A projectile is launched at a height of h feet above the ground at an angle of θ with the horizontal. The initial velocity is v0 feet per second, and the path of the projectile is modeled by the parametric equations
x=(v0cosθ)t and y=h+(v0sinθ)t-16t^2
Write the parametric equations to model the path of a projectile launched from ground level (h = 0) at the given values of θ and v0. Use your equations to answer the following questions.

θ=40∘ , v0=128 feet per second
Determine the maximum height
Give the time the object reaches this height (to one decimal place).
Give the approximate horizontal distance the objects is at this point (to one decimal place).
Determine the time the object will hit the ground after it is launched (to one decimal place).

Answers

Answer 1

Using the equation, the time the object will hit the ground after it is launched is 3.4 seconds.

To model the path of a projectile launched from ground level (h = 0), we can set h = 0 in the equation for y:

[tex]y = (v_0sin \theta)t - 16t^2[/tex]

Therefore, the parametric equations for the path of the projectile are:

[tex]x = (v_0cos\theta)t \\y = (v_0sin \theta)t - 16t^2[/tex]

Substituting θ = 40∘ and v0 = 128 feet per second, we get:

[tex]x = (128 cos 40^o)t\\y = (128 sin 40^o)t - 16t^2[/tex]

To determine the maximum height, we need to find the vertex of the parabolic path, which is given by:

t = -b/2a

where a = -16, b = 128 sin 40∘, and c = 0 (since the projectile starts and ends at ground level). Substituting the values, we get:

t = -128 sin 40∘ / (2*(-16)) = 2.3 seconds (approx)

The maximum height can be found by substituting this value of t into the equation for y:

y = (128 sin 40∘)(2.3) - 16(2.3)^2 = 230.3 feet (approx)

Therefore, the maximum height is 230.3 feet and it is reached at 2.3 seconds.

To find the horizontal distance at this point, we can substitute the value of t into the equation for x:

x = (128 cos 40∘)(2.3) = 172.8 feet (approx)

Therefore, the approximate horizontal distance the object is at this point is 172.8 feet.

To determine the time the object will hit the ground after it is launched, we need to find the time when y = 0:

[tex]0 = (128 sin 40)t - 16t^2[/tex]

Solving for t using the quadratic formula, we get:

t = 0 or t = 8 sin 40∘ / 2 = 3.4 seconds (approx)

Therefore, the time the object will hit the ground after it is launched is 3.4 seconds.

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Add the following and simplify if possible.

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Answer:

2x+3

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

48 crayons

Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

 A barrel contains 56 litres of kerosene. It has two taps. One tap draws 500 ml every 6 minutes. After first 5 litres are drawn from the barrel, the second tap also starts. It draws 1 litre in every 5 minutes. How many hours will be taken in all to empty the tank?​

Answers

Answer:

The tank will empty in 4 hours.

Step-by-step explanation:

Since a barrel contains 56 liters of kerosene, and it has two taps, one tap that draws 500 ml every 6 minutes and after first 5 liters are drawn from the barrel, the second tap also starts, and it draws 1 liter in every 5 minutes, to determine how many hours will be taken in all to empty the tank, the following calculation must be performed:

0.5 x X = 5

X = 5 / 0.5

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1 hour 30 minutes = 51 - (1 x 6) - (0.5 x 5) = 42.5

2 hours = 42.5 - (1 x 6) - (0.5 x 5) = 34

2 hours 30 minutes = 34 - (1 x 6) - (0.5 x 5) = 25.5

3 hours = 25.5 - (1 x 6) - (0.5 x 5) = 17

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Answer:

Heyaa!!! Im Pinky! Im here to inform you that your answer is....

Step-by-step explanation:

               

                   

                       

1st. We need to Distribute:  

      3(+2)=2(2−)

      3+6=2(2−)

Just like That!

2nd. We have to Rearrange terms:

    3+6=2(2−)

   3+6=2(−+2)

3rd. Distribute One Last Time:

       3+6=2(−+2)

      3+6= −2+4

4th. Simplify:

    3=−2−2

5th. Add 2 to both sides of the equation:

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6th. Simplify:

    5=−2  

7th. Divide both sides of the equation by the same term:

       5=−2

      5/5 = -2/5

8th. Solve:

  x = -2/5

        Have an Amazing day!!

~Pinky~

help me plzzzzzzzzzz⏳zzzzzzzzzz

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Step-by-step explanation:

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Answer:

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Answers

The total amount of rainfall is an illustration of the sum operator

The total amount of rainfall that fell on Tuesday is 35 mm

How to determine the total amount of rainfall?

From the graph (see attachment), we have the following function values

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Evaluate the sum

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Answers Attached

__________________________________________________________

                                       

Does anyone know the answer to this?

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Answer:

0.4032

Step-by-step explanation:

1. We assume, that the number 72 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

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Step-by-step explanation:

your a  fattie

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Answer:

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Step-by-step explanation:

The solutions of a quadratic equation are :

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9.4 ——“”-“-“-“-“-“-“-“-“-“-“”—“-“-“-“-“-

find the value of x 3,9,10,8,7,x the mean is 7

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Here is the solution for that
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