a container in the form of a right circular cone (vertex down) has radius 4 m and height 16 m. see the figure. if water is poured into the container at the constant rate of 16 m3/min, how fast is the water level rising when the water is 8 m deep?

A stack of books rests on a level frictionless surface. a force f acts on the stack, and it accelerates at 3.0 m/s2. a 1.0 kg book is then added to the stack. the same force is applied, 2.0kg was the mass of the original stack.

The concept of the frictionless plane first appeared in the writings of Galileo Galilei. In his 1638 book The Two New Sciences, Galileo offered a formula that predicted the motion of an object falling down an inclined plane. His model was not based on experiments with objects moving down an inclined plane, but rather on his conceptual modeling of the forces acting against the object. His formula was based on earlier experiments with free-falling bodies. Galileo understood the mechanics of the inclined plane as a combination of horizontal and vertical vectors because gravity acting on the object and being redirected by the slope of the plane. Galileo's equations, on the other hand, do not take friction into account, and as a result, they do not accurately predict the results of a practical experiment. This is due to the fact that whenever one mass exerts a non-zero normal force on another, some energy is always lost.

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Answer:

the mass of the car is very big

Explanation:

its heavy

The specific gravity of an material is defined as the ratio of the density of the material to the density of water then the fraction of ice berg above the surface of water is 1.11ppm.

Specific gravity is defined by ASTM D4439 as the ratio of the density of the material in question to that of the reference material at the specified temperature and pressure conditions.

In practice, this is accomplished by measuring the mass of a unit volume of geosynthetics in a standard laboratory atmosphere and measuring again with the geosynthetics immersed in water. Substances with a specific gravity less than 1 float in water.

Geotextile specific gravity is actually the specific gravity of the polymeric raw material used to make the geotextile. Polyethylene and polypropylene float in the specific gravity range of 0.90 to 0.96, so be careful when working in water.

Fraction of iceberg = 1.025/0.917=1.11ppm

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A lunar astronaut carries a 110 kg box and a 230 kg load. The forces required to move the containers straight up on the moon are enormous compared to the forces required to hoist them on Earth.

A forces is an influence with the capacity to change the motion of an object. When an object with mass moves away from rest, for example, a force can cause it to accelerate as its velocity increases. A push or a pull are two straightforward ways to demonstrate force. Since a force has both magnitude and direction, it is a vector quantity. It is computed using the SI unit of newton (N). The letter F stands for force (formerly P). The original wording of Newton's second law states that the net force acting on an item is equal to the rate of change of its momentum over time. This law states that if an object's mass stays constant, its acceleration should be directly proportional to the net force exerted on it and inversely proportional to the object's mass. Thrust, which increases an object's velocity; drag, which decreases an object's velocity; and torque, which modifies an object's rotational speed, are all ideas connected to force. Internal mechanical stress describes how these forces are distributed within the body. The adjacent regions are frequently put under stress by each expanded body part.

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The probe that NASA sends will encounter the destinations in the order as follows:

A probe, or space probe specifically, is a robotic spacecraft made to explore outer space. Generally, a probe will encounter its destinations from the nearest to Earth to the farthest from Earth.

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The maximum speed she can tolerate at the low point of her swing is 10.78 m/s.

Given that,

Mass of the carpenter = 61.7 kg

Length of the rope = 11.5 m

Capable force = 1229 N

Centripetal force acting on the body, F = mv²/r = 61.7* v²/11.5 = 5.37 v²

Gravitational force acting on her is

F = mg = 61.7* 9.81 = 605.28 N

Equating the summation of centripetal force and gravitational force with total capable force,

5.37 v² + 605.28 = 1229

5.37 v² = 623.72

v² = 116.15

v = 10.78 m/s

Thus, the maximum speed she can tolerate at the low point of her swing is 10.78 m/s.

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Internal energy of equipartition energy is due to kinetic energy of molecules.

There are now two possible cases:

1) Expansion occurs at the expense of the gas's internal energy, so the gas temperature decreases as it expands. Therefore U decreases.

2) As the temperature decreases, so does the velocity of the gas molecules and the K of the gas decreases continuously.

This concept often takes into account what considers heat as internal energy. Molecular kinetic energy, vibrations, rotations, electron "shell" positions, molecular bending, crystal lattice vibrations, etc.

Generally, pressure should be considered part of the internal energy. Theoretically, matter can be expanded or heat can be transferred to do work.

At absolute zero temperature and pressure we can see that there is still internal energy. This can be seen as a result of the blurring principle. Particles cannot be confined to too small a volume and velocity.

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Constructive interference between points A and B will occur at 2.5m from source A. Destructive interference between points A and B will occur 4m and 1m from source A.

Interference refers to a phenomenon where two waves are combined by adding their displacement together at every single point in space and time, to form a resultant wave of greater, lower, or the same amplitude. Constructive interference occurs when two waves overlap in a way to create a larger wave. Destructive interference occurs when two waves overlap in a way to cancel each other out.

The condition for constructive interference to occur is |dA-dB|=mλ

Where dA is the distance of the point from source A, dB is the distance of the point from source B, m is an integer number, and λ is the wavelength = 6m.

Based on the condition, there can be one solution when m = 0 otherwise the difference between dA and dB would be at least 6m which is impossible as the sources are at a distance of 5m. Hence,

dA – dB = 0

dA = dB = 5/2 = 2.5m

The condition for constructive interference to occur is |dA-dB|=(m+1/2)λ

Based on the condition, the solution will occur when m = 0 otherwise the point will not be between source A and B.

Hence, when m = 0

|dA-dB|=(0+1/2)λ=λ/2=3

Using dB = 5 – dA to find the possible solutions.

dA = dB + 3

dA = 5 - dA + 3

2dA = 8

dA = 4m

and

dB – dA = 3

5 – dA – dA = 3

2dA = 2

dA = 1m

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We need to know angular acceleration α to  give answer to this question. For completing the question, suppose the disc is spinning at 300 RPM.

Angular acceleration α = (300× 2/ 60)/2.50 = 4 m/square second

The required torque L is given by

L = I*alpha,

where,

I = the moment of inertia of the disc,

I = (1/2) M R^2

Therefore

L = (1/2) M R^2 *4 rad/s^2

The units will be Newton-meters

Once you have determined L, use

F = L/R for the required friction force, in Newtons.

Friction is the force that always resists motion of a moving object on the surface of other object.

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On the starting blocks, sprinters use their feet to push backward. The blocks respond by pressing forward with a force equal to this with their feet.

Vertical forces must be larger than the pull of gravity in order to assist the sprinter in moving forward as gravity is pushing him or her downward. The propulsive force is the force that propelled the runner forward.

An interaction diagram and a free-body diagram should be included in your explanation. The player pushes down on the ground, which pushes up against him in return. As a result of his push being stronger than gravity, the player accelerates upward.

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.Answer: All options are correct.

What is sports medicine specialist?

--Sports medicine is a branch of medicine that deals with physical fitness and the treatment and prevention of injuries related to sports and exercise.

Lets understand every points--

1. During playing any sports if a person get any type of injury , at that situation it need instant relief to continue the game. So first option is correct i.e it performs emergency medical care.

2. Many times during heavy injury sportsman require surgery to get again health life.And surgery needs time., so that's why second option is also correcti e performs long term medical care

3.Without diagnosis surgery is not possible i.e. thirds option is also correct.

4. Also sports medicine specialist provide training and such types of exercise so that body as soon as possible i .e forth option is also correct.

from above discussion we see all points.

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The momentum of the moving car is 30000 kg m/s.

The momentum of a moving body is calculated as the product of mass and velocity. It is a vector quantity. In simple terms, it is the strength or force gained by a moving object.

Newton's second law is related to momentum. According to newton's second law, " The time rate of change of momentum is equal to force".

We have the formula for finding the momentum,

Momentum = Mass× Velocity

P = M × V

Put the value in the formula,

P = 1200 × 25 kg m/s

= 30000 kg m/s

So, the car is moving with a momentum of 30000 kg m/s.

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Dilation doesn't always change the vertices.

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Thus, light with an intensity of 2I will be incident on the second polarizer. The intensity will fall by a factor of cos2 across the second polarizer. As a result, the intensity is 2Icos2=2Icos2(450)=4I after going through the second polarizer.

I = Io cos2, where Io is the original intensity and is the angle formed by the polarization direction and the filter's axis, gives the intensity of polarized light after it has passed through a polarizing filter.

I = P > A is the formula for intensity in physics. Power is measured in Watts while researching light waves, and since light is so large, area is typically measured in meters.

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When the train approaches you, the Doppler's effect gives the frequency  240.12 Hz

When the train moves away from you, the Doppler's effect gives the frequency  199.6 Hz

Given that,

Frequency of train horn, f = 218 Hz

Speed of train, Vt = 31.7 m/s

The speed of the sound , V = 344 m/s

When the train approaches you, the Doppler's effect gives the frequency as follows :

[tex]f^{'} = f (V/ V-V_{0} )[/tex]

[tex]f^{'}[/tex] = 218 * ( 344/ 344 - 31.7)

   = 240.12 Hz

When the train moves away from you, the Doppler's effect gives the frequency as follows :

[tex]f^{'} = f ( V / V+ Vt)[/tex]

   = 218 * ( 344/ 344 + 31.7)

   = 199.6 Hz

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The drift velocity of electron is 4.54 * 10⁻⁴ m/s.

Given that, Density of copper is 8.8* 10³ kg/m³

Charge of an electron is 1.6* 10⁻¹⁹ C

For the density of copper, the number of free electrons n can be calculated by

n = number of electrons per kg * ρ

⇒ (9.4776* 10²⁴ ) (8.8 * 10³ kg/ 1 m³) = 8.314 * 10²⁸ electrons per m³

Diameter of the wire is given as 2.053 mm

Let us calculate A for the provided diameter of wire

A = π * (d/2)² = π * (2.053 /2)² = 3.310* 10⁻⁶ m²

Given, I = 20 A

We know the expression for drift velocity as

Vd = I /(n* A* e) = 20 / (8.314 * 10²⁸ * 3.310* 10⁻⁶ * 1.6* 10⁻¹⁹) = 20 / (4.403 * 10⁴) = 4.54 * 10⁻⁴ m/s

Thus, the drift velocity of electron is 4.54 * 10⁻⁴ m/s.

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a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s .The amplitude of the subsequent oscillations 48.13 cm/s

a 1.25 kilogram block is fastened to a spring with a 17.0 newtons per meter spring constant. Given that K is equal to 14 Newtons per meter and mass equals 10.5 kg. The block is then struck with a hammer by a student while it is at rest, giving it a speedo of 46.0 cm for a brief period of time. The required energy provided by the hammer, which is half mv squared, is transformed into potential energy as a result of the succeeding oscillations. This is because we know that energy is still available for consultation. So access the amplitude here from here. He will therefore be equal to and by. Consequently, the Newton's spring constant is 14 and the value is 10.5. The velocity multiplied by 0.49

Speed at X equals 0.35 into amplitude, or vice versa. At this point, the spirit will equal half of K X 1 squared plus half. Due to the fact that this is the overall energy, square is equivalent to half of a K square or an angry square. amplitude is 13 and half case 14 x one is 0.35. calculate that is equal to initial velocities of 49 squares and masses of 10.5. This will be divided in half and start at about 10.5 into the 49-square-minus-14. 13.42 into the entire square in 20.35. dividing by 10.5 and taking the square as a result. 231 6.9 Six centimeters per square second. 10.5 into 49 sq. 14. 2 into a 13.42 square entire. then subtract 10.5 from the result to get the square. So that is 48.13cm/s.

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This is incomplete question Complete Question is:

a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s . what are The amplitude of the subsequent oscillations?

The Carnot engine is 40% efficient.

It's far a super reversible thermodynamic manner that includes the subsequent 4 tactics, Isothermal growth, No different heating is more efficient than this one, as there may be no finite temperature distinction between the warmth supply and warmth receiver. Therefore, it's miles the most efficient reversible system.

A Carnot engine can be notion of to include a cylinder with adiabatic lateral partitions packed with a substance which can take in and supply warmness. The cylinder is closed by way of an adiabatic piston which could move out and deliver work. The cylinder can acquire paintings by means of shifting the piston inward.

The Carnot engine is a theoretical thermodynamic cycle proposed by means of Leonard Carnot. It estimates the maximum feasible performance that a heat engine all through the conversion manner of warmth into paintings and, conversely, operating among two reservoirs can own.

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Work done is calculated as the scalar product of force and displacement along the force's direction, so it should be zero because there is no net force acting on the object (hence the constant velocity). Thus, W is equal to 0.

Newton's first law of motion states that any object moving at a constant speed experiences no net external forces, so the total amount of forces acting on the object must be zero. The mathematical expression for an object being under no net external force is Fnet=0 or F=0.

Acceleration equals zero when velocity stays the same. Therefore, an object moving at a constant speed does not require any force.

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a) the total friction on long side =107 N

b) The total friction on short side = 151.4 N

a) fluid parallel to long side of the plate

here the initial velocity is= 6m/s

F = 1/2 ρCf.AU²

ρ= density= 870kg/m³

Cf = friction of coefficient

depends on reynolds number,

Re = ρuL/ μ

l = 1.1m

μ = 1.04 X 10⁻¹kg/m.s

Re = 870 X 6 X 1.1/ 1.04 X 10 ⁻¹

Re = 55211.54

this Re = 55211.54 is less than 5 X 10⁵

Cf = 1.328/√55211.5

Cf = 0.00565

A being area of plate A = 110 X 55 /10000

A = 0.55m²

F = 1/2 ρCf.AU²

F = 1/2 X 870 X 0.0056 X 2 X 0.55 X 6 ²

F = 107N

b) for short side the Re = 27606

since the value is less than 5 X 10⁵

Cf = 0.00799

to calculate F

F = 1/2 ρCf.AU²

F = 1/2 X 870 X 0.00799X 2 X 0.55 X 6²

F = 151.4 N

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6.25 s does the car come to a stop and 78.125 m distance travelled before stopping.

Solution:

Given:

Initial velocity, v0 = 25 m/s

Acceleration, a = -4m/s2

Final velocity, vf = 0

Put these values in the formula,

To find time,

vf = v0 + a*t

0 = 25 - 4t

t = 25/4

t = 6.25 s

To find distance travelled,

d = ((vf + v0)/2)*t

d = 25/2 * 6.25

d = 12.5 * 6.25

d = 78.125 m

Hence,  6.25 s does the car come to a stop and 78.125 m distance travelled before stopping.

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The coefficient of static friction between the box and table is 0.45.

What is friction?

We are constantly surrounded by a force called friction that prevents relative motion between surfaces in contact while simultaneously allowing us to move (which you have discovered if you have ever tried to walk on ice). Even though friction is a common force, its behavior is actually quite complex and still not fully understood. For any understandings we can obtain, we must heavily rely on observations. We are nevertheless able to deal with its simpler general qualities and comprehend the situations in which it functions.

Given,

[tex]m_{A}[/tex] = 3kg

[tex]m_{B}[/tex] = 1.35 kg

A) Solving for static friction,

T = [tex]m_{B}[/tex]g

T = 1.35 × 9.8

T = 13.23

Now,

T = [tex]F_{f}[/tex] = μ[tex]m_{A}[/tex]g

Here, μ = static friction

13.23 = μ × 3 × 9.8

μ = 0.45

So, coefficient of static friction is 0.45.

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Infrared Radiation lies on third place of electromagnetic spectrum in the increasing order of frequency.

In his experiments to measure temperature differences between colors in the visible spectrum, he placed a thermometer in the path of light within each color in the visible spectrum. He noticed that the temperature rose from blue to red, and found that just beyond the red end of the visible spectrum showed even higher temperatures. Within the electromagnetic spectrum, infrared waves occur at frequencies higher than those of microwaves and slightly lower than those of red visible light, hence the name "infrared".

Infrared radiation is an integral part of the electromagnetic spectrum.

It has wavelength of 700nm and has good application for earth sciences.

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The mass  of the planet is 6.67×10^25 kg

let the mass of the planet be M and r be the radius of the planet and g be the gravitational acceleration.

The gravitational acceleration is given by:

g = G×M/(r^2)

M = g×r^2/G

  = [(18)×(1.2×10^7)^2]/(6.67408×10^-11)

  = 6.67×10^25 kg

therefore, the mass of the planet is 6.67×10^25 kg

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The fish seems to be -12.96 cm when viewed from above, directly in front of the bowl. the point at which a fish is 10.8 cm from the front surface of a fish bowl with a 40 cm radius.

A surface is the outermost or highest layer of a physical object or place, to use the term in its most common usage. It is the area or piece of the thing where an observer can first perceive it through touch and sight and where other materials first come into contact with it. Any line segment that connects a circle's centre to its perimeter is considered a circle's or sphere's radius in classical geometry.

n1/do+n2/di = n2-n1/R

1/10.8 + 1.3/di = -.3/39

di = -12.96 cm  12.96 cm from the front surface of bowl.

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When viewed directly in front of the bowl from above, the fish seems to be 12.96 cm long. the spot where a fish is 10.8 cm from the front surface of a fish bowl with a 40 cm radius.

To use the word in its most common sense, a surface is the outermost or uppermost layer of a physical item or location. It is the region or portion of the object where an observer can first experience it through touch and sight and where other materials first come into contact with it. In classical geometry, a circle's or sphere's radius is any line segment that connects the center to the edge of the object.

n1/do + n2/di = n2/n1/R

1/10.8 + 1.3/di = -.3/39

di = -12.96 cm 12.96 cm away from the front surface of bowl.

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A cart speed will often increase on a downhill slope while decreasing on an uphill section. A steeper gradient portion has a more pronounced impact on the acceleration or slowdown of a vehicle's speed.

The cart speed/velocity will progressively rise by the same amount each second. The rate of acceleration of the car increases with the slope's steepness (or the ramp's greater angle of inclination). This is so because the slope's angle determines how much gravity is felt.

Therefore, the more gravitational potential energy that can be turned into kinetic energy, the higher the ramp will be, and the more kinetic energy there is, the faster the car will move.

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The heat flow of the thermal resistance is (r2 - r1) / 4πkr1r2).

Consider the diagram below, the heat flow will be

Fourier's law in radial coordinates

qr = -k.AdT/dr

Substituting the values of the area of sphere,

qr = -k (4πr²) dT/dr

Integrating we get

qr/4π∫dr/r^2 = ∫kdt

qr/4π ∫dr/r^2 = ∫kdt

qr/4π (1/r1 - 1/r2) = k(t2-t1)

qr = 4πkr1r2(t1-t2) / (r2 - r1)

The thermal resistance is expressed as

R = (r2 - r1) / 4πkr1r2)

Therefore, the heat flow of the thermal resistance is (r2 - r1) / 4πkr1r2).

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The distance of lens from the object is 4.16 cm, so that its image is seen at the near-point distance of 25 cm.

The near-point distance of a human eye, described to be s = 25 cm, is the shortest item distance that a typical or "normal" eye is capable of accommodate, or to photo onto the retina. The some distance point of a human eye is the farthest object distance that a standard eye is able to photo onto the retina.

The human eye can see objects genuinely with none pressure on the attention while an item is placed at the least 25 cm away. This distance of 25 cm is called the close to point of the eye. while the object is positioned at a distance between 25 cm and infinity, the photo of the object is fashioned on the retina and interpreted surely.

Calculation:-

for magnifier

magnification m = 25 cm /f

5 = 25/f

f = 25/5 = 5 cm

ten using lens equation

1/f = 1/do + 1/di

1/5 = (1/do)-(1/25)

1/do = (1/5)+(1/25)

do = 4.16 cm

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The light travels faster in water medium with a density of 1.33 when compared to diamond medium with a density of 2.42.

A denser medium will have more matter compared to rarer medium. So, the scattering of light is higher in a denser medium resulting in lesser travel speed. Slower the speed higher will be the index of refraction. So light will travel more slowly in a dense medium.

Refractive index of Diamond = 2.42

Refractive index of water = 1.33

Since, refractive index is inversely proportional to speed of the wave, speed of light in water is higher than the speed of light in diamond.

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