A student in track and field is running a hurdles race. The hurdles are 91.4 cm tall. The student is running with a horizontal velocity of 4.00 m/s and leaps with a vertical velocity of 9.00 m/s. If the student makes this leap 0.400 m before the hurdle, will they clear the hurdle?

Answers

Answer 1

No, they will not be able to clear the hurdle from the given distance of their leap.

What are the projectile motion?

Projectile motion includes vertical and horizontal velocity components. It's important to understand that the two are independent of each other. But what is a projectile and what is a good example. Well, a projectile is an object that is thrown by applying a force that falls under gravity and is subject to the resistance of the medium in which it travels. It can be thrown into the air and fall under the influence of gravity.

First of all the time required to reach the hurdle is:

by using horizontal velocity we have time = [tex]\frac{distance}{speed}[/tex]

t = [tex]\frac{0.400}{4}[/tex]

t = 0.100s

Now for the vertical distance covered by student:

S = ut + [tex]\frac{1}{2}[/tex] gt²

S = 9 × 0.100 +  [tex]\frac{1}{2}[/tex] 9.8 × 0.100²

S = 0.851m or 85.1cm

Since the distance calculated is less than the height of hurdles which is 91.4 cm so the student may not be able to clear the hurdle.

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Related Questions

what is the direction of the magnetic force on a positive charge moving into the page in a b field that is facing to the right?

Answers

According to the right hand rule, the thumb of the right hand should point in the direction of the magnetic force acting on a positive moving charge.

Which magnetic field direction is positive?

It is demonstrated that the magnetic line's direction is from north to south and the electric line's direction is from positive to negative.

What direction does the coil's left-hand side force come from?

A downward force is produced when current flows through the left hand of the coil, and an upward force is produced when current flows through the right hand of the coil.

What direction does this magnetic force go in?

The direction of the magnetic field's force is opposite the direction that it acts.

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a child is sledding down a hill. the child has 200 j of potential energy and 500 j of kinetic energy at one point on the hill. how much more kinetic energy does the child gain for the remainder of the motion to the bottom of the hill?

Answers

The additional kinetic energy that the child gains after reaching the bottom of the hill is 200 Joule. The result is obtained by using the principle of Conservation of Mechanical Energy.

What is Conservation of Mechanical Energy?

The principle of conservation of energy states that "The total energy is neither increased nor decreased in any process. Energy can be transformed from one form to another, and transferred from one object to another, but the total amount remains constant."

In the same way, the Conservation of Mechanical Energy states that the total mechanical energy of a system is conserved. It can be expressed as

[tex]E_{1} = E_{2}[/tex]

[tex]K_{1} + U_{1} = K_{2} + U_{2}[/tex]

[tex]\frac{1}{2} mv_{1} ^{2} + mgh_{1} = \frac{1}{2} mv_{2} ^{2} + mgh_{2}[/tex]

Where

E₁ = mechanical energy at point 1E₂ = mechanical energy at point 2K₁ = kinetic energy at point 1K₂ = kinetic energy at point 2U₁ = potential energy at point 1U₂ = potential energy at point 2m = mass of an objectv₁ = velocity of object at point 1v₂ = velocity of object at point 2h₁ = height of object at point 1h₂ = height of object at point 2

At one point, a child has:

U₁ = 200 JK₁ = 500 J

How much more kinetic energy does the child gain at the bottom of the hill?

At the bottom of the hill, the height of the child is zero, h₂ = 0. So, the potential energy is

[tex]U_{2} = mgh_{2}[/tex]

[tex]U_{2} = mg(0)[/tex]

[tex]U_{2} = 0[/tex]

The kinetic energy at the bottom of the hill is

[tex]K_{1} + U_{1} = K_{2} + U_{2}[/tex]

[tex]500 + 200 = K_{2} + 0[/tex]

[tex]K_{2} = 700 J[/tex]

The kinetic energy added for the remainder of the motion is

[tex]K = K_{2} - K_{1}[/tex]

[tex]K = 700 - 500[/tex]

[tex]K = 200 J[/tex]

Hence, the additional kinetic energy that the child gains after reaching the bottom of the hill is 200 Joule.

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A monochromatic laser is exciting hydrogen atoms from the n=2 state to the n=5 state.

Answers

A monochromatic laser is responsible for exciting hydrogen atoms from their n=2 state to their n=5 state in which :

wavelength λ of the laser =435 nm

longest wavelength = λmax = 4052 nm

shortest wavelength = λmin= 95 nm

To do excitation, the energy of the laser should be greater than or equal to the energy of transition of the hydrogen atom.

In this case, the states of energy are explained by the Bohr model.

       En = -  13,606 /n²    [eV]

therefore the energy of the transition is

         ΔE  =  E 5 -  E2

         ΔE  =  13.606  (1  n2^2  -  1  n5^5 )

        ΔE  =  13.606(1 /2^2   -  1 /5^5).

        ΔE =    2,85726 eV

Using the Planck's equation

         E   =   h f

  Light’s relation to wavelength and frequencies

       c = λ f

       f = c /λ

  λ = h c / E

reducing energy to the SI system

     E  =  2,85726  eV    (1.6x10⁻¹⁹  J /1 eV)   =   4.5716 x 10⁻¹⁹   J

hence,  λ =  6,626 x 10⁻³⁴  3 x 10⁸ /4  ,5716 x 10⁻¹⁹

      λ   = 4.348x 10⁺⁷ m (10⁹ nm / 1 m)

      λ   = 435   nm

photon emission [e] , to the base state n = 1,  from n = 5.

Initial  state,  n = 5

final  state,    n = 4

ΔE = 13.606 (1/4² - 1/5²)

ΔE = 0.306 eV

λ =h c / E

λ = 4052  nm

n = 5

final /  level          ΔE (eV)     λ (nm)

 

  4                 0.306      4052

  3               0.9675     1281

  2                 2,857       435

  1               13.06           95

 n = 4

 3                 0.661        1876

 2                                    2,551         486

 1                 11,905       104

n = 3

 2                1.89            656

 1                                 12.09         102.5

n = 2

1                 10.20         121.6.

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a child pulls a friend in a little red wagon with constant speed. if the child pulls with a force of 16 n for 10.0 m, and the handle of

Answers

The work done by the child to pull the wagon is found to be 67.61N.

The child pulls the wagon with a force 16N and the handle of the wagon is inclined at the angle of 25°. The wagon is puled till a distance of 10m.

So, the force will have to component, one vertical and one is horizontal,

The horizontal component will move the wagon,

So, the work done by the child is given by,

W = F.S.sin(25°)

F is the force and S is the distance, Putting values,

W = 16 x 10 x 0.42

W = 67.61 N.

The work done by the child in pulling the wagon is 67.61 N.

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Complete Question - A child pulls a friend in a little red wagon with constant speed. If the child pulls with a force of 16 N for 10.0 m, and the handle of the wagon is inclined at an angle of 25° above the horizontal, how much work does the child do on the wagon?

this is a 3 part question6) (a) Your heart beats with a frequency of 1.45 Hz. How many beats occur in a minute? (b) If the frequency of your heartbeat increases, will the number of beats in a minute increase, decrease, or stay the same? (c) How many beats occur in a minute if the frequency increases to 1.55 Hz?

Answers

Given,

The initial frequency of the heartbeat, f₁=1.45 Hz

The increased heartbeat, f₂=1.55 Hz

The frequency of the heartbeat can be described as the number of occurence of the heartbeat per second. That is every second, the heart beats 1.45 times.

(a)

Thus for a minute, the number of the heartbeats is,

[tex]\begin{gathered} N_1=f_1\times60 \\ =1.45\times60=87 \end{gathered}[/tex]

Thus 87 beats occur for a minute.

(b)The increase in the frequency of the heartbeat implies the increase in the number of the heartbeat for every second. And hence the beats in a minute increase when the frequency of the heartbeat increases.

(c)

The number of the beats per minute after the increase of the frequency is,

[tex]\begin{gathered} N_2=f_2\times60 \\ =1.55\times60 \\ =93 \end{gathered}[/tex]

Thus after the increase in the frequency, 93 beats occur in a minute.

a car headlight and an interior dome light use the same voltage, but the headlight consumes much more power because

Answers

The lights on and in your vehicle can be as important to your and your passengers' safety as seatbelts, and as visually appealing as great rims or an unusual paint color.

Why headlight consumes much more power than interior dome light ?

Automobiles have been around for nearly a decade, almost as long as mass-marketable light bulbs. The first light bulbs were incandescent, which simply passed any current, AC or DC, through a high-impedance filament, which heated up, glowed, and emitted light.

Although their efficiency is low (as low as 10%), they emit light in all directions and are inexpensive. Under the heat required to generate light, the filament material (typically tungsten) evaporates and tends to collect on the inside of the glass bulb, darkening it over time.

Consumers are looking beyond incandescent lights to high intensity discharge headlights and other 12v LED lighting solutions as the automotive industry grows, but there are even more options and modifications available. While there are amazing new technologies available, not all of them are true advancements or even road-legal. Let us shed some light on the situation.

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A light ray travels through water and reflects off a glass surface back into the water. How do the phases of the incident light and the reflected light compare?.

Answers

The light travels through water and gets reflected off on the glass surface into the water. There had been a 180° phase change between the incident and the reflected wave. This is called Total internal reflection (TIR).

In total internal reflection, in physics, a ray of light in a medium such as water or glass is completely reflected back into the medium from the surrounding surfaces. This phenomenon occurs when the angle of incidence is greater than a certain critical angle called the critical angle.

TIR only occurs when both of the following two conditions are met

Light is in a denser medium and is approaching a less dense medium. The angle of incidence should be greater than the so-called critical angle.

Thus, the phases which include the TIR are the incident and the reflected phase and the incident light hits the surface while the reflected light reflects back.

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A tsunami can travel over 970 kilometers in an hour. If it’s been 3 hours since the tsunami was created, how far has it traveled?

Answers

Answer:

2910

Explanation:

970 × 3. 970 in one hour × 3 hrs. 2910 kilometers

A runner covers the last straight stretch of a race in 8s.During that time he speeds up from 7 m/s to 9m/s. What is the acceleration

Answers

Given

Time taken is t=8 s.

The initial speed is u=7 m/s

The final speed is v=9 m/s.

To find

The acceleration

Explanation

We know the acceleration is the ratio of the difference in the speed to the time taken.

Thus,

[tex]\begin{gathered} a=\frac{v-u}{t} \\ \Rightarrow a=\frac{9-7}{8} \\ \Rightarrow a=\frac{2}{8}=\frac{1}{4}=0.25\text{ m/s}^2 \end{gathered}[/tex]

Conclusion

The acceleration is

[tex]0.25\text{ m/s}^2[/tex]

When tightening a bolt, you push perpendicularly on a wrench with a force of 165 n exerting a torque 23. 1 n. M relative to the center of the bolt. At what distance from the center of the bolt was the force applied?.

Answers

The torque was applied at distance of 14cm from the center of the bolt.

The perpendicular force on the wrench applied is 165N.

The total torque experienced by the bolt is 23.1 N-m.

The torque on any body is given by,

T = Fr

Where,

T is the torque on the body,

F is the force applied in the circular manner for the body,

r is the perpendicular distance of the force applied on the body.

So, now putting the values for the bolt,

23.1 = 165r

r = 0.14m

So, we can conclude here that the force was applied at a distance of 14 cm from the center of the bolt.

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Rudolph's mother is a physicist. She gave him a present for his birthday, but
she told him he can only open it if he can calculate its mass. She told him that
the normal force the table exerts on the gift is 55 N. What is the mass of the
gift?

Answers

The mass of the gift if it exert a normal force of 55 N is 5.61 kg.

What is mass?

Mass can be defined as the quantity of matter a body contains.

To calculate the mass of the gift, we use the formula below.

Formula:

m = N/g................. Equation 1

Where:

m = Mass of the giftN = Normal forceg = Acceleration due to gravity

From the question,

Given:

N = 55 Ng = 9.8 m/s²

Substitute these values into equation 1

m = 55/9.8 m = 5.61 kg.

Hence, the mass of the gift is 5.61 kg.

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A 25N force is acting on a body moving on a straight line with Initial momentum 20 kam's. Find the final momentum after 4 seconds. (Fxt=Pr-Pi)

Answers

The final momentum of the body is equal to 120 Kg.m/s.

What is momentum?

Momentum can be described as the multiplication of the mass and velocity of an object. Momentum is a vector quantity as it carries magnitude and direction.

If m is an object's mass and v is its velocity then the object's momentum p is: [tex]{\displaystyle \mathbf {p} =m\mathbf {v}[/tex] . The S.I. unit of measurement of momentum is kg⋅m/s, which is equivalent to the N.s.

Given the initial momentum of the body = Pi = 20 Kg.m/s

The force acting on the body, Pf = 25 N

The time, Δt = 4-0 = 4s

The Force is equal to the change in momentum: F ×Δt = ΔP

25 × 4 = P - 20

100 = P - 20

P = 100 + 20 = 120  Kg.m/s

Therefore, the final momentum of a body is 120 Kg.m/s.

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A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, it’s height in feet t seconds after launch is given by s= -16t^2+v0t. Find the time(s) that the projectile will (a) reach a height of 272 ft and (b) return to the ground when v0 is 32 feet per second

Answers

We know that the inital velity for this motion is 32 ft/s, this means that the height is given by:

[tex]s=-16t^2+32t[/tex]

a)

To determine at what time the projectile will reach 272 we plug s=272 in the equation above and solve for t:

[tex]\begin{gathered} -16t^2+32t=272 \\ 16t^2-32t+272=0 \\ t^2-2t+17=0 \\ \text{ then} \\ t=\frac{-(-2)\pm\sqrt[]{(-2)^2-4(1)(17)}}{2(1)} \\ t=\frac{2\pm\sqrt[]{-64}}{2} \end{gathered}[/tex]

since the discrimant of the equation is negative this means that the equation does not have real solutions.

This means that the projectile does not reach that height.

b)

To find at what time the projectile return to the ground we equate the expression for the height to zero and solve for t:

[tex]\begin{gathered} -16t^2+32t=0 \\ t(-16t+32)=0 \\ \text{then} \\ t=0 \\ or \\ -16t+32=0 \\ 16t=32 \\ t=\frac{32}{16} \\ t=2 \end{gathered}[/tex]

Therefore it takes 2 seconds for the projectile to return to the ground

An object is launched at a velocity of 20 m/s in a direction making an angle of 22° upward with the horizontal.What is the maximum height achieved by the projectile?

Answers

Given data:

Initial velocity,

[tex]u=20\text{ m/s}[/tex]

Angle of projection,

[tex]\theta=22\degree[/tex]

The maximum height achieved by the projectile is given as,

[tex]H=\frac{u^2\sin ^2\theta}{2g}[/tex]

Here, g is the acceleration due to gravity.

Substituting all known values,

[tex]\begin{gathered} H=\frac{(20\text{ m/s})^2\times\sin ^2(22\degree)}{2\times(9.8\text{ m/s}^2)} \\ \approx2.86\text{ m} \end{gathered}[/tex]

Therefore, the maximum height achieved by the projectile is 2.86 m.

What was the impact of the caravel, astrolabe, and magnetic compass on sea navigation?.

Answers

Astrolabe by measuring the sun's angles, this tool allowed sailors to determine their latitude, or where they were in relation to the equator of the planet. By keeping an eye on where the sun is in the sky, an astrolabe can also be used to tell time.

What does a magnetic compass do?

A magnetic compass is a tool used in surveying or navigation that uses a magnetic pointer that is aligned with the Earth's magnetic field to determine direction on the surface of the planet.

The north-south axis is the alignment point for magnets because of how powerful a magnet the Earth is. The Earth's rotational axis and the magnetic field's poles roughly line up. This indicates that the north geographic pole, also known as true north, and the north magnetic pole are nearly parallel. A light magnet that is free to move will align itself north-south. On the other hand, gravity and friction will prevent a heavy bar magnet from moving when it is placed on a tabletop.

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the speed of light in a material is what is the critical angle of light ray at the interface between material and vacuum

Answers

This problem indicates that the speed of light in a material medium is 0.5 10⁸ m / s, they ask to find the critical angle between the material and the vacuum.

Let's find the refractive index of the material

           n = c / v

          n = 3 10⁸ / 0.5 10⁸

          n = 6

When the material passes from one medium to another, it must comply with the law of refraction.

          n₁ sin θ = n₂ sin θ₂

for the angle criticize the angles tea2 = 90

         t = sin⁻¹n₂/ n₁

The vacuum replacement index is n₂ = 1

        t = sin⁻¹ (1/6)

        t = 9.59º

Therefore, the angle of refractive index will be 9.59°.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: The speed of light in a material is 0.50 c. what is the critical angle of a light ray at the interface between the material and a vacuum?]

4. A 1.5 m tall man is standing 2m away from the concave lens (remember f is negative) of a peephole with a focal length of 3.0 cm. a) What is the distance to the image in centimeters? b) What is the magnification of the image in meters?

Answers

Here,

Size of object = 1.5 m;

Object distance (u) = - 2m = -200cm

focal length (f) = - 3.0 cm

Image distance (v) = ?

Using lens formula

[tex]\begin{gathered} \frac{1}{f}=\text{ }\frac{1}{v}-\frac{1}{u}; \\ \frac{1}{-3}=\frac{1}{v}-\frac{1}{-200}; \\ \frac{1}{-3}=\text{ }\frac{1}{v}\text{ +}\frac{1}{200} \\ \frac{1}{v}=\text{ -}\frac{1}{3}-\frac{1}{200}=-\text{ }\frac{203}{600} \\ v=\text{ - }\frac{600}{203}=\text{ -2.96 cm} \end{gathered}[/tex]

Now magnification is given by

[tex]Magnification=\text{ }\frac{v}{u}=\text{ }\frac{2.96}{200}=0.0148[/tex]

Final answer is :-

Image distance = - 2.96 cm & magnification = 0.0148

Which factor will increase the resistance of a conductor?

Answers

Length is directly proportional to resistance. When length increases resistance increases and vice versa.

Cross sectional area is inversely proportional to resistance. When cross sectional area of a conductor increases resistance decreases and vice versa.

Different materials have different resistances.

Temperature is directly proportional to resistance. When temperature increases resistance increases and vice versa.

a container holds a gas consisting of 1.50 moles of oxygen molecules. One in a million of these molecules has lost a single electron. What is the net charge of the gas?

Answers

A container holds a gas consisting of 1.50 moles of oxygen molecules. One in a million of these molecules has lost a single electron. the net charge of the gas will be + 9.033 * [tex]10^{17}[/tex]

If a negative charge is lost by an atom , then due to conservation of charge , that atom will acquire a positive charge . Similarly , if positive charge is lost then that atom  will acquire a negative charge .Now in above question

Total number of moles = 1.5

number of molecules in 1.5 moles of oxygen = 1.5 * 6.022 *[tex]10^{23}[/tex]  = 9.033 *[tex]10^{23}[/tex]  molecules

9.033 *[tex]10^{23}[/tex] / [tex]10^{6}[/tex] million molecules = 9.033 * [tex]10^{17}[/tex] million molecule

1 in a million has lost a single electron

9.033 * [tex]10^{17}[/tex] million molecule will loose 9.033 * [tex]10^{17}[/tex]  electron

the net charge of the gas will be + 9.033 * [tex]10^{17}[/tex]

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A ball is dropped from a hot air balloon at a height of 425 m and falls straight to the ground.
Determine the height above ground, the velocity and the acceleration of the ball after it has fallen
for 2.00 s.

Answers

The velocity and the acceleration of the ball after it has fallen

for 2.00 s  9.8 m/s.

Calculation:-

S = ut + 1/2 at²

  = 0 + 0.5 × 9.8 (2)²

 = 4.9 × 4

 = 19.6 m

v² = u² + 2aS

v² = 0 +2×9.8 × 19.6

  v  = √96.04 m

       =  9.8 m/s

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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Now that you have your research, you must write 6-8 sentence summary of how Newton’s Laws, energy, and forces are seen/used on roller coasters. You must use the vocabulary words above in your explanation. Bold and/or underline the vocabulary words in your writing. (PLEASE I NEED THIS) 0o0000

Answers

Based on  Newton's first law of motion, the roller coaster will continue its motion in a straight line unless and external force (the break) acts on it.

In accordance with the law of conservation of energy, as the roller coaster moves from the top position to the lower position, its potential energy will be converted to kinetic energy.

What is Newton's first law of motion?

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.

Based on  Newton's first law of motion, the roller coaster will continue its motion in a straight line unless and external force (the break) acts on it.

The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

Based on the law of conservation of energy, as the roller coaster moves from the top position to the lower position, its potential energy will be converted to kinetic energy.

The potential energy of the roller coaster is maximum at the highest position while the kinetic energy is maximum at the lowest position.

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why do we spread our fingers wide open while sitting before the fire or heater?​

Answers

Answer: This is an evolutionary adaption

Explanation:

As a result, practically all the heat you receive from a campfire when you are sitting next to one is transmitted through thermal radiation. Because of this, the side of your body that is facing the fire warms up, while the side that is facing away from it remains cool.

What our fingers wide open while sitting in a heater?

Since all the hot air is rising, you can actually fit your hand through the flame's base, which is also where the cold air from the surrounding space is drawn in. The flame's base is extremely chilly. You may reach through it and touch it with some soot.

Therefore, Heat is transferred through convection, which is the large-scale movement of molecules in fluids like liquid and gas. Consequently, one becomes warm while seated close to a fire.

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PLS HURRY
The photo shows a roller coaster. Assume the system is closed. Which roller-coaster car has the least potential energy due to gravity?
A. Car A
B. Car B
C. Car C
D. Car D

Answers

Answer: it's rather A or B

Explanation: those are the moments it stops but most likely it is answer A.

what happens to the molecules when carbon dioxide is heated

Answers

When the molecules of carbon dioxide is heated, it is disintegrated into molecules of carbon monoxide and oxygen atoms.

CO2 → CO + O

This is the basic reaction expected to happen by carbon dioxide molecules are heated. However it may also disintegrate into C2, O2, C, etc.

Since heat is absorbed in this reaction, it is an example of endothermic reaction. In an exothermic reaction heat is released. These are the basic two types of chemical reactions on basis of heat.

Therefore, when the molecules of carbon dioxide is heated, it is disintegrated into molecules of carbon monoxide and oxygen atoms.

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What does it mean to tare a balance and why do you think it is important to complete this before you begin measuring mass?.

Answers

When weighing chemicals on a balance, the term "tare" is used. Pressing the tare button enables you to record only the weight of the substance being measured, not the weight of the container it is being measured in.

Why is tare the balance prior to use important?

Weighing by difference is automatically accomplished by tarring a balance. When a balance is tared with an object on the balance pan, the weight of the object is automatically subtracted from each reading up until the balance is re-tared or zeroed.

Testing a balance is crucial because you want an accurate result when you weigh an object. The calculations could all be off if a balance is not set to zero.

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what is an advantage of concentrating solar energy as compared to other solar technologies? choose the best answer.

Answers

CSP technologies can be used to generate electricity by converting sunlight energy to power a turbine, but the same basic technologies can also be used to deliver heat to a variety of industrial applications such as water desalination, enhanced oil recovery, food processing, chemical production, and mineral processing.

What is concentrating solar-thermal power (CSP) technology and how does it work?

Concentrating  solar-thermal powertechnologies use mirrors to reflect and concentrate sunlight onto a receiver. The energy from the concentrated sunlight heats a high temperature fluid in the receiver.

This heat, also known as thermal energy, can be used to spin a turbine or power an engine, thereby producing electricity. It can also be used in industrial applications such as water desalination, improved oil recovery, food processing, chemical production, and mineral processing.

Utility-scale projects typically employ concentrated solar-thermal power systems. Utility-scale CSP plants can be configured in a variety of ways. Mirrors are arranged around a central tower that serves as the receiver in power tower systems. Linear systems use rows of mirrors to focus sunlight onto parallel tube receivers located above them.

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An electroscope is a device that detects charge on
What methods of charging does John use?
objects that touch it or are brought near it. John rubs a
piece of cotton fabric on a plastic rod and then louches
John charges the rod through induction, then charges
the rod to the electroscope.
the electroscope through friction.
• John charges the rod through conduction, then
charges the electroscope through induction.
• John charges the rod through friction, then charges
the electroscope through induction.
John charges the rod through friction, then charges
the electroscope through conduction.

Answers

John charges the rod through friction, then charges the electroscope through induction.

What is induction charging?

A charging technique called induction charging involves charging a thing without actually contacting it to another charged object.

The charged particle is held close to an uncharged conductive substance that is grounded on a neutrally charged material during the charging by induction process. When a charge is transferred between two objects, an uncharged conductive substance produces an oppositely polarized charge.

The rod is firstly charged by friction with the cotton fabric then John charges the rod through induction, then charges the rod to the electroscope.

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On which object will Earth's gravity act with the greatest magnitude? *
An apple
A cereal bowl
A watermelon
A TV remote

Answers

Answer: The watermelon

Explanation: The watermelon has a larger mass than the rest of the three.

What happens to light waves from a star as the star moves toward Earth?A. They appear to shift toward red.B. They appear to shift toward blue.C. They appear to become mechanical waves.D. They appear to stop.

Answers

When a star moves toward or away from the earth, the light will be in a slightly different place in the spectrum from where a start would be at rest.

Due to the doppler effect, if a star moves toward the earth, the star's spectral lines will make a shift toward the blue end of the spectrum.

Therefore, the light waves from a star as the star moves toward the earth will appear to shift toward blue.

ANSWER:

B. They appear to shift toward blue.

What diagrams can help support my answer and explain why is does it support?

Answers

Sunburn is caused by UV radiation by damaging DNA, as the following diagram shows:

Visible light and UV radiation differ in wavelength:

Since only Sunscreen A blocks UVA and UVB radiation, then it effectively prevents sunburn.

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