Accessibility ModePrintFindPart II: Limiting Reactant1. Consider the reaction: 5C +2SO₂ → CS₂ + 4COa.) If you had 10 mol of Carbon, how many moles of carbon monoxide would be produced?b.) If you had 10 mol of sulfur dioxide, how many moles of carbon monoxide would beproduced?c.) If you had 10 mol of C and SO2 which reactant would be limiting?d.) What is the theoretical yield of CO, in moles if you react 10 moles of each reactant?SAMEFaPmenSavarہےEP Immersive Reader

Accessibility ModePrintFindPart II: Limiting Reactant1. Consider The Reaction: 5C +2SO CS + 4COa.) If

Answers

Answer 1

Answer:

a.) 8 moles of carbon monoxide (CO).

b.) 20 moles of carbon monoxide (CO)

c.) C is the limiting reactant.

d.) The theoretical yield of CO would be 8 moles.

Explanation:

Let's write the chemical equation:

[tex]5C+2SO_2\rightarrow CS_2+4CO.[/tex]

a.) You can see that 5 moles of carbon (C) reacted produces 4 moles of carbon monoxide (CO), so if we want to know how many moles of carbon monoxide can be produced, we can multiply each coefficient in the chemical equation by 2 (because we will have 10 moles of carbon):

[tex]10C+4SO_2\operatorname{\rightarrow}2CS_2+8CO.[/tex]

The answer is that we will produce 8 moles of carbon monoxide (CO) by 10 moles of carbon (C).

b.) We can apply the same logic to this case. In the chemical equation, we have 2 moles of sulfur dioxide (SO2) reacted that produces 4 moles of carbon monoxide (CO), so if we want to know how many moles of carbon monoxide can be produced, we can multiply each coefficient by 5 so we will have 10 moles of sulfur dioxide:

[tex]25C+10SO_2\operatorname{\rightarrow}5CS_2+20CO.[/tex]

The answer is that we will produce 20 moles of carbon monoxide (CO) by 10 moles of sulfur dioxide (SO2).

c.) We have already known that 10 moles of C will produce 8 moles of CO, and 10 moles of SO2 will produce 20 moles of CO. If we react 10 moles of C and 10 moles of SO2, you can note that we're going to have an excess of SO2 because we don't have enough amount of C to produce 20 moles of CO as SO2 do. So based on this logic, C is being consumed first and C would be the limiting reactant.

d.) Remember that the theoretical yield indicates the amount of a product obtained in a chemical reaction.

As we saw before, C is the limiting reactant if we react 10 moles of each reactant, so we have already known that 10 moles of C reacted produces 8 moles of CO, so the theoretical yield of CO would be 8 moles.


Related Questions

KH D m d c mEJOg3.65 g = [?] mg=Enter

Answers

In each 1 gram, we have 1000 miligrams, that is:

1 g = 1000 mg

So, we can use rule of three to find the answer:

x ---- 3.65 g

1000 mg ---- 1 g

Thus:

[tex]\begin{gathered} \frac{x}{1000mg}=\frac{3.65\cancel{g}}{1\cancel{g}} \\ x=1000mg\cdot3.65 \\ x=3650mg \end{gathered}[/tex]

So, we have:

3.65 g = 3650 mg

When the temperature of a gas is increased and the pressure is held constant what happens to the density of the gas?

Answers

Answer:

The density of the gas will increase.

Explanation:

From the Charles's law of Ideal gases, we know that, if the pressure is constant, the behavior of the gas will be represented like:

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

So, if the temperature of a gas is increased, the volume of the gas will decrease, because temperature and volume (in the charles's law, that is with constant pressure) are inversely proportional.

Now, to analyze what happens with the density, we can see the density formula:

[tex]\text{ Density = }\frac{\text{ Mass}}{\text{ Volume}}[/tex]

So, if the volume of the gas decrease, the density of the gas will increase, because in the density formula, volume and density are inversely proportional.

Finally, if the temperature of a gas is increased and the pressure is held constant, the density of the gas will increase.

A gas occupies 12.3 L at a pressure of 40 mmHg. What is the volume when the pressure is increases to 60 mmHg?

Answers

Step 1 - Understanding the relation between pressure and volume

There are three main variables that can modify the state of a gas: pressure (P), temperature (T) and volume (V). When one of them is kept constant, linear relationships arise between the other two variables, i.e., proportionality relations.

When the temperature is kept constant (isothermic transformation), the pressure and the volume become inversely proportional, i.e., increasing the pressure reduces the volume.

We can state it mathematically as:

[tex]P_1V_1=P_2V_2[/tex]

Step 2 - Using the equation to solve the exercise

To calculate the new volume (V2), we can use the equation. The values we need are given in the exercise:

[tex]\begin{gathered} V_1=12.3L \\ P_1=40\operatorname{mm}Hg \\ P_2=60\operatorname{mm}Hg \\ V_2=\text{?} \end{gathered}[/tex]

Substituting these values in the equation above, we have:

[tex]\begin{gathered} 12.3\times40=x\times60 \\ \\ x=\frac{12.3\times40}{60}=8.2L \end{gathered}[/tex]

The final volume would be thus 8.2L.

Which of the following can be mixed in solution with H₂CO3 to make a buffer?OA. Na₂CO3OB. HFOC. NH3OD. NaHCO3

Answers

A buffer system usually will need a weak acid, like H2CO3, which is carbonic acid, and a strong base, and the only compound that could figure a fairly strong base among the options given is Na2CO3. NH3 and NaHCO3 are weak bases and HF is a strong acid. Therefore the best answer will be letter A

What is the mass percent concentration of a solution containing 30.0 g NaCl and 170.0 mL of water? Assume a density of 1.00 g/mL for water.

Answers

The expression used to calculate the mass percent concentration is: % (m/m) = (mass of solute) / (mass of solution (solute + solvent)) x 100.

First let's transform mL into grams of water:

1 g of water ---- 1 mL of water

x g of water ---- 170 mL of water

x = 170 g of water

Now let's calculate the mass of solution:

mass of solute = 30 g of NaCl

mass of solvent = 170 g of water

solute + solvent = 30 + 170 = 200 g

% (m/m) = (mass of solute) / (mass of solution (solute + solvent)) x 100.

% (m/m) = (30g/200g) x 100.

% (m/m) = 15.0%

Answer: 15.0%

Write the balanced molecular chemical equation for the reaction of solid lithium with aqueous chromium(III) acetate. If no reaction occurs, simply write only NR. Be sure to include the proper phases for all species within the reaction.

Answers

The balanced molecular chemical equation for the reaction of solid lithium with aqueous chromium(III) acetate is given below:

3 Li (s) + Cr(CH₃CO₂)₃ (aq) ---> 3 LiCH₃CO₂ + Cr(s)

What are chemical reactions?

Chemical reactions are reactions that involve the rearrangement of atoms of the substances reacting such that new substances are formed.

Chemical reactions are usually represented using chemical equations.

Chemical equations can be written as molecular equations or as ionic equations.

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what’s the mass of NaCL is in 0.625L of 0.207M solution

Answers

ANSWER

The mass of NaCl is 7.5 grams

EXPLANATION

Given that;

The volume of the solution is 0.625L

The molarity of the solution is 0.207 M

Follow the steps below to find the mass of NaCl

Step 1; Find the number of moles using the below formula

[tex]\begin{gathered} \text{ Molarity =}\frac{moles\text{ of solute}}{\text{ volume of solution}} \\ \end{gathered}[/tex][tex]\begin{gathered} \text{ 0.207 = }\frac{\text{ moles of solute}}{\text{ 0.625}} \\ \text{ cross multiply} \\ \text{ moles of solute = 0.207 }\times\text{ 0.625} \\ \text{ moles of solute = 0.1294 mole} \end{gathered}[/tex]

Step 2; Find the mass of NaCl using the below formula

[tex]\begin{gathered} \text{ mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \text{ cross multiply} \\ \text{ mass = mole }\times\text{ molar mass} \end{gathered}[/tex]

Recall, that the molar mass of NaCl is 58.44g/mol

[tex]\begin{gathered} \text{ mass = 0.1294 }\times\text{ 58.44} \\ \text{ mass = 7.5 grams} \end{gathered}[/tex]

Therefore, the mass of NaCl is 7.5 grams

I just want to know if I did this correctly

Answers

First, let's count down the number of carbon. There are six carbon, so the name have "hex"

There are no double or triple bonds, sou hexane.

The compound is a cyclo, so cyclohexane

There are 2 chlorines, one in position 1 and other in position 2 of the cyclo.

The right name is:

1,2-Dichlorocyclohexane

Each part has its own answer & part 2/2 is a continuation of the first part 1/2 :)

Answers

Answer:

Explanations:

1) According to the first question, we are to find the molar mass of Na₂SO₄.

Find the molar mass of each element present on the compound

• Molar mass of Sodium (Na) = 23g/mol

,

• Molar mass of sulfur (S) = 32g/mol

,

• Molar mass of Oxygen (O) = 16g/mol

Get the molar mass of Na₂SO₄.

[tex]\begin{gathered} \text{Molar mass of }Na_{2}SO_{4}=2(23)+32+4(16) \\ \text{Molar mass of }Na_2SO_4=46+32+64 \\ \text{Molar mass of }Na_{2}SO_{4}=142g\text{/mol} \end{gathered}[/tex]

Therefore the molar mass of Na₂SO₄ is 142g/mol

2) The formula for calculating the number of moles of the compound Na₂SO₄ is expressed as:

[tex]n=\text{Molar conc.}\times\text{volume}[/tex]

Given the following parameters:

• Molar concentration = 0.202M = 0.202mol/L

,

• Volume = 784mL= 0.784L

Substitute the given parameters into the formula:

[tex]\begin{gathered} n=0.202\frac{mol}{\cancel{L}}\times0.784\cancel{L} \\ n=0.1584\text{moles} \end{gathered}[/tex]

Hence the number of Na₂SO₄ needed is 0.1584moles.

Now, provide the following information: Molecular formula

Answers

The molecular

Step-by-step explanation:

Molecular formula consists of the chemical symbols for the constituent elements followed by numeric subscripts. The numeric subscripts only tell us the number of atoms of the constituent elements

[tex]\begin{gathered} _{}_{}_{}_{} \\ \text{ Molecular formula of water} \\ H_2O\text{ } \\ \text{The constistuent elements are hydrogen and oxygen} \\ \text{Water has 2 atoms of hydrogen and 1 atom of oxygen} \end{gathered}[/tex]

Molecular mass of water can be calculated as follows

H2O

The molar mass of hydrogen is 1

The molar mass of oxygen is 16

Since water has two atoms of hydrogen and 1 atom of oxygen

Molecular mass of water = 2(1) + 1(16)

Molecular mass of water = 2 + 16

Molecular mass of water = 18g/mol

Hence, the molecular mass of water is 18g/mol

Complete the second row of the table.Express the volume in liters to three significant figures.

Answers

In this case you need to use the volume and temperature equation from Charles law.

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

We are given T1 = 139 k

T2= 317 k

V2= 176 L

We want to find V1. Now lets re-arrange the equation.

[tex]V_1=\frac{V_2}{T_2}xT_1[/tex]

V1 = (176 x 139)/317

V1= 77.2 L

Empriical formula for Na=29.1 S=40.5. O=30.4

Answers

Answer:

Na2S2O3.

Explanation:

What is given?

If we suppose that the compound has a mass of 100 g:

Mass of Na = 29.1 g,

Mass of S = 40.5 g,

Mass of O = 30.4 g,

Molar mass of Na = 23 g/mol,

Molar mass of S = 32 g/mol,

Molar mass of O = 16 g/mol.

Step-by-step solution:

First, we have to convert all the given masses of each element to moles using their respective molar mass, like this:

[tex]\begin{gathered} 29.1\text{ g Na}\cdot\frac{1\text{ mol Na}}{23\text{ g Na}}=1.27\text{ mol Na,} \\ \\ 40.5\text{ g S}\cdot\frac{1\text{ mol S}}{32\text{ g }}=1.27\text{ mol S,} \\ \\ 30.4\text{ g O}\cdot\frac{1\text{ mol O}}{16\text{ g O}}=1.9\text{ mol O.} \end{gathered}[/tex]

The next step is to divide each number of moles by the least number of moles obtained, which in this case is 1.27, as follows:

[tex]\begin{gathered} 1.27\text{ mol Na/1.27=1 mol Na,} \\ 1.27\text{ mol S/1.27=1 mol S,} \\ 1.9\text{ mol O/1.27=1.5 mol O.} \end{gathered}[/tex]

Remember that we need to have the number of moles of each element as integers, so if we multiply each number of moles of each element by 2, we will obtain:

[tex]\begin{gathered} 1\text{ mol Na}\cdot2=2\text{ mol Na,} \\ 1\text{ mol S}\cdot2=2\text{ mol S,} \\ 1.5\text{ mol O}\cdot2=3\text{ mol O.} \end{gathered}[/tex]

We would have 2 mol of Na, 2 mol of S, and 3 mol of O, so the empirical formula is Na2S2O3

Three students (A, B, and C) are asked to determine the volume of a sample of water. Each student measures the volume three times with a graduated cylinder. The results in milliliters are: A (87.1, 88.2, 87.6); B (86.9, 87.1, 87.2); C (87.6, 87.8, 87.9). The true volume is 87.0 mL. Comment on the precision and the accuracy of each student’s results. aStudent A has results that are neither precise nor accurate. bStudent B has results that are both precise and accurate. cStudent C has results that are precise but not accurate. dStudent A has results that are precise and accurate. eStudent B has results that are neither precise and accurate. fStudent C has results that are accurate but not precise.

Answers

Answer:

a. Student A has results that are neither precise nor accurate.

b. Student B has results that are both precise and accurate.

c. Student C has results that are precise but not accurate.

Explanation:

First, let's remember the concepts of accuracy and precision:

Accuracy is a measure of how close a measurement is to the correct or accepted value of the quantity being measured.

Precision is a measure of how close a series of measurements are to one another.

You can see this better in the following picture:

Based on this logic, you can note that:

- The results of Student A are not accurate and are not precise.

- The results of Student B are very close to each other which is precise and in turn, they are close to the real value which is very accurate.

- The results of Student C are very close to each other which is precise but it isn't close to the real value, so it isn't accurate.

The answers would be:

a. Student A has results that are neither precise nor accurate.

b. Student B has results that are both precise and accurate.

c. Student C has results that are precise but not accurate.

what volume will 2.0 moles of hydrogen occupy at STP?

Answers

In this question, at STP (standard temperature and pressure) it is conventional to assume that 1 mol of a substance is equal to 22.4 Liters of volume, therefore, if we have 2 moles of Hydrogen gas:

1 mol H2 = 22.4 L

2 moles H2 = x L

x = 44.8 Liters of volume

why is boiling point of vegetable oil higher than boiling point of maple syrup?

Answers

Firstly, what you need to understand is that boiling points reflect the intermolecular attractive forces within the sustance.

The stronger the intermolecular forces, the lower the vapor pressure of the substance and the higher the boiling point.

In this case, vegetable oil has stronger intermolecular forces, these forces are difficult to break, which then leads to increased/higher temperatures needed to break them. That is why vegetable oil has a boiling point of approximately 300 degrees celsius.

Maple syrup has a lower boiling point because its intermolecular forces are less stronger compared to vegetable oil. Not a lot of energy is required to break the intermolecular bonds, thus lower boiling temperature.

reaction of alkanes with potassium permanganate solution​

Answers

Alkanes are paraffins and that means they don't react a lot. SO when potassium permanganate solution is introduced to alkanes, it will not react with KMnO4 & the pink color of the solution shall persist as there is no change in the reaction.

Alkanes do not react with potassium permanganate solution.

Alkanes are the least reactive type of compound. Alkanes are saturated hydrocarbons that are slightly stable due to the presence of only single bonds. Double bonds are absent in them. Two important reactions they undergo are combustion, which is the reaction with oxygen and halogenation, and which is the reaction with halogens. Potassium permanganate is a potent oxidizing agent that dissolves in water to give the purple solution.

Alkanes do not react with potassium permanganate solution because potassium permanganate is an oxidizer and alkanes have no functional groups such as double bonds that can be further oxidized. Thus, alkanes do not react with potassium permanganate.

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Carbon dioxide and water react to form methane oxygen like this: CO2(g)+2H2O(g)——>CH4(g)+2O2(g)The reaction is endothermic. How was the mixture of CO2, H2O, CH four and O2 has come to equilibrium in a closed reaction vessel. Predict that changed, if any, the perturbations In the table below will cause In the Composition Of the mixture in the vessel. Also decide whether the equilibrium shifts to the right or left.Perturbation: The temperature is raisedChange in composition:Pressure in the H20 will?Go up, go down, not change.Shift in equilibrium:To the right, to the left, none.Perturbation:The temperature is loweredChange in the composition:The pressure of the CH4 will?Go up, go down, not change.Shift in equilibrium:To the right, to the left, none.

Answers

ANSWER

An increased temperature will shift the equilibrium to the right and the pressure of water will be decreased.

A decreased in temperature will shift the equilibrium to the left and the pressure of the

STEP-BY-STEP EXPLANATION:

Firstly, we need to write out the balanced equation of the chemical equation.

[tex]CO_{2(g)}+2H_2O_{(g)}\rightarrow CH_{4_{((g)}}+2O_{2(g)}[/tex]

What is chemical equilibrium?

Chemical equilibrium is the condition in the course of a reversible chemical reaction in which no net change in the amounts of reactant and products occurs.

According to the balanced equation, it shows that the reaction is an endothermic reaction. This means that heat was absorbed from the surroundings during the reaction.

To study the change in the equilibrium shift, we need to apply Le Chatelier's principle.

Le Chatelier's principle states that when an external constraint such as (temperature, pressure, or concentration) is imposed on a chemical system in equilibrium, the equilibrium of the system shift in order to annul or neutralize the effect of the constraints.

When the temperature of the chemical system is increased, the products side of the system will be favored. This is because an increase in temperature will lead to a faster collision between the two reactants, hence, producing more methane. Therefore, the equilibrium will shift to the left.

When the temperature is increased, the equilibrium will shift to the right.

The pressure of water will be decreased when the temperature is increased. This is because has no effect on the equilibrium system

When the temperature is lowered, the reactants side is favored and the equilibrium will shift to the left.

Looking at the balanced equation critically, the number of moles at the reactant side is equal to the number of moles at the sides of the product.

When the temperature is lowered, the pressure of methane gas will be decreased

Name each of the following Acids and BasesH3PO3

Answers

So,

The compound:

[tex]H_3PO_3[/tex]

Can be called as:

Phosphorous acid

REACTION; C5H12 + 8O2 5CO2 + 6H2OWhen 2.50 moles of C5H12 react with 12.0 moles of O2, what is the maximum amount of H2O that can be produced in moles?

Answers

The first thing we do is to verify that the equation is balanced. We are going to count the atoms of each element on each side of the reaction.

Reagents side:

Carbon (C) = 5 atoms.

Hydrogen (H) = 12 atoms.

Oxygen (O) = 16 atoms.

Products side:

Carbon (C) = 5 atoms.

Hydrogen (H) = 12 atoms.

Oxygen (O) =16 atoms.

We have the same number of atoms on both sides of the reaction. So, the reaction is balanced. Now, we must determine which is the limiting reagent.

For each mole of C5H12 that reacts, 8 moles of oxygen are needed and 5 moles of CO2 and 6 moles of H2O are produced.

So, if we have 2.5 moles of C5H12 we will need:

Moles of O2 = 2.5 moles of C5H12 x 8 = 20 moles of oxygen.

We only have 12 moles of oxygen, we don't have enough moles to react to 2.5 moles of C5H12. So oxygen is the limiting reagent. So we will calculate based on the number of moles of oxygen.

So, for every 8 moles of oxygen 1 mole of C5H12 reacts, if we have 12 moles of the oxygen we divide this amount by 8 to know how many moles of C5H12 react.

Moles of C5H12 that reacts = 12 moles of oxygen / 8 = 1.5 moles of C5H12

For each mole of C5H12 6 moles of H2O are produced. So the number of moles produced will be:

Moles of H2O produced= 1.5 moles of C5H12 x 6 = 9 moles of H2O

So, the maximum amount of H2O that can be produced is 9 moles.

What is the value of the equilibrium constant / Kc?

Answers

answer and explanation

in order to determine the equilibrium constant we have to use the ICE method

the initial concentration of PCl5 is given as 0.300M and at this stage, the concentration of PCl3 and Cl2 are zero

the equilibrium constant is 0.5

The correctly drawn Lewis structure for CH2CH2 will have ____1. 4 single bonds to carbon2. 2 single bonds to carbon and 1 double bond to a carbon3. 2 single bonds to carbon and 1 singic bond to hydrogen4. 3 single bonds to carbon and 1 single bonds to a carbon5. 2 single bonds to carbon and 2 double bonds to carbon

Answers

Answer:

[tex]2\text{ : 2 single bonds to carbon and 1 double bond to a carbon}[/tex]

Explanation:

Here, we want to describe the correct Lewis diagram for the molecule

For the molecule, we will have a double bond between the two central carbon atoms. Then, we will have 2 single bonds from each carbon atom to the hydrogen atoms.

Thus, the correct answer choice here is 2 single bonds to carbon and 1 double bond to a carbon

The correctly drawn Lewis structure for CH₂CH₂ will have 2 single bonds to carbon and one double bond to carbon. Therefore, the correct option is option 2.

A Lewis structure is a representation of a molecule or ion that shows the arrangement of atoms, the bonding between them, and the distribution of valence electrons. It is a simplified way to visualize the electronic structure of a compound.

In a Lewis structure, atoms are represented by their chemical symbols, and valence electrons are represented as dots or lines. Dots are placed around the atomic symbols to indicate non-bonding electrons, and lines represent covalent bonds between atoms. Lewis structures help in understanding the bonding and molecular geometry of a compound, as well as predicting its chemical behavior.

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In this set of chemical reactions, which is a singlereplacement reaction?Pb(NO3)2(aq) + 2NaCl(aq) → PbCl2(s) + 2NaNO3(aq)CuSO4(aq) + BaCl2(aq) → BaSO4(s) + CuCl2(aq)K2504(aq) + BaCl2(aq) → BaSO4(s) + 2Cl(aq)AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)

Answers

ANSWER

[tex]\begin{gathered} \text{ Zn}_{(s)}+\text{ H}_2SO_{4(aq)}\rightarrow\text{ ZnSO}_{4(aq)}\text{ + H}_{2(g)} \\ \text{ option D} \end{gathered}[/tex]

EXPLANATION:

A single replacement reaction is also called a single displacement reaction.

A single replacement reaction is a type of reaction where one element is substituted for another element in a compound during a chemical reaction.

Below reaction is an example of a single replacement reaction

[tex]\text{ A + BC }\rightarrow\text{ B + AC}[/tex]

From the given options, you will see that the reaction between Zn and H2SO4 is a single replacement reaction

Zn will displace H2 because it is more reactive than hydrogen

Hence, the correct option is D

If 8.54 g of CuNO3 is dissolved in water to make a 0.520 M solution, what is the volume of the solution in milliliters?

Answers

For solving this exercise we need the molar mass of CuNO3 which is 125.5 g/mol

Step 1) We calculate the moles of this compound:

8.54 g CuNO3 / 125.5 g/mol = 0.0680 moles CuNO3

Step 2) We calculate the volume of the solution in L:

(Remember M is equal to mol/L)

0.0680 moles CuNO3 / 0.520 mol/L = 0.131 L

Step 3) We change L to mL:

(Remember 1L=1000mL)

0.131 L x (1000mL/1L) = 131 mL

Answer: Volume = 131 mL

According to the phase diagram for H₂O, what happens to the phases ofwater at 0.5 atm pressure as the temperature is decreased from 110°C to -10°C?A) water changes from a gas to a solid to a liquidB) Water changes from a solid to a liquid to a gasC) water changes from a liquid to a gas to a solidD) water changes from a gas to a liquid to a solid

Answers

Answer:

[tex]D[/tex]

Explanation:

Here, we want to get what happens to the phases of water as the temperature is decreased at 5 atm

From what we have in the question, we would be moving from left to right

What would happen here is that we move from the gaseous state to the liquid and then to the ice state

This means we have a change from a gas to a liquid then a solid

Density is the ratio of a substance's _______ to its volume.Question options:A) weightB) forceC) thicknessD) mass

Answers

Answer

D) mass

Explanation

The density of a substance is a ratio of its mass to volume.

Therefore, density is the ratio of a substance's mass to its volume.

The correct answer is option D) mass

Imagine you are a chef. You must make a lunch that does not involve any chemical changes in the preparation. Name three foods or drinks you will serve, and describe what physical changes you will use to prepare them.

Answers

So,

First of all, let's remember what physical and chemical changes are.

A physical change occurs when there's changes in the size or shape of matter. Changes of state, for example, from solid to liquid or from liquid to gas, are also physical changes. In this kind of change, the composition of the matter doesn't change.

A chemical change occurs when a substance combines with another to form a new substance, and the composition of the matter changes.

Now that we know what these changes are, we could give some examples of a physical change in cooking, for example:

1. Suppose we want to serve a freezed drink, like a popsicle. For this, we could freeze a fruit juice. This is a physical change because the composition of the juice changes from liquid to solid.

2. Suppose we want to serve pasta. We need to boil the pasta to make it soft, which is a physical change clearly.

3. Suppose we want to serve meat but this is freezed, so, we need to thaw it to start cooking, which is a physical change.

What is the pH of 5.43 M solution of potassium trifluoroacetate KC2F302) at 25 C?

Answers

Potassium trifluoroacetate is the salt of a weak acid (trifluoroacetic acid) and a strong base (potassium hydroxide). In water it will dissociate into its ions.

KC₂F₃O₂ ------> K⁺ + C₂F₃O₂⁻

The trifluoroacetate ion is the conjugate base of a weak acid:

C₂F₃O₂⁻ + H₂O <-----> C₂F₃O₂H + OH⁻

The dissociation constant of this conjugate base will be:

Kb = [C₂F₃O₂H] * [OH⁻]/[C₂F₃O₂⁻]

I searched for the value of the Ka for the trifluoroacetatic acid. With this value we can find the Kb for the trifluoroacetate.

Ka = 1

Ka * Kb = 1 * 10^(-14)

Kb = 1 * 10^(-14)/1

Kb = 1 * 10^(-14)

So first we will have to find the concentration of OH⁻ and then we will be able to find the concentration of H+ and finally the pH.

We have to use the ICE table.

C₂F₃O₂⁻ + H₂O <-----> C₂F₃O₂H + OH⁻

I 5.43 0 0

C -x +x +x

E 5.43 - x x x

The initial concentration of the trifluoroacetate ion is 5.43, then some moles of it will convert into moles of C₂F₃O₂H and OH⁻. And finally we found the equilibrium concentrations that we can replace of the expression of the Kb.

Kb = [C₂F₃O₂H] * [OH⁻]/[C₂F₃O₂⁻]

Kb = x * x /(5.43 - x)

Kb = x²/(5.43 - x)

We can replace the Kb for the value that we found and solve this quadratic equation for x.

1 * 10^(-14) = x²/(5.43 - x)

1 * 10^(-14) * (5.43 - x) = x²

x² + 1 * 10^(-14) x - 5.43 * 10^(-14) = 0

This quadratic equation has two roots. We will use the positive one since it is a concentration.

x₁ = 2.33 * 10^(-7) x₂ = - 2.33 * 10^(-7)

The concentration of OH- in the equilibrium is x. We can determine the pOH.

[OH-]eq = x₁

[OH-]eq = 2.33 * 10^(-7)

pOH = - log [OH-]

pOH = - log (2.33 * 10^(-7))

pOH = 6.63

Finally we can find the pH using that value:

pH + pOH = 14

pH = 14 - pOH = 14 - 6.63

pH = 7.37

Answer: the pH of a 5.43 M solution of potassium trifluoroacetate is 7.37 supposing that ka of trifluoroacetic acid is 1.

Do structural isomers have the same number of Carbon atoms?

Answers

Structural isomers have the same formula, but they have different bonds, that's why they can have the same number of carbon atoms.

What is the percent of H inNH3?(H = 1.008 amu, N = 14.01 amu)=

Answers

In order to find the percentage of an element within a compound, we need to have the mass for this element and also the mass of the whole compound, and the masses are:

H = 1.008 g/mol or amu

and we have 3 H in the compound, therefore = 3.024 g/mol or amu

NH3 = 17.031 g/mol

Now we know that 17.031 is the total mass, so we will call it 100%

17.031 g/mol = 100%

3.024 g/mol = x %

x = 17.75% of H in NH3

Is the following statement about our solar system true or false?
Mercury orbits the Sun at more than four times the speed of Saturn.

Answers

The speed of Mercury around the sun is 47 Km/s while the speed of Saturn around the sun is 9.69 Km/s. Therefore, Mercury orbits the Sun at a speed more than four times the speed of Saturn. Therefore, the given statement is true.

What is planet Mercury?

Mercury can be described as the smallest planet in the Solar System and also the closest to the Sun. Mercury orbits around the Sun and takes 88 Earth days. Mercury rotates in a unique way in the Solar System as it is tidally locked with the Sun in a 3 : 2 spin-orbit resonance.

Mercury can be described as a rocky body like Earth with an equatorial radius of 2,439.7 kilometers. Mercury contains approximately 70% metallic and 30% silicate material.

Saturn is the second-largest and the sixth planet from the sun in the Solar System, after Jupiter. Saturn is a gas giant with a radius of about nine and a half times that of Earth. The speed of Mercury orbits the Sun is more than four times the speed of Saturn.

Learn more about Mercury planet, here:

https://brainly.com/question/17575132

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