Answer: Volume of 0.25 M solution is 38 ml
Explanation: Amount of substance n remains same.
n = c1V1 = c2V2 Solve V2 = V1c1 / c2 = 73,0 ml · 0.13 M / 0.25 M = 37.96 ml
is this correct im just asking because my little brother not sure for his answer
cómo se puede comprobar el efecto universo
Answer:
???! huhhhjhhh no I speak English
Explanation:
?
Answer:
vifucivud UKvi uiiijhhh
Products will form faster if___
A) temperature is decreased
B) the reaction is not stirred
C) the particle size of the reactants are larger
D) concentration of the reactants are increased
Answer:
C(btw this could be wrong)
Explanation:
Answer:
B is the answer
Explanation:
2) Choose the best answer. Which type of reaction is this? NaOH + H2O → Na+ + OH strong base dissociation strong acid dissociation weak base dissociation neutralization weak acide dissociation
Answer:
strong Base Dissociation
Explanation:
NaOH is baseNaOH is strong base that means strong acids ionizes almost completely when dissolved in water.Which of the following does NOT represent a balanced reaction?
Answer:
letter D i thinkExplanation:
correct me if im wrong
How many grams of carbon dioxide will be produced if 76.4 grams of
C2H3Br3 reacted with 49.1 grams of O2? How many grams of the
excess reactant will be left after the reaction is over? Consider the
equation: C2H3Br3+O2 -> CO2+H2O+Br2
Answer:
Assuming that all of the oxygen is used up, 1.53×4111.53×411 or 0.556 moles of C2H3Br3 are required. Because there are only 0.286 moles of C2H3Br3 available, C2H3Br3 is the limiting reagent.
Limiting Reagent What is the limiting reagent if 76.4 grams of C2H3Br3 were reacted with 49.1 grams of O2? C2H3Br3 + 11O2 → 8CO2 + 6H2O + 6Br2 SOLUTION Using Approach 1: A. 76.4g × (1 mol/ 266.72 g) = 0.286 moles C2H3Br3 49.1g × (1 mole/ 32 g) = 1.53 moles O2 B.
Explanation:
MRK ME BRAINLIEST PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
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7. What is the mass of a piece of copper (Cu) that undergoes a 25.0 °C
temperature change with the loss of 428 J of energy?
Answer:
0.0428 kg or 42.8 g
Explanation:
Applying,
Q = cmΔt.............. Equation 1
Where Q = heat lost of heat gained, c = specific heat capacity of copper, m = mass of copper, Δt = temperature change.
make m the subject of the equation above
m = Q/cΔt.................. Equation 2
From the question,
Given: Q = 428 J, Δt = 25 °C
Constant: c = 400 J/kg.°C
Substitute these values into equation 2
m = 428/(25×400)
m = 0.0428 kg
m = 42.8 g
ACTIVITY NO.3
DIRECTIONS: Read each item carefully. Choose the letter of your answer.
1. Light travels in a
line when is passes through a single medium.
a. curve
b. straight
C. crooked
d. dotted
2. When the sound travels through solids, the vibration of the particles occurs
?
a. fast
b. slowly
c. moderately
irregularly
3. What affects the speed of sound as it travels?
a. Person receiving it
b. The origin of the sound
c. The nature of materials
d. Loudness of the sound
4. How is heart transferred in solid materials?
a. Through convection
b. Through conduction
c. Through radiation
d. Through vacuum
5. What is the direction of heat transfer?
a. From hot to cold
b. From Cold to hot
c. From bottom to top
d. From side to side
What is (aq),(I), and (g) mean in H2O2(aq) -> H2O(l) + O2(g) and why is it nesesary to have (aq),(I), and (g)
Explanation:
A matter can be present in different states like solid, liquid or gas. When we write a chemical equation then states of species involved are also mentioned.
This is because it tells in what state the reactants were present and in what state the products are then formed.
For example, [tex]H_{2}O_{2}(aq) \rightarrow H_{2}O(l) + O_{2}(g)[/tex]
Now here, (aq) means aqueous, (l) means liquid and (g) means gas.
So, these states denoted are necessary as it tells that [tex]H_{2}O_{2}[/tex] in aqueous state dissociates to give [tex]H_{2}O[/tex] in liquid state and [tex]O_{2}[/tex] in gaseous state.
pls help i need asap will mark brainlest
Answer:
B. 50%
Explanation:
2H₂ + CO → CH₃OHFirst we convert the given masses of the reactants into moles, using their respective molar masses:
4 g H₂ ÷ 2 g/mol = 2 mol H₂25 g CO ÷ 28 g/mol = 0.893 mol CO0.893 moles of CO would react completely with (0.893 * 2) 1.786 moles of H₂. As there are more H₂ moles than that, H₂ is the reactant in excess and CO is the limiting reactant.
Now we calculate how many CH₃OH moles would have been formed if all CO would have been consumed:
0.893 mol CO * [tex]\frac{1molCH_3OH}{1molCO}[/tex] = 0.893 mol CH₃OHThen we convert 0.893 moles of CH₃OH into grams, using its molar mass:
0.893 mol CH₃OH * 32 g/mol = 28.57 gFinally we calculate the percent yield:
14 g / 28.57 g * 100% = 49%Phosphorus (P4) and hydrogen gas can combine to form phosphine (PH3), a toxic gas with the odor of rotting fish. Complete and balance the equation for this chemical reaction.
Answer:
P₄ + 6 H₂ ⇒ 4 PH₃
Explanation:
Let's consider the unbalanced reaction that takes place when phosphorus reacts with hydrogen to form phosphine. This is a synthesis reaction.
P₄ + H₂ ⇒ PH₃
We will balance this reaction using the trial and error method. First, we will balance P atoms by multiplying PH₃ by 4.
P₄ + H₂ ⇒ 4 PH₃
Finally, we get the balanced equation by multiplying H₂ by 6.
P₄ + 6 H₂ ⇒ 4 PH₃
how many moles are in 89 grams of Pb(CH3COO)4
Answer:
0.20 moles of Pb(CH3COO)4
Explanation:
89g Pb(CH3COO)4 x 1 mol Pb(CH3COO)4 / 443.376 g Pb(CH3COO)4
= 0.20 moles of Pb(CH3COO)4
One mole of lead acetate weighs 443.29 g. Then, 89 grams of lead acetate contains 0.20 moles of Pb (CH₃COO)₄.
What is one mole ?One mole of a substance is its amount containing 6.02 × 10²³ atoms or molecules. This number is called Avogadro number. One mole of every elements contains Avogadro number of atoms.
Similarly one mole of every compound contains 6.02 × 10²³ molecules. The mass of one mole of compound is called its molar mass. The number of moles of the compound can be determined by dividing the given mass by molar mass.
Molar mass of lead acetate = 443.29 g/mol
given mass = 89 grams
then , no.of moles = weight/molar mass
n = 89 g/ (443.29 g/mol) = 0.20 moles
Therefore, the number of moles of Pb (CH₃COO)₄ in 89 g is 0.20 moles.
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Determine the type of reaction: AgNO3 + Cu --> Cu(NO3)2 + Ag
Explanation:
Cu + 2 AgNO3 → Cu(NO3)2 + 2 Ag
Cu is oxidized
Ag+ is reduced
Cu is the reducing agent
To solve such this we must know the concept of displacement reaction. The balanced reaction of silver nitrate with copper is of displacement type of reaction.
AgNO[tex]_3[/tex] + Cu [tex]\rightarrow[/tex] Cu(NO[tex]_3[/tex])[tex]_2[/tex] + Ag
What is Balanced equation?Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, displacement reaction.
The reaction between silver nitrate and copper is example of displacement reaction. Copper displaces silver from silver nitrate. to form copper nitrate.
Therefore, the balanced equation is of displacement type of reaction.
AgNO[tex]_3[/tex] + Cu [tex]\rightarrow[/tex] Cu(NO[tex]_3[/tex])[tex]_2[/tex] + Ag
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PLZ ANSWER QUICK I AM IN TIMER HELP WILL GIVE BRAINLIEST
Which is greater, the moon's period of rotation or its period of revolution?
They are equal.
the moon's revolution period around Earth
Neither are known.
the moon's rotational period
Answer:
B
Explanation:
If you have 1.82 moles of mercury (Hg), how many grams of mercury do you have?
Answer:
182
Explanation:
1 hectogram (hg) = 100 grams (g)
1.82 x 100 = 182
write a story of your life when you were hurted by someone whom you trusted blindly...
Answer:
Sis I think it happened with me but I am not able to remember if u want u can share if it happened with u
The primary structure of a protein is determined by
A. The order of amino acids in the protein.
B. The amino acid composition.
C. The hydrogen bonding that gives the protein three dimensional shape.
D. The intertwining of protein molecules to form a “functional” protein.
Answer: I believe the answer is A. The order of amino acids in the protein.
Explanation:
You can find the speed on a distance-versus-time graph by finding the slope of the line.
True
False
Answer both of these true or false correctly
brainliest if correct
Answer:
There both true.
Explanation:
Hope this helps
Answer:
The first one is True
The second one is false
Explanation:
to make a large quantity of a 5% solution of HCl but only have 25mL HCl. what volume of 5% solution can be made from this volume of HCl?
Answer:What is the volume of 37% HCl?
If however you meant to say 0.025M and assuming you want to prepare 1L solution then the volume of 37% HCl needed should be= (1000 X 0.025X 36.5)/ (37X1.19X10)=2.07 mL diluted to 1 L using DI water. Good day. If you want 0.025 mole HCl solution, you should take a 2.09 ml of your acid.
Explanation:To prepare 5% solution from this acid; simply take 5 ml. of the acid and add it to 95 ml of distilled water.You get a 5%HCl solution. By the way, Hydrogen Chloride is the name designated to the gas evolved from HCl acid
To determine the volume of a 5% solution that can be made from 25 mL of HCl, we need to use the equation: C1V1 = C2V2
Where:
C1 = Initial concentration of HCl
V1 = Initial volume of HCl
C2 = Final concentration of the solution (5% or 0.05 in decimal form)
V2 = Final volume of the solution (unknown)
What is HCl?HCl stands for hydrochloric acid. It is a strong, highly corrosive acid that is commonly used in various industrial, laboratory, and chemical applications. In its pure form, hydrochloric acid is a colorless liquid with a pungent odor. It is composed of hydrogen (H) and chlorine (Cl) and is known for its acidic properties.
Let's plug in the known values:
C1 = 100% (since the initial HCl is undiluted)
V1 = 25 mL
C2 = 5% or 0.05
V2 = Unknown
Solving for V2:
C1V1 = C2V2
(1)(25 mL) = (0.05)(V2)
25 mL = 0.05V2
Divide both sides by 0.05 to isolate V2:
V2 = 25 mL / 0.05
V2 = 500 mL
Therefore, from 25 mL of HCl, you can make a 500 mL solution with a concentration of 5%.
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Why would you want to slow down a chemical reaction?
Answer:
We often want to decrease the rates of certain reactions rather than speeding them up. For example, to prolong the shelf lives of certain foods, the chemical reactions by which they spoil must be slowed down.
Find the % composition for each element in Zinc Chlorate
Answer:
chlorine ~ 30%
zinc ~ 28%
oxygen ~ 41%
Explanation:
Draw a schematic diagram of a circuit with an output device, a energy source and a controller.
Answer:
ch∪pαpi munαn0?
Explanation:
Place the following in order of increasing entropy at 298 K.
Ne Xe He Ar Kr
A) He < Kr < Ne < Ar < Xe.
B) Xe < Kr < Ar < Ne < He.
C) Ar < He < Ar < Ne < Kr.
D) Ar < Ne < Xe < Kr < He.
E) He < Ne < Ar < Kr < Xe.
Answer:
E
Explanation:
The simple rule of thumb is that as the atomic or molar mass of an atom increases, the entropy increases. This means that more the mass more will be entropy.
The atomic mass of various elements is as follows
Ne = 20 g/mol
Xe = 131 g/mol
He = 4 g/mol
Ar = 40 g/mol
Kr = 84 g/mol
Therefore, the order of increasing entropy must be
He<Ne<Ar<Kr<Xe.
Hence, option E is the correct answer.
True or False: A higher vapor pressure (evaporates easily) corresponds to strong intermolecular forces.
Which particles appear in equal numbers in all uncharged atoms? Proton, Neutron, Electron, None
Answer:
In an uncharged atom, the number of protons is always equal to the number of electrons. Apr 24, 2017
Explanation:
Neutron: An uncharged particle found in the nucleus of an atom.
There is only one stable atom that does not have neutrons. It is an isotope of the element hydrogen called protium. Protium, which contains a single proton and a single electron, is the simplest atom.
For each event stated below, indicate how the concentration of each species in the chemical equation will then change to reach equilibrium.
2CO(g) + O2(g) ⇌ 2CO2(g)
a. increasing the concentration of CO
b. decreasing the amount of O2
c. decreasing the the volume of the system
Answer:
See Explanation
Explanation:
When a constraint such as a change in temperature, concentration or pressure is imposed on a reaction system in equilibrium, the system will readjust itself in such a way as to annul the constraint. This readjustment occurs when the equilibrium position shifts towards the left or right in order to annul the constraint.
a. increasing the concentration of CO: When the concentration of CO is increased, the equilibrium position shifts to the right in order to annul the constraint. This means that more CO2 is produced in the system while the concentration of CO and O2 are decreased until equilibrium is reestablished.
b. decreasing the amount of O2: When the amount of O2 is decreased, the equilibrium position will shift to the left and more CO and O2 are produced while the concentration of CO2 decreases until equilibrium is reestablished.
c. decreasing the the volume of the system: When the volume of the system is decreased, the equilibrium position shifts towards the right hand side where there is less total volume. Hence the concentration of CO and O2 decreases while the concentration of CO2 increases.
How do we measure the rate of this reaction A + B —> C
If oxygen gas at 118 °C and 10.8 atm was heated to 948 °C, what would the new
pressure be?
Answer: The new pressure is 1.34 atm.
Explanation:
Given: [tex]P_{1}[/tex] = 10.8 atm, [tex]T_{1} = 118^{o}C[/tex]
[tex]P_{2}[/tex] = ?, [tex]T_{2} = 948^{o}C[/tex]
Formula used to calculate the new pressure is as follows.
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{10.8 atm}{118^{o}C} = \frac{P_{2}}{948^{o}C}\\P_{2} = 1.34 atm[/tex]
Thu, we can conclude that the new pressure is 1.34 atm.
the mass concentration the mass concentration for a solution containing 45 g of calcium carbonate is 100 cm3
Answer: The mass concentration for a solution containing 45 g of calcium carbonate for 100 [tex]cm^{3}[/tex] is 0.045 M.
Explanation:
Given: Mass of calcium carbonate = 45 g
Volume = [tex]100 cm^{3}[/tex]
Convert [tex]cm^{3}[/tex] into L as follows.
[tex]1 cm^{3} = 0.001 L\\100 cm^{3} = 100 cm^{3} \times \frac{0.001 L}{1 cm^{3}}\\= 0.1 L[/tex]
Moles of calcium carbonate (molar mass = 100 g/mol) is as follows.
[tex]No. of moles = \frac{45 g}{100 g/mol}\\= 0.45 mol[/tex]
Molarity is the number of moles of solute present in a liter of solution.
Hence, molarity (or mass concentration) of given solution is calculated as follows.
[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.45 mol}{0.1 L}\\= 0.045 M[/tex]
Thus, we can conclude that the mass concentration for a solution containing 45 g of calcium carbonate for 100 [tex]cm^{3}[/tex] is 0.045 M.