Given :
Solid 1:
The side of the cube is, a = 8 cm.
Solid 3:
The side of the cube is, b = 4 cm.
The volume of the third cube can be calculate as,
[tex]V=b^3=(4cm)^3=64cm^3[/tex]The volume of first cube is,
[tex]V^{\prime}=a^3=(8cm)^3=512cm^3[/tex]Thus, the ratio can be calculated as,
[tex]\frac{V^{\prime}}{V}=\frac{512}{64}=\frac{8}{1}[/tex]Thus the required ratio is 8:1.
Since the volume is proprtional to the cube of the side, the ratio will also be in the range of cube of the fractional difference between the sides.
(3x-3)
[6(x - 10)] What is the value of x?
what fraction is equivalent to 2/2
Answer:
4/4,6/6 etc
Step-by-step explanation:
multiply both numerator and denominator with the same number
need HELPPPPPPP with
let x be the number that we pick. So the final answer and the pattern is:
[tex]\frac{2(x+4)-6}{2}=(x+4)-3=x+1[/tex]so the pattern is that we get the x+1 if we choose x. so the pattern is to add 1 to the initial number
Express the difference in medians as a multiple of the IQR of EACH dataset.Class A.Class B440506070Height (inches)
From the given box plot, let's express the difference in the medians of the IQR of each data.
Given:
Median of class A = 56
Q1 of class A = 50
Q3 of class A = 58
Median of class B = 52
Q1 of class B = 48
Q3 of class B = 54
Thus, we have:
IQR for class A = Q3 - Q1 = 58 - 50 = 8
IQR for class B = Q3 - Q1 = 54 - 48 = 6
Diffrence in median = 56 - 52 = 4
Thus, to find the expression of the difference in medians as a multiple of IQR of each data, we have:
[tex]\begin{gathered} \text{Difference class A: 4 = 8}\ast n \\ \\ \text{Difference class B: 4 = 6 }\ast n \end{gathered}[/tex]Let's solve for each difference.
Difference class A:
[tex]n=\frac{4}{8}=\frac{1}{2}[/tex]Difference class B:
[tex]n=\frac{4}{6}=\frac{2}{3}[/tex]ANSWER:
[tex]\begin{gathered} \text{CLass A = }\frac{1}{2} \\ \\ \text{Class B = }\frac{2}{3} \end{gathered}[/tex]8 and 7 are like terms true or false
8 and 7 are like terms, because they share the same power of x:
[tex]\begin{gathered} 8x^0\rightarrow8 \\ 7x^0\rightarrow7 \end{gathered}[/tex]Flora has an annual income of $18,500. She has $6,500 withheld asdeductions. What is the amount of each paycheck if she gets paidsemimonthly?a. $500b. $461.54c. $711.54d. $1,000
To calculate the amount of each semimonthly paycheck, we need to find the actual amount of money Flora actually receives annually.
Her income is $18500, but $6500 are deducted. Then:
[tex]18500-6500=12000[/tex]The actual money she receives in one year, after deductions, is $12000.
If she receives semimonthly paychecks, we need to bear in mind that in total she receives 24 paychecks in one year. This considering that semimonthly means that she receives two paychecks in a month.
Then, we just need to divide $12000 by 24 to obtain the amount of each paycheck:
[tex]\frac{12000}{24}=500[/tex]The amount of each paycheck is $500.
The correct answer is option a.
True or False Then need explanation in one paragraph or word
1) True
2) False
3) True
4) False
5) False
Explanations:Domains are indepedent variables for which a function exists while the range are dependent variables for which a function exist.
Foa a given coordinates (x, y), all the sets of first coordinates are the domain while all the sets of second coordinates are the range;
All functions are also known as relations but not all given relations are function.
Based on the explanations above, then;
1) A relation is a set of ordered pairs is TRUE
2) The set of all the first coordinates is called is range is FALSE
3) All functions are relations is TRUE
4) The set of all the second coordinates is called is domain is FALSE
5) All relations are function is FALSE
On New Year's Eve, the probability of a person having a car accident is 0.08. The probability of a person driving while intoxicated is 0.28, and the probability of a person having a car accident while intoxicated is 0.04. What is the probability of a person driving while intoxicated or having a car accident ? A.0.15 B.0.16 C.0.18 D.0.32
Answer:
D. 0.32
Explanation:
The probability of a person driving while intoxicated or having a car accident can be calculated as:
[tex]P=P(\text{Intoxicated)}+P(\text{ Accident) - P(Intoxicated and Accident)}[/tex]So, replacing P(Intoxicated) = 0.28, P(Accident) = 0.08 and P(Intoxicated and Accident) = 0.04, we get
[tex]\begin{gathered} P=0.28+0.08-0.04 \\ P=0.32 \end{gathered}[/tex]Therefore, the answer is
D. 0.32
A line has an x-intercept of 12 and a y-intercept of -4. What is the equation of theline?
A line has an x-intercept of 12 and a y-intercept of -4. What is the equation of the
line?
that means
we have the points
(12,0) and (0,-4)
Find the slope
m=(-4-0)/(0-12)
m=-4/-12
m=1/3
Find teh equation in slope intercept form
y=mx+b
we have
m=1/3
b=-4
therefore
y=(1/3)x-4Find the distance between the points (0, 4) and (-7, -5).Round to the nearest tenthThe distance between them isunits.alm3
the distance between the points is
[tex]d=\sqrt[]{(-5-4)^2+(-7-0)^2}[/tex][tex]\begin{gathered} d=\sqrt[]{(-9)^2+(-7)^2} \\ d=\sqrt[]{81+49} \\ d=\sqrt[]{130} \end{gathered}[/tex][tex]d=11.401[/tex]rounding off to nearest tenth
d = 11.4
Spongebob was trying to fill up Gary's bath with water. He noticed the tub filled up 1 gallon per minute.AContinuousBDiscrete
given data:
Spongebob was trying to fill up Gary's bath with water. He noticed the tub filled up 1 gallon per minute.
to find what kind of data this is.
it is discrete because it is measurable. that is countiuse while countable.
Thus the answer is discrete.
I need help solving this problem any help is appreciated
If we want to solve this problem we first need to list a few properties of trigonometric functions:
[tex]\begin{gathered} \text{cot }\theta=\frac{\cos\theta}{\sin\theta} \\ \sin^2\theta+\cos^2\theta=1 \end{gathered}[/tex]We are told that cot(θ)=1/2. Using the first equation and this data we obtain the following:
[tex]\frac{1}{2}=\frac{\cos\theta}{\sin\theta}[/tex]We multiply both sides and we get an expression for the cosine of θ:
[tex]\begin{gathered} \frac{1}{2}\sin\theta=\frac{\cos\theta}{\sin\theta}\cdot\sin\theta \\ \cos\theta=\frac{1}{2}\sin\theta \end{gathered}[/tex]Now we are going to take the second property I wrote in the begining and replace the cosine of θ with this new expression that we found:
[tex]\begin{gathered} \sin^2\theta+\cos^2\theta=\sin^2\theta+(\frac{1}{2}\sin\theta)^2=1 \\ \sin^2\theta+\frac{1}{4}\sin^2\theta=1 \\ \frac{5}{4}\sin^2\theta=1 \end{gathered}[/tex]We must solve this equation for the sine of θ. We can multiply both sides by 4/5:
[tex]\begin{gathered} \frac{4}{5}\cdot\frac{5}{4}\sin^2\theta=1\cdot\frac{4}{5} \\ \sin^2\theta=\frac{4}{5} \end{gathered}[/tex]And we apply a square root to both sides:
[tex]\begin{gathered} \sqrt{\sin^2\theta}=\sqrt{\frac{4}{5}} \\ |\sin\theta|=\frac{2}{\sqrt{5}} \end{gathered}[/tex]We are told that θ is located in quadrant I which means that its sine is positive. Therefore we get:
[tex]\sin\theta=\frac{2}{\sqrt{5}}[/tex]AnswerThen the answer is 2/√5
You have a set of cards labeled one through ten. Event A is drawing an even card. Event B is drawing a seven or higher. What is the P(A∩B) ?
Hello!
First, let's write the information that we know and then each event:
[tex]Set=\mleft\{1,2,3,4,5,6,7,8,9,10\mright\}[/tex]Event A is drawing an even card:[tex]A=\mleft\lbrace2,4,6,8,10\mright\rbrace[/tex]Event B is drawing a seven or higher:[tex]B=\mleft\lbrace7,8,9,10\mright\rbrace[/tex]When we use the interception symbol (∩), it means that we want to know which numbers are part of both sets simultaneously.
Let's calculate it:
[tex]A\cap B=\mleft\lbrace8,10\mright\rbrace[/tex]Can you please help me out
The bag contains,
Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,
Total marbles (possible outcome) is,
[tex]\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}[/tex]Let P(R) represent the probablity of picking a red marble,
P(G) represent the probability of picking a green marble and,
P(B) represent the probability of picking a blue marble.
Probability , P, is,
[tex]\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}[/tex][tex]\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}[/tex]Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,
That means once a marble is drawn, the total marbles (possible outcome) reduces as well,
[tex]\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}[/tex]Hence, the best option is G.
11. Mr. Garcia uses a cylindrical container to protect his diploma. The dimensions of the cylinder are shown in the diagram. IS cm ------ 10 cm Which measurement is closest to the total surface area of the container in square centimeters?
Given data:
The given figure of cylinder.
The total surface area of the cylinder is,
[tex]\begin{gathered} SA=2\pi r(r+h) \\ =2\pi\frac{d}{2}(\frac{d}{2}+h) \end{gathered}[/tex]Substitute the given values in the above expression.
[tex]undefined[/tex]at work one day, erica recieved 18 packages. speed delivery delivered three times as many as ralphs express, while ralphs express delivered two more than send quick service. how many packages did each service deliver to erica
Answer:
Let the number of packages delivered by Ralph's Express be x.
The number of packages delivered by Speedee Delivery would then be 4x.
The number of packages delivered by Send Quick Package Service would be x-5.
Adding all of these together,
x + 4x + (x - 5) = 6x -5
6x - 5 = 55
6x = 60
x = 10
Hence,
Ralph's Express delivered 10 packages.
Speedee Delivery delivered 40 packages.
Send Quick Package Service delivered 5 packages. Hope this help's you
Step-by-step explanation:
The ratio of boys to girls in our class is 1210
The ratio of boys to girls in our class is 12:10
that means
12 divided by 10
so
12/10
simplify
6/5 or 6:5
Express (5/6x + 4) 2 as trinomial in simplest form (2 is an exponent)
We are given the expression (5/6x + 4)^2 and we are asked to express it as a trinomial in the simplest form.
To do this, we will be using the FOIL method. FOIL stands for First-Outer-Inner-Last.
The product will then be:
[tex]\begin{gathered} (\frac{5}{6}x+4)^2=(\frac{5}{6}x+4)(\frac{5}{6}x+4) \\ \\ (\frac{5}{6}x+4)^2=(\frac{5}{6}x)^2+(\frac{5}{6}x)(4)+(4)(\frac{5}{6}x)+4(4) \\ \\ (\frac{5}{6}x+4)^2=\frac{25}{36}x^2+\frac{10}{3}x+\frac{10}{3}x+16 \\ \\ (\frac{5}{6}x+4)^2=\frac{25}{36}x^2+\frac{20}{3}x+16 \end{gathered}[/tex]So, the final answer is 25/36 x^2 + 20/3 x + 16.
Would lines 4x+3y=52 and 3x-4y=44 be perpendicular parallel or neither? I just need a brief explanation with the answer
Would lines 4x+3y=52 and 3x-4y=44 be perpendicular parallel or neither?
step 1
Find out the slopes of the given lines
4x+3y=52
isolate the variable y
3y=-4x+52
y=-(4/3)x+52/3 ------> m=-4/3
3x-4y=44
4y=3x-44
y=(3/4)x-44/4 ------> m=3/4
step 2
Compare their slopes
m=-4/3 and m=3/4
the slopes are opposite reciprocal
that means
the lines are perpendicularthe number of employees Forrester company of vindication each year by 4% of the company currently k670 employees and this rate continues from the number of employees in 16 years
The expression for number of employee after n year if population, P decreases at rate of r % is,
[tex]p=P(1-\frac{r}{100})^n[/tex]Substitute the values in the formula to determine the population after 16 years.
[tex]undefined[/tex]Bradley rolls two fair 6-sided dice with faces numbered 1 through 6. What is the probability that the sum of her two rolls has an odd number of factors?
Answer:
The probability that the sum of her two rolls has an odd number of factors will be;
[tex]P=\frac{7}{36}[/tex]Explanation:
We want to find the probability that the sum of her two rolls has an odd number of factors.
For the two rolls the total number of possible outcomes is;
[tex]6\times6=36[/tex]Let us list out the possible outcomes of the two rolls;
[tex]\begin{gathered} (\text{outcome)= sum= number of factors of the sum} \\ \mleft(1,1\mright)=2=2\text{ factors} \\ (1,2)=3=2\text{ factors} \\ (1,3)=4=3\text{ factors} \\ (1,4)=5=2\text{ factors} \\ (1,5)=6=4\text{ factors} \\ (1,6)=7=2\text{ factors} \\ \end{gathered}[/tex][tex]\begin{gathered} (2,1)=3=2\text{ factors} \\ (2,2)=4=3\text{ factors} \\ (2,3)=5=2\text{ factors} \\ (2,4)=6=4\text{ factors} \\ (2,5)=7=2\text{ factors} \\ (2,6)=8=4\text{ factors} \end{gathered}[/tex][tex]\begin{gathered} (3,1)=4=3\text{ factors} \\ (3,2)=5=2\text{ factors} \\ (3,3)=6=4\text{ factors} \\ (3,4)=7=2\text{ factors} \\ (3,5)=8=4\text{ factors} \\ (3,6)=9=3\text{ factors} \end{gathered}[/tex][tex]\begin{gathered} (4,1)=5=2\text{ factors} \\ (4,2)=6=4\text{ factors} \\ (4,3)=7=2\text{ factors} \\ (4,4)=8=4\text{ factors} \\ (4,5)=9=3\text{ factors} \\ (4,6)=10=4\text{ factors} \\ \end{gathered}[/tex][tex]\begin{gathered} (5,1)=6=4\text{ factors} \\ (5,2)=7=2\text{ factors} \\ (5,3)=8=4\text{ factors} \\ (5,4)=9=3\text{ factors} \\ (5,5)=10=4\text{ factors} \\ (5,6)=11=2\text{ factors} \end{gathered}[/tex][tex]\begin{gathered} (6,1)=7=2\text{ factors} \\ (6,2)=8=4\text{ factors} \\ (6,3)=9=3\text{ factors} \\ (6,4)=10=4\text{ factors} \\ (6,5)=11=2\text{ factors} \\ (6,6)=12=6\text{ factors} \end{gathered}[/tex]From the listed possible outcomes, the number of oucomes with odd number of factors of the sum is;
[tex]n_A=7[/tex]Total number of possibles outcomes is;
[tex]n_T=36[/tex]The probability that the sum of her two rolls has an odd number of factors will be;
[tex]\begin{gathered} P=\frac{n_A}{n_T}=\frac{7}{36} \\ P=\frac{7}{36} \end{gathered}[/tex]Solve the system: y = 12 + 4x y = -33 - 5x
The equation system is:
[tex]\begin{gathered} y=12+4x \\ y=-33-5x \end{gathered}[/tex]So we can made the equation equal so:
[tex]\begin{gathered} 12+4x=-33-5x \\ 4x+5x=-33-12 \\ 9x=-45 \\ x=-\frac{45}{9} \\ x=-5 \end{gathered}[/tex]Now we can replace the value of x to find y in the first equation so:
[tex]\begin{gathered} y=12+4(-5) \\ y=12-20 \\ y=-8 \end{gathered}[/tex]so the solution is:
[tex](-5,-8)[/tex]upper menu options: 1 3 7 8left menu options: 10 11 12 15
In order to find the amount of blue paint needed, we can write the following rule of three:
[tex]\begin{gathered} \text{green}\to\text{blue} \\ 1\text{ batch}\to2\frac{3}{8}\text{ oz} \\ 5\text{ batches}\to x\text{ oz} \end{gathered}[/tex]First, let's convert the mixed number into an improper fraction:
[tex]2\frac{3}{8}=2+\frac{3}{8}=\frac{16}{8}+\frac{3}{8}=\frac{19}{8}[/tex]From this rule of three, we can write the following equation and solve it for x:
[tex]\begin{gathered} \frac{1}{5}=\frac{\frac{19}{8}}{x} \\ x\cdot1=5\cdot\frac{19}{8} \\ x=\frac{95}{8} \\ x=\frac{88}{8}+\frac{7}{8} \\ x=11+\frac{7}{8} \\ x=11\frac{7}{8} \end{gathered}[/tex]Therefore the upper menu is 7 and the left menu is 11.
find f such that the given conditions are satisfiedf’(x)=x-4, f(2)=-1
Given:
[tex]f^{\prime}\left(x\right)=x-4,\text{ and}f\left(2\right)=-1[/tex]To find:
The correct function.
Explanation:
Let us consider the function given in option D.
[tex]f(x)=\frac{x^2}{2}-4x+5[/tex]Differentiating with respect to x we get,
[tex]\begin{gathered} f^{\prime}(x)=\frac{2x}{2}-4 \\ f^{\prime}(x)=x-4 \end{gathered}[/tex]Substituting x = 2 in the function f(x), we get
[tex]\begin{gathered} f(2)=\frac{2^2}{2}-4(2)+5 \\ =2-8+5 \\ =-6+5 \\ f(2)=-1 \end{gathered}[/tex]Therefore, the given conditions are satisfied.
So, the function is,
[tex]f(x)=\frac{x^{2}}{2}-4x+5[/tex]Final answer: Option D
which expression is equivalent to 7y + 7y?
Evaluate the value of expression.
[tex]7y+7y=14y[/tex]So answer is 14y.
QuestionLet x be a constant. The 5th term of an arithmetic sequence is a5=4x−3. The 9th term of the sequence is a9=12x+9. Find the first term of the sequence. Write your answer in simplest form.
The nth term of an arithmetic sequence is :
[tex]a_n=a_1+d(n-1)[/tex]From the problem, we have :
[tex]\begin{gathered} a_5=4x-3 \\ a_9=12x+9 \end{gathered}[/tex]Substitute a5 and n = 5 :
[tex]\begin{gathered} a_n=a_1+d(n-1) \\ a_5=a_1+d(5-1) \\ 4x-3=a_1+4d \end{gathered}[/tex]Rewrite the equation as d in terms of x and a1 :
[tex]\begin{gathered} 4x-3=a_1+4d \\ 4x-3-a_1=4d \\ d=\frac{4x-3-a_1}{4} \end{gathered}[/tex]Subsitute a9 and n = 9
[tex]\begin{gathered} a_n=a_1+d(n-1) \\ a_9=a_1+d(9-1) \\ 12x+9=a_1+8d \end{gathered}[/tex]Rewrite the equation as d in terms of x and a1 :
[tex]\begin{gathered} 12x+9=a_1+8d \\ 12x+9-a_1=8d \\ d=\frac{12x+9-a_1}{8} \end{gathered}[/tex]Now, equate two equations of d :
[tex]\begin{gathered} \frac{4x-3-a_1}{4}=\frac{12x+9-a_1}{8} \\ 8(4x-3-a_1)=4(12x+9-a_1) \\ 32x-24-8a_1=48x+36-4a_1 \\ 4a_1-8a_1=48x+36-32x+24 \\ -4a_1=16x+60 \\ a_1=-4x-15 \end{gathered}[/tex]The answer is a1 = -4x-15
If the 5th term of an arithmetic sequence is a5=4x−3. The 9th term of the sequence is a9=12x+9. The first term of the sequence is -4x-15
What is Sequence?a sequence is an enumerated collection of objects in which repetitions are allowed and order matters.
The nth term of AP
aₙ=a+(n-1)d..(1)
From give we have,
a₅=4x−3
a₉=12x+9.
Substitute n=5 in (1)
a₅=a+4d
4x-3=a+4d
4d=4x-3-a
d=4x-3-a/4...(2)
Substitute n=9 in (1)
a₉=a+8d
12x+9=a+8d
12x+9-a/8=d..(3)
Equate 2 and 3
4x-3-a/4=12x+9-a/8
8(4x-3-a)=4(12x+9-a)
32x-24-8a=48x+36-4a
32x-24-8a-48x-36+4a=0
-16x-4a-60
-16x-60=4a
a=-4x-15
Hence the first term of the AP sequence is -4x-15
To learn more on Sequence click:
https://brainly.com/question/21961097
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Using the cosine law to determine the measure of we could use _______:
Solution
- The Cosine law is given below as:
[tex]\begin{gathered} Given\text{ }\triangle ABC,\text{ with sides }a,b,c\text{ and angles }\angle A,\angle B,\angle C\text{ such that} \\ a\text{ is opposite }\angle A \\ b\text{ is opposite }\angle B \\ c\text{ is opposite }\angle C \\ \\ \text{ We have:} \\ a^2=b^2+c^2-2(bc)\cos\angle A \end{gathered}[/tex]- We can make [tex]\begin{gathered} a^2=b^2+c^2-2bc\cos\angle A \\ \text{ Subtract }b^2\text{ and }c^2\text{ from both sides} \\ \\ a^2-b^2-c^2=-2bc\cos\angle A \\ \\ \text{ Divide both sides by }-2bc \\ \cos\angle A=\frac{a^2-b^2-c^2}{-2bc} \\ \text{ } \\ \text{ Take the cos inverse of both sides} \\ \\ \therefore\angle A=\cos^{-1}(\frac{a^2-b^2-c^2}{-2bc}) \end{gathered}[/tex]
Final Answer
The answer is
[tex]\operatorname{\angle}A=\cos^{-1}(\frac{a^{2}-b^{2}-c^{2}}{-2bc})\text{ \lparen OPTION C\rparen}[/tex]solve by factoring, by square roots, by completing the square, or using the quadratic formulaSolve for x in the equation belowX^2 −15x+54=0
STEP 1: Identify and Set up.
We have a quadratic equation and are asked to solve, i.e, solve for x. We approach this problem via the factoring method.
We look for two factors of the third term, c that add up to the coefficient of x, favtorise and solve.
STEP 2: Execute
[tex]\begin{gathered} x^2-15x+54=0 \\ \text{the factors are -6 and -9} \\ x^2-9x-6x+54=0 \\ Factorizing\text{ gives us:} \\ x(x-9)-6(x-9)=0 \\ (x-9)(x-6)=0 \\ x\text{ is either 9 or 6} \end{gathered}[/tex]x = 9 and x = 6
find two expressions that are equivalent by the distributive property 42g+2142g+3. 7(6g+3) 7g+7select all that apply42g+217(6g+3)7g+742g+3
the expressions are
42g+21 and 7(6g+3)
because
[tex]\begin{gathered} 7(6g+3) \\ 7\times6g+7\times3 \\ 42g+21 \end{gathered}[/tex]the expressions are equivalents
convert to degrees minutes and seconds54.158°
Convert 54.158 degrees
Firstly, Use the whole number as degree
54 degree
to convert to minutes
(54.548 - 54) x 60
= 0.158 x 60
= 9 minutes
To convert to seconds
(54.158 - 54 - 9/60) x 3600
= (0.158 - 0.15) x 3600
= 0.008 x 3600
= 28.8 seconds
This can be written as
[tex]54^o\text{ 9' 28.8''}[/tex]