The number of ways which he can choose 4 courses if more than 2 must be science is; 224 ways.
Combination of outcomes;
He can choose from 4 humanities courses and 8 science courses.
If the condition requires that he chooses more than 2 science courses, it follows that;
He can only choose three science courses and only 1 humanities courses.
8C3 x 4C1 = 56x 4 = 224
On this note, the number of ways he can choose the required 4 courses is; 224 ways.
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Victor normally sells roadside cashews for $12 per pound and his roadside stands today is discounting the price 25% if Carla buys 2 3/4 pounds of roasted cashews at the Discounted price how much will she pay
Victor sells roadside cashews for $12 per pound.
Today, the price is discounted by 25%. The discount is
25% of $12 = 25/100*$12 = $3
Thus the discounted price is $12 - $3 = $9 per pound
Carla buys 2 3/4 pounds of roasted cashews at that discounted price, thus she will pay:
$9 * 2 3/4
Expressing 2 3/4 as a single fraction:
2 3/4 = 2 + 3/4 = (8+3)/4 = 11/4
Carla will pay:
$9 * 11/4 = $24.75
Carla will pay $24.75
What is the value of x? ? 21 21 Drawing not to scale 78 156 D787
We can find the value of x, by using the property of issoceles triangle:
A isosceles triangle is a triangle that has two sides of equal length.
In the given figure, triangle have two sides of equal length 21, thus the given triangle is issoceles.
Since, the angle opposite to the equal sides are equal,
so, the third angle of the given triangle is x
The sum of all angles in a triangle is equal to 180 degrees.
In the given figure : x, x & 34
[tex]\begin{gathered} x\text{ + x +34=180} \\ 2x+34=180 \\ 2x=180-34 \\ 2x=146 \\ x=\frac{146}{2} \\ x=73 \end{gathered}[/tex]So, x = 73º
Answer: D) 73º
Multiply the following polynomials. Once simplified, name the resulting polynomial. (3x^2 - 4) (5x - 6)name:
Cubic
Explanation:(3x² - 4) (5x - 6)
= 3x²(5x - 6) - 4(5x - 6)
Multiplication of same sign gives positive number. Multiplication of opposite signs give negative number.
= 15x³ - 18x² - 20x + 24
Naming polynomial base on the number of terms:
There are 4 terms in the polynomial above
4 terms is named polynomial of 4 terms
Naming by degree:
The highest degree (exponent) = 3
Polynomial with degree 3 is called cubic
So we can name the polynomial as cubic
Let f(x)=x^2 and g(x)=x-3. Find (f o g)(-5)
Solution
Given that
[tex]\begin{gathered} f(x)=x^2 \\ \\ g(x)=x-3 \\ \\ \Rightarrow(f\circ g)(-5)=f(g(-5)) \\ \\ g(-5)=-5-3=-8 \\ \\ \Rightarrow f(g(-5))=f(-8) \\ \\ f(-8)=(-8)^2=64 \\ \\ \Rightarrow(f\circ g)(-5)=64 \end{gathered}[/tex]There are 28 students in a homeroom. How may différent ways can they be chosen tobe elected President, Vice President, Treasurer, and Secretary?
There are 28 students in a homeroom. How many différent ways can they be chosen to be elected President, Vice President, Treasurer, and Secretary?
In this problem, we have a permutation
so
Find out 28P4
[tex]28P4=\frac{28!}{(28-4)!}[/tex]28P4=491,400
therefore
the answer is 491,400The letters S, E, M, I, T, R, O, P, I, C, A, and L are written on pieces of paper and placed in a hat. Without looking, you draw one letter. Find the probability of drawing a consonant.
Answer:
P = 7/12
Explanation:
There are 12 letters in the hat and 7 of them (S, M, T, R, P, C, L) are consonants. The probability of drawing a consonant is the ratio of the number of consonants to the total number of letters, so the probability is
P = 7/12
During a probability experiment, Jesse draws one marble each from two different jars and records the result. She then places the marbles back in their respective jars and repeats the experiment for a total of 10 trials. On her first trial, Jesse pulls a blue marble from the first far and a green marble from the second jar, and the results are indicated as BG. The results are shown in the table, where B stands for blue, G stands for green, and R stands for red. Trial 1 2 3 4 5 6 7 8 9 10 Result BG RB RR BG RG BB GG BR GB RR Based on the results in the table, what is the experimental probability of pulling a red marble from the first jar and a green marble from the second jar (RG) ? 1 A. 5 B. 1 6 Ос. 1 OD 1 1 10
SOLUTION AND EXPLANATION OF CONCEPT
From the table in the question, the result for Red in the first jar and green in the second trials (RG) occurs in the fifth trials
The formular for probability is give as
[tex]Pr(E)=\frac{required\text{ outcome}}{total\text{ outcome}}[/tex][tex]Pr(RG)=\frac{Number\text{ of trials for RG}}{Total\text{ number ot Trials}}=\frac{1}{10}[/tex]Hence the probability of red in the fir
Linear function ху 60 10-8 The values in the table represent a linear function. How does the value of y change in relation to a change in the value of x? A) for every change in x by-2, y changes by 4 B) for every change in x by 2, y changes by-4 C) for every change in x by -4, y changes by -2 D) for every change in x by -2, y changes by -4
Here, we want to get how the value of y change relative to a change in value of x
Create a box and whisker plot (Label everything!!)
Solution
We have the following data:
11,16,11,15,9,10,11,13,15,17,10,14,17,10,13,15,11,12,12,11,12,14,15,15,13,10,15,12,11
We can calculate the median and the respective quartiles so we need to sort the data and we have:
9 10 10 10 10 11 11 11 11 11 11 12 12 12 12 13 13 13 14 14 15 15 15 15 15 15 16 17 17
Then we have:
Min = 9
Q1 = 11
Median = 12
Q3= 15
Max = 17
And then we can create the boxplot and we got:
AABC is isosceles.mZA = 3x + 40 and mZC = x + 50BAmZA= [ ? 1°
ANSWER:
The value of the angle A is 55°
STEP-BY-STEP EXPLANATION:
Angles opposite equal sides are angles that are also equal.
Therefore, in this case A and C are equal angles, therefore we can do the following equation:
[tex]\begin{gathered} A=C \\ 3x+40=x+50 \end{gathered}[/tex]Solving for x:
[tex]\begin{gathered} 3x-x=50-40 \\ 2x=10 \\ x=\frac{10}{2} \\ x=5 \end{gathered}[/tex]Now we replace the value of x, in A and we are left with:
[tex]\begin{gathered} A=3\cdot5+40 \\ A=15+40 \\ A=55 \end{gathered}[/tex]Can someone explain this to me please thank you !!
The figure can be drawn as,
From the triangle ABC,
[tex]\begin{gathered} \sin 70=\frac{AB}{AC} \\ \sin 70=\frac{h}{400ft} \\ h=400\sin 70ft \\ h=375.87ft \\ \approx376ft \end{gathered}[/tex]Thus, the required value of height is 376 ft.
In parallelogram DEFG, DE=6 Inches and DF= 6.4 Inches. Diagonals GE and DF Intersect at point H. If GH=4 inches, what is the length of GE?
SOLUTION
Consider the figure below:
It is given that the diagonals DF and GE intersects at H
Recall that the daigonals of parallelogram bisect each other
It follows:
[tex]GH=HE[/tex]Since it is given that GH=4, it follows:
[tex]HE=4[/tex]Using segment addition postulate, it follows:
[tex]\begin{gathered} GE=GH+HE \\ GE=4+4 \\ GE=8 \end{gathered}[/tex]Therefore the required answer is GE=8 inches
On the math test last week,Jacob got 85% of the questions correct. How can this be percent be written as a fraction ?
The number in percent can be expressed as the fraction of 100. So 85% can be expressed as,
[tex]\begin{gathered} \frac{85}{100}=\frac{17\cdot5}{20\cdot5} \\ =\frac{17}{20} \end{gathered}[/tex]85% is expressed as 17/20 in fraction.
Answer: 17/20
Answer:
85/100 = 17/20
Step-by-step explanation: In general, 85% is 85/100, but we can shorten that to an easier answer like 17/20.
what would be the best first step in solving this system x^2 - 3x + 2y = -4 y = 3x + 2A. isolate x in the first equationB. substitute for y in the first equationc. substitute for x in the second equationD.n isolate x in the second equation
Explanation
we are asked to solve the system of equations:
[tex]\begin{gathered} x^2-3x+2y=-4 \\ y=3x+2 \end{gathered}[/tex]The first step in getting the solution to this will be to substitute for y = 3x +2 in the first equation
Therefore, option B is correct
A randomly generated list of numbers from 0 to 4 is being used to simulatean event, with the number 4 representing a success. What is the estimatedprobability of a success?A. 20%B. 75%C. 25%D. 80%
Given:
A randomly generated list of numbers from 0 to 4 is being used to simulate an event, with the number 4 representing success.
Required:
What is the estimated probability of success.
Explanation:
The probability is
[tex]=\frac{\text{ Number of favorable cases}}{\text{ Total number of cases}}[/tex]0, 1, 2, 3, 4, 5 are choices.
Favorable case is number 4.
So, probability
[tex]\begin{gathered} =\frac{1}{5} \\ =0.2 \\ =20\% \end{gathered}[/tex]Answer:
Option A is correct.
Algebra1B CP identify a nonviable solution and explain why it is nonviable within the context of the problem
SOLUTION
Step 1 : Attached is the graph that shows the solutions of the two equations:
Step 2: We need the get the values of x and y in the two sets of the equations.
[tex]\begin{gathered} x\text{ + 2y }\leq\text{ 500 --equ 1 multiplied by 3 = 3 x + 6y }\leq\text{ 1500 ---equ 3} \\ 3x\text{ + 4y }\leq\text{ 1200 ---- equ 2} \\ \text{equ 3 minus equ 2, we have that :} \\ 6y\text{ - 4y }\leq\text{ }1500\text{ - 1200} \\ 2y\text{ }\leq\text{ 300} \\ \text{Divide both sides by 2 , we have that:} \\ y\text{ }\leq150 \\ \text{put y }\leq\text{ 150 in equ 1, } \\ x\text{ + 2y }\leq\text{ 500} \\ x\text{ + 2 (150 ) }\leq\text{ 500} \\ x\text{ + 300 }\leq\text{ 150} \\ x\text{ }\leq\text{ 500 - 300} \\ x\text{ }\leq\text{ 200} \end{gathered}[/tex]CONCLUSION: It means that the number of shirts, x = 200
while the number of pyjamas , y = 150
Sally's wallet contains• 5 quarters• 3 dimes• 8 nickels• 4 penniesSally will randomly choose a coin, replace it, and randomly choose another coin. What is teh probability thatshe will choose a dime and then a quater?
Sally's wallet contains the following coins
Quarters = 5
Dimes = 3
Nickels = 8
Pennies = 4
What is the probability that she will choose a dime and then a quarter?
Recall that the probability of an event is given by
[tex]P=\frac{\text{number of favorable outcomes}}{\text{total number of outcomes}}[/tex]The probability that she will choose a dime is given by
[tex]P(dime)=\frac{3}{5+3+8+4}=\frac{3}{20}[/tex]The probability that she will choose a quarter is given by
(note that replacement is allowed so the total number of coins remains the same)
[tex]P(quarter)=\frac{5}{5+3+8+4}=\frac{5}{20}=\frac{1}{4}[/tex]So, the probability that she will choose a dime and then a quarter is
[tex]\begin{gathered} P(dime\: and\: quarter)=P(dime)\times P(quarter) \\ P(dime\: and\: quarter)=\frac{3}{20}\times\frac{1}{4} \\ P(dime\: and\: quarter)=\frac{3}{80} \end{gathered}[/tex]Therefore, the probability that she will choose a dime and then a quarter is 3/80
Find X and y intercepts 7x+10y=40
To find the intercept of the function on the x-axis, replace y = 0 and solve for x:
[tex]\begin{gathered} y=0 \\ 7x+10y=40 \\ 7x+10(0)=40 \\ 7x+0=40 \\ 7x=40 \\ \text{ Divide by 7 from both sides of the equation} \\ \frac{7x}{7}=\frac{40}{7} \\ x=\frac{40}{7} \end{gathered}[/tex]Therefore, the x-intercept of the function is in the ordered pair:
[tex](\frac{40}{7},0)[/tex]To find the intercept of the function on the y-axis, replace x = 0 and solve for y:
[tex]\begin{gathered} x=0 \\ 7(0)+10y=40 \\ 0+10y=40 \\ 10y=40 \\ \text{ Divide by 10 from both sides of the equation} \\ \frac{10y}{10}=\frac{40}{10} \\ y=4 \end{gathered}[/tex]Therefore, the y-intercept of the function is in the ordered pair:
[tex](0,4)[/tex]I need the work and the right answer and explain what the mistake he made was
The mistake was the inequalities sign that was changed .The inequality sign is not suppose to be greater than or equal to but it should be less than or equal to.
Given the graph of a function f. A) Graph f(x) -3B) Graph f(x+4)C) Graph -f(x)See picture of the graph of function f attached
From the given problem, the figure shows the graph of f(x).
Note that translating the graph in a manner of :
[tex]f(x)+c[/tex]will shift the graph c units upward if the sign is positive or c units downward if the sign is negative.
We are looking for the graph of f(x) - 3
Since the sign is negative, we will shift the grahp 3 units downward, the graph will be like this.
As you can see, the orginal graph intersects at the origin (0, 0). The new graph intersects at (0, -3) since we moved or shifted the graph 3 units downward.
Additional :
If f(x) is translated in a manner of f(x+c), the graph will be shifted c units to the left if c is positive and will be shifted c units to the right if c is negative.
If f(x) is transformed in a manner of -f(x), the graph will reflect over the x-axis.
If the original point is (x, y). It will become (x, -y)
Circle all systems of equations that have NO solutions. A. y = 5 – 3x y = -3x + 4 B. y = 4x – 1 4y = 16x – 4 C. 5x – 2y = 3 10x – 4y = 6 D. 3x + 7y = 42 6x + 14 y = 50 E. y = 5 + 2x y = 5x + 2
To determine if a system of equation have solution you have to determine if the slope (m) is equal or diferent.
If the slope is the same it has NO solution
If the slope is different has a solution
If the equations are equivalents have infinite solutions
To determine the slope the equation must be is the form:
[tex]y=mx+b[/tex]Then
A.
y = 5 – 3x
In this equation the slope is m = -3
y = -3x + 4
In this equation the slope is m= - 3
The system has NO solution
B.
y = 4x – 1
m= 4
4y = 16x – 4
You need to simplify the equation, as follow:
[tex]\frac{4}{4}y=\frac{16}{4}x-\frac{4}{4}[/tex][tex]y=4x-1[/tex]Then the equation are the same it means the system has infinited solutions.
C.
5x – 2y = 3
[tex]-2y=3-5x[/tex][tex]y=-\frac{3}{2}+\frac{5}{2}x[/tex]m= 5/2
10x – 4y = 6
[tex]-4y=6-10x[/tex][tex]y=-\frac{6}{4}+\frac{10}{4}x[/tex]Simplify:
[tex]y=-\frac{3}{2}+\frac{5}{2}x[/tex]Then the equation are the same it means the system has infinited solutions.
D.
3x + 7y = 42
[tex]7y=42-3x[/tex][tex]y=\frac{42}{7}-\frac{3}{7}x[/tex][tex]y=6-\frac{3}{7}x[/tex]m= -3/7
6x + 14 y = 50
[tex]14y=50-6x[/tex][tex]y=\frac{50}{14}-\frac{6}{14}x[/tex][tex]y=\frac{25}{7}-\frac{3}{7}x[/tex]m= -3/7
The system has NO solution
E.
y = 5 + 2x
m= 2
y = 5x + 2
m= 5
The system has one solution
Then the systems that have NO solution are: A and D
Took a pic for better quality, Can you answer as quick as possible, this is due at 9:00, Thanks
The scatter plot represents a group of points that is clearly decreasing at a steady rate, this means that the equation that represents them is a linear equation with negative inclination. A linear equation is given by the following formulla:
[tex]y=m\cdot x+b[/tex]Where m is the inclination and b is the y-intercept. Since the inclination must be negative, the only possible option is A.
Use the rules of exponents to evaluate and simplify the expression. Type all without negative exponents. Make sure “a”and “b” are both in parentheses
We are given the following expression:
[tex](ab)^{-2}[/tex]First, we will use the following property of exponentials:
[tex](xy)^{-c}=x{}^{-c}y^{-c}[/tex]Applying the property we get:
[tex](ab)^{-2}=(a^{-2})(b^{-2})[/tex]Now, we use the following property of exponentials:
[tex]x^{-c}=\frac{1}{x^c}[/tex]Applying the property we get:
[tex](a^{-2})(b^{-2})=\frac{1}{(a^2)(b^2)}=\frac{1}{(ab)^2}[/tex]Since we can't simplify any further this is the final answer.
How do you write 7 square root x^5 in exponential form
Given:
[tex]7(\sqrt[]{x})^5[/tex]To find the exponential form:
[tex]\begin{gathered} 7(\sqrt[]{x})^5=7(x^{\frac{1}{2}})^5 \\ =7x^{\frac{5}{2}} \end{gathered}[/tex]Hence, exponential form is,
[tex]7x^{\frac{5}{2}}[/tex]PLEASE HELP ASAPName all sets to which the number belongs. There may be more thanone answer.Sqaurerootof50
We have to find to which group the square root of 50 belongs.
Not all square roots are irrational, but some are, like the square root of prime numbers.
In this case we have to factorize 50:
[tex]\sqrt{50}=\sqrt{25\cdot2}=\sqrt{25}\cdot\sqrt{2}=5\sqrt{2}[/tex]As we know that the square root of 2 is irrational, a multiple of this has to be irrational.
So the square root of 50 is an irrational number.
Hi I’m looking to get a step by step solution in solving this problem in the red
Given:
[tex]\begin{gathered} f(x)=13x+2 \\ \\ g(x)=3x^2-13 \\ \\ h(x)=\frac{13}{x+13} \end{gathered}[/tex]Find-:
The inverse of a function.
Explanation-:
(a)
For the inverse of a function, x change as y and y change as x and solve for 'y'
[tex]\begin{gathered} f(x)=13x+2 \\ \\ f(y)=13y+2 \\ \\ x\rightarrow y \\ \\ y\rightarrow x \\ \\ \end{gathered}[/tex]Then solve,
[tex]\begin{gathered} y=13x+2 \\ \\ y-2=13x \\ \\ x=\frac{y-2}{13} \end{gathered}[/tex]So, value,
[tex]f^{-1}(y)=\frac{y-2}{13}[/tex](b)
[tex]g(x)=3x^2-13[/tex]So, the value is:
[tex]g(y)=3y^2-13[/tex]The inverse of a function is:
[tex]\begin{gathered} x=3y^2-13 \\ \\ x\rightarrow y \\ \\ y\rightarrow x \\ \\ y=3x^2-13 \\ \\ 3x^2=y+13 \\ \\ x^2=\frac{y+13}{3} \\ \\ x=\sqrt{\frac{y+13}{3}} \end{gathered}[/tex]So, the inverse value is:
[tex]g^{-1}(y)=\sqrt{\frac{y+13}{3}}[/tex](c)
[tex]h(x)=\frac{13}{x+13}[/tex]Value of h(y) is:
[tex]h(y)=\frac{13}{y+13}[/tex]Then solve for inverse function,
[tex]\begin{gathered} x=\frac{13}{y+13} \\ \\ x\rightarrow y \\ \\ y\rightarrow x \\ \\ y=\frac{13}{x+13} \\ \\ y(x+13)=13 \\ \\ x+13=\frac{13}{y} \\ \\ x=\frac{13}{y}-13 \end{gathered}[/tex]So, inverse value is:
[tex]h^{-1}(y)=\frac{13}{y}-13[/tex]
-5x+2=-9x+38 am crying
The given equation is
[tex]-5x+2=-9x+38[/tex]First, we add 9x on each side.
[tex]\begin{gathered} -5x+9x+2=-9x+9x+38 \\ 4x+2=38 \end{gathered}[/tex]Then, we subtract 2 from each side.
[tex]\begin{gathered} 4x+2-2=38-2 \\ 4x=36 \end{gathered}[/tex]At last, we divide the equation by 4.
[tex]\begin{gathered} \frac{4x}{4}=\frac{36}{4} \\ x=9 \end{gathered}[/tex]Hence, the solution is x = 9.Click on ,begin emphasis,all,end emphasis, the factors of the polynomial.
Let's assume that we have a polynomial p(x) with a leading coefficient a and zeros are labelled with letters r. Then its factors have the form:
[tex](x-r)[/tex]Remember that the zeros of a function are the x-values of its x-intercepts i.e. the points where it meets with the x-axis. By looking at the picture you'll notice that the graph of the function intercepts the x-axis at three x values: -3, -1 and 3. Then the factors of this polynomial are:
[tex]\begin{gathered} (x-(-3))=(x+3) \\ (x-(-1))=(x+1) \\ (x-3) \end{gathered}[/tex]AnswerThen the correct options are (x+3), (x-3) and (x+1).
A purse sells for $325. What was the original price of the purse if it is being sold at a 1625% markup?
You have that the price of a purse is $325 with a 16.25% markup.
In order to determine what was the original price of the purse, you consider that the original price minus 16.25% of the unknown original price x is equal to 325.
Consider that the 16.25% of a quantity is simply the multiplication of (16.25/100) for such a quanity.
Then, you have:
x - (16.25/100)x = 325 "original price minus 16.25% of the original price"
calculate the quotient left side:
x - 0.1625x = 325
simplify like terms left side:
0.8375x = 325
divide by 0.8375 both sides:
x = 325/0.8375
x = 388.05
Hence, the original price of the purse was $388.05
Question 8 of 10The diagonal of a TV is 30 inches long. Assuming that this diagonal forms apair of 30-60-90 right triangles, what are the exact length and width of the TV?A. 60 inches by 60/3 inchesB. 15 inches by 15/5 inchesC. 60/2 inches by 600/2 inchesO D. 15.2 inches by 15.2 inches
The diagram of the triangle formed is shown below
The length is BC and the width is AB
To find BC, we would apply the cosine trigonometric ratio which is expressed as
Cos# = adjacent side /hypotenuse
hypotenuse = AC = 30
adjacent side = BC
# = 30
Thus, we have
[tex]\begin{gathered} \text{Cos}30\text{ = }\frac{BC}{30} \\ \text{Note, Cos30 = }\frac{\sqrt[]{3}}{2} \\ We\text{ have} \\ \frac{\sqrt[]{3}}{2}=\text{ }\frac{BC}{30} \\ 2BC\text{ = 30}\sqrt[]{3} \\ BC\text{ = }\frac{30\sqrt[]{3}}{2} \\ BC\text{ = 15}\sqrt[]{3} \end{gathered}[/tex]To find AB, we would apply the sine trigonometric ratio which is expressed as
Sin# = opposite side /hypotenuse
hypotenuse = AC = 30
opposite side = AB
# = 30
Thus, we have
Sin30 = AB/30
Recall, sin30 = 0.5
Thus,
0.5 = AB/30
AB = 30 * 0,5
AB = 15
Thus, the correct option is B