Bromination of isobutane is a two‑step reaction.
The enthalpy of each step : step 1: ΔH = 34 kJ/mol. step 2 : ΔH = -99 kJ/mol enthalpy of the overall reaction , ΔH = 65 kJ/mol.
Bond dissociation energy :
H - H = 436 kJ/mol
H - Br = 366 kJ/mol
Br - Br = 193 kJ/mol
(CH₃)₃C - H = 400 kJ/mol
(CH₃)₃C - Br = 292 kJ/mol
Step 1 : (CH₃)₃C - H + Br ------> (CH₃)₃C° + H - Br
ΔH = ∑ Bond broken - ∑ Bond form
ΔH = 400 kJ/mol - 366 kJ/mol
ΔH = 34 kJ/mol
Step 2: (CH₃)₃C° + Br - Br ----> (CH₃)₃ - Br + Br
ΔH = ∑ Bond broken - ∑ Bond form
ΔH = 193 - 292
ΔH = - 99 kJ/mol
overall reaction :
(CH₃)₃ - H + Br - Br ----> (CH₃)₃ - Br + H- Br
ΔH = ( 400 + 193 ) - ( 292 + 366 )
ΔH = 593 - 658
ΔH = - 65 kJ/mol
Thus, Bromination of isobutane is a two‑step reaction.
The enthalpy of each step : step 1: ΔH = 34 kJ/mol. step 2 : ΔH = -99 kJ/mol enthalpy of the overall reaction , ΔH = 65 kJ/mol.
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You have 2.7 x10^24 particles of C3H8:. How many grams are present?
Step 1 - Understanding molar mass
As we have previously seen, one mole corresponds to 6*10^23 particles.
When we weight one mole of something, we obtain what is called the molar mass: the mass of one mole of particles.
Each element has his own molar mass, which can be found in the periodic table. We can use them to calculate the molar mass of a molecule.
Let's see an example. Water is H2O. Looking at a periodic table, we find the molar masses 1 g/mol for H and 16 g/mol for O. Therefore, the molar mass of water will be:
[tex]M_{H2O}\rightarrow2H+1O=2\times1+1\times16=18\text{ g/mol}[/tex]Which means that 1 mole of water weights 18g.
Step 2 - Solving the exercise
Let's start by calculating the molar mass of C3H8. The molar mass for C is 12 g/molj, so:
[tex]M_{C3H8}=3C+8H=3\times12+8\times1=44\text{ g/mol}[/tex]44g corresponds thus to one mol of C3H8. Since one mole is 6.10^23 particles, we can set the following proportion:
[tex]\begin{gathered} 6.10^{23^\text{ }}particles\text{ of C3H8 ------ 44g} \\ 2.7\times10^{24}\text{ particles of C3H8 ----- x} \\ \\ x=\frac{2.7\times10^{24}\times44}{6.10^{23}}=\frac{1188}{6}=198g \\ \end{gathered}[/tex]Answer: 198g of C3H8 are present.
How much heat is released when a 50 g piece of paraffin cools from 55⁰C to 18⁰. Specific heat of paraffin = 2.9J/gC
Answer:
Q = -5,365 J
Explanation:
To find the amount of heat released, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = heat (J)
-----> m = mass (g)
-----> c = specific heat capacity (J/g°C)
-----> ΔT = T₂ - T₁ = change in temperature (°C)
"T₂" represents the final temperature and "T₁" represents the initial temperature. You can plug the given values into the equation and solve to find "Q".
Q = ? J c = 2.9 J/g°C
m = 50 g ΔT = 18°C - 55°C = -37°C
Q = mcΔT <----- Given equation
Q = (50 g)(2.9 J/g°C)(-37°C) <----- Insert values
Q = -5,365 J <----- Multiply
*the answer is negative because the reaction is exothermic (heat is being released from the system)
At sea level, there are approximately 2.6 × 1025 molecules m–3 of the atmosphere. There are 5.20 × 1021 molecules m–3 of one of the gases making up the atmosphere. What is the concentration of this gas as a proportion of the total number of molecules in the atmosphere, expressed in parts per million (ppm)?
Answer:
[tex]200\text{ ppm}[/tex]Explanation:
Here, we want to calculate the concentration of the gas in ppm
What we have to do here is to divide the number of molecules of the gas by the total number of molecules in the atmosphere, after which we can convert it to ppm
Mathematically, we have that as:
[tex]\frac{5.20\text{ }\times\text{ 10}^{21}}{2.6\times10^{25}}\text{ = 0.0002}[/tex]Now, we have to convert to ppm
To convert to ppm, we simply have to multiply the given ratio by 1,000,000
We have this as:
[tex]0.0002\text{ }\times\text{ 1000000 = 200 ppm}[/tex]I don't know how to solve this. Thank you.An iron cube 20 cm on each side is completely submerged in water. If you have a mass of 5.60kg,Calculate the density of the block and the mass of water displaced (the density of water is 1000kg/m3).
a) Calculate the density of the block.
The density of any substance is defined as the mass divided the volume.
Density of the block = mass of the block/volume of the block.
We are given the mass of the block.
mass of the block = 5.60 kg
Since the it is an iron cube, we can find its volume.
Side = 20 cm = 0.20 m
Volume of the block = (side)³
Volume of the block = (20 cm)³ = (0.20 m)³
Volume of the block = 8000 cm³ = 0.008 m³
Now that we know the mass and the volume we can find the density of the block.
Density of the block = Mass of the block / Volume of the block
Density of the block = 5.60 kg / 8000 cm³
Density of the block = 0.0007 kg/cm³
Density of the block = 5.60 kg / 0.008 m³
Density of the block = 700 kg/m³
Answer: The density of the block is 0.0007 kg/cm³ or 700 kg/m³
b) Calculate the mass of water displaced:
If we consider that the cube is completely submerged (as the problem says) it will displace some water. How much water does it displace? Archimedes' says: "The volume of displaced fluid is equivalent to the volume of an object fully immersed in a fluid". That means that the block completely submerged in water (fluid) will displace its volume of water.
volume of water displaced = volume of the block
volume of water displaced = 8000 cm³ = 0.008 m³
Now that we know the volume of water displaced, and since we are given the density of water, we can find the mass of water displaced.
Density of water = mass of water / volume of water
mass of water = volume of water * density of water
mass of water = 0.008 m³ * 1000 kg/m³
mass of water displaced = 8.0 kg
Answer: Supposing that the block is completely submerged it displaces 8.0 kg of water.
PLEASE HELPPPP CHEMISTRY
There are 1.02391×1024 no. of atoms in 1.70 moles of Calcium (Ca)
What is a Avogadro number?The approximate number of nucleons (protons or neutrons) in a gram of common stuff is known as the Avogadro number. 1 mole of any material contains the no of particles equal to the Avogadro number, that is, 6.023×1023particles.
What is Calcium?The chemical element calcium has the atomic number 20 and the letter Ca as its symbol. Calcium is an alkaline earth metal that reacts with air to create a black oxide-nitride coating. Its heavier homologues barium and strontium are most similar to it in terms of physical and chemical characteristics.
Now,
Acc. to the Avogadro Number principal every 1 mole of any material contains the no of particles equal to the Avogadro number, that is, 6.023×1023particles.
So, the given amount of Calcium contains atom as follows:
1.70×6.023×1023 =1.02391×1024 atoms
Hence, There are 1.02391×1024 no. of atoms in 1.70 moles of Calcium (Ca)
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Write and balance the equation for the combustion of the fatty acid lauric acid, (C12H24O2)Write and balance the equation for the combustion of the fatty acid stearic acid, (C18H36O2).
1) Write the chemical equation.
[tex]C_{12}H_{24}O_2+O_2\rightarrow CO_2+H_2O[/tex]List the elements in the reaction.
Reactants
C: 12
H: 24
O: 4
Products
C: 1
H: 2
O: 3
2) Balance C.
[tex]C_{12}H_{24}O_2+O_2\rightarrow12CO_2+H_2O[/tex]List the elements in the reaction.
Reactants
C: 12
H: 24
O: 4
Products
C: 12
H: 2
O: 25
3) Balance H.
[tex]C_{12}H_{24}O_2+O_2\rightarrow12CO_2+12H_2O[/tex]List the elements in the reaction.
Reactants
C: 12
H: 24
O: 4
Products
C: 12
H: 24
O: 36
4) Balance O.
[tex]C_{12}H_{24}O_2+17O_2\rightarrow12CO_2+12H_2O[/tex]List the elements in the reaction.
Reactants
C: 12
H: 24
O: 36
Products
C: 12
H: 24
O: 36
5) Balanced chemical equation.
[tex]C_{12}H_{24}O_2+17O_2\rightarrow12CO_2+12H_2O[/tex]Perform the followingmathematical operation, andreport the answer to thecorrect number of significantfigures.16.52 x 5.8 = [?]=Enter
For multiplication and division operations, we perform the operations normally, and the final result must be written with the same number of significant figures as the factor that has the fewest significant figures.
16.52 x 5.8 = 95.816
The result obtained in the above multiplication must be rounded to two significant figures, which correspond to the number of significant figures of the number 5.8. Therefore, we must round the result, giving as answer 96.
Answer: 96
What is the 238 U enrichment required for the following applications?
Naturally occurring Uranium: _____ %
Nuclear fuel for power generation: _____ %
Nuclear bombs: _____ %
Naturally occurring Uranium: 99.2745 %
Nuclear fuel for power generation: 97%
Nuclear bombs: 90 %
With a relative abundance of 99%, uranium-238 (238U or U-238) is the most prevalent isotope of uranium to be discovered in nature. It is non-fissile, unlike uranium-235, hence it cannot support a chain reaction in a thermal-neutron reactor.
A 1000 MWe pressurized water reactor needs about 27 tonnes of uranium per year, or over 18 million fuel pellets contained in more than 50,000 fuel rods. In contrast, a coal power plant of comparable scale would require more than 2.5 million tonnes of coal to generate the same amount of electricity.
15 kilograms: weight of a solid sphere of 100 percent uranium-235, just large enough to reach a critical mass with a beryllium reflector, nuclear weapons normally use a concentration of more than 90 percent.
Hence, the percentages are 99.27, 97 and 90% respectively.
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What is the molarity of a solution after 14.38 mL of 1.950 M NaCI solution is distilled into a total of 533.98 mL solution?
To answer this question we have to use the rule of dilutions:
[tex]C1V1=C2V2[/tex]Where C1 and C2 are the initial and final concentrations and V1 and V2 are the initial and final volumes, respectively. In this case we have to find C2 and the other values are given:
[tex]\begin{gathered} C2=\frac{C1V1}{V2} \\ C2=\frac{14.38mL\cdot1.950M}{533.98mL} \\ C2=0.052M \end{gathered}[/tex]It means that the answer is 0.052M.
24. Predict the Products
a. Ca + H3N→
b. KF→
c. NaBr + MgO→
i,ii&iii only the alkanes forms 3-bromo-3-methylpentane as the major product when it's react with hbr.
What is alkane forms?
Alkanes are the series of a compounds that is contain carbon and hydrogen atoms of the with single covalently bonds. Theses are knowns as saturated if hydrocarbons. This group of the compounds consists of a carbon and hydrogen and atoms with single covalent bonds. Also it is comprises a homologous series of having a molecular formula of NaBr+MgO.
Sol-this problem which of the following Elkins yields three bromo three metal painting as the major product upon addition of HBR. So let me just write an equation right? I'm writing here directly. So when HBR is reacted, so what will be the compound here? We will be getting a compound like this. Alright, so this is B. R. Again, we are processing here with H beyond right.
This is it. So now organic compound is going to be seen. This is beard. Right? So here you can point one more when you add here it's B. R. We will be getting here. Yeah, again, for this when weird it's beard. So again we will be getting to come home like this. So same compound we're getting that means this is this is nothing but three Bromo three metal contains as the major product. So all are having the same product and option is all of them is correct. Right? No next question it is asked at which of the following cardboard signs bill undergo At 1 2 metal shift. Right? So None of them ever was the correct answer because none of them will undergo 12 m shift.
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Can you help me how do I get the grams?
Answer:
[tex]1290g\text{ NaBr}[/tex]Explanation:
Here, we want to get the number of grams in 12.5 moles NaBr
To get this, we have to multiply the number of moles by the molar mass of NaBr
The molar mass of NaBr is 103 g/mol
Thus, we have the mass as:
[tex]\begin{gathered} Mass\text{ = number of moles }\times\text{ molar mass} \\ =\text{ 12.5 }\times\text{ 103 = 1,287.5 g} \end{gathered}[/tex]This can be approximated to 1290 which is the nearest whole number
2.60 moles CO and 2.60 moles H2O are placed in a 2.00L container at 690 °C (Keg=10.0).Calculate all equilibrium concentrations in the following reaction:
Answer:
considering the information given, the concentrations at equilbrium are:
CO(g) = 1.30 M
H2O(g) = 1.30 M
CO2(g) = 4.11 M
H2(g) = 4.11 M
Explanation:
The question requires us to calculate the concentration of CO, H2O, CO2 and H2, given the following information:
- number of moles of CO = 2.60 mol
- number of moles of H2O = 2.60 mol
- volume of container = 2.00 L
- temperature = 690°C
- equilibrium constant = 10.0
- balanced chemical equation:
[tex]CO_{(g)}+H_2O_{(g)}\rightleftarrows CO_{2(g)}+H_{2(g)}[/tex]Since the number of moles of CO and H2O were provided, as well as the volume of the container, we can calculate the concentration of this gases in moles per liter:
[tex]\begin{gathered} [CO\rbrack=\frac{2.60mol}{2.00L}=1.30mol/L=1.30M \\ \\ [H_2O\rbrack=\frac{2.60mol}{2.00L}=1.30M \end{gathered}[/tex]Also, since we have the equilibrium constant for this reaction and the concetrations of CO2 and H2 at equilibrium will be the same (they have the same stoichiometric coefficient), we can calculate the concentration of the products using the expression for Keq.
First, let's write the Keq expression for this reaction:
[tex]K_{eq}=\frac{[CO_2\rbrack\times[H_2\rbrack}{[CO\rbrack\times[H_2O\rbrack}[/tex]Considering,
[CO2] = [H2] = x
and rearranging this equation to calculate x:
[tex]K_{eq}\times[CO\rbrack\times[H_2O\rbrack=x^2\rightarrow x=\sqrt[2]{K_{eq}\times[CO\rbrack\times[H_2O\rbrack}[/tex]Now, applying the value of Keq given by the question, and the values of concentration calculated previously, we'll have:
[tex]x=\sqrt[2]{10.0\times1.30M\times1.30M}\rightarrow x=4.11M^[/tex]Therefore, considering the information given, the concentrations at equilbrium are:
CO(g) = 1.30 M
H2O(g) = 1.30 M
CO2(g) = 4.11 M
H2(g) = 4.11 M
It was determined that 1.4 x 1024 carbon dioxide molecules are produced when propane is combusted according to the equation below. Calculate the number of moles of propane that was burned.C 3H 8 + 5O 2 ----> 3CO 2 + 4H 2O
First, we have to convert the number of molecules to the number of moles of CO2 (carbon dioxide), and to do this we can do the Avogadro's number:
The Avogadro's number helps us to determine the number of moles based on the number of molecules or atoms of a compound. This number is 6.022 x 10 ^(23) /mol.
So, the conversion from molecules to moles would be:
[tex]1.4\cdot10^{24}moleculesCO_2\cdot\frac{1molCO_2}{6.022\cdot10^{23}moleculesCO_2}=2.325molCO_2.[/tex]Now, using this data we can calculate the number of moles needed for propane (C3H8).
In the chemical reaction, you can see that 1 mol of propane produces 3 moles of CO2, so the calculation would be:
[tex]2.325molCO_2\cdot\frac{1molC_3H_8}{3molesCO_2}=0.775molC_3H_8.[/tex]The answer is that 0.78 moles of C3H8 were burned and produced 2.325 moles of CO2 which is 1.4 x 10 ^(24) molecules of CO2.
on4Suppose that the pressure of 1.23 L of gas is 300.6 mm Hg when the temperature is 218.5 K. At what temperature is the volume 8.32 L and the pressure 802.75 mm Hg?O a. 3950O b. 8610O c. 1250O d. 12.1Check
Answer:
The final temperature is 3,952K. (The closest option is 3,950K).
Explanation:
The given information from the exercise is:
- Initial pressure (P1): 300.6mmHg
- Initial volume (V1): 1.23L
- Initial temperature (T1): 218.5K
- Final volume (V2): 8.32L
- Final pressure (P2): 802.75mmHg
We can calculate the final temperature (T2), by replacing the values of P1, V1, T1, V2 and P2 in the following formula of Ideal Gases:
[tex]\begin{gathered} \frac{P_1*V_1}{T_1}=\frac{P_2*V_2}{T_2} \\ \frac{300.6mmHg*1.23L}{218.5K}=\frac{802.75mmHg*8.32L}{T_2} \\ 1.69\frac{mmHgL}{K}=\frac{6,678.88mmHgL}{T_2} \\ T_2=\frac{6,678.88mmHgL}{1.69\frac{mmHgL}{K}} \\ T_2=3,952K \end{gathered}[/tex]So, the final temperature is 3,952K. (The closest option is 3,950K).
Calculate the concentration of H3O + ions in a solution of NaoH whose concentration is 0.62M at 25 ° C.
The pH of this solution is 0.207
Hello
To solve this question, we need to use the formula of solving pH of a solution from hydrogen or hydronium ion.
[tex]\begin{gathered} pH=-\text{log\lbrack{}H}_3O^+\rbrack \\ \end{gathered}[/tex]Now, we would proceed to substitute the given value and solve for it.
[tex]\begin{gathered} pH=-\log \lbrack0.62\rbrack \\ pH=0.207 \end{gathered}[/tex]NB: we did not use the value of temperature because it is not needed in this solution.
From the calculation above, the pH of this solution is 0.207
2. Sodium Na has an electronegativity = 0.9 and nitrogen N is 3.0. which is correct about the bond between Na and N
Polar covalent because the difference is 2.1
Ionic because the difference is 2
. nonpolar covalent because the difference is 2.1
they cannot form a bond because the difference is 2.1
3.. which is correct about ionic bond ?
Based on loss and gain of electrons
Based on sharing electrons
. Takes place between nonmetals
. Found between noble gase
4. In a polar covalent bond, the bonded atoms.(1 Point)
Share the electrons equally
Share the electrons unequally.
One atom loses and the other gains.
Both atoms gain electrons
Answer:
2. Ionic because the difference is 2
3. Based on loss and gain of electrons
4. Share the electrons unequally.
Write 5 sentences about voltaic cells.
ANSWER
EXPLANATION
Voltaic cell is a type of an electrochemical cell that uses chemical reaction to generate electrical energy
In voltaic cell, the oxidation process occur at the anode while reduction processes occur at the cathode.
The G base of a DNA molecule has the molecular formula C10H12O6N5P. Which two elements in the given formula exhibit show similar chemical and physical properties?A) C and H B) O and PC) N and O D) N and P
Explanation:
The question requires us to identify the two elements present in the molecular formula C10H12O6N5P which present similar chemical and physical properties.
First, we need to identify all elements present in the molecule C10H12O6N5P:
- carbon (C)
- hydrogen (H)
- oxygen (O)
- nitrogen (N)
- phosporus (P)
Next, we can analyze the position of these elements in the periodic table:
Note that H is on the left side of the table, while the other elements (C, N, O and P) are closer together on the right side of the table.
We can see that although there are some elements close on the table, only N and P are part of the same group of the periodic table. Based on this, we can say that N and P should present similar properties because they are part of the same group.
Final answer: N and P should present similar chemical and physical properties (letter D).
what is the logic behind drawing lewis fomrulas for like harder and weird compounds like how can you figure it out easy.harder compounds like ch3och3
Answer:
The logic behind drawing Lewis formulas is to use the valence electrons of the elements and complete the Octet rule.
Explanation:
The logic behind drawing Lewis formulas is to use the valence electrons of the elements and complete the Octet rule.
Valence electrons are the electrons of an atom that are located in the last shell. We represent the valence electrons using dots between covalent bonds.
The Octet rule says that an element loses or gains electrons in order to achieve the electron configuration of the nearest noble gas, it means that it will try to have 8 electrons in the last shell.
For example: CH3OCH3
1st) It is necessary to find the total number of valence electrons. We can find the electrons of valence of each atom in the Periodic Table, and then we have to multiply it by the number of atoms in the molecule:
- Total number of valence electrons of C: 4e * 2 = 8e
- Total number of valence electrons of H: 1e * 6 = 6e
- Total number of valence electrons of O: 6e * 1 = 6e
Total number of valence electrons of CH3OCH3 = 20e (8 + 6 + 6 = 20)
2nd) Now we have to start drawing with the least electronegative atom in the center. In this case, we have to draw the O in the center (even though it is not the least electronegative atom in the molecule), because it is the only one that has only 1 atom in this molecule, and hydrogen atoms always go on the outside:
We have to start drawing the electrons, trying to complete the octets on the outside atoms, in this case, hydrogen, then carbon, and finally oxygen.
Hydrogen atom only needs 2 valence electrons to complete the last sheel.
How much motion energy does an 0.5-kg hockey puck sliding across the ice rink at 4 m/s have?
Answer:
A hockey puck is given an initial speed of 5.3 m/s . If the coefficient of kinetic friction between the puck and the ice is 0.05, how far does the puck slide before coming to rest? Solve this problem using conservation of energy.
Explanation:
This is easy to do and it is very cool how it works.
Force here is what converts the kinetic energy to heat by friction and slows the puck
fu = coefficient of Kinetic friction
g = is the acceleration of gravity
Fu*g = a.
So friction force on the puck is the acceleration of gravity times the coefficient of kinetic friction and the acceleration force is made negative here because it is slowing down the puck. .
Puck friction to negative acceleration
fu=0.05
g = -9.81m/s^2
so
a = 0.05 * -9.81m/s^2 = -0.4905 m/s^2
For the moving puck
Velocity = v = u + (a*t) | u=initial velocity
So
Time = t = (v-u)/a
Distance = d = t *(v + u)/2
So
Distance d= ((v-u)/a) * ((v+u)/2)
This becomes d = (v-u)(v+u)/2a
Plugging in the numbers
d= (0 - 5.3)(0 + 5.3)/(2*-0.49.5) =28.63 meters
Part A identify club soda as an element, compound, or mixture part B explain why you chose the answer for part A.
EXPLANATION:
PART
Soda drink is a mixture
PART B
Soda drink is a mixture and not a compound. This is because it contains different constituents and they are mixed together in the right proportion. Also, the composition of the constituents is uniform throughout the mixture.
edAnswersweredQuestion 6How many H atoms are in 3.4 mol C21H23NO5?1.3 x 10³2.9 x 1042.0 x 10244.7 x 10254.7 x1025. This was the correct answer.↓0/1 pts0/1 ptc
Given the following parameters
moles of C21H23NO5 = 3.4 moles
Since there are 23 atoms of hydrogen in the compound, hence the moles of hydrogen in the compound is given as:
[tex]\begin{gathered} moles\text{ of H}=23\times3.4 \\ moles\text{ of H}=78.2moles \end{gathered}[/tex]According to the Avogadro's constant
[tex]1mole\text{ of a substance}=6.02\times10^{23}atoms[/tex]Convert the moles of hydrogen to atoms
[tex]\begin{gathered} atoms\text{ of H}=78.2\times6.02\times10^{23} \\ atoms\text{ of H}=470.764\times10^{23} \\ atoms\text{ of H}=4.70764\times10^{25} \\ atoms\text{ of H}=4.7\times10^{25}atoms \end{gathered}[/tex]A 0.19 mole sample of nitrogen gas occupies a volume of 2.25 L. What is the volume of 0.27 mol of nitrogen gas under the same conditions?
Step 1 - Discover the relation between moles and volume
The gas state equation states that:
[tex]pV=\text{nRT}[/tex]Since the exercise says that both pressure and temperature will remain the same ("under the same conditions"), and R is already a constant, we can obtain a direct relation between moles and volume:
[tex]V=n(\frac{RT}{P})\rightarrow V\propto n[/tex]Since R, T and P will not vary, the quocient in parenthesis is a constant. Therefore, the volume will be directly proportional to the number of moles of gas.
Step 2 - using the relation to solve the problem
Since, as we saw, volume and moles are directly proportional to each other, we can set the following proportion to discover the new volume:
[tex]\begin{gathered} 0.19\text{ moles of N2----2.25 L} \\ 0.27\text{ moles of N2-----x} \\ \\ x=\frac{0.27\times2.25}{0.19}=3.19\text{ L} \end{gathered}[/tex]So, the volume of 0.27 moles of N2 gas, under the same conditions, will be 3.19 L.
A gas occupies 3.8 L at -18° C and 975. torr. What volume would this gas occupy at STP?
To solve the question we will assume that the gas behaves like an ideal gas, that is to say, that there is no interaction between the molecules. Assuming ideal gas we can apply the following equation:
[tex]PV=nRT[/tex]Where,
P is the pressure of the gas
V is the volume of the gas
n is the number of moles
R is a constant
T is the temperature
Now, we have two states, an initial state, and a final state. The conditions for each state will be.
Initial state (1)
P1=975Torr=1.28atm
V1=3.8L
T1=-18°C=255.15K
Final state(2), STP conditions
P2=1atm
T2=273.15K
V2=?
We will assume that the number of moles remains constant, so the nR term of the first equation will be constant. For each state, we will have:
[tex]\begin{gathered} \frac{P_1V_1}{T_1}=nR \\ \frac{P_2V_2}{T_2}=nR \end{gathered}[/tex]Since nR is the same for both states, we can equate the equations and solve for V2:
[tex]\begin{gathered} \frac{P_{2}V_{2}}{T_{2}}=\frac{P_1V_1}{T_1} \\ V_2=\frac{P_{1}V_{1}}{T_{1}}\times\frac{T_2}{P_2} \end{gathered}[/tex]We replace the known values:
[tex]V_2=\frac{1.28atm\times3.8L}{255.15K}\times\frac{273.15K}{1atm}=5.2L[/tex]At STP conditions the gas would occupy 5.2L. First option
in the periodic table how would you group copper, chlorine, iodine, vanadium, astatine ? (based on columns) A. (copper, vanadium) (chlorine, iodine, astatine)B. (copper, astatine) (chlorine, iodine, vanadium)C. (copper, chlorine, iodine) (vanadium, astatine)D. (copper, astatine, vanadium) (chlorine, iodine)
1) Characteristics of the elements mentioned.
Chlorine, Iodine, and Astatine are nonmetals. They are in the 17th group the halogens. They're in the p-block
Copper and Vanadium are transition metals. They're in the d-block.
We can group these elements in metals (Copper and Vanadium) and nonmetals (Chlorine, Iodine, and Astatine)
4 Which protective measure is 100 percent effective at reducing the risk of sexually transmitted disease? A. Use a condom during intercourse. B. Keep the number of partners to a minimum. C. Use birth control pills correctly. D. Abstain from sexual activity.
Which protective measure is 100 percent effective at reducing the risk of sexually transmitted disease is . and Abstain from sexual activity.
The protective measure is 100 percent effective at reducing the risk of sexually transmitted disease is only Abstain from sexual activity. The other methods that is keep number of partners to a minimum , use birth control pills correctly are for reducing risk for pregnancy. Use a condom during intercourse is reduce the risk for sexually transmitted disease but not 100 % effective.
Thus, Which protective measure is 100 percent effective at reducing the risk of sexually transmitted disease is Abstain from sexual activity.
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write the chemical structure of 2 ethyl pentanoic acid
Hope this answer helps you
5
Which of the following shows kinetic energy being converted into potential energy?
A-a boulder rolling across the ground
B-a rock being tossed high into the air
C-a boulder falling off the edge of a cliff
D-a rock sitting in the grass
Answer:
c
Explanation:
boulder was at rest on top of a hill so it contains abundant potentialenergy. When the boulder falls, its potential energy will change to kinetic energy, the energy of motion. When the boulder stops moving, its kinetic energy will transform back to potential energy
If an ideal gas does not really exist, why do scientists use this this concept?
The ideal gas model was created to summarize some laws and study the behaviour of the gases, that depends on the properties.
It is really helpful and it is the first approach to the real behaviour of the gases, because all the other equations that came out after it, they have a basis on it. Historically, the ideal gas model was one of the first and most suitable ways to describe and calculate the properties of the gases.
It is also important that it's one of the easiest ways to relate the properties that are in the model, and it's very useful under certain conditions (specially temperature and pressure).
Iron (III) oxide reacts with Carbon to form Iron and Carbon monoxide. How many moles of Iron can be formed from 125 KILOGRAMS of Iron (III) oxide?
For the complete reaction of 130 ml 0.140 mole ,130 ml of 0.14 moles is required.
What is moles?
mole Is the unit of amount of substance in the international system of unit.
For the complete reaction of 130 ml 0.140 M CO (NO3)2, 130 ml of 0.14 is required.
The reaction of Li2S with CO(NO3)2 will be:
Li2S +CO(NO3)2-->2LiNO3+COS
Accordingly, 1 mole of Li2S completely reacts with 1 mole of CO(NO3)2.
moles of CO(NO3)2 - Molarity Volume (L)
moles of = 0.140 M × 0.13 L
moles of CO(NO3)2 = 0.0182 moles.
The moles of Li2S reacts with CO(NO3)2 will be 0.0182 moles.
Volume of = Li2S= moles/molarity
Volume of = Li2S 0.0182/0.140
Volume of Li2S = 0.13 L
Volume of Li2S = 130 ml.
For the complete reaction of 130 ml 0.140 M , 130 ml of 0.14 is required.
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