Reduce to the lowest terms by canceling -14/9 times -3/7
Answer:
2/3
Explanation:
Given the below;
[tex]\frac{-14}{9}\times\frac{(-3)}{7}[/tex]We can see from the above that 9 is divisible by 3 and that 14 is divisible by 7, let's go ahead and reduce to the lowest term as shown below;
[tex]\frac{-14}{9}\times\frac{(-3)}{7}=\frac{-2}{3}\times\frac{(-1)}{1}=\frac{2}{3}[/tex]A physics student want to calculate her final grade. The grade distribution is tests = 30%, quizzes = 15%, homework=10%, labs=25%, and the final exam= 20%. Calculate her final grade if she got the following averages for each category: Tests=80%; Quizzes=70%; Homework=80%; Labs=90%; Final exam=90%.
Given:
The grade distribution is tests = 30%, quizzes = 15%, homework=10%, labs=25%, and the final exam= 20%.
Averages for each category: Tests=80%; Quizzes=70%; Homework=80%; Labs=90%; Final exam=90%.
Required:
We need to find the final grade.
Explanation:
Let the total mark for each is 100,
The mark for the test is 80.
We need to find 30% of 80.
[tex]grade\text{ for test =}\frac{30}{100}\times80=24[/tex]The mark for the quizzes is 70.
We need to find 15% of 70.
[tex]grade\text{ for quizzes =}\frac{15}{100}\times70=10.5[/tex]The mark for the homework is 80.
We need to find 10% of 80.
[tex]grade\text{ for homework =}\frac{10}{100}\times80=8[/tex]The mark for the labs is 90.
We need to find 25% of 90.
[tex]grade\text{ for labs =}\frac{25}{100}\times90=22.5[/tex]The mark for the final exam is 90.
We need to find 20% of 90.
[tex]grade\text{ for final exam=}\frac{20}{100}\times90=18[/tex]Add grade values for all the categories.
[tex]Final\text{ grade =24+10.5+8+22.5+18}[/tex]The final grade was 83 out of 100.
Divide 83 by 10.
The final grade is 8.3 out of 10.
Final answer:
[tex]Final\text{ grade =83 out of 100}[/tex][tex]Final\text{ grade =8.3 out of 10}[/tex]The waiter places a bowl of soup in front of Lacy. In a counterclockwise direction, she passes the soup 90°. The person receiving the soup passes it 30°. After the two passes, the soup is in front of which person ?○ Haifa○darcy○garret○igor
Notice that we have 12 people evenly distributed in a round table (360°).
This way, each person would be
[tex]\frac{360}{12}=30[/tex]30° from each other.
After the two passes, the soup would have moved 120°, meaning that
[tex]\frac{120}{30}=4[/tex]It would have moved 4 places.
Now, the person sitting 4 places away from Lacy, if the soup is passed counterclockwise, is Haifa
Therefore, the soup would be in front of Haifa.
Find the value of b.a=5 and c = 10A.9.5B.10C.9D.8.7Please can you explain.
1) Assuming this is a right triangle, we can find the missing leg by making use of the Pythagorean Theorem.
2) Thus, we can write out this:
[tex]\begin{gathered} c^2=a^2+b^2 \\ \\ (10)^2=5^2+b^2 \\ \\ 100=25+b^2 \\ \\ b^2=100-25 \\ \\ b=\sqrt{75} \\ \\ b\approx8.7 \end{gathered}[/tex]Note that the hypotenuse (the largest side) is always on the left side. And that this is an approximation rounded off to the nearest tenth.
3) Thus, the answer is:
[tex]D.\:8.7[/tex]The dash in-front of the whole number is a negative sign, Just a little heads up :)
Okay, here we have this:
We need to solve the following expression:
[tex]\begin{gathered} -5\cdot2\text{ }\frac{1}{4} \\ =-5\cdot\frac{8+1}{4} \\ =-5\cdot\frac{9}{4} \\ =-\frac{45}{4} \\ =-11.25 \end{gathered}[/tex]Finally we obtain that the result is -11.25.
On your fifteenth birthday you discover you have a rich aunt sally aunt sally is a very generous women and wants to provide for your future she has decided that she will initially give you $1 then $2 the next year and so on doubling the amount each year until your 30. Use a chart to keep track how much money she will give you each year for the first 5 years.
Let's fill a table with the first two years, we already know those
So, we need to complete the chart for years 3,4, and 5. We know that in year 3, will receive double the money than we get in year 2, this is 2*$2=$4. Now we write that result on our table.
In year 4 we'll get double the money than in year 3, this is 2*$4=$8
Similarly, in year 5 we get double the money than what we got in year 4: 2*$8=$16
And we have filled in the table!
Now, a bonus, the pattern here seems to be an equation, notice this:
year 1 -> $1 = $2^0
year 2 ->$2 = $2^1
year 3 -> $4 = $2^2
year 4 -> $8 = $2^3
year 5 -> $16 = $2^4
This means that the amount of money we'll receive each year is given by
[tex]2^{t-1}[/tex]Where t is the year! (year 1, year 2, etc)
Which expression would be easier to simplify if you used the associative property to change the grouping? OA. 6+ 1; +3) OB. I(-0.2) +(-0.6)] +1.7 O c.(2+)+-) O D. (60+ 40) +-27)
A.
[tex]6+\lbrack\frac{4}{9}+(-\frac{2}{9})\rbrack[/tex]Since both fractions have the same numerator, you can factorize 1/9 aout of the parentheses, because:
[tex]\begin{gathered} \frac{1}{9}\cdot4=\frac{4}{9} \\ \text{and} \\ \frac{1}{9}\cdot2=\frac{2}{9} \end{gathered}[/tex]Then you can simplify the expression as:
[tex]6+\frac{1}{9}\lbrack4+(-2)\rbrack=6+\frac{1}{9}\lbrack4-2\rbrack[/tex]Suppose that an item regularly costs $100.00 and is discounted 24%. If it is then marked up 24%, is the resulting price $100.00? If not, what is it?
Given the cost of item =$ 100
If it is discounted 24%
So, the discount will be = 24% of 100 = 0.24 x 100 = $24
The cost after discount = 100 - 24 = $76
If it is marked up 24%
so, the rise will be = 24% of 76 = 0.24 x 76 = $18.24
The cost after marked up = 76 + 18.24 = $94.24
So, the answer is : No, and the cost will be = $94.24
Solve x2 + 12x + 25Hias17 by completing the square. Select all the possible solutions.-6 + 70-6 + 2.7–6 – 276-606-270-6-77
we are given the following expression:
[tex]x^2+12x+25=17[/tex]First, we will subtract 17 to both sides:
[tex]\begin{gathered} x^2+12x+25-17=17-17 \\ x^2+12x+8=0 \end{gathered}[/tex]We get an expression of the form:
[tex]ax^2+bx+c=0[/tex]To complete the square we will add and subtract the following term:
[tex]\frac{b^2}{4a}[/tex]Replacing the values:
[tex]\frac{12^2}{4(1)}=36[/tex]Therefore, we will add and subtract 36:
[tex]x^2+12x+36-36+8=0[/tex]Now we associate the first three terms:
[tex](x^2+12x+36)-36+8=0[/tex]Now we factor in the associated terms:
[tex](x+6)^2-36+8=0[/tex]Solving the operations:
[tex](x+6)^2-28=0[/tex]Now we solve for "x", first by adding 28 to both sides:
[tex](x+6)^2=28[/tex]Now we take square root to both sides:
[tex](x+6)=\sqrt[]{28}[/tex]Now we subtract 6 to both sides:
[tex]x=-6\pm\sqrt[]{28}[/tex]Now we factor 28 as 7*4:
[tex]undefined[/tex]graph the line that passes through the given point and has the given slope m(1,7); m=-5/2
Given that the line passes through the points;
[tex](1,7)[/tex]And slope;
[tex]m=-\frac{5}{2}[/tex]Holli works for the ymca and is making snack packs for the kids and afterschool program.If she has 76 cheese cracker snacks and 80 juice boxes, what is the greatest number of snack packs that she can make?How many juice boxes will go into each snack pack?
Assuming that each snack pack has 1 juice box and 1 cheese cracker snack, then Holli can make as much as the lowest quantity of juice boxes or cheese cracker snacks.
Let the triangles represent cheese cracker snacks and squares represent juice boxes:
The smallest pack possible includes one cheese cracker snack and one juice box:
The red ovals represent snack packs. Since there are not enough cheese cracker packs to make 77 snack packs, the maximum amount of packs that can be made is 76.
From the drawing, we can see that each snack pack will have one juice box.
When multiplying and/or dividing fractions, answer if each of the statements below are TRUE or FALSE.1: The denominators MUST be the same.2: You must convert mixed numbers into improper fractions before multiplying or dividing.3: You can keep mixed numbers when performing multiplication or division.4: Numerators must be multiplied by numerators and denominators must be multiplied by denominators.
EXPLANATION:
When multiplying and/or dividing fractions, answer if each of the statements below are TRUE or FALSE.
1.The denominators MUST be the same. (FALSE);They can have different denominators for both multiplying and dividing fractions.
2.You must convert mixed numbers into improper fractions before multiplying or dividing.(TRUE) ; This procedure is important so that the operation between fractions is as easy and correct.
3.You can keep mixed numbers when performing multiplication or division.
(FALSE) ; These mixed fractions must be converted to improper fractions to later do the correct multiplication or division.
4.Numerators must be multiplied by numerators and denominators must be multiplied by denominators.(FALSE); The numerator of the first fraction must be multiplied in a cross by the denominator of the second fraction; the denominators are multiplied by each other.
I need help with this please thank you number 14
Answer:
The question is given below as
Concept:
The question will be solved using the linear pair theorem below
The Linear Pair Theorem states that two angles that form a linear pair are supplementary; that is, their measures add up to 180 degrees.
By applying the principle, we will have that
[tex]\begin{gathered} \angle x+88^0=180^0 \\ collect\text{ similar terms,} \\ subtract\text{ 88 from both sides} \\ \operatorname{\angle}x+88^0-88^0=180^0-88^0 \\ \angle x=92^0 \end{gathered}[/tex]Hence,
The value of x= 92°
Step 2:
By applying the linear pair theorem, we will also have that
[tex]\begin{gathered} \angle z+88^0=180^0 \\ collect\text{ similar terms, } \\ subtract\text{ 88 from both sides} \\ \operatorname{\angle}z+88^0-88=180^0-88 \\ \angle z=92^0 \end{gathered}[/tex]Hence,
The value of z= 92°
Step 3:
By applying the linear pair theorem also, we will have that
[tex]\begin{gathered} \angle x+\angle y=180^0 \\ 92^0+\angle y=180^0 \\ collect\text{ similar terms,} \\ substract\text{ 92 from both sides} \\ 92^0-92^0+\operatorname{\angle}y=180^0-92^0 \\ \angle y=88^0 \end{gathered}[/tex]Hence,
The value of y= 88°
using the digits -9 to 9, without repeating any numbers, place a number in each box to create a system of equations that has a solution in quadrant 2. Tip: in quadrant 2, the x - coordinate is negative and the y-coordinate is positive.
Okay, here we have this:
Considering the provided information and options, we are going to find the requested numbers, so we obtain the following:
So first we will choose two values for x and y that meet the given tip: in quadrant 2, the x - coordinate is negative and the y-coordinate is positive.
For our case we will take x=-1 and y=1, then we can write the following two equations:
1x+3y=2 -> 1(-1)+3(1)=2 -> -1+3=2 -> 2=2
y=7x+8 -> 1=7(-1)+8 -> 1=-7+8 -> 1=1
3. The angle of depression of an aeroplane measured from a control tower, PQ, of height 88.9 m is 48°. When the plane moves along the runway from point Ato point Band stops, the angle of depression becomes 25.2°. The distance from point P to point Ais given as 119.6 m. Complete the diagram below to represent this informatior Р brid (ii) Leaving your answers correct to ONE decimal place calculate (a) Durmine the distance from the control tower to point A. (2) (b) Calculate the distance moved by the plane from its initial position.
The Solution:
Part (a)
Representing the problem fully in a diagram, we have:
Part (b)
We are required to find the length of QA= x.
We shall use Trigonometrical Ratio as below:
[tex]\begin{gathered} tan48^o=\frac{opposite}{adjacent}=\frac{88.9}{x} \\ \\ tan48=\frac{88.9}{x} \end{gathered}[/tex]Making x the subject of the formula, we get
[tex]x=\frac{88.9}{tan48}=80.0459\approx80.0m[/tex]Thus, the distance from the control tower to point A is 80.0 meters.
Part (c)
We are required to find the length of AB= y.
Considering triangle PQB, we have:
[tex]\begin{gathered} tan25.2=\frac{88.9}{x+y}=\frac{88.9}{80+y} \\ \\ 0.47056=\frac{88.9}{80+y} \end{gathered}[/tex]Solving for y, we get
[tex]\begin{gathered} 80+y=\frac{88.9}{0.47056} \\ \\ y=188.922-80 \\ y=108.922\approx108.9m \end{gathered}[/tex]Thus, the distance moved by the plane from its initial position is 108.9 meters.
using the change-of-base formula, which of the following is equivalent to the logarithmic expression below? log6 21
Given:
Log6 21.
We are asked to use change of base formula to determine form the options which is equivalent.
let's apply the base change formula:
For C:
Log10 10
Log10 21
Log10 10
Log10 6
Apply power law of logarithm to simplify the expression:
1
LOg10 21
1
Log10 6
ivide fraction by multiplying its reciprocal:
1 x Log10 6
Log10 21
Write as a single fraction:
Log10 6
Log10 21
Apply the base chande formula: log21 6
Check its equivalency: False.
Option A is False
Find the slope of the line that passes through (4, 3) and (9, 10). Simplify your answer and write it as a proper fraction, improper fraction
Answer:
Slope = 7/5
Explanation:
The slope of a line that passes through the points (x1, y1) and (x2, y2) can be calculated as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]So, replacing (x1, y1) by (4, 3) and (x2, y2) by (9, 10), we get that the slope of the line is equal to:
[tex]m=\frac{10-3}{9-4}=\frac{7}{5}[/tex]Therefore, the slope is equal to 7/5
Amber has a job babysitting. She makes 7.50 per hour. What is the constant rate of change?
Remember that the constant rate of change refers to the change between the variable.
In this case, the constant rate of change is $7.50 per hour, in other words, it's 7.50. As an equation would be
[tex]y=\frac{15}{2}x[/tex]3(y-5) = 15
Solve the following.
Answer:
y= 10
Step-by-step explanation:
look at picture for explanation
Solve this system of equations by graphing. First graph the equations, and then type the solution.x+3y=6y=1/2x+7
Given the system of equations;
[tex]\begin{gathered} x+3y=6---(1) \\ y=\frac{1}{2}x+7---(2) \end{gathered}[/tex]We shall first of all re-arrange the equations in the slope-intercept form;
[tex]y=mx+b[/tex]Note that the second one has already been expressed in the slope-intercept form. For the first one we would now have;
[tex]\begin{gathered} x+3y=6 \\ 3y=-x+6 \\ \text{Divide both sides by 3;} \\ \frac{3y}{3}=-\frac{x}{3}+\frac{6}{3} \\ y=-\frac{1}{3}x+2 \end{gathered}[/tex]To plot this equations on a graph we take two extreme points. We can do this by finding the value of y when x = 0, and y when x = 0.
For the first equation, we would have;
[tex]\begin{gathered} y=-\frac{1}{3}x+2 \\ \text{When x}=0 \\ y=-\frac{1}{3}(0)+2 \\ y=0+2 \\ y=2 \\ \text{That means we have the point }(0,2) \\ \text{Also, when y}=0 \\ 0=-\frac{1}{3}x+2 \\ \frac{1}{3}x=2 \\ \text{Cross multiply this and you'll have;} \\ x=2\times3 \\ x=6 \\ We\text{ now have our second point, }(6,0) \end{gathered}[/tex]Hence, for the first equation we have the two points;
[tex]\begin{gathered} A(0,2) \\ B(6,0) \end{gathered}[/tex]For the second equation;
[tex]\begin{gathered} y=\frac{1}{2}x+7 \\ \text{When x}=0 \\ y=\frac{1}{2}(0)+7 \\ y=0+7 \\ y=7 \\ \text{This means we have the point }(0,7) \\ \text{Also, when y}=0 \\ 0=\frac{1}{2}x+7 \\ -\frac{1}{2}x=7 \\ \text{Cross multiply and you'll have;} \\ x=7\times(-2) \\ x=-14 \\ \text{That means we now have the second point which is }(-14,0) \end{gathered}[/tex]For the second equation we now have the points;
[tex]\begin{gathered} A(0,7) \\ B(-14,0) \end{gathered}[/tex]We can now input both sets of coordinates and our graph would come out as shown below.
The point of intersection as we can see is at where x = -6 and y = 4. Therefore;
ANSWER:
The solution to the system of equations as shown on the graph is;
[tex](-6,4)[/tex]Use a calculator and inverse functions to find the radian measures of a given angle around your answer to the nearest hundredth.angles whose sign is -0.26
Answer
Option C is correct.
x = -0.26 + 2pn
OR
x = -2.88 + 2pn
Explanation
Using the calculator and inverse functions
Let the unknown angle be x
Sin x = -0.26
x = Sin⁻¹ (-0.26)
x = -0.26 or -2.88 (From the calculator)
In order to generalize it, we add 2pi to both of them.
x = -0.26 + 2pn
OR
x = -2.88 + 2pn
Hope this Helps!!!
What happens to the graph when you change the value of a?
we have that
the value of a represent a vertical dilation
so
We stretch the graph in the vertical direction by a scale factor of
If the value of a> 1
then
we have stretching of the graph
If the value of 0 < a < 1
then
we have a compress of the graph
I need help with question 3, the model is above it.
we have Pattern A
0,4,8,12,
In this problem we have an arithmetic sequence
the common factor d=4
therefore
in step 4
there are 12+4=16 dots
answer is 16 dotsDetermine whether each parabola has a horizontal directrix or vertical directrix 1. (y-3)²= 1/8 (x+1) horizontal or vertical directrix2. (x-2)²=6(y-3) horizontal or vertical directrix 3. (y+4)²=-12(x+2)horizontal or vertical directrix4. (x+3)²= -8(y+2) horizontal or vertical directrix
Answer
1) Horizontal directrix.
2) Vertical directix.
3) Horizontal directix.
4) Vertical directrix.
Explanation
A parabola with a vertical axis will have a horizontal directrix.
A parabola with a horizontal axis will have a vertical directrix.
A parabola with a vertical axis will have a standard equation of the parabola as
(x - h)² = 4p (y - k),
where p ≠ 0.
The vertex of this parabola is at (h, k). The focus is at (h, k + p).
The directrix is the line y = k - p and it is a vertical directrix.
A parabola with a horizontal axis will have a standard equation of the parabola as
(y - k)² = 4p (x - h),
where p ≠ 0.
The vertex of this parabola is at (h, k). The focus is at (h + p, k).
The directrix is the line x = h - p and it is a horizontal directrix.
So, for this questions,
1.) (y - 3)² = 1/8 (x + 1)
This is of the form (y - k)² = 4p (x - h), so, we can easily see that this parabola has a horizontal directrix.
2.) (x - 2)²= 6 (y - 3)
This is of the form (x - h)² = 4p (y - k), so, we can easily see that this parabola has a vertical directrix.
3.) (y + 4)² = -12 (x + 2)
This is of the form (y - k)² = 4p (x - h), so, we can easily see that this parabola has a horizontal directrix.
4.) (x+3)²= -8(y+2)
This is of the form (x - h)² = 4p (y - k), so, we can easily see that this parabola has a vertical directrix.
Hope this Helps!!!
The ratio of the sides of two smaller polygons is 4:5. Find the ratio of the areas.
Given that the ratio of the sides of two smaller polygons is 4:5
To Determine: The ratio of the areas
Solution:
Note that if the ratio of the sides of two similar shapes is a : b, then the ratio of their areas would be a² : b²
It was given in the question that the ratio of the sides of two smaller polygons is 4:5. Then, their areas would be
[tex]\begin{gathered} 4^2\colon5^2 \\ =16\colon25 \end{gathered}[/tex]Hence, the ratio of the areas is 16 : 25
what is the probability of a student owning a car that is not blue or green round to two decimal places
0.83
Explanation
The probability of an event is the number of favorable outcomes divided by the total number of outcomes possible
[tex]P=\frac{favorable\text{ ourcomes}}{\text{total possible outcomes}}[/tex]Step |
Let
[tex]\begin{gathered} \text{favorable outcomes=car that is not blue or gre}en,\text{ so} \\ \text{favorable outcomes=}red\text{ cars+yellow cars+white cars+other} \\ \text{favorable outcomes=}40+29+26+14 \\ \text{favorable outcomes=}109 \end{gathered}[/tex]now, the total outcomes is the total of cars
[tex]\text{total outcomes=40+13+29+26+10+14=132}[/tex]Finally, replace in the equation
[tex]\begin{gathered} P=\frac{favorable\text{ ourcomes}}{\text{total possible outcomes}} \\ p=\frac{109}{132} \\ P=0.83 \end{gathered}[/tex]so, the answer is 0.83
I hope this helps you
Point L is on line segment KM. Given LM = 5 and KL = 12, determine the length KM.
ANSWER
KM = 17
EXPLANATION
We have that point L is on the line segment KM.
Let us draw a diagram to represent it:
From the diagram, we see that the length of KM is the sum of the lengths of KL and LM.
This means that:
KM = KL + LM
KM = 12 + 5
KM = 17
That is the value of the length of KM.
What is 3[cos(60)+isin60]*1/2[cos(15)+isin(15)]
1) Let's simplify this expression considering the trigonometric ratios and the complex numbers as well.
[tex]\begin{gathered} 3\left[\cos \left(60^{\circ \:}\right)+i\sin \left(60^{\circ \:}\right)\right]\frac{1}{2}\left[\cos \left(15^{\circ \:}\right)+i\sin \left(15^{\circ \:}\right)\right] \\ Convert\:to\:radians: \\ 3\left[\cos \left(\frac{\pi }{3}\right)+i\sin \left(\frac{\pi }{3}\right)\right]\frac{1}{2}\left[\cos \left(\frac{\pi }{12}\right)+i\sin \left(\frac{\pi }{12}\right)\right] \\ \quad \cos \left(x\right)+i\sin \left(x\right)=e^{ix} \\ 3\times\frac{1}{2}\lbrack\left[e^{i\frac{\pi}{3}}\right]\left[e^{i\frac{\pi}{12}}\right] \\ \frac{3\left(-1\right)^{\frac{5}{12}}}{2} \\ \end{gathered}[/tex]We have transitioned that to work with radians for convenience and used one identity. Note that we could have written our final answer in a radical form.
identify the terms, like terms, coefficients and constants 2c - 2b + c + 3 + b - 4
1) In this expression, we have
1.1 ) Terms: We have 6 terms in total.
2c -2b +c +3 + b -4 Combining like terms we can rewrite them as
c -b -1
1.2) Like terms are the ones that share the same variable
2c, c
-2b, b
1.3) Coefficients the numbers that multiply the variables
2c - 2b + c + 3 + b - 4
So we have:
2, -2, 1
1.4) The constants. Simply put in this case, the numbers that do not vary
-4 and 3
Simplify the inequality. Graph it, write it in interval notation, and then inequality notation. Write your answer in interval notation.3x+2<−4 or 3x+3>27Clear All Draw: Line segments interval inequality
given the inequality
[tex]3x+2<−4\text{ }or\text{ }3x+3>27[/tex]then
[tex]3x<−4-2\text{ }or\text{ }3x>27-3[/tex][tex]3x<−6\text{ }or\text{ }3x>24[/tex][tex]x<−2\text{ }or\text{ }x>8[/tex]Graph:
notice the empty circle because the ineqaulity does not have equal symbol
interval:
[tex]\left(-\infty \:,\:-2\right)\cup \left(8,\:\infty \:\right)[/tex]inequality:
[tex]x<-2\text{ }or\text{ }x>8[/tex]