A petrified stump that is 4 ft tall casts a shadow that is 2 ft long. Find the height of a tent that casts a 5 ft shadow
Answers
The petrified stump is 4 ft tall and cast a shadow that is 2 ft long .
2 ft shadow has a 4 ft height
5 ft shadow will have ? height
cross multiply
[tex]\begin{gathered} \text{height of tent = }\frac{5\times4}{2} \\ \text{height of tent = }\frac{20}{2} \\ \text{height of tent = 10 ft} \end{gathered}[/tex]
Related Questions
2(3x + 8) = 6x + 16How many solutions does this equation have
Answers
Answer:
The equation has infinite number of solutions
Explanation:
Given the equation:
2(3x + 8) = 6x + 16
To know how many solutions this equation has, we need to solve it and see.
Remove the brackets on the left-hand side
6x + 16 = 6x + 16
The expression on the left-hand side is exactly the same as the one on the right-hand side, this reason, there is infinite number of solutions that would satisfy this.
How do I find the restrictions on x if there are any? [tex] \frac{1}{x - 1} = \frac{5}{x - 10} [/tex]
Answers
We have the expression:
[tex]\frac{1}{x - 1}=\frac{5}{x - 10}[/tex]When we have rational functions, where the denominator is a function of x, we have a restriction for the domain for any value of x that makes the denominator equal to 0.
That is because if the denominator is 0, then we have a function f(x) that is a division by zero and is undefined.
If we have a value that makes f(x) to be undefined, then this value of x does not belong to the domain of f(x).
Expression:
[tex]\begin{gathered} \frac{1}{x-1}=\frac{5}{x-10} \\ \frac{x-1}{1}=\frac{x-10}{5} \\ x-1=\frac{x}{5}-\frac{10}{5} \\ x-1=\frac{1}{5}x-2 \\ x-\frac{1}{5}x=-2+1 \\ \frac{4}{5}x=-1 \\ x=-1\cdot\frac{5}{4} \\ x=-\frac{5}{4} \end{gathered}[/tex]Answer: There is no restriction for x in the expression.
the ratio of isabella's money to Shane's money is 5:10.if Isabelle has $55 how much money do Shane have?what about they have together?
Answers
Suppose that the manufacturer of a gas clothes dryer has found that, when the unit price is p dollars, the revenue R (in dollars) is R(P) = -9p2 + 18,000p. What unitprice should be established for the dryer to maximize revenue? What is the maximum revenue?
Answers
Suppose that the manufacturer of a gas clothes dryer has found that, when the unit price is p dollars, the revenue R (in dollars) is R(P) = -9p2 + 18,000p. What unit
price should be established for the dryer to maximize revenue? What is the maximum revenue?
we have the quadratic equation
[tex]R(p)=-9p^2+18,000p[/tex]this is a vertical parabola, open downward
the vertex represents a maximum
Convert to factored form
Complete the square
factor -9
[tex]R(p)=-9(p^2-2,000p)[/tex][tex]R(p)=-9(p^2-2,000p+1,000^2-1,000^2^{})[/tex][tex]\begin{gathered} R(p)=-9(p^2-2,000p+1,000^2)+9,000,000 \\ R(p)=-9(p^{}-1,000)^2+9,000,000 \end{gathered}[/tex]the vertex is the point (1,000, 9,000,000)
therefore
the price is $1,000 and the maximum revenue is $9,000,000Problem N 2
we have the equation
[tex]C(x)=0.7x^2+26x-292+\frac{2800}{x}[/tex]using a graphing tool
the minimum is the point (8.58,308.95)
therefore
Part a
the average cost is minimized when approximately 9 lawnmowers ........
Part b
the minimum average cost is approximately $309 per mower
How to find the diagonal side one triangle like the measure with the Pythagorean Theorem
Answers
How to find the diagonal side one triangle like the measure with the Pythagorean Theorem
see the attached figure to better understand the p
Solve the following system of linear equations by graphing:4.Ex+3y54 9- 5858615+cilo=Answer 2 PointsKeypadKeyboard ShortcutsGraph the linear equations by writing the equations in slope-intercept form:y =Ixty =IxtIdentify the appropriate number of solutions. If there is a solution, give thepoint:O One SolutionO No SolutionO Infinite Number of Solutions
Answers
We have a system of equations:
[tex]\begin{gathered} -\frac{4}{5}x+3y=-\frac{58}{5} \\ \frac{4}{3}x+\frac{9}{5}y=\frac{86}{15} \end{gathered}[/tex]We have to write the equations in slope-intercept form.
We start with the first equation:
[tex]\begin{gathered} -\frac{4}{5}x+3y=-\frac{58}{5} \\ 3y=-\frac{58}{5}+\frac{4}{5}x \\ 5\cdot3y=4x-58 \\ 15y=4x-58 \\ y=\frac{4}{15}x-\frac{58}{15} \end{gathered}[/tex]For the second equation we get:
[tex]\begin{gathered} \frac{4}{3}x+\frac{9}{5}y=\frac{86}{15} \\ \frac{9}{5}y=\frac{86}{15}-\frac{4}{3}x \\ y=\frac{5}{9}\cdot\frac{86}{15}-\frac{5}{9}\cdot\frac{4}{3}x \\ y=\frac{86}{9\cdot3}-\frac{20}{27}x \\ y=-\frac{20}{27}x+\frac{86}{27} \end{gathered}[/tex]To graph the equations we need two points. We can easily identify the y-intercept from the equations, but we have to identify one more point for each equation.
We can give a value to x and find the corresponding value of y.
Then, for example we can calculate y for x = 1 in the first equation:
[tex]\begin{gathered} y=\frac{4}{15}(1)-\frac{58}{15} \\ y=\frac{4}{15}-\frac{58}{15} \\ y=-\frac{54}{15} \end{gathered}[/tex]Then, for the first equation we know the points (0, -58/15) and (1, -54/15).
For the second equation we can do the same, by giving a value of 1 to x (NOTE: we can give any arbitrary value to x, it does not have to be the same for both equations) and calculate y:
[tex]\begin{gathered} y=-\frac{20}{27}(1)+\frac{86}{27} \\ y=-\frac{20}{27}+\frac{86}{27} \\ y=\frac{66}{27} \end{gathered}[/tex]Now we know the points of the second equation: (0, 86/27) and (1, 66/27).
With such fractions we can not make an accurate graph in paper, as they don't match the divisions of the grid.
We can use approximate decimals values for the fractions and graph the points.
The approximations for the first equation are:
[tex]\begin{gathered} (0,-\frac{58}{15})\approx(0,-3.9) \\ (1,-\frac{54}{15})=(1,-3.6) \end{gathered}[/tex]and for the second equation:
[tex]\begin{gathered} (0,\frac{86}{27})\approx(0,3.2) \\ (1,\frac{66}{27})\approx(1,2.4) \end{gathered}[/tex]We can then graph the equations as:
If we graph the equations with the exact points, we get an intersection point at (7,-2).
This intersection is the unique solution to both equations at the same time, so it is the only solution to the system of equations.
Answer:
The equations in slope-intercept form are:
y = 4/15 x + (-58/15)
y = -20/27 * x + 86/27
The system has only one solution: (7, -2).
⦁ It takes the earth 24 h to complete a full rotation. It takes Mercury approximately 58 days, 15 h, and 30 min to complete a full rotation. How many hours does it take Mercury to complete a full rotation? Show your work using the correct conversion factors.
Answer:
Answers
1 day = 24 hours
24*58= 1392hours 58/1 * 24/1 + 30/1* 1/60
1392+15=1407hours
1407hours+30min= 1407.5hours
2) (0.25 inches per hour)
24h=1day 12inches=1ft
0.5/24 = 0.02083
0.02083*12= 0.25 inches per hour
3) 0.08(50h)
50h means $50 per hour and 0.08 stands for 8% sales tax so the which means she is pay 8% of the total cost so the answer is 0.08(50h)
Answer:
58 days, 15 h, and 30 min
Step-by-step explanation:
PDonald has xxx twenty-dollar bills and 111 ten-dollar bill
Answers
the equation for this problem is
20x +10
where x is the number of bills with 20-dollars
Does the point (2, 6) satisfy the inequality 2x + 2y ≥ 16?
yes
no
Answers
Multiple the binomials (simplify) (y-4)(y-8)
Answers
Given
[tex](y-4)(y-8)[/tex]Simplify as shown below
[tex]\begin{gathered} (y-4)(y-8)=y(y-8)-4(y-8)=y^2-8y-4y+(-4)(-8)=y^2-12y+32 \\ \Rightarrow(y-4)(y-8)=y^2-12y+32 \end{gathered}[/tex]The answer is y^2-12y+32
15. A beekeeper estimates that his bee population will triple each year.
Answers
Answer:
[tex]P\mleft(x\mright)=150(3^x)[/tex]Explanation:
The initial number of bees = 150
[tex]P(0)=150[/tex]The beekeeper estimates that his bee population will triple each year. Thus, after 1 and 2 years:
[tex]\begin{gathered} P(1)=150\times3 \\ P(2)=150\times3\times3=150\times3^2 \end{gathered}[/tex]Continuing in like manner, after x years:
[tex]P(x)=150(3^x)[/tex]P(x) is the required function.
Write the percent as decimal 49%
Answers
Solution;
Given: The given number in percentage is 49 %
Required: Decimal value of given percentage.
Explanation:
Convert percentage into decimal as follows:
[tex]49\text{ \%=}\frac{49}{100}[/tex][tex]49\text{ \%=0.49}[/tex]Therefore, the required answer is 0.49
Final answer: The de
Tickets to a play cost $10 at the door and $8 in advance.
The theatre club wants to raise at least $800 from the sale of the tickets from the play. Write and
graph an inequality for the number of tickets the theatre club needs to sell. If
the club sells 40 tickets in advance, how many does it need to sell at the door to
reach its goal? Use x to represent the number of tickets sold at the door. Use y
to represent the number of tickets sold in advance.
Answers
The system of linear inequality is solved to determine that they need to sell at least 48 door ticket. The graph of the problem is attached below
System of Linear InequalityA system of linear inequalities in two variables consists of at least two linear inequalities in the same variables. The solution of a linear inequality is the ordered pair that is a solution to all inequalities in the system and the graph of the linear inequality is the graph of all solutions of the system.
To solve this problem, we have to write out a system of linear inequality and solve.
x = number of tickets sold at doory = number of tickets sold in advance10x + 8y ≥ 800 ...eq(i)
y = 40 ...eq(ii)
put y = 40 in eq(i)
10x + 8(40) ≥ 800
10x + 320 ≥ 800
10x ≥ 800 - 320
10x ≥480
x ≥ 48
They need to sell at least 48 door tickets to meet the target.
The graph of the inequality is attached below
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Which products are greater than 2 5/6?A.1/8 × 2 5/6B.2 5/6 × 2 5/6C.2 5/6 × 1 5/8D.5/6 × 2 5/6E.6/5 × 2 5/6
Answers
First, we need to change the mixed number to an improper fraction:
[tex]2\frac{5}{6}=\frac{(6\cdot2)+5}{6}=\frac{17}{6}\approx2.83[/tex]Now let's evaluate each of the options:
A.
[tex]\frac{1}{8}\times2\frac{5}{6}=\frac{1}{8}\times\frac{17}{6}=\frac{1\cdot17}{8\cdot6}=\frac{17}{48}\approx0.354[/tex]B.
[tex]2\frac{5}{6}\times2\frac{5}{6}=\frac{17}{6}\times\frac{17}{6}=\frac{17\cdot17}{6\cdot6}=\frac{289}{36}\approx8.02[/tex]C.
[tex]2\frac{5}{6}\times1\frac{5}{8}=\frac{17}{6}\times\frac{13}{8}=\frac{17\cdot13}{6\cdot8}=\frac{221}{48}\approx4.60[/tex]D.
[tex]\frac{5}{6}\times2\frac{5}{6}=\frac{5}{6}\times\frac{17}{6}=\frac{5\cdot17}{6\cdot6}=\frac{85}{36}\approx2.36[/tex]E.
[tex]\frac{6}{5}\times2\frac{5}{6}=\frac{6}{5}\times\frac{17}{6}=\frac{6\cdot17}{5\cdot6}=\frac{17}{5}\approx3.4[/tex]Now, we can conclude that options B, C, and E are greater than 2 5/6.
Evaluate the expression when x = 32 and y = 2.
x/14 A. 1/16
B.16/21
D.2
C.4
Answers
Answer:
I think its 16/21
Step-by-step explanation:
Answer:
2Step-by-step explanation:
Given x = 14, y = 2x/14
Void "y" because it is not in this equation.= x/14
32/14
= 2.2
≈ 2
I’m stuck on how to verify number 7 and how to find the possible value for sin theta
Answers
Given:
There are given the trigonometric function:
[tex]sec^2\theta cos2\theta=1-tan^2\theta[/tex]Explanation:
To verify the above trigonometric function, we need to solve the left side of the equation.
So,
From the left side of the given equation:
[tex]sec^2\theta cos2\theta[/tex]Now,
From the formula of cos function:
[tex]cos2\theta=cos^2\theta-sin^2\theta[/tex]Then,
Use the above formula on the above-left side of the equation:
[tex]sec^2\theta cos2\theta=sec^2\theta(cos^2\theta-sin^2\theta)[/tex]Now,
From the formula of sec function:
[tex]sec^2\theta=\frac{1}{cos^2\theta}[/tex]Then,
Apply the above sec function into the above equation:
[tex]\begin{gathered} sec^2\theta cos2\theta=sec^2\theta(cos^2\theta-s\imaginaryI n^2\theta) \\ =\frac{1}{cos^2\theta}(cos^2\theta-s\mathrm{i}n^2\theta) \\ =\frac{(cos^2\theta-s\mathrm{i}n^2\theta)}{cos^2\theta} \end{gathered}[/tex]Then,
[tex]\frac{(cos^{2}\theta- s\mathrm{\imaginaryI}n^{2}\theta)}{cos^{2}\theta}=\frac{cos^2\theta}{cos^2\theta}-\frac{sin^2\theta}{cos^2\theta}[/tex]Then,
From the formula for tan function:
[tex]\frac{sin^2\theta}{cos^2\theta}=tan^2\theta[/tex]Then,
Apply the above formula into the given result:
So,
[tex]\begin{gathered} \frac{(cos^{2}\theta- s\mathrm{\imaginaryI}n^{2}\theta)}{cos^{2}\theta}=\frac{cos^{2}\theta}{cos^{2}\theta}-\frac{s\imaginaryI n^{2}\theta}{cos^{2}\theta} \\ =1-\frac{s\mathrm{i}n^2\theta}{cos^2\theta} \\ =1-tan^2\theta \end{gathered}[/tex]Final answer:
Hence, the above trigonometric function has been proved.
[tex]sec^2\theta cos2\theta=1-tan^2\theta[/tex]Mr. Eric’s business class has 91 students, classified by academic year and gender, As illustrated in the following table. Mr. Eric randomly chooses one student to collect yesterday’s work. What is the probability that he selects a female, given that he chooses randomly from only the juniors? Express your answer as a fraction.
Answers
Given:
Eric’s business class has 91 students
Mr. Eric randomly chooses one student to collect yesterday’s work
We will find the probability that he selects a female, given that he chooses randomly from only the juniors
As shown from the table:
The number of females from the juniors = 6
The number of juniors = 6 +13 = 19
So, the probability will be =
[tex]\frac{6}{19}[/tex]help me please asap!!!
Answers
The slope of the function is 1/2 and the y - intercept is 2
The standard form of slope-intercept form of line is y = mx + b
where , m is slope of line
and b is y-intercept.
Observing the graph ,
we can say Linear function also passes through two points
At (4,0) on x-axis and at (0,2) on y-axis and
also , the graph is making right angles triangle at (0,0)
Slope of the function = m = Tan∅
Tan∅ = Perpendicular of right triangle / base of triangle
Perpendicular of triangle = 2 unit
and base = 4 unit
Tan∅ = 2/4 = 1/2
Therefore , slope of line = 1/2
equation of line : y = 1/2 x + b
This line is passing through (0,2)
2 = 1/2(0) + b
b = 2
Therefore , the y-intercept = 2
Hence , the equation of line = y = 1/2 x + 2
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which of the following gives the line of symmetry
Answers
To be able to reflect the trapezoid to itself, the reflection must be at the point where the figure will be divided symmetrically.
For a trapezoid, it must be reflected at the center of its base.
In the given figure, the center of the base of the trapezoid falls at x = 4.
Thus, to reflect it by itself, it must be reflected at x = 4.
The answer is letter B.
Ed earns a $100 commission on each computer he sells plus a base salary of $50,000 . His total income last year was 75,000 . Which equation can be used to find how many computers Ed sold last year ? A. 50,000 + 100x = 75,000 B. 50,000 - 100 x = 75,000 C. 75,000 + 100x = 50,000
Answers
ANSWER
50,000 + 100x = 75,000
STEP-BY-STEP EXPLANATION:
Given parameters
• Ed base salary = $50, 000
,• Commission on each computer sells = $100
,• Total income = $75,000
Let x be the number of computers sold
Total income = base salary + commission * number of cars sold
75000 = 50000 + 100* x
50,000 + 100x = 75, 000
Hence, the equation that can be used to find the number of cars sold is
50,000 + 100x = 75,000
THE GRAPH OF THIS SYSTEM OF LINEAR INEQUALITIES IS X-2Y< OR EQUAL 6 X> OR EQUAL TO 0 Y< OR EQUAL TO 2GRAPH
Answers
The graph of the system of linear inequalities x - 2y ≤ 6 , x ≥ 0 and y ≤ 2 is attached below.
The system of linear inequalities is x - 2y ≤ 6 , x ≥ 0 and y ≤ 2
The solution set of x ≥ 0 includes {x ∈ R , x ≥ 0 }
The solution set of y ≤ 2 includes {y ∈ R , y ≤ 2 }
The solution set of x - 2y ≤ 6 , shows the region of the graph that is below the straight line x - 2y = 6 .
Let us now plot the graph of the straight line x - 2y = 6 with the slope of -1/2 .
At x = 0 , y = - 3
At x = 2 , y = - 2
At x = -4 , y = - 5
hence the graph will pass through the points (0,-3) , (2,-2) and (-4,-5)
The line x = 0 indicates the x-axis and the line y=2 indicates the straight line parallel to x axis passing through (0,2) .
The shaded region of the graph indicates the solution set of the system of inequalities.
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What is 44.445 to the nearest hundredth
Answers
Answer:
44.45
Explanation:
Given 44.445
We are to convert to the nearest hundredth
Since the last value at the back is greater than 4, we will add 1 to the preceding value behind it to make it 5 as shown
44.445 = 44.4(4+1) [1 is added to the second value from the back
44.445 = 44.45
Hence the value to nearest hundredth is 44.45
4. Find the midpoint of DK, given the coordinates D (-10, -4) and K is located at the origin.m:|| m:1 m:Midpoint:Equation of the line:
Answers
The midpoint between two coordinates can be calculated using the equation
[tex]m=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]Point D has the coordinates (-10, -4). The problem stated that point K is located at the origin, hence, we can say that its coordinates are (0, 0).
Using the formula stated above to solve the coordinates of the midpoint, we get
[tex]\begin{gathered} m=(\frac{-10+0}{2},\frac{-4+0}{2}) \\ m=(\frac{-10}{2},-\frac{4}{2}) \\ m=(-5,-2) \end{gathered}[/tex]Answer: The midpoint of the line segment DK is located at (-5,-2).
Find the restricted values of x for the following rational expression. If there are no restricted values of x,indicate "No Restrictions".x² +8x² - x - 12AnswerHow to enter your answer (opens in new window)Separate multiple answers with commas.KeypadKeyboard ShortcutsSelecting a radio button will replace the entered answer value(s) with the radio button value. If the radiobutton is not selected, the entered answer is used.
Answers
Answer:
To find the restricted values of x for the given rational expression,
[tex]\frac{x^2+8}{x^2-x-12}[/tex]The above expression is defined only when x^2-x-12 not equal to 0.
x values are restricted for the solution of x^2-x-12=0
To find the values of x when x^2-x-12=0.
Consider, x^2-x-12=0
we get,
[tex]x^2-x-12=0[/tex][tex]x^2-4x+3x-12=0[/tex][tex]x\left(x-4\right)+3\left(x-4\right)=0[/tex]Taking x-4 as common we get,
[tex]\left(x-4\right)\left(x+3\right)=0[/tex]we get, x=4,x=-3
The restricted values of x are 4,-3.
we get,
[tex]x\ne4,-3[/tex]Answer is:
[tex]x\ne4,-3[/tex]The coordinates of the midpoint of GH are M(-2,5) and the coordinates of one endpoint are H(-3, 7).
The coordinates of the other endpoint are(
).
Echeck
? Help
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What are the coordinates of the other endpoint
Answers
EXPLANATION :
From the problem, we have segment GH and the midpoint is M(-2, 5).
One of the endpoints has coordinates of H(-3, 7)
and we need to find the coordinates of G(x, y)
The midpoint formula is :
[tex]M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]where (x1, y1) are the coordinates of G
(x2, y2) = (-3, 7) are the coordinates of H
and (-2, 5) are the coordinates of the midpoint.
Then :
[tex](-2,5)=(\frac{x+(-3)}{2},\frac{y+7}{2})[/tex]We can equate the x coordinate :
[tex]\begin{gathered} -2=\frac{x+(-3)}{2} \\ \\ \text{ cross multiply :} \\ -2(2)=x-3 \\ -4=x-3 \\ -4+3=x \\ -1=x \\ x=-1 \end{gathered}[/tex]then the y coordinate :
[tex]\begin{gathered} 5=\frac{y+7}{2} \\ \\ \text{ cross multiply :} \\ 5(2)=y+7 \\ 10=y+7 \\ 10-7=y \\ 3=y \\ y=3 \end{gathered}[/tex]Now we have the point (-1, 3)
ANSWER :
The coordinates of the other endpoint are G(-1, 3)
Find the indicated values for the function f(x)= Answer all that is shown
Answers
For this problem, we are given a certain function and we need to evaluate it in various points.
The function is given below:
[tex]f(x)=\sqrt{5x-15}[/tex]The first value we need to calculate is f(4), we need to replace x with 4 and evaluate the expression.
[tex]f(4)=\sqrt{5\cdot4-15}=\sqrt{20-15}=\sqrt{5}=2.24[/tex]The second value we need to calculate is f(3), we need to replace x with 3 and evaluate the expression.
[tex]f(3)=\sqrt{5\cdot3-15}=\sqrt{15-15}=0[/tex]The third value we need to calculate is f(2), we need to replace x with 2 and evaluate the expression.
[tex]f(2)=\sqrt{5\cdot2-15}=\sqrt{10-15}=\sqrt{-5}[/tex]The value for this is not real.
turn the expression from radical form to exponential expression in fractional form. No need to evaluate just be out in simplest form
Answers
To answer this question, we need to remember the next property of radicals:
[tex]\sqrt[n]{a^m}=a^{\frac{m}{n}}[/tex]In this case, we have that:
[tex]\sqrt[3x]{5}[/tex]And we can see that the exponent for 5 is m = 1. Therefore, we can rewrite the expression as follows:
[tex]\begin{gathered} \sqrt[3x]{5}=5^{\frac{1}{3x}} \\ \end{gathered}[/tex]In summary, therefore, we can say that the radical form to an exponential in fractional form is:
[tex]undefined[/tex]Write 3.6x10^-4 in standard form
Answers
In order to write the given number in standard form, you take into account that the factor 10^(-4) can be written as follow:
[tex]10^{-4}=\frac{1}{10^4}[/tex]Next, you consider that the number of the exponent in a 10 factor means the number of zeros right side number 1:
[tex]\frac{1}{10^4}=\frac{1}{10000}[/tex]that is, there are four zeros right side of number 1.
Finally, you write the complete number:
[tex]3.6\times10^{-4}=\frac{3.6}{10^4}=\frac{3.6}{10000}[/tex]A circular arc has measure of 4 cm and is intercepted by a central angle of 73°. Find the radius r of the circle. Do not round any intermediate computations, and round your answer to the nearest tenth.r= __ cm
Answers
The arc lenghr is given by:
[tex]s=r\theta[/tex]where s is the arc lenght, r is tha raidus and theta is the angle measure in radians. Since in our problem the angle is given in degrees we have to convert it to radians, to do this we have to multiply the angle by the factor:
[tex]\frac{\pi}{180}[/tex]Then:
[tex]\theta=(73)(\frac{\pi}{180})[/tex]Plugging the value of the arc lenght and the angle in the first formula, and solving for r we have:
[tex]\begin{gathered} 4=r(73)(\frac{\pi}{180}) \\ r=\frac{4\cdot180}{73\cdot\pi} \\ r=3.1 \end{gathered}[/tex]Therefore, the radius of the circle is 3.1 cm.
Find the distance between (-4, 2) and (10, 2) c. -14d. 14
Answers
The distance between two points (a, b) and (c, d) is given by:
[tex]\sqrt[]{(c-a)^2+(d-b)^2}[/tex]For points (-4, 2) and (10, 2), we have:
a = -4
b = 2
c = 10
d = 2
Thus, the distance between those points is
[tex]\sqrt[]{\lbrack10-(-4)\rbrack^2+(2-2)^2}=\sqrt[]{(10+4)^2+0}=\sqrt[]{14^2}=14[/tex]Therefore, the answer is 14.