an airplane traveling at half the speed of sound emits a sound of frequency 4.90 khz. (a) at what frequency does a stationary listener hear the sound as the plane approaches? khz

Answers

Answer 1

The frequency does a desk bound listener pay attention the sound because the aircraft approaches is 10.0kHz

Calculation :

velocity of the of sound (air plane) v= 172m/s

frequency emmited n=four.9 kHz

       = four.9*[tex]10^{three}[/tex]

n' =[tex](frac{V-Vo}{V-V,} )*n\[/tex]

[tex]V,[/tex]= [tex]frac{V}{2}[/tex]

Then the obvious frequency heard wiil be

n' =[tex](four.nine*10^{three} Hz)(frac{V}{V-frac{V}{2} } )[/tex]

   = (4.nine[tex]10^{3}Hz[/tex]*)(2)

   =10.0kHz

Frequency is the quantity of occurrences of a repeating event according to unit time. [1] For readability, additionally called temporal frequency, which is different from angular frequency. Frequency is measured in hertz (Hz) and corresponds to 1 event in keeping with 2d. length is the reciprocal of frequency due to the fact period is the time c language between events. [2]

For example, if the coronary heart beats 120 instances according to minute (2 hertz), the length T (the c language between repeated beats) is zero.5 seconds (60 seconds divided by way of one hundred twenty beats). cost). Frequency is an crucial parameter used in technological know-how and engineering to explain the speed of vibrations and vibrational phenomena inclusive of mechanical vibrations, audio indicators (sound), radio waves, and light.

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Related Questions

A car accelerates uniformly from rest and reaches a speed of 11.9 m/s in 11.5 s. The diameter of a tire is 89 cm. Find the number of revolutions the tire
makes during this motion, assuming no slip-ping

Answers

Answer:

153 revolutions

Explanation:

D = (Vi)t + 1/2(a)(t²)

Since Vi = 0, the first term drops out

a = Δv/t = (11.9 m/s)/(11.5 s) = 1.03 m/s²

D = 1/2(1.03 m/s²)(11.5 s)² = 68.1 m

Circumference of a circle = C = 2πr

r =  D/2 = (0.89 m)/2 = 0.445 m

So for every 1 revolution of a tire, the distance traveled is 0.445 m

68.1 m / 0.445 m/rev  = 153 revolutions

1. thomas jefferson proposed using the length (l) of a simple pendulum whose period (t) was exactly 2 seconds as the definition of a standard meter. what is the length (l) of a 2 sec. pendulum in si units?

Answers

The length of a 2 sec pendulum is 1 m.

Given that, initial length of the simple pendulum L₁ = 1 m

Initial time period T₁ = 2 sec

We need to find the length of the pendulum whose time period is 2 sec

T₂ = 2 sec

L₂ = ?

We know that the time period of the simple pendulum is given by the formula,

T = 2π√(L/g)

From the above relation, we can write T ∝ √L

T₁ / T₂ = √(L₁/L₂)

Making L₂ from the above relation, we have,

L₂ = (T₂² * L₁)/ T₁² = 2² * 1/ 2² = 1 m

Thus, the length of a 2 sec pendulum is 1 m.

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The muscular system consists of exclusively this kind of tissue.
A.skeletal muscle
B.the muscular system is comprised of all types of muscle tissue
C.smooth muscle
D.cardiac muscle

Answers

Skeletal muscle tissue, connective tissue, nerve tissue, and blood or vascular tissue make up each muscle and organ. Thus, any form of tissue may be found in the muscular system.

The muscular system is made up of cells with particular functions called muscle fibers. Its primary trait is its capacity to contract. Things are moved by muscles that are connected to blood vessels, internal organs, or bones. Almost all body movement is primarily caused by muscle contraction. The whole skeletal muscle is a component of the muscular system.

The bulk of the organs that make up muscles are muscle cells, also known as muscle fibers or monocytes (primarily in skeletal and cardiac muscle) (mainly in smooth muscle).The muscles around the stomach help food move through the digestive system by contracting and pushing food to the small intestine through a process known as peristalsis.

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1. a metal ring with a clockwise current produces a magnetic field (right-hand-rule). if the current increases (which increases the field) over time, what direction will the induced current on the ring be?

Answers

A counterclockwise current will be induced (ccw). The area of the loop shrinks as the bar ascends through the zone of constant magnetic field, and as a result, the flux through the loop also shrinks. Any induced current will tend to oppose the decrease, according to Lenz's law.

When current I in the wire is gradually growing, in which direction does induced current flow through metal rings?

In accordance with Lenz's law, induced current in metal ring 1 will flow clockwise, but induced current in metal ring 2 will flow counterclockwise.

Is the induced emf's direction the same as the induced current's direction?

An electric circuit's induced emf always behaves in a way that the current it pushes through the circuit opposes the change in magnetic flux that results from it.

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how does the difference between the ranges of the strong nuclear force and the coulomb force affect the makeup of each atom’s nucleus?

Answers

Because the range of the Coulomb force is longer, heavier atoms have more neutrons than protons.

What is  strong nuclear force?The force that holds protons and neutrons in atoms' nuclei is an example of the strong nuclear force. the substances heavier than an atom of hydrogen. the core of the sun's hydrogen and helium fusion.Quarks are constrained into proton, neutron, and other hadron particles by the strong interaction, also known as the strong nuclear force. The nuclear force, commonly known as the strong interaction, is what holds neutrons and protons together to form atomic nuclei.Because the range of the Coulomb force is longer, heavier atoms have more neutrons than protons.The nuclear force also known as the strong interaction binds protons and neutrons to form atomic nuclei.

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if the string is released at the instant the ball is at the top of the loop, how far to the right does the ball hit the ground?

Answers

if the string is released at the instant the ball is at the top of the loop, 139.23 cm far to the right does the ball hit the ground.

What is minimum velocity?

A minimum velocity is present at a position where acceleration is both negative to the left and positive to the right.

At the minimum velocity at the top v, the weight mg provides the centripetal acceleration -

R = 50 cm = 0.5 m

Thus, mv²/R = mg

or, v² = Rg

or, v = v Rg

or, v = v × 0.50 x 9.8

or, v =v × 4.9

or, v = 2.21 m/s

The ball goes off horizontally at this speed and falls through a height

y = h + R

or, y = 150 + 50

or, y = 200 cm

or, y = 2 m

Using y = 0 + 0.5g.t2

or, t = v (2.y/g)

or, t = v [2 x 2/9.8]

or, t = 0.63 s

The horizontal distance travelled, x = v.t

x = 2.21 x 0.63

x = 1.3923 m

x = 139.23 cm.

If the string is released at the instant the ball is at the top of the loop, 139.23 cm far to the right does the ball hit the ground.

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Your physics teacher crumples a piece of paper into a ball and releases it from rest 2. 0 m from the ground. How long does the ball take to hit the ground?.

Answers

When the ball is released from rest 2m from the ground, it will hit the ground at 0.63 seconds.

Here, we will use free fall kinematics equations.The ball hits the ground due to gravity of earth. we use equation of motion and will find time after which ball hit the ground. There are 3 main equations of motion. The paper ball falls from the rest, so the initial velocity will be 0.

[tex]s = ut + \frac{1}{2} a {t}^{2} [/tex]

S is the height

u is the initial velocity

g is the gravity (9.81 m/s²)

t the time

Now, the height will be 2m, u = 0

and we have to solve it for t

[tex]2 = 0 \times t + \frac{1}{2} \times 10 \times {t}^{2} [/tex]

[tex]2 = 5 {t}^{2} [/tex]

[tex] {t}^{2} = \frac{2}{5} [/tex]

t = 0.63

t = 0.63 seconds.

hence, the ball will hit the ground after 0.63 seconds of it's release.

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an object is placed between the focal and the center of curvature of a concave mirror. the object is then moved closer to the mirror, but still remains between the focal point and the center of curvature. do the magnitudes of (a) the image distance and (b) the image height become larger or smaller?

Answers

When an object is moved closer to the concave mirror, then

a)magnitude of image distance increases.

b)the image height become larger.

In concave mirror, we know that when an object is placed at the focus, its image will formed in enlarged size at infinity, it means height of image is large as compared to height of object. Here the scenario is same when object is placed at the center of curvature, object formed at the center of curvature of mirror in opposite direction of object. When object is moved closer to mirror from the center of curvature, image starts moving away from the mirror.

Image will formed below the positive y-axis and nature of image will be inverted and size of image starts increasing when it moves closer to mirror.

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Astronomers will never directly observe the first few minutes of the universe because:_______.

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Astronomers will never directly observe the first few minutes of the universe because the universe was opaque at that time.

The universe is all of space and time and its contents, along with planets, stars, galaxies, and all other forms of count number and strength. The huge Bang theory is the winning cosmological description of the improvement of the universe.

The Universe is thought to consist of three types of substance: normal remember, 'dark count number', and 'dark energy. Regular remember consists of the atoms that make up stars, planets, human beings, and every different seen object in the Universe.

The actual spatial length of the universe is unknown. but, through measuring the observable universe, the current length of the universe is approximately ninety-five billion mild-years in diameter.

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a space station of diameter 80 m is turning about its axis at a constant rate. if the acceleration of the outer rim of the station is 2.5 m/s2 , what is the period of revolution of the space station?

Answers

the period of revolution of the space station is 25.1 seconds.

Calculation :

acceleration ac=v2/r

velocity v=(2*pi*r)/T

therefore T2 = (4*pi²*r)/ac

                 = (4*pi²*40)/2.5  

                given, diameter = 80m  therefore  radius  r=40m

                 =  25.1 seconds

A space station is a spacecraft capable of supporting a human crew in orbit for long periods of time, and is therefore a kind of living space in space. No greater propulsion or landing system. An orbital station or orbital space station is a satellite (that is, a type of orbital spaceflight). A station needs a docking port so that other spacecraft can dock to transfer crew and supplies. The purpose of maintaining an orbital outpost varies by program. The space station was launched primarily for scientific purposes, but military launches have also taken place.

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find the distance required such that the fields of this mode will be reduced in magnitude by 20 db if the operating frequency is 10 ghz.

Answers

When operating at a frequency of 10 GHz, 16.54 cm is needed to reduce the fields of this mode's magnitude by 20 dB.

Given,

f=18 GHz,

TE₁₀ mode,[tex]f_{c}[/tex]=12GHz

wave length,λ=?,phase constant ,β=?

d=? when magnitude by 20dB

if the operating frequency is 10 GHz

defined, F₁₀=[tex]\sqrt{1-(\frac{f_{c} }{f})^{2} }[/tex] = [tex]\sqrt{1-(\frac{12}{18})^{2} }[/tex] = 0.75

wavelength,λ₁₀=λ₀/F₁₀=1/0.75=1.33cm

phase constant ,β₁₀=2π/λ₁₀ =2π/(1/0.75)*10⁻²

β₁₀=2π*0.75*100

β₁₀=150π rad/m

for operation below the cutoff frequency,

[tex]r_{mn}[/tex]=[tex]\alpha_{mn}[/tex]=[tex]\sqrt{4\pi^{2}\mu \epsilon(f_{c}^{2}-f^{2}) }[/tex]

[tex]\alpha _{10}[/tex]=[tex]\beta \sqrt{(f_{c}/f)^{2} -1 }[/tex]

here,[tex]\beta =\frac{2\pi f}{u_{0} }[/tex]

[tex]\beta[/tex]=6.67π rad/m

α₁₀=6.67π[tex]\sqrt{(12/10)^{2}-1 }[/tex]

α₁₀=13.9 [tex]N_{p}[/tex]/m

[tex]e^{-\alpha_{10}d }[/tex]=1/10

-α₁₀d=-2.3

d=2.3/139

d=16.54cm

The number of waves that pass a fixed point in a unit of time is known as the frequency in physics. It is also the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. When a body in periodic motion moves through a series of events or locations before returning to its initial state, it is said to have experienced one cycle or one vibration. moreover, simple harmonic motion; angular velocity.

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an organ pipe is made to play a low note at 27.5 hz, the same as the lowest note on a piano. assuming a sound speed of 343 m/s, what length of open-open pipe is needed?

Answers

Similar to the lowest note on a piano, an organ pipe is designed to play a low note at 27.5 Hz. utilizing the 343 m/s sound speed, The required open-open pipe length is 3.12 m.

λ = v / f = 343 m/s / 27.5 s = 12.5 m

A) open-ended, L = λ/2, so

L = 12.5 m / 2 = 6.24 m

B) closed-ended, L = λ / 4, so

L = 12.5 m / 4 = 3.12 m

When pressurized air (also known as wind) is driven through an organ pipe, it causes it to resonate at a particular pitch, producing the sound of the pipe organ. A specific musical note is tuned into each pipe. A rank is a collection of organ pipes with a similar tonality that makes up the entire scale; a stop is made up of one or more ranks.

Lead is typically used to make metal pipes; however, tin, antimony, and copper are also alloyed with it for added rigidity. The characteristics of the resulting pipe depend on the ratio of each metal in the alloy. Tin content increases the color's brightness just a little bit.

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A roller coaster is moving along the track. Complete the sentence that describes the conservation of energy. Mechanical energy is (conserved, not conserved) because the roller coaster (loses, gains) energy due to friction and air resistance as it travels down the track.

Answers

Mechanical energy is not conserved because the roller coaster loses energy due to friction and air resistance as it travels down the track.

In a roller coaster, the energy changes from potential energy to kinetic energy and back again many times over the course of a ride.

As there are external forces acting on the system, the mechanical energy will not be conserved.

When the coaster moves down the track, the amount of available mechanical energy decreases throughout the ride because of the friction between the track and coaster and air resistance. These two forces absorb energy from the cart and transform it into thermal energy as well as sound energy, which is then lost to the surrounding.

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a 4.5 kg object is suspended by a string from the ceiling of an elevator. the acceleration of gravity is 9.8 m/s 2 . determine the tension in the string if it is accelerating upward at a rate of 2.2 m/s 2 .

Answers

The tension in the string is 54 N.

Given that, mass of the object m = 4.5 kg

String is acting in the upward direction with acceleration a = 2.2 m/s²

Acceleration due to gravity g = 9.8 m/s²

As the string is accelerating upwards, it means that the net force acting on it is given by the formula

T = m(a + g)

where, T is tension

m is mass

a is acceleration

g is acceleration due to gravity

Substituting the values in the above equation to find out tension in the string,

T = m(a + g)

⇒ 4.5 * (2.2 + 9.8)

⇒ 4.5* 12

⇒ 54 N

So, the tension in the string is calculated to be 54 N.

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a hydraulic has two pistons. the area of piston 1 is eleven times smaller than the area of piston 2. if a pressure of 98 atm is applied to piston 1, how much pressure will piston 2 experience as a result?

Answers

The pressure will piston 2 experience as a result is 8.99atm if area of piston1 is eleven times smaller then area of piston 2.

We know very well pressure is inversely proportional to area.It means when we increase pressure, then area will decrease or vice-versa.

Equation of pressure is given by P=F/A.

Now,it is given that area of piston 1 is 11 times smaller than area of piston 2.It means if we assume area of piston 1 is A.

Then area of piston 2 is 11 times of area of piston 1 which is 11A.

Now, writting the expression

=>P₁/P₂ = (F/A₁) / (F/A₂)

=>P₁/P₂ = A₂/A₁

So, we have P₁=98atm,A₂=11A,A₁=A and we need to find P₂=?

So, on putting the values,we get

=>98/P₂=11A/A

=>98/P₂=11

=>P₂=98/11

=>P₂=8.99atm

Hence, pressure will piston 2 experience is 8.99atm.

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What is the wavelength of radiation that has a frequency of 5.70 1014 S − 1?

Answers

The wavelength of the radiation is 5.263 x 10⁻⁷m.

Using this equation, we can calculate the energy of only single wave particles: photons, electrons, protons, neutrinos, muons, etc. It does not work for other types of waves, including vibrations of materials or media, i.e. sound waves/pressure waves.

Water waves, solid vibrations, etc. In these types of waves the energy depends on various factors. B. Whether the wave is longitudinal or transverse, plane or spherical, wave velocity, material density, viscosity, elasticity, etc. Physics often talks more about energy density than the total energy of a wave.

E=hv

E=hc/y

c/y=v

c/v=y

3x 10⁸/5.70 x 10¹⁴=y

y=5.263 x 10⁻⁷m

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a skater holds her arms outstretched as she spins at 180 rpm. what is the speed of her hands if they are 140 cm apart?

Answers

The speed of her hands when they are 140cm apart is 20m/s, after calculating the given angular speed and distance.

What is Angular Speed?

The object's rotating speed is known as its angular speed. The symbol for distance, which is expressed in radians, is θ. Seconds are used to determine how long something takes. Radians per second, or rad/s, is the unit used to express angular speed.

Calculation:

The fundamental idea behind this is the linear speed of a body travelling at a fixed rotational speed.

To solve for the linear speed, first substitute the expression for the hand's distance from the centre of motion in the linear speed expression.

Angular speed  

ω= V/r

Where,

ω = angular speed

r = distance (radius) Or d/2

v = linear speed

Given,

r= d/2 = 140cm/2 = 70cm = 0.7m

V= ω/r = 140rpm/0.7cm= 20m/s.

Hence, the speed of her hands when they are 140cm apart is 20m/s, after calculating the given angular speed and distance.

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a 4.0-m-long, 500 kg steel beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. a 70 kg construction worker stands at the far end of the beam. what is the magnitude of the torque about the point where the beam is bolted into place?

Answers

The magnitude of torque about the point where the beam is bolted into place is 12544 Nm.

The length of the beam = l = 4 m

The mass of the steel beam = M = 500 Kg

Mass of the construction worker = m = 70 Kg

Torque of steel beam = T₁

Torque of worker = T₂

The magnitude of torque = T =

Torque is the force in a distance the relation is proportional so the torque of weight first is:

= Torque of steel beam = Force of steel beam X distance

= T₁ = F₁ X d

= T₁ = M X g X l

= T₁ = 500 X 9.8 X 4

= T₁ = 9800 Nm

Torque is the force in a distance the relation is proportional so the torque of weight second is:

= Torque of steel beam = Force of steel beam X distance

= T₂ = F₂ X d

= T₂ = m X g X l

= T₂ = 70 X 9.8 X 4

= T₂ = 2744 Nm

Net torque = T =

= T = T₁ + T₂

= T = 9800 + 2744

= T = 12544 Nm

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object 1 has a temperature of 80 c, and object 2 has a temperature of 20 c. which way will heat flow if they are brought in contact?

Answers

Heat will flow from object 1 to object 2, as heat always flows from hotter objects to colder objects.

Heat will flow from object 1 to object 2 because heat will always flow from the object with the higher temperature (object 1) to the object with the lower temperature (object 2). This is known as the 1st Law of Thermodynamics, and is related to the concept of entropy.

When the two objects are brought in contact, there will be an exchange of energy in the form of heat. The molecules in object 1 will be moving faster than the molecules in object 2, and so they will transfer some of their kinetic energy to the molecules in object 2, causing them to move faster and the temperature of object 2 to increase. This process will continue until both objects reach the same temperature.

The amount of heat transferred between the two objects is determined by the following equation:

Q = mc∆T

Where Q is the amount of heat transferred, m is the mass of the object, c is the specific heat capacity of the object, and ∆T is the change in temperature between the two objects.

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michael leans on a shopping cart, causing it to start moving. which statement is true about the forces michael and the cart exert on each other?

Answers

Michael and the cart exert equal and opposite forces on each other.

When equal and opposite force is applied, it do not let the body to move. This equal and opposite force is called couple.

What an equal and opposite force does to an object?

Whenever two equal and opposite forces act on a moving object, motion remains unaffected because the net force acting on the body is zero. Thus, the object will not move.

This basically justifies Newton's third law of motion which states, for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A.

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what does the red line on an airspeed indicator represent? maneuvering speed. turbulent or rough-air speed. never-exceed speed.

Answers

An airspeed indicator's red line represents the top speed an aircraft can fly in calm air; this speed should never be purposely exceeded. The never-exceed speed is the name given to this speed.

The values are given in meters. The trail will be white if the plane is less than 100 meters in the air. If the trail is higher than 100 meters, it will first turn yellow, then green, then light blue, dark blue, purple, and finally red at an altitude of more than 2500 meters. Hope this was helpful. On one of their wings, most commercial aircraft have a green light, and on the other, a red light. The green light is positioned on the right wing of the aircraft, while the red light is on the left wing.

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A key feature of an object moving in a circular orbit due to the gravitational interaction is that the object is moving at a constant speed for the duration of the orbit. Why does an object follow a circular orbit at a constant speed?

Answers

It keeps moving in a direction that is parallel to the gravitational pull .The gravitational force generated by the planet's gravity, which the satellite experiences because it orbits it, acts as the necessary centrifugal force.

The reason for the constant speed of a satellite in a circular orbit is what?The gravitational force generated by the planet's gravity, which the satellite experiences because it orbits it, acts as the necessary centrifugal force. As long as the satellite is in a circular orbit, the gravitational force will remain constant, maintaining the satellite's velocity.The centripetal force driving the motion is a result of their gravitational pull in the unique instance of the Earth's round motion around the Sun, or any satellite's circular motion around any celestial body.      

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How can two stars with the same mass be different?

Answers

Two stars with the same mass number can be different in their luminosity, life time and distance with respect other stars and planets.

What are stars?

Stars are spatial objects with brightness and are made of gases and dust. The major part of stars are hydrogen and helium gases. There are trillions of stars for each galaxies in the universe.

The energy formed inside the stars is from  the nuclear fusion of hydrogen nuclei forming helium nuclei releases tones of heat and light energy. The light and heat energy produced from each stars differ.

The luminosity or brightness of stars with same mass will be different. The life time of each stars also differ from other stars.

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what is the mass of an object that weighs 250 n on the surface of the earth where the acceleration due to gravity is 9.80 m/s2?

Answers

The mass of an object that weighs about 25.5kg.

Mass: What is it?

Mass in physics is a numerical representation of inertia, a fundamental property of all matter. What a body of matter is fundamentally is the resistance it offers to a change in its speed or position as a result of the application of a force. Less change occurs when a force is applied to a body with more mass.

Given,

F = 250N

a = 9.8m/s²

F = ma

250 = m×9.8

m = 250/9.8

m = 25.5kg.

Therefore, the mass of an object that weighs about 25.5kg.

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a stack of books rests on a level frictionless surface. a force f acts on the stack, and it accelerates at 3.0 m/s2. a 1.0 kg book is then added to the stack. the same force is applied, and now the stack accelerates at 2.0 m/s2. what was the mass of the original stack?

Answers

A stack of books rests on a level frictionless surface. a force f acts on the stack, and it accelerates at 3.0 m/s2. a 1.0 kg book is then added to the stack. the same force is applied, 2.0kg was the mass of the original stack.

The concept of the frictionless plane first appeared in the writings of Galileo Galilei. In his 1638 book The Two New Sciences, Galileo offered a formula that predicted the motion of an object falling down an inclined plane. His model was not based on experiments with objects moving down an inclined plane, but rather on his conceptual modeling of the forces acting against the object. His formula was based on earlier experiments with free-falling bodies. Galileo understood the mechanics of the inclined plane as a combination of horizontal and vertical vectors because gravity acting on the object and being redirected by the slope of the plane. Galileo's equations, on the other hand, do not take friction into account, and as a result, they do not accurately predict the results of a practical experiment. This is due to the fact that whenever one mass exerts a non-zero normal force on another, some energy is always lost.

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what is the pattern? i need help please ill give 100 point if help

Answers

The mass of the bowling ball is 5kg and the energy of player will be 62.5 kcl. With the denominator is greater the acceleration should decrease by the same factor that increases the mass.

What Newton's second law states?

Newton's second law states that force is proportional to mass and acceleration.

F = m a

The applied force creates an acceleration in the elephant a = F / m. If the mass of the elephant increases m2> m, the expression takes the form a = F / m2. With the denominator is greater the acceleration should decrease by the same factor that increases the mass.

The frequency of a wave depends on the properties of medium density and the elasticity properties change the amplitude depends on the energy carried by the wave, that is, the amplitude is proportional to the height of the wave (oscillation).

Therefore, The mass of the bowling ball is 5kg and the energy of player will be 62.5 kcl. With the denominator is greater the acceleration should decrease by the same factor that increases the mass.

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two coherent sources of radio waves, a and b, are 5.00 meters apart. each source emits waves with wavelength 6.00 meters. consider points along the line connecting the two sources. 1) At what distance from source A is there constructive interference between points A and B?
2) At what distances from source A is there destructive interference between points A and B? Note that there will be two separate interference fringes between point A and point B.

Answers

The distance from source A at which there is constructive interference between points A and B is 3.50 meters.There will be two separate interference fringes between points A and B, with the first fringe occurring at 3.00 meters and the second fringe occurring at 6.00 meters.

The distance from source A at which there is constructive interference between points A and B can be found by setting the phase difference between the waves from sources A and B to a multiple of 2π. The phase difference between the waves at a given point is given by:

To determine the distance from source A at which there is constructive interference between points A and B, we can use the formula for the constructive interference of two waves:

d = (m + 1/2) *λ / 2

where d is the distance from source A, m is an integer, lambda is the wavelength of the radio waves, and the term (m + 1/2) is the phase difference between the two waves.

Plugging in the values given in the problem, we get:

d = (m + 1/2) * 6.00 meters / 2

= (m + 0.5) * 3.00 meters

Since we want constructive interference, the phase difference must be an integer multiple of 2π, which means the value of m must be an even integer. Therefore, we can set m = 2 to get:

d = (2 + 0.5) * 3.00 meters

= 3.50 meters

So the distance from source A at which there is constructive interference between points A and B is 3.50 meters.

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which labeled structure is in charge of editing and sorting incoming sensory stimuli, and controlling information entry into the cerebral cortex?

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The central sulcus is located in front of the parieto-occipital sulcus, which divides the parietal lobe from the occipital lobe. The somatosensory cortex is contained within it, which is in charge of processing sensory data.

The cerebral cortex is located where in the brain?

The top layer of your cerebrum is called the cerebral cortex. Your brain's largest region is called your cerebrum. Your brain is split into two parts by your cerebrum, which is known as hemispheres. A group of nerve fibers known as the corpus callosum holds the hemispheres together.

Which area of the spinal cord controls the processing of sensory information?

Processing of sensory data is carried out by the posterior horn. To the skeletal muscles, the anterior horn transmits motor signals. The primary structure of the sympathetic division of the autonomic nervous system is the lateral horn, which is only present in the thoracic, upper lumbar, and sacral regions.

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a 0.460 kg mass suspended from a spring oscillates with a period of 1.50 s. how much mass must be added to the object to change the period to 1.90 s?

Answers

The mass must be added to the object to change the period to 1.90s is 0.428Kg.

What is the formula for time periods?

A thing's time period is the length of time needed for it to complete one oscillation. Any wave element's angle displacement in relation to time is known as its frequency. T is the period, and f is the frequency, and the formula for time is T = 1/f. equals c / f, where c is the wave speed (m/s) and f is the frequency (Hz).

A mass of 0.460 kg oscillates with a period of 1.90 s when it is suspended from a spring.

The time period's formula is provided by,

T = 2π √m/k ....(1)

K denotes the spring's constant, and m denotes the mass.

The new duration is specified by,

T' = 2π √m'/K....(2)

where K is the spring constant, and m' is the final total mass following the addition.

Subtract equation (1) from equation (2).

T/T' = √m/m'

Now change the previously mentioned expression with the known terms.

1.5/1.9 = √0.46/m'

To find the value of m', simplify the expression above.

m' = 0.5/0.5625

m' = 0.888kg

Now, we can calculate the mass that must be added to the object to make the period 1.90s:

m' = 0.889 - 0.460

m' = 0.428Kg.

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how large a mass would have to be placed on top of the wooden block when floating in the water so that the block would be completely submerged, i.e. its top would be level with the surface of the water?

Answers

In the question, the floating level is known as upthrust. It happens due to the density of that object.

Upthrust is an upward force on an object (in this case the wooden block) provided by the liquid (water) as a result of it displacing some of the liquid. Thus floating objects will normally displace some part of the liquid; making some part of it to be submerged in water.

The percentage of the submerged wooden block can be calculated as

length (in height) of the wood block submerged in water/total length (in height) of the wood × 100

This concept is based on the density of the floating object.The concept of density seeks to measure the weight of an object in relation to its size. It is the measure of how packed together the particles of that object are.

An object placed in a liquid displaces a certain volume of the liquid, based on the relative density of the object and the liquid.

If an object is less dense than a liquid in which it is placed, it displaces a smaller volume of the liquid than its volume, hence only some part of the object will be seen to be under the liquid, the other part will float.

If an object is denser than the liquid in which it is placed, it displaces a larger volume of the liquid than its own volume, making the object to sink and is submerged.

Therefore, if the density of an object and the liquid into which it is submerged is the same. the object's mass per unit volume is the same as the liquid's mass per unit volume.

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