/epsilon naught
To find sigma (charge density), we will need to divide the total charge by the area
sigma = (.576 x 10^-9)/(4.952x10^-2)^2 = 2.34 x 10^-7
E = 2.34 x 10^-7/ (8.85x10^-12) = 26541.04 V/m
in a particle accelerator a proton moves at constant speed 0.750c in a circle of radius 663 m. what is the net force on the proton?
Answers
In a particle accelerator a proton moves at constant speed 0.750c in a circle of radius 663 m. The net force on the proton will be .0127 * [tex]10^{-11}[/tex] N
Any object moving in a circle (or along a circular path) experiences a centripetal force. That is, there is some physical force pushing or pulling the object towards the center of the circle.
Force = m ( [tex]v^{2} / R[/tex])
m= mass
v = speed
R = radius
force = 1.67 * [tex]10^{-27}[/tex] * [tex](0.75 * 3 * 10^{8}) ^{2}[/tex] / 663 = 0.0127 * [tex]10^{-11}[/tex] N
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Question 28 of 30The graph below shows the conservation of energy for a skydiver jumping outof a plane and landing safely on the ground. Which energy is represented byline A?сAEnergy (kJ)BDistance (m)A. Potential energyB. Kinetic energy
Answers
Answer:
Explanation:
Potential energy depends on the height of the object above the ground. As the height decreases, the potential energy decreases. Looking at line A, the energy is decreasing as the distance is increasing. Thus, the energy represented by line A is
A. Potential energy
a given mass of a gas at - 73°C exerts pressure of 40 cm of mercury. what pressure will be exerted at 127 °C if the volume remains constant
Answers
The pressure that will be exerted at 127 °C if the volume remains constant is 80 cm of mercury
How do I determine the new pressure?First, we shall list out the given parameters from the question. This is shown below:
Initial temperature (T₁) = -73 °C = -73 + 273 = 200 K Initial pressure (P₁) = 40 cm of mercuryNew temperature (T₂) = 127 °C = 127 + 273 = 400 KVolume = ConstantNew pressure (P₂) = ?Thus, we can obtain the new pressure of the gas at 127 °C as illustrated below:
P₁ / T₁ = P₂ / T₂
40 / 200 = P₂ / 400
Cross multiply
200 × P₂ = 40 × 400
200 × P₂ = 16000
Divide both sides by 200
P₂ = 16000 / 200
P₂ = 80 cm of mercury
Therefore, the new pressure is 80 cm of mercury
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An acorn is dropped and reaches the ground in 2.0s. What is the acorn’s velocity just as it hits the ground? How high above the ground was it released?
Answers
Take into account that the vertical distance traveled by the acorn can be calculated by using:
[tex]h=\frac{1}{2}gt^2[/tex]where,
g: gravitational acceleration constant = 9.8m/s^2
t: time acorn takes to hit the ground = 2.0s
h: height at which acorn is initially = ?
Replace the given values of the parameters into the previous formula and simplfiy:
[tex]h=\frac{1}{2}(9.8\frac{m}{s^2})(2.0s)^2=19.6m[/tex]Hence, the acorn was released from a high of 19.6m above the ground.
The velocity just after acorn hits the ground is given by:
[tex]\begin{gathered} v=gt \\ v=(9.8\frac{m}{s^2})(2.0s)=19.6\frac{m}{s} \end{gathered}[/tex]Hence, the speed is 19.6 m/s
A spaceship travels at an enormous speed to go from one star system to another. As it reaches its destination, its “hyperdrive” deactivates, bringing the ship to an immediate halt in orbit around a planet.
Why does this defy physics? Give Equations/ Laws to justify yourself
Answers
This situation defies the laws of physics because it has no physical basis to explain the immediate stoppage of the ship.
Why does this situation defy physics?This situation defies the laws of physics because it describes an event in which an ship stops abruptly without any apparent physical explanation.
From the above, it can be inferred that this does not have scientific support. Additionally, it is defying the laws of physics because, according to Newton's second law, every body in motion continues to move at a constant speed. Therefore, if the ship goes to a hypervelocity it must continue moving, by Newton's second law. Additionally, if there were a force such as friction or gravity that causes it to stop, this would not be immediately but progressively.
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What is the area under the curve on the velocity time graph in physics represent
Answers
When given a graph of velocity vs time as the following:
The area under the curve represents the distance that the object has moved in the given time interval.
A bicycle wheel, of radius 0.300 m and mass 2.07 kg (concentrated on the rim), is rotating at 4.00 rev/s. After 59.0 s the wheel comes to a stop because of friction. What is the magnitude of the average torque due to frictional forces?
Answers
ANSWER:
0.079 J
STEP-BY-STEP EXPLANATION:
The average torque exerted due to friction force is:
[tex]\tau=I\alpha[/tex]Here, I is the moment of inertia and α is the angular acceleration.
The mass of wheel is concentrated at the rim. Therefore, the moment of inertia of wheel is,
[tex]I=m\cdot r^2[/tex]Here, m is the mass of wheel and r is the radius of wheel.
replacing:
[tex]\begin{gathered} I=2.07\cdot0.3^2 \\ I=0.1863\text{ kg}\cdot s^2 \end{gathered}[/tex]The angular speed is decreased from 4 rev/s to 0 rev/s in 59 sec. Therefore, the angular acceleration is calculated as:
[tex]\begin{gathered} \alpha=\frac{0-4}{59} \\ \alpha=0.068\cdot\frac{rev}{\sec}\cdot\frac{2\pi\text{ rad/rev}}{1rev/sec^2} \\ \alpha=-0.426rad/sec^2 \end{gathered}[/tex]The negative sign represents that the wheel is de-accelerating.
Replacing:
[tex]\begin{gathered} \tau=I\alpha \\ \tau=0.1863\cdot-0.426 \\ \tau=-0.079\text{J} \end{gathered}[/tex]The negative sign represents the direction of torque i.e. clockwise direction. Thus, the magnitude of average torque is 0.079 J.
Write a rule for the sequence. 3, -3, -9, -15. A. Start with 3 and add -6 repeatedly B. Start with -6 and add 3 repeatedly C. Start with 3 and 6 repeatedly D. Start with 3 and subtract -6 repeatedly
Answers
Substract two consecutive terms of the sequence to see if there is a common difference:
[tex]\begin{gathered} (-3)-(3)=-3-3=-6 \\ (-9)-(-3)=-9+3=-6 \\ (-15)-(-9)=-15+9=-6 \end{gathered}[/tex]As we can see, there is a common difference of -6.
Then, if a number of the sequence is given, the next one can be found by adding -6 (which is the same as subtracting 6).
Notice that the first term of the sequence is 3.
Then, the rule for the sequence is to start with 3 and add -6 repeatedly.
Therefore, the correct choice is option A) Start with 3 and add -6 repeatedly.
Light of wavelength 589 nm in vacuum passes through a piece of fused quartz of index of refraction n = 1.458. (a) Find the speed of light in fused quartz. (b) What is the wavelength of this light in fused quartz? (c) What is the frequency of the light in fused quartz?
Answers
The speed of light in fused quartz 2.058 * [tex]10^{8}[/tex] m/s
The wavelength of the light in fused quartz 404.322 * [tex]10^{-9}[/tex] m
The frequency of the light in fused quartz 0.00509 * [tex]10^{17}[/tex] hz
refractive index of a material = speed of light in vacuum / speed of light in that medium
1.458 = 3 * [tex]10^{8}[/tex] / speed of light in that medium
speed of light in fused quartz = 3 * [tex]10^{8}[/tex] / 1.458 = 2.058 * [tex]10^{8}[/tex] m/s
frequency = c / lambda = 3 * [tex]10^{8}[/tex] / 589 * [tex]10^{-9}[/tex] = 0.00509 * [tex]10^{17}[/tex] hz
wavelength of light in fused quartz = speed of light in fused quartz / frequency
= 2.058 * [tex]10^{8}[/tex] / 0.00509 * [tex]10^{17}[/tex] = 404.322 * [tex]10^{-9}[/tex] m = 404.322 nm
wavelength = wave velocity in fused quartz / frequency
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of the following and draw a neat, properly labelled free body diagram. Indicate the size of forces with the lengths of the arrows. i.e., if two forces are the same size draw them the same length and if one is much bigger draw it much longer. a) The Space Shuttle accelerating vertically just after leaving the launch pad.
Answers
We will have that the diagram will be the following:
Here "F" is the force the shuttle is using to take off, friction is the friction with the air and "W" is the weight of the shuttle.
Circuit breakers are connected in series so that the circuit will open in case of dangerously high current.TrueFalse
Answers
Circuit breakers are connected in series so that the circuit will open in case of dangerously high current.
that is True
A 0.24 kg blob of clay strikes a wall with an Initial velocity of 25 m/s the clay come to a stop against the wall in 91 ms what is the average impact force on the clay
Answers
ANSWER
65.9N
EXPLANATION
The impact force of an object is
[tex]F=\frac{\Delta p}{\Delta t}[/tex]And the change in momentum is
[tex]\Delta p=m(v_f-v_i)[/tex]We know that the mass of the blob of clay is 0.24kg, its initial velocity is 25m/s and its final velocity is 0m/s. Also, the time of the collision is 91 ms.
The force is:
[tex]F=\frac{m(v_f-v_i)}{\Delta t}[/tex]To be consistent with the units, we have to write the time in seconds, not milliseconds:
[tex]F=\frac{0.24\operatorname{kg}(0-25)m/s}{0.091s}[/tex][tex]F\approx-65.9N[/tex]This result is negative because this is the force the clay exerts on the wall. By Newton's third law, the impact force on the clay is the force with the same magnitude and opposite direction. Therefore, the average impact force on the clay is 65.9N
Two astronauts, of masses 60 kg and 80 kg, are initially right next to each other and at rest in outer space. They suddenly push each other apart. What is their separation after the heavier astronaut has moved 12 m?24 m16 m9.0 m28 m21 m
Answers
We will have the following:
First, we recall that momentum is given by:
[tex]m_1v_0+m_2v_0=m_1v_1+m_2v_2[/tex]So:
[tex]\begin{gathered} (60kg)(0m/s)+(80kg)(0m/s)=(60kg)v_1+(80kg)v_2 \\ \\ \Rightarrow v_1=\frac{-(80kg)v_2}{(60kg)}\Rightarrow v_1=-\frac{4}{3}v_2 \end{gathered}[/tex]Then:
[Let's assume that when astronaut 2 moved 12 meters = t]
[tex]\begin{gathered} x_1=v_1t\Rightarrow x_1=-\frac{4}{3}v_2t \\ \\ x_2=v_2t\Rightarrow t=\frac{12}{v_2} \end{gathered}[/tex]Then:
[tex]x_1=-\frac{4}{3}v_2\ast\frac{12}{v_2}\Rightarrow x_1=-16m[/tex]Finally, the total distance will be:
[tex]\begin{gathered} d=|x_1|+|x_2|\Rightarrow d=16m+12m \\ \\ \Rightarrow d=28m \end{gathered}[/tex]i need help asap i just need the vocab i need help with this please help
Answers
ANSWERS
0. First law of Thermodynamics:, ,B,. Thermal energy can change form and location, but it cannot be created or destroyed
,1. Thermal Energy: ,H,. Kinetic energy in transit from one object to another due to temperature difference
,2. Temperature: ,D,. the average kinetic energy of particles in an object - not the total amount of kinetic energy particles
,3. Absolute zero: ,J, occurs when all kinetic energy is removed from an object
,4. Thermal Equilibrium: ,E, obtained when touching objects within a system reach the same temperature
,5. Zeroth Law of Thermodynamics: ,C, if two systems are separately found to be in thermal equilibrium with a third system, the first two systems are in thermal equilibrium with each other.
,6. Conduction: ,F, ,the transfer of thermal energy within an object or between objects from molecule to molecule
,7. Coefficient of Heat Conductivity: ,G, is the measure of a material's ability to conduct heat.
,8. Thermal resistance of a material: ,A, the measure of a material's ability to resist heat
,9. Radiation: ,I, the process by which energy is transmitted through a medium, including empty space, as electromagnetic waves.
EXPLANATION
The zeroth and first laws of thermodynamics are known statements, as well as the definition of thermal equilibrium, so there is nothing to explain about these three.
Thermal energy is a form of kinetic energy. It is "generated" by the vibrations of the molecules or atoms that form the object, causing the object to increase its temperature. As a result, the temperature is the average kinetic energy of these particles.
Absolute zero is a temperature of 0 degrees Kelvin - approximately -273 degrees Celsius. When an object reaches this particular temperature it is considered as if the object has "no temperature" - that is why it is called absolute zero. As explained above, the temperature is the average kinetic energy of the object's particles, so if the particles have no kinetic energy, then the object has zero temperature.
Heat conductivity and thermal resistance are basically opposites. The first is the object's ability to conduct heat while the second is the ability to resist the conduction of heat.
Radiation and Conduction are two ways energy can be transferred. The first does not need a medium - that is why energy can be transmitted through empty space, and the second is by contact between two objects or an object and a medium.
Describe in simple terms each of Kepler's three laws. Why were Tycho Brahe's observations so important for Kepler to develop these laws?
Answers
Kepler's first law of planetary motion states that every planet’s orbit is elliptical and has the Sun at a focus
Kepler's second law of planetary motion states that the line joining the Sun and a planet sweeps out equal areas in equal times
Kepler's third law of planetary motion states that the square of a planet’s orbital period is proportional to the cube of the semi-major axis of its orbit
Tycho Brahe provided some accurate astronomical data which makes it possible for Kepler to develop the laws of planetary motion. He devised the best instruments available before the invention of the telescope. These data and instrument provided by Tycho Brahe was able to assist Kepler in formulating these laws
Unbeknownst to most students, every time the school floors are waxed, the physics teachers get together to have a barrel of phun doing friction experiments in their socks (uhm - they do have clothes on; its just that they don't have any shoes on their feet). On one occasion, Mr. London applies a horizontal force to accelerate Mr. Schneider (mass of 84 kg) rightward at a rate of 1.2 m/s/s. If the coefficient of friction between Mr. Schneider 's socks and the freshly waxed floors is 0.35, then with what force (in Newtons) must Mr. London be pulling?
Answers
The frictional force is taken away from the net force. Mr. London will pull with a force of 388.9 N
What is Force ?Force can simply be defined as a pull or push. It is a product of mass and acceleration. It is a vector quantity.
Given that Mr. London applies a horizontal force to accelerate Mr. Schneider (mass of 84 kg) rightward at a rate of 1.2 m/s/s. If the coefficient of friction between Mr. Schneider 's socks and the freshly waxed floors is 0.35, then the force F in which Mr. London is pulling will be;
F - Fr = ma
Where
F = ?m = 84 kga = 1.2 m/s²N = ?μ = 0.35N = mg
N = 84 × 9.8
N = 823.2 N
Fr = μN
Fr = 0.35 × 823.2
Fr = 288.12 N
F - 288.12 = 84 × 1.2
F - 288.12 = 100.8
F = 100.8 + 288.12
F = 388.92 N
Therefore, Mr. London must be pulling with a force of 388.9 N
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the position of an object is given by: x(t)=2t^3-35t^2+10 what is the acceleration of the object at t=250 seconds?
Answers
We are given that a particle's position is determined by the function:
[tex]x\left(t\right)=2t^3-35t^2+10[/tex]We are asked to determine the acceleration of the object. To do that we will first determine the first derivative of the position with respect to time, i. e. the velocity of the particle:
[tex]\frac{dx}{dt}=\frac{d}{dt}(2t^3-35t^2+10)[/tex]Now, we distribute the derivative operator:
[tex]\frac{dx}{dt}=\frac{d}{dt}(2t^3)-\frac{d}{dt}(35t^2)+\frac{d}{dt}(10)[/tex]Now, we use the following rule to determine each derivative:
[tex][/tex]A sample of silver at 10°C is heated to 90°C when 1 kcal of heat is added. What is the mass of the silver?
Answers
We can use the following formula:
[tex]q=m\cdot c\cdot(T2-T1)[/tex]Where:
q = heat = 1 kcal = 4184000J
c = specific heat (of silver) = 0.235 J °C /g
m = mass
T1 = Initial temperature = 10°C
T2 = Final temperature = 90°C
Therefore, solve for m:
[tex]\begin{gathered} m=\frac{q}{c(T2-T1)} \\ m=\frac{4184000}{0.235(90-10)} \\ m=222553.1915g \end{gathered}[/tex]Answer:
222553.1915g
Could really some help answering this question I don’t really understand! :)
Answers
Given:
Object A is at a higher temperature than object B.
Here, there is a difference in temperature.
Temperature flow is similar to water flow.
The water stops flowing if the water level becomes the same in botht containers.
Similarly, thermal energy transfers between the objects until the objects have changed the temperature by the same amount.
Thus, option B is correct.
A proton is accelerated through a potential difference of 100 V and then enters a region where it is moving perpendicular to a magnetic field B = 0.20 T. Calculate the radius of the circular path in which it will travel.
Answers
The radius of the circular path in which it will travel inside the magnetic field will be 7mm.
Magnetic field is the area around a magnet or an electric charge in which the effect of magnetism is felt.
Magnetic field of the proton = B = 0.20 T
Electric potential difference of the proton = E = 100 V
Kinetic energy of proton = 100p = [tex]\frac{1}{2}m v^{2}[/tex]
[tex]v = \sqrt{\frac{2*100e}{m} }[/tex]
The centripetal acceleration is provided by the magnetic field.
therefore,
[tex]\frac{mv^{2} }{r} = evB[/tex]
mv = eBr
[tex]r = \frac{mv}{eB}[/tex]
m = 1.67 × [tex]10^{-27}[/tex] kg
e = 1.60 × [tex]10^{-19}[/tex] C
B = 0.20 T
v = [tex]\sqrt{\frac{2*100e}{m} }[/tex] = 13.8 × [tex]10^{4}[/tex] m/s
on putting the values of all the quantities in the equation of r, we get
r = 0.07 m
r = 7 mm
The radius of the circular path is 7 mm.
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