A rectangular chocolate bar is made of equal squares. Irena breaks off two complete strips of squares and eats the 12 squares she obtains. Later, Jack breaks off one complete strip of squares from the same bar and eats the 9 squares he obtains. How many squares of chocolate are left in the bar?

Answer:

Step-by-step explanation:

o

Step-by-step explanation:

Figure ABCD is similar to figure A'B'C'D'. is the correct awnser.

Figure ABCD is similar to figure A'B'C'D'. is the correct awnser.this is became ABCD is reflected over the y-axis so it is simular too A'B'C'D.

A is incorrect because the size of the shape doesn't change when getting reflected.

B and D is incorrect because just by looking at the shape D is not equal to A' or B'

Hope this helps!!

Answer:

individuacion división como quieras

A cone has a diameter of 12 centimeters and a height of 9 centimeters. The volume of the cone would be 2034.72 cubic cm.

Suppose that the radius of considered right circular cone be 'r' units.

And let its height be 'h' units.

Then, its volume is given as:

[tex]V = \dfrac{1}{3} \pi r^3 h \: \rm unit^3[/tex]

The right circular cone is the cone in which the line joining the peak of the cone to the center of the base of the circle is perpendicular to the surface of its base.

A cone has a diameter of 12 centimeters and a height of 9 centimeters.

Radius = 12/2 = 6cm

Height h = 9 cm

The volume of the cone

[tex]V = \dfrac{1}{3} \pi r^3 h \: \rm unit^3[/tex]

[tex]V = \dfrac{1}{3} \times 3.14 \times 6^3 \times 9\: \rm unit^3\\\\V = 3.14 \times 648\\\\V = 2034.72 cm^{3}[/tex]

Hence, The volume of the cone would be 2034.72 cubic cm.

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The linear inequality (B) y>4x-5 represents the given solution set graph.

So, the linear inequality that represents the graph:

Graph the inequation as follows:

Now, we can easily notice that graph 2 which is of equation (B) y>4x-5 matches the given graph.

Therefore, the linear inequality (B) y>4x-5 represents the given solution set graph.

Know more about linear equality here:

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The correct question is given below;
Which linear inequality represents the solution set graphed?

A. y≥4x+5

B. y>4x-5

C. y>-4x-5

Answer:

X=180-124

X=56

Bpwxjpwxjwxwx

Answer:

56

Step-by-step explanation:

180 - 124 = 56

Answer:

33.49 cubic units

Step-by-step explanation:

[tex]V_{sphere} = \frac{4}{3} \times \pi {r}^{3} \\ \\ V_{sphere} = \frac{4}{3} \times \pi {(2)}^{3} \\ \\ V_{sphere} = \frac{4}{3} \times \pi \times 8 \\ \\ V_{sphere} = \frac{32 \times 3.14}{3} \\ \\ V_{sphere} = \frac{100.48}{3} \\ \\ V_{sphere} = 33.4933333\\ \\ V_{sphere} \approx 33.49\: units^3 [/tex]

Answer:

30 Skittles

Step-by-step explanation:

12 = .4 x S

12/.4 = S

30

taste the rainbow

-7 = 1 + 2/3n

Subtract 1 from both sides:

-8 = 2/3n

Multiply both sides by 3:

-24 = 2n

Divide both sides by 2:

N= -12

Answer:

n=-12

Step-by-step explanation:

Okay this isn't to hard first in the equation you must subtract 1 from both sides

So this: -7=1+2/3n

Becomes This: -8=2/3n

Then I divided by 2 on both sides to get:-4=1/3n

Then I multiplied by three to get -12=n

Let me know if you're still confused

Answer:

final for what?

Step-by-step explanation:

Answer:

171

Step-by-step explanation:

Okay since the exterior angles of every polygon is always 360

and this polygon has 40 sides,

360/40=9

180-9=171

Hope This helps

(what grade is this?)

Answer:

Option (b) will be the correct answer.

Step-by-step explanation:

190×10⁸

1.9×10²×10⁸

1.9×10¹⁰

Answer:

B

Step-by-step explanation:

190 x 10^8 = 19000000000

1.9 x 10 ^10= 19000000000

Answer:

Así es como lo escribes ^_^

Step-by-step explanation:

32.755

y si no lo siento

Answer:

Treinta y dos con siete mil quinientas cuarenta y ocho diéz milésimas y mil.

Espéro que te sirva!

Answer:

no

Step-by-step explanation:

f = 9

20 - 9 = 11

11 < 11 is incorrect

Answer:

A, E

Step-by-step explanation:

A: The angles are opposite (and we know that in parallelograms, opposite angles are congruent.)

E: In parallelograms opposite sides are parallel.

Answer:

2

Step-by-step explanation:

Answer:

the answer to the question is 2

Answer:

e(to the power of 9)

Step-by-step explanation:

when you multiply variables with exponents, you have to add the exponents together.

Hi there!

Answer:   [tex]\huge\boxed{\ e^9}[/tex]

Explaination:

  1. e^5 multiplied by e^4 = e^(5 + 4) = e^9

Hope this helps!

Given:

[tex]b(1)=-12[/tex]

[tex]b(n)=b(n-1)\cdot 4[/tex]

To find:

The third term of the sequence.

Solution:

We have,

[tex]b(n)=b(n-1)\cdot 4[/tex]

For n=2, we get

[tex]b(2)=b(2-1)\cdot 4[/tex]

[tex]b(2)=b(1)\cdot 4[/tex]

[tex]b(2)=-12\cdot 4[/tex]              [tex][\because b(1)=-12][/tex]

[tex]b(2)=-48[/tex]

For n=3, we get

[tex]b(3)=b(3-1)\cdot 4[/tex]

[tex]b(3)=b(2)\cdot 4[/tex]

[tex]b(3)=-48\cdot 4[/tex]              [tex][\because b(2)=-48][/tex]

[tex]b(3)=-192[/tex]

Therefore, the 3rd term of the sequence is -192.

Answer and Step-by-step explanation:

The answer that we have agreed upon is answer choice 2, C, A, B.

This is because the first distance is found, and could possibly be the hypotenuse, noted as C, then the other two sides are created, becoming the legs of a triangle, noted as A and B respectively.

I hope this helps and is correct!

#teamtrees #PAW (Plant And Water)

Question: Dave wants to invest $2000 in an account that earns 2.5% interest compounded monthly. If he  leaves the money in the account for 5 years, how much money will he have at the end of those 5 years?

Answer:

Step-by-step explanation:

Answer:

graph y=2x-7

Step-by-step explanation:

Answer:

Step-by-step explanation:

What is the question? If you want to know how to graph this equation, it's usually easiest to start with the intercepts, i.e., the points where the line crosses the axes.

y  = ½x + 3 tells you that the line crosses the y-axis at (0,3), so plot that point.

Then let y = 0 and solve for x.

0 = ½x + 3

x = 6

The line crosses the x-axis at (6,0), so plot that point as well.

Then draw the line passing through those two points.

Answer:

1.What is the theoretical probability that a coin toss results in two heads showing?

33%

2.What is the experimental probability that a coin toss results in two heads showing?

25%

3.What is the theoretical probability that a coin toss results in two tails showing?

33%

4.What is the experimental probability that a coin toss results in two tails showing?

21%

5.What is the theoretical probability that a coin toss results in one head and one tail showing?

33%

6.What is the experimental probability that a coin toss results in one head and one tail showing?

54%

Step-by-step explanation:

Hope this helps, I just finished my assingmnet like this tonight :))

[tex]\text{ as } x \to \infty, \ f(x) \to \infty\\\\\text{ as } x \to -\infty, \ f(x) \to -\infty[/tex]

In other words, as x gets really large in the positive direction, so does f(x).

As x gets really large in the negative direction, so does f(x). We can see that x and f(x) move in the same direction toward the same type of infinity.

In laymen's terms or in plain English, we can say that "The graph falls to the left and rises to the right". We don't worry about the wiggle motion in the middle, since all we care about is what's going on as x goes to either infinity.

"Falls to the left" means it goes down forever as we move leftward. "Rises to the right" means it goes up forever as we move to the right. This type of behavior of "falls to the left and rises to the right" is indicative of any odd degree polynomial where the leading coefficient is positive. In this case, it appears we're dealing with a cubic function of degree 3.

The derivative of [tex]f(x) = (3 + \tan x)\cdot (4 + 3\cdot \cos x)[/tex] is [tex]f'(x) = \frac{4+3\cdot \cos x-9\cdot \sin x \cdot \cos^{2}x+3\cdot \sin^{2}x\cdot \cos x}{\cos^{2}x}[/tex].

In this question we shall use the following derivative rules:

Derivative of a sum of functions

[tex]\frac{d}{dt}(f(t) + g(t)) = \frac{df(t)}{dt} + \frac{dg(t)}{dt}[/tex] (1)

Derivative of a product of functions

[tex]\frac{d}{dt}(f(t)\cdot g(t)) = \frac{df(t)}{dt}\cdot g(t) + f(t)\cdot \frac{dg(t)}{dt}[/tex] (2)

Derivative of a constant

[tex]\frac{d}{dt}(k) = 0[/tex], [tex]\forall k \in \mathbb{R}[/tex] (3)

Derivative of a function multiplied by a constant

[tex]\frac{d}{dt}(c\cdot f(t)) = c\cdot \frac{df(t)}{dt}[/tex], [tex]\forall\, c\in \mathbb{R}[/tex] (4)

Derivative of the cosine function

[tex]\frac{d}{dt} \cos t = -\sin t[/tex] (5)

Derivative of the tangent function

[tex]\frac{d}{dt}\tan t = \sec^{2} t[/tex] (6)

Chain rule

[tex]\frac{d}{dt}f[u(t)] = \frac{df(u)}{du}\cdot \frac{du(t)}{dt}[/tex] (7)

Let be [tex]f(x) = (3 + \tan x)\cdot (4 + 3\cdot \cos x)[/tex], then the derivative of [tex]f(x)[/tex] is:

[tex]f'(x) = \sec^{2}x\cdot (4 + 3\cdot \cos x) + (3+\tan x)\cdot (-3\cdot \sin x)[/tex]

[tex]f'(x) = 4\cdot \sec^{2}x+3\cdot \sec x -9\cdot \sin x -3\cdot \sin x\cdot \tan x[/tex]

[tex]f'(x) = \frac{4+3\cdot \cos x}{\cos^{2}x} -\frac{9\cdot \sin x \cdot \cos x+3\cdot \sin^{2}x}{\cos x}[/tex]

[tex]f'(x) = \frac{4+3\cdot \cos x-9\cdot \sin x \cdot \cos^{2}x+3\cdot \sin^{2}x\cdot \cos x}{\cos^{2}x}[/tex]

The derivative of [tex]f(x) = (3 + \tan x)\cdot (4 + 3\cdot \cos x)[/tex] is [tex]f'(x) = \frac{4+3\cdot \cos x-9\cdot \sin x \cdot \cos^{2}x+3\cdot \sin^{2}x\cdot \cos x}{\cos^{2}x}[/tex].

We kindly invite to check this question on derivatives: https://brainly.com/question/21202620

Answer:

10

Step-by-step explanation:

4k + 5 + 6k + 10 = 115  {Exterior angle property}

4k + 6k + 5 +10 = 115

         10k + 15 = 115

               10k = 115 - 15

               10k = 100

                  k = 100/10

k = 10

Step-by-step explanation:

g(fx)=g(3x+5)

= (3x+5)²+1

Answer:

about 52.1 in.

Step-by-step explanation:

PM=PE=5 inches, PR=4 inches, and OP=19 inches.

Since the figure is a kite, the diagonals ME and OR are perpendicular and form right triangles with their hypotenuses forming the sides of the kite, OM, MR, RE, and EO.

The figure shows the same kite O M R E as in the beginning of the task. Diagonal O R is perpendicular to diagonal M E.

Use the Pythagorean Theorem to calculate the length of OM.

OM=OP2+PM2−−−−−−−−−−√

Substitute 19 for OP and 5 for PM.

OM=192+52−−−−−−−√

=361+25−−−−−−−√

=386−−−√

Therefore, OM=386−−−√ in.

By the definition of a kite, OM≅EO. So, EO is also equal to 386−−−√ inches.

Use the Pythagorean Theorem to calculate the length of MR.

MR=PM2+PR2−−−−−−−−−−√

Substitute 5 for PM and 4 for PR.

MR=52+42−−−−−−√

=25+16−−−−−−√

=41−−√

Therefore, MR=41−−√ in.

By the definition of a kite, MR≅RE. So, RE is also equal to 41−−√ inches.

The figure shows the same kite O M R E as in the beginning of the task. Sides O M and E O are square root of 386 inches long. Sides M R and R E are square root of 41 inches long.

The perimeter of the kite is the sum of the four sides.

Perimeter of OMRE=OM+MR+RE+EO

=386−−−√+41−−√+41−−√+386−−−√

=2386−−−√+241−−√

Use a calculator to approximate.

Perimeter of OMRE≈52.1 in.

So, the perimeter of OMRE is about 52.1 inches.

Therefore, about 52.1 inches of binding are needed to cover the edges of the kite.

Answer:

50.8 degrees

Step-by-step explanation:

cos(x)=12/19