A survey of 85 persons was conducted at TCC, and it was found that 54 persons carried a cell phone, 19 persons carried a tablet computer, and 16 carried both a cell phone and a tablet.How many people carried a cell phone or a tablet?How many people carried neither a cell phone nor a tablet?How many people carried a cell phone only?How many people carried a tablet but not a cell phone?

Answers

Answer 1

Answer:

The universal set is given below as

[tex]\xi=85[/tex]

The number of people with cell phone is

[tex]n(C)=54[/tex]

The number of persons with tablet is

[tex]n(T)=19[/tex]

The number of people who carry both cellphone and tablet

[tex]n(C\cap T)=16[/tex]

Step 1:

To figure our the number of students that carry cellphone or tablets will be

[tex]\begin{gathered} =38+16+3 \\ =57\text{ }people \end{gathered}[/tex]

Hence,

The number of people that carried cell phone or tablet

[tex]\Rightarrow57people[/tex]

Step 2:

How many people carried neither a cell phone nor a tablet?

[tex]\begin{gathered} =85-(38+16+3) \\ =85-57 \\ =28 \end{gathered}[/tex]

Hence,

The number of people that carried neither cell phone nor a tablet is

[tex]\Rightarrow28people[/tex]

Step 3:

How many people carried a cell phone only?

Hence,

The number of people who carried cell-phone only is

[tex]\Rightarrow38people[/tex]

Step 4:

How many people carried a tablet but not a cell phone?

Hence,

The number of people that carried a tablet but not a cell phone is

[tex]\Rightarrow3people[/tex]

A Survey Of 85 Persons Was Conducted At TCC, And It Was Found That 54 Persons Carried A Cell Phone, 19

Related Questions

The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).8,20,50,...Find the 10th term.

Answers

[tex]\begin{gathered} \text{This is a Geometry progression } \\ n\text{ = 10} \\ a\text{ = 8} \\ r\text{ =}\frac{20}{8}=\text{ }\frac{10}{4}=\frac{5}{2} \\ T_{10\text{ }}=ar^{n-1} \\ T_{10\text{ }}\text{ = 8 }\times\text{ ( }\frac{5}{2})^{10-1} \\ \text{ = 8 }\times\text{ ( }\frac{5}{2})^9 \\ =\text{ 8}\times\frac{1953125}{512} \\ =8\times3814.697 \\ =30517.578 \end{gathered}[/tex]

You invest $3,150.00 in a stock plan. The first year, it loses 5% of its value. The second year, it gains 9% of its value. What is the difference between the value of your stocks at the end of the second year and your initial investment?

Answers

Given:

The investment is $3,150.00.

The loss percent for the first year is 5 %.

The gain percent for the second year is 9 %.

Required:

We need to find the investment amount at end of the second year.

Explanation:

The investment amount at the end of the first year is

[tex]=3150(1-\frac{5}{100})[/tex][tex]=3150(1-0.05)[/tex][tex]=2992.5[/tex]

The investment amount at the end of the first year is $2992.5.

The investment amount at the end of the second year is

[tex]=2992.5(1+\frac{9}{100})[/tex][tex]=2992.5(1+0.09)[/tex][tex]=3261.825[/tex][tex]=3261.83[/tex]

The investment amount at the end of the second year is $3261.83.

Final answer:

The investment amount at the end of the second year is $3261.83.

Which equation could be used to find how many soft drink refills Ryan ordered

Answers

Solution

We are given

Restaurant charge = $16.99

Soft drink refill charge each = $1.75

Ryan paid = C

Let x denotes the number of soft drink refill Ryan ordered, so we have

[tex]16.99+1.75x=C[/tex]

Therefore, the answer is

[tex]1.75x+16.99=C[/tex]

Which of the following functions best describes this graph?O A. y=x2- 8x+15O B. y=x+8x+15O c. y = x + x - 12O D. y=x2-5x+6

Answers

We will investigate how to best represent a parabolic graph using a function description.

All parabolas are denoted as either a " U " or inverted " U ". There are two principal parameters of a parabola. The vertex i.e the maximum or minimum point attained by the parabola. The line of symmetry or focus point: The line of symmetry can either be vertical or horizontal but it always passes through the focus point.

We are given a graph of a parabola that has two zeros which can be read off from the plot.

We will locate these zeros and write them down:

[tex]\begin{gathered} x\text{ = 3} \\ x\text{ = 5} \end{gathered}[/tex]

All parabolas are expressed by a quadratic polynomial function. The quadratic polynomial can be expressed in factorized form as follows:

[tex](\text{ x - }\alpha\text{ )}\cdot(x\text{ - }\beta\text{ )}[/tex]

Where,

[tex]\begin{gathered} \alpha\text{ = 3 ( First Zero )} \\ \beta\text{ = 5 , ( Second Zero )} \end{gathered}[/tex]

We will express our located zeros in the factorized quadratic expressed above:

[tex](\text{ x - 3 )}\cdot(x\text{ - 5 )}[/tex]

Then we will try to solve the parenthesis and expand the factorized form as follows:

[tex]\begin{gathered} -5\cdot(x\text{ - 3 ) + x}\cdot(x\text{ - 3 )} \\ -5x+15+x^2\text{ - 3x} \end{gathered}[/tex]

Group the similar terms and simplify:

[tex]x^2\text{ - 8x + 15 }[/tex]

Therefore the function that best describes the given plot is:

[tex]y=x^2\text{ -8x + 15 }\ldots\text{ Option A}[/tex]

I have 2 sets of numbers and need to calculate the percentage between them.

Answers

Answer:

It is 0.696% for Part A, and 0.634% for Part B

Male students are more represented in Part A.

Explanation:

Given that there are 19100 students.

For Part A, the percentage of male students is part A is:

[tex]\begin{gathered} \frac{\text{Sum of male students in part A}}{\text{Total male students}} \\ \\ =\frac{133}{19100}\times100 \\ \\ =0.696 \end{gathered}[/tex]

For Part A, the percentage of male students is part B is:

[tex]\begin{gathered} \frac{121}{19100}\times100 \\ \\ =0.634 \end{gathered}[/tex]

A) Find the points of intersection between the curve y = x(x - 1) (x - 2) and x-axis.

Answers

To find the intersection of the curve

[tex]y=x(x-1)(x-2)[/tex]

And the x-axis, we first have to notice that the x-axis is the same as the line:

[tex]y=0[/tex]

Now, we have a system of two equations.

If we substitute y = 0 into the first, we have:

[tex]x(x-1)(x-2)=0[/tex]

Now, for this equation to be true, one of the factors, "x", "(x-1)" or "(x-2)" has to be zero.

So, we will have three solutions:

[tex]\begin{gathered} x=0 \\ x-1=0\leftrightarrow x=1 \\ x-2=0\leftrightarrow x=2 \end{gathered}[/tex]

And since these are on the x-axis, we already know that the y values for them are all y = 0.

Thus, the points of intersections are:

[tex]\begin{gathered} (0,0) \\ (0,1) \\ (0,2) \end{gathered}[/tex]

how many marriage licenses were issued in 2006 ? round answer to the nearest hundred

Answers

To solve the exercise we have to replace the value requested on the equation given to model the problem as above

[tex]y=3.4905(2006)^2-17674(2006)+21533000=124853.658[/tex]

As we see and approximating the result to the options, we get that the correct answer is the second one (124900)

what theorems or postulates could you use to prove this relationship

Answers

From the diagram given, we can see that line a is parallel to line b. This means that the position of each of the angle on line a is equal to the position of each of the angle in line b

From the figure <1 = <(7x+19)degree (corresponding angle). Also <5 = 7x+19 = <1 (corresponding angle as well)

From the above, we can say that <5 = <1 and since <5 and <6 lies on the same stright line, their sum will be 180.

Don't forget that <5 is now replaced as <1. Hence <1+<6 = 180 (supplementary angle).

From the expalnation above, the theorems that was used to prove the relationship between <1 and <6 are supplementary angle, corresponding angle and same side interior angle

Hence option D is correcct

What are all of the answers for these questions? Use 3 for pi. Please do not use a file to answer, I cannot read it.Question 8.

Answers

To calculate the area of the doughnut, we need to calculate the area of the larger circle and substract the area of the smaller circle.

The area of a circle can be calculated using its radius:

[tex]A=\pi r^2[/tex]

The diameter of the larger circle is 6cm which meand that its radius is half as large, so the radius is 3 cm and the area of the larger circle is:

[tex]A_L=\pi3^2=9\pi[/tex]

Area of 9π cm².

The smaller one have a diameter of 2 cm, so its radius is half as large, radius of 1 cm.

So, the area of the smaller circle is:

[tex]A_S=\pi1^2=\pi[/tex]

Area of π cm².

The total shaded area is, then, the area of the larger minus the area of the smaller.

So, the shaded area is:

[tex]\begin{gathered} A=A_L-A_S \\ A=(9\pi-\pi)cm^2 \\ A=8\pi cm^2 \\ A\approx(9\cdot3)cm^2 \\ A\approx27cm^2 \end{gathered}[/tex]

Find the product. 1. 9 х 10 4 2 10 5. 2 1 X 12 12

Answers

First, convert into an improper fraction, then operate and simplify:

[tex]\begin{gathered} 3\frac{2}{8}\cdot\frac{9}{10}\rightarrow\frac{3\cdot8+2}{8}\cdot\frac{9}{10}\rightarrow\frac{26}{8}\cdot\frac{9}{10}\rightarrow\frac{13}{4}\cdot\frac{9}{10}\rightarrow\frac{117}{40} \\ \\ 2\frac{4}{10}\cdot\frac{4}{5}\rightarrow\frac{2\cdot10+4}{10}\cdot\frac{4}{5}\rightarrow\frac{24}{10}\cdot\frac{4}{5}\rightarrow\frac{12}{5}\cdot\frac{4}{5}\rightarrow\frac{48}{25} \\ \\ 1\frac{4}{12}\cdot\frac{2}{12}\rightarrow\frac{12+4}{12}\cdot\frac{2}{12}\rightarrow\frac{16}{12}\cdot\frac{2}{12}\rightarrow\frac{4}{3}\cdot\frac{1}{6}\rightarrow\frac{4}{18}\rightarrow\frac{2}{9} \\ \\ 3\frac{2}{3}\cdot\frac{2}{8}\rightarrow\frac{3\cdot3+2}{3}\cdot\frac{2}{8}\rightarrow\frac{11}{3}\cdot\frac{1}{4}\rightarrow\frac{11}{12} \end{gathered}[/tex]

HEL LE Maria has 36 episodes of Grey's Anatomy to watch with her friends. They watch 3 episodes each day. Which of the following equations represents the number days, d, it took for them to have 21 episodes left? 0210 - 3 = 36 O 21 - 3d = 36 36 - 3d = 21 36 + 3d = 21 LE

Answers

Total episodes: 36

Episodes watched per day: 3

Number of days: d

To represents the number of days, d, it will take for them to have 21 episodes left:

Subtract the episodes watched per day (3d) to the total episodes (36), and that expression must be equal to 21:

36-3d=21

I can’t figure this out. Getting different answer than listed. Please help with attached pic.

Answers

Solution

We are required to use synthetic division to rewrite the expression

[tex](x^3+6x^2-5)\div(x+2)[/tex]

The synthetic division is shown below

Re-write the result in polynomial form

[tex]=x^2+4x-8+\frac{11}{x+2}[/tex]

The answer is

[tex]=x^2+4x-8+\frac{11}{x+2}[/tex]

An experiment was conducted to determine whether a deficiency of carbon dioxide in the soil affects the phenotype of peas. Lisphenotype codes where 1 = smooth-yellow, 2 = smooth-green, 3 = wrinkled-yellow, and 4 = wrinkled-green. Do the results make1 1 3 2 1 2. 4 2 3 1 3 3 3 3A. The mode phenotype code is(Use a comma to separate answers as needed.)Help me solve thisView an exampleGet more help210SongOLD

Answers

Step 1

The mode is the value that occurs most often. The mode is the only average that can have no value, one value or more than one value. When finding the mode, it helps to order the numbers first.

For this qustion , the number code that occurs most are/is;

[tex]3[/tex]

The mode phenotype code = 3 and this represents wrinkled yellow

two segments are interesting outside the circle, choose the correct equation to set up before having to solve for y

Answers

Option (C)

Given:

Two segments are interesting outside the circle.

The objective is to find the correct equation.

Since the two lines drawn from a point outside the circle passes through two points in a circle, the line is call secant line.

Consider the given figure as,

If two secant line is drawn from a point outside the circle, the equation wil be,

[tex]a(a+b)=c(c+d)[/tex]

Now, substitute the given values in the above formula,

[tex]\begin{gathered} 4(4+6)=2(2+y) \\ 4(10)=2(2+y) \end{gathered}[/tex]

Hence, option (C) is the correct answer.

Sec 0=9/4, 0 in quadrant 4. Find tan 0. Show your work

Answers

Determine the value of angle theta.

[tex]\begin{gathered} \sec \theta=\frac{9}{4} \\ \theta=\sec ^{-1}(\frac{9}{4}) \\ =296.3878\text{ (As }\theta\text{ lie in fourth quadrant)} \end{gathered}[/tex]

Determine the value of tan theta.

[tex]undefined[/tex]

Use the Law of Sines to find the indicated side x. (Assume a = 400. Round your answer to two decimal places.)

Answers

The law of sines is given by:

a/sinA = b/sinB = c/sinC

Take into account that in the given problem you need to know what is the measure of angle C, to be able to use the law of sines.

Consider that the sum of the interioiro angles of a triangle is 180°. Then, you have:

m∠C + 98.4° + 24.6° = 180°

m∠C + 123° = 180°

m∠C = 180° - 123°

m∠C = 57°

Next, use the law of sines with sides a and x, angle A and C:

a/sinA = x/sinC solve for x

(a/sinA)(sinC) = x

x = (a/sinA)(sinC) replace the values of known parameters (a = 400)

x = (400/sin98.4°)(sin57°)

x = 339.106

Hence, the length of side x is x = 339.106

Solve the following logarithmic equation. Express all solutions in exact form.√log x-3 =log x-3

Answers

Square both side of equation and simplify the equation.

[tex]\begin{gathered} (\sqrt[]{\log x-3})^2=(\log x-3)^2 \\ \log x-3=(\log x)^2-6\log x+9 \\ (\log x)^2-6\log x-\log x+9+3=0 \\ (\log x)^2-7\log x+12=0 \end{gathered}[/tex]

Assume log x = y. So equation is,

[tex]y^2-7y+12=0[/tex]

Simplify the equation to obtain the value of y.

[tex]\begin{gathered} y^2-7y+12=0 \\ y^2-4y-3y+12=0 \\ y(y-4)-3(y-4)=0 \\ (y-3)(y-4)=0 \\ y=3,4 \end{gathered}[/tex]

So the value of y is 3 or 4,

[tex]\begin{gathered} \log x=3 \\ x=e^3 \end{gathered}[/tex]

Or

[tex]\begin{gathered} \log x=4 \\ x=e^4 \end{gathered}[/tex]

I am in alternative school I am a 12th grader I dropped out Beginning 10th grade then came back to school 12th grade I have applied math I have no clue what I'm doing I'm scared for my finals in May I need help

Answers

we have the expression

4÷5×6+7×55

Remember that

Applying PEMDAS

P ----> Parentheses first

E -----> Exponents (Powers and Square Roots, etc.)

MD ----> Multiplication and Division (left-to-right)

AS ----> Addition and Subtraction (left-to-right)

so

step 1

Multiplication and Division (left-to-right)

5x6=30

7x55=385

substitute in the given expression

4÷30+385

step 2

Multiplication and Division (left-to-right)

4÷30=0.13

substitute

0.13+385

step 3

Addition and Subtraction (left-to-right)

0.13+385=385.13

therefore

the answer is 385.13

10c - 6(2c - 1) = -2( c- 3) Your answer

Answers

10c - 6(2c - 1) = -2( c- 3)

[tex]10c-6\left(2c-1\right)=-2\left(c-3\right)[/tex]

in this case, we have a equation with an unknown value (c9

Step 1

operate to eliminate ()

[tex]\begin{gathered} 10c-(6\cdot2c)-(6)(-1)=-2c+6 \\ 10c-12c+6=-2c+6 \\ 10c-12c+2c=6-6 \\ 12c-12c=0 \\ 0=0 \end{gathered}[/tex]

it means, that for any value of x, it will work

this equation has infinite solutions

Consider the sequence below:-2,1,6,13,22, ....What explicit expression can be used to find the nth term of this sequence?

Answers

Answer:

f(n)=n²-3

Explanation:

In the sequence:

[tex]-2,1,6,13,22,...[/tex]

First, we find the difference between the terms.

[tex]\begin{gathered} 1-(-2)=3 \\ 6-1=5 \\ 13-6=7 \\ 22-13=9 \end{gathered}[/tex]

It is observed that the difference between successive terms is the addition of consecutive odd numbers.

This is an example of a quadratic sequence.

The general form of a quadratic sequence is:

[tex]\begin{gathered} f(n)=an^2+bn+c \\ f(1)=-2 \\ \implies a+b+c=-2 \\ f(2)=1 \\ \implies4a+2b+c=1 \\ f(3)=6 \\ \implies9a+3b+c=6 \end{gathered}[/tex]

If we solve the system of equations:

[tex]\begin{gathered} a+b+c=-2 \\ 4a+2b+c=1 \\ 9a+3b+c=6 \\ a=1,b=0,c=-3 \end{gathered}[/tex]

The explicit expression for this sequence is:

[tex]f(n)=n^2-3[/tex]

the sum of 2 numbers is 30. the sum of the squares of the two numbers is 468 what is the product of the two numbers

Answers

Take x and y as the 2 numbers

Define the equation that represents each situation

The sum of 2 numbers is 30

[tex]x+y=30[/tex]

The sum of the squares of the numbers is 468

[tex]x^2+y^2=468[/tex]

Complete the square in the second equation (don't forget to write

Find the greatest common factor of the following terms. 20x^5,80x^6, and 30x

Answers

Answer:

10x

Explanation:

Given the terms: 20x⁵, 80x⁶, and 30x

In order to find the greatest common factor, express each of the terms as a product of its factors.

[tex]\begin{gathered} 20x^5=10x\times2x^4 \\ 80x^6=10x\times8x^5 \\ 30x=10x\times3 \end{gathered}[/tex]

Observing the three products, 10x is the only common factor,

Therefore, the greatest common factor is 10x.

Triangles RTS and XYZ are similar. Match each given side of triangle XYZ with the corresponding side on triangle RTS. R À À S TY YZ XY 111 XZ :: RS :: RT :: TS hp

Answers

we know that

if the triangles are similar, thrn itcs corresponding sides are proportional

so

In this problem

the corresponding sides are

YZ and TS

XY and RT

XZ and RS

A 20% tip on a $26.00 dinner bill ishow much money?

Answers

Mela, this is the solution:

Dinner bill = $ 26

Tip = 20% or 0.2

Tip = 26 * 0.2

Tip = $ 5.20

NO -6 -10 Use the graph to complete the function table. Input Output -7 1 5 Submit

Answers

In order to complete the function table, we just need to locate the input values in the x-axis and then find the corresponding values of y in the line.

For x = -7, we have y = 9

For x = 1, we have y = -3

For x = 5, we have y = -9

So the output values for the table are

18, 32Using rounding, what is the best estimate for the product of these numbers?200300600800

Answers

We are given the following two numbers

18 and 32

Using rounding, what is the best estimate for the product of these numbers?

We can round up 18 to 20

We can round down 32 to 30

20×30 = 600

Therefore, the best estimate for the product of 18 and 32 is 600.

a/5 + 8<13 please help

Answers

We have the inequality

[tex]\frac{a}{5}+8<13[/tex]

solving for a, we have

[tex]\begin{gathered} \frac{a}{5}+8<13 \\ \frac{a}{5}<13-8 \\ \frac{a}{5}<5 \\ a<5\cdot5 \\ a<25 \end{gathered}[/tex]

Then a has to be less than 25. Written the solution in interval form we have:

[tex](-\infty,25)[/tex]

The principal is trying to come up with a playground policy to protect students from the risk of getting heatstroke on especially hot and humid days. If that's her goal, at which temperature should students stop being allowed outside for recess?A 80 degrees B 90 degrees C 105 degreesD 130 degrees

Answers

The temperature should be the following:

*Temperatures greater than 80° on hot or humid days should be the temperature limit.

The area of the entire figure below is 111 square unit.The area of the entire figure below is 111 square unit.

Answers

Looking at the image, the width of the rectangle is 7 small rectangles and the length is 9 small rectangles, therefore the area of 1 square unit is equal to 9 * 7 = 63 small rectangles.

From these small rectangles, an area of 5 * 4 = 20 small rectangles is shaded.

Therefore the shaded area is calculated as:

[tex]\frac{20}{63}\cdot1\text{ square unit}=\frac{20}{63}\text{ of a square unit}[/tex]

PLEASE HELP!!!

As part of a major renovation at the beginning of the year, Atiase Pharmaceuticals, Incorporated, sold shelving units (recorded as Equipment) that were 10 years old for $800 cash. The shelves originally cost $6,400 and had been depreciated on a straight-line basis over an estimated useful life of 10 years with an estimated residual value of $400.


1. Complete the table below, indicating the account, amount, and direction of the effect on disposal. Assume that depreciation has been recorded to the date of sale. (Enter any decreases to Assets, Liabilities, or Stockholders' Equity with a minus sign. Do not round intermediate calculations.)


ASSETS = LIABILITIES + STOCKHOLDERS' EQUITY

Answers

The total asset account balance is $400 and total liabilities and stockholders’ equity balance is $400.

Given that,

Aliases Pharmaceuticals, Incorporated sold shelving units (recorded as Equipment) that were ten years old for $800 cash as part of a significant upgrade at the beginning of the year. The shelves had a $6,400 initial cost that had been straight-line depreciated over a 10-year anticipated useful life, leaving a $400 estimated residual value.

What is Accounting equation?

It is the relationship among the assets, liabilities and stockholders’ equity. Total liabilities, as well as stockholders' equity, equal total assets. This equation states that an increase in assets will result in an increase in either liabilities or owners' equity. The accounting equation is solved using the formula below.

Assets = Liabilities +Stockholders equity

Calculate accumulated depreciation for 10 years.

Accumulated depreciation for 10 years=[(Original cost of the equipment-Residual value) / Useful life] ×10 years

=[($6400-$400)/10 years]×10 years

=$600×10 years

=$6000

Calculate book value of equipment.

Book value equipment=Original cost of the equipment-Accumulated depreciation for 10 years

=$6400-$6000

=$400

Calculate gain on sale of equipment.

Gain on equipment sale equals selling price minus book value of equipment

=$800-$400

=$400

Therefore, the total asset account balance is $400 and total liabilities and stockholders’ equity balance is $400.

The table we can see in the picture.

To learn more about liability visit: https://brainly.com/question/18484315

#SPJ1

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