As the [h+] in a solution decreases, what happens to the [OH^-]?

А. It increases and the pH increases.

B. It increases and the pH decreases.

C. It increases and the pH stays constant.

D. It decreases and the pH increases.

E. It decreases and the pH decreases.

Answers

Answer 1

Explanation:

as the Hydrogen (acid) ion decreases there is a corresponding increase in the Hydroxide (basic) ion.


Related Questions

The percent composition by mass of nitrogen in NH OH (gram-formula mass = 35 grams/mole) is equal to

Answers

Answer:

the percentage composition of mass of nitrogen in NH OH is 42.86 %

How do the causes of surface and deep water currents differ?
A. Surface currents are caused by wind deep water currents are caused by difference in water density
B. Surface currents are caused by the Coriolis effect deep water currents are caused by differences in water density
C. Surface currents are caused by differences in water salinity deep water currents are caused by differences in water temperature
D. Surface currents are caused by differences in water density deep water currents are caused by wind

Answers

Answer:

The answer is A. Surface currents are caused by wind deep water currents are caused by difference in water density.

Balance the chemical equation
C2H6+O2 = CO2 +H2O

Answers

c26886
........................

why blood is separated into different parts​

Answers

Answer:

Blood fractionation is the process of fractionating whole blood, or separating it into its component parts. This is typically done by centrifuging the blood. The resulting components are: a clear solution of blood plasma in the upper phase (which can be separated into its own fractions, see Blood plasma fractionation),

Answer: Centrifugal force is used to separate the components of blood – red blood cells, platelets and plasma – from each other. ... The red blood cells precipitate to the bottom of the bag, with the platelets above them, then the white blood cells and the plasma at the very top. Also because Each part of the blood has a different function. Separating the blood into parts lets patients get only the specific part or parts of the blood that they need. So a whole blood donation can be used for several patients.

Hope this helps have a awesome day/nigh❤️✨t

Explanation:

A granulated cylinder was filled to 30.0 mL with liquid. An unknown metal cylinder having a mass of 60.27 g was submerged in the liquid. The final volume of the liquid level was 45.2 mL.

Answers

Answer:

Explanation:

A graduated cylinder was filled to 30.0 mL with a liquid. An unknown metal cylinder having a mass of 60.27 g was submerged in the in the liquid. The final volume of the liquid level was 45.2 mL.

a. Calculate the density of the unknown metal cylinder.

b. The density of the liquid is 0.899 g/mL. What is the mass of the liquid in the graduated cylinder?

The particle on a ring is a useful model for the motion of electrons around the porphine ring, the conjugated macrocycle that forms the structural basis of the heme group and the chlorophylls. We may treat the group as a circular ring of radius 440 pm, with 22 electrons in the conjugation system moving along the perimeter of the ring. In the ground state of the molecules each state is occupied by two electrons.
A) Calculate the energy and angular momentum of an electron in the highest occupied level.
B) Calculate the frequency of radiation that can induce a transition between the highest occupied and lowest unoccupied levels.

Answers

Answer:

Explanation:

The formula for determining the energy of state [tex]m_l[/tex] can be computed by using the formula:

[tex]Em_i = \dfrac{m_1^2h^2}{2I}[/tex]

Also, the momentum is:

[tex]l_2 = m_i h[/tex]

There are 22 electrons with two electrons in each of the lowest II energy levels so that the highest occupied states are [tex]m_1 = \pm 5[/tex]

The moment of inertia of an electron on a ring of radius 440 ppm is:

[tex]I = mR^2 \\ \\ = 9.109 \times 10^{31} \ kg (440 \times 10^{-12}) ^2 \\ \\ = 1.76 \times 10^{-49} \ kgm^2[/tex]

[tex]E_{\pm 5 } = \dfrac{25h^2}{2I} \\ \\ = \mathbf{7.89 \times 10^{-19} \ J}[/tex]

The angular  momentum is:

[tex]l_2 = \pm 5h \\ \\ = \pm 5 \tiems ( 1.05457 \times 10^{-34} \ Js)[/tex]

[tex]= \mathbf{5.275 \times 10^{-34} \ Js}[/tex]

B) Let's recall that:

The lowest occupied energy level is [tex]m_1 = \pm 6[/tex] which implies that the energy  [tex]E_{\pm 6}= 1.14 \times 10^{-18} \ J[/tex]

Thus;

[tex]\Delta E = E_{\pm 6} - E_{\pm 5} \\ \\ = 1.14 \times 10^{-18 \ J} - 0.79 \times 10^{-18} \ J \\ \\ = 0.35 \times 10^{-18} \ J \\ \\ 0.35 \times 10^{-18} \ J = hv \\ \\ 0.35 \times 10^{-18} \ J = h \dfrac{c}{\lambda}[/tex]

Hence, the radiation which would induce a transition that relates to the wavelength of about 570nm, a wavelength of visible light.

what energy is walking?
A. light energy
B. sound energy
C. Thermal energy
D. Mechanical energy
E. electrical energy

Answers

Answer:

Mechanical

Explanation:


Mechanical Energy - is moving energy. It is the form that we most see around us. All moving objects produce mechanical energy. The movements within machines is also mechanical energy.
Examples: People, a rolling bicycle, moving gears, and running cars.

Suppose you want to make an acetic acid/acetate buffer to a pH of 5.00 using 10.0 mL of 1.00 M acetic acid solution. How many milliliters of 1.00 M sodium acetate solution would you need to add? The pKa for acetate buffer is 4.75.

Answers

Answer:

Explanation:

Molarity of NaOAc needed

Using the Henderson-Hasselbalch Equation calculate base molarity needed given [HOAc] = 1.00M and pKa(NaOAc) = 4.75 and [HOAc] = 1.00m.

pH = pKa + log [NaOAc]/[HOAc]

5.00 = 4.75 + log[NaOAc]/[1.00M]

5.00 - 4.75 = log [NaOAc] - log[1.00M]

log [NaOAc] = 0.25 => [NaOAc] = 10⁰·²⁵ M = 1.78

Given 10ml of HOAc, how much (ml) 1.78M NaOAc to obtain a buffer pH of 5.00.

Determine Volume of Base Needed

(M·V)acid = (M·V)base => V(base) = (M·V)acid / (M)base

Vol (NaOAc) needed = (1.00M)(0.010L)/(1.78M) = 0.0056 liter = 5.6 ml.

Checking Results:

5.00 = 4.75 + log [1.78M]/[1.00M] = 4.75 + 0.25 = 5.00    QED.

The volume of 1.00 M sodium acetate solution needed to prepare an acetic/acetate buffer of pH 5.00 using 10.0 mL of 1.00M acetic acid solution is 17.8 mL.

We can find the volume of the acetate solution with the Henderson-Hasselbalch equation:

[tex]pH = pka + log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]})[/tex]   (1)  

Where:

[CH₃COOH] = 1.00 M                      

[CH₃COONa] =?

pH = 5.00

pKa = 4.75

From equation (1), we have:

[tex] log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]}) = pH - pKa [/tex]

[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{pH - pKa} [/tex]

[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{5.00 - 4.75} = 1.78 [/tex]

Now, the volume of the acetate solution is:

[tex]\frac{n_{CH_{3}COONa}/Vt}{n_{CH_{3}COOH}/Vt} = 1.78[/tex]  

Since the total volume is the same, we have:

[tex]\frac{n_{CH_{3}COONa}}{n_{CH_{3}COOH}} = 1.78[/tex]  

[tex] \frac{[CH_{3}COONa]_{i}*V_{b}}{[CH_{3}COOH]_{i}*Va} = 1.78 [/tex]  

Solving for Vb

[tex] Vb = \frac{1.78*[CH_{3}COOH]_{i}*Va}{[CH_{3}COONa]_{i}} = \frac{1.78*1.00M*10.0mL}{1.00 M} = 17.8 mL [/tex]

Therefore, we need to add 17.8 mL of sodium acetate solution.

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Chemical energy is released when bonds blank in a chemical reaction

Answers

Answer:

form

Explanation:

Convert 5.7 kcal to its value in calories.

Answers

Answer:

5700

Explanation:

what does the word interact

Lift

Fly

Discuss

Work with

Answers

Answer:

The answer would be work with.

Explanation:

Because, if we know what the word interact means then we can look for a word similar to interact. hope this makes sense <3.

1. At an environmental testing lab, a lab technician calculated the known concentration of the calibrating solution three times too high. How will this affect the results of the samples run using this calibration solution

Answers

Answer:

The deviation in the results will be too large when compared with the actual result

Explanation:

The effect this will have on the results of the samples run using this Calibration solution is that the deviation in the results will be too large when compared with the actual result that was supposed to be obtained. and this will also lead to wrong analysis by the technician .

This will cause a result that is very different from the actual result, which will lead to errors in the analysis.

We can arrive at this answer because:

A laboratory test must be done accurately and all calibrations must follow the test protocol.Changing the calibration will cause inaccurate and incorrect results, which differ from the actual result.This will promote an analysis that is unreal, false, and far from true, which will leave the entire test inaccurate.

As we can see from the question above, the lab technician used a much higher calibration than what was recommended in the lab. This will lead to inaccurate and incorrect results.

More information:

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Mario’s teacher asked him to explain the important role of the sun in the water cycle. Which response would be correct?

Answers

it evaporate water and make it go back into the air or sky and start the whole circle all over

Given the reaction
3 H3PO4 + 2 Ba(OH)2 ⇒ BaPO4 + 6 H20
How many grams of precipitate could you make if you reacted 286.0 mL of 3.000 M H3PO4 with 855.0 mL of 1.400 M Ba(OH)2

Answers

Answer:

240.17 g Ba3(PO4)2

Explanation:

1. Determine the limiting reactant.

2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O

moles H3PO4 = M x V = 3 x 0.286 = .858 moles H3PO4

moles Ba(OH)2 = M x V = 1.4 x 0.855 = 1.197 moles Ba(OH)2

ratio Ba(OH)2 : H3PO4 = 1.197: .858 = 1.39: 1

stoichiometric ratio Ba(OH)2 : H3PO4  = 3:2

Ba(OH)2is the limiting reactant

MM Ba3(PO4)2 = 601.92 g/mol

g Ba3(PO4)2 = moles Ba(OH)2 x(1 mol Ba3(PO4)2/3 moles Ba(OH)2) x (MM Ba3(PO4)2/ 1mol Ba3(PO4)2) = 1.197 x 1/3 x 601.92 = 240.17 g Ba3(PO4)2

How many moles are in 2.5L of 1.75 M Na2CO3

Answers

Answer:

4.4 mol.

Explanation:

Hello!

In this case, since the formula for calculating the molarity is:

[tex]M=n/V[/tex]

Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:

[tex]n=V*M[/tex]

Thus, we plug in the given data to obtain:

[tex]n=2.5L*1.75mol/L=4.4mol[/tex]

Best regards!

Answer:

4.4 mol.

Explanation:

Have a great day

Fill in the blanks. 3NH3

Answers

Answer:

3, 9, 3

Explanation:

The coefficient of 3 tells us that there are three molecules (the chemical unit of NH3). Each molecule of ammonia (NH3) is made up of 1 atom of nitrogen bonded to 3 atoms of hydrogen.

Since there are three molecules, we have three times the amount of atoms there are in one molecule.

3 x 1 = 3 nitrogen

3 x 3 = 9 hydrogen

Methods of Heat Transfer
Identify the following examples of heat transfer as conduction, convection, or radiation.
1. Touching a metal spoon that is sitting in a pot of boiling water.
Will mark brainliest

Answers

Answer:

1

Explanation:

touching a metal spoon ....................water.

The smallest arteries in your body are called _____. arterioles capillaries veins bronchioles

Answers

Answer: arterioles

Explanation:

Hydrofluoric acid and Water react to form fluoride anion and hydronium cation, like this HF(aq) + H_2O(l) rightarrow F(aq) + H_3O^+ (aq) At a certain temperature, a chemist finds that a 5.6 L reaction vessel containing an aqueous solution of hydrofluoric acid, water, fluoride anion, and hydronium cation at equilibrium has the following composition: Calculate the value of the equilibrium constant K_C for this reaction. Round your answer to 2 significant digits. K_C =

Answers

Answer:

Kc = 1.09x10⁻⁴

Explanation:

HF = 1.62g

H₂O = 516g

F⁻ = 0.163g

H₃O⁺ = 0.110g

To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:

Kc = [H₃O⁺] [F⁻] / [HF]

Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:

[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M

[F⁻] = 0.163g * (1mol /19.0g) = 0.00858moles / 5.6L = 1.53x10⁻³M

[HF] = 1.62g * (1mol /20g) = 0.081moles / 5.6L = 0.0145M

Kc = [1.03x10⁻³M] [1.53x10⁻³M] / [0.0145M]

Kc = 1.09x10⁻⁴

I guess this is free:)))): ((((

Answers

Answer:

tysm!!!! :D <<<33333

Explanation:

How many molecules are in 450.0 grams of aluminum fluoride(AIF3)?

Answers

Answer:

It would be exactly 5.3586262014272155. But if you were to round it up it would be 5.35.

Here is the answer:)

Which type of rock does Florian predict these pieces will change into when subjected to heat and pressure?

Answers

Answer:

The Florian predict the metamorphic rocks because it changes when subjected to heat and pressure.

Explanation:

i hope this helps

Cell Walls are found in Prokaryotes and Plant cells. True O False​

Answers

Answer:

i think true

Explanation:

lemme know if right if not sorry :))

The answer is true. Cell walls are found in both. :)

If you began a reaction with the following ions in solution, what would be the net ionic equation?
Na+, PO43–, Fe2+, and NO3–

Answers

Answer:

2 PO₄³⁻(aq) + 3 Fe²⁺(aq) ⇒ Fe₃(PO₄)₂

Explanation:

Let's consider the complete ionic equation between the ions present. It includes all the ions and the insoluble compounds (Fe₃(PO₄)₂ is insoluble).

Na⁺(aq) + 2 PO₄³⁻(aq) + 3 Fe²⁺(aq) + NO₃⁻(aq) ⇒ Fe₃(PO₄)₂ + Na⁺(aq) + NO₃⁻(aq)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the insoluble compounds.

2 PO₄³⁻(aq) + 3 Fe²⁺(aq) ⇒ Fe₃(PO₄)₂

Which statement best describes the energy in the food web? A. The amount of energy available at level B depends on the amount of energy available at level C. B. The amount of energy available at level A depends on the energy provided from an abiotic source. C. The amount of energy available at level C is greater that the amount of energy available ate level A. D. The amount of energy available at level B is transferred to level A

Answers

Answer:

The amount of energy available at level A depend on energy provided from an a biotic source

Cool air can hold less water vapor than warm air. Apply this fact to explain why clouds and precipitation form on the windward side of the mountain.​

Answers

The pressure is directly proportional to temperature (when the pressure decrease the temperature decrease too). Because the air parcel expands so the molecules will not interact with each other as much.

The energy of the particles does not change but the fact that the particles are more spaced out means the parcel is cooler.

so now, the warmer a parcel of air the more water vapor it can hold. so, if a parcel of air cools it's ability to hold water vapor drops and if it drops to a low enough point that is when the water vapor will condense and turn back into liquid water. This is how clouds and precipitation form on the the windward side of the mountain.

Clouds and precipitation form on the windward side of the mountain due to change in temperature and pressure.

What is the relation between pressure and temperature?

Temperature of any substance is directly proportional to the pressure of that substance.

If the temperature of the wind increases so that winds get warmer and at the same time pressure of gas also increases, due to which particles will go far from each other. After this warm air rises up and cools down will condenses to form clouds, after this precipitate will falls on the windward side of the mountain.

Hence due to temperature and pressure precipitate will form on the windward side of the mountain.​

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Cu + 2AgNO3 → Cu(NO3)2 + 2Ag

If a 40. g sample of Copper is used with an excess of silver nitrate, calculate the theoretical yield of silver. What is the percent yield of the silver, if 120 g was collected?

Answers

Answer:

[tex]m_{Ag}=135.8gAg[/tex]

[tex]Y=88.4\%[/tex]

Explanation:

Hello there!

In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:

[tex]m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\ m_{Ag}=135.8gAg[/tex]

Next, given the actual yield of 120 g, we compute the percent yield via:

[tex]Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%[/tex]

Regards!

molar mass of Mg(CO3)

Answers

Answer:

[tex]\boxed {\boxed {\sf 84.313 \ g/mol}}[/tex]

Explanation:

The molar mass is the mass per mole of an element or substance. The values for atomic mass on the Periodic Table are used as the molar mass. Look up the molar masses for the elements in the formula.

Mg: 24.305 g/molC: 12.011 g/molO: 15.999 g/mol

Analyze the formula. Magnesium and carbon have no subscript, so there is only one atom of each. Oxygen has a subscript of 3, so there are 3 atoms and the mass has to be multiplied by 3.

MgCO₃= 24.305 + 12.011+ 3(15.999) MgCO₃= 24.305+12.011+47.997=84.313 g/mol

The molar mass of magnesium carbonate is 84.313 grams per mole.

In a single replacement reaction, the chloride ion in NaCl can be replaced
by

a. potassium
b. carbon
c.fluorine
d.neon

Answers

Answer:

c. fluorine

Explanation:

A single replacement reaction is defined as the chemical reaction in which a strong molecule replaces the weak molecule from a compound.

In a single replacement reaction, the chloride ion in NaCl can be replaced     by fluorine and gives Sodium fluoride as fluorine (F) is stronger than chlorine (Cl) and from other given molecules also. So the single replacement reaction between NaCl and F will be:

NaCl + F2 => NaF + Cl2

Hence, the correct answer is "c. fluorine".

Pls someone help rn!! Pls pls

Answers

Answer:

A. Mass = 61kg, weight on moon = 97.8N

Explanation:

To calculate the weight (force) from Mass of a body, the following formula is used:

W = mg

Where;

W = weight (Newtons)

m = mass (kg)

g = acceleration due to gravity (9.8m/s²)

According to this question, a scale shows that I weigh 600N on Earth, the mass on Earth can be calculated thus:

Using W = mg

m = W/g

m = 600/9.8

m = 61.2

m = 61kg

However, this mass on Earth will weigh differently on the Moon because gravity in the moon is 1.6 N/kg. The weight of the 61kg on the Moon is:

W(moon) = mass × gravity

W = 61 × 1.6

W = 97.6 N

Therefore, Mass = 61kg, weight on moon = 97.8N

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