Answer:
Mg₃N₂ + 4 H₂SO₄ ⇒ 3 MgSO₄ + (NH₄)₂SO₄
Explanation:
To balance an equation, you need to make both sides of the equation have equal number of each element. Also, I think that you didn't write the whole equation since the reaction you gave is not likely.
Mg₃N₂ + 4 H₂SO₄ ⇒ 3 MgSO₄ + (NH₄)₂SO₄
Carbon dioxide ( a greenhouse gas) is breathed out by billions of people all over the world? Yes or no
Answer:
yes
Explanation:
Answer:
yes
Explanation:
Humans inhale oxygen and breath out carbon dioxide.
which statement describes the process of budding
Answer:
Budding, in biology, a form of asexual reproduction in which a new individual develops from some generative anatomical point of the parent organism. ... The initial protuberance of proliferating cytoplasm or cells, the bud, eventually develops into an organism duplicating the parent.
Explanation: im not sure if this will help because you didnt give any statements.
Answer: Cell division with mitosis causes new individuals to develop on a parent.
Explanation: did the test A.P.E.X. hope this helps <3
hellpppppppp me pleaseeeeeeeee
what element is this?????/
Answer:
Helium
Explanation:
Answer:
the element is helium as it's mass number is 4 and number of electrons is equal to it's atomic no. which is 2
what is the structure of methane
Answer:
CH4
Explanation:
if it is wrong, i blame my brain
Tris is a molecule that can be used to prepare buffers for biochemical experiments. It exists in two forms: Tris (a base) and TrisH (an acid). The MW of Tris base is 121.14 g/mol; the MW of TrisH is 157.6 g/mol (the extra weight is due to the Cl- counterion that is present in the acid). The Ka of the acid is 8.32 X 10-9. Assume that you have TrisH in solid form (a powder), unlimited 1M HCl, unlimited 1 M NaOH and an unlimited supply of distilled water. How would you prepare 1 L of a 0.02 M Tris Buffer, pH
Solution :
The reaction :
[tex]$\text{TrisH}^+ + \text{H}_2\text{O} \rightarrow \text{Tris}^- +\text{H}_3\text{O}^+$[/tex]
We have
[tex]$K_a = \frac{[\text{Tris}^-]\times[\text{H}_3\text{O}^-]}{[\text{TrisH}^+]}$[/tex]
[tex]$=\frac{x^2}{0.02-x}$[/tex]
[tex]$= 8.32 \times 10^{-9}$[/tex]
Clearing x, we have [tex]$x=1.29 \times 10^{-5}$[/tex] moles of acid
Now to reach pH = [tex]$7.8 (\text{ pOH} = 14-7.8 = 6.2)$[/tex], we must have an [tex]$OH^-$[/tex] concentration of
[tex]$[OH^-] = 10^{-pOH}$[/tex]
[tex]$=10^{-6.2}$[/tex]
[tex]$=6.31 \times 10^{-7}$[/tex] moles of base
We must add enough NaOH of 1 M to neutralize the acid calculated above and also add the calculated base.
[tex]$n \ NaOH = 1.29 \times 10^{-5} + 6.31 \times 10^{-7}$[/tex]
[tex]$=1.35 \times 10^{-5}$[/tex] moles
Vol [tex]$NaOH = 1.35 \times 10^{-5} \text{ moles} \times \frac{1000 \ mL}{1 \ mol}$[/tex]
= 0.0135 L
Tris mass [tex]$H^+ = 0.02 \text{ mol} \times 157.6 \ g/mol$[/tex]
= 3.152 g
To prepare the said solution we must mix
-- [tex]$3.152 \ g \text{ TrisH}^+$[/tex]
-- [tex]$0.0135 \ mL \ NaOH \ 1M$[/tex]
-- [tex]$\text{Gauge to 1000 mL with H}_2\text{O}$[/tex]
What enzyme catalyses the reaction of PRPP transfer to hypoxanthine with
formation of IMP?
Answer:
HPRT
Explanation:
HPRT catalyzes the salvage reactions of hypoxanthine and guanine with PRPP to form IMP and GMP
The formation of GMP from IMP requires oxidation at C-2 of the purine ring, followed by a glutamine-dependent amidotransferase reaction that replaces the oxygen on C-2 with an amino group to yield 2-amino,6-oxy purine nucleoside monophosphate, or as this compound is commonly known, guanosine monophosphate.
What information in the passage helps answer the question asked previously?
Gravity smooths out even the lumpiest black hole.
A symmetrical collapse forms a smooth hole.
Erratic gravity pulls a black hole in different directions.
A collapse can be symmetrical or lopsided.
Please Hurrry
Answer:
D. A collapse can be symmetrical or lopsided.
Explanation:
I hope this helps
-Have a wonderful day
-Tell me if it is wrong :)
-ED Language Arts
-Questioning in A Black Hole Is NOT a Hole
-Assignment
Thank you
A collapse can be symmetrical or lopsided. Therefore, the correct option is option D among all the given options.
What is black hole?The event horizon of a black hole is an area of spacetime wherein gravity is so intense that nothing, not even light or even other electromagnetic waves, have the energy to cross it. According to general relativity theory, a compact enough mass can bend spacetime into a black hole.
The event horizon is the line beyond which there is no escape. Despite having a significant impact on the outcome and conditions of an object traversing it, general relativity states that it lacks any locally observable characteristics. A black hole behaves in many ways like a perfect black body since it does not reflect light. A collapse can be symmetrical or lopsided. This helps answer the question asked previously.
Therefore, the correct option is option D.
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Your question is incomplete but most probably your full question was,
If the star was spinning before the collapse, then the black hole will spin, too. If the collapse is perfectly symmetric, a smooth black hole forms. On the other hand, even a slightly lopsided collapse leads to a lumpy black hole, with erratic gravitational effects. The gravity might be strong in some places and weak in others, and pull in different directions. However, a lumpy hole won't stay lumpy for long, because its own gravity will work to smooth it out. —A Black Hole Is NOT a Hole, Carolyn Cinami DeCristofano What information in the passage helps answer the question asked previously? Gravity smooths out even the lumpiest black hole. A symmetrical collapse forms a smooth hole. Erratic gravity pulls a black hole in different directions. A collapse can be symmetrical or lopsided.
If 280.4 g of KOH react with an excess of FeCl3, how many grams of Fe(OH)3 will be produced?
FeCl3 + 3 KOH — Fe(OH)3 + 3 KCI
How many grams will be produced?
Answer:
From 00:11
Balance the Molecular Equation
From 01:35
Ions for the Complete Ionic Equation
From 03:04
Net Ionic EquationExplanation:
You want to decaffeinate your coffee by extracting the caffeine out with dichloromethane (they don't do it that way anymore, but they used to). It's too late to extract the caffeine from the coffee beans, because you've already brewed yourself a 200 mL cup of coffee. Your particular brand of coffee contains 100 mg of caffeine in that 200 mL cup. The partition coefficient of caffeine in dichloromethane/water is 9.0 (it is more soluble in the dichloromethane).
How much caffeine would still be in your 200 mL if you did:_____.
A. One extraction using 200 mL ofdichloromethane
B. Two extractions using 100 mL ofdichloromethan each.
Solution :
Partition coefficient Kd
[tex]$=\frac{\frac{\text{mass of caffeine in } CH_2Cl_2}{\text{volume of } CH_2Cl_2}}{\frac{\text{mass of caffeine in water}}{\text{volume of water}}}$[/tex]
= 9.0
A). 1 x 200 mL extraction :
Let m be the mass of caffeine in the water
Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = 100 - m
[tex]$\frac{\frac{100-m}{200}}{\frac{m}{200}} = 9.0$[/tex]
[tex]$=\frac{100-m}{m} = 9.0$[/tex]
[tex]$= 10 m = 100$[/tex]
m = 10
Mass remaining in coffee = m = 10 mg
B). 2 x 100 mL extraction :
First extraction :
Let [tex]$m_1$[/tex] be the mass of caffeine in the water
Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = [tex]$100-m_1$[/tex]
[tex]$\frac{\frac{100-m_1}{100}}{\frac{m_1}{200}} = 9.0$[/tex]
[tex]$=\frac{100-m_1}{m_1} = 4.5$[/tex]
[tex]$ 5.5 \ m_1 = 100$[/tex]
[tex]$m_1$[/tex] = 18.18
Mass remaining in coffee = [tex]$m_1$[/tex] = 18.18 mg
Second Extraction :
Let [tex]$m_2$[/tex] be the mass of caffeine in the water
Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = [tex]$18.18-m_2$[/tex]
[tex]$\frac{\frac{18.18-m_2}{100}}{\frac{m_2}{200}} = 9.0$[/tex]
[tex]$=\frac{18.18-m_2}{m_2} = 4.5$[/tex]
[tex]$ 5.5 \ m_2 = 18.18$[/tex]
[tex]$m_2$[/tex] = 3.3
Mass remaining in coffee = [tex]$m_2$[/tex] = 3.3 mg
Who among, Amit and Saaketh, is correct? Explain.
Answer:
What is their question answers exactly? I won't be able to explain who is correct.
Explanation:
Answer:
Not a lot to draw from this question if im going to be honest
Explanation
Please answer by the number ! I will mark any correct answer brainliest :)
Answer:
36 joules is the answer
1/2mv^2
1/2* 8*3*3
4*9
36joules
how many significant digits are in the number 1.0 × 10^3?
need help whoever answers will be awarded branliest answer
Answer:
1.used to seperate solids from liquids, and is a act of pouring a mixture onto a membrane this allows the passage of liquid and results in the collection of a solid
2. the solution would passed through without losing and solids
3 would allow them to dry or on further hearing decompose
Explanation:
Assume that the ratio of moles of Cl to moles of Cu are 2.39. If we can represent the formula by CuClx, what is the value for x? Round your answer to the nearest whole number. Do NOT include units. So, if you think the formula is CuCl6, you enter the number 6.
Answer:
x=2.
Explanation:
Hello there!
In this case, since we have a mole ratio of moles of Cl to moles of Cu as 2.39, it is possible to write the following:
[tex]\frac{2.39molCl}{1molCu}[/tex]
Thus, since the two possible copper chlorides are CuCl and CuCl₂, we can therefore infer that x=2 since it is close but not as close as it should to the whole number 2.
Best regards!
How are fossil fuels formed from geologic processes?
Answer:
Explanation:
Fossil fuels are hydrocarbons, namely, petroleum , coal and natural gas, formed from buried combustible geologic deposits of organic and natural materials. They are created from decayed animals and plants that convert into coal, crude oil or heavy oil due to constant exposure to pressure and heart in the earth’s crust.
The compounds that make up plankton and plants convert into fossil fuels. Plankton decomposes into natural gas and oil, while plants become coal. Nowadays, humans extract these resources through coal mining and the drilling of oil.
What are fossil fuel ?The term fossil fuel is defined as they are made from decomposing plants and animals. An example of a fossil fuel is coal, as well as oil and natural gas.
Because they were generated from the petrified, buried remains of plants and animals that once lived millions of years ago, coal, crude oil, and natural gas are all referred to as fossil fuels.
Thus, The remains of these animals underwent a transformation into what we now know as fossil fuels over millions of years at great pressure and high temperature.
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A cylinder of oxygen (O2) gas at STP has a volume of 2.75 L. How many oxygen molecules does it contain?
Answer:
7.40×10²² molecules.
Explanation:
From the question given above, the following data were obtained:
Volume of oxygen = 2.75 L
Number of molecules of oxygen =?
Next, we shall determine the number of mole of oxygen present. This can be obtained as follow:
22.4 L contains 1 mole of oxygen at STP.
Therefore, 2.75 L will contain = 2.75 / 22.4 = 0.123 mole of oxygen at STP.
Finally, we shall determine the number of molecules of oxygen present. This can be obtained as follow:
From Avogadro's hypothesis:
1 mole of oxygen = 6.02×10²³ molecules
Therefore,
0.123 mole of oxygen = 0.123 × 6.02×10²³
0.123 mole of oxygen = 7.40×10²² molecules.
Thus, the cylinder contains 7.40×10²² molecules of oxygen.
After you set up your apparatus for the second part of the experiment, your group begins to add the textbooks on top of the plunger. It appears that the plunger continues to drop with every added book and does not return to its original place after the books are removed. What possible sources of error could be given for this experimental outcome? Be specific and give at least two reasons.
The possible sources of error that could be given for this experimental outcome is the change in the density of the air.
What is an experiment?An experiment simply means the procedure that is carried out in order to refute a particular hypothesis. It should be noted that experiments are important to provide insights into the cause and effect of a particular situation.
In this situation, with every added book, the volume of that air column will reduce. It is just important that the temperature should remain constant when the gas compression is taking place.
Another source of error is the assumption of moles that was assumed was constant during the experiment. In this scenario, it's possible that some gas could have escaped while the compression was taking place.
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A 497.9-gallon steel storage tank contains 91.7kg of methane. If the temperature is 23.7˚C what is the pressure inside the tank?
Answer:
74.08 atm
Explanation:
We'll begin by converting 91.7 kg to grams (g). This can be obtained as follow:
1 kg = 1000 g
Therefore,
91.7 kg = 91.7 kg × 1000 g / 1 kg
91.7 kg = 91700 g
Next, we shall determine the number of mole present in 91700 g of methane, CH₄. This can be obtained as follow:
Mass of CH₄ = 91700 g
Molar mass of CH₄ = 12 + (4"1)
= 12 + 4
= 16 g/mol
Mole of CH₄ =?
Mole = mass /Molar mass
Mole of CH₄ = 91700 / 16
Mole of CH₄ = 5731.25 moles
Next, we shall convert 497.9 gallon to litres (L). This can be obtained as follow:
1 gallon = 3.785 L
Therefore,
497.9 gallon = 497.9 × 3.785
497.9 gallon = 1884.55 L
Next, we shall convert 23.7 ˚C to Kelvin temperature. This can be obtained as follow:
T(K) = T(˚C) + 273
T(˚C) = 23.7 ˚C
T(K) = 23.7 °C + 273
T(K) = 296.7 K
Finally, we shall determine the pressure in the tank as follow:
Number of mole (n) = 5731.25
Volume = 1884.55 L
Temperature (T) = 296.7 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =?
PV = nRT
P × 1884.55 = 5731.25 × 0.0821 × 296.7
P × 1884.55 = 139607.92
Divide both side by 1884.55
P = 139607.92 / 1884.55
P = 74.08 atm
Therefore the pressure in the tank is 74.08 atm
The irreversible elementary gas-phase reaction is carried out isothermally at 305 K in a packed-bed reactor with 100 kg of catalyst. The entering pressure was 20 atm and the exit pressure is 2 atm. The feed is equal molar in A and B and the flow is in the turbulent flow regime, with F A0 10 mol/min and C A0 0.4 mol/dm 3 . Currently 80% conversion is achieved. What would be the conversion if the catalyst particle size were doubled and everything else remained the same
Answer:
0.856
Explanation:
Given data:
Feed molar rate ( Fao ) = 10 mol/min
Feed concentration ( Cao ) = 0.4 mol/dm^3
current conversion rate = 80%
Temperature = 305 K
catalyst = 100 kg
entering pressure = 20 atm
exit pressure = 2 atm
Determine the conversion if the catalyst particle size were doubled and everything else remained the same
The conversion if the catalyst particle size were doubled and other factors remains the same = 0.856
attached below is a detailed solution
HELPPP PLZZZZ NOWWW !!!!!!!
Who knows how to do this please help
Answer: You forgot to zero the balance
Explanation:
(80 points)
Requirements
You must include each of the following in your diagram, story/explanation:
1. precipitation
2. runoff
3. evaporation
4. condensation
5. transpiration
6. infiltration
7. groundwater
8. clouds
9. collection areas (example: ocean or lake)
Instructions
1. Complete either the diagram or written explanation – 10 points
• Diagram – you will draw the water cycle process. You must include each of the required items and label each. You are not required to color it, but it is encouraged to help differentiate between the processes.
• Written Explanation – for either of these options you need to include each of the processes. It may be beneficial to explain them in the order in which they occur but is not necessary.
2. Answer the questions
Questions
1. What process drives evaporation and transpiration? Explain how this process operates in the water cycle? (2 Points)
2. What role does gravity play in the water cycle? Hint: it is in more than 1 process (2 Points)
3. What states of matter will your find water in going through the water cycle? (1 Point)
Answer:
1.solar energy drives the cycle by evaporating water from its source and water moves from plants by the process of transpiration
2. in precipitation because the water falls from the sky
3.liquid and gas
Mg(NO3)2 soluble or insoluble?
Answer:
The chemical compound Mg(NO3)2, also known as magnesium nitrate, is very soluble, especially in water.
Can we change a planet’s gravity?
Answer:
No, We cannot change a gravitational field directly. Gravity is due or caused by the energy in objects with mass. ... Either way, once a particle, it is an object thus a source of gravitational potential.
Hope it helps,
Please mark me as the brainliest
Thank you
there are no current practical outer space applications of artificial gravity for humans due to concerns about the size and cost of a spacecraft necessary to produce a useful centripetal force comparable to the gravitational field strength on Earth.
What does this even mean? Help please and thank you!
Answer:
T₁ = P₁V₁T₂ / P₂V₂
Explanation:
The combine gas equation is given by:
P₁V₁ / T₁ = P₂V₂ / T₂
Where:
P₁ => is the initial pressure
V₁ => is the initial volume
T₁ => is the initial temperature
P₂ => is the final pressure
V₂ => is the final volume
T₂ => is the final temperature
Finally, we shall make T₁ the subject of the above expression. This can be obtained as follow:
P₁V₁ / T₁ = P₂V₂ / T₂
Cross multiply
T₁P₂V₂ = P₁V₁T₂
Divide both side by P₂V₂
T₁ = P₁V₁T₂ / P₂V₂
Thus, the formula for T₁ is:
T₁ = P₁V₁T₂ / P₂V₂
I need help with this chem problem!
is clorox an acid or base?
Answer:
Chlorine bleach is strongly basic. We actually make it by dissolving chlorine gas in a concentrated solution of sodium hydroxide, which forms sodium hypochlorite and sodium chloride, in the following equilibrium.
Explanation:
BTS ARMY
PLEASE HELP ME!!! i have no idea how to answer these!
Answer: Im answering this for points
DONT COME ON MY STUFF SAYING THAT I GOT SCHOOL TO DO JUST LIKE YOU AND YOUR GIVING ME IRRELEVANT ANWSERS JUST TO GET POINTS? THATS A WASTE OF MY TIME
Explanation:
*PLEASE HELP*
Write the word equation and the balanced symbol equation for the following reactions
1.Sulfuric acid reacting with sodium carbonate
2.Hydrochloric acid reacting with magnesium hydrogencarbonate
Answer:
1. H₂SO₄ + Na₂CO₃ ⇒ Na₂SO₄ + H₂O + CO₂
sulfuric acid + sodium carbonate ⇒ sodium sulfate + water + carbon dioxide
2. 2 HCl + Mg(HCO₃)₂ ⇒ MgCl₂ + 2 H₂O + 2 CO₂
hydrochloric acid + magnesium hydrogencarbonate ⇒ magnesium chloride + water + carbon dioxide
Explanation:
1. Sulfuric acid is H₂SO₄. Sodium carbonate is Na₂CO₃.
H₂SO₄ + Na₂CO₃ ⇒ Na₂SO₄ + H₂O + CO₂
sulfuric acid + sodium carbonate ⇒ sodium sulfate + water + carbon dioxide
2. Hydrochloric acid is HCl. Magnesium hydrogencarbonate is Mg(HCO₃)₂.
2 HCl + Mg(HCO₃)₂ ⇒ MgCl₂ + 2 H₂O + 2 CO₂
hydrochloric acid + magnesium hydrogencarbonate ⇒ magnesium chloride + water + carbon dioxide
Rick is creating a love potion for Morty. To make the potion, Rick's needs 51 mL of a mixture solution where 40% is carbonated water. After checking around his shop, Rick finds two solutions he could use. The first solution he found is 65% green tea, 15% carbonated water, and 20% whole milk. The second solution is 17% orange juice, 38% lemonade, and 45% carbonated water. How much of the first solution and second solution does Rick need to mix together to create the love potion? Round your final answers to one decimal place. You may solve this problem using any method we have learned in the class.
Answer:
The amount of the first solution rick needs to mix together to create the love portion is 8.5 mL
Explanation:
So as to make the love potion, we have;
The percentage of carbonated water in the love portion = 40%
The percentage of green tea in the first solution = 65%
The percentage of carbonated water in the first solution = 15%
The percentage of whole milk in the first solution = 20%
The percentage of orange juice in the second solution = 17%
The percentage of lemonade in the second solution = 38%
The percentage of carbonated water in the second solution = 45%
Let 'x' represent the volume in mL of the first solution added to make the love portion, and let 'y' be the volume in mL of the second solution added to make the love portion, we have;
x + y = 51...(1)
0.15·x + 0.45·y = 0.40×51 = 20.4
0.15·x + 0.45·y = 20.4...(2)
Solving the system of simultaneous equation by making 'y' the subject of each of the equation gives;
For equation (1)
y = 51 - x
For equation (2)
y = 20.4/0.45 - (0.15/0.45)·x = 136 - 3·x
y = 136/3 - (1/3)·x
Equating the two equations of 'y', gives;
51 - x = 136/3 - (1/3)·x
51 - 136/3 = x - (1/3)·x
17/3 = (2/3)·x
(2/3)·x = 17/3
x = (3/2) × (17/3) = 17/2 = 8.5
x = 8.5
y = 51 - x = 42.5
y = 42.5
Therefore, the amount of the first solution rick needs to mix together to create the love portion, x = 8.5 mL