EXPLANATION :
From the problem, we have two events :
Event A : rolling an even number {2, 4, 6}
Event B : rolling a number greater than four {5, 6}
1. Union of A and B is the combination of Event A and B
Since there's a common element, 6, we will take this as one only.
That will be {2, 4, 5, 6}
2. Intersection of A and B is the common element between the two events.
So that is {6}
3. Complement of A is the set of elements that is NOT present in Event A.
Since a cube has 6 sides, the elements are {1, 2, 3, 4, 5, 6}
The complement of A will be {1, 3, 5}
4. Event B, from the data we have from above, B will have {5, 6}
Problem ID: PRABMVM9 For each of the functions f, g, h, P, and q, the domain is o sxs 100. For which functions is the average rate of change a good measure of how the function changes for this domain? Select all that apply. A. F(x)=x+2 B. g(x)=2* C. h(x)= 111x-23 D. p(x)=50,000 x 3% E. g(x)= 87.5
a) b) c) d)
1) Examining each function, let's test considering that the average rate of change is given by:
[tex]\Delta=\frac{f(b)-f(a)}{b-a}[/tex]2) So let's plug the functions:
[tex]\begin{gathered} a)\text{ }\Delta=\frac{(100)+2\text{ -\lbrack(0)+2\rbrack}}{100-0}=\frac{102-2}{100}=\frac{100}{100}=1 \\ b)\text{ }g(x)=2^x\text{ }\Delta=\frac{2^{100}-2^0}{100-0}=\frac{1.26\times10^{30}}{100}=1.26\times10^{28} \\ c)\text{ }h(x)\text{ = }111x-23\text{ }\Delta=\frac{111(100)-23\text{ -\lbrack{}111(0)-23}}{100}=111 \\ d)\text{ }p(x)\text{ = }50,000\times3^x\Delta=\frac{50,000-3^{100}-\lbrack50,000-3^0}{100}=-5.15\times10^{45} \\ e)q(x)=87.5 \end{gathered}[/tex]3) Since the average rate of change is a "measure of how much a function changes in the given interval" and considering that we have linear and exponential functions and the last one e) is not a function but an equation.
Then we can say that for the functions below the average rate of change is a good measure, not applying for the last one which, indeed is not a function.
a)
b)
c)
d)
Answer:
If you go off of the explanation below... the actual answers are A, C, E...
Step-by-step explanation:
Correct Answer
A)
f(x)=x+2
C)
h(x)=111x−23
E)
q(x)=87.5
If the lines /1 and /2 are parallel, what must be value of y?
ANSWER
y = 130 degrees
STEP-BY-STEP EXPLANATION
Key points to note in the provided figure
Alternate exterior angles are equal
The sum of supplementary angles is 180 degrees
From the figure given, angle y and angle 5x are alternate exterior angles
Since alternate exterior angles are equal. Hence, angle y = angle 5x
y = 5x
Also, angle (2x - 2) and y are supplementary angles
Recall, the sum of supplementary angles is 180 degrees
Hence, we have
y + (2x - 2) = 180
Note, y = 5x
substitute y = 5x into the above equation
5x + (2x - 2) = 180
Open the parenthesis
5x + 2x - 2 = 180
Collect the like terms
5x + 2x - 2 = 180
7x - 2 = 180
Add 2 to both sides of the equation
7x - 2 + 2 = 180 + 2
7x = 182
Divide both sides by 7
7x/7 = 182/7
x = 26 degrees
Since we have gotten the value of x = 26 degrees. Hence, we can now find the value of y
Recall, y = 5x
y = 5(26)
y = 130 degrees
Which answer choice correctly represents 1.436363636…?A) 1.436 _B) 1.436 __D) 1.436 ___C) 1.436
Given: The number below
[tex]1.436363636\ldots[/tex]To Determine: The simplified form of writing the given number
It can be observed the given number that 36 keeps recurring indefinitely
Hence, the nuumber can be written as
[tex]1.436363636\ldots=1.4\bar{36}[/tex]Hence, option C is the correct answer
it is due today!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
The value of 5/9x - 2/3y + xy when x = 3/5 and y = 1/2 is 3/10
We need to evaluate the expression
5/9x - 2/3y + xy
x = 3/5 and y = 1/2
(5/9)(3/5) - (2/3)(1/2) + (3/5)(1/2)
(15/45) - (2/6) + (3/10)
1/3 - 1/3 + 3/10
= 3/10
Therefore, the value of 5/9x - 2/3y + xy when x = 3/5 and y = 1/2 is 3/10
To learn more about fraction refer here
https://brainly.com/question/78672
#SPJ1
Write a numerical expression in the first box that represents the number of points earned or lost each round.then write Andy's final point total at the end of the competition in the second box.
In the first round, Andy has -320 times 1/2, which corresponds to
[tex]-320\times\frac{1}{2}=-\frac{320}{2}=-160[/tex]In the second round, Ansy has
[tex]710\times\frac{1}{4}=\frac{710}{4}=\frac{355}{2}[/tex]which corresponds to 177.5 (in decimals).
Finally, Andy's final point is
[tex]-320\times\frac{1}{2}+710\times\frac{1}{4}-500[/tex]which is equal to
[tex]-160+177.5-500=-482.5[/tex]that is, Andy's final point is - 482.5.
a dime has a diameter of 17.91 millimeters. What is the area of the face of the dime? use 3.14 for π. Round to the nearest hundredth if necessary
The area of a circle is:
[tex]A=\pi\cdot r^2[/tex]As you have the diameter, use it to find the radius: the radius of a circle is equal to the half of the diameter:
[tex]\begin{gathered} r=\frac{d}{2} \\ \\ r=\frac{17.91\operatorname{mm}}{2}=8.955\operatorname{mm} \end{gathered}[/tex]Then, the area is: 251.80 millimeters[tex]\begin{gathered} A=(3.14)(8.955mm)^2 \\ A=251.80\operatorname{mm} \end{gathered}[/tex]A gopher has dug hose and opposite corners of a rectangle yard if the artist 12 m x 16 m how far will the golfer have to run to get from one of its holes to the other
Given:
There are given that a rectangular yard.
Explanation:
To find the distance that one holes to other:
We need to use the Pythagoras theorem.
So,
From the Pythagoras theorem:
[tex]c^2=a^2+b^2[/tex]Where,
[tex]\begin{gathered} a=12 \\ b=16 \end{gathered}[/tex]Then,
Put both values into the above formula
So,
[tex]\begin{gathered} c^2=a^2+b^2 \\ c^2=12^2+16^2 \\ c^2=144+256 \\ c^2=400 \\ c=\sqrt[]{400} \\ c=20 \end{gathered}[/tex]Final answer:
Hence, 20 meters that will the gopher have to run get from one of its holes to the other.
There are given that a rectanglua
How much medicine is to be taken in each dose
what is the reflexive property of equality?
The reflexive property of equality states that every element is equal to itselft, for example, 3 = 3, or a = a. In algebra is often applied for numbers. In geometry is applied to sides or angles, for example, side A
Allison drew a map of where she and her friends live. Allison's house is at point A, and her friends live at points B, C, and D. She only wrote some of the distances, in blocks, on the map. Also, AD¯¯¯¯¯¯¯¯ is a perpendicular bisector of BC¯¯¯¯¯¯¯¯. Allison wants to know the distance between her house and point C.What is the measure of AC?
Solution:
Given that;
Allison drew a map of where she and her friends live.
Allison's house is at point A, and her friends live at points B, C, and D
Where, line segment AD is a perpendicular bisector of BC,
And a perpendicular bisector is a line segment which bisects another line segment at 90 degrees, and divides it into two equal parts..
Since, AD is a perpendicular bisector of BC, then
[tex]\begin{gathered} BD=CD=3 \\ \angle ADB=\angle ADC \\ And,\text{ }AD=CD \\ Thus, \\ \Delta ADB\cong\Delta ADC\text{ \lparen SAS\rparen} \end{gathered}[/tex]Hence,
[tex]AB=AC=4.24[/tex]The measure of AC is 4.24
You earn $8.00 for every lawn that you mow. You went out to lunch andspent $25.75. At the end of the day, you had $94.25. Write and solve anequation to figure out howmany lawnsyou mowed.
Let individual move x lawns.
The equation for the number of lawns is,
[tex]8x-25.75=94.25[/tex]Solve the equation to obtai the value of x.
PLEASE EEEEEEEE this is very important :’)
number attended/ total people
a) 153/225 = 17/25 = 0.68 = 68%
Answer:
A
Step-by-step explanation:
[tex]{ \tt{ = \frac{153 \div 9}{225 \div 9} }} \\ \\ = { \tt{ \frac{17}{25} }} \\ \\ = 0.68 \times 100\% \\ \\ = 68\%[/tex]
Solve the following system of equations by using elimination: 3x - y = -1 x + y = 13
Solution
For this case we have the following system of equations:
3x-y =-1 (1)
x +y= 13 (2)
Solving x from the (2) equation we have:
x=13-y (3)
Replacing (3) into (1) we got:
3(13-y) -y= -1
Solving for y we have:
39 -3y -y = -1
4y = 40
y= 10
And solving for x we got:
x= 13-10 = 3
A store has clearance items that have been marked down by 45%. They are having a sale, advertising anadditional 50% off clearance items. What percent of the original price do you end up paying?%Give your answer accurate to at least one decimal place.
We have clearance items that have two discounts applied to its price.
We can use a $1 item to find the final discount.
If we apply a 45% mark down, we will obtain a price of:
[tex]1-1*0.45=0.55[/tex]The discounted price is $0.55.
To this price we apply a 50% off. This can be expressed as:
[tex]0.55(1-0.5)=0.55*0.5=0.275[/tex]This is the final price.
We can calculate the percentage of the original price as:
[tex]\frac{P_d}{P_0}=\frac{0.275}{1}=0.275=27.5\%[/tex]Answer: 27.5%
Write an equation of the line in slope intercept form that passes through the given point and is perpendicular to the given line.(-2,4) , y = 2x + 9
We are given the point (-2,4) and the line y=2x+9. We want the equation of the line that passes through the given point and that is perpendicular to the given line.
To do so, we will use the following equation of a line
[tex]y\text{ -a = m\lparen x -b\rparen}[/tex]in this equation, m is the slope of the line and (a,b) is a point in the line. In our case, we are given that (-2,4) is in the line. That is, a=-2 and b=4. So our equation becomes
[tex]y\text{ -4=m\lparen x -\lparen-2\rparen\rparen}[/tex]or equivalently
[tex]y\text{ -4}=m(x\text{ +2\rparen}[/tex]now, we only need to find the value of m. To do so, we use the given line and the fact that the product of the slopes of perpendicular lines is -1.
The given line (2x+9) has a slope of 2. So, we have the following equation
[tex]m\cdot2=\text{ -1}[/tex]so if we divide both sides by 2, we get that
[tex]m=\text{ -}\frac{1}{2}[/tex]So the equation we are looking for becomes
[tex]y\text{ -4 }=\text{ -}\frac{1}{2}(x\text{ +2\rparen}[/tex]We want this equation in the slope intercept form. So we operate to find y in this equation. So first, we distribute on the right hand side. We get
[tex]y\text{ -4}=\text{ -}\frac{1}{2}x\text{ -}\frac{2}{2}=\text{ -}\frac{1}{2}x\text{ -1}[/tex]now we add 4 on both sides, so we get
[tex]y=\text{ -}\frac{1}{2}x\text{ -1+4= -}\frac{1}{2}x+3[/tex]we can check that if x= -2 we get
[tex]y=\text{ -}\frac{1}{2}(\text{ -2\rparen+3=1+3=4}[/tex]which confirms that the point (-2,4) is on the line
In right triangle ABC, m 2 A = 32°, m 2 B= 90°, andAC = 6.2 cm. What is the length of BC, to the nearesttenth of a centimeter?
Given Data:
In a triangle ABC,
[tex]\begin{gathered} \angle A=32^{\circ} \\ \angle B=90^{\circ} \\ AC=6.2\text{ cm.} \end{gathered}[/tex]From the triginometry,
[tex]undefined[/tex]which improper is equal to 4
Looking at the given fractions,
4/4 = 1
12/3 = 4
12/4 = 3
Thus, the improper fraction that is equal to 4 is 12/3
USE THE NORMAL CURVE TABLE TO DETERMINE THE PERCENT OF DATA SPECIFIED.A) TO THE LEFT OF z = 1.62B) BETWEEN z = -1.53 AND z = -1.82
SOLUTION:
Using a normal distribution table, we find that;
a. The area to the left of z = 1.62 is;
[tex]P(z<1.62)=0.9474[/tex]b. The area between z = -1.53 and z = -1.82, this is;
[tex]P(-1.82f(x) = -x^2 - 4x + 13find f(3)
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
f(x) = -x^2 - 4x + 13
f(3) = ?
Step 02:
f(x) = - x² - 4x + 13
f(3) = - (3)² - 4(3) + 13
f(3) = - 9 - 12 + 13
f(3) = - 21 + 13
f(3) = - 8
The answer is:
f(3) = - 8
What are the characteristics of a t-distribution? (Give at least 3characteristics).
Given,
T-distribution.
T-distribution: The T-distribution, also known as the student's t-distribution, is a type of probability distribution that is similar to the normal distribution with its bell shape but has heavier tails.
There are 3 characteristice of the distribution:
shape, central tendency and variability.
Write a equation of the line described
Passes through (4,8)
Parallel to the line y=-7/4x-4
Answer:
y=-7/4x+15
Step-by-step explanation:
Parallel line so has the same gradient:
y=-7/4x+c
Substitute (4,8) into above equation
8=(-7/4 x 4)+ c
rearrange to find c
8=-7+c
c=15
New equation: y=-7/4x+15
Hope this helps!
s Southern New Ham... t: This question is similar to Example 4 in "1-3 Reading and Participation Ac blications" in Module One. You can check your answers to part c and d to make right track. rectangle has perimeter 86 cm and its length is 1 cm more than twice its width. 1 the dimensions of a rectangle given that its perimeter is 86 cm and its leng e its width. ip your solution using the variables L for the length. W for the width, and P for the perimeter
You have that a rectangle has a perimeter of 86cm and its length is 1cm more than twice its width.
If W is the width and L is the length you can write the previous situation as follow:
part a:
2W + 2L = 86 perimeter of the rectangle
part b:
L = 2W + 1
replace the expression for y into the equation 2x + 2y = 86, just as follow:
2W + 2(2W + 1) = 86 expand the parenthesis
2W + 4W + 2 = 86 subtract 2 both sides and simplify like terms
6W = 86 - 2
6W = 84
W = 84/6
W = 14
L = 2W + 1 = 2(14) + 1 = 28 + 1 = 29
part c:
The length is 29 cm
part d:
The width is 14 cm
What is the perimeter of the figure Assume that all angles are right anglesA) 23 yardsB) 30 yardsC) 32 yardsD) 26 yards
The perimeter of the figure is the sum of the lengths of its sides. Find the missing side lengths to calculate the perimeter of the figure.
The length of then missing horizontal side is 6yd because it must add up to 8yd with the 2yd segment.
The length of the missing vertical side is 4yd because it must add up to 7yd with the 3yd segment.
Then, the perimeter of the figure is:
[tex]\begin{gathered} P=7yd+8yd+3yd+2yd+4yd+6yd \\ =30yd \end{gathered}[/tex]Therefore, the correct choice is option B) 30 yards.
Determine the type of triangle that is drawn below. W 5.57 50° X 80° 7.13 5-57 50° V
Given the triangle VWX
AS shown:
[tex]\begin{gathered} m\angle V=m\angle W=50 \\ m\angle X=80 \end{gathered}[/tex]So, the three angles are less than 90, which mean it is an acute triangle
And there are two congruent angles, which mean it is an isosceles triangle
so, the type of the triangle is an acute isosceles triangle
using the values from the graph, compute the values for the terms given in the problem. Choose the correct answer. Age of car = 4 years Original cost = 13,850 The current market value is $ _
Answer:
3462.5$
Step-by-step explanation:
If the percentage after 4 years was 25% then it dropped to 3462.5$.
5(2x-7)+42-3x=2 what is the answer
Problem
5(2x-7)+42-3x=2 what is the answer
Solution
For this case we can distribute the terms on this way:
10x -35 +42 -3x = 2
Now we can aggrupate similar terms and we got:
7x= 2+35-42
7x = -5
And then solving for x we got:
x= -5/7
1.75,____,6.75,9.25,11.75
Answer:
This looks like an addition (summation is the technical term) series. Here we need to figure out the difference between each number in the series. The difference between 6.75 and 9.25 is 2.5 (You can subtract the larger number from the smaller number to find out). So, 6.75-2.5=4.25.
So the correct answer in the blank is 4.25, and the rule is +2.5.
Step-by-step explanation:
For any positive number b not equal to 1 and any number or variable n, evaluate the following expression. logb (b^n) = ?
The logarithm is the inverse function of the exponentiation, and viceversa. The property of the logarithms and exponents tells us:
[tex]\log_b(b^n)=n[/tex] Thus, the correct answer is option A. n420, 84, 16.8, 3.36,... What is the explicit rule for this sequence? An =___ *(____)^n-1
Answer:
[tex]a_n=420\ast(0.2)^{n-1}[/tex]Explanation:
The explicit formula for a geometric sequence is always given in the form;
[tex]a_n=a_1\ast(r)^{n-1}[/tex]where an = the nth term of the sequence
a1 = the 1st term of the sequence
r = the common ratio of the sequence
From the given sequence, we can see that the 1st term, a1, is 420.
We can find the common ratio, r, by dividing any number of the sequence with its preceding number;
[tex]\begin{gathered} r=\frac{84}{420}=0.2\text{ or 16.8/84 = 0.2} \\ \therefore r=0.2 \end{gathered}[/tex]Substituting the above values into our formula above, we'll have;
[tex]a_n=420\ast(0.2)^{n-1}[/tex]A full 275 L tank contains a 20% saline solution. How many litres must be replaced with a 100% saline solution to produce a full tank with a 45% saline solution? Round your final answer to 1 decimal place if necessary.
Let x be the volume of 20% solution in the tank after the given process
Let y be the volume of 100% solution used.
The sum of x and y needs to be equal to the final volume 275L:
[tex]x+y=275[/tex]The amount of substance (salt) in each solution is calculated by multipliying the volume by the concentration (in decimals); then, the amount of salt in 20% solution is 0.2x, in 100% solution is 1y and in the final solution (45%) is 0.45(275).
Sum amount in 20% solution with amount in 100% solution to get the amount in final solution:
[tex]\begin{gathered} 0.2x+y=0.45\left(275\right) \\ 0.2x+y=123.75 \end{gathered}[/tex]Use the next system of equations to answer the question:
[tex]\begin{gathered} x+y=275 \\ 0.2x+y=123.75 \end{gathered}[/tex]1. Solve x in the first equation:
[tex]x=275-y[/tex]2. Use the value of x (step 1) in the second equation:
[tex]0.2\left(275-y\right)+y=123.75[/tex]3. Solve y:
[tex]\begin{gathered} 55-0.2y+y=123.75 \\ 55+0.8y=123.75 \\ 0.8y=123.75-55 \\ 0.8y=68.75 \\ y=\frac{68.75}{0.8} \\ \\ y=85.93 \end{gathered}[/tex]The volume of 100% solution that needs to be used is 85.9 Litres.
Then, the litres that must be replaced with 100% solution to produce a full tank with 45% saline solution is 85.9