A university class has 29 students: 14 are accounting majors, 9 are business majors, and 6 are history majors. The professor is planning to select two of the students for a demonstration. The first student will be selected at random, and then the second student will be selected at random from the remaining students. What is the probability that the first student selected is an accounting major and the second student is a history major

Answer:

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Step-by-step explanation:

Answer:

$34.51

Step-by-step explanation:

Okay, to find percentage of numbers in problems, all you have to do is multiply 29 by 0.19 to get 5.51, that's the tip

you then add 29 and 5.51 to get $34.51

Explanation:

You can verify this by plugging each root into the equation.

So for instance, plug in x = -2 and we get

f(x) = -3*(x+2)*(x-sqrt(3))*(x-4)

f(-2) = -3*(-2+2)*(-2-sqrt(3))*(-2-4)

f(-2) = -3*(0)*(-2-sqrt(3))*(-2-4)

f(-2) = 0

This verifies x = -2 is a root.

All that matters is that zero buried in there in the second to last step. Multiplying 0 by anything leads to 0. The other roots are verified in the same manner. The -3 out front is the leading coefficient.

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Extra info:

Answer:

The second one

Step-by-step explanation:

Answer:

Is the third one,as you can see it goes thru the point (2,5)

Step-by-step explanation:

Answer:

19.1

Step-by-step explanation:

i took the testttttt

Perimeter is the sum of the length of the sides used to make the given figure. The perimeter of the given shape is 19.1 units.

The distance or length of any line on the graph,

[tex]{\rm Distance} = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]

where,

d = distance or length of the line between points 1 and 2,

(x₁ , y₁) = coordinate of point 1,

(x₂ , y₂) = coordinate of point 2,

To find the perimeter of the given figure we need to calculate the length of each line segment on the given graph. Therefore, the length of the different sides of the given quadrilateral can be written as,

AB = √[(5-0)²+(-1-0)²] = √26 units

BC = √[(5-3)²+(-1+5)²] = √20 units

CD = √[(3+2)²+(-5+4)²] = √26 units

AD = √[(-4 - 0)²+(- 2 - 0)²] = √20 units

Perimeter = AB + BC + CD + AD

                 = √26 units + √20 units + √26 units + √20 units

                 = 19.1423 units ≈ 19.1 units

Hence, the perimeter of the given shape is 19.1 units.

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Answer:

32 cats in total

Step-by-step explanation:

so 18 siamese

the ratio was9:7=siameese:house

18=9 units

divide 9

2=1 unit

house=7 units

7 times 2=14

14 house cats

combined=siameese+house=18+14=32

² = QR² - QT²

= 13² - 5²

= 169 - 25

= 144

TR = √144

TR = 12 cm

Menentukan panjang PR

PR = 2 × TR

= 2 × 12 cm

PR = 24 cm

Answer:

20 banna slices can be cut from a banna

Step-by-step explanation:

8 divided by 0.4 equals 20

Answer:

y = 4; x = 11/4

Step-by-step explanation:

4x - 5y = -9

-4x + y = -7

Add the two equations to eliminate x:

-4y = -16

-4y/-4 = -16/-4

y = 4

Plug in y for x

4x - 5y = -9

4x - 5(4) = -9

4x - 20 = -9

4x = -9 + 20

4x = 11

4x/4 = 11/4

x = 11/4

Answer from Gauthmath

Answer:

4000

Step-by-step explanation:

36kg = 36000g

36000g/9 bags = 4000g

The weight of one bag of potatoes is 4 Kg,

The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.

For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

Given:

The total weight of 9 bags of potatoes is 36 kilograms.

Then, weight of one bag of Potato is

= 36/9

= 4 Kg

Thus, One bag weigh 4 Kg.

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Answer:

x=-3

Step-by-step explanation:

How?

so the easiest and quickest way to answer these type of questions are to do the opposite.

so -11+8=-3

if you get a question like

3x+2=17

17-2=15

15 divided by 3=5

so x=5

hope that helps

thank you

Answer:

a. Outcomes of A = { (C,C,C) , (D,D,D), (S,S,S) }

b. Outcomes of B = { (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

c. Outcomes of C = { (C,C,C),(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }

d. Outcomes of A⋂C = { (C,C,C) }

e. Outcomes of Sample space = { (C,C,C), (C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S),   (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }

f. Outcomes of A U B = { (C,C,C) , (D,D,D), (S,S,S), (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

g. Outcomes of A⋂[tex]C^{c}[/tex] = { (D,D,D), (S,S,S) }

h. Outcomes of [tex]A^{c}[/tex]⋂C = {(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C)}

i. Events A and C are not mutually exclusive

j. Events B and C are mutually exclusive

Step-by-step explanation:

Given - Three times each day, a quality engineer samples a component

             from a recently manufactured batch and tests it. Each part is

             classified as conforming (suitable for its intended use),  

             downgraded (unsuitable for the intended purpose but usable for  

             another purpose), or scrap (not usable). An experiment consists

             of recording the categories of the three parts tested in a particular

              day.

To find - a. Let A be the event that all the parts fall into the same

                  category. List the outcomes in A.

              b. Let B be the event that there is one part in each category.

                  List the outcomes in B.

              c. Let C be the event that at least two parts are conforming.

                  List the outcomes in C.

              d. List the outcomes in A⋂C

              e. List the 27 outcomes in the sample space.

               f. List the outcomes in A U B.

              g. List the outcomes in A⋂[tex]C^{c}[/tex]

              h. List the outcomes in ⋂C.

              i. Are events A and C mutually exclusive? Explain.

              j. Are events B and C mutually exclusive? Explain.

Proof -

Let

Conforming part = C

Downgraded part = D

Scrap part = S

a.)

Given , Let A be the event that all the parts fall into the same category.

Outcomes of A = { (C,C,C) , (D,D,D), (S,S,S) }

b.)

Given, Let B be the event that there is one part in each category.

Outcomes of B = { (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

c.)

Given,  Let C be the event that at least two parts are conforming.

Outcomes of C = { (C,C,C),(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }

d.)

Outcomes of A⋂C = { (C,C,C) }

e.)

Outcomes of Sample space = { (C,C,C), (C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S),   (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }

f.)

Outcomes of A U B = { (C,C,C) , (D,D,D), (S,S,S), (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

g.)

Outcomes of [tex]C^{c}[/tex]  =  {  (C,D,D), (C,D,S), (C,S,D), (C,S,S), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }

Outcomes of A⋂[tex]C^{c}[/tex] = { (D,D,D), (S,S,S) }

h.)

Outcomes of [tex]A^{c}[/tex] = {(C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C),  (D,D,S), (D,S,C), (D,S,D), (D,S,S),   (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), }

Outcomes of [tex]A^{c}[/tex]⋂C = {(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }

i.)

As we two that Two events A and C are mutually exclusive iff A ∩ C = ∅

Now,

A ∩ C = { (C,C,C) }

⇒Events A and C are not mutually exclusive.

j.)

As we two that Two events B and C are mutually exclusive iff B ∩ C = ∅

Now,

B ∩ C = ∅

⇒Events B and C are mutually exclusive.

The measure of <1 and <2 are  alternate exterior angles

From the given diagram, the horizontal lines are parallel to each other with a transversal.

The alternate angles are formed from the shape formed by a letter Z. From the given diagram, the measure of <1 and <2 are  alternate exterior angles

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Answer:

X= 6.2 + 68 ???

Step-by-step explanation:

I'm not sure that's what I would write in an exam

Answer:

what is the question....?

Answer:

Answer:We need to know the question!!

Answer and Step-by-step explanation:

Twelve times four squared.

This is how you would write the expression in word format.

#teamtrees #PAW (Plant And Water)

Answer:

Twelve times four squared.

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

a:b::c:d

a/b=c/d .......(eq 1)

let a=0.2, b=0.5, c=6, d=x

Not put values in eq 1

0.2/0.5 = 6/a

By cross multiplication we get:

0.2xa = 6x0.5

0.2a = 3

Dividing by 0.2 on both sides we get

0.2a/0.2 = 3/0.2

a = 15

Therefore The fourth proportional is 15

Answer:

7 or -7

Step-by-step explain

This depends on how it works. if we are including negative numbers then an option is -7. If we are going backwards and not including negatives then it would be 7

Answer:

C) 0%

Step-by-step explanation:

Let’s give the square sides equaling 4. The area would equal 16.

Decreasing the top by 75% would make it 1.  Increasing the bottom by 75% makes it 7.

(1+7)/2=4

The height is still four so 4x4=16

No change in area.

Answer:

In a nutshell, [tex]f(x)[/tex] is obtained by applying an horizontal translation on [tex]g(x)[/tex], followed by a vertical translation.

Step-by-step explanation:

Let be [tex]g(x) = x^{3}[/tex] the parent function, [tex]f(x)[/tex] is obtained by applying an horizontal translation on [tex]g(x)[/tex], followed by a vertical translation, that is:

[tex]f(x) = g(x-a)-b,\,a,b\in\mathbb{R}[/tex] (1)

If [tex]a > 0[/tex], then translation is rightwards.

If [tex]b > 0[/tex], then translation in downwars.

If [tex]a = 2[/tex] and [tex]b = 1[/tex], then the resulting function is:

[tex]f(x) = g(x-2)-1[/tex]

[tex]f(x) = (x-2)^{3}-1[/tex] (2)

In a nutshell, [tex]f(x)[/tex] is obtained by applying an horizontal translation on [tex]g(x)[/tex], followed by a vertical translation.

Answer:

1. Trapezoid.

2. Rectangle, Parallelogram

3. Rhombus, Parallelogram

4. Rectangle, Parallelogram, Square

5. No, a figure cannot have more than one parallel side and exactly one parallel side at once.

Step-by-step explanation:

Hope ths helped.

Answer:

16 pi

Step-by-step explanation:

Since 2r is the circumference and the radius is 8, it's 8 x 2 which gives you 16. You don't need to add in the pi since they already gave you at the options.