ANSWER
Bubbles forming from hydrogen gas production
EXPLANATION
Given that;
[tex]\text{ Zn}_{(s)}\text{ + 2HCl}_{(aq)}\rightarrow\text{ ZnCl}_{2(aq)}\text{ + H}_{2(g)}[/tex]One of the method used in the preparation of hydrogen gas is the reaction of metals with acid
The above reaction is one of the method of producing hydrogen gas
When Zn reacts with HCl, bubbles formed which is as a result of hydrogen production.
Therefore, the correct answer is Bubbles forming from hydrogen gas production
Which of the following are spectator ions in the reaction shown below? Select all that apply.
In this question, we have to find which ions are classified as spectator ions. The definition of spectator ions is the ones that will not participate directly in any change in the reaction.
In a reaction we usually have 2 main changes for the ions, they can change their oxidation number, in a reaction called redox reaction. They can also change their physical state, going from aqueous to solid.
The spectator ions will not have their oxidation number changed and they will not change their physical state.
The 2 ions that can be classified as spectator ions are Na+ and NO3-
Answer: son Na+ y NO3-
Explanation:
A student stops a titration BEFORE theequivalence point is reached. If NaOH isbeing added to an unknown acid, HA, whations are present in the clear solution in theflask?A. H+, A-, Na+, OH-B. A-, Na+, OH-C. A-, Na+ and H+
Answer
ions are present in the clear solution in the flask, if NaOH is being added to an unknown acid, HA, before equivalence are:
. A⁻, Na⁺ and H⁺
Calculate percent volume/volume of a solution that contains 80 ml of methanol and 230 ml of water?
25.81%
Explanations:The formula for calculating the percent volume/volume of a solution is given as:
[tex]\%v\text{/v}.=\frac{volume\text{ of solute}}{volume\text{ of solution}}\times100[/tex]Given the following parameters
volume of solute (methanol) = 80mL
volume of solution = volume of water + methanol
volume of solution = 80mL + 230mL = 310mL
Determine the required percent v/v
[tex]\begin{gathered} \%v\text{/}v=\frac{80mL}{310mL}\times100 \\ \%v\text{/}v=\frac{800}{31} \\ \%v\text{/}v=25.81\% \end{gathered}[/tex]Hence the percent volume/volume of a solution that contains 80 ml of methanol and 230 ml of water is 25.81%
Energy is absorbed when an electron changes from principal energy level3 to 53 to 22 to 14 to 2
Answer:
[tex]3\text{ to 5}[/tex]Explanation:
When an electron moves from one energy level to another, energy is either absorbed or released
When an electron moves from a lower to a higher energy level, energy is absorbed. When an electron moves from a higher level to a lower level, energy is released
Since the electron moves from a lower level 3 to a higher level 5, emergy is absorbed
Thus, movement from 3 to 5 is the answer
Describe two properties that the elements in the last two columns of the Periodic Table share with one another.
Two properties that the elements in the last two columns of the Periodic Table share with one another are;
they are all non-metalsthey show gradation in their physical and chemical properties.What are the elements in the last two columns of the periodic table?The elements in the last two columns of the periodic table are the group 17 and group 18 elements of the periodic table.
The elements in group 17 are known as halogens while the elements in group 18 are known as noble gases.
The halogens includes the following elements - Fluorine, Chlorine, Bromine, Iodine, Astatine, and Ununsepetium.
The noble gases include the following elements - Helium, Neon, Argon, Krypton, Xenon, and Unonoctium.
A common feature of these elements is that they are all non-metals. The elements also show gradation in their physical and chemical properties.
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(07.05 HC)In an experiment, sulfuric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was formed during thereaction. A cross drawn at the base of each flask became gradually invisible due the formation of this yellow precipitate. The time taken for thecross to become invisible was recorded. A partial record of the experiment is shown.Experimental RecordFlask Volume of Volume of Volume of TimeH2SO4 Sodium Thiosulfate Water5 mL 50 mL10 mL 119 seconds5 mL 40 ml10 mL3 5 ml 30 ml120 mL4 15 ml 120 mL30 mLBased on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the experimental record.Use complete sentences to explain the trend you predicted. You do not have to determine exact values for time; just describe the trend youwould expect (increase or decrease) and why it occurs.
The rate of the reaction usually depends on the concentration of the reactants. We have to reactants in this reaction, sulfuric acid and sodium thiosulfate. Let's look at the values that were recorded.
The volume of sulfuric acid that is added is constant, but the volume of sodium thiosulfate is not. It decreases and the volume of water increases, so we are diluting the sodium thiosulfate. The concentration of one reactant is decreasing. So the rate of the reaction is also decreasing. Then the time that it takes for the cross to become invisible should increase.
Answer: the time should increase.
Please help me because I am unable to find help and I have to turn in this assignment or else I will fail this class for the year.
Explanation:
To solve this question, we need to use the following equation:
M = n/V
where:
M = molarity
n = number in moles
V = volume
For trial 1 we have:
M of NaOH = 0.112 mol/L
n = ??
V = 7.18 mL (we need to transform it to L, just divide by 1000)
V = 0.718 L
So:
M = n/V
n = M*V
n = 0.112*0.718
n = 0.080 moles of NaOH
The equation of dissociation of NaOH is:
NaOH --> Na+ + OH-
0.080 0.080 0.080
Answer for trial one: 0.080 moles of OH- or 8.0x10^-2 moles
For trial 2 we have:
For trial 1 we have:
M of NaOH = 0.112 mol/L
n = ??
V = 7.20 mL (we need to transform it to L, just divide by 1000)
V = 0.720 L
So:
M = n/V
n = M*V
n = 0.112*0.720
n = 0.081 moles of NaOH
The equation of dissociation of NaOH is:
NaOH --> Na+ + OH-
0.081 0.081 0.081
Answer for trial two: 0.081 moles of OH- or 8.1x10^-2 moles
Oxygen and oxygen-containing compounds are involved in many different reactions. which balanced equation represents a reaction that involves 14 atoms of oxygen
Answer: 2C2H6+7O2→4CO2+6H2O
Explanation:
Answer:2C2H6+7O2→4CO2+6H2O
Explanation:
The best example of a solution among the following is ______.A. chalk powder in waterB. muddy waterC. table salt (sodium chloride) in waterD. oil in water
Answer
C. table salt (sodium chloride) in water
Explanation
Sodium chloride dissolves in water forming a solution
How do I calculate each of these?- Fractional uncertainty in mass of liquid sample - Fractional uncertainty in volume of liquid sample - Fractional uncertainty in density of liquid sample - Uncertainty in density of liquid sample
Fractional uncertainty is found by dividing the absolute uncertainty by the quantity itself. It is always the same for every measure: mass, volume, density, etc.
For example, if we have this measure 7.5+-0.1kg. The fractional uncertainty is:
[tex]\frac{0.1}{7.5}=0.013[/tex]A block of al with a density of 2.7/ml has a mass of 549 g. what's the volume. ( show steps)
Explanation:
We are given: density of Al = 2.7g/mL
: mass of Al = 549g
[tex]\begin{gathered} \rho\text{ = }\frac{m}{V} \\ \\ \therefore\text{ V =}\frac{m}{\rho} \\ \\ \text{ =}\frac{549}{2.7} \\ \\ \text{ = 203.33mL} \end{gathered}[/tex]Answer:
The volume is 203.33mL
In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was formed during the reaction. A cross drawn at the base of each flask became gradually invisible due the formation of this yellow precipitate. The time taken for the cross to become invisible was recorded. A partial record of the experiment is shown.Experimental RecordFlaskVolume ofHClVolume ofSodium ThiosulfateVolume ofWaterTime110 mL10 mL40 mL14 seconds210 mL20 mL30 mL310 mL30 mL20 mL410 mL40 mL10 mLBased on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the experimental record. Use complete sentences to explain the trend you predicted. You do not have to determine exact values for time; just describe the trend you would expect (increase or decrease) and why it occurs.
Answer
Decrease
Explanation
In the last column, the time it will take for the reaction to complete with decrease, meaning the rate of reaction will increase, this is because the reactant concentration was increased. Increasing the concentration of one or more reactants will often increase the rate of reaction. Because a higher concentration will lead to more collisions of that reactant at a specific time.
midterm 3 In an effort to stretch already thin educational budgets, a county’s school cut home economics from their offered programs. Fast forward to 10 years down the road, which statement shows the MOST likely consequence of that choice? A. The county now has a generation of young adults who eat mostly fast food and take out. B. The county has a higher rate of college graduates and the median income has risen. C. The county has seen little to no change that can be traced back to the decision to cut the program. D. The county now has a generation of young adults who are opening new bars, breweries, and restaurants. wellness & nutrition
In an effort to stretch already thin educational budgets, a county’s school cut home economics from their offered programs fast forward to 10 years down the road then the county has a higher rate of college graduates and the median income has risen
Home economics be thought in the school again because student all over the world can be empowered by home economics programs by learning essential life skills that, occasionally, cannot be gained from textbooks or parents
And most significantly the knowledge and ability acquire on the home economic class give every student the confidence and positive reinforcement they require
Due to fact that it cover important concepts related to the family house, clothes, and food, this subject aids society in advancing human growth
Human advancement is essential to the development of society and also building essential life skills
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Calculate the moles of HCI needed to react completely with 8.25 moles of zinc. I picked C but I’m not sure if I’m correct
Answer:
D. 16.5 moles
Explanation:
From the balanced reaction we know that 1 mole of Zn reacts with 2 moles of HCl.
We can calculate the moles of HCl needed to react completely with 8.25 moles of zinc, using the stoichiometry of the reaction and a mathematical rule of three:
[tex]\begin{gathered} 1moleZn-2molesHCl \\ 8.25molesZn-x=\frac{8.25molesZn*2molesHCl}{1moleZn} \\ x=16.5molesHCl \end{gathered}[/tex]So, 16.5 moles of HCl are needed.
Which of the following describes how difficult it is to remove a valence electron from an atom of a particular element?
A: Electron Affinity
B: Ionization energy
C: Atomic Radius
D: Electronegativity
The term that describes how difficult it is to remove a valence electron from an atom of a particular element is electron affinity (option A).
What is electron affinity?Electron affinity is the energy released when an electron is attached to an atom or molecule; used as a measure of its ability to form an anion.
It becomes harder to remove an electron when an atom has a net positive charge because the attraction that the nuclear charge exerts per electron gets larger.
It takes a large amount of energy to remove electrons from an element with high electron affinity, hence, electron affinity determines how difficult it is to remove a valence electron from an atom.
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12. What are the 2 types of stability and how do they relate to the parts of the atom?
An atom is stable when its total charge is equal to 0 (zero).
There are 2 situacions that can make an atom not stable (or its total charge is not zero):
1. One situation is that the atom has excess of negative charge. In this case, the atom is stabilized by transferring valence electrons to another atom.
2. Another situation is that the atom has excess of positive charge. In this case, the atom is stabilized by obtaining electrons from another atom.
In both cases, the parts of the atom related to the stable state are the electrons.
Iodine-131 has a half-life of 8 days. If you start with a sample of 150 grams, how much of the original isotope will remain after 30 days?A. 144 gramsB. 150 gramsC. 11 gramsD. 8 grams
The first step is to remember the equation for radioactive disintegration:
[tex]M(t)=\text{ M}_{0\text{ }}*\text{ }e^{\frac{-t\text{ * ln 2}}{T}}[/tex]Where M(t) is the mass of the atom at any time t, Mo is the initial mass of the element, and T is the half-life time.
In this case, we have to calculate M(t), which is the remaining mass of the radioactive element. We have all the data from the right part of the equation (initial mass Mo, the time t at we want to calculate the remaining mass, and the half-life T of the element):
[tex]\begin{gathered} M(8)=\text{ 150 g * }e^{\frac{-30\text{ d }*\text{ }ln\text{ 2}}{8\text{ d}}\text{ }} \\ M(8)=\text{ 11.1488 g} \end{gathered}[/tex]Then, the answer is that the remaining mass of iodine-131 is C. 11 g approx
Question 4 of 25aFor a bond to be covalent, the electronegativity difference between the atomsmust be:OA. zero.B. less than 1.7.OC. less than 0.5.D. over 2.
Answer:
B. Less than 1.7.
Explanation:
A covalent bond can be polar o non polar, but if the electronegativity difference between the atoms is less than 1.7 will be covalent polar and it will be covalent nonpolar if it is less that 0.5.
Calculate the number of moles of carbon dioxide gas in this fire extinguisher. Gas type CO2 temperature: 212 K pressure: 4.55 atm Volume: 3.5L
Answer
0.9154 mol CO₂
Procedure
To solve this question you will need to use the ideal gas law
PV=nRT
Data
P=4.55 atm
V= 3.5 L
T= 212 K
R=0.082057 L⋅atm⋅K⁻¹⋅mol⁻¹
Solve for n
[tex]n=\frac{PV}{RT}=\frac{4.55\text{ atm }3.5\text{L mol }\degree\text{K}}{0.082057\text{ L.atm }212\degree\text{K}}=0.9154\text{ mol }[/tex]Bromination of isobutane is a two‑step reaction. Step 1 reaction is: a coumpound with a central carbon atom with three single bonded C H 3 groups and one single bonded hydrogen plus radical bromine react to form a compound with a central carbon atom with a single electron and three single bonded C H 3 groups plus bromine with a single bonded hydrogen atom. Step 2 reaction is: a compound with a central carbon atom with a single electron and three single bonded C H 3 groups plus bromine single bonded to bromine react to form a coumpound with a central carbon atom with three single bonded C H 3 groups and one single bonded bromine plus radical bromine. The overall reaction is: a coumpound with a central carbon atom with three single bonded C H 3 groups and one single bonded hydrogen plus bromine single bonded to bromine react to form a coumpound with a central carbon atom with three single bonded C H 3 groups and one single bonded bromine plus bromine with a single bonded hydrogen atom. Using the table of bond dissociation energies for A−B⟶A+B, calculate the enthalpy of each step and the enthalpy of the overall reaction.
Bromination of isobutane is a two‑step reaction.
The enthalpy of each step : step 1: ΔH = 34 kJ/mol. step 2 : ΔH = -99 kJ/mol enthalpy of the overall reaction , ΔH = 65 kJ/mol.
Bond dissociation energy :
H - H = 436 kJ/mol
H - Br = 366 kJ/mol
Br - Br = 193 kJ/mol
(CH₃)₃C - H = 400 kJ/mol
(CH₃)₃C - Br = 292 kJ/mol
Step 1 : (CH₃)₃C - H + Br ------> (CH₃)₃C° + H - Br
ΔH = ∑ Bond broken - ∑ Bond form
ΔH = 400 kJ/mol - 366 kJ/mol
ΔH = 34 kJ/mol
Step 2: (CH₃)₃C° + Br - Br ----> (CH₃)₃ - Br + Br
ΔH = ∑ Bond broken - ∑ Bond form
ΔH = 193 - 292
ΔH = - 99 kJ/mol
overall reaction :
(CH₃)₃ - H + Br - Br ----> (CH₃)₃ - Br + H- Br
ΔH = ( 400 + 193 ) - ( 292 + 366 )
ΔH = 593 - 658
ΔH = - 65 kJ/mol
Thus, Bromination of isobutane is a two‑step reaction.
The enthalpy of each step : step 1: ΔH = 34 kJ/mol. step 2 : ΔH = -99 kJ/mol enthalpy of the overall reaction , ΔH = 65 kJ/mol.
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Calculate the quantity (in grams) of sucrose (C12H22011) required to make a 1.00 M strength solution with a volume of 500. mL.
Let us first define the term molarity. Molarity is a way of expressing the concentration of a compound in solution and is defined as the number of moles per liter of solution.
We are given the molarity value, 1.00M, and the volume of the solution, 500 mL=0.5L. We can find the number of moles by clearing them from the following equation:
[tex]\begin{gathered} Molarity=\frac{MolesSolute}{Lsolution} \\ MolesSolute=Molarity\times Lsolution \end{gathered}[/tex]We replace the known data:
[tex]\begin{gathered} MolesSolute=1.00M\times0.5L \\ MolesSolute=1.00\frac{mol}{L}\times0.500L=0.500molC_{12}H_{22}O_{11} \end{gathered}[/tex]Now, the grams of sucralose are found by multiplying the moles found by the molar mass of sucralose, which is 342.3 g/mol:
[tex]gC_{12}H_{22}O_{11}=0.500molC_{12}H_{22}O_{11}\times\frac{342.3gC_{12}H_{22}O_{11}}{1molC_{12}H_{22}O_{11}}=171gC_{12}H_{22}O_{11}[/tex]The quantity of sucrose required will be 171 g of sucrose
ObjectiveYou will write a report on the states ofmatter, answering the question:How do water molecules change as theirstate of matter changes from solid, to liquid,to gas?MaterialsParagraph graphic organizerRubricThe Changing Water MoleculeReportHow do water molecules change as theirstate of matter changes? You will explorethese changes as you write your report onthe changing molecules.Hydrogen and oxygen bond together to formwater molecules. Water's state of matter willchange depending on how these moleculesare arranged. You have been learning aboutthe three states of matter - solid, liquid, andgas. Use this knowledge to write a report inresponse to this question:How do water molecules change as theirstate of matter changes from solid, toliquid, to gas?Your report should include an introduction, aparagraph for each state of matter..
Topic sentence:
All matter is composed of atoms that are in constant motion, three types of motion can be identified translation, rotation, and vibration. These particles are so small that they cannot be observed even with the smallest microscope, but they are so important that depending on their motion and interaction with other particles will be their state and how we see them at the macroscopic level. The greater the movement of the molecules the greater the disorder, so we can distinguish three states of matter presented from greater to lesser disorder: gas, liquid and solid.
Gas:
The motion in gases presents the three types of movement: translation, rotation, and vibration, and is the most intense. In the case of gases, the particles are quite far apart compared to their size. The approximate average distance between particles, under normal conditions, is ten times the particle size. In gases the particles do not occupy fixed positions, they are disordered and move randomly vibrating, rotating, and moving in all directions.
Liquid:
Liquids also exhibit all three types of motion (translation, rotation, and vibration) but with less intensity than in gases. In liquids, the particles do not occupy fixed They are disordered, although less so than in gases, and move randomly, as in gases, but with less intensity.
Solid:
The cohesive forces in solids are strong, much greater than in liquids, which are weak, and practically non-existent in gases. In solids, the particles occupy fixed positions, are ordered, and have no translational or rotational motion, only vibration.
Concluding sentence:
For all states of matter, the pressure and temperature involved will affect the order of the molecules making it possible to pass from one state to another by changing these variables.
At equilibrium, 1.0 mol of a 4.5 x 10-4 M solution of substance A reacts with 1 mol of a solid to form 2.0 mol of a 1.2 x 10-2 M solution of substance C and 1.0 mol of a solution of substance D. Given that K = 2.0 x 10-6, what is the equilibrium concentration of substance D?
Step 1
The reaction:
1 A (aq) + 1 B (s) <=> 2 C (aq) + 1 D (aq)
A, C and D participate in the equilibrium constant K
B doesn't participate
--------------------
Step 2
Data provided:
At equilibrium:
[A] =4.5 x 10^-4 M
[C] = 1.2 x 10^-2 M
[D] = Unknown
-------------------
Step 3
[tex]K\text{ = }\frac{\lbrack D\rbrack^1\lbrack C\rbrack^2}{\lbrack A\rbrack^1}=\frac{\lbrack D\rbrack.(1.2x10^{-2}M)^2}{(4.5x10^{-4}M)}=\text{ 2.0 x 10}^{-6}[/tex]Answer:
[D] = 6.25x10^-6 M
b) Assuming a reaction starts with 1 mole of octane, which burns at 220°C, and is at a pressure of 1 atm, what volume will the products occupy upon reaction completion?
Answer
40.48 liters
Explanation
Given: that:
n = mole = 1 mol
P = Pressure = 1 atm
T = Temperature = 220 °C = (220 + 273K) = 493 K
What to find:
The volume of the product.
Step-by-step solution:
The volume, V of the product can be calculated using the ideal gas equation:
PV = nRT
Putting the values of the parameters and molar gas constant, R = 0.0821 liter·atm/mol·K into the formula, we have:
[tex]\begin{gathered} V=\frac{nRT}{P}=\frac{1\text{ }mol\times0.0821\text{ }L.atm\text{/}mol.K\times493\text{ }K}{1\text{ }atm}=40.48\text{ }L \\ \end{gathered}[/tex]Thus, the volume of the product, upon reaction completion, will occupy 40.48 liters.
With the following information: Volume of vinegar 25 mL Mass of sodium bicarbonate 1 g Initial temperature of vinegar 17 °C Final temperature of vinegar 14 °C Change in temperature °C (∆T) ?? (answer needed) Calculate the approximate enthalpy of the reaction in joules. Estimate that 1.0 mL of vinegar has the same thermal mass as 1.0 mL of water. Ignore the thermal mass of the sodium bicarbonate. Note: It takes about 4.2 joules (J) to change 1.0 gram (1.0 mL) of water 1.0 °C.
First, let's calculate the change in temperature, which results in making the next subtraction:
[tex]\Delta T=\text{ T}_{fin}\text{ - T}_{in}=\text{ 14\degree C-17\degree C= -3\degree C}[/tex]Now, let's calculate the enthalpy of the reaction with the next assumptions:
[tex]\begin{gathered} -\Delta H_r=\text{ Q}_{sen}^{vinegar}+\text{ Q}_{sen}^{NaHCO_3} \\ \\ As\text{ we are told in the exercise, we ignore the second term. Then:} \\ \\ -\Delta H_r=\text{ Q}_{sen}^{vinegar} \end{gathered}[/tex]We also have to make the following assumptions: the vinegar's thermal mass and density are the same as the water's. Then, we can make the calculation:
[tex]\begin{gathered} Q_{sen}^{vinegar}=\text{ m*Cp*}\Delta T \\ \\ Where\text{ m is the mass. } \\ Cp\text{ is the specific thermal capacity. } \\ \Delta T\text{ is the change in temperature. } \end{gathered}[/tex][tex]Q_{sen}^{vinegar}=\text{ 25 mL * }\frac{1\text{ g}}{1\text{ mL}}*\text{ 4.2 }\frac{J}{g*^oC}*(-3^oC)=\text{ -315 J = -}\Delta H_r[/tex]So, the reaction enthalpy equals 315 J approx.
If the density of an ether was 0.727g/mL and the mass 17.7 grams, what is the volume?Report the answer in (mL) to three significant figures and also include the correct unit
Remembering the formula of density, we can clear the volume and replace the given data in the new formula:
[tex]\begin{gathered} \text{density}=\frac{mass}{volume}, \\ \text{volume}=\frac{mass}{density}. \end{gathered}[/tex]Our data is: for mass is 17.7 grams (g) and for density is 0.727 g/mL:
[tex]\text{volume}=\frac{17.7\text{ g}}{0.727\text{ }\frac{g}{mL}}=24.347mL=24.3mL.[/tex]The volume of the ether is 24.3 mL of 17.7g and 0.727 g/mL.
I just need a clarification please for me I see they’re synthesis I want to be clear P4 + 6 H2 = 4 PH32 H2 + O2 = 2 H2O
In a synthesis reaction, two or more reagents react to form a new product. In decomposition reactions, a single reagent is separated into two or more new products.
According to the given equations:
Phosphorus and hydrogen react to form a new product which is phosphane.
It means that the first is a synthesis reaction.
Hydrogen and oxygen react to form a new product which is water.
It means that the second is also a synthesis reaction.
-4 AI (s) + 302(g)=2Al2O3(s)How many grams of Al2O3 can be formed from 43.91 g of Al and 54.13 g of O2?(Hint: You need to determine which one is the limiting reactant).
82.94g of Al2O3 will be produced.
1st) With the molar mass of each compound and the balanced equation, we need to find which reactant is the limiting reactant.
- Al molar mass: 27g/mol
- O2 molar mass: 32g/mol
- Al2O3 molar mass: 102g/mol
Calculation with Al:
According to the balanced equation, 108g of Al (4 x 27g) needs 96g of O2 (3 x 32g), so with a mathematical rule of three we can calculate the amount of oxygen that is needed to react with 43.91g of Al:
[tex]\begin{gathered} 108\text{gAl}-96gO_2 \\ 43.91\text{gAl}-x=\frac{43.91\text{gAl}\cdot96gO_2}{108\text{gAl}} \\ x=39.03gO_2 \end{gathered}[/tex]Now we know that, 43.91g of Al will need 39.03g of O2 to react, and we have 54.13g of O2, so there is excess of oxygen.
Calculation with O2:
According to the balanced equation, 108g of Al (4 x 27g) needs 96g of O2 (3 x 32g), so with a mathematical rule of three we can calculate the amount of aluminum that is needed to react with 54.13g of O2:
[tex]\begin{gathered} 96gO_2-108gAl \\ 54.13gO_2-x=\frac{54.13gO_2\cdot108gAl}{96gO_2} \\ x=60.89\text{gAl} \end{gathered}[/tex]Now we know that 54.13g of O2 will need 60.89g of Al to react, and we have only 43.91g of Al, so it is not sufficient, and that's why Al is the limiting reactant.
2nd) Now that we know that Al is the limiting reactant, we can calculate the grams of Al2O3 that will be produced in the reaction by using the limiting reactant (43.91g):
[tex]\begin{gathered} 108\text{gAl}-204gAl_2O_3 \\ 43.91\text{gAl}-x=\frac{43.91\text{gAl}\cdot204gAl_2O_3}{108\text{gAl}} \\ x=82.94gAl_2O_3 \end{gathered}[/tex]In this calculation we use the balanced equation, so we know that 108g of Al will produce 204g of Al2O3 (2 x 102g).
Finally, 82.94g of Al2O3 will be produced from 43.91g of Al and 54.13g of O2.
How much energy must be removed from 13.9 grams of gaseous oxygen in order to decrease the temperature from 38.8°C to 23.8°C? The specific heat of oxygen is 0.219 cal/g °C. in cal
So,
To solve this question, we could use the equation:
What we're going to do now is to replace the values that we know:
The negative sign of the result indicates that this heat will be lost.
Therefore, the amount of energy that must be removed, equals 45.6615 cal.
Question in image can you please answer it
Answer:
C
Explanation:
The answer is c because the formula for calcium sulfate is CaSO4, and there is only one equation with this in.
Hope this helps!