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In a vacuum x-rays and microwaves have the same velocity but different wavelengths.
Correct option: D. the same
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What constant torque is required to bring it up to an angular speed of 400 rev/min in 8. 00 s , starting from rest?.
Answers
The required Torque would be 13.0895 Nm.
The force that can cause an object to rotate around an axis is measured in torque.
Similar to how force accelerates an object in linear kinematics, torque accelerates an object in an angular direction.
In rotational kinematics, torque takes the place of force in linear kinematics. There is a direct equivalent to Newton’s 2ⁿᵈ law of motion (F=maF=maF, equals, m, a),
[tex]\tau = I \alphaτ=Iαtau[/tex]= αI
Given,
Time (t) =8.00 sec
Ang Velocity (W) = 400 rev/min
Moment of Inertia (I) = 2.50 kg m²
As we know,
W=Wo+αt T
= αI
400 rev/min to rad/sec-
400 × 2π/60sec = 41.8876 rad/sec
41.8876 rad/sec = 0 + α(8 sec) α = 5.2358 rad/sec²
Torque, T=αI.
T=(5.2358)(2.50)
T=13.0895 Nm
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Question 9 of 10: you purchased $100 each of three different stocks in january. stock a increased 30% in value. stock b increased 15% in value. stock c lost 20% of its original value. what was the overall net percentage of gain in the three stocks? (round to the nearest percent.)
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The overall net percentage of gain in the three stocks purchased each with $ 100 in which stock a increased 30% in value. stock b increased 15% in value. stock c lost 20% of its original value is 8.3 %
Value of Stock a = 100 + 30%
Value of Stock a = $ 130
Value of stock b = 100 + 15%
Value of stock b = $ 115
Value of stock c = 100 - 20%
Value of stock c = $ 80
Net percentage gain = ( Net profit / Total investment - 1 ) * 100
Net profit = 130 + 115 + 80
Net profit = $ 325
Total investment = 100 + 100 + 100
Total investment = $ 300
Net percentage gain = ( 325 / 300 - 1 ) * 100
Net percentage gain = ( 0.083 ) * 100
Net percentage gain = 8.3 %
Therefore, the the overall net percentage of gain in the three stocks is 8.3 %
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when the meteorite is halfway to the surface, however, the rope breaks. what is the acceleration of the meteorite as it sinks back to the bottom of the pool?
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The acceleration of the meteorite as it sinks back to the bottom of the pool is 8.46 m/s2
sinc we are given the Weight of the meteorite iron which is 1000 N, the Density of meteorite iron which is 7300 kg/m³, the density of water which is 1000 kg/m3, and the Maximum force of 450 N.Since the mass of the meteorite iron, m = W / g =1000/ 9.80 =102.04 kg, and the volume of the meteorite iron, V = 102.04/7300 =1.40×10⁻² m³ .Since The minimum force, the curator has to apply to lift the meteorite from the bottom of the water is the apparent weight of the meteorite in the water. so the minimum force will be :
Fmin=W−Fb =W−Vρ₂g = 1000−1.40×10⁻²×1000×9.8 = 862.8 N
Now since lifting the rope of the crane breaks and the meteorite sinks back into the pool. In such a case, the net downward force acting on the meteorite is the apparent weight of the meteorite. So the acceleration of the meteorite is :
a= W /m = 862.8 N/ 102.04 kg= 8.46 ms⁻²
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The curator of a science museum is transporting a chunk of meteorite iron (i.e., a piece of iron that fell from the sky) from one part of the museum to another. Since the chunk of iron weighs 1000 N and is too big for her to lift by herself, she is using a hand cart. While passing through the marine mammal section of the museum, she accidentally hits a bump, and the meteorite tips off the hand truck and into the dolphin pool. Fortunately, the iron didn't hit the dolphin, but it quickly sinks to the bottom. Unfortunately, the meteorite has many sharp edges and she is worried the dolphins, curious creatures that they are, will come to inspect it and be cut when they rub against it. She wants to get it up out of the pool as quickly as possible. Fortunately, the meteorite has lots of holes in it and there are ropes with hooks on one end lying around. If she could get a hook into one of the holes, she might be able to pull it up to the top. Unfortunately, she remembers that the meteorite is too heavy for her to lift. When the meteorite is halfway to the surface, however, the rope breaks. What is the acceleration of the meteorite as it sinks back to the bottom of the pool?
12Question 17 (1 point)It's been said that "Dilution is the solution to pollution." Which of the following is anexample of this saying?✓15Gasoline leaks into a sewage system and is filtered out at the sewage treatmentplant.A doctor's office throws all their trash into the Atlantic Ocean. Waves andcurrents wash it all ashore.18An camper washes her dishes then dumps the water into a large river.Mercury is absorbed into fish and humans eat the fish.1
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detectableThe solution to pollution is not dilution. That is, due to the low levels
of contaminants in the effluent and the high volume cmd rate of flow in the St.
Clair River, most substances would be dispersed to the point of undetectability
within ten metres or so, If the contaminants were still decte after ten
kilometres. for example, that would be considered using dilution as a solution.
Since ICI trecrts the waste water before it is released. and with the mixhg zones
ço small, Lusby is confident thd the discharge is hdess because the
concentration is extremely low
The average kinetic energy
of the particles in matter?
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The average kinetic energy of the substance's particles is its temperature.
What is average kinetic energy?The average kinetic energy of a substance's particles is inversely correlated with that substance's temperature, according to the kinetic-molecular hypothesis.
When a substance is heated, some of the energy received is retained by the particles, while other energy quickens the motion of the particles. The material's temperature increases as a result of this.
The average kinetic energy of a substance's particles is directly proportional to the substance's temperature. These particles must move more quickly as the temperature rises because their mass is constant.
Lowering the system's temperature causes a decrease in a particle's kinetic energy.
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What is the si unit of mass and length
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Answer:
Mass: Kg (kilogram)
Length: M (meter)
In order to have kinetic energy an object must be
1.moving
2. At rest
3.rigid
4.elevated
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Which of the following objects has gravitational energy? CHOOSE TWO ANSWERS
a book on the edge of a table
a ball sitting on the floor
a falling skydiver
a car driving on a road
Answers
A baseball player throws a ball horizontally off a cliff that is 19.8 m tall. The ball lands 29.3 m away from the base of the cliff. What is the horizontal velocity of the ball?
Answers
Answer:
v = 58.893 m/s
Explanation:
I assume we are assuming -10 for gravity
Vertically:
Thrown vertically so initial vertical velocity is 0
Δy = vi*t + 0.5*a*t^2
-19.8 = 0*t + 0.5*-9.8*t^2
t^2 = 4.0408
t = 2.01s
Horizontally:
v = d*t
v = 29.3m * 2.01s
v = 58.893 m/s
A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is travelling Enter a number m/s
Answers
Answer: Velocity = v = 35 m/s
Explanation:
Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.
Mathematically,
v = 35 m/s
the beam is balanced use the principle of moments to calculate the weight, W, of the monkey in newtons.
the objects weight on the left is 350N and the distance from the pivot is 20m. the second object on the right weight is x and distance from the pivot is 1.5m
Answers
Answer:
below
Explanation:
350 * 20 has to equal x * 1.5
350 * 20 = 1.5 x
x = 4666.7 N
The half-life of iodine-131 is 8.07 days. If 0.25 g are left after 40.35 days, how many gramswere in the original sample?
Answers
Given data
*The half-life of iodine-131 is t = 8.07 days
*The amount of quantity left is N = 0.25 g
*The number of days is T = 40.35 days
The expression for the radioactivity decay is given as
[tex]N=N_0(\frac{1}{2})^{\frac{T}{t}}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} \text{0}.25=N_0(\frac{1}{2})^{\frac{40.35}{8.07}} \\ N_0=8\text{ g} \end{gathered}[/tex]Answer:
See below
Explanation:
40.35 days / (8.07 day per half life) = 5 half lives
.25 = x ( 1/2)^5
.25 / ( 1/2)^5 = x = 8 gm originally
Mix a liter of 20°C water with 2 liters of 30°C water and you’ll have 3 liters of water at?
Answers
We can solve this question by using the principle of calorimetry.
The density of water is 1000 kg/m^3
According to the principle of calorimetry,
Heat lost by hot body = Heat gained by the cold body.
This principle is based on conservation of energy.
Let assume that the final temperature is t(f).
So,
[tex]\begin{gathered} Q=mc\Delta t \\ Where,\text{ } \\ Q=Heat \\ m=mass \\ c=Specific\text{ }heat\text{ }capacity \\ \Delta t=Change\text{ }in\text{ }temperature \end{gathered}[/tex]For two liter of water the final temperature is t(f) and initial temperature is 30°celcius,
So here the water will lose heat because it is at higher temperature,
[tex]\begin{gathered} Heat\text{ loose by the water is,} \\ Q=mc\Delta t=1000\times2\times c\times[t(f)-30] \end{gathered}[/tex]And for 1 liter of water the gain in heat is,
[tex]Q=mc\Delta t=1000\times1\times c\times[t(f)-20][/tex]Now,
[tex]\begin{gathered} Q\text{ }lose=Q\text{ }gain \\ -1000\times2\times c\times[t(f)-30]=1000\times1\times c\times[t(f)-20] \\ -2\times[t(f)-30]=[t(f)-20] \\ -2t(f)+60=t(f)-20 \\ -3t(f)=-20-60 \\ t(f)=\frac{80}{3}=26.667\mathring{\text{ }}celcius \end{gathered}[/tex]So the final temperature of the 3 liter water = 26.667 degree cus.
what would happen to the distances between bright spots (intensity maxima) on the screen if the spacing between the slits is doubled? group of answer choices
Answers
If the spacing between the slits is doubled, then the distances between bright spots (intensity maxima) on the screen will become half
From the young double slit experiment, we come up with a formula which is : β = λD/d, where β is the fringe width, λ is the wavelength of the light rays, D is the distance between the screen and the source of the rays, and the d is the distance between the two slits. here the distance between the two bright spots is also called the bandwidth. If d is doubled then the value of β will be halved.
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If you start with 500g of water in your pot, and after it boils away, the steam takes up 2 m3 of space, what is the density of the steam in g/m3?
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The density of the steam is 250g/m³.
What is the procedure for determining density?d = M/V
Density is defined as d = m/v, where m stands for mass, and for volume. The unit of density that is most frequently used is grams per cubic centimeter. For instance, the density of Earth is 5.51 grams per cubic centimeter, while the density of water is 1 gram per cubic centimeter.
A material's density is determined by how much space a given amount of the substance occupies relative to its mass (volume). A substance's density is based on the mass, size, and arrangement of its atoms. Density (D) is defined as the substance's mass divided by its volume.
Given,
mass = 500g
volume = 2m³
density = 500/2
density = 250g/m³.
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At what decibel Level two sounds starts to becomeHarmful to the ears and the hearing?
Answers
Sound intensity more than 70 dB (noise) for a long period of time may start to damage your hearing.
A loud noise with sound intensity more than 120 dB can cause immediate harm to your ears.
A horizontal pipe of diameter D = 3.0 cm passes through a reservoir dam at depth d = 5.0 m. A plug secures the pipe opening. The water density is p = 1.0 x103 kg/m3. (a) Find the magnitude of the frictional force between the plug and pipe wall. (b) If the plug is removed, what water volume exits the pipe in 1.0 minute? Ignore water viscosity. (c) If the pipe is h = 10.0 m above the ground, how far will the water travel horizontally from the pipe exit when hitting the ground? Ignore air friction.
Answers
Given data
*The given horizontal piper of diameter is D = 3.0 cm = 0.03 m
*The given depth is d = 5.0 m
*The given water desnsity is
[tex]p=1.0\times10^3kg/m^3[/tex](a)
The magnitude of the frictional force between the plug and pipe wall is given as
[tex]\begin{gathered} F=\text{pgd}\times A \\ =\text{pgd}\times\pi r^2 \end{gathered}[/tex]*Here r = d/2 is the radius
Substitute the values in the above expression as
[tex]\begin{gathered} F=(1.0\times10^3)(9.8)(5.0)\times3.14\times(\frac{0.03}{2})^2 \\ =34.61\text{ N} \end{gathered}[/tex](b)
The volume flow rate is calculated as
[tex]\begin{gathered} V=Av \\ =\pi r^2\sqrt[]{2gd} \\ =3.14\times(\frac{0.03}{2})^2\times\sqrt[]{2\times9.8\times5.0} \\ =6.99\times10^{-3} \end{gathered}[/tex]The total volume is calculated as
[tex]\begin{gathered} V_{T_{}}=V\times t \\ =6.99\times10^{-3}\times1.0\times60 \\ =0.4194m^3 \end{gathered}[/tex]I need help with this question someone
Answers
The properties of group 18 elements, also referred to as noble gases or group 8 elements.
Eight valence electrons make them up.
They have enough electrons in their octet, therefore they don't need any more (stable).
are steady
Noble gases are those that are not reactive.
Why do elements desire to create ions?In order to gain or lose valence electrons to the element they interact with, elements create ions. They acquire a whole octet as a result. You might be wondering what a whole octet is. When an element contains all 8 valence electrons and is stable, it is said to have an octet, rendering it nonreactive.
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If mass of an empty 7.0 mL pycnometer is 10.2g and the mass of the same pycnometer with an unknown liquid is 21.8g. Determine the density of the unknown liquid to ONE DECIMAL PLACE in g/mL.
Answers
The formula for calculating density is expressed as
Density = mass/volume
From the information given,
mass of empty pycnometer = 10.2
mass of the same pycnometer with an unknown liquid is 21.8.
Mass of unkown liquid = 21.8 - 10.2 = 11.6
volume of unknown liquid = 7
Thus,
Density = 11.6/7
Density = 1.7 g/ml
How much pressure does a box whose sides are 1.44 m long each exert on the ground due to gravity?Assume that the box has a mass of 17.3 kg. HINT: Look at the definition of pressure - what force is doing the "pushing?" What's the area?
Answers
Pressure = Force / area
m= mass = 17.3 kg
g= gravity = 9.8 m/s^2
Force = m * g = 17.3 kg * 9.8 m/s^2 = 169.54 N
P = F / A
A = area = 1.44^2 = 2.0736 m^2
P = 169.54 N/ 2.0736 m^2 = 81.76 Pa
if you take a picture of your friend, who is standing 3.90 m from the lens, using a camera with a lens with an 85 mm focal length, how far from the sensor is the lens?
Answers
If you take a picture of your friend, who is standing 3.90 m from the lens, using a camera with a lens with an 85 mm focal length, the sensor is 1.087 m from the lens.
1 / f = 1 / v + 1 / u
f = Focal length
v = Image distance
u = Object distance
u = 3.9 m
f = 85 mm
f = 0.85 m
1 / v = 1 / f - 1 / u
1 / v = 1 / 0.85 - 1 / 3.9
1 / v = 3.05 / 3.315
v = 1.087 m
The sign convention for this formula is:
When the object is on the same side of the refracting surface as the incoming light, the value of u is taken as positive else taken as negative.When the image is on the same side of the refracting surface as the incoming light, the value of v is taken as positive else taken as negative.Therefore, the sensor is 1.087 m from the lens.
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how do astronomers currently think the amount of detectable (observable) matter in the universe compares to the amount of dark matter and dark energy?
Answers
Astronomers think the amount of detectable matter as one of some hundred thousand million out of which some are compared and contrasted with the help of modern telescopes.
In 1920 when astronomers began to study the spectra of stars in other galaxies , they found something most peculiar. There were same characteristic sets of missing colours as for stars in galaxy. But they were shifted by some relative amount towards red end of spectrum.The present rate of expanding universe has some resolutions in thermodynamics as the third law states "entropy of universe keeps increasing" , where entropy states the randomness of the universe.Some non luminous material that is believed to exist in space and have the ability to take any several forms including the weakly interacting particles , further having classification of hot dark matter and cold dark matter. Gravity has its field in every particle due to which the stability is maintained with centrifugal force. Something pairing to oppose this fundamental force or field is the dark energy that is negative in nature. And this is responsible for slowing the rate of expansion of universe.[tex]Dark. energy= \frac{\alpha }{\beta } \\\\\alpha =pressure \\\\\beta =energy-Density[/tex]
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what is the net force and acceleration of a falling crate (mass including parachute 132 kg) when the upward force or air resistance is one-fourth its weight?
Answers
the net force and acceleration of a falling crate (mass including parachute 132 kg) when the upward force or air resistance is one-fourth of its weight is 7.35m/s²
We know from newton's second law
sum of forces = ma
here, the forces are weight (down) and resistance (up)
choosing down as the positive direction, we have
weight - resistance = ma
mg - [tex]\frac{1}{4}[/tex](mg)=ma
[tex]\frac{3}{4}[/tex] mg = ma or a = [tex]\frac{3}{4}[/tex] g =7.35m/s²
The net pressure is defined as the sum of all the forces appearing on an item. internet force can boost up a mass. some different pressure acts on a body either at relaxation or movement. Internet forces is a term utilized in a system while there may be an extensive range of forces.
the net pressure is the vector sum of forces performed on a particle or object. The internet pressure is an unmarried force that replaces the impact of the unique forces on the particle's motion. It gives the particle equal acceleration as all those actual forces collectively as defined via Newton's 2nd law of motion.
it's miles possible to decide the torque related to the factor of application of an internet pressure so that it maintains the movement of jets of the object below the original machine of forces. Its related torque, the net pressure, turns into the consequent force and has an identical impact on the rotational motion of the object as all actual forces have taken together.
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Objects with smaller masses have more gravitational energy than objects with larger masses. True or false?
Answers
Answer:
False
Explanation:
The greater the size of the mass, the greater the size of the gravitational force/energy.
A boy and a dog are both pulling oppositely on the same bone when the boy pulls as hard as he can. What is the equal and opposite force for the force of the boy pulling on the bone as described by newton's third law?.
Answers
The equal and opposite force for the force of the boy pulling on the bone, the net force is zero.
A boy and a dog are both pulling oppositely on the same bone when the boy pulls as hard as he can. There is no net force. Each dog exerts an equal amount of force in opposing directions, which causes the combined force to cancel out.
Newton's third law :
When one body applies pressure to another, the first body feels pressure that is equal to the applied pressure but applied in the opposite direction.Fa = - Fb force exerted on a body is equal and opposite to the force exerted on another body.The equal and opposite force for the force of the boy pulling on the bone, the net force is zero.
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When a pole vaulter reaches the top of her vault, how does her potential energy compare to her kinetic energy?.
Answers
Answer
Explanation:
the kinetic energy is twice the amount of potential energy.
Greenhouse A. Open system B. Closed system C. Isolated system
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In an open system, both energy and matter are exchanged with the surroundings.
In a closed system, only energy is exchanged with the surroundings.
In an isolated system, neither matter nor energy is exchanged with the surroundings.
In the greenhouse, only energy is exchanged with the surroundings.
Thus, the greenhouse is a closed system.
Geremy rolled a can of soup off the kitchen table. The can landed 0.75m from the table. The height of the table is 1.35m. At what velocity did Geremy roll the can horizontally?
Please show all work, thank you
Answers
The velocity used by Geremy to roll the can horizontally is 1.44 m/s
How do I determine the horizontal velocity used by Geremy?First we shall obtain the time taken for the can to reach the ground. This is shown below:
Height (h) = 1.35 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =?h = ½gt²
1.35 = ½ × 9.8 × t²
1.35 = 4.9 × t²
Divide both side by 4.9
t² = 1.35 / 4.9
Take the square root of both side
t = √(1.35 / 4.9)
t = 0.52 second
Finally, we shall determine the velocity used by Geremy to roll the can horizontally. Detail below:
Horizontal distance (s) = 0.75 mTime (t) = 0.52 secondHorizontal velocity (u) = ?s = ut
0.75 = u × 0.52
Divide both sides by 0.52
u = 0.75 / 0.52
u = 1.44 m/s
Thus, we can conclude that the horizontal velocity used is 1.44 m/s
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The length of an iron rod is measures by a brass scale. When both of them are at 10°C, the measured length is 50cm. What is the length of the rod at 40°C when measured by the brass scale at 40°C.? (a for brass=24x10-6°C, a for iron = 16x10 °C -¹)
Answers
Answer: The answer is 222.8
A roller coaster car is cresting a hill at 10 m/s . if the hill has a 30 m radius, what force will the 70 kg rider feel from the seat of the coaster? (the seat force is the normal force)
Answers
Answer:
A 53.5-kg rider on a roller coaster car is moving 10.3 m/s at the top of a loop which has a radius of curvature of 7.29 m.
Explanation: